Cinco menos paréntesis menos dos paréntesis igual cinco más dos igual siete

Answer:

1.......c

2.....a

3.....b

4......e

5.....d

Because of the size of the black section,

Answer: P= -60

Step-by-step explanation:

5/6p +1=3/4p -4

5/6p=3/4p-4.       Subtract 1 from both sides

5p=9/2p-30.        Trick( if there is a fraction multiply the denominator on both sides to make it a non fraction so life is easier, as I did I first multiply by 6)

10p=9p-60.           multiply the second denominator on both sides(multiple by 2)

P=-60.                     Subtract 9p on both sides and keep the sign and you’ll get -60

The value of the integral ∫[4,-2] f(x) 8dx is -576.

If the average value of a continuous function f on the interval [−2, 4] is 12

∫ 4−2 f(x) 8 dx = 12 (4 - (-2) )

∫ 4−2 f(x) 8 dx =  72

The integral of ∫ [4,-2] f (x) 8dx is constant value

∫ [4,-2] f (x) 8 dx = 8 ∫ [4,-2] f (x) dx

we already know that ∫ [-2,4] f (x) dx = 72

The integral over the interval [4,-2] by using the property of definite integrals

∫ [a, b] f (x) dx = -∫ [b, a] f (x) dx

∫ [4,-2] f (x) dx = -∫ [-2,4] f (x) dx = -72

Putting value back into the original expression, we get:

∫ [4,-2] f (x) 8dx = 8 ∫ [4,-2] f (x) dx = 8(-72) = -576

The value of the integral ∫ [4,-2] f (x) 8dx is -576.

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i think it is 1/5

Hope this helped :T

Answer:

2 2/3 is what I have

Step-by-step explanation:

5/3÷5/8

=2 2/3

Answer:

Step-by-step explanation:

A real number is called a zero of the polynomial f (x), if ​the polynomial results in zero when that number is plugged into the function

Answer:

A

Step-by-step explanation:

Answer:

Step-by-step explanation:

Hi there... I understood your "2" as a typo and considering it as x.

       -(x - 3y = 5)

       -x + 3y = -5

Hence, the resulting equation is '4y = 2'

Hoped this helped.

\(BrainiacUser1357\)

Answer:

Step-by-step explanation:

It seems a typo:

Subtract to eliminate x and solve for y:

Now you can find the value of x:

Answer:

Step-by-step explanation:

m∠A = arctan \(\frac{9.6}{7.2}\) ≈ 53°  

Given statement solution is :- a) Power set for two sets A and B with any 2 elements:

Set A: {1, 2}, Set B: {3, 4}

Power set of A: {{}, {1}, {2}, {1, 2}}

Power set of B: {{}, {3}, {4}, {3, 4}}

b) Power set for two sets A and B with any 3 elements:

Set A: {1, 2, 3}, Set B: {4, 5, 6}

Power set of A: {{}, {1}, {2}, {3}, {1, 2}, {1, 3}, {2, 3}, {1, 2, 3}}

Power set of B: {{}, {4}, {5}, {6}, {4, 5}, {4, 6}, {5, 6}, {4, 5, 6}}

c) Power set for two sets A and B with any 4 elements:

Set A: {1, 2, 3, 4}, Set B: {5, 6, 7, 8}

Power set of A: {{}, {1}, {2}, {3}, {4}, {1, 2}, {1, 3}, {1, 4}, {2, 3}, {2, 4}, {3, 4}, {1, 2, 3}, {1, 2, 4}, {1, 3, 4}, {2, 3, 4}, {1, 2, 3, 4}}

Power set of B: {{}, {5}, {6}, {7}, {8}, {5, 6}, {5, 7}, {5, 8}, {6, 7}, {6, 8}, {7, 8}, {5, 6, 7}, {5, 6, 8}, {5, 7, 8}, {6, 7, 8},

a) Power set for two sets A and B with any 2 elements:

