Chlorine will combine spontaneously with methane. True False

Answer:

Iron will disolve in acid. The acid eats away at the iron. :)

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A 50-mL vial of SENSORCAINE/EPINEPHRINE solution contains approximately 0.25 mg of epinephrine. This is calculated based on the concentration of 1:200,000 w/v in the solution.

To determine the amount of epinephrine (mg) in a 50-mL vial of SENSORCAINE/EPINEPHRINE solution, we need to consider the concentration of epinephrine in the solution. The solution contains 1:200,000 w/v epinephrine, which means that for every 1 part of epinephrine, there are 200,000 parts of the solution.

To calculate the amount of epinephrine in the solution, we can use the following formula:

Amount of epinephrine = Total volume of solution (mL) × Concentration of epinephrine (mg/mL)

In this case, the total volume of the solution is 50 mL, and the concentration of epinephrine is 1:200,000 w/v. To convert the concentration to mg/mL, we divide 1 mg by 200,000 mL:

Concentration of epinephrine (mg/mL) = 1 mg / 200,000 mL = 0.000005 mg/mL

Finally, we can calculate the amount of epinephrine in the 50-mL vial:

Amount of epinephrine = 50 mL × 0.000005 mg/mL = 0.00025 mg

Rounding to the nearest hundredth, the amount of epinephrine in a 50-mL vial of SENSORCAINE/EPINEPHRINE solution is 0.25 mg.

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We can use the ideal gas law to determine the number of moles of nitrogen gas present in the container:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles of gas, R is the gas constant, and T is the temperature in Kelvin.

We are given that the container is rigid, which means its volume is constant. We can also assume that nitrogen gas behaves ideally at these conditions.

Substituting the given values into the ideal gas law, we get:

n = PV/RT

where P = 1.0 atm, V = 2.5 L, T = 25°C + 273.15 = 298.15 K, and R = 0.08206 L·atm/(mol·K).

Plugging in these values:

n = (1.0 atm) x (2.5 L) / (0.08206 L·atm/(mol·K) x (298.15 K))

n = 0.102 moles

Therefore, there are approximately 0.10 moles of nitrogen gas present in the container.

Answer:

Look in explanation.

Explanation:

Mendeleev has ordered the elements based on increasing atomic mass, he has skipped some elements but assumed that they existed and managed to find the atomic mass of the "unknown" elements.

Mendeleev corrected some elements' known atomic masses and used the patterns in his table to anticipate the properties of elements he thought must exist but had yet to be discovered. To depict those unknown elements, he left blank spaces in his chart.

The periodic table is a tabular array of chemical elements organized by atomic number, beginning with hydrogen and progressing to oganesson, which has the highest atomic number.

An element's atomic number is the number of protons in the nucleus of an atom of that element.

Mendeleev adjusted the recognized atomic masses of certain elements and utilized the patterns in his chart to predict the composition of the sample he assumed must reside but that had yet to be unearthed.

He left blank spaces in his chart to represent those unknown elements.

Thus, this way, he predicted their atomic weights and chemical properties.

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The remaining concentration of the substrate after 0.8 minute is 0.74 M.

To calculate the remaining concentration in an enzyme-catalyzed reaction following zero-order kinetics, use the equation:

[substrate] = [initial substrate] - (rate constant x time)

In this case, the initial concentration of the substrate is 1.38 M, the rate constant is 0.48 M/min, and the time elapsed is 0.8 minutes. Plug these values into the equation:

Remaining concentration = 1.38 M - (0.48 M/min x 0.8 min)

Remaining concentration = 1.38 M - 0.384 M

Remaining concentration = 0.996 M, which when rounded to 2 decimal places, is 0.74 M.

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The final temperature is 280.59 degrees Celsius.

The term atmospheres (atm), defined as follows: A mercury column one millimetre high would impose a pressure of one atm, or 1.01325 x 105 Pa. millimetres of mercury (mmHg). One atmosphere of pressure is generated by a mercury column that is 760 mm high. Because pressure and force are connected, you may use the physics equation to compute one if you know the other.

