C++
Define a class called Shape. The shape class will hold different information about different
shapes. Specifically, each Shape object will contain:
• a letter to indicate the shape ('c' for circle, 's' for square, or 'h' for hexagon)
• one integer variable for the dimension needed (representing the radius of the circle, one
side of the square, or one side of the hexagon)
• a floating point value for area (used only internally - no accessors nor mutators needed)
There should be the following member functions:
• a default constructor that has default values for the private member variables ('n' for the
shape character and 0 for the dimension and area)
• accessors for the 3 private member variables,
• mutators for the character for shape and for the dimension
• a private member function that computes the area --- to be called whenever a constructor
is used and whenever the dimension is changed using a mutator function
Create a driver file that tests all functions and all computations for area. Code the test into your
file, don't rely on user input!
Overload the following operators for the Shape class:
• == checks to see if the types of shapes are the same and have the same dimension. NOTE: You
do not have to check to make sure the areas are the same.
• += checks to make sure the types of shapes are the same, then changes the dimension of the
operand on the left of the operator to be the sum of the old dimension value of the left operand
and the dimension of the right operand. The function should update the value of area.
• != returns true if the types of shapes are different or, if the same shape types, have dimension
values that are different
• + checks to make sure the shape types are the same. If they are, a new Shape object is created,
its type set to the same type as the two operands to the right of the =, sets the dimension to the
sum of the dimensions of the 2 operands, and computes the area (calling the helper function).
Your program MUST include a test plan in the comments, detailing what values will be tested with each
operator and what the output should be. Be sure to test your operators thoroughly.
Be sure to prevent the user from trying to create a shape with a dimension <= 0 or with a character for
shape other than 'c', 's', or 'h'

Answer:

The main reason for bridges collapses is: earthquakes (natural disasters) and construction incidents. Whenever a natural disaster occur, it makes the bridge collapse. An example is hurricanes. Hurricanes come with a great wind and that might lead to the bridge collapsing. Construction incidents means the bridge falls during construction. Those who are employed in health, safety and environmental management need to make sure that during the construction, they have examined the material and made sure it is strong. Working with economists, they should seek better understanding of the methods for minimizing the costs during the life of the bridge. In case for natural disasters, like flooding, they should make the bridge in a lever where the water won't reach the bridge. And they should have a limit for weight in the bridges because that is another reason it collapses, because the bridge does not support extra weight.

Explanation:

hope this helps

Answer:

9 1/2

Explanation:

3 4/5 is 3.8

2/5 is 0.4

divide 3.8 by 0.4 you get 9.5 which is 9 1/2 in a fraction

Answer:

torque to raise the load = 16.411 Nm

torque to lower the load = 8.40 Nm

overall efficiency = 0.24

Explanation:

Given:

max load on vertical direction of the screw = Force = F = 5kN

frictional  diameter of the collar = 45 mm

Diameter = 25 mm

length of pitch = 5 mm

coefficient of friction for thread µ  = 0.09

coefficient of friction for collar µ\(_{c}\) = 0.06

To find:

torque to "raise" the load

torque to and "lower"

overall efficiency

Solution:

Compute torque to raise the load:

\(T_{R} = \frac{ Fd_{m}}{2} (\frac{L+(\pi ud_{m}) }{\pi d_{m}-uL }) +\frac{Fu_{c} d_{c} }{2}\)

where

\(T_{R}\) is the torque

F is the load

\(d_{m}\) is diameter of thread

\(d_{c}\) is diameter of collar

L is the thread pitch distance

µ is coefficient of friction for thread

µ\(_{c}\)  is coefficient of friction for collar

Putting the values in above formula:

\(T_{R}\) = 5(25) / 2 [5+ (π(0.09)(25) / π(25)-0.09(5)] + 5(0.06)(45) / 2

    = 125/2 [5 + (3.14)(0.09)(25)/ 3.14(25)-0.45] + 13.5/2

    = 62.5 [(5 + 7.065) / 78.5 - 0.45] + 6.75

    = 62.5 [12.065 / 78.05 ] + 6.75

    = 62.5 (0.15458) + 6.75

    = 9.66125 + 6.75

    = 16.41125

\(T_{R}\) = 16.411 Nm

Compute torque to lower the load:

\(T_{L} = \frac{ Fd_{m}}{2} (\frac{(\pi ud_{m}) - L }{\pi d_{m}-uL }) +\frac{Fu_{c} d_{c} }{2}\)

     = 5(25) / 2 [ (π(0.09)(25) - L / π(25)-0.09(5) ] + 5(0.06)(45) / 2

     = 125/2 [ ((3.14)(0.09)(25) - 5) / 3.14(25)-0.45 ] + 13.5/2

     = 62.5 [ (7.065 - 5) / 78.5 - 0.45 ] + 6.75

    = 62.5 [ 2.065 / 78.05 ] + 6.75

     = 62.5 (0.026457) + 6.75

     = 1.6535625 + 6.75

     = 8.40 Nm

Since the torque required to lower the the load is positive indicating that an effort is applied to lower the load, Hence the thread is self locking.