Set A: {1, 2}, Set B: {3, 4}

Power set of A: {{}, {1}, {2}, {1, 2}}

Power set of B: {{}, {3}, {4}, {3, 4}}

Set A: {apple, banana}, Set B: {cat, dog}

Power set of A: {{}, {apple}, {banana}, {apple, banana}}

Power set of B: {{}, {cat}, {dog}, {cat, dog}}

Set A: {red, blue}, Set B: {circle, square}

Power set of A: {{}, {red}, {blue}, {red, blue}}

Power set of B: {{}, {circle}, {square}, {circle, square}}

b) Power set for two sets A and B with any 3 elements:

Set A: {1, 2, 3}, Set B: {4, 5, 6}

Power set of A: {{}, {1}, {2}, {3}, {1, 2}, {1, 3}, {2, 3}, {1, 2, 3}}

Power set of B: {{}, {4}, {5}, {6}, {4, 5}, {4, 6}, {5, 6}, {4, 5, 6}}

Set A: {apple, banana, orange}, Set B: {cat, dog, elephant}

Power set of A: {{}, {apple}, {banana}, {orange}, {apple, banana}, {apple, orange}, {banana, orange}, {apple, banana, orange}}

Power set of B: {{}, {cat}, {dog}, {elephant}, {cat, dog}, {cat, elephant}, {dog, elephant}, {cat, dog, elephant}}

Set A: {red, blue, green}, Set B: {circle, square, triangle}

Power set of A: {{}, {red}, {blue}, {green}, {red, blue}, {red, green}, {blue, green}, {red, blue, green}}

Power set of B: {{}, {circle}, {square}, {triangle}, {circle, square}, {circle, triangle}, {square, triangle}, {circle, square, triangle}}

c) Power set for two sets A and B with any 4 elements:

Set A: {1, 2, 3, 4}, Set B: {5, 6, 7, 8}

Power set of A: {{}, {1}, {2}, {3}, {4}, {1, 2}, {1, 3}, {1, 4}, {2, 3}, {2, 4}, {3, 4}, {1, 2, 3}, {1, 2, 4}, {1, 3, 4}, {2, 3, 4}, {1, 2, 3, 4}}

Power set of B: {{}, {5}, {6}, {7}, {8}, {5, 6}, {5, 7}, {5, 8}, {6, 7}, {6, 8}, {7, 8}, {5, 6, 7}, {5, 6, 8}, {5, 7, 8}, {6, 7, 8},

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The probability of randomly selected patient selected for coronary, oncology or both is equal to P( H∪C ) = 0.24.

Let patient admitted with heart disease represented by P(H)

P(H) = 12%

       = 0.12

And patient admitted for cancer disease represented by P(C)

P(H) = 16%

       = 0.16

Percent of patient received both coronary and oncology = 4%

P( H∩C ) = 0.04

Probability of randomly selected patient admitted for coronary, oncology or both is :

P( H∪C ) = P(H) + P(C) - P(H∩C )

⇒P( H∪C ) = 0.12 + 0.16 - 0.04

⇒ P( H∪C ) = 0.24

Therefore, the probability of randomly selected patient getting treatment for coronary, oncology or both is given by  P( H∪C ) = 0.24.

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the probability that the emergency center will receive five calls on a given day is approximately 0.156, or 15.6%.

To find the probability of receiving five calls on a given day at the emergency center, we need to use the Poisson distribution formula:

\(P(x = 5) = (e^{-4})*\frac{(4^5)}{(5!)}\)
Where:
- x = number of phone inquiries
- e = Euler's number (approximately 2.71828)

- ! = factorial (i.e. 5! = 5*4*3*2*1)

Given that the average number of phone inquiries per day is four, we can use that as our lambda (λ) value in the Poisson distribution formula, since lambda represents the mean number of events in a specific time interval:

λ = 4

Now we can substitute these values into the formula and solve:

P(x = 5) = (e^-4)*(4^5)/(5!) = (2.71828^-4)*(1024)/(120) ≈ 0.156

Therefore, the probability that the emergency center will receive five calls on a given day is approximately 0.156, or 15.6%.

