Chase decided he was going to start selling cups of lemonade this weekend too. He calculated his profit using the given table

number of cups sold (c) 15 20 25 30 35
total profit earned S(c) $5. 05 $9. 05 $13. 05 $17. 05 $21. 5

The clock minutes rotate 270 degrees in 45 minutes.

While rotating, the clock's hands are seen to move at a speed of six degrees per minute.

The number of degrees for a clock minute is solved by

60 minutes  = 360 degrees

1 minute = ?

cross multiplying

60 * ? = 360

? = 360 / 60

? = 6

hence 1 minute is 6 degrees

The formula to use to get the calculation is multiplying the number of minutes by 6

Number of degrees in 45 minutes = 45 * 6

Number of degrees in 45 minutes = 270 degrees

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Answer:

(-2, 32, -21)

Step-by-step explanation:

You just multiply B by 3 and then subtract the corresponding parts. For example -2 -(0*3). and then 14-(-6*3)

The type of energy the box have after it is done being pulled is "kinetic energy".

Kinetic energy is the type of energy which an item or particle has as a result of its motion. When work, that transfers energy, is performed on an item by exerting a net force, that object accelerates and obtains kinetic energy.

Now, according to the question;

The box's mass, m = 10 kg

F = 50 N, the force that occurs when the box is pulled

It has been moved 4 meters.

Friction force operating upon that box, f = 20 N

We must determine the box's initial kinetic energy. The box appears to be at rest at first. Because there is no movement in the box at the time.

The formula for box's kinetic energy is as follows:

K.E = (1/2)mv²

As velocity is given zero; v = 0.

Thus, K.E = 0.

The initial velocity of the box is zero.

Therefore, as the box starts moving its zero kinetic energy will start increasing.

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The given expression:

(3/8)*( 1 + √49)^2 - (4 - 1)^3

Can be simplified to -3.

So we have the equality:

(3/8)*( 1 + √49)^2 - (4 - 1)^3 = -3

Which means that the first option is the correct one.

Here we have the expression:

(3/8)*( 1 + √49)^2 - (4 - 1)^3

(I think is something like that)

And we want to simplify it, so first let's simplify the things inside the two parentheses.

The first one is:

1 + √49

We know that 7*7 = 49, then the square root of 49 is 7.

1 + √49 = 1 + 7 = 8

The other one is:

4 - 1 = 3

Replacing that in the expression we get:

(3/8)*( 1 + √49)^2 - (4 - 1)^3 = (3/8)*(8)^2 - (3)^3

Now we can solve the exponents:

8^2 = 8*8 = 64

3^3 = 3*3*3 = 27

Replacing that we get:

(3/8)*64 - 27 = 3*8 - 27 = 24 - 27 = -3

We conclude that the given expression:

(3/8)*( 1 + √49)^2 - (4 - 1)^3

Can be simplified to -3.

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The matrix can be diagonalized, and the correct choice is B. For P= ⎡⎣​3−110​11​⎤⎦, D= ⎡⎣​393​000​⎤⎦.

To diagonalize a matrix, we need to find its eigenvectors and use them to construct a matrix P, where the columns of P are the eigenvectors. The diagonal matrix D is formed by placing the eigenvalues on the diagonal.

First, we find the eigenvalues λ by solving the characteristic equation det(A - λI) = 0, where A is the given matrix and I is the identity matrix. By calculating the determinant, we have (33 - λ)(9 - λ) - (-3)(18) = 0, which simplifies to λ^2 - 42λ + 315 = 0. Solving this quadratic equation gives λ = 3 and λ = 9.

Next, we find the corresponding eigenvectors. For λ = 3, we solve the equation (A - 3I)v = 0, where v is the eigenvector. This leads to the eigenvector v = ⎡⎣​3−110​⎤⎦. For λ = 9, we solve (A - 9I)v = 0, which gives v = ⎡⎣​11​1​⎤⎦.

