Answer:
The answer is 439.60 mmHgExplanation:
To find the original pressure we use the formula for Boyle's law which is
\(P_1V_1 = P_2V_2\)
where
P1 is the initial pressure
P2 is the final pressure
V1 is the initial volume
V2 is the final volume
Since we are finding the original pressure
\(P_1 = \frac{P_2V_2}{V_1} \\\)
From the question
V1 = 20 L = 20,000 mL
P2 = 560.0mmHg
V2 = 15700mL
We have
\(P_1 = \frac{560 \times 15700}{20000} = \frac{8792000}{20000} = \frac{2198}{5 } \\ \)
We have the final answer as
439.60 mmHgHope this helps you
The first step in the industrial recovery of zinc from zinc sulfide ore is roasting, that is, the conversion of ZnS to ZnO by heating: 2 ZnS(s) + 3 O2(g) → 2 ZnO(s) + 2 SO2(g) ΔH = –879 kJ/mol Based on your answer to the first question, calculate the heat for the reaction per gram of ZnS used (kJ/g). Hint: Use the molar mass of ZnS: 97.46 g/mo
The heat for the reaction per gram of ZnS used is -4.51 kJ/g.
To calculate the heat for the reaction per gram of ZnS used, we need to first calculate the amount of heat released per mole of ZnS used and then convert that to per gram.
The given balanced chemical equation shows that 2 moles of ZnS react with 3 moles of O2 to produce 2 moles of ZnO and 2 moles of SO2, and the amount of heat released during the reaction is -879 kJ/mol.
So, the amount of heat released per mole of ZnS used is:
(-879 kJ/mol) / 2 = -439.5 kJ/mol
Now, to calculate the amount of heat released per gram of ZnS used, we need to divide the amount of heat released per mole by the molar mass of ZnS:
-439.5 kJ/mol / 97.46 g/mol = -4.51 kJ/g.
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How did Robert Millikan's oil drop experiment change scientists' view of the
atom?
A. It identified the location of the nucleus.
B. It showed that atoms could not be divided into smaller particles.
C. It identified the charge on a single electron.
D. It showed that atoms were found in different energy levels.
SUBMIT
Answer:
Hello There!!
Explanation:
I think the answer is possibly C. It identified the charge on a single electron.
hope this helps,have a great day!!
~Pinky~
\(\huge{\textbf{\textsf{{\color{navy}{An}}{\purple{sw}}{\pink{er}} {\color{pink}{:}}}}}\)
C. It identified the charge on a single electron.
ThanksHope it helpsHow is heat involved in chemical reactions and processes
Most chemical reactions involve the breaking and formation of chemical bonds. It takes energy to break a chemical bond but energy is released when chemical bonds are formed. If more energy is released than consumed, then the chemical reaction evolves heat and is said to be exothermic.
(Have a good day!)
Answer:
Most chemical reactions involve the breaking and formation of chemical bonds. It takes energy to break a chemical bond but energy is released when chemical bonds are formed. If more energy is released than consumed, then the chemical reaction evolves heat and it called exothermic.
129.13 mL of a 112.9 mM solution of NH4l is added to a 105.31 mL solution of 0.87 M Mgl2. What
is the final concentration of I ions in the resulting solution? Express your answer in units of
molarity using at least three significant figures.
The final concentration of I ions in the resulting solution is approximately 0.0311 M, expressed with three significant figures.
To determine the final concentration of I ions in the resulting solution, we need to consider the stoichiometry and volumes of the solutions being mixed.Given:
Volume of NH4l solution = 129.13 mL
Concentration of NH4l solution = 112.9 mM = 0.1129 M (converting from millimolar to molar)
Volume of Mgl2 solution = 105.31 mL
Concentration of Mgl2 solution = 0.87 M
First, we need to determine the moles of NH4l and Mgl2 in their respective solutions:
Moles of NH4l = Volume of NH4l solution * Concentration of NH4l solution
Moles of NH4l = 0.12913 L * 0.1129 M = 0.01459 moles NH4l
Moles of Mgl2 = Volume of Mgl2 solution * Concentration of Mgl2 solution
Moles of Mgl2 = 0.10531 L * 0.87 M = 0.09157 moles Mgl2
Next, we determine the limiting reagent, which is the reactant that is completely consumed and determines the maximum amount of product formed. In this case, the limiting reagent is NH4l because it has fewer moles than Mgl2.