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The probability that the emergency center will receive five calls on a given day is approximately 0.1755 or 17.55%.

To find the probability that the emergency center will receive five calls on a given day, given that the average number of phone inquiries per day is four, we can use the Poisson distribution formula.

Identify the average rate (λ): In this case, λ = 4 calls per day.

Identify the desired number of events (k): In this case, k = 5 calls.

Use the Poisson distribution formula: \(P(X = k) = (e^(-λ) \times (λ^k)) / k!\)

e is the base of the natural logarithm (approximately 2.71828)

λ is the average rate

k is the desired number of events

k! is the factorial of k

Plug in the values and calculate the probability:

\(P(X = 5) = (e^{(-4)} \TIMES (4^5)) / 5!\)

\(P(X = 5) = (0.0183 \times 1024) / 120\)

P(X = 5) ≈ 0.1755

So, the probability that the emergency center will receive five calls on a given day is approximately 0.1755 or 17.55%.

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Answer:

7/2

Step-by-step explanation:

Calculate the product: 15/2 - 4

Solve: 7/2

The experimenter selects a bad battery in the first two trials. The experiment stops after two trials.

The outcomes that are contained in A are as follows: Either the experimenter selects a good battery or a bad battery in the first trial. Assume that the experimenter chooses a good battery first.

If the selected battery is good, the experiment is completed. On the other hand, if the chosen battery is bad, the experimenter tries again. If a good battery is selected in the second trial, the experiment is completed.

On the other hand, if the chosen battery is bad again, the experiment is stopped. Basically, the outcomes in A are as follows: The experimenter selects a good battery in the first trial.2.

The experimenter selects a bad battery in the first trial but a good battery in the second trial.3.

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jAlright, let's take this problem step-by-step:

What is the perimeter:

 ⇒ all the side-lengths added up

    ⇒ need to find side-length using distance formula

                \(Distance_._. Formula=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\)

                         - (x₁,y₁): first point

                         - (x₂,y₂): second point

Let's solve:

           ⇒ first point: (5,7)

           ⇒ second point: (3,3)

           \(Distance =\sqrt{(3-5)^2+(3-7)^2} =\sqrt{4+16} =\sqrt{20} =4.472\)

          ⇒ first point: (5,7)

          ⇒ second point:(8,6)

           \(Distance=\sqrt{(8-5)^2+(6-7)^2} =\sqrt{9+1} =\sqrt{10}=3.162\)

          ⇒ first point: (8,6)

          ⇒ second point: (3,3)

           \(Distance = \sqrt{(3-8)^2+(3-6)^2} =\sqrt{25+9} =\sqrt{34}=5.831\)

Now let's solve for the perimeter:

  \(Perimeter = 4.472+ 3.126+ 5.831=13.429\)

Answer: 13.43 (rounded to the nearest hundredth)

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Answer:

m=3

Step-by-step explanation:

6m-2=16

6m=18

m=3

Answer:

m = 3

Step-by-step explanation:

So what times 6 minus 2 will get you 16.

That would be 3 my good sir.

Here is an equation, hope this helps.

6(3) - 2 = 16

6 x (3) - 2 = 16

18 - 2 = 16

16 = 16 .          

Hope it helps You out.

a. Point-slope form is: y - y0 = m(x - x0). Plugging in our values, we get: y - 2 = -3(x - 11). Typically we can just leave it like this, but for the sake of simplifying it down to slope-intercept form, it would be y = -3x + 35.

b. y - 2 = -3((0) - 11)

y - 2 = 33

y = 35.

c. y = -3x + 35.

Edit: Bolded the last answer.