P1V1/T1 = P2V2/T2

Where P1, V1, and T1 are the initial pressure, volume, and temperature, and P2, V2, and T2 are the final pressure, volume, and temperature.

Given:

Initial pressure (P1) = 1.015 atm

Initial volume (V1) = 9.00 L

Initial temperature (T1) = -211.76 °C (62.39 K)

Mass of hydrogen gas initially (m1) = 2.035 g

Additional mass of hydrogen gas added (m2) = 2.099 g

Final pressure (P2) = 20.15 atm

PV = nRT

n1 = m1/MH2 = 2.035 g / 2.016 g/mol = 1.011 mol

n2 = m1/MH2 + m2/MH2 = 2.035 g / 2.016 g/mol + 2.099 g / 2.016 g/mol = 2.059 mol

We can assume that the volume of the container is constant, so we can set V1 = V2 in the combined gas law equation:

P1/T1 = P2/T2

Solving for T2:

T2 = P2T1V1 / (P1*V2)

Substituting the values:

V2 = V1 = 9.00 L

T2 = (20.15 atm)(62.39 K)(9.00 L) / (1.015 atm)(2.059 mol)(8.314 J/(mol*K))

T2 = 553.75 K or 280.59 °C

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Question:

A container holds 2.035 grams of hydrogen gas at a pressure of 1.015 atm and a temperature of -211.76 °C. What will be the temperature in °C if an additional 2.099 grams of hydrogen gas is added to the container and the pressure increases to 20.15 atm?

Rutherford's model of atom could not explain chemical properties as it did not make any mention as to how chemical changes take place.

These properties are defined as those properties which become evident during or after a chemical reaction after the identity of the substance is changed during chemical reaction.

These properties cannot be determined externally just by viewing the substance ,these change immensely after a substance undergoes a chemical change.These are used for identification of unknown substances and for building up chemical classifications.

The major chemical properties are flammability,toxicity,reactivity,acidity and heat of combustion.For a chemical property to be apparent , it is necessary that the structure of the substance is altered.

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Answer: Nuclear fusion is a nuclear reaction where atomic nuclei of a low atomic number fuse to form a heavier nucleus releasing energy.

Explanation:

The atomic ratio of carbon to oxygen in carbon monoxide (CO) is 1:1, and the atomic ratio of carbon to oxygen in carbon dioxide (CO₂) is 2:1.

Firstly, we can analyze the decomposition of carbon monoxide (CO) and carbon dioxide (CO₂) to determine the atomic ratios involved.

Let's denote the atomic ratio of carbon to oxygen in carbon monoxide as x, and the atomic ratio of carbon to oxygen in carbon dioxide as y.

According to the given data;

Decomposition of carbon monoxide (CO);

Oxygen produced = 3.36 g

Carbon produced = 2.52 g

We know that the atomic mass of carbon is 12 g/mol, and the atomic mass of oxygen is 16 g/mol. Using these values, we can calculate the number of moles for each element;

Number of moles of oxygen = mass / atomic mass = 3.36 g / 16 g/mol = 0.21 mol

Number of moles of carbon = mass / atomic mass = 2.52 g / 12 g/mol = 0.21 mol

Since the atomic ratio of carbon to oxygen in carbon monoxide is x, we can write the following equation;

0.21 mol C / (0.21 mol O) = x

Simplifying the equation, we have;

x = 1

Therefore, the atomic ratio of carbon to oxygen in carbon monoxide is 1:1.

Decomposition of carbon dioxide (CO₂);

Oxygen produced = 9.92 g

Carbon produced = 3.72 g

Following the same calculations as before;

Number of moles of oxygen = mass / atomic mass = 9.92 g / 16 g/mol = 0.62 mol

Number of moles of carbon = mass / atomic mass = 3.72 g / 12 g/mol = 0.31 mol

Since the atomic ratio of carbon to oxygen in carbon dioxide is y, we can write the following equation;

0.31 mol C / (0.62 mol O) = y

Simplifying the equation, we have;

y = 0.5

Therefore, the atomic ratio of carbon to oxygen in carbon dioxide is 1:0.5, which can be simplified to 2:1.

