Answer:
C: Viscosity, the resistance to flow that fluids exhibit
Explanation:
Did it on Edge :)
Answer:
C: Viscosity, the resistance to flow that fluids exhibit
Explanation:
A 1.9-mm-diameter tube is inserted into an unknown liquid whose density is 960 kg/m3, and it is observed that the liquid rises 5 mm in the tube, making a contact angle of 15°. Determine the surface tension of the liquid.
Answer:
a 9mm dimeter tube is inserted into un known whose density is 960kg/m3 and it is obsered that the liquid rises 5mm inthe tube,making a contact angle of15. determin the surface tention of the fluid.
Explanation:
A 1.9-mm-diameter tube is inserted into an unknown liquid whose density is 960 kg/m3, and it is observed that the liquid rises 5 mm in the tube, making a contact angle of 15°. The surface tension of the liquid is 0.041 N/m.
What is surface tension?Surface tension is the property that is displayed by the liquid surface, which increases its surface area due to intermolecular forces of attraction.
We can use the capillary rise equation to solve this problem:
h = (2Tcosθ)/(ρgr)
where:
h = height of liquid rise in the tube (5 mm)
T = surface tension of the liquid (to be determined)
θ = contact angle (15°)
ρ = density of the liquid (960 kg/m^3)
g = acceleration due to gravity (9.81 m/s^2)
r = radius of the tube (1.9/2 = 0.95 mm = 0.00095 m)
Substituting the given values and solving for T, we get:
T = (hρgr)/(2cosθr)
= (0.005 m)(960 kg/m³)(9.81 m/s²)(0.00095 m)/(2cos(15°)(0.00095 m))
= 0.041 N/m
Therefore, the surface tension of the liquid is 0.041 N/m.
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Which of the following is a true statement concerning the production of electricity in conventional nuclear power plants using fission reactors?
A. New nuclear power plants will be built without containment structures, due to the increased insulation in the reactor core.
B. Thermal energy is converted into mechanical energy and then to electrical energy, as in coal-burning power plants.
C. Regularly scheduled releases of radioactive gases during production are well below the maximum contamination levels set by the EPA (Environmental Protection Agency).
D. Nuclear production of electricity is much less expensive per kilowatt-hour than production of electricity at a coal-burning or natural- gas-fueled power plant.
E. Storage of nuclear waste is no longer an issue, because power plants are now storing all wastes on-site in specialized containment units.
Thermal energy is converted into mechanical energy and then to electrical energy, as in coal-burning power plants.
What is Thermal energy?The movement and transfer of heat energy is the focus of the specific subfield of thermal engineering in mechanical engineering. The energy can be changed into different types of energy or transported between two different media.The movement and transfer of heat energy is the focus of the specific subfield of thermal engineering in mechanical engineering. The energy can be changed into different types of energy or transported between two different media. Thermal engineering focuses on heat transfer, fluid mechanics, and heating and cooling systems, such as those used in the electric power business, the automotive industry, and the heating, ventilation, and air conditioning (HVAC) industry. Thermal energy is the motion of molecules within a material or an item.To learn more about Thermal energy refer to:
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There are 4 types of Mechanical weathering we'll focus on: 1) exfoliation, 2) Frost wedging, 3) Salt wedging, and 4) Biomechanical.
Read the text on each of these and match the following:
Tree roots that crack and fracture rock.
Answer 1Choose...Frost wedgingSalt wedgingExfoliationBiomechanical
Salt crystals collect in small cracks in rocks. As salt crystals grow they push the minerals in the rock apart to form small holes!
Answer 2Choose...Frost wedgingSalt wedgingExfoliationBiomechanical
Figure 5.1.5 shows which type of mechanical weathering?
Answer 3Choose...Frost wedgingSalt wedgingExfoliationBiomechanical
Water collects in cracks in rock. When it gets cold the water freezes, expands and cracks the rock even more. Then the ice thaws and the rock cracks and fractures even more.
Answer 4Choose...Frost wedgingSalt wedgingExfoliationBiomechanical
Figure 5.1.1 shows which type of mechanical weathering?
Answer 5Choose...Frost wedgingSalt wedgingExfoliationBiomechanical
Animals that crack and fracture rock.
Answer 6Choose...Frost wedgingSalt wedgingExfoliationBiomechanical
How pot-holes in our streets of Rock Island are formed, is due to which type of mechanical weathering?!