The area of one of the bases of the hexagonal prism is approximately 7.39 units^2.

To solve this problem, we can use the formula for the volume of a hexagonal prism:

V = (3√3/2) * a^2 * h

where V is the volume, a is the length of one side of the hexagonal base, and h is the height of the prism.

We are given that the height of the prism is 4 units and the volume is 98 units^3. Plugging these values into the formula, we can solve for the length of one side of the base:

98 = (3√3/2) * a^2 * 4
a^2 = 98 / (12√3)
a ≈ 2.95

Now that we know the length of one side of the base, we can find the area of the hexagon by using the formula:

A = (3√3/2) * a^2

where A is the area of one of the bases. Plugging in the value we found for a, we get:

A = (3√3/2) * (2.95)^2
A ≈ 7.39

Therefore, the area of one of the bases of the hexagonal prism is approximately 7.39 units^2.

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The volume of a cylinder is given by the formula:

V = πr^2h

where V is the volume, r is the radius, and h is the height.

We are given that the tank has a length of 4 ft and a diameter of 1.4 ft, which means the radius is 0.7 ft. Therefore, the volume of the tank is:

V = π(0.7)^2(4) = 7.348 ft^3

We are also given that gas is poured into the tank at a rate of 2.5 ft^3 per minute. Therefore, the time it takes to fill the tank is:

t = V / r

where r is the rate of gas poured into the tank per minute.

Substituting the given values, we get:

t = 7.348 / 2.5 = 2.9392 minutes

Rounding to the nearest minute, we get:

t ≈ 3 minutes

Therefore, it takes approximately 3 minutes to fill the empty tank.

Answer:

B

Step-by-step explanation:

(b-7) is a factor of \(b^{2} -5b-14\), not the other way around

Answer: The correct answer is B. Only Ramata :)

If the actual mean is 18 ounces, there is a 0.0003 chance that the sample mean was 18.2 ounces or more.

Given that 18 ounces are what Kellogg estimates to be the typical weight of a box of Frosted Flaked. The average weight of the 30 cartons they sampled was 18.2 ounces. According to past data, the filling procedure's standard deviation is 0.32 ounces.

Let Y be a box weights random variable.

μ = 18 ounces

SD = 0.32 ounces

The sample size and mean are provided as,

Sample size (n)  = 30

Sample mean (y) = 18.2

Y then follows roughly the standard deviation N(μ = 18, SD = 0.32)

Z score appears as:

\(z = \frac{\sqrt{n}(y-u)} {SD}\)

where z is a normal standard variable having a mean of 0 and a standard deviation of 1.

Since sample size n is 30 and the standard deviation is given. y follows approximately Normal distribution

If the actual mean is 18 ounces, the likelihood that the sample mean will have been 18.2 ounces or more is given as,

\(P[Y \geq 18.2] = P [\frac{\sqrt{n(y - u)} }{SD} \geq \frac{\sqrt{30}(18.2- 18) }{0.32}\\ \\ =P [z\geq \frac{\sqrt{30}* 0.2 }{0.32}]\\ \\= P [z\geq \frac{1.0954}{0.32}]\\ \\=P [z\geq 3.4233]\\\\= 0.0003\)

Therefore, if the actual mean is 18 ounces, there is a 0.0003 chance that the sample mean was 18.2 ounces or more.

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Answer:

yes

Step-by-step explanation:

you are correct

Answer/Step-by-step explanation:

\(16-7=9\)

Therefore \(y\geq9\)

There was no picture to go off of, but this should be correct anyways!

For the given conditions expressions 1 and 2 are obtained as (10 + 16) ÷ 2 and 2/3 x 2 + 1/4 respectively.

A phrase is considered a mathematical expression if it contains at least two numbers or variables and one or more mathematical operations. Mathematicians can multiply, divide, add, or subtract. An expression is structured as follows: Number/variable, mathematical operator, and expression

It is given that the expression is,

Sandra selected 16 red flowers as well as 10 blue blooms. She then equally split the flowers into 2 bouquets.