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--The given question is incomplete, the complete question is

"Missed this? watch kcv: atomic theory; read section 2.3. you can click on the review link to access the section in your text. carbon and oxygen form both carbon monoxide and carbon dioxide. when samples of these are decomposed, the carbon monoxide produces 3.36 g of oxygen and 2.52 g of carbon, while the carbon dioxide produces 9.92 g of oxygen and 3.72 g of carbon. Calculate the atomic ratio of carbon to oxygen in carbon monoxide, and carbon dioxide."--

Answer:

In this reaction, nitrogen acts as the oxidizing agent. Mg is a reducing agent.

Answer:

4.2 moles of Ar

Explanation:

Given data:

Number of moles of Ar = ?

Number of atoms of Ar = 2.53 × 10²⁴

Solution:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.  The number 6.022 × 10²³ is called Avogadro number.

1 mole = 6.022 × 10²³ atoms

2.53 × 10²⁴  atoms ×  1 mole  / 6.022 × 10²³ atoms

0.42 × 10¹ mole

4.2 moles

Answer:

Hi, There! Your Answer Is Below.

A. gloves

Explanation:

Personal protective equipment, commonly referred to as “PPE”, is equipment worn to minimize exposure to a variety of hazards. Examples of PPE include such items as gloves, foot and eye protection, protective hearing devices (earplugs, muffs) hard hats, respirators and full body suits. Understand the types of PPE.

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Safety equipment provides personal protection in a laboratory and includes gloves, safety goggles, aprons, etc. A fire blanket is not often required in labs. Thus, option C is correct.

Safety equipment is defined as the material used in laboratories to provide protection against reactive dangerous chemicals, gases, spills, radiological emissions, and other hazardous events.

Gloves, eyewear, aprons, lab coats, safety goggles, first aid kits, and fire extinguishers are the most important personal safety protection equipment. They are used so to avoid any chemical spills on the skin, eye irritation, etc.

Fire blankets are not generally used as safety equipment in laboratories though they are used in fire emergencies to put the fire out on a person or an object by cutting down the supply of oxygen.

Therefore, option C. a fire blanket is not used for personal protection.

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Answer: C

Explanation:its on unit test

Answer:

C is  the correct answer

Explanation:

\(W = \displaystyle \int dW = \displaystyle \int^{V_2}_{V_1} p ~dV = p(V_2 - V_1) = p \Delta V\)

The compound that has been capable to shift the equilibrium with common ion effect has been  \(\rm \bold{Na_2CO_3}\).  Thus, option D is correct.

The complete equation for the decomposition of calcium carbonate has been:

\(\rm CaCO_3\rightleftharpoons Ca^2^+\;+\;CO_3^2^-\)

The equilibrium has been the state in the reaction, when the number of products and has been equivalent to the number of reactants. The increase or decrease in the concentration of any of the reactant or product results in the shift in the equilibrium.

For the given reaction, the addition of Calcium or carbonate ions to the solution results in the increase in the product concentration with the common ion effect, and thereby shifts the equilibrium condition.

The ions liberated by the following compounds has been:

\(\rm CCl_4\;=\text{not dissolved}\\CO_2\;+\;H_2O\leftrightharpoons CO_3^-\;+\;H^+\\CuSO_4\leftrightharpoons Cu^2^+\;+\;SO_4^2^-\\Na_2CO_3\leftrightharpoons 2\;Na^+\;+\;CO_3^-\)

The compound, that has been capable of liberating the carbonate ions in the medium has been \(\rm \bold{Na_2CO_3}\). Thus, it results in the shift of the equilibrium due to common ion effect. Hence, option D is correct.

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The rate constant for a reaction at 55.0°C with activation energy of 84.0 kJ/mol and frequency factor of 7.83×10¹¹ s⁻¹ is 3.50×10¹⁰ s⁻¹ .

The Arrhenius equation relates the rate constant (k) of a chemical reaction to its activation energy (Ea), temperature (T), and frequency factor (A):

k = A x exp(-Ea/RT)

where R is the gas constant.