Answer 7Choose...Frost wedgingSalt wedgingExfoliationBiomechanical
Granite (an intrusive igneous rock!) is uplifted and exposed at the surface - so pressure is reduced and the rock fractures.
Answer 8Choose...Frost wedgingSalt wedgingExfoliationBiomechanical
Figure 5.1.6 shows which type of mechanical weathering?
Answer 9Choose...Frost wedgingSalt wedgingExfoliationBiomechanical
Figure 5.1.3 shows which type of mechanical weathering?
Biomechanical weathering occurs when tree roots exert pressure on rocks, causing them to crack and fracture.
Biomechanical weathering is a type of mechanical weathering caused by living organisms, particularly plants and animals. In the case of tree roots, as they grow and expand, they can exert significant pressure on rocks. This pressure can cause the rocks to crack and fracture, leading to the breakdown of the rock over time. Tree roots are particularly effective at exploiting existing cracks and crevices in the rocks, widening them through their growth. Eventually, this process can lead to the disintegration of rocks into smaller fragments, contributing to the overall weathering of the landscape.
Biomechanical weathering is a slow but continuous process that occurs over extended periods. It is an important factor in the physical breakdown of rocks, especially in environments where vegetation is prevalent. By exerting mechanical stress on rocks, tree roots and other organisms actively contribute to the fragmentation and erosion of the Earth's surface.
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Discuss types of environmental hazards and impact of the environmental hazards.
An environmental hazard is a substance, state or event which has the potential to threaten the surrounding natural environment and/or adversely affect human's health. This term incorporates topics like pollution, natural disasters and human-made hazards. Health studies investigate the human health effects of exposure to environmental hazards ranging from chemical pollutants to natural, technological or terrorist disasters. The environment in which we live can be considered as having three fundamental sets of components, physical, chemical, biological. Associations between an exposure and an adverse health effect do not, on their own, prove that the former is the cause of the latter. Many other non-causal associations could explain the findings. Physical hazards involve environmental hazards that can cause harm with or without contact. Examples are earthquakes, electromagnetic fields, floods, light pollution, noise pollution, vibration, x-rays etc. Radioactivity is associated with an exposure dependent risk of some cancers notably leukaemia. The scientific evidence of adverse health effects from general environmental exposure to these fields is "not proven". If there are adverse effects yet to be proven, the risk is probably likely to be small. Chemical substances cause significant damage to the environment. Tobacco smoke is the single biggest known airborne chemical risk to health, whether measured in terms of death rates or ill-health. To a much lesser degree of risk, these adverse effects apply to non-smokers exposed passively to sidestream tobacco smoke. Health effects of concern are asthma, bronchitis, lung cancer and similar lung diseases, and there is good evidence relating an increased risk of symptoms of these diseases with increasing concentration of Sulphur dioxide, ozone and other pollutants. Biohazards generally fall into two broad categories: those which produce adverse health effects through infection (microorganisms, viruses or toxins) and those which produce adverse effects in non-infective (allergic) ways.
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Kinetic energy kx is 1/2mvx2. evaluate the mean square kinetic energy < kx2 >in one dimension for n2 molecules at 25°c (hint: in the derivation of < kx2 > use f (vx.) )
The mean kinetic energy of the N₂ molecules at 25 °C is 3593.519 joules per mole.
How to estimate the mean square kinetic energy associated to gas molecules
Let suppose that the gas sample behaves ideally. The Graham's law establishes a connection between the ideal gas model and the kinetic theory of gases.
In this question we need to use this law to estimate the average kinetic energy (Kₐ), in joules per mole, of a diatomic gas (N₂), which is defined by the following expression:
\(K_{a} = \frac{3}{2}\cdot R_{u}\cdot T\) (1)
Where:
\(R_{u}\) - Ideal gas constant, in joules per mole-Kelvin.\(T\) - Temperature, in KelvinIf we know that \(R_{u} = 8.314\,\frac{J}{mol\cdot K}\) and \(T = 288.15\,K\), then the average kinetic energy is:
\(K_{a} = \frac{3}{2}\cdot \left(8.314\,\frac{J}{mol\cdot K} \right) \cdot (288.15\,K)\)
\(K_{a} = 3593.519\,\frac{J}{mol}\)
The mean kinetic energy of the N₂ molecules at 25 °C is 3593.519 joules per mole. \(\blacksquare\)
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Compare automation and autonomous
Answer:
Automation generally means “a process performed without human assistance”, while autonomy implies “satisfactory performance under significant uncertainties in the environment and the ability to compensate for system failures without external intervention [emphasis mine].”