We construct matrix P by using the eigenvectors as columns: P = ⎡⎣​3−110​11​⎤⎦. The diagonal matrix D is formed by placing the eigenvalues on the diagonal: D = ⎡⎣​393​000​⎤⎦.

Therefore, the correct choice is B. For P= ⎡⎣​3−110​11​⎤⎦, D= ⎡⎣​393​000​⎤⎦.

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A. The y-intercept is at the point (0, 0).

B.  The zeros are x = 0 or x = ±√5

C.

A) The y-intercept of this graph is the point where x = 0.

When  x = 0, the value of y

= 0^4 - 5*0^2

= 0.

Therefore, the y-intercept is at the point (0, 0).

B) The x-intercepts/roots of the function are the values of x that make y = 0.

To find these values, we need to set y = 0 and solve for x:

x⁴ - 5x² = 0

x⁴ = 5x²

x² = x⁴/5

x = ±√(x⁴/5)

We can simplify this expression by factoring x² out of both sides:

x²(x² - 5) = 0

x² = 0 or x² - 5 = 0

x = 0 or x = ±√5

hence the x-intercepts are at x = 0 and x = ±√5.

C) The end behavior of this function refers to how the graph of the function approaches the x-axis as x approaches positive infinity and negative infinity.

x → ∞ f(x) → ∞

x → -∞ f(x) → -∞

D) The graph is attached

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The probability of four unrelated cases of smallpox being reported in Metro City in any given week, assuming a probability of 0.0034 for a single case, can be calculated using the binomial distribution formula. The probability of getting exactly 4 cases in a week is:

P(X=4) = (4 choose 4) * (0.0034)^4 * (1-0.0034)^(4-4) = 1 * 0.000000061 * 1 = 0.0000061

This means that the probability of four unrelated cases of smallpox being reported in Metro City in any given week is very low, about 0.0006%. However, it's important to note that these events are not necessarily independent. If the four cases are related in some way, such as being part of an outbreak or cluster, then the probability of all four occurring in the same week would be much higher. Therefore, further investigation would be needed to determine the independence of these events.

The probability of four unrelated cases of smallpox occurring in Metro City in the week of July 17, given that the probability of a single case in any given week is 0.0034, can be calculated using the binomial probability formula, since these are independent events.

The formula is: P(X=k) = C(n,k) * p^k * (1-p)^(n-k)

In this case, n = 4 (number of cases), k = 4 (number of successes), and p = 0.0034 (probability of a single case).

Using the formula, we have:
P(X=4) = C(4,4) * (0.0034)^4 * (1-0.0034)^(4-4)
P(X=4) = 1 * (0.0000001331) * 1
P(X=4) = 0.0000001331

The probability of this occurring is approximately 0.0000001331, which is extremely low. Given this low probability, it is unlikely that these cases are independent events, and further investigation might be warranted to determine if there is a common source or reason for the cases to occur simultaneously.

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Answer:

0.56

Step-by-step explanation:

14/25 = 14×4/25×4

=56/100

=0.56

Answer:

6.80 x 10⁻⁷ m

Step-by-step explanation:

You can find the value of λ by inserting the given values into the equation and simplifying.

c = vλ                                                            <----- Given equation

2.998 x 10⁸ m/s = (4.41 x 10¹⁴ s⁻¹)λ               <----- Insert values

6.80 x 10⁻⁷ m = λ                                          <----- Divide both sides by 4.41 x 10¹⁴

Step-by-step explanation:

a) The dependent variable is the velocity of the scooter, and the independent variable is time.

b) Using the kinematic equation v = u + at, where u is the initial velocity, a is the acceleration, t is time, and v is the final velocity, we can find the velocity as a function of time for t ≤ 6 seconds:

v = u + at = 1.0 + (a × t)

c) The graph of velocity as a function of time for the scooter would be a straight line with a positive slope, starting at (0,1.0) and ending at (6,4.0). The x-axis would be labeled "Time (s)" and the y-axis would be labeled "Velocity (mph)".

