Carbonyl bromide, cobr2, can be formed by reacting co with br2. a mixture of 0.400 mol co, 0.300 mol br2, and 0.0200 mol cobr2 is sealed in a 5.00l flask. calculate equilibrium concentrations for all gases, given that the kc

Answer:

d. trust me

Explanation:

all the other answers point to why the cup stays hot.

By titration, it is found that the concentration of the HCl solution is 0.175 M.

To solve this problem using titration, we need to use the balanced chemical equation for the neutralization reaction between NaOH and HCl:

NaOH + HCl → NaCl + H2O

From the equation, we know that 1 mole of NaOH reacts with 1 mole of HCl to produce 1 mole of NaCl and 1 mole of H2O. Therefore, we can use the following formula to calculate the concentration of the HCl solution:

M(HCl) = (M(NaOH) x V(NaOH)) / V(HCl)

Where:
M(HCl) = concentration of HCl solution
M(NaOH) = concentration of NaOH solution (given as 0.179 M)
V(NaOH) = volume of NaOH solution used (given as 24.7 mL or 0.0247 L)
V(HCl) = volume of HCl solution used (given as 25.0 mL or 0.0250 L)

Plugging in the values, we get:

M(HCl) = (0.179 M x 0.0247 L) / 0.0250 L
M(HCl) = 0.175 M

Therefore, the concentration of the HCl solution is 0.175 M.

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Answer:

V = 9

Explanation:

n = 0.410

T = 47.0C (must be convert to K by + 273.15) = 320.15 K

P = 1.20 atm

R = 0.08205

V = ?

To solve this equation, we must follow the equation below:

PV = nRT

1.20 x V = 0.410 x 0.08205 x 320.15 K

1.20 x V = 10.8

V = 9

So the answer is 9.

Answer:

E

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BRAINLIEST PLEASE

Answer:

a. To compare the concentration of 80 g/litre NaOH solution and 3 M NaOH solution, we need to convert one of the concentrations to the other unit.

One mole of NaOH weighs 40 grams. So, to convert 80 g/litre NaOH to Molarity, we can divide 80 g/litre by 40 g/mol to get:

80 g/litre NaOH = 2 M NaOH

Therefore, 3 M NaOH has a higher concentration than 80 g/litre NaOH solution.

b. To compare the concentration of 5.3 g/litre Na2CO3 and N/10 Na2CO3 solution, we need to first understand what N/10 solution means.

N/10 Na2CO3 means that the solution contains 1/10th of the normal concentration of Na2CO3. The normal concentration of Na2CO3 is the molar concentration of Na2CO3 that corresponds to the formula weight of Na2CO3, which is 106 g/mol.

So, the normal concentration of Na2CO3 is 1 mol/L or 1 M Na2CO3.

Therefore, N/10 Na2CO3 solution has a concentration of 1/10 M Na2CO3.

Now, let's compare the two concentrations:

5.3 g/litre Na2CO3 = (5.3/106) M Na2CO3 = 0.05 M Na2CO3

Since 0.05 M Na2CO3 is greater than 1/10 M Na2CO3, the concentration of 5.3 g/litre Na2CO3 solution is higher than that of N/10 Na2CO3 solution.

Explanation:

It is known as acid mine drainage.

What is acid mine drainage?

Pyrite, an iron sulfide, reacts with air and water to produce sulfuric acid and dissolved iron when it is exposed, which causes mine drainage. In the bottom of streams containing mine drainage, some or all of this iron may precipitate to create red, orange, or yellow sediments.

The benefits

These tried-and-true technologies offer a chemical precipitation solution that effectively scavenges dangerous heavy metals and eliminates over 99.4% of the sulfate content of water, assisting in the reduction of ground and surface water pollution from mines.

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In an experiment comparing the tension bond strength of polymer latex modified mortar (portland cement mortar with added polymer latex emulsions) to that of unmodified mortar, the result was x.

To conduct this experiment, you would need to follow these steps:

1. Prepare the materials: Gather all the necessary materials, including polymer latex emulsions, portland cement, sand, water, and any other additives required for the mortar mixture.

2. Prepare the polymer latex modified mortar: Mix the portland cement, sand, water, and polymer latex emulsions according to the specified proportions. Ensure thorough mixing to achieve a homogeneous mixture.

3. Prepare the unmodified mortar: Mix the portland cement, sand, and water according to the specified proportions. Again, ensure thorough mixing for a consistent mixture.

4. Perform the tension bond test: Apply both the polymer latex modified mortar and the unmodified mortar onto separate test surfaces, such as concrete blocks or metal plates. Make sure the surfaces are clean and free from any contaminants.