Explanation:
The boost converter of Fig. 6-8 has parameter Vs 20 V, D 0.6, R 12.5 , L 10 H, C 40 F, and the switching frequency is 200 kHz. (a) Determine the output voltage. (b) Determine the average, maximum, and minimum inductor currents. (c) Determine the output voltage ripple. (d) Determine the average current in the diode. Assume ideal components.
Answer:
a) the output voltage is 50 V
b)
- the average inductor current is 10 A
- the maximum inductor current is 13 A
- the maximum inductor current is 7 A
c) the output voltage ripple is 0.006 or 0.6%V₀
d) the average current in the diode under ideal components is 4 A
Explanation:
Given the data in the question;
a) the output voltage
V₀ = V\(_s\)/( 1 - D )
given that; V\(_s\) = 20 V, D = 0.6
we substitute
V₀ = 20 / ( 1 - 0.6 )
V₀ = 20 / 0.4
V₀ = 50 V
Therefore, the output voltage is 50 V
b)
- the average inductor current
\(I_L\) = V\(_s\) / ( 1 - D )²R
given that R = 12.5 Ω, V\(_s\) = 20 V, D = 0.6
we substitute
\(I_L\) = 20 / (( 1 - 0.6 )² × 12.5)
\(I_L\) = 20 / (( 0.4)² × 12.5)
\(I_L\) = 20 / ( 0.16 × 12.5 )
\(I_L\) = 20 / 2
\(I_L\) = 10 A
Therefore, the average inductor current is 10 A
- the maximum inductor current
\(I_{Lmax\) = [V\(_s\) / ( 1 - D )²R] + [ V
given that, R = 12.5 Ω, V\(_s\) = 20 V, D = 0.6, L = 10 μH, T = 1/200 kHz = 5 hz
we substitute
\(I_{Lmax\) = [20 / (( 1 - 0.6 )² × 12.5)] + [ (20 × 0.6 × 5) / (2 × 10) ]
\(I_{Lmax\) = [20 / 2 ] + [ 60 / 20 ]
\(I_{Lmax\) = 10 + 3
\(I_{Lmax\) = 13 A
Therefore, the maximum inductor current is 13 A
- The minimum inductor current
\(I_{Lmax\) = [V\(_s\) / ( 1 - D )²R] - [ V
given that, R = 12.5 Ω, V\(_s\) = 20 V, D = 0.6, L = 10 μH, T = 1/200 kHz = 5 hz
we substitute
\(I_{Lmin\) = [20 / (( 1 - 0.6 )² × 12.5)] - [ (20 × 0.6 × 5) / (2 × 10) ]
\(I_{Lmin\) = [20 / 2 ] -[ 60 / 20 ]
\(I_{Lmin\) = 10 - 3
\(I_{Lmin\) = 7 A
Therefore, the maximum inductor current is 7 A
c) the output voltage ripple
ΔV₀/V₀ = D/RCf
given that; R = 12.5 Ω, C = 40 μF = 40 × 10⁻⁶ F, D = 0.6, f = 200 Khz = 2 × 10⁵ Hz
we substitute
ΔV₀/V₀ = 0.6 / (12.5 × (40 × 10⁻⁶) × (2 × 10⁵) )
ΔV₀/V₀ = 0.6 / 100
ΔV₀/V₀ = 0.006 or 0.6%V₀
Therefore, the output voltage ripple is 0.006 or 0.6%V₀
d) the average current in the diode under ideal components;
under ideal components; diode current = output current
hence the diode current will be;
\(I_D\) = V₀/R
as V₀ = 50 V and R = 12.5 Ω
we substitute
\(I_D\) = 50 / 12.5
\(I_D\) = 4 A
Therefore, the average current in the diode under ideal components is 4 A
Using the correlation for the second virial coefficient (Pitzer correlation), find the molar volume of acetylene vapour at 247.1 K and 13.5 bar, giving your answer to the nearest cm3/mol. The critical temperature is 308.3 K and the critical pressure of acetylene is 61.39 bar. Take R = 8.314 J/mol-K and the acentric factor for acetylene is 0.187.