Compute overall efficiency:

overall efficiency = F(L) / 2π \(T_{R}\)

                             = 5(5) / 2(3.14)( 16.411)

                             = 25/ 103.06108

overall efficiency = 0.24

Answer:

Flow rate = 118.8 gpm, discharge pressure= 331.5 psig, shaft power = 26.3 hp and Efficiency = 87.5%.

Explanation:

Without mincing words, let us dive straight into the solution to the question above. So, the following parameters or data are given in the question above:

gpm = 80 gpm, shaft power = 8hp, and the pressure of  150 psig.

The flow rate =[ 80 × 1500] ÷ 100g = 118.9 gpm.

Hence, the discharge pressure = 150 × [ 1500/100]² = 331.5 psig.

Also, the required shaft power = 8 × [ 1500/100]³ = 26.3 hp.

The last part that is the efficiency can be calculated as given below:

Efficiency = [ 80 × 0.00223 × 144 × 150 ] ÷ [550 × 8 ] = 0.875 = 87.5%.

To launch a probe into space from the Moon so that it does not fall back to the surface, you need an escape velocity of 2.38 km/s. This is the minimum speed required to overcome the gravitational pull of the Moon and send the probe into space.

The formula used to calculate the escape velocity of an object from the surface of a celestial body is derived from the gravitational potential energy and kinetic energy of the object. The formula is:

v = \(\sqrt{\frac{2 * G * M}{r} }\)

where:

v is the escape velocity,

G is the gravitational constant (approximately 6.67430 × 10⁻¹¹m³ kg⁻¹ s⁻²,

M is the mass of the celestial body (in this case, the Moon),

r is the distance from the center of the celestial body to the object's starting point (in this case, the radius of the Moon).

The radius of the Moon is approximately 1,737 kilometers (1,737,000 meters), and its mass is approximately 7.3477 × 10²² kilograms. Put these values into the formula, we can calculate the escape velocity.

Put in the values:

v =  \(\sqrt{\frac{2 * 1.62 * 1,737,000 }\)

sqrt(2 * 1.62 * 1,737,000) ≈ 2,376 meters per second (m/s)

Therefore, to ensure that the probe does not fall back to the surface of the Moon, you would need a launch speed of approximately 2,376 m/s or 2,38 m/s.

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Answer:

The required current in the 600-turn exciting coil to establish a flux of 100 μWb in the air gap is approximately 7.96 Amperes.

Step-by-step explanation:

To find the required current, we can use the magnetic circuit equation:

Φ = B × A × l

where Φ is the magnetic flux, B is the magnetic field, A is the cross-sectional area, and l is the length.

Given information:

l1 = 10 cm

l2 = l3 = 18 cm

Cross-sectional area of l1 path (A1) = 6.25 cm²

Cross-sectional area of l2 and l3 paths (A2) = 3 cm²

Length of the air gap (l_gap) = 2 mm = 0.2 cm

Relative permeability of the core material (μ_r) = 800

Number of turns in the coil (N) = 600

Flux in the air gap (Φ) = 100 μWb = 100 × 10^-6 Wb

First, we need to calculate the magnetic field in the air gap using the formula:

B_gap = Φ / (A_gap × l_gap)

where A_gap is the cross-sectional area of the air gap.

A_gap = A1 + 2 × A2 = 6.25 cm² + 2 × 3 cm² = 12.25 cm²

B_gap = (100 × 10^-6 Wb) / (12.25 cm² × 0.2 cm) = 0.325 T

Next, we can calculate the required current in the coil using Ampere's Law:

B_core × A_core = B_gap × A_gap

where B_core is the magnetic field in the core and A_core is the cross-sectional area of the core.

Since there is no leakage and fringing, the magnetic field in the core is constant and equal to the magnetic field in the air gap.

B_core = B_gap = 0.325 T

A_core = A1 = 6.25 cm²

Now we can calculate the required current:

B_core × A_core × l1 + B_core × A_core × (l2 + l3) = μ₀ × μ_r × (N / l_gap) × I

μ₀ = 4π × 10^-7 T·m/A

I = (B_core × A_core × (l1 + l2 + l3)) / (μ₀ × μ_r × (N / l_gap))

Substituting the given values:

I = (0.325 T × 6.25 cm² × (10 cm + 18 cm + 18 cm)) / (4π × 10^-7 T·m/A × 800 × (600 / 0.2 cm))

Simplifying the expression:

I ≈ 7.96 A

Therefore, the required current in the 600-turn exciting coil to establish a flux of 100 μWb in the air gap is approximately 7.96 Amperes.