5. Allow the mortar to cure: Let both the modified and unmodified mortar cure for a specific duration, following the manufacturer's instructions or established industry standards.

6. Test the bond strength: Use a tension bond strength test apparatus, such as a hydraulic or mechanical testing machine, to apply a force perpendicular to the bond interface of the mortar. Apply increasing force until the bond fails and records the maximum force required for bond failure in both cases.

7. Compare the results: Analyze the data obtained from the tension bond test for both the polymer latex modified mortar and the unmodified mortar. Determine the maximum force or stress required for bond failure in each case.

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While Separating sand and salt by filtration and evaporation, the observation is during the filtration the sand gets accumulated in the filter paper while separating it from the salt solution, while in evaporation the salt gets accumulated.

When we tried to separate the individual components from the mixture of the salt and sand the first step is dissolving the mixture in water as the salt gets dissolved so it is easy for us to filter the sand from the solution, it is followed by the method of evaporation, in which the filtered salt solution is boiled until the water gets evaporated and we are left with the salt,  that's how salt and sand are separated from a mixture.

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Answer:

569K

Explanation:

Q = 3.5kJ = 3500J

mass = 28.2g

∅1 = 20°C = 20 + 273 = 293K

∅2 = x

c = 0.449

Q = mc∆∅

3500 = 28.2×0.449×∆∅

3500 = 12.6618×∆∅

∆∅ = 3500/12.6618

∆∅ = 276.4220

∅2 - ∅1 = 276.4220

∅2 = 276.4220 + ∅1

∅2 = 276.4220 + 293

∅2 = 569.4220K

∅2 = 569K

When the temperature is increased, there is the increase in thermal energy of the system. The final temperature of the iron in kelvins is 570 K.

The energy is the ability to do work.

Given is the energy Q = 3.5 kJ = 3500 J, mass of sample m = 28.2 g, specific heat of iron Cp = 0.449 J(g•K).

The initial temperature in kelvins is T1 = 20°C = 20 + 273 = 293K

The heat is related to the temperature difference as

Q = m c ∆T

Substitute the values into the expression,

3500 = 28.2 × 0.449 × ∆T

3500 = 12.6618 × (T2 -T1)

T2 - T1 = 276.4220

T2 = 276.4220 K +293 K

T2 = 569.4220K

The temperature of the iron is approximately 570 K.

Thus, the final temperature of the iron in kelvins is 570K.

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Answer:

wave c i think

Explanation:

Answer:

lanthanum

Explanation:

lanthanum is an inner transition metal

Answer: OCl2 is polar because the two O-Cl bond dipoles don't cancel each other.

Photosynthesis is a process of food and energy production by autotrophs. Water and carbon dioxide in the presence of sunlight gives oxygen and sugar.

Photosynthesis is a biochemical reaction that uses organic and inorganic compounds and converts the molecules with the help of biological organs and substances.

The reactant of the process includes atmospheric water vapours, carbon dioxide and the heat and energy from the sun. These reactants are used by plants and some other organisms.

The organism utilizes the reactants and produces molecules of sugar like glucose and by-product oxygen. These molecules are necessary for the metabolic and respiratory processes.

Therefore, option B. \(\rm sunlight + water + carbon\; dioxide \rightarrow oxygen + sugar\) is the correct equation that describes photosynthesis.

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Answer:

The answer is D, organisms that are mostly related belong in a species.

Explanation:

Therefore, the pH and the equilibrium concentration of S²⁻ in a 6.89x10⁻² M hydrosulfuric acid solution are pH = 7.78 and [S²⁻] = 2.31x10⁻¹¹ M.

Hydrosulfuric acid (H₂S) is a weak acid that dissociates in water to produce hydrogen ions (H⁺) and bisulfide ions (HS⁻). H₂S(aq) + H₂O(l) ⇌ H₃O⁺(aq) + HS⁻(aq)

The bisulfide ions (HS⁻) in turn reacts with water to produce hydronium ions (H₃O⁺) and sulfide ions (S²⁻).

HS⁻(aq) + H₂O(l) ⇌ H₃O⁺(aq) + S²⁻(aq) Ka1

= 1.0x10⁻⁷,

Ka2 = 1.0x10⁻¹⁹

To calculate the pH and the equilibrium concentration of S²⁻ in a 6.89x10⁻² M H₂S(aq) solution, we must first determine if H₂S(aq) is a strong or weak acid.

It has Ka1 = 1.0x10⁻⁷, which is a very small value; thus, we can conclude that H₂S(aq) is a weak acid.

To calculate the equilibrium concentration of S²⁻ in a 6.89x10⁻² M H₂S(aq) solution, we need to use the Ka2 value (Ka2 = 1.0x10⁻¹⁹) and a chemical equilibrium table.