The molar volume of acetylene vapor at 247.1 K and 13.5 bar, using the Pitzer correlation for the second virial coefficient, is approximately 72.5 cm3/mol.
Explanation:
The Pitzer correlation can be used to estimate the second virial coefficient of a gas. The equation is given by B = (RTc)/(Pc) * (1 + m(1 - (T/Tc)^(0.5))) where B is the second virial coefficient, R is the ideal gas constant, Tc is the critical temperature, Pc is the critical pressure, T is the temperature, and m is the acentric factor.
Plugging in the given values and solving for B, we get B = -0.009413 m3/mol. Then, using the ideal gas law, V = RT/P, we can calculate the molar volume as V = (RT)/P = (8.314 J/mol-K * 247.1 K) / (13.5 bar * 10^5 Pa/bar) ≈ 0.0725 m3/mol ≈ 72.5 cm3/mol.
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state two disadvantages and two advantages of a simple manometer.
1. a major reason for the projected shortage of trained craft professionals is
a. construction salaries are too low
b. technology has eliminated many construction careers
c. demand for construction projects is declining
d. the retirement of baby boomers
A major reason for the projected shortage of trained craft professionals is that: b. technology has eliminated many construction careers.
What is computing?Autonomic computing can be defined as a process which involves the use of both computer hardware and software to manage, analyze, and process, so as to complete a goal-oriented task.
Also, autonomic computing systems are self-managing and it is similar in operations with the autonomic nervous system in humans, and as such it can be used in construction projects and assembly lines for optimum automated production.
In conclusion, automation technology through robots, smart machines and computers has reduced the need for people in many jobs, including trained craft professionals.
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read each of the following descriptions. match each description to one of the zone control system types listed. provides cooling only and the air handlers are not constantly operating at full capacity. answer 1 choose... provides temperature and humidity control for multiple zones and includes a cooling coil at the air handling unit and then a heating coil is located in each zone to provide the required temperature for that zone. answer 2 choose... serves very large buildings with many zones and is flexible to allow for easy expansion. answer 3 choose... warmed and cooled air flows through separate duct systems and mixes the warmed and cooled air together in a terminal located in a space. answer 4 choose... a system that uses refrigerant coils and does not need ductwork. answer 5 choose...
The correct answer is: 1, 2, 4. provides cooling only and the air handlers are not constantly operating at full capacity.
What is capacity?
Capacity refers to your capacity or the volume that something can hold. If your bird cage is already full, adding another bird won't prevent the bird from developing claustrophobia. "Breadth" and "capacity" are the meanings of the Latin word capacitatem. A room's capacity to hold a certain number of people, a law's ability to reduce crime rates, or your capacity to learn new languages are all examples of capacity as a noun, which simply means "ability" or "capability." You may hear about factories operating at "full capacity," which refers to operating at maximum speed and output.
Serves very large structures with numerous zones and is adaptable to facilitate simple expansion. warmed and cooled air flows through separate duct systems and mixes the warmed and cooled air together in a terminal located in a space.
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Tech A says that radial ply tires have much more flexible sidewalls than bias-ply tires because of their construction. Tech B says that bias-ply tires have a more durable construction than radial tires. Who is correct?
Answer:
Tech A and Tech B are correct
Explanation:
Tech A is correct because radial ply tires have more flexible sidewalls than radial tires due to the fact that radial tires make use of two or more layers of casing piles and are thus not much flexible.
Also, tech B is correct because bias-ply tires typically have more durable construction than radial tires
an aerial photograph taken at 3000m above ground surface, the top and bottom distances of a telecommunication tower are 4.65cm and 4.5cm from the principal point, the bottom of the tower is 2700 above mean sea level.
determine tower height.
what is non demilitarized zone and what devices comprise its establishment?
A non-demilitarized zone (DMZ) is an area or region that is designated as a neutral or buffer zone between two conflicting or potentially hostile entities, often countries or territories. The purpose of establishing a non-DMZ is to create a physical barrier and reduce the risk of military conflict or aggression between the entities involved.