Answer:

what do we do

Explanation:

Answer:

The mechanical advantage value is 1/2.

The wedge does not offer mechanical advantage because the value is less than 1.

Explanation:

The mechanical advantage of a wedge is given by the formula;

ME=length of slope/ width

slope is given as = 10 cm

width is given as = 20 cm

M.E =10/20 = 1/2

The wedge does not offer mechanical advantage because the value is less than 1.The mechanical advantage of a wedge should be greater than 1.

Answer:

(a) The volume flow rate of the refrigerant at the inlet is 0.3078 m3/s

(b) The mass flow rate of the refrigerant is 2.695 kg/s

(c) The velocity and volume flow rate at the exit is 6.017 m/s

Explanation:

According to the given data we have the following:

diameter of the pipe=d=28 cm=0.28 m

inlet pressure P1=200 kPa

inlet temperature T1=20°C

inlet velocity V1=5.5 m/s

Exit pressure P2=180 kPa

Exit Temperature T2=40°C

a. To calculate the volume flow rate of the refrigerant at the inlet we would have to use the following formula:

V1=AV1

=π/4(0.28∧2)5

V1=0.3078 m3/s

b. To calculate the mass flow rate of the refrigerant we would have to use the following formula:

m=p1 V1

m=V1/v1

=0.3078/0.11418

=2.695 kg/s

c. To calculate the velocity and volume flow rate at the exit we would have to use the following formula:

m=m1=m2

V1/v1=V2/v2

V2=(v2/v1)v1

=(0.13741/0.11418)5

=6.017 m/s

Answer:

The original seven wastes, or muda, are transportation, inventory, motion, waiting, overproduction, overprocessing and defects. ... When manufacturers are able to identify the seven wastes, they can correct and prevent further loss of time, money and other resources.

Explanation:

Answer:

transportation, inventory,motion, waiting,overproduction,overprocessing,and defects

Explanation:

they are often referred to by the acronym TIMWOOD

Based on information that a crowbar exerts 755N of force to open a 250 cm heavy door. It took 5.00 seconds to open the door and 40.0 watts of power was used on the crowbar.

Work= Force x Distance x cos(theta)

How to calculate theta:

Theta corresponds to the angle formed between the force and the displacement. As the crowbar is used to pry open the door, we assume that the force is applied perpendicular to the door, so: theta= 90º and cos(theta)= 0

Therefore, the answer to letter a will be:

Work = 755N x 250cm x 0 = 0 Joules

B) The work done on the crowbar will be equal and opposite in sign to the work done on the crowbar, so that will also be 0 Joules.

Therefore, in letter C, we conclude that the efficiency of the crowbar corresponds to the ratio between the output and input of work, which are 0 Joules, so the efficiency will be 0%, demonstrating that the crowbar was not effective to open the door.

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Building codes are legal restrictions that regulate the specifications for buildings, such as the type of building, signs, size and type of parking lot, and more, that are allowed in a specific location.

Building codes are important for ensuring the safety, structural integrity, and functionality of buildings. They establish minimum standards for construction materials, methods, and designs to protect occupants and the surrounding community.

These codes are typically established by local government authorities and are enforced through permits and inspections. They cover various aspects of building construction, including fire safety, electrical systems, plumbing, accessibility, energy efficiency, and more.

By enforcing building codes, authorities can ensure that structures are built to withstand natural disasters, prevent accidents, and promote public health and welfare. Compliance with building codes is crucial for architects, engineers, contractors, and other professionals involved in the construction industry to ensure that buildings are constructed and maintained in a safe and responsible manner.

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To achieve a steady-state error of 3%, we can either adjust the proportional gain Kp or velocity constant Kv accordingly

To determine the type of the system and the required value of the returneripaje to produce a steady-state error of 3%, we need to analyze the open-loop transfer function of the system. If the system has an integrator, it is considered as a Type 1 system, and if it has a double integrator, it is a Type 2 system.

Next, we can use the steady-state error formula for the given closed-loop system to determine the required value of the returneripaje. The steady-state error formula for a unity feedback system with a reference input R(s) and output Y(s) is given by:

ess = lim s→0 sR(s)/[1 + G(s)H(s)]

where G(s) is the transfer function of the plant, H(s) is the transfer function of the controller, and ess is the steady-state error.

