Clara and Miles each improved their yards by planting

roses and daisies. They bought their supplies from the

same store. Clara spent $120 on 6 rose bushes and

8 pots of daises. Miles spent $116 on 10 rose bushes

and 4 pots of daisies. What is the cost of one rose

bush and the cost of one pot of daisies?

Answer:

Step-by-step explanation:

Sure! I'll perform the mathematical operations using the given numbers and apply the rules of precision. Please find the results below:

(9.11) + (6.232)

The sum of 9.11 and 6.232 is 15.342.

(7.4023) x (19)

The product of 7.4023 and 19 is 140.844.

(9.162) - (2.39)

The difference between 9.162 and 2.39 is 6.772.

(0.00482) x (213)

The product of 0.00482 and 213 is 1.02786.

(8.73) / (5.198)

The division of 8.73 by 5.198 is 1.67920734.

(7644) / (0.13)

The division of 7644 by 0.13 is 58,800.

Please note that the results are rounded to the appropriate number of decimal places based on the precision rules.

Answer:

tan2(x) + 1 = sin2(x)/cos2(x) + 1 = [sin2(x) + cos2(x)]/cos2(x) = 1/cos2(x) = (1/cos(x))2 = sec2(x). Thus tan2(x) + 1 = sec2(x).

Step-by-step explanation:

Answer: Not an identity

Step-by-step explanation:

The line integral is zero.

To use Green's Theorem, we need to calculate the curl of the vector field \(F(x, y) = (2y - e^{(n*)})i + 9aj\). The curl of a vector field F = (P, Q) is given by the formula:

curl(F) = (∂Q/∂x - ∂P/∂y)k,

where k is the unit vector in the z-direction.

Let's calculate the curl of F(x, y):

\(P = 2y - e^{(n*)}\)

Q = 9a

∂Q/∂x = 0 (since Q does not depend on x)

∂P/∂y = 2

Therefore, the curl of F is:

curl(F) = (∂Q/∂x - ∂P/∂y)k = -2k.

Now, we can apply Green's Theorem. Green's Theorem states that for a vector field F = (P, Q) and a curve C equipped with the counterclockwise orientation,

∫ C F.dr = ∬ R curl(F).n dA,

where n is the unit outward normal vector to the region R enclosed by the curve C.

In this case, the curve C is the boundary of a 5 x 3 rectangle in the sy-plane, equipped with the counterclockwise orientation. The region R is the entire rectangular region.

Since the curl of F is -2k, the dot product of curl(F) with the outward normal vector n will be zero, as k is perpendicular to n.

Therefore, ∬ R curl(F).n dA = 0, and as a result:

∫ C F.dr = 0.

Hence, the value of the line integral ∫ C F.dr using Green's Theorem is zero.

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Answer:

f = 560

Step-by-step explanation:

reduce the fraction with 3

\(\frac{f}{791}\) = \(\frac{80}{113}\)

simplify the equation using cross-multiplication

113 f = 63280

divide both sides of the equation by 113

f = 560

and your answer is

f = 560

The vector space that has exactly one basis is the trivial vector space, which is the vector space containing only the zero vector.

A basis for a vector space is a set of linearly independent vectors that span the entire space. In a non-trivial vector space (a space that contains more than just the zero vector), there are infinitely many possible bases. This is because any set of linearly independent vectors that span the space can be used as a basis.

However, in the trivial vector space, there is only one vector (the zero vector), and it is linearly independent of itself. Therefore, the trivial vector space has exactly one basis, which is the set containing only the zero vector. Any other set of vectors in the trivial vector space is linearly dependent, and therefore cannot be used as a basis.

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Answer:

70.3068

explanation:

divide the mass value by 2.205

Answer:

69.75 kg

Step-by-step explanation:

1:0.45

155:x

x=155×0.45

x=69.75 kg

Tina and Carl will use 6 and 12 ounces of clay, respectively. Tina uses 3/10 of the 20-ounce bucket and Carl uses 3/5 of the 20-ounce bucket.

To determine how much clay Tina and Carl will use, we need to first find the total amount of clay they will use together.

If 3/10 of the clay is used by Tina and 3/5 of the clay is used by Carl, we can find the total amount of clay used by adding these fractions:

3/10 + 3/5 = (3/10 * 1/2) + (3/5 * 1/2) (we multiply by 1/2 to find the common denominator of 10)

= 3/20 + 6/20

= 9/20

Therefore, Tina and Carl will use a total of 9/20 of the 20-ounce bucket of clay.

