CH3CH2CH2CH2CH3

Balanced chemical equation for this

When hydrogen bromide (HBr) is added to 2-methylbut-2-ene ((CH3)2CCHCH3), an electrophilic addition reaction takes place, where the π bond of the alkene is broken, and the hydrogen and bromine atoms are added to the resulting carbocation.

The reaction proceeds through a Markovnikov addition, where the hydrogen atom attaches to the carbon atom with the greater number of hydrogen atoms.

In this case, the initial addition of HBr to 2-methylbut-2-ene leads to the formation of a primary carbocation, as the positively charged carbon atom only has one alkyl group attached to it. The primary carbocation is relatively unstable, and it can undergo a rearrangement to form a more stable secondary carbocation.

The major product that is typically obtained is the 2-bromo-2-methylbutane. The hydrogen atom from HBr adds to the carbon with three hydrogen atoms (the more substituted carbon), resulting in the formation of a secondary carbocation.

On the other hand, a minor product is also formed, which is 3-bromo-2-methylbutane. This product arises from the addition of HBr to the primary carbocation, which is less stable. Although the primary carbocation is less favored, it can still be formed and lead to the formation of the minor product.

In summary, the addition of HBr to 2-methylbut-2-ene yields two products: the major product is 2-bromo-2-methylbutane, resulting from the addition of HBr to the more stable secondary carbocation, and the minor product is 3-bromo-2-methylbutane, originating from the less stable primary carbocation.

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Explanation:

Dilution refers to the process of preparing a lower concentration solution from higher concentrations. Thus, the volume of the solution of interest is combined with the appropriate volume of solvent, reaching the desired concentration.

Therefore, the dilution factor is the total number of volumes your material will be dissolved in.

Dilution solutions are a necessary process in the laboratory, as stock solutions are often purchased and stored in very concentrated forms.

In order for solutions to be used (in a titration, for example), they must be precisely diluted, obtaining a known, lower concentration.

The preparation of solutions from liquid solute should follow the following order:

1. Measure the solute volume;

2. Quantitatively transfer to the volumetric flask;

3. Makeup to volume with solvent;

4. Homogenize the solution;

5. Store the solutions in suitable, labeled containers.

Answer: 1. Measure the solute volume;

2. Quantitatively transfer to the volumetric flask;

3. Makeup to volume with solvent;

4. Homogenize the solution;

5. Store the solutions in suitable, labeled containers.

Answer:

False.

Explanation:

I majored in Chemistry

Answer:

The reaction between carbon (C) and water (H2O) forms carbon monoxide (CO) and hydrogen gas (H2). The balanced chemical equation for this reaction is:

C(s) + H2O(g) -> CO(g) + H2(g)

According to this balanced equation, one mole of carbon reacts with one mole of water to produce one mole of carbon monoxide and one mole of hydrogen gas.

First, calculate the number of moles of carbon in 34 grams. The molar mass of carbon is approximately 12.01 grams/mole.

Moles of carbon = 34 grams / 12.01 grams/mole = 2.831 moles

As the stoichiometry of the reaction shows a 1:1 ratio between carbon and hydrogen, the moles of hydrogen produced would also be 2.831 moles.

The molar mass of hydrogen (H2) is approximately 2 grams/mole.

So, the mass of hydrogen produced = 2.831 moles * 2 grams/mole = 5.662 grams

Therefore, if 34 grams of carbon reacts with an unlimited amount of water, approximately 5.66 grams of hydrogen gas would be formed.

Explanation:

Approximations followed for answer.

Due to comparable differences in electronegativity of different elements, partial positive and negative charges developed, hence polarity designated in a molecule.

The terms "polar" and "nonpolar" normally seek advice from covalent bonds. To determine the polarity of a covalent bond the usage of a numerical manner, find the distinction among the electronegativity of the atoms; if the end result is between 0.4 and 1.7, then, generally, the bond is polar covalent.

When the atoms linked by way of a covalent bond are distinct, the bonding electrons are shared, however now not similar. rather, the bonding electrons are extra attracted to at least one atom than the alternative, giving upward thrust to a shift of electron density closer to that atom.

This unequal distribution of electrons is referred to as a polar covalent bond, characterized by means of a partial nice fee on one atom and a partial negative price on the other. The atom that attracts the electrons extra strongly acquires the partial poor fee and vice versa.

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Answer:

Specific Heat Capacity

Answer:

Your mom

Explanation:

Julie I think that this is the most easiest  question someone has every asked in my whole entire life. I think you should really go to a lower class and will benefit you more. I wish you some what of some success!!!!

Mass of the object is 5.6196 * 10^4 g.