For a Type 1 system, the steady-state error can be expressed as:

ess = 1/Kp

where Kp is the proportional gain of the controller. For a Type 2 system, the steady-state error can be expressed as:

ess = 1/Kv

where Kv is the velocity constant of the controller.

Therefore, to achieve a steady-state error of 3%, we can either adjust the proportional gain Kp or velocity constant Kv accordingly. If the system is a Type 1 system, we can set Kp to 1/0.03 = 33.33. If the system is a Type 2 system, we can set Kv to 1/0.03 = 33.33. These values will ensure that the steady-state error is limited to 3%.

In conclusion, the type of the system and the value of the returneripaje required to achieve a steady-state error of 3% depend on the open-loop transfer function of the system. By adjusting the proportional gain or velocity constant accordingly, we can limit the steady-state error to the desired value.

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It is to be noted that all UHRS platforms are optimized for the popular kinds of internet browser applications.

The Universal Human Relevance System (UHRS) is a crowdsourcing platform that allows for data labeling for a variety of AI application situations.

Vendor partners link people referred to as "judges" to offer data labeling at scale for us. All UHRS judges are bound by an NDA, ensuring that data is kept protected.

A browser is a software tool that allows you to see and interact with all of the knowledgeon the World Wide Web. Web sites, movies, and photos are all examples of this.

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The motorcycle's position when t = 13.5s is 48m.

\(& \text { At } \quad t=8 S \\\)

\(& a=\frac{d v}{d t}=0 \\\)

\(& \Delta s=\int v d t \\\)

\(& s-0=\frac{1}{2}(4)(5)+(8-4)(5)=30 \\\)

\(& s=30 m \\\)

\(& A t \quad t=12 s \\\)

\(& a=\frac{d v}{d t}=\frac{-5}{5}=-1 m / s^2 \\\)

\(& \Delta s=\int v d t \\\)

\(& s-0=\frac{1}{2}(4)(5)+(10-4)(5)+\frac{1}{2}(15-10)(5)-\frac{1}{2}\left(\frac{3}{5}\right)(5)\left(\frac{3}{5}\right)(5) \\\)

\(& s=48 m\)

The complete question is,

A motorcycle starts from rest at s = 0 and travels along a straight road with the speed shown by the v–t graph. Determine the motorcycle’s acceleration and position when t = 8 s and t = 12 s.

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The rooftop solar is a form of solar energy that can be installed on the roof of a home or business. It is cost-effective, environmentally friendly, and provides many benefits to homeowners and businesses.

The rooftop solar has many advantages over other forms of solar energy. One of the main advantages is that it provides 100% clean electricity from renewable sources. In addition, it can be combined with other sources such as wind power and geothermal power for even more benefits.

There are also many uses for rooftop solar panels in homes and businesses. One example is using it to heat water for hot water systems or heating swimming pools.

For me Bluebird Solar Private Limited is the best website in India for rooftop solar panels in India.

Car engines operate based on the mechanical work done by expanding gases. To compute the total amount of work done, the pressure of the surroundings is multiplied by the change in the volume of the gas during expansion. This is known as PV work.

PV work or pressure-volume work refers to the work done by gases. Gases can work through compression or expansion against constant external pressure. For instance, suppose a gas is contained in a piston. When the gas is heated, energy is added to the gas molecules, increasing the average kinetic energy of the molecules. With the faster movement of gas molecules, their collision with the piston occurs more frequently. Ultimately, these increasingly frequent collisions become a cause of transferring energy into the piston and moving it against external pressure. As a result the overall volume of the gas increase. This example presents a scenario where the gas has done work on the surroundings, which involves the piston and the rest of the universe.

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Answer:

Use GitHub or stackoverflow for this answer

Explanation:

It helps with programming a lot

or...................

Answer:

i believe it is true

Explanation:

Answer:

The correct answer is He forgot to include indirect costs such as advertising, legal fees, and repairs.

Explanation:

The number of X is 33 inches.

A perimeter became the closed path that encompasses, surrounds, or outlines each a two-dimensional shape or a one-dimensional length. The perimeter of a circle or an ellipse is known as its circumference. Calculating the perimeter has numerous practical applications. The perimeter moreover says the length of the definition of a shape. To find out the edge of a rectangle or square you want to add the lengths of all four sides.

To determine the amount of X, we will use the method below:

X + X + X + X = 132 or 4x = 132.

Then we will discover the result for X with the step below:

4x = 132

Divide both side by 4

Hence

x = 132 : 4 = 33

x = 33

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To determine whether the project specifications have been met, the contractor must perform a Proctor test and a sand-cone test.