To find how much each of them will use, we can multiply the total amount of clay by each person's fraction:

Tina: (3/10) x 20 ounces = 6 ounces

Carl: (3/5) x 20 ounces = 12 ounces

Therefore, Tina will use 6 ounces of clay, while Carl will use 12 ounces of clay.

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Tina and carl share a 20 ounce bucket of clay 3/10 and 3/5, how much of the clay each of them will use?

Answer:

Simply y= Mx + c

M = -5/4

x = -8

y = 1

1 = 10 + c

c = -9

Step-by-step explanation:

Answer:

327

Step-by-step explanation:

Calculation for How large of a sample would be required in order to estimate the mean per capita income

First step is to find z 80% confidence level

At 80% confidence level the z will be:

α/2 = 1 - 80% = 1 - 0.80 = 0.20

α/2= 0.20 / 2 = 0.01

Zα/2= Z0.01= 1.28 from z table

Now let calculate the Sample size using this formula

Sample size = n= [( Zα/2* σ ) / E]^2

Let plug in the formula

n = (1.28*7.9/0.56)^2

n= 326.06

n=327 (Approximately)

Therefore How large of a sample would be required in order to estimate the mean per capita income will be 327

Point A is located at (5,4)

To reflect over the y axis, we flip the sign of the x coordinate while keeping the y coordinate the same. The rule is \((x,y) \to (-x,y)\)

So we will have \((5,4) \to (-5,4)\) as the location of A'

MyCLSS is an electronic tool designed for land administrators to facilitate the approval process of survey plans. It offers various functionalities and user-friendliness to streamline the tasks involved in land administration. The correct answer is option A).

To gain access to MyCLSS, administrators need to contact the Surveyor General's Branch (SGB) and obtain the necessary login information. This ensures that only authorized individuals can utilize the tool and carry out the approval process.

The upcoming version, MyCLSS 2.0, is expected to introduce additional features and improvements to enhance its functionality and user experience. The new interface will also cater to the needs of surveyors, setting the groundwork for their involvement in the survey plan process.

Therefore, the correct answer is A) MyCLSS provides an electronic tool for land administrators to carry out the approval process of survey plans. Administrators should contact the SGB to obtain access information.

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(a) The probability that a randomly selected bag contains between 1000 and 1400 chocolate chips inclusive is 0.9192.

(b) The probability that a randomly selected bag contains fewer than 1050 chocolate chips is 0.1064.

(c) The proportion of bags that contain more than 1225 chocolate chips is 0.4013.

(d) The percentile rank of a bag that contains 1450 chocolate chips is approximately 97.72%.

The number of chocolate chips in an 18-ounce bag of chocolate chip cookies is approximately normally distributed with a mean of 1252 chips and a standard deviation of 129 chips.

(a) To find the probability that a randomly selected bag contains between 1000 and 1400 chocolate chips inclusive, calculate the z-scores for 1000 and 1400. The z-score for 1000 is

(1000-1252)/129 = -1.95

and the z-score for 1400 is

(1400-1252)/129 = 1.15.

Using a standard normal distribution table, find that the probability of a z-score being between -1.95 and 1.15 is approximately 0.9192.

(b) To find the probability that a randomly selected bag contains fewer than 1050 chocolate chips, calculate the z-score for 1050. The z-score for 1050 is

(1050-1252)/129 = -1.57.

Using a standard normal distribution table, find that the probability of a z-score being less than -1.57 is approximately 0.1064.

(c) To find the proportion of bags that contain more than 1225 chocolate chips, calculate the z-score for 1225. The z-score for 1225 is

(1225-1252)/129 = -0.21.

Using a standard normal distribution table, find that the probability of a z-score being greater than -0.21 is approximately 0.4013.

(d) To find the percentile rank of a bag that contains 1450 chocolate chips, calculate the z-score for 1450. The z-score for 1450 is

(1450-1252)/129 = 1.53.

Using a standard normal distribution table, find that the probability of a z-score being less than or equal to 1.53 is approximately 0.9772 or 97.72%.

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Answer:

0

Step-by-step explanation:

Jordan hasn't got enough money to buy any books, as $11.40<$280.

Given that A X+1 + Bx+C x2²+5Let us perform partial decomposition of the given expression as follows:=> A X+1 + Bx+C x2²+5 => A/(X+1) + B/(x+ √5) + C/(x-√5)

Now we have to solve for A,B and C.Solving for A:As we see, if we substitute x= -1 in the above equation we get a finite value, so it must be equal to 0.So, A/(-1 + 1) + B/(-1+ √5) + C/(-1-√5) = 0=> B/(-1+ √5) + C/(-1-√5) = 0 (On simplifying)=> C/(-1-√5) = - B/(-1+ √5)Solving for C:We know that C/(-1-√5) = - B/(-1+ √5).Now substituting the value of B in terms of C we get,C/(-1-√5) = C(-1+ √5)Solving for C,=> C = -2/√5Solving for B:We know that B/(-1+ √5) = -C/(-1-√5).