The expression for the given condition is,

=(10 + 16) ÷ 2

If a recipe required 2/3 cup of flour. The recipe was quadrupled by Kyle. He then increased the flour by 1/4 cup to make the dough less sticky. The expression for the given condition is,

=2/3 x 2 + 1/4

Thus, the obtained expressions are (10 + 16) ÷ 2 and 2/3 x 2 + 1/4.

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Answer:

area = 35 in²

Step-by-step explanation:

The fact that statistical sampling enables an auditor to assess the adequacy of the evidence gathered gives it an edge over nonstatistical sampling.

The fact that statistical techniques of attribute sampling offer a scientific framework for designing the sample size over non-statistical approaches is one of their main advantages.

It enables an auditor to assess the risk associated with sampling and limit it to a manageable level.

These techniques would aid in determining the sample size needed to achieve an auditor's objectives and aims.

The auditor uses statistical sampling to create an effective sample, gauge the quality of the evidence collected, and assess the sample findings. Auditors are expected to collect enough relevant evidence. The quantity of the evidence is gauged by its sufficiency. It has to do with the layout and scope of the sample.

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Given that we have to find the probability of each of the following when we roll a pair of fair dice:

Probability of getting a sum of 1 = 0

Probability of getting a sum of 5= {4}/{36}=0.1111

Probability of getting a sum of 12= {1}/{36}= 0.0278

Explanation: When we roll a pair of dice, there are 36 possible outcomes or events. When we roll the dice, the number on the dice will be an integer from 1 to 6.

The following table represents the possible outcome when we roll a pair of dice.

There is only one way to obtain the sum of 1, i.e., when both dice show 1. As there is only one way, the probability is 0.

There are 4 possible ways to obtain the sum of 5. They are (1,4),(2,3),(3,2),(4,1). The probability is 4/36.

There is only one way to obtain the sum of 12, i.e., when both dice show 6. As there is only one way, the probability is 1/36.

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Answer:

  (x, y) = (-1, 5)

Step-by-step explanation:

You want to solve this system of equations by substitution.

The idea of substitution means we want to replace an expression in one equation for an equivalent expression based on the other equation.

Here, the second equation gives an expression equivalent to "y", so we can use that expression in place of y in the first equation:

  5x +2(-2x +3) = 5 . . . . . . . . (-2x+3) substitutes for y

  x +6 = 5 . . . . . . . . . . simplify

  x = -1 . . . . . . . . . subtract 6

  y = -2(-1) +3 = 5 . . . . . use the second equation to find y

The solution is (x, y) = (-1, 5).

__

Additional comment

Choosing substitution as the solution method often works well if one of the equations gives an expression for one of the variables, or if it can be solved easily for one of the variables. The "y=" equation is a good candidate for providing an expression that can be substituted for y.

Any equation that has one of the variables with a coefficient of +1 or -1 is also a good candidate for providing a substitution expression.

  4x -y = 3   ⇒   y = 4x -3 . . . . . for example

The attached graph confirms the solution above.

The symbol that represents the dependent variable in a regression equation is:

a. y

The dependent variable is the variable that is being predicted or explained by the independent variable(s) in the regression analysis. It is typically represented by the symbol "y" in the regression equation. The independent variable(s) are usually represented by the symbol "x" or other appropriate letters.

In a regression equation, the dependent variable is the variable that we are trying to predict or explain based on the independent variable(s). It is the variable whose value is influenced or determined by the independent variable(s). For example, if we are studying the relationship between income (dependent variable) and education level (independent variable), we want to understand how education level affects or predicts income. In this case, income would be represented by the symbol "y" in the regression equation, as it is the variable we are interested in explaining or predicting. The independent variable(s), such as education level, would be represented by the symbol "x".

Therefore, the correct answer is option a. y.

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