The term density has to do with the ratio of the mass to the volume of a substance. The density is an intrinsic property of a substance which could be used to identify a substance.

Mass of the substances = ?

Volume of the substance = 20. cm x 20.0 cm x 70.0 cm =28000 cm^3

Density of the substance = 2.007 g/cm3

Density = mass/volume

mass = density * volume

mass = 2.007 g/cm3  * 28000 cm^3

mass = 5.6196 * 10^4 g

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Answer:

D, E,C, A,F,B

Explanation:

Answer:

Filter it

Explanation:

hope it's helpful

Explanation:

its is classified as ionic cyrstal

The complete Lewis electron-dot diagram for ethyne is shown in the attached diagram below:

A lewis electron dot structure can be utilized to represent the number of bonds, the lone pairs left in the atoms, and the bonding atoms in the molecule.

Solid lines are used to represent the bonds between atoms that are directly bonded to one another and excess electrons are denoted as dot pairs and are represented next to the atoms.

As the valence electrons of each carbon atom are equal to 4 from the electronic configuration of the carbon atom. First, the total number of valence electrons in a molecule is 4 + 1 + 1 + 4 = 10.

As each carbon atom needs only 4 electrons to complete its octet. As the octet completes, the rest of the electrons are assigned as the lone pairs of atoms. But there are no lone pairs in the molecule of the ethyne.

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Answer:

22 neutrons

Explanation:

If so please sorry

Answer:

4.76

Explanation:

In this case, we have to start with the buffer system:

\(CH_3COOH~->~CH_3COO^-~+~H^+\)

We have an acid (\(CH_3COOH\)) and a base (\(CH_3COO^-\)). Therefore we can write the henderson-hasselbach reaction:

\(pH~=~pKa+Log\frac{[CH_3COO^-]}{[CH_3COOH]}\)

If we want to calculate the pH, we have to calculate the pKa:

\(pH=-Log~Ka=4.76\)

According to the problem, we have the same concentration for the acid and the base 0.1M. Therefore:

\([CH_3COO^-]=[CH_3COOH]\)

If we divide:

\(\frac{[CH_3COO^-]}{[CH_3COOH]}~=~1\)

If we do the Log of 1:

\(Log~1=~zero\)

So:

\(pH~=~pKa\)

With this in mind, the pH is 4.76.

I hope it helps!

Answer:

huauususuuskkajsjjja

Answer: 4.88 g/mol. and helium

Explanation:

To find the molar mass of the gas, we can use the ideal gas law equation which is PV=nRT where:

P = pressure = 2.000 atm

V = volume = 50.00 L

n = number of moles

R = gas constant = 0.08206 L·atm/K·mol

T = temperature = 273.15 K

First, we need to find the number of moles of the gas:

PV = nRT

n = PV/RT

n = (2.000 atm)(50.00 L)/(0.08206 L·atm/K·mol)(273.15 K)

n = 1.844 mol

Now, we can find the molar mass of the gas by dividing its mass by the number of moles:

molar mass = mass/number of moles

mass = 9.00 g

molar mass = 9.00 g/1.844 mol

molar mass = 4.88 g/mol

Therefore, the molar mass of the gas is 4.88 g/mol.

To determine what gas this is, we can compare the molar mass of the gas to the molar masses of known gases. The molar mass of 4.88 g/mol is closest to that of helium (4.00 g/mol). Therefore, this gas is most likely helium.

Answer:

mass no = 70 amu

mass no = neutrons+ protons

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Explanation:

After the reaction is complete, no nitrogen and no hydrogen molecules remain, and 8.00 x 1014 molecules of NH3 are produced.

In the equation, nitrogen and hydrogen react at a high temperature, in the presence of a catalyst, to produce ammonia, according to the balanced chemical equation:N2(g)+3H2(g)⟶2NH3(g)The coefficients of each molecule suggest that one molecule of nitrogen reacts with three molecules of hydrogen to create two molecules of ammonia.

So, to determine how many molecules of ammonia are produced when four nitrogen and nine hydrogen molecules are present, we must first determine which of the two reactants is the limiting reactant.

To find the limiting reactant, the number of moles of each reactant present in the equation must be determined.

Calculations:
Nitrogen (N2) molecules = 4Hence, the number of moles of N2 = 4/6.02 x 1023 mol-1 = 6.64 x 10-24 mol
Hydrogen (H2) molecules = 9Hence, the number of moles of H2 = 9/6.02 x 1023 mol-1 = 1.50 x 10-23 mol

Now we have to calculate the number of moles of NH3 produced when the number of moles of nitrogen and hydrogen are known, i.e., mole ratio of N2 and H2 is 1:3.