Now substituting the value of C in terms of B we get,=> B/(-1+ √5) = 2/√5Solving for B we get,=> B = -2√5 + COn substituting the value of C in terms of B we get,=> B = -2√5 - 2/√5Now we have found the value of all the constants A,B and C.Hence, A = 2/√5, B = -2√5 - 2/√5 and C = -2/√5

Partial fraction decomposition is an important concept in mathematics. Here, we performed partial decomposition of the given expression. We simplified the given equation by substituting the values of A, B, and C and found that A = 2/√5, B = -2√5 - 2/√5, and C = -2/√5. Therefore, this is the final solution.

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The simplification of the equation by substituting the values of A, B, and C and found that A = 2/√5, B = -2√5 - 2/√5, and C = -2/√5. Therefore, this is the final solution.

We are Given that A X+1 + Bx+C x2²+5

To perform partial decomposition of the given expression

A X+1 + Bx+C x2²+5

A/(X+1) + B/(x+ √5) + C/(x-√5)

Now we have to solve for A,B and C.

Here if we substitute x= -1 in the above equation we get a finite value, so it must be 0.

Thus, A/(-1 + 1) + B/(-1+ √5) + C/(-1-√5) = 0

B/(-1+ √5) + C/(-1-√5) = 0

(On simplifying)

C/(-1-√5) = - B/(-1+ √5)

Now Solving for C:

We know that C/(-1-√5) = - B/(-1+ √5).

Now substituting the value of B in terms of C we get;

C/(-1-√5) = C(-1+ √5)

C = -2/√5

For Solving for B:

We know that B/(-1+ √5) = -C/(-1-√5).

B/(-1+ √5) = 2/√5

B = -2√5 + C

On substituting the value of C in terms of B

B = -2√5 - 2/√5

Hence, A = 2/√5, B = -2√5 - 2/√5 and C = -2/√5

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Answer:

The degree of the term is 5

Don't forget to mark me as brainliest

Answer:

6845.86

Step-by-step explanation:

Answer:

Their ages are 38,39 and 40.

Step by step explanation:

If they were all the same age, then their ages would be:

But, they are consecutive integers. So, you can make Elsa 40 and Edna 38.

Answer:

The current temperature = 34.2°C

Step-by-step explanation:

Initial temperature = 46.8°C

After 20 minutes temperature reduced by 12.6°C

Therefore, the current temperature is = 46.8°C - 12.6°C = 34.2°C

Four two-digit numbers are constructed from numbers 1, 2, 3, ..., 8. The largest number of  primes that could possibly formed among those four numbers is 3 numbers.

A prime number is a whole number greater than 1 which only divisible by 1 and itself. Example of prime numbers are 2, 3, 5, 7, ...

We want to form 4 two-digit numbers from, 1, 2, 3, 4, 5, 6, 7, 8.

Recall that: other than 2, all even numbers are not prime since they are divisible by 2. Hence, from those numbers, we look at which odd two-digit numbers are prime.

We have four odd numbers in the list that can construct two-digit odd numbers: 1, 3, 5, 7.

However, two-digit numbers with 5 as its second digit is not prime since they are exactly divisible by 5.

Therefore, now we only have 3 numbers (1, 3, 7) that can construct two-digit odd numbers. Hence, the largest number of primes that could possibly formed is 3 numbers.

Example, the constructed four two-digit numbers are:

47, 53, 61, 28

47, 53, and 61 are prime, while 28 is not.

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Answer:

Clay

Step-by-step explanation:

Clay soil has small, fine particles, which is why it retains the most amount of water. Sand, with its larger particles and low nutritional content, retains the least amount of water, although it is easily replenished with water. Silt and loam, with medium-size particles, retain a moderate amount of water.

The probability that the sample mean will be greater than 57.95 is 0.0495.

Probability means possibility. It is a branch of mathematics that deals with the occurrence of a random event. The value is expressed from zero to one. This is the basic probability theory, which is also used in the probability distribution.

To solve this question, we need to know the concepts of the normal probability distribution and of the central limit theorem.

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \(\mu\) and standard deviation \(\sigma\), the z-score of a measure X is given by:

\(Z=\dfrac{X-\mu}{\sigma}\)

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

The Central Limit Theorem establishes that, for a random variable X, with mean \(\mu\) and standard deviation \(\sigma\), a large sample size can be approximated to a normal distribution with mean \(\mu\) and standard deviation \(\frac{\sigma}{\sqrt{\text{n}} }\).