d) We can find the acceleration of the scooter by rearranging the equation from part (b) to a = (v - u) / t, where v = 4.0 mph, u = 1.0 mph, and t = 6 seconds:

a = (4.0 - 1.0) / 6 = 0.5 mph/s

We can label the acceleration as 0.5 mph/s on the graph.

e) The initial velocity of the scooter is 1.0 mph, which we can label on the graph.

f) To find the distance traveled by the scooter between 0 and 6 seconds using the graphical method, we can calculate the area under the velocity-time graph. The graph forms a trapezoid with a base of 6 seconds, a height of 3 mph (the difference between the final and initial velocities), and a top length of 1.0 mph. The distance traveled is therefore:

distance = 0.5 × (1.0 + 4.0) × 6 = 15.0 miles

g) To find the distance traveled by the scooter between 0 and 6 seconds using the kinematic equations, we can use the equation s = ut + 0.5at^2, where s is the distance traveled, u is the initial velocity, a is the acceleration, and t is time. Since the acceleration is constant, we can use the average velocity (2.5 mph) to find the distance traveled:

s = 1.0 × 6 + 0.5 × 0.5 × 6^2 = 15.75 miles

The result from the kinematic equation is slightly larger than the result from the graphical method. This is likely due to rounding errors and the approximation of the trapezoidal area under the velocity-time graph. Overall, both methods provide a good estimate of the distance traveled by the scooter between 0 and 6 seconds.

Factors other than independent variables which may act on the dependent variable , when these factors vary systematically with independent variable they are known as confounds variables or extraneous variable.

Therefore, factors which vary systematically with the given independent variable is called  confounds variables or extraneous variable.

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Answer: 2. Linear pair postulate

4. 60 + mACB=180

5. mACB=120

6. definition of obtuse angle

The value of straight angle ∠BCD = 180° thus the angle ∠ACB = 180°- 60° = 120° therefore, the given triangle ABC is the obtuse triangle.

A triangle is a 3-sided shape that is occasionally referred to as a triangle. There are three sides and three angles in every triangle.

The sum of all three angles inside a triangle will be 180° and the area of a triangle is given as (1/2) × base × height.

As per the given triangle ABC with extended line CD.

Since CD is colinear with BC, therefore, BCD will be a single straight-line segment.

The ∠BCD is straight angle so it will be 180°.

∠BCD = ∠ACB + ∠ACD

∠ACB + 60 = 180

∠ACB = 180 - 60 = 120°.

An obtuse triangle is a triangle whose one or more interior angle is greater than 90°.

Since∠ACB > 90° therefore triangle ABC is an obtuse angle.

Hence "The value of straight angle ∠BCD = 180° thus the angle ∠ACB = 180°- 60° = 120° therefore, the given triangle ABC is the obtuse triangle".

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Answer:

no

Step-by-step explanation:

yes

The student's final moment of inertia is 18.18 kgm².

The moment of inertia of an objecr is the property of an object which shows its ability to rotate.

Since a student is standing with her arms outstretched, on a platform that is rotating at 1.6 rev/s. She pulls her arms in and the platform now rotates at 2.2 rev/s. Her original moment of inertia (I0) is 25 kgm². To find the r final moment of inertia, we use the law of conservation of angular momentum.

The law of conservation of angular momentum states that for any rotation, angular momnetum is constant.

So, Iω = constant where

So, Iω = I'ω' where

Making I' subject of the formula, we have that

I' = Iω/ω'

So, substituting the values of the variables into the equation, we have that

I' = Iω/ω'

I' = 25 kgm² × 1.6 rev/s ÷ 2.2 rev/s

= 40 kgm²rev/s ÷ 2.2 rev/s

= 18.18 kgm²

So, the final moment of inertia is 18.18 kgm².

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The given statement "for continuous random variables, the probability of any specific value of the random variable is one." is false because the random variable taking on any specific value is then given by the area under the PDF curve at that value, which is zero.