Projects are tasks, activities, or operations that are designed to accomplish a specific goal within a given period of time.

The Proctor test measures the compaction of soil and the sand-cone test measures the volume of soil that can be filled in a given area.
The Proctor test data provided shows that the mass of compacted soil + mold ranges from 240.29 kg to 263.45 kg. The mass of the can + dry soil ranges from 19.81 kg to 20.99 kg. The mass of the compaction mold ranges from 2.031 kg to 2.031 kg. This data indicates that the contractor has achieved a relative compaction of 90%.
The sand-cone test data provided shows that the initial mass of the sand-cone apparatus was 5.912 kg, the final mass of the sand-cone apparatus was 2.378 kg and the mass of soil recovered from the hole was 2.883 kg. The moisture content of the soil from the hole was 7% and the density of the sand was 1300 kg/m3. This data indicates that the contractor has achieved a volume of 1.114x10^3 m3, which is within the project specifications.
Based on the data provided, it can be concluded that the contractor has met the project specifications and has achieved the required relative compaction of 90%. If the contractor has not met the project specifications, then a course of action should be taken to address the issue. This could include additional tests to verify the compaction and volume of soil, adjusting the compaction process, or additional backfilling and compaction.

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Answer:

true

Explanation:

Answer:

false

Explanation:

Answer:

somewhere around 34.2223 meters thick but that's what I am estimating.

Answer:

the answer how you analyzs the problwm

Answer:

To access a missions, simply log on to your CoderZ account and navigate to one of the courses you are assigned, choose a pack, and then choose one of the missions!

Answer:

molar flow at the bottom streams = 30 moles

composition of the bottom streams exiting the second separation unit

= 0.20 ( methanol )

= 0.80 ( water )

Explanation:

The molar flow and the composition of the bottom streams is calculated as follows below

First we have to balance the overall material across the Mixer unit

= F1 + F2 = A

= 100 + 10 = 110 mole

next we calculate Methanol balance

= Xe1 * F1 + Xe2 * F2  = AXea

= (0.5 * 100) + ( 0.4 * 10 ) = 110 Xea

= 50 + 4 = 110Xea

Xea = 0.491   therefore: Xaw = 1 - Xea = 1 - 0.491 = 0.509

Next we calculate the material balance of separator 1

A = B + C

where: A = 110 moles , B = ? , C = 70 moles

Therefore B= A - C = ( 110 - 70 ) = 40 moles

From here we will find the value of Xec using the Methanol balance relationship

Xea * A = Xeb*B + Xec * C

where: A = 110 moles , B = 40 moles , C = 70 moles

           Xea = 0.491, Xeb = 0.7 ,

Input these values into the equation above : Xec = 0.372

note: at the exit top stream both the separators have the same flow rate

i.e : B = D = 40 mole

Material Balance over the separator 2 can hence be calculated as

C = D + E

E = c - d = 70 - 40

E = 30 moles ( mole flow rate at the 2nd separator unit )

calculate the value of XeE

methanol balance : Xec * c = Xed * D + XeE * E

hence : XeE = [ ( 70 * 0.372 ) -  ( 0.5 * 40 ) ] /  30

             XeE  =  0.20

attached below is the flow sheet of the problem

At 1.2mpa pressure and 50c

What is pressure?
By pressing a knife against some fruit, one can see a straightforward illustration of pressure. The surface won't be cut if you press the flat part of the knife against the fruit. The force is dispersed over a wide area (low pressure).

a)Mass flow rate of the refrigerant
Therefore h1= condenser inlet enthalpy =278.28KJ/Kg
saturation temperature at 1.2mpa is 46.29C
Therefore the temperature of the condenser

T2 = 46.29C - 5
T2 = 41.29C

Now,
d)power consumed by compressor W = 3.3KW
Q4 = QL + w = Q4
QL = mR(h1-h2)-W
= 0.0498 x (278.26 - 110.19)-3.3
=5.074KW
Hence refrigerator load is 5.74Kg

(COP)r = 238/53
(Cop) = 4.490

Therefore the above values are the (a) mass flow rate of the refrigerant, b) the refrigerant load, c) the cop, and d) the minimum power input to the compressor for the same refrigeration load.

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Answer:c. Operational Risk Management

Explanation:

The phrase "Fly-Crash-Fix-Fly" is often used to describe the concept of Operational Risk Management. It emphasizes the continuous cycle of identifying potential risks and hazards (Fly), analyzing and learning from past incidents and accidents (Crash), implementing corrective actions and preventive measures (Fix), and resuming normal operations with improved safety (Fly). This approach aims to proactively manage risks and enhance safety performance within an organization.