The balanced chemical equation for the reaction between NH4l and Mgl2 is:
2 NH4l + Mgl2 → 2 NH4+ + MgI2
From the balanced equation, we can see that for every 2 moles of NH4l, we get 1 mole of MgI2.
Since the moles of NH4l is the limiting reagent, it will be completely consumed, and the moles of MgI2 formed will be half of the moles of NH4l.
Moles of MgI2 = 0.01459 moles NH4l * (1 mole MgI2 / 2 moles NH4l) = 0.007295 moles MgI2
Finally, we calculate the final concentration of I ions in the resulting solution:
Volume of resulting solution = Volume of NH4l solution + Volume of Mgl2 solution
Volume of resulting solution = 0.12913 L + 0.10531 L = 0.23444 L
Final concentration of I ions = Moles of MgI2 / Volume of resulting solution
Final concentration of I ions = 0.007295 moles / 0.23444 L = 0.0311 M
Therefore, the final concentration of I ions in the resulting solution is approximately 0.0311 M, expressed with three significant figures.
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Three 15.0 mL acid samples - 0.10 M HA, 0.10M HB, and 0.10 M H2C - are all titrated with 0.100 M NaOH.If HA is a weak acid, HB is a strong acid, and H2C is a diprotic acid, which statement is true of all three titrations?
All three titrations have the same final pH.
All three titrations require the same volume of NaOH to reach the first equivalence point.
All three titrations have the same pH at the first equivalence point.
All three titrations have the same initial pH.
All three titrations require the same volume of NaOH to reach the first equivalence point.
The type of acid used in the titration determines the pH of the result: a strong acid results in a pH of 7 at the titration's equivalent. Equivalence point for a weak acid is influenced by the type of conjugate base and weak acid's beginning pH. The type of the acid is another factor for a diprotic acid.
Thus:
The initial pH of all three titrations is the same, as is the pH at the first equivalence point in all three titrations. Moreover, the final pH of all three titrations is the same. of the three are FALSE.
Thus:
To reach the first equivalence point, all three titrations need the same volume of NaOH.
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If HA is the weak acid, HB is the strong acid, and H₂C is a diprotic acid, the statement is true for the titrations is All three titrations require the same volume of NaOH to reach the first equivalence point.
The pH of the titration is depend on the nature of acid. here the the HA is the weak acid and the HB is the strong acid. the H₂C is the diprotic acid. the diprotic acid means the acid which contains the two hydrogen atoms and will ionized in the water.
Thus, the from all the statements the true one is that All three titrations require the same volume of NaOH to reach the first equivalence point.
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Balance the redox reaction by inserting the appropriate coefficients.
redox reaction:
Fe^{3 + } + NO_{2}^{-} + H_{2}O -> Fe^{2 + } + H^{ + } + NO_{3}^{-}
Fe3++NO−2+H2O⟶Fe2++H++NO−3
The balanced redox reaction is \(Fe^{3+}+NO^{2-}+H_{2}O- > Fe^{2+}+H^{+}+NO^{3-}+H_{2}O\)
To balance the redox reaction: \(Fe^{3+}+NO^{2-}+H_{2}O- > Fe^{2+}+H^{+}+NO^{3-}\), we need to ensure that the number of atoms and charges are balanced on both sides of the equation.
First, let's balance the atoms. We have one Fe atom on both sides, so it's already balanced. Next, we have two oxygen atoms on the reactant side (from \(NO^{2-}\) and \(H_{2}O\)) and three on the product side (from \(NO^{3-}\)). To balance oxygen, we can add an \(H_{2}O\) molecule to the reactant side:
\(Fe^{3+}+NO^{2-}+H_{2}O- > Fe^{2+}+H^{+}+NO^{3-}+H_{2}O\)
Now, let's balance the charges. On the reactant side, the total charge is 3+ (from \(Fe^{3+}\) ) + 1- (from \(NO^{2-}\)) = 2+. On the product side, the total charge is 2+ (from \(Fe^{2+}\)) + 1+ (from \(H^{+}\)) + 1- (from \(NO^{3-}\)) = 2+. The charges are already balanced.