The mole ratio of N2 to NH3 is 1:2; thus, for every 1 mole of N2 consumed, 2 moles of NH3 are produced.
The mole ratio of H2 to NH3 is 3:2; thus, for every 3 moles of H2 consumed, 2 moles of NH3 are produced.
From these mole ratios, it can be observed that the limiting reactant is nitrogen.

Calculation for NH3 production:
Nitrogen (N2) moles = 6.64 x 10-24 moles
The mole ratio of N2 to NH3 is 1:2; therefore, moles of NH3 produced is 2 × 6.64 × 10−24 = 1.33 × 10−23 moles.

Now, to determine how many molecules of NH3 are produced, we need to convert moles to molecules.
1 mole = 6.02 x 1023 molecules
Thus, 1.33 x 10-23 moles of NH3 = 8.00 x 1014 molecules of NH3 produced.

To find the amount of each reactant remaining after the reaction is complete, we must first determine how many moles of nitrogen are consumed, then how many moles of hydrogen are consumed, and then subtract these from the initial number of moles of each reactant.

The moles of nitrogen consumed = 4 moles × 1 mole/1 mole N2 × 2 mole NH3/1 mole N2 = 8 moles NH3
The moles of hydrogen consumed = 9 moles × 2 mole NH3/3 mole H2 × 2 mole NH3/1 mole N2 = 4 moles NH3
Thus, the moles of nitrogen remaining = 6.64 × 10−24 mol – 8 × 2/3 × 6.02 × 10^23 mol-1 = 5.06 × 10−24 mol
The moles of hydrogen remaining = 1.50 × 10−23 mol – 4 × 2/3 × 6.02 × 10^23 mol-1 = 8.77 × 10−24 mol

Finally, the number of molecules of each reactant remaining can be calculated as follows:
Number of N2 molecules remaining = 5.06 × 10−24 mol × 6.02 × 10^23 molecules/mol = 3.05 × 10−1 molecules ≈ 0 molecules
Number of H2 molecules remaining = 8.77 × 10−24 mol × 6.02 × 10^23 molecules/mol = 5.28 × 10−1 molecules ≈ 0 molecules.

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Answer:

CH3CH2CH2CH3 + Cl2 --------> CH3CH2CH2CH2Cl + HCl

Explanation:

Alkanes react with halogens in the presence of light to yield alkyl halides. The degree of substitution increases as the reaction progresses. The reaction occurs by free radical mechanism.

The reaction between butane and chlorine molecule to yields a monosubstitution product occurs as follows;

CH3CH2CH2CH3 + Cl2 --------> CH3CH2CH2CH2Cl + HCl

Yes, it is possible to identify the liquid, and the density of the liquid is closest to 0.889 g/cm³ so the liquid is most likely tetrahydrofuran.

To calculate the density of the unknown liquid, we use the formula:

Density = Mass / Volume

Substituting the given values, we get:

Density = 682. g / 0.767 L

Density = 888.5 g/L

Rounding to three significant digits, the density of the unknown liquid is 889 g/L.

Using the information provided in the question, we can compare the density of the unknown liquid to the known densities of the listed chemicals. The densities (in g/cm³) of the chemicals are:

Dimethyl sulfoxide: 1.092

Acetone: 0.790

Diethylamine: 0.707

Tetrahydrofuran: 0.889

Carbon tetrachloride: 1.594

Comparing the density of the unknown liquid to the known densities, we see that it is closest to the density of tetrahydrofuran, which is 0.889 g/cm³. Therefore, it is likely that the unknown liquid is tetrahydrofuran.

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The pressure of the helium gas (He) in the wet gas mixture is 833.8 mmHg.

In order to find the pressure of the helium gas in the wet gas mixture, we need to use the concept of partial pressures. According to Dalton's Law of Partial Pressures, the total pressure of a gas mixture is equal to the sum of the partial pressures of each individual gas present in the mixture. In this case, the wet gas mixture contains helium (He) and water vapor (H2O). The pressure of water vapor (H2O) is given as 21.2 mmHg, which means that the partial pressure of water vapor (H2O) in the mixture is 21.2 mmHg. We can now use the total pressure and the partial pressure of water vapor (H2O) to find the partial pressure of helium (He) in the mixture. To do this, we can subtract the partial pressure of water vapor (H2O) from the total pressure:

Partial pressure of helium (He) = Total pressure - Partial pressure of water vapor (H2O)

Partial pressure of helium (He) = 855 mmHg - 21.2 mmHg

Partial pressure of helium (He) = 833.8 mmHg

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The orbital diagram of the compound has been shown in the  image attached.

