change from a gaseous to a liquid state is known as what phase change?

A. vaporization
B. fusion
C. condensation
D. evaporation

Better temperatures can growth the quantity of water vapor withinside the air, that could growth the probability of precipitation.

Different factors, inclusive of air pressure, wind, and atmospheric instability, additionally play a function withinside the formation of rain, and the connection among temperature and precipitation may be complicated. The temperature of atmospheric gases could have a substantial effect at the manufacturing of rain. The environment is a complicated device that performs a vital function with inside the Earth`s water cycle, which incorporates the system of precipitation, inclusive of rain. Precipitation takes place while water vapor with inside the air condenses into liquid droplets or ice crystals, which fall to the floor as rain, snow, or hail. The temperature of the environment impacts the quantity of water vapor that the air can preserve. As temperature increases, the air can preserve extra water vapor, that could cause better tiers of humidity. When the air will become saturated with water vapor, it reaches its dew point, and the extra water vapor condenses into liquid droplets or ice crystals, that could shape clouds and subsequently precipitation. In addition, international warming, that's inflicting an growth in atmospheric temperatures, can cause modifications in precipitation styles and extra severe climate events. Understanding the connection among temperature and precipitation is vital for predicting and mitigating the affects of weather change.

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Answer:

During the early Paleozoic Era, the Earth's surface was very different from what it is today. The continents were arranged differently, forming one large supercontinent called Pangea. This landmass was surrounded by a single large ocean called Panthalassa. The climate was much warmer and wetter than it is today, with no ice caps at the poles.

The first land plants, known as bryophytes, appeared during the early Silurian Period, around 430 million years ago. These plants were small and simple, lacking roots and vascular tissue. They grew in damp environments, such as along the edges of lakes and streams. They were important in the development of soils and in the colonization of land by other organisms, such as insects and other arthropods.

Answer:

\(^{127}_{53} I\)

53 protons and electrons and 74 neutrons.

Explanation:

Hello!

In this case, since the nuclide symbol of an isotope is represented by putting the atomic mass as a prefixed superscript and the number of protons as a prefixed subscript, for I-127 we have:

\(^{127}_{53} I\)

Now we realize this isotope have 53 electrons and protons and the following number of neutrons:

\(neutrons= 127-53=74\)

Notice this isotope has about the same molar mass of the average iodine atom.

Best regards!

Answer:

18 c

19 b

20 a

21 a

Explanation:

18 LiOH is a powerful base citric acid is a weak acid so when we mix a powerful base with a weak acid mixture become basic

when we mix powerful base with a powerful acid it becomes neutral(need to take equal quantities)

when we mix powerful acid with weak base mixture becomes acidic

when we mix weak acid with weak base we cannot tell what happens to find this we need to do some calculations

19 when the ka value is high it becomes more acidic

20 A polyprotic acid is an acid that can donate more than one proton or hydrogen atom per molecule to an aqueous solution. In contrast, a monoprotic acid (e.g., HCl) can only donate one proton per molecule.

so here it has 3H so it can donate 3H+

in here we need to write the ionization of the acid in water

do the answer is a

21 A proton acceptor is another name for a base, which is the opposite of an acid. In the Broensted-Lowry definition, a base is a negatively charged ion that will react with, or accept, a positively charged hydrogen ion. Since a hydrogen ion is a proton, the base is called a proton acceptor.

an acid is any proton donor, and a base is any proton acceptor. The focus of this definition is on donating and accepting protons, and is not limited to aqueous solution. The Brønsted-Lowry definition of acids and bases is one of two definitions we commonly use

Answer:

No power - breaker, switch off or dead battery

Line voltage below minimum operable voltage (brownout)

Dimmer at minimum so 0% light

Switch/Dimmer faulty

A connection faulty between source of power and bulb

Failure in fixture (Lower Voltage transformer, overheat switch, driver)

Bulb not secured correctly - check base tab for being squished down and cleanliness

Fault in bulb

Safety triggered (overheated component shutdown item)

The volume of \(N_2O_5\) needed to produce 9.64 L of \(NO_2\) is 4.97 L, calculated using stoichiometry and the ideal gas equation.

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0.013 g of the stock solution of riboflavin needs to be added to 25 ml of water to prepare a 14 μM solution.

To prepare a 0.059 mM riboflavin solution in 25 ml, we need to calculate the amount of riboflavin to add to 25 ml of water.