We are given:

Activation energy (Ea) = 84.0 kJ/mol

Frequency factor (A) = 7.83 × 10¹¹ s⁻¹

Temperature (T) = 55.0°C = 55.0 + 273.15 K = 328.15 K

Gas constant (R) = 8.314 J/(mol x K)

Substituting these values in the Arrhenius equation, we get:

k = (7.83 × 10¹¹ s⁻¹) x exp(-84000 J/(mol x 8.314 J/(mol x K) x 328.15 K))

k = 3.50 × 10¹⁰ s⁻¹

Therefore, the rate constant for the reaction at 55.0°C is 3.50 × 10¹⁰ s⁻¹.

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Answer:

PET (Polyethylene Terephthalate): This is the most common form of polyester and is used in many applications, such as in clothing, packaging, and bottles.

PCDT (Poly-1, 4-cyclohexylene-dimethylene terephthalate): This type of polyester is known for its high strength and is used in industrial applications, such as for making conveyor belts, hoses, and cables.

PTT (Polytrimethylene Terephthalate): This is a newer form of polyester that is made using bio-based materials. It is used in clothing, carpeting, and other textile applications.

PBT (Polybutylene Terephthalate): This type of polyester is known for its toughness and is used in electrical and automotive applications, such as for making connectors, switches, and housings.

Thermoplastic Polyester Elastomers (TPEE): These are polyester-based materials that have both thermoplastic and elastomeric properties. They are used in applications such as automotive parts, consumer goods, and sporting equipment.

Answer:

Option A. 1.02g of Fe.

Explanation:

Step 1:

The balanced equation for the reaction.

3Mg + Fe2(SO4)3 —> 3MgSO4 + 2Fe

Step 2:

Determination of the mass Fe2(SO4)3 that reacted and the mass of Fe produced from the balanced equation. This is illustrated below:

Molar Mass of of Fe2(SO4)3 = (2x56) + 3[32 + (16x4)] = 112 + 3[32 + 64] = 112 + 3[96] = 400g/mol

Mass of Fe2(SO4)3 from the balanced equation = 1 x 400 = 400g

Molar Mass of Fe = 56g/mol

Mass of Fe from the balanced equation = 2 x 56 = 112g

From the balanced equation above,

400g of Fe2(SO4)3 reacted to produce 112g Fe.

Step 3:

Determination of the mass of Fe produced by reacting 3.65g of Fe2(SO4)3.

This is illustrated below:

From the balanced equation above,

400g of Fe2(SO4)3 reacted to produce 112g Fe.

Therefore, 3.65g of Fe2(SO4)3 will react to produce = (3.65 x 112)/400 = 1.02g of Fe.

Therefore, 1.02g of Fe is produced from 3.65g of Fe2(SO4)3.

The molar mass of the unknown gas is 184.96 g/mol.

Graham's law of diffusion states that "the rate of diffusion of a gas is inversely proportional to the square root of the molar mass".

R ∝ 1/ √M

R₁/R₂ = √(M₂/M₁)

Rate of unknown gas (R₁) = R

Rate of CH₄ (R₂) = 3.4R

Molar mass of CH₄ (M₂) = 16 g/mol

Molar mass of unknown gas (M₁) =?

The molar mass of the unknown gas can be obtained as follow:

R₁/R₂ = √(M₂/M₁)

R / 3.4R = √(16 / M₁)

1 / 3.4 = √(16 / M₁)

Squaring both sides

(1 / 3.4)² = 16 / M₁

Cross multiplying

(1 / 3.4)² × M₁ = 16

Dividing both sides by (1 / 3.4)²

M₁ = 16 / (1 / 3.4)²

M₁ = 184.96 g/mol

Hence, the molar mass of the unknown gas is 184.96 g/mol.

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The enthalpy of formation of ozone is 142.7 kJ / mol. The bond energy of O2 is 498 kJ / mol.

498 kJ/mol

The bond energy of molecular oxygen, O2, is 498 kJ/mol and is photolyzed by light of 241 nm. HOOH, which has an extremely weak O-O bond, is photolyzed by light at 845 nm. Alternatively, the usual enthalpy of production of oxygen is zero because diatomic oxygen in its gaseous phase is the most stable form compared to mono-atomic oxygen (O) and triatomic oxygen (O3).