Devices that typically comprise the establishment of a non-DMZ can include:
Fences or Barriers: Physical barriers such as walls, fences, or other structures are often erected to clearly demarcate the boundaries of the non-DMZ. These barriers can help prevent unauthorized entry and maintain separation between the conflicting parties. Observation Posts: Observation posts are manned stations or surveillance systems strategically placed within the non-DMZ to monitor activities and movements. These posts may include personnel, surveillance cameras, radar systems, or other monitoring devices.Checkpoints: Checkpoints are designated areas where personnel or vehicles entering or exiting the non-DMZ are subjected to scrutiny and inspection. They serve as control points to regulate access and ensure compliance with established rules and regulations.Security Forces: Security forces, such as military or law enforcement personnel, may be stationed within the non-DMZ to maintain order, enforce regulations, and respond to any potential security threats. They play a crucial role in preventing unauthorized activities and maintaining the stability of the non-DMZ.Communication Systems: Effective communication systems, including wired or wireless networks, are essential for coordinating activities and sharing information within the non-DMZ. These systems enable real-time communication between the entities involved and facilitate efficient coordination of security measures.Warning Devices: Warning devices, such as sirens, alarms, or notification systems, may be installed to alert personnel of any breach or security concerns within the non-DMZ. These devices provide early warning and allow for timely response to potential threats.It's important to note that the specific devices and measures implemented in a non-DMZ can vary depending on the context, the entities involved, and the nature of the conflict or potential risks. The goal is to establish a secure and controlled zone that promotes stability and reduces the likelihood of military confrontations or aggression.
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A horizontal turbine takes in steam with an enthalpy of h = 2.80 MJ/kg at 45 m/s. A steam-water mixture exits the turbine with an enthalpy of h = 1.55 MJ/kg at 20 m/s. If the heat loss to the surroundings from the turbine is 300 J/s, determine the power the fluid supplies to the turbine. The mass flow rate is 0.85 kg/s.
Answer:
The power that fluid supplies to the turbine is 1752.825 kilowatts.
Explanation:
A turbine is a device that works usually at steady state. Given that heat losses exists and changes in kinetic energy are not negligible, the following expression allows us to determine the power supplied by the fluid to the turbine by the First Law of Thermodynamics:
\(-\dot Q_{loss} - \dot W_{out} + \dot m \cdot \left[(h_{in}-h_{out}) + \frac{1}{2}\cdot (v_{in}^{2}-v_{out}^{2}) \right] = 0\)
Output power is cleared:
\(\dot W_{out} = -\dot Q_{loss} + \dot m \cdot \left[(h_{in}-h_{out})+\frac{1}{2}\cdot (v_{in}^{2}-v_{out}^{2}) \right]\)
If \(\dot Q_{loss} = 0.3\,kW\), \(\dot m = 0.85\,\frac{kg}{s}\), \(h_{in} = 2800\,\frac{kJ}{kg}\), \(h_{out} = 1550\,\frac{kJ}{kg}\), \(v_{in} = 45\,\frac{m}{s}\) and \(v_{out} = 20\,\frac{m}{s}\), then:
\(\dot W_{out} = -0.3\,kW + \left(0.85\,\frac{kg}{s} \right)\cdot \left\{\left(2800\,\frac{kJ}{kg}-1550\,\frac{kJ}{kg} \right)+\frac{1}{2}\cdot \left[\left(45\,\frac{m}{s} \right)^{2}-\left(20\,\frac{m}{s} \right)^{2}\right] \right\}\)
\(\dot W_{out} = 1752.825\,kW\)
The power that fluid supplies to the turbine is 1752.825 kilowatts.
An amount P is deposited now so that an equal annual amount of A1=2000 per year for the first 5 years, starting 1year after the deposit. And a different annual withdrawal of A2= 3000 per year for the following 3 years. Draw the cash flow diagram if i=8.5% per year.
Based on the amounts to be withdrawn over the years and the interest rate, the amount deposited now is $12,977.
How much is deposited now?This can be found as:
= (2,000 x Present value of annuity interest factor, 8.5%, 5 years) + (3,000 x Present value of annuity interest factor, 8.5%, 8 years) - (P/A, 8.5%, 5 years)
= (2,000 x 3.9406) + (3,000 x (5.6392 - 3.94064))
= $12,977
The cashflow diagram is attached.