First, we need to convert the concentration from mM to μM:

0.059 mM × 1000 μM/1 mM = 59 μM

Next, we need to calculate the amount of riboflavin required to prepare a 25 ml solution with a concentration of 59 μM:

59 μM × 25 ml = 1475 μmol

Finally, we need to convert μmol to milligrams:

1475 μmol × (375.2 g/mol) / (10⁻⁶ μmol/mol) = 0.055 g

So, 0.055 g of the stock solution of riboflavin needs to be added to 25 ml of water to prepare a 0.059 mM solution.

To prepare a 14 μM riboflavin solution in 25 ml, we need to calculate the amount of riboflavin to add to 25 ml of water:

14 μM × 25 ml = 350 μmol

Finally, we need to convert μmol to milligrams:

350 μmol × (375.2 g/mol) / (10⁻⁶ μmol/mol) = 0.013 g

So, 0.013 g of the stock solution of riboflavin needs to be added to 25 ml of water to prepare a 14 μM solution.

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Answer:

We need more? What else is in the question? This is unanswerable.

Explanation:

Answer:D, HBr

Explanation:

Answer:

D. HBr because divide the moles of the substances given in the question by the co-efficient in the equation. Smallest quotient is the limiting reactant

Answer:

Explanation:

Answer: 0.656168 Feet per minute

Explanation:



0.656168 feet per minute

The formula is:

for an approximate result, divide the speed value by 1829

The student pulling out the pH electrode from the titration beaker and rinsing it off with DI water into a waste container several times during the titration will not significantly affect the measured equivalent mass.

This is because the equivalent mass of a substance is determined by the stoichiometry of the reaction, which is not influenced by the pH electrode or the rinsing process. However, it is important to note that if the student is rinsing the electrode with a significant amount of water, it could dilute the solution and affect the accuracy of the titration. Therefore, it is recommended to use a minimal amount of water during the rinsing process to minimize any potential dilution effect.

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Answer:

Chemists generally use the mole as the unit for the number of atoms or molecules of a material. One mole (abbreviated mol) is equal to 6.022×1023 molecular entities (Avogadro's number), and each element has a different molar mass depending on the weight of 6.022×1023 of its atoms (1 mole).\

Have a great day!!!!

Explanation:

1 mole of (NH₄)₂CO₃ has:

Let's consider the chemical formula of ammonium carbonate: (NH₄)₂CO₃.

The subscripts inform us of the number of moles of atoms in 1 mole of molecules.

Nitrogen has 2 subscripts: "1" (which is not written) and "2" (outside the parenthesis). The global subscript for nitrogen is obtained by multiplying both subscripts.

\(N: 1 \times 2 = 2\)

Hydrogen has 2 subscripts: "4" and "2" (outside the parenthesis). The global subscript for nitrogen is obtained by multiplying both subscripts.

\(H: 4 \times 2 = 8\)

The subscript for carbon is "1".

The subscript for oxygen is "3".

1 mole of (NH₄)₂CO₃ has:

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Waste is removed from the body in various ways. Kidneys filter out metabolic waste, excess fluid and eliminate it in the form of urine. Lungs exhale CO2 from the deoxygenated blood. The undigested solid waste is egested out from the large intestine. Excretion is the process of removing wastes and excess water from the body. It is one of the major ways the body maintains homeostasis. Organs of excretion make up the excretory system. They include the kidneys, large intestine, liver, skin, and lungs.

The solubility of\(LaF_3\) in water is 3.04 x 10^-6 mol/L.

The solubility of \(LaF_3\) in water can be determined using the Ksp expression:

\(Ksp = [La^{3+}][F^-]^3\)

Where \([La^{3+}]\)and \([F^-]\) are the molar concentrations of the \(La^{3+}\) and \(F^-\) ions in the solution.

Since each \(LaF_3\) formula unit dissociates into one \(La^{3+}\) ion and three \(F^-\) ions, the molar solubility of \(LaF_3\) can be represented as x. Thus, the molar concentrations of \(La^{3+}\) and \(F^-\) ions in the solution can be written as x and 3x, respectively.