In fact, for continuous random variables, the probability of any specific value is zero. This may seem counterintuitive at first, but it is a fundamental property of continuous random variables.

The PDF is a function that describes the relative likelihood of the random variable taking on a particular value within its range. The probability of the random variable taking on a specific value is then given by the area under the PDF curve at that value.

Since the PDF is a continuous function, the probability of the random variable taking on any specific value is zero. This is because the area under a continuous curve at any single point is zero.

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The mean absolute deviation over three period of time is 200

The absolute value of error in period 1 = 300

The absolute value of error in period 2 = 200

The absolute value of error in period 3 = -100

Total absolute value of error = The absolute value of error in period 1 + The absolute value of error in period 2 + The absolute value of error in period 3

Substitute values in the equation

Total absolute value of error  = 300 + 200 + 100

= 600

The mean absolute deviation = Total absolute value of error / 3

Substitute the values in the equation

The mean absolute deviation  = 600 / 3

= 200

Therefore, the mean absolute deviation is 200

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Answer:

my answer is incorrect

Step-by-step explanation:

Since the two shapes are similar, you can answer this question with a proportion.

\(\frac{12}{200} = \frac{15}{area} \\12area = 200*15\\area = \frac{200*15}{12} = 250\)

Another way you could solve it is to find the percentage growth of the height of the area.

\(\frac{15-12}{12} = \frac{3}{12} = 25\) percent growth.

We can multiply the area of A by 1.25 to find the area of B

\(200*1.25 = 250\)

edit: I was incorrect, it is not linear.

It would be \(200*(1.25)^2\)

Answer:

Step-by-step explanation:

12²=200cm²

15²=??

(15²×200)÷12²

=312.5

The first four terms and the stated term, with an as the first term, are given the arithmetic sequence: 11 + 9n, a6.

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If the concentration of the product COCl2 were to double, the equilibrium constant of the reaction would not be affected.

The equilibrium constant (K) is a measure of the ratio of product concentrations to reactant concentrations at equilibrium for a given chemical reaction. It is determined solely by the temperature of the reaction and is independent of the initial concentrations or changes in concentrations during the reaction.

Therefore, doubling the concentration of the product COCl2 would not alter the equilibrium constant of the reaction. The equilibrium constant reflects the relative concentrations of reactants and products at equilibrium and remains constant as long as the temperature remains the same. Any changes in concentration would simply shift the reaction towards the formation of reactants or products until a new equilibrium is reached, without affecting the equilibrium constant itself.

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GIVEN:

We are given a circle with center A and diameter CB.

The length of arc CDB is 14;

Required;

We are required to calculate the lenght of the radius.

Step-by-step solution;

The length of an arc with the central angle measured in radians is;

The length of the arc is given, so also is the angle theta (180 degrees, that is half the circle).

We can convert the degree measure of the angle into radians as follows;

Now we substitute the value of d (degree measure);

Now we take the formula for the length of an arc as follows;

Divide both sides by pi;

Therefore, the radius is

ANSWER:

Answer:

its A or the first one ;)

Step-by-step explanation:

True, a researcher wants to compare performance scores for men versus women on a motor skills task. it would not be possible to use a repeated measures design for this study.

What is a performance comparison?

They are frequently used while benchmarking, which is the practice of evaluating an organization's performance versus that of the best-performing businesses.

                 The measures are employed in productivity improvement projects to monitor changes in productivity over time.

Why is performance measurement important?

Comparing is one of the most important growth drivers. Only when we contrast our development with that of our rivals or our current performance with our former performance do we get motivated to advance and accomplish greater feats.

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The example that illustrates the difference between statistical significance and practial significance is

In a survey arranged by school-authority of a district on participation in sports by school-going boys and girls, it is found that 60% of boys and 57% of girls participate in outdoor sports. Thus the survey shows a 3% difference between school-going boy-participants and girl-participants in outdoor sports. Now the point is how much significance this 3% difference has statistically as well as practically. Statistical significance of this 3% depends upon the size of data used in determining the percentage of boys and girls participate in sports. If a sufficiently big sample size is used then the difference is statistically significant, and if a very small sample size is used then the difference is statistically insignificant. Thus bigger the sample size more is the statistical significance of a computed figure.