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1. The only purpose of a personal fall arrest system is to
A) Keep workers from falling
B) Hoist materials
C) Avoid having to use a
net
D)All of the above
✅C) Avoid having to use a net ✅
IamSugarBee
are there any companies that you can get a job at as an air craft engeer after university
Explanation:
most big airports. my father has the same degree and works for southwest airlines
You have a 12-inch PVC water main that is 850 feet long flowing at 5.6 cfs. Point A is at an elevation of 750 ft. Point B is at an elevation of 765 ft. If the pressure in a water main at Point A is 85 psi, what is the pressure at point B, in psi? (5 points)
Known :
D = 12 in = 1 ft
L = 850 ft
Q = 5.6 cfs
hA = 750 ft
hB = 765 ft
PA = 85 psi = 12240 lb/ft²
Solution :
A = πD² / 4 = π(1²) / 4
A = 0.785 ft²
Velocity of water :
U = Q / A = 5.6 / 0.785
U = 7.134 ft/s
Friction loss due to pipe length :
Re = UD / v = (7.134)(1) / (0.511 × 10^(-5))
Re = 1.4 × 10⁶
(From Moody Chart, We Get f = 0.015)
hf = f(L / d)(U² / 2g) = 0.015(850 / 1)((7.134²) / 2(32.2))
hf = 10 ft
PA + γhA = PB + γhB + γhf
PB = PA + γ(hA - hB - hf)
PB = 12240 + (62.4)(750 - 765 - 10)
PB = 10680 lb/ft²
PB = 74.167 psi
Vapor lock occurs when the gasoline is cooled and forms a gel, preventing fuel flow and
engine operation. TRUE or FALSE
Answer:
True
Explanation:
Ohm's law states that the current (I) in amps equals the voltage (E) in volts decided by the resistance (R) in ohm's. If you connected a 2 megohm resistor (2•10^6 ohms)across a 2.4 kilovolt voltage source (2.4•10^3 volts ) , what would be the currents amps ?
Answer:
1.14 * 10^-3 amperes
Explanation:
According to ohms law
V = IR ---- ( 1 )
V = voltage = 2.4 * 10^3 v
I = current = ?
R = resistance = 2.1 * 10^6 Ω
from equation 1
I = V / R
= ( 2.4 * 10^3 ) / (2.1 * 10^6 )
= 1.14 * 10^-3 amperes
a) For Well A, provide a cross-section sketch that shows (i) ground elevation, (ii) casing height, (iii) depth to
water table, (iv) sampling depth, (v) elevation of the well top of casing, (vi) water table elevation, (vii) elevation
head of the water sampled for bromide, and (viii) pressure head of the water sampled for bromide. Label each of
these distances with the above phrases, plus a unique variable.
b) Calculate the following for each well: (i) elevation of the well top of casing, (ii) water table elevation,
(iii) sampling port elevation, (iv) elevation head of the water sampled for bromide, and (v) pressure head of the
water sampled for bromide. Use sea level as your vertical datum. Write out all calculations (including equations
with variables) for Well A.
Q1-What is Polling? Discuss at least two disadvantages of polling?
Q2-What is memory interleaving? How it’s used for performance enhancements?
Answer:
Explanation:
Q1: Polling is a method of computer programming where a program repeatedly checks a specific location in memory for new data or an event to occur. This is often done in a loop, where the program continuously checks for new data or an event until it occurs.
Two disadvantages of polling are:
It can be inefficient, as the program must continuously check for new data or an event, which can consume a lot of processing power.
It can also lead to missed events or data, as the program may not be checking at the exact moment when the event or data occurs.
Q2: Memory interleaving is a technique used to improve the performance of computer memory systems by spreading data across multiple memory modules. This is done by interleaving the memory addresses so that data is spread evenly across all the modules, rather than being stored in one module.
This technique is used for performance enhancements because it allows for faster access to data by allowing multiple memory modules to be accessed at the same time, rather than having to access data from one module at a time. This results in faster data transfer rates and improved system performance. Additionally, memory interleaving can also improve the reliability of a system by spreading data across multiple memory modules, which reduces the risk of data loss in the event of a module failure.
If you see cars parked on both sides of the road facing the same direction that means?
If you see cars parked on both sides of the road facing the same direction that means they have one direction of travel, and that it is seen as a one-way street.
What is the rule of the one-way street?The rule states that if Cars parked are known to be facing the same direction on both ends of the street, it clearly shows the direction of travel, as well as the fact that it is a one-way street.
Note that a lot of people do not always follows the rules about the right direction they can park on a public street. Cars that are parked in both opposing directions connote the fact that the street should be two-way.
Therefore, If you see cars parked on both sides of the road facing the same direction that means they have one direction of travel, and that it is seen as a one-way street.