Therefore, the balanced redox reaction is:
\(Fe^{3+}+NO^{2-}+H_{2}O- > Fe^{2+}+H^{+}+NO^{3-}+H_{2}O\)
By adding an additional H2O molecule to the reactant side, we balanced both the atoms and charges in the equation.
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Which of the following is not true
regarding ozone?
A. It contains 3 oxygen atoms
B. It is just like regular oxygen
C. It protects us from UV light
D. It is a layer within another layer in our
atmosphere
Answer:
B
Explanation:
Which orbital diagram represents neon
(atomic number = 10)?
Answer:
b because the another has the arrows equal and in chemistry is not that way
The orbital diagram which represents neon (atomic number = 10) is option B.
An orbital diagram is a visual representation of the electrons in an atom's electron orbitals. It shows the number of electrons in each orbital and the spin of each electron.
The orbital diagram of neon shows that the first energy level (n=1) is filled with 2 electrons in the 1s orbital, and the second energy level (n=2) is filled with 8 electrons in the 2s and 2p orbitals.
The electrons fill the orbitals from the lowest energy level to the highest energy level in accordance with the Aufbau principle.And the spin of 2 electrons in each orbital is that one electron is in clockwise direction while the other is in anti-clockwise direction.Therefore, the orbital diagram of neon is \(\rm 1s^2 2s^2 2p^6\). The correct answer is option B.
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At which temperature would the molecules in a one
gram sample of water have the lowest average
kinetic energy?
1) 5°C
3) 5K
2) -100°C
4) 100 K
Answer:
-100 K
Explanation:
Kinetic energy is related to temperature. The molecules in water will move faster in warmer temperatures than in colder ones.
100 K is equal to -279.67°F (-173.15°C). So 100 K would have the lowest average kinetic energy.
Given that π = n M R T, rearrange the equation to solve for V
Answer:
V= n/M
Explanation:
From;
π = nRT/V = MRT
Where;
n= number of moles
R= gas constant
T= absolute temperature
M= molar mass
V= volume of the solution
π= osmotic pressure
Thus;
nRT/V = MRT
nRT = VMRT
V= nRT/MRT
V= n/M
Identify an element that is NOT in its standard state.
Choose the one alternative that best completes the statement or answers the question.
A) N2(g)
B) Xe(g)
C) Ca(s)
D) N(g)
Explanation:
Xenon is a gas in its standard state
Calcium is a solid in its standard state
Nitrogen is a gas in its standard state
I am assuming that N2 is a isotope of nitrogen, not sure which but by the process of elimination I think that is the answer
Can someone please help me with EARTH SCIENCE, in New York State?! I need you to label each box with a number. it’s called “rock strata correlation practice”. Number 1 would be the oldest when u label it and it’d be at the bottom.
In the rock strata correlation practice for New York State, you'll need to label each box with a number, with number 1 representing the oldest layer, located at the bottom.
To perform the correlation, start by examining the different rock layers across different locations or outcrops in New York State. Compare the characteristics of these layers, such as their composition, fossil content, and sedimentary structures. Look for similarities and patterns between the layers to determine their correlation. By identifying key markers, such as unique fossils or distinctive sedimentary structures, you can establish relationships between the rock layers at different locations. Remember to consider the principle of superposition, which states that younger rocks are typically found above older rocks unless they have been disturbed by geological processes. Applying these principles will help you accurately correlate the rock strata in New York State.For such more question on rock strata
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A student dissolves of sodium hydroxide in of water in a well-insulated open cup. He then observes the temperature of the water rise from to over the course of minutes. Use this data, and any information you need from the ALEKS Data resource, to answer the questions below about this reaction: ()()() You can make any reasonable assumptions about the physical properties of the solution. Be sure answers you calculate using measured data are rounded to the correct number of significant digits. Note for advanced students: it's possible the student did not do the experiment carefully, and the values you calculate may not be the same as the known and published values for this reaction.
Is this reaction exothermic, endothermic, or neither?
a. exothermic
b. endothermic
c. neither
Answer: a. exothermic
Explanation:
An Endothermic reaction is a type of chemical reaction in which energy is absorbed from the surrounding. The temperature of the surrounding decreases.