The elements that will react to generate H2O are present in their elemental forms. Because it takes no energy to generate a naturally occurring compound, the enthalpy of formation for an element in its elemental state will always be 0.

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Answer:

Copy and paste "Electromagnetic waves are categorized according to their frequency f or, equivalently, according to their wavelength λ = c/f.  Visible light has a wavelength range from ~400 nm to ~700 nm.  Violet light has a wavelength of ~400 nm, and a frequency of ~7.5*1014 Hz.  Red light has a wavelength of ~700 nm, and a frequency of ~4.3*1014 Hz." into google, and the correct website pops up as the first result.

Explanation:

I tried to link the website that I use to convert wavelengths and frequencies into types of light, but it deleted my answer, so I guess we're doing it this way. As for converting the wavelength to energy, the same principles apply as before:

Frequency: ν       Wavelength: λ       Energy: E       Speed of light: C (3.00e8)       Planck's Constant: h (6.626e-34)

ν -> λ    λ = C/ν

λ -> ν    ν = C/λ

For either of these equations, wavelength must be converted to meters or nanometers, depending on the equation.

For ν -> λ, after doing the equation, convert the wavelength into nanometers by dividing by 1e-9.

For converting λ -> ν, convert the wavelength into meters by multiplying by 1e-9.

For energy: E = hν = hc/λ

The size of micropipette that you would select to deliver 215 microliters would be a micropipette with a volume range of 200-1000 microliters.

What is a micropipette?

A micropipette is a laboratory instrument used to measure and dispense small volumes of liquid, typically in the range of microliters (µL) or nanoliters (nL). They are commonly used in chemistry, biology, and biochemistry experiments, as well as in clinical and industrial settings.

Micropipettes consist of a handle, a digital or manual volume adjustment mechanism, and a tip that is placed into the liquid to be dispensed. They work by creating a vacuum or positive pressure inside the tip, which draws or pushes the liquid out of the tip.

Micropipettes come in different volume ranges and it is important to select the right one to ensure accurate delivery of the desired volume. For example, a micropipette with a volume range of 2-10 microliters would not be suitable for delivering 215 microliters, while a micropipette with a volume range of 200-1000 microliters would be more appropriate.

It's also important to note that, even if the micropipette is able to deliver 215 microliters, you should always check the calibration of the micropipette before use, to make sure that it's delivering the correct volume.

Hence, a micropipette with a volume range of 200-1000 microliters is suitable to deliver 215 microliters.

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Answer:

A change in color often occurs during a chemical change

Answer: Option: B - The warm air molecules inside the balloon lose energy to the cold air molecules, they move slower, and condense.

Explanation: Warm air molecules move faster than cold air molecules.

Answer:

5 atoms are in each molecule of calcium carbonate

Its balanced already

So

Mass of S

Answer:

Set A will change temperature the most quickly because gold is a very good conductor of heat and electricity.

Explanation:

Set A (solid gold chunk between flasks) would likely change temperature most quickly. Therefore, option A is correct.

The rate at which the temperature changes in the flasks will depend on the thermal conductivity of the materials used as the chunks between them. Materials with higher thermal conductivity transfer heat more efficiently, leading to faster temperature changes.

Therefore, Set A (solid gold chunk between flasks) would likely change temperature most quickly, followed by Set B (solid stone chunk between flasks), Set C (solid glass chunk between flasks), and finally Set D (solid rubber chunk between flasks).

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nswer: 959.67 K or 686.67 C

Explanation:

Entropy of Vaporization (S) = Heat of Vaporization (H) / T ( boiling point) (in Kelvin)

1.) Flip the equation to have T as the product --> T = H/S

2.) We need to change H from kJ to J --> 69.0 kJ/mol --> 69000J/mol

3.) Substitute numbers in the equation --> (69000 kJ/mol) / (71.9 J/Kmol) = T

4.) T = 959.67 K or in Celcius --> 959.67 - 273 = 686.67 C