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n order to test whether camshafts are being manufactured to specification a sample of n = 35 camshafts are selected at random. The average value of the sample is calculated to be 4.44 mm and the depths of the camshafts in the sample vary by a standard deviation of s = 0.34 mm. Test the hypotheses selected previously, by filling in the blanks in the following: An estimate of the population mean is 4.44 . The standard error is 0.06 . The distribution is normal (examples: normal / t12 / chisquare4 / F5,6). The test statistic has value TS= . Testing at significance level α = 0.01, the rejection region is: less than and greater than (2 dec places). Since the test statistic (is in/is not in) the rejection region, there (is evidence/is no evidence) to reject the null hypothesis, H0. There (is sufficient/is insufficient) evidence to suggest that the average hardness depth, μ, is different to 4.5 mm. Were any assumptions required in order for this inference to be valid? a: No - the Central Limit Theorem applies, which states the sampling distribution is normal for any population distribution. b: Yes - the population distribution must be normally distributed.
A centimeter is Viooth of a meter, while a kilo-
meter is equal to 1000 meters.
a. True
b. False
Answer:
b. False
Explanation:
A centimeter is a hundredth of a meter. This means 1/100 ,1 cm = 0.01 m
A kilo is 1000 grams.
The first answer is false because a hundredth isnot written well.
The second statement is false because the comparison given is of different units of measure. For distance is meters where as for weight is kilograms.
technician a says liquid cooling an engine maintains a constant operating temperature. technician b says that air cooling lets the engine operate more efficiently. who is correct?
Technician A is correct. The liquid cooling an engine maintains a constant operating temperature. Technician B is wrong because the usage of air condition can increase fuel consumption by up to 20%.
Component of systems are a radiator to dissipate heat, a fan or fans to ensure adequate airflow for radiator cooling, a thermostat valve that opens when the desired operating temperature is reached and a water pump (or coolant pump) to circulate coolant through the engine, hoses and other elements. The engine cooling system has responsible for holding it at a stable temperature to avoid damage to the vehicle. There are two kind of cooling systems for engines:
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You are a designer of a new processor. You have to choose between two possible implementations (called M1 and M2) of the same architecture. a. Machine M1 has a clock rate of 2.8 GHz and the following characteristics:Instruction classes CPI (Clocks per instruction) for each Instruction classes Frequency A 1 40% B 3 25%C 3 25%D 5 10%Instruction classes CPI (Clocks per instruction) Frequency A 2 40%B 2 20% C 3 15%D 4 25%Required:a. What is the CPI for each machine? b. What are the native MIPS ratings for M1 and M2? c. Which machine has a better by the MIPS performance (by comparing their MIPS values) and by how much?
Answer:
A ) CPI : M1 = 2.4 , M2 = 2.65
B ) MIPS : M1 = 1083, M2 = 1056
C ) The machine that has a better performance based on MIPS is M1 and this is by 27 million number of instructions per sec
Explanation:
A) The CPI for each machine
CPI = ( Total number of execution cycles ) / ( instruction counter executed )
For Machine 1 ( M1 )
we have to make some assumptions : number of instructions = 10
number of times A was executed = 4 , Number of times B was executed = 2.5 , number of times C was executed = 2.5, Number of times D was executed = 1. and this was based on the frequency given above
hence CPI for M1 =[ ( 1 * 4 ) + ( 3 * 2.5 ) + ( 3 * 2.5 ) + ( 5 * 1 ) ] / 10
CPI for M1 = 2.4
For Machine 2 ( M2 )
we have to make some assumptions : number of instructions = 10
number of times A was executed = 4 , Number of times B was executed = 2. number of times C was executed = 1.5, Number of times D was executed = 2.5 times. and this was based on the frequency given above
Hence CPI for M1 = [ ( 2 * 4 ) + ( 2 * 2 ) + ( 3 * 1.5 ) + ( 4 * 2.5 ) ] / 10
CPI for M2 = 2.65
B ) Calculate the native MIPS ratings for M1 and M2
MIPS = ( instruction counts ) / ( Execution time * 10^6 )
For M1
Assumptions : number of instructions executed = 10
each clock cycle = 0.3846 * 10^-9. frequency = 2.6 Ghz
first we calculate the total execution time which is equal to :
= [ ( 1 * 4 ) + ( 3 * 2.5 ) + ( 3 * 2.5 ) + ( 5 * 1 ) ] * 0.3846 * 10 ^-9
= 9.2304 * 10 ^-9 secs
therefore the MIPS for M1
= 10 / ( 9.2304 * 10^-9 ) * 10^6 = 1083
For M2
Assumptions : number of instructions executed = 10
each clock cycle = 0.3846 * 10^-9. frequency = 2.8 Ghz
first we calculate the total execution time which is equal to :
= [ (2*4) + (2*2) + (3 * 1.5 ) + ( 4 * 2.5 ) ] * 0.3846 * 10^-9 = 9.4631 * 10^-9 secs
therefor the MIPS for M2
= 10 / ( 9.4631*10^-9) * 10^6 = 1056
C ) The machine that has a better performance based on MIPS is M1 and this is by 27 million number of instructions per sec
build this assembly in solidworks it contains 3 machined brackets and 2 pins brackets 2mm thickness and equal size holes through all material 6061 alloy density 0.0027g mm 3 the top edge of the notch is located 20 mm from the top
To build the given assembly in Solidworks, follow these steps:
Step 1: Create a new assembly in Solidworks.
