Classify the following substances as strong electrolytes, weak electrolytes, or nonelectrolytes:
(d) Calcium acetate [Ca(C₂H₃O₂)₂]

6.375 moles of O2 are required to form 4.25mol \(CaCO_{3}\) if the net balanced equation given is,

                Ca (solid) + C (solid) + 3/2 O2 (gas) ⟶\(CaCO_{3}\) (solid).

The balanced equation is,

  Ca (solid) + C (s) + 3/2 O2 (g)  ⟶ \(CaCO_{3}\) (solid).

A balanced equation is defined as a chemical equation in which mass is conserved and there are equal numbers of atoms of each element on both sides of the equation. This equation has an equal number of atoms of each element on both sides of the chemical equation. The mass of the reactants is said to be equals to the mass of the products.

The number of moles of a substance can be expresses as the ratio of its given mass in a chemical reaction to the mass of one mole of that substance. One mole of any substance is equals to Avogadro's number, that is 6.023 × 1023. It is generally used to express concentration units such as mole per liter or molecular weight.

1 mole of \(CaCO_{3}\) is formed by 3/2 moles of O2.

4.25 moles of \(CaCO_{3}\) will be formed by,

    =   3/2 * 4.25

    = 6.375 mole

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From the following balanced equation,

Ca(s) + C(s) + 3/2 O2(g) ⟶\(CaCO_{3}\) (s) how many moles of O2 are required to form 4.25mol CaCO3?

Answer:

hi

Explanation:

hi

Answer:

sry i don't know answer of This question

Answer:

it reacts to limestone better and is a bit more firmer and mostly preferred over because of how fast it can react towards chemicals

Answer:

ionic bond

Explanation:

The maximum required wavelength of light for which an oxygen-oxygen double bond could be broken by absorbing a single photon is 2.40 x 10⁻⁷ m = 240 nm.

A photon can be characterized by its wavelength, expressed by λ or it can also be characterized by its energy, expressed by E. The energy of a photon (E) and the wavelength of light (λ) have an inverse relationship

E = hc/λ

h is Planck's constant and c is the speed of light.

h = (6.628) (10⁻³⁴) Js

c = (2.998) (10⁸) m/s

When both are multiplied we get hc = (1.99) (10⁻²⁵) Joule m⁻¹

We have,

The photon energy = 498 /kJ mol ⇒ (8.27) (10⁻¹⁹) J

So,

E = hc/λ

(8.27) (10⁻¹⁹) = (1.99) (10⁻²⁵)/λ

λ = 2.40 x 10⁻⁷ m

= 240 nm.

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Answer:

53.18 grams of H₂SO₄ are needed to react with 78.86 grams of Al(NO₃)₃.

Explanation:

The balanced reaction between Al(NO₃)₃ and H₂SO₄ is:

2 Al(NO₃)₃ + 3 H₂SO₄ → Al₂(SO₄)₃ + 6 HNO₃

By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of reagents are required:

Being the molar mass of the elements:

then the molar mass of the reactants are:

Then, by reaction stoichiometry, the following reagent mass amounts are required:

Then you can apply the following rule of three:  If by stoichiometry 436 g of Al(NO₃)₃ react with 294 g of H₂SO₄, 78.86 g of Al(NO₃)₃ with how much mass of H₂SO₄ will it react?

\(mass of H_{2} SO_{4} =\frac{78.86 grams of Al(NO_{3} )_{3}*294gramsofH_{2} SO_{4} }{436 grams of Al(NO_{3} )_{3}}\)

mass of H₂SO₄=53.18 g

53.18 grams of H₂SO₄ are needed to react with 78.86 grams of Al(NO₃)₃.

The correct answer to the question is c. Insolubility in concentrated sulfuric acid is an aid to the definite identification of anthracitic pigment.

To identify anthracotic pigment, a sample is typically treated with concentrated sulfuric acid. This is because anthracotic pigment is insoluble in concentrated sulfuric acid, while other pigments are soluble.

Therefore, if a sample is treated with concentrated sulfuric acid and anthracotic pigment remains, it can be definitively identified as anthracitic pigment.

It is important to note that while the insolubility of anthracitic pigment in concentrated sulfuric acid is an aid to its identification, it should not be the only method used to identify the pigment.

Other methods, such as microscopy and histochemical staining, may also be necessary for definitive identification.

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Given the symbol Cl-37, the element is Cl, but there is no information about its charge. When this is like that, it is implicit it is an atom, that is, it is neutral, its charge is 0.

The number indicates is the mass number, so its mass is 37.

So, mass is 37 and charge is 0.

A - 3

B - 4

C - 1

D - 5

E - 2

(hope this helps ^^)

Answer:

Ya I kinda just new, answers I feel Mede it easier to.