An Exothermic reaction is a type of of chemical reaction in which energy is released into the surrounding. The temperature of the surrounding increases.
When sodium hydroxide is dissolved in water, the temperature of water rise which means the heat has been released during dissolution of sodium hydroxide, thus the reaction is exothermic.
Solar and wind energy are both intermittent resources that cannot be relied upon for a constant stream of energy production. Explain why developing better ways to store energy is an important part of making these energy sources more practical to use.
By removing the need to build additional transmission lines and equipment, energy storage may reduce costs for utilities and their customers.
By removing the need to build additional transmission lines and equipment, energy storage may reduce costs for utilities and their customers. Energy storage's inherent ability to offer backup power in the event of grid failure is a feature that both residential consumers and commercial owners find highly desirable.
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Asappp plzz help mee
Strontium-90, a radioactive isotope with applications in medicine, has a half-life of approximately 30 years. Out of a 100-gram sample, approximately how much remains after 170 years? 2 grams 8 grams 17 grams 81 grams
There are 2 grams remain
Further explanationGiven
t1/2 = 30 years
t = 170 years
No = 100 g
Required
Remaining sample
Solution
General formulas used in decay:
\(\large{\boxed{\bold{N_t=N_0(\dfrac{1}{2})^{t/t\frac{1}{2} }}}\)
Input the value :
\(\tt Nt=100.\dfrac{1}{2}^{170/30}\\\\Nt=1.969\approx 2~grams\)
Why does 50 g of copper require less heat (q) than 50 g of water, in order to raise the temperature by 15 oC? (Hint - the heat capacity may play a role, but how?)
Answer:
See Explanation
Explanation:
Specific heat capacity is an intensive physical property of matter. It is a measure of the quantity of heat that must be supplied in order to change the temperature of a unit mass of a substance by 1°C.
The specific heat capacity of a substance determines the quantity of heat that must be supplied in order to effect a temperature change of a unit mass of a substance. The higher the specific heat capacity of a substance, the greater the quantity of heat required to effect a temperature change in a given mass of the substance.
The specific heat capacity of water is 4,200 Joules per kilogram while the specific heat capacity of copper is 385 Joules per kilogram. Hence, the heat capacity of water is far greater than that of copper and consequently, 50 g of copper require less heat (q) than 50 g of water, in order to raise the temperature by 15 oC.
Based on the activity series provided, which reactants will form products? F > Cl > Br > I CuI2 + Br2 Right arrow. Cl2 + AlF3 Right arrow. Br2 + NaCl Right arrow. CuF2 + I2 Right arrow.
Answer: Cul2 + Br2 ->
Explanation:
Answer:
i believe the answer is a
Explanation:
When is the atomic number NOT equal to the number of electrons?
Explanation:
where there are negative or positive ions
Explanation:
Protons
Each element has an atomic number. The atomic numbers are listed along with the names and symbols of the elements on the inside cover of the text. The atomic number equals the charge on the nucleus. It therefore also equals the number of protons in the nucleus and also equals numerically the number of electrons in the neutral atom. The atomic number has the symbol Z.
Different elements have different atomic numbers; therefore, atoms of different elements contain different numbers of protons (and electrons). Oxygen has the atomic number 8; its atoms contain 8 protons and 8 electrons. Uranium has the atomic number 92; its atoms contain 92 protons and 92 electrons.
The relationship between atomic number and the number of protons or electrons can be stated as follows:
Atomic number= number of protons per atom= number of electrons per neutral atom
B. Mass Number Equals Protons plus Neutrons
Each atom also has a mass number, denoted by the symbol A. The mass number of an atom is equal to the number of protons plus the number of neutrons that it contains. In other words, the number of neutrons in any atom is its mass number minus its atomic number.