Step 2: In the assembly, select the Front plane and create a new sketch.
Step 3: Draw the first bracket by selecting the Rectangle tool from the Sketch tab and then selecting the Smart Dimension tool to add dimensions to the sketch.
The first bracket will be 100mm x 50mm, with holes of 5mm diameter located 10mm from each edge. The thickness of the bracket will be 2mm.
Step 4: Extrude the first bracket sketch by selecting the Extruded Boss/Base tool. Enter 2mm as the extrude depth.
Step 5: Create a new sketch on the top plane of the first bracket.
Step 6: Draw a circle of 2.5mm diameter in the center of the new sketch and extrude it by 2mm.
Step 7: Now, select the bottom face of the first bracket and create a new sketch.
Step 8: Draw the second bracket sketch in the new sketch. The second bracket will be identical to the first bracket.
Step 9: Extrude the second bracket sketch by 2mm.
Step 10: Now, select the right face of the first bracket and create a new sketch.
Step 11: Draw the third bracket sketch in the new sketch. The third bracket will be identical to the first and second brackets.
Step 12: Extrude the third bracket sketch by 2mm.Step 13: Now, select the top face of the second bracket and create a new sketch.
Step 14: Draw a circle of 2.5mm diameter in the center of the new sketch and extrude it by 10mm.Step 15: Now, select the bottom face of the third bracket and create a new sketch.
Step 16: Draw a circle of 2.5mm diameter in the center of the new sketch and extrude it by 10mm.
Step 17: Now, insert two pins with 5mm diameter and 20mm length in the holes of the brackets.
Step 18: Finally, save the assembly.The assembly contains 3 machined brackets and 2 pins. The brackets have a thickness of 2mm and equal size holes through all material. The material used is 6061 alloy with a density of 0.0027g/mm3. The top edge of the notch is located 20mm from the top.
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What lives at layer 3 (the network layer) of the OSI model?
Layer 3 of the OSI (Open Systems Interconnection) model, known as the network layer, is responsible for providing end-to-end communication between hosts in different networks.
The network layer is responsible for routing and forwarding data packets across different networks, as well as handling addressing and logical connectivity.
The main entities that live at layer 3 (the network layer) of the OSI model include:
Routers: Routers are network devices that operate at the network layer and are responsible for forwarding data packets between different networks. They use routing tables and protocols to determine the best path for data packets to reach their destination across multiple networks.
IP (Internet Protocol): IP is a network layer protocol that provides logical addressing and routing functionality. It is responsible for assigning unique IP addresses to devices on a network, and for routing data packets based on those IP addresses.
ICMP (Internet Control Message Protocol): ICMP is a network layer protocol that is used for sending error messages and operational information about network conditions. It is often used for diagnostic purposes, such as ping and traceroute, to check the connectivity and status of network devices.
Network Addressing: Layer 3 is also responsible for assigning and managing IP addresses, which are used to uniquely identify devices on a network.
Subnetting and VLANs: Layer 3 may also involve subnetting and VLANs (Virtual Local Area Networks), which are used for network segmentation and management to improve efficiency and security.
In summary, layer 3 of the OSI model includes routers, IP, ICMP, network addressing, and other protocols and technologies that are responsible for routing, addressing, and logical connectivity in a network.
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