Connecting a zinc rod to an iron pipe offers advantages in protecting the iron surface from corrosion. The zinc acts as a sacrificial anode, corroding in place of the iron and providing uniform and extended protection to the entire iron pipe.

Connecting a zinc rod to an iron pipe is advantageous to protect the iron (Fe) surface from undergoing corrosion. This process is known as cathodic protection, where the zinc acts as a sacrificial anode. Here's the justification for this answer:

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Radioactive dating measures the ratio of C¹²(normal) and C¹⁴ (radioactive) in fossils to determine the exact age of the specimen. C¹⁴ is unstable and has a half life of 5730 years.

The organism ages the amount of C¹⁴ diminishes but the amount of C¹² remains constant. The ratio of C¹⁴ to C¹² is used to analyze the decay of atomic particles to determine exact age.

Relative dating uses rock layers and index fossils to determine an object's estimated age. Relative dating is a method of dating archaeological structures or discoveries based on how they are temporally or formally compared to others. This is in contrast to absolute dating, where the material itself dates.

Therefore, Relative dating can be done by stratigraphic dating, typology or climatic dating.

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Answer:7

Explanation:

Answer:

its c

Explanation:

Charge flowed : 240 Coulombs

Given

t = time = 60 s

I = current = 4 A

Required

Charge

Solution

General formula :

Q = I x t

Q = charge (electricity), C

Input the value :

Q = 4 x 60

Q = 240 Coulombs

Answer:

It Is Transitional Energy.

Explanation: I Took The Quiz And Got It Wrong. It Showed That Transitional Energy Was The Correct Answer.

Answer:

heat energy

Explanation:

L1 and L2 can be separated by the process of fractional distillation and L2 and L4 can be separated by the process of separation.

The method for separating crude oil into clusters of hydrocarbons with similar numbers of carbon molecules is known as fractional distillation. These groups of hydrocarbons are referred to as "fractions." Hydrocarbons with short chains. Short-chain hydrocarbons are hydrocarbons with few carbon atoms.

Fractional distillation is used to purify water as well as separate ethanol and water. Fractional distillation is used in many industries, including oil refineries and chemical plants, to purify and separate many organic compounds.

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I understand the question you are looking for :

1. The table below shows liquids that are miscible and those that are immiscible

Liquid L3 L4

L1 Miscible Miscible

L2 Miscible Immiscible

Use the information given in the table to answer that questions that follow;

i) Name the method that can be used to separate L1 and L2 from a mixture of the two

ii) Describe how a mixture of L2 and L4 can be separated

Answer:

inhibits glycolysis

Explanation:

In a specimen collected for plasma glucose analysis, sodium fluoride is commonly used as a preservative and inhibitor of glycolysis.

Sodium fluoride prevents the breakdown of glucose in the sample, thereby stabilizing the glucose concentration and preventing falsely low results. This is particularly important for samples that will be analyzed for glucose over a period of time. By inhibiting glycolysis, sodium fluoride can help ensure accurate and reliable glucose measurements in clinical settings.

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Answer: Crystallization is a technique which chemists use to purify solid compounds. Crystals often form in nature when liquids cool and start to harden. Certain molecules in the liquid gather together as they attempt to become stable. They do this in a uniform and repeating pattern that forms the crystal. The process is based on the principles of solubility: compounds (solutes) tend to be more soluble in hot liquids (solvents) than they are in cold liquids. If a saturated hot solution is allowed to cool, the solute is no longer soluble in the solvent and forms crystals of pure compound. Impurities are excluded from the growing crystals and the pure solid crystals can be separated from the dissolved impurities by filtration.
For an example the salt we get from seawater can have many impurities in it. Hence, the process of crystallization is in use to remove these impurities.

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   hope it helped
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As the solution cools, the solvent can no longer hold all of the solute molecules, and they begin to leave the solution and form solid crystals.

During this cooling, each solute molecule in turn approaches a growing crystal and rests on the crystal surface.

Hope this helps!!

>Rijja<

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Would be well appreciated :)

These three options are correct for assisting crystal formation- 1. Scrape the inside of the Erlenmeyer flask with a glass rod below the surface of the solvent. 2. Nucleate the crystals with a scrap of paper. 3. Include some crystals of the compound being crystallized.

Crystallization is the process by which a solid material forms a structured arrangement of its particles, producing a highly ordered and frequently repeating pattern. The formation of solid crystals such as salt, sugar, and diamonds exemplifies this. When the molecules of a solid tend to organize themselves into a more ordered pattern, this is referred to as crystallization.