Number of neutrons = mass number - atomic number
or
Mass number = number of protons + number of neutrons
The atomic number and the mass number of an atom of an element can be shown by writing, in front of the symbol of the element, the mass number as a superscript and the atomic number as a subscript:
mass number
atomic numberSymbol of elementorA
ZX
For example, an atom of gold (symbol Au), with an atomic number 79 and mass number of 196 is denoted as:
196
79Au
C. Isotopes
Although all atoms of a given element must have the same atomic number, they need not all have the same mass number. For example, some atoms of carbon (atomic number 6) have a mass number of 12, others have a mass number of 13, and still others have a mass number of 14. These different kinds of the same element are called isotopes. Isotopes are atoms that have the same atomic number (and are therefore of the same element) but different mass numbers. The composition of atoms of the naturally occurring isotopes of carbon are shown in Table 4.2.
TABLE 4.2 The naturally occurring isotopes of carbonIsotopeProtonsElectronsNeutrons12
6C66613
6C66714
6C668
The various isotopes of an element can be designated by using superscripts and subscripts to show the mass number and the atomic number. They can also be identified by the name of the element with the mass number of the particular isotope. For example, as an alternative to
12
6C,13
6C,and14
6C
we can write carbon-12, carbon-13, and carbon-14.
About 350 isotopes occur naturally on Earth, and another 1500 have been produced artificially. The isotopes of a given element are by no means equally abundant. For example, 98.89% of all carbon occurring in nature is carbon-12, 1.11% is carbon-13, and only a trace is carbon-14. Some elements have only one naturally occurring isotope. Table 4.3 lists the naturally occurring isotopes of several common elements, along with their relative abundance.
TABLE 4.3 Relative abundance of naturally occurring isotopes of several elementsIsotopeAbundance (%)hydrogen-199.985hydrogen-20.015hydrogen-3tracecarbon-1298.89carbon-131.11carbon-14tracenitrogen-1499.63nitrogen-150.37 oxygen-1699.76oxygen-170.037oxygen-180.204IsotopeAbundance (%)silicon-2892.21silicon-294.70silicon-303.09chlorine-3575.53chlorine-3724.47phosphorus-31100iron-545.82iron-5696.66iron-572.19iron-580.33 aluminum-27100
Calculate the amount of copper in moles in a 27.5g pure copper sheet
The amount of copper in moles in the 27.5 g pure copper sheet is approximately 0.433 moles.
To calculate the amount of copper in moles in a pure copper sheet, we need to use the molar mass of copper and the given mass of the sheet.
The molar mass of copper (Cu) is approximately 63.55 g/mol. This value represents the mass of one mole of copper atoms.
Given that the mass of the pure copper sheet is 27.5 g, we can calculate the number of moles using the following formula:
moles = mass / molar mass
Substituting the values:
moles = 27.5 g / 63.55 g/mol
moles ≈ 0.433 mol
Therefore, the amount of copper in moles in the 27.5 g pure copper sheet is approximately 0.433 moles.
To arrive at this result, we divided the given mass of the sheet (27.5 g) by the molar mass of copper (63.55 g/mol). This calculation allows us to convert the mass of the sheet into the corresponding number of moles of copper.
The result tells us that the 27.5 g pure copper sheet contains approximately 0.433 moles of copper atoms. This conversion to moles is useful in various chemical calculations and allows for easier comparison and analysis of quantities on a molecular scale.
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Does anyone have Personal Care services on E2020
Here are some questions on Personal Care services on E2020 are:
A client with a new ileostomy has been home for four days. The HHA is giving the client a bath and notices that the pouch is full. The HHA should say to the client: D. "I'll empty the pouch for you."A client is bedridden at home and has an infected draining sacral wound. The infection control supplies that should be kept in the home is: Gloves.What is infection?An infection is the entrance and growth of dangerous microorganisms in the body that harm the host, such as bacteria, viruses, fungus, or parasites.
Infections can be systemic (affecting the entire body) or localized (affecting a particular area of the body), and they can be moderate to severe.
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Enough of a monoprotic acid is dissolved in water to produce a 1.64 M solution. The pH of the resulting solution is 2.82 . Calculate the Ka for the acid.
Answer:
Ka = 1.39x10⁻⁶
Explanation:
A monoprotic acid, HX, will be in equilibrium in an aqueous medium such as:
HX(aq) ⇄ H⁺(aq) + X⁻(aq)
Where Ka is:
Ka = [H⁺] [X⁻] / [HX]
Where [] is the molar concentration in equilibrium of each specie.