On the other hand practical significance of this 3% difference arises if decision is made or action is taken or needs to be taken on the basis of this 3% difference. If cost permits, the authority may consider promoting girl students participation in sports in order to bring about more gender parity in outdoor sports. In this case the 3% difference though small, may be practically significant.

Statistical significance is a measure of whether your research findings are meaningful. It is concerned with whether a research result is due to chance or sampling variability. Where, practical significance is concerened with wheteher the result is useful in the real world.

Therefore, the example that illustrates the difference between statistical significance and practial significance is

In a survey arranged by school-authority of a district on participation in sports by school-going boys and girls, it is found that 60% of boys and 57% of girls participate in outdoor sports. Thus the survey shows a 3% difference between school-going boy-participants and girl-participants in outdoor sports. Now the point is how much significance this 3% difference has statistically as well as practically. Statistical significance of this 3% depends upon the size of data used in determining the percentage of boys and girls participate in sports. If a sufficiently big sample size is used then the difference is statistically significant, and if a very small sample size is used then the difference is statistically insignificant. Thus bigger the sample size more is the statistical significance of a computed figure.

On the other hand practical significance of this 3% difference arises if decision is made or action is taken or needs to be taken on the basis of this 3% difference. If cost permits, the authority may consider promoting girl students participation in sports in order to bring about more gender parity in outdoor sports. In this case the 3% difference though small, may be practically significant.

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Answer:

hdnjejrjdjvaudnforbfbks

On solving the provided question, we can say that 1 degree = 3600 arc seconds and 1 degree = 60 arc minutes.

A 160 degree angle is measured in arc minutes, often known as arcmin, arcmin, arcmin, or arc minutes (represented by the sign '). One minute is equal to 121600 revolutions, or one degree, hence one degree equals 1360 revolutions (or one complete revolution). A degree, also known as a complete angle of arc, angle of arc, or angle of arc, is a unit of measurement for plane angles in which a full rotation equals 360 degrees. A degree is sometimes referred to as an arc degree if it has an arc of 60 minutes. Since there are 360 degrees in a circle, an arc's angles make up 1/360 of its circumference.

1 degree = 3600 arc seconds

1 degree = 60 arc minutes

A. 2 degree 18'36 = 2 + 18/60 + 36 / 2600 = 231 / 100 degree

B. 36 ′ 18 ′′ = 36/60 + 18/2600 = 121 / 200 degree

C. 7 degrees 59′ 59′′ = 7 + 59 / 60 + 59 / 3600 = 28799 / 3600 degree

D. 1' = 1/60 degree

F. 1" = 1/3600 degree

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Answer:

16

Step-by-step explanation:

Let us take the number be x . So the three fourths of the number will be , ¾ x . And this is equal to 10. So , According to Question ,

⇒ 3x/4 -2 = 10

⇒ 3x/4 = 10 + 2

⇒ 3/4 x = 12

⇒ x = 12 * 4/3

⇒ x = 16 .

Answer:

B , C , D

I hope I helped you^_^

Yes, a normal approximation can be used for a sampling distribution of sample means from a population with μ = 56 and σ = 10 when n = 9. Since the sample size is less than 30 and the population distribution is normal,

we can use the central limit theorem, which allows us to assume that the distribution of sample means is approximately normal.In order to use the normal approximation, we need to verify whether the sample size is large enough for a normal distribution to be a good approximation. According to the central limit theorem, if the sample size is less than 30, the normal approximation is valid if the population distribution is approximately normal. Since the population distribution is normal,

we can use the normal approximation for a sample size of n=9. Thus, the correct answer is: Yes, because the sample size is less than 30.

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