Substituting these values into the Ksp expression gives:

Ksp = x*(3x)^3 = 27x^4

Now, we can solve for x:

x = (Ksp/27)^(1/4)

= (2 x 10^-19 / 27)^(1/4)

= 3.04 x 10^-6 mol/L

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Answer:

A. 2.65 atm.

B. 18.11 g/L.

Explanation:

A. Determination of the pressure

Mass of N₂O = 21.3 g

Volume = 5.76 L

Temperature (T) = 111 °C

Pressure (P) =.?

First, we shall determine the number of mole in 21.3 g of dinitrogen monoxide, N₂O. This can be obtained as follow:

Mass of N₂O = 21.3 g

Molar mass of N₂O = (14×2) + 16

= 28 + 16

= 44 g/mol

Mole of N₂O =?

Mole = mass /Molar mass

Mole of N₂O = 21.3/44

Mole of N₂O = 0.484 mole

Next, we shall convert 111°C to Kelvin temperature. This can be obtained as follow:

T(K) = T(°C) + 273

Temperature (T) = 111 °C

Temperature (T) = 111 °C + 273

Temperature (T) = 384 K

Finally, we shall determine the pressure. This can be obtained as follow:

Number mole of N₂O = 0.484 mole

Volume = 5.76 L

Temperature (T) = 384 K

Gas constant (R) = 0.0821 atm.L/Kmol

Pressure (P) =.?

PV = nRT

P × 5.76 = 0.484 × 0.0821 × 384

Divide both side by 5.76

P = (0.484 × 0.0821 × 384) / 5.76

P = 2.65 atm

B. Determination of the density of CFCl₃

Temperature (T) = 157°C

Pressure (P) = 4.65 atm.

Density of CFCl₃ =?

First, we shall determine the molar mass of CFCl₃. This can be obtained as follow:

Molar mass of CFCl₃ = 12 + 19 + (35.5×3)

= 12 + 19 + 106.5

= 137.5 g/mol

Next, we shall convert 157°C to Kelvin temperature. This can be obtained as follow:

T(K) = T(°C) + 273

Temperature (T) = 157 °C

Temperature (T) = 157 °C + 273

Temperature (T) = 430 K

Finally, we shall determine the density of CFCl₃. This can be obtained as follow:

Temperature (T) = 430 K

Pressure (P) = 4.65 atm.

Molar mass of CFCl₃ (M) = 137.5 g/mol

Gas constant (R) = 0.0821 atm.L/Kmol

Density (D) of CFCl₃ =?

D = PM / RT

D = (4.65 × 137.5) / (0.0821 × 430)

D = 18.11 g/L

Answer:

The answer will be 1992/5 or 398.4

Answer:

\(C_{14}H_8O_2+15O_2\rightarrow 14CO_2+4H_2O\)

Explanation:

Hello there!

In this case, according to the given description, it turns out possible for us to set up the required chemical reaction as follows:

\(C_{14}H_8O_2+O_2\rightarrow CO_2+H_2O\)

However, it turns out mandatory to balance it according to the law of conservation of mass, which states that the atoms must the same on the reactants side as on the products side; thus, we proceed as follows:

\(C_{14}H_8O_2+15O_2\rightarrow 14CO_2+4H_2O\)

In order to have 14 C atoms, 8 H atoms and 32 O atoms on both sides of the chemical equation.

Regards!

Answer:

Explanation:

2 electrons

Because the atomic number of helium is 2

The synthesis reactions are generally exothermic. They release energy in the form of heat and light. In such reactions new compounds are found to be formed. Among the given options, none are synthesis reaction. So the given options are incorrect.

A reaction in which multiple reactants combine together to form a single product is defined as the synthesis reaction. It is a chemical reaction in which two or more simple substances combine to form a more complex compound.

1. H₂ + Br₂ → 2HBr = Redox reaction

2. 2H₂O + 2Na → 2NaOH = Redox reaction

3. NaCl → Na+ + Cl = Dissociation

4. Mg + H₂SO4 → MgSO4 + H₂​ = Single replacement

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ANSWER

The length of the plank in cm is 113.375 cm

STEP-BY-STEP EXPLANATION:

Given information

Length of the plank in inches = 45.35 inches

You were asked to convert 45.35 inches to centimeters

Let x represents the converted length in cm

Recall that, 1 inch is equivalent to 2.5 centimeters according to the Standard International unit

The next step is to convert the length to cm

Therefore, the length of the plank in cm is 113.375 cm

371.4 g of glucose must be metabolized to produce 223 g of water.