The configuration of the molecular orbitals (MOs) within a molecule is shown in an orbital diagram of the molecule. Atomic orbitals from different molecules' individual atoms overlap to create molecular orbitals. According to the rules of quantum physics, electrons can fill these molecular orbitals.

Each chemical orbital is depicted in an orbital diagram by a line or a box, and the electrons are shown as arrows. The arrow's direction—upward for "spin up" and downward for "spin down"—indicates the spin of the electron.

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Answer:

To convert joules to calories, you can use the conversion factor:

1 calorie = 4.184 joules

To find out how many calories are in 4,180 joules, divide the given value by the conversion factor:

4,180 joules / 4.184 joules per calorie = 0.9 calories (approximately)

Therefore, there are approximately 0.9 calories in 4,180 joules.

Answer: 2.3% :)

............................

Answer: 34%

Explanation:

Explanation:

endothermic because absorbing

energy

H2O is absorbing heat to release hydrogen and oxygen gas. any reaction that requires energy from outside is endothermic.

Answer:

Electrical power is the product of voltage times current.

Answer:

Explanation:

Combined Gas Law

T2= T1P2V2/ (P1V1) = 348.15 X .5 X 3.4/(2 X 7.5) =39.46 K or -233.69C

Answer:

B: All of the choices!

Explanation:

Choice 1: Simply, there is no current without voltage, so it DOES cause current.

Choice 3: Voltage DOES push free electrons around a circuit. Without it, free electrons will move around between atoms, but randomly, so they wouldn't be much use.

Choice 4: Voltage IS measured in volts, so this option is true as well.

Choice 2: Voltage is all of those answers, so it is true! :D

Hope i helped! :]

Answer:

Its B! :D

Explanation: I got it correct!

Considering the phase diagram, the state of matter that exists in area B is gas.

The correct option is A.

A phase diagram is a graphical representation that shows the conditions of temperature and pressure at which different phases or states of a substance exist.

The axes of a phase diagram typically represent temperature (usually on the horizontal axis) and pressure (usually on the vertical axis). The diagram is divided into regions that correspond to different phases, and the lines separating these regions represent phase boundaries.

The point where three phase boundaries meet is known as the triple point, which represents the temperature and pressure at which all three phases can coexist in equilibrium.

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Answer:

The time taken is  \(t = 1.11 *10^{-9} \ s\)

Explanation:

From the question we are told that

    The  rate constant is  \(k = 1.50 *10^{10} \ L /mol \cdot s\)

    The initial concentration of iodine atom  is  \([I] = 2.0*10^{-2} \ M\)

Generally the integrated  rate law for a second order reaction is  mathematically represented as

        \(\frac{1 }{[I_r]} = \frac{1}{[I]} * k * t\)

Where \([I_r]\) is the concentration of the remaining iodine atom  after the recombination which is mathematically evaluated as

      \([I_r ] = [I_o ] *\)[100%  - 94%]

The reason for the 94%  is that we are told from the question that only 94% of the iodine atom recombined

=>  \([I_r ] = [I_o ] *\)[6%]

=>  \([I_r ] = [I_o ] *0.06\)

substituting values

    \([I_r ] = 2.0 *10^{-2}*0.06\)

    \([I_r ] = 1.2 *10^{-3}\)

So

    \(\frac{1 }{1.2 *10^{-3}} = \frac{1}{2.0 *10^{-2}} * 1.50*10^{10} * t\)

  \(t = 1.11 *10^{-9} \ s\)

It will take "1.11 × 10⁻⁹ s".

A process wherein the two or even more compounds collide with both the proper orientation as well as enough effort to generate a new substance or the outcomes, is considered as Chemical reaction. This process involves the breaking as well as formation of atom connections.

According to the question,

Rate constant, k = 1.5 × 10¹⁰ L/mol.s

Initial concentration, [I] = 2.0 × 10⁻² M

By using the integrated rate law,

→ \(\frac{1}{[I]_r} = \frac{1}{[I]}\) × k × t ...(Equation 1)

Now,

The concentration of remaining Iodine atom,

[\(I_r\)] = [\(I_o\)] × [100% - 94%]  

     = [\(I_o\)] × 6%

     =  [\(I_o\)] × 0.06

By substituting the values is above equation,

[\(I_r\)] = 2.0 × 10⁻² × 0.06

     = 1.2 × 10⁻³

hence,

The time taken will be:

\(\frac{1}{[I]_r} = \frac{1}{[I]}\) × k × t

By substituting the values,

\(\frac{1}{1.2\times 10^{-3}} = \frac{1}{2.0\times 10^{-2}}\) × 1.50 × 10 × t

           t = 1.11 × 10⁻⁹ s

Thus the above answer is correct.

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