In this problem, we have that:

The probability that the sample mean will be greater than 57.95

This is 1 subtracted by the p-value of Z when X = 57.95. So

\(Z=\dfrac{X-\mu}{\sigma}\)

By the Central Limit Theorem

\(Z=\dfrac{X-\mu}{\text{s}}\)

\(Z=\dfrac{57.95-53}{3}\)

\(Z=1.65\)

\(Z=1.65\) has a p-value of 0.9505.

Therefore, the probability that the sample mean will be greater than 57.95 is 1-0.9505 = 0.0495

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x is present in the algebraic expression, therefore, option A is correct.- x is present in the expression, therefore, option B is correct.- x + y is present in the expression, therefore, option D is correct.

The given expression is: 3x[3(x + y)]^3x[3(x + y)]^3 × (x + 3)(x + y)

To simplify the given expression, we will first solve the expression within the brackets as follows:

(3(x + y))^3 = (3)³(x + y)³ = 27(x + y)³

Now, we will substitute the above value in the expression:

3x[3(x + y)]^3 = 3

x × 27(x + y)³ = 81x(x + y)³

Multiplying both terms of (x + 3)(x + y), we get:

(x + 3)(x + y)

= x(x + y) + 3(x + y) + 3y

= x² + xy + 3x + 3y + yx + 3y

= x² + 4xy + 6y + 3x

The final expression after substituting the value of 3x[3(x + y)]^3 and (x + 3)(x + y) is:

81x(x + y)³ × (x² + 4xy + 6y + 3x)

= 81x(x + y)³x² + 81xy(x + y) + 6xy + 27x(x + y)

= 81x³ + 189xy² + 81x²y + 6xy + 27x² + 81xy

Now, let's check which options are correct:- 3x is present in the expression, therefore, option A is correct.- x is present in the expression, therefore, option B is correct.- x + y is present in the expression, therefore, option D is correct.

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Answer:

I would venture to say that puts the first option. I may be wrong but I'd doubt it.

Number line going from 0 to 6.5 in increments of 0.5. An arrow goes from 0 to 1.5 and from 1.5 to 4.

A number system is defined as a system of writing to express numbers.

A number line is a picture of a graduated straight line that serves as visual representation of the real numbers.

We need to find which number line represents 1.5 + 2.5

When we add 1.5 + 2.5

One point five plus two point five

4.

So number line going from 0 to 6.5 in increments of 0.5. An arrow goes from 0 to 1.5 and from 1.5 to 4.

Hence, number line going from 0 to 6.5 in increments of 0.5. An arrow goes from 0 to 1.5 and from 1.5 to 4.

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Answer:

C, A and B

Step-by-step explanation:

Tank A holds 40 Liters and 5 fish.

Tank B holds 100 Liters and 12 fish.

Tank C holds 180 Liters and 23 fish.

Therefore, the volume per fish from least to greatest is:

7.83, 8 and 8.33

These correspond to the tanks: C, A and B respectively.

Answer:

CAB

Step-by-step explanation:

Got it right in Khan!

Answer:

C.15.5r

Step-by-step explanation:

Answer:

13.5r

Step-by-step explanation:

Just took it

Catherine rolls a standard 6-sided die five times, and the product of her rolls is 300. The task is to determine the number of different sequences of rolls that could have resulted in this product.

To find the number of different sequences of rolls that could result in a product of 300, we need to consider the prime factorization of 300. The prime factorization of 300 is 2^2 * 3 * 5^2. Now, let's break down the problem into cases based on the number of factors of each prime number in the factorization.

1. Number of 2s: Since the prime factorization of 300 contains 2^2, there must be either 0, 1, or 2 rolls that resulted in a 2. This gives us three possibilities.

2. Number of 3s: The prime factorization contains 3^1, so there must be either 0 or 1 roll that resulted in a 3. This gives us two possibilities.

3. Number of 5s: The prime factorization contains 5^2, so there must be either 0, 1, or 2 rolls that resulted in a 5. This gives us three possibilities.

By multiplying the possibilities for each prime factor together (3 * 2 * 3), we find that there are 18 different sequences of rolls that could have resulted in a product of 300.

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The row of the table that reveals the x-intercept of the function f is given as follows:

Second row.

A function has two intercepts, which are listed as follows:

The definition of each type of intercept is given as follows:

From the second row of the table, we have that when x = -4, f(x) = 0, hence the x-intercept of the function is of x = -4.

The y-intercept is of y = -16, as from the fourth row, when x = 0, y assumes a value of 16.

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