The balanced chemical equation for the complete combustion of glucose is:

C₆H₁₂O₆ + 6O₂ → 6CO₂ + 6H₂O

According to the equation, for every 1 mole of glucose consumed, 6 moles of water are produced.

The molar mass of glucose is:

6(12.01 g/mol) + 12(1.01 g/mol) + 6(16.00 g/mol) = 180.18 g/mol

To calculate the mass of glucose required to produce 223 g of water, we need to first convert the mass of water to moles:

223 g / 18.015 g/mol = 12.38 mol H₂O

Now we can use the mole ratio from the balanced equation to calculate the moles of glucose required:

1 mol glucose / 6 mol H₂O = x mol glucose / 12.38 mol H₂O

x = 2.06 mol glucose

Finally, we can calculate the mass of glucose:

mass = moles × molar mass

mass = 2.06 mol × 180.18 g/mol = 371.4 g

Therefore, 371.4 g of glucose must be metabolized to produce 223 g of water.

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ANSWER

The heat of the reaction is -335 KJ/mol

EXPLANATION

Answer:

Parasites take nutrients from another organism's body.

Explanation:

The total amount of hydrogen gas generated is 9.76 L, under the condition that 15.9 g of hydrochloric acid reacts with excess zine metal.

Furthermore the balanced chemical equation for the reaction between hydrochloric acid and zinc metal is:
2HCl + Zn → ZnCl₂ + H₂
The molar mass of HCl is 36.46 g/mol.
Then, 15.9 g of HCl is equivalent to 15.9 g / 36.46 g/mol = 0.436 mol of HCl.
As per  the balanced chemical equation, 1 mole of HCl reacts with 1 mole of Zn to produce 1 mole of H₂ gas.
Hence, 0.436 mol of HCl will produce 0.436 mol of H₂ gas.
In Stp (Standard Temperature and Pressure), one mole of any gas occupies 22.4 L.
So, 0.436 mol of H₂ gas will occupy:
0.436 mol × 22.4 L/mol = 9.76 L (approx)
Then, approximately 9.76 L of hydrogen gas will be produced when 15.9 g of hydrochloric acid reacts with excess zinc metal at STP.
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Answer:

\(P_{He}=9.06torr\)

Explanation:

Hello there!

In this case, we can identify the solution to this problem via the Dalton's rule because the partial pressure of helium is given by:

\(P_{He}=x_{He}P_T\)

Whereas the mole fraction of helium is calculated by firstly obtaining the moles and then the mole fraction:

\(n_{He}=8.00g\frac{1mol}{4.00g}=2.00mol\\\\ x_{He}=\frac{n_{He}}{n_{He}+n_{Ar}} \\\\ x_{He}=\frac{2.00mol}{2.00mol+8.60mol}\\\\x_{He}=0.189\)

Then, we calculate the partial pressure as shown below:

\(P_{He}=0.189 *48.0torr\\\\P_{He}=9.06torr\)

Best regards!

Answer:

D

Explanation:

Color, texture, and density are all physical properties but reactivity is a chemical property so the answer is D.

The Microscope part and their right descriptions are as follows

Iris Diaphragm: A. Increases or decreases the light intensity

Objective Lens System: B. After light passes through the specimen, it next enters this lens system

Stage: C. Platform that supports a microscope slide

Adjustment Knob: D. Causes stage (or objective lens) to move upward or downward

Condenser: E. Concentrates light onto the specimen

Other parts of a microscope and their description that you should know about includes;

Eyepiece - The lens that you look through to see the image of the specimen.

Body tube - The tube that connects the eyepiece to the objective lenses.

Arm - The part of the microscope that supports the body tube and connects it to the base.

Base - The part of the microscope that supports the arm and provides stability.

Illuminator - The light source that provides light for the microscope.

Stage clips - The clips that hold the microscope slide in place on the stage.

Revolving nosepiece - The part of the microscope that holds the objective lenses and allows them to be rotated into place.

The above answer is in response to the full question below;

Match the names of the microscope parts in column A with the descriptions in column B. Place the letter of your choice in the space provided.

1. Iris diaphram

2. Objective lens system

3. Stage

4. Adjustment knob

5. Condenser

Increases or decreases the light intensity

2. After light passes through the specimen, it next enters this lens system

3. Platform that supports a microscope slide

4. Causes stage (or objective lens) to move upward or downward

5. Concentrates light onto the specimen

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