Seeding is the process of adding a scrap of paper to nucleate the crystals. Seeding entails placing a small crystal in a container of supersaturated solution, which serves as a nucleus for other crystals to form around. This process accelerates crystal growth and can be used to produce larger, more consistent crystals. It can also be used to make crystals of various shapes and sizes. The addition of a scrap of paper causes the solution to form around it, promoting crystal formation.

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Mass of water = 8.84 g

Heat can be calculated using the formula:  

Q = mc∆T  

Q = heat, J  

m = mass, g  

c = specific heat, joules / g ° C  

∆T = temperature difference, ° C / K  

c of water = 4.182 J / g ° C  

Q = 925 J

mass of water :

\(\tt Q=m.c.\Delta T\\\\925=m\times 4.182\times (40-15)\\\\m=8.84~g\)

Answer:

White dwarfs are the smallest type stars, with a similar size to earth, and with extreme mass. Brown Dwarf. Brown dwarfs are strange altogether.

Explanation:

Answer:

D

Explanation:

Answer:

the answer is D I did that one in 5th grade

Waves are rhythmic disturbances that carry energy through matter or space without transferring matter,

Waves are disturbance that occur in a medium that tranfers energy as it is being propageated but wihout a pearmament displacement of the partcle of the medium.

There are two main types of waves, namely:

Mechanical waves - these are waves that require a materila medium for their propagation. For example, soud waves and water waves.

Electromagnetic waves - these are waved that  do not require a metarial medium for their propagetion. For example, light waves and radio waves.

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Answer:

The rule states that electron occupy each orbital singly first before pairing takes place in a degenerate orbital. These implies that the most stable arrangement of electrons in subsheells is the one with the greatest number of parallel spin

The chemical formula for the compounds in the photo are:

Na₃N

Al₂O₃

AlCl₃

MgO

Chemical formulas are symbols and numbers used to represent the types and numbers of atoms of elements that make up a compound.

The chemical formula for a compound is determined by the type and number of atoms in the molecule.

For example, the chemical formula for water is H₂O, which indicates that it contains two hydrogen atoms (H) and one oxygen atom (O).

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The temperature of CO₂ at an initial volume of 201 mL is approximately 327.44 K.

According to Charles's Law, which states that the volume of a gas is directly proportional to its temperature at constant pressure, we can use the equation V₁/T₁ = V₂/T₂ to solve for the initial temperature, T₁.

V₁ = 201 mL, V₂ = 651 mL, and T₂ = 399 K, we can solve for T₁.

(201 mL) / T₁ = (651 mL) / (399 K)

T₁ = (651 mL) × (201 mL) / (399 K)

T₁ ≈ 327.44 K

The Temperature is approx 327.44 K.

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According to Boyle's law which is a law for constant temperature the  the total equilibrium pressure of the system if the volume of the reaction vessel is reduced to 1.0 l  is 2.4 atmospheres.

Boyle's law is an experimental gas law which describes how the pressure of the gas decreases as the volume increases. It's statement can be stated as, the absolute pressure which is exerted by a given mass of an ideal gas is inversely proportional to its volume provided temperature and amount of gas remains unchanged.

Mathematically, it can be stated as,

P∝1/V or PV=K. The equation states that the product of of pressure and volume is constant for a given mass of gas and the equation holds true as long as temperature is maintained constant.

According to the equation the unknown pressure and volume of any one gas can be determined if two gases are to be considered.That is,

P₁V₁=P₂V₂

Substitution in above equation gives P₂=1.2×2/1=2.4 atmospheres.

Hence, the total equilibrium pressure of the system if the volume of the reaction vessel is reduced to 1.0 l  is 2.4 atmospheres.

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1.) Formulas of all the cations are Li+ , Mg2+, Al3+.

2.) Formulas of all the anions are N3-, O2-, P3-.

3.) Formulas of all the compounds are Li3N, MgO, AlP.

The given electron configurations and the respective cations and anions that form are:

Electron Configurations Cation Anion1s22s1      

Li+           1s22s22p6        

N3-1s22s22p4    

Mg2+          1s22s22p6        

O2-1s22s22p6    

Al3+          1s22s22p6        

P3-Using the cations and anions formed by each electron configuration, the formulas of the compounds that are formed are:

Li3N for the electron configuration of 1s22s1MgO for the electron configuration of 1s22s22p4

AlP for the electron configuration of 1s22s22p6

The names of the compounds formed by the respective electron configurations are: Lithium nitride for the compound Li3N

Magnesium oxide for the compound MgO

Aluminium phosphide for the compound AlP.

1.) Formulas of all the cations are Li+ , Mg2+, Al3+.

2.) Formulas of all the anions are N3-, O2-, P3-.

3.) Formulas of all the compounds are Li3N, MgO, AlP.

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