The equilibrium is reached when some HX reacts producing H+ and X-, that is:
[HX] = 1.64M - X
[H⁺] = X
[X⁻] = X
As pH is 2.82 = -log [H⁺]:
[H⁺] = 1.51x10⁻³M:
[HX] = 1.64M - 1.51x10⁻³M = 1.638M
[H⁺] = 1.51x10⁻³M
[X⁻] = 1.51x10⁻³M
And Ka is:
Ka = [1.51x10⁻³M] [1.51x10⁻³M] / [1.638M]
Ka = 1.39x10⁻⁶Draw the structures of organic compounds A and B. Omit all byproducts. OH Mg 1. acetaldehyde Compound A Compound B ether 2. H20 Draw compound A. Draw compound B. Select Draw Rings More Erase Select Draw Rings More H Br F / / / с H Mg Br
Compound A: Acetaldehyde
- Acetaldehyde is an organic compound with the chemical formula CH3CHO. It is an aldehyde with a carbonyl group (C=O) attached to a methyl group (CH3) and a hydrogen atom (H). The structure of acetaldehyde can be drawn as follows:
H H
| |
H-C-C=O
| |
H H
Compound B: Ether
- Ether is a class of organic compounds with the general formula R-O-R', where R and R' are alkyl or aryl groups. An example of an ether is diethyl ether, which has the chemical formula CH3CH2OCH2CH3. The structure of diethyl ether can be drawn as follows:
H H H H
| | | |
H-C-C-O-C-C-H
| | | |
H H H H
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a)
Ammonia and nitrogen monoxide react together according to the following
equation:
4NH3(g) + 6NO (9) - 5N2 (9) + 6H20 (g)
50.0 dm3 of ammonia is reacted with 50.0 dm3 of nitrogen monoxide at 150.0 °C and
100 kPa. Identify the excess reagent and determine the volume of nitrogen produced.
(2)
b)
Determine the volume of excess gas and hence total volume of gas after the reaction
has finished.
(1)
c)
What mass of nitrogen is produced in the reaction? Express your answer to an
appropriate number of significant figures.
(2)
sorry what us this i don't get it
Which of the following describes a common role played by decomposers in the carbon cycle?
Dissolve and store carbon for long periods of time
Take carbon from the atmosphere to use to make food
Break down carbon stored in rocks through the process of weathering
Release carbon into the soil and atmosphere by breaking down dead matter
The most common role played by decomposers in the carbon cycle is the release of carbon into soil and atmosphere by breaking down dead matter.
The natural way of reusing carbon atoms that travel from the atmosphere to the organisms on Earth and then return to the atmosphere over and over again is known as carbon cycle.
Most carbon is stored in rocks and sediments, and the rest is stored in the ocean, atmosphere and organisms.
Decomposers are the microorganisms that decompose animals and plants and convert them into humus in soil. Bacteria and Fungi are the two most common examples of decomposers.
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GIVING 21 POINTS AWAY PLEASE HELP ME WITH BOTH QUESTIONS ASAP!!!!
Cobalt – 60 used in cancer therapy, decays by beta and gamma emission. The decay constant is 4.18x10 -9 /s. What is the half-life in years?
The decay constant ( λ) tells us the probability of a radioactive nuclide in time. We can relate the decay constant to the half-life of the nuclide by the following equation:
\(t_{\frac{1}{2}}=\frac{ln2}{\lambda}\)Where λ is the decay constant and t1/2 is the half-life time
We replace the value of λ and we find the half-life time
\(t_{1/2}=\frac{ln2}{4.18\times10^{-9}/s}\)\(t_{1/2}=1.66\times10^8s\times\frac{1year}{3.154\times10^7s}=5.26years\)The half-time of Cobalt-60 is 5.26 years
Answer: 5.26 years
4.All of these are types of radioactive decay except
a. Alpha
b. Beta
c. Gamma
d. Delta
How does the air temperature at the bottom of a mountain compare with the air temperature at the top of the mountain?
A. The air is colder at the bottom.
B. The air is warmer at the top.
C. The air temperature at the top is lower.
D. The air temperature is the same.
Explanation: C) the air temp. at the top is lower
PLEASE HELPPPPPPPPPPPPPP