[H₂S] = 6.89x10⁻² M[H₃O⁺] [HS⁻] [S²⁻]

Initial 0 0 0Change -x +x +x

Equilibrium (6.89x10⁻² - x) x xKa2 = [H₃O⁺][S²⁻]/[HS⁻]1.0x10⁻¹⁹

= x² / (6.89x10⁻² - x)

Simplifying: 1.0x10⁻¹⁹ = x² / (6.89x10⁻²)

Thus: x = √[(1.0x10⁻¹⁹)(6.89x10⁻²)]

x = 2.31x10⁻¹¹ M

Thus, [S²⁻] = 2.31x10⁻¹¹ M

To calculate the pH of the solution, we can use the Ka1 value and the following chemical equilibrium table.

[H₂S] = 6.89x10⁻² M[H₃O⁺] [HS⁻] [S²⁻]

Initial 0 0 0

Change -x +x +x

Equilibrium (6.89x10⁻² - x) x x

Ka1 = [H₃O⁺][HS⁻]/[H₂S]1.0x10⁻⁷

= x(6.89x10⁻² - x) / (6.89x10⁻²)

Simplifying: 1.0x10⁻⁷ = x(6.89x10⁻² - x) / (6.89x10⁻²)

Thus: x = 1.66x10⁻⁸ M[H₃O⁺]

= 1.66x10⁻⁸ M

Then, pH = -log[H₃O⁺]

= -log(1.66x10⁻⁸)

= 7.78 (rounded to two decimal places)

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Answer:

mass

Explanation:

The amount of kinetic energy an object has, depends on its mass and its speed.

Answer: motion

Explanation:

I just took the quiz in edging

Answer:

No.

Explanation:

Weight is the measure of the gravitational force between two massive things.

W = g . m

g = gravity

m = mass

Also, we can say that gravity is equal to G.M/d² where G is the constant of Newton's gravity, M the massa of the corp and d is their distance.

In Einstein's theory, that's not true, but it works for small gravitys.

The description of the question is the definition of density.

Here's a classification of the given processes into exothermic and endothermic categories:

(a) Combustion: Exothermic. Combustion releases heat as chemical bonds are broken and new ones are formed, usually accompanied by the release of energy.

(b) Freezing water: Exothermic. During freezing, water molecules lose energy and form a solid structure, releasing heat in the process.

(c) Melting ice: Endothermic. Melting ice requires the absorption of heat to break the bonds between water molecules in the solid state and convert them into a liquid state.

(d) Boiling water: Endothermic. Boiling water involves the absorption of heat to convert liquid water into water vapor.

(e) Condensing steam: Exothermic. During condensation, water vapor molecules release heat as they transition from the gaseous state to the liquid state.

(f) Burning paper: Exothermic. Burning paper is a form of combustion, where chemical reactions release heat as the paper is broken down.

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150g•1moles/189.36g= 0.792moles

Answer:

72.0366 gramos de Al

Explanation:

2.67 moles Al* 26.98 gramos Al/ 1 mol Al= 72.0366 gramos de Al

Answer:

The velocity of the bb when it reaches a height of 203 m can be determined using the laws of projectile motion. Since the bb is moving vertically upwards, its velocity at that height will be zero.

brainlest?

Answer: v = 83.96 m/s

Assuming the acceleration due to gravity is approximately 9.8 m/s^2, we can use the principles of projectile motion and energy conservation.

Using the equation for the vertical displacement of an object in free fall:

Δy = (v₀² - v²) / (2g)

Δy = vertical displacement (203m)

v₀ = initial velocity (105 m/s)

v = final velocity (not known yet)

g = accerlation due to gravity (9.8 m/s^2)

Lets rearrange the equation to solve for the final velocity:

v = v = √(v₀² - 2gΔy)

Substituting the given values:

v = √(105² - 2 * 9.8 * 203)

v ≈ √(11025 - 3979.6)

v ≈ √(7054.4)

v ≈ 83.96 m/s

Therefore, when the BB pellet is at the height of 203m, its velocity will be approximately 83.96 m/s.

In a nuclear fission reaction, a freely moving neutron is introduced to a nuclear fuel, then a neutron is absorbed by an atom's nucleus.

Nuclear fission is a process in which an unstable nuclei will convert into stable nuclei after releasing the energy in the form of particles.

When we introduce a freely moving neutron to the nuclear fuel of uranium-235 nuclei then this introduced neutron was absorbed by the nuclei and makes the nuclei more unstable. Then this unstable nuclei will convert into two nuclei in the addition of three neutrons.

Hence, a neutron is absorbed by an atom's nucleus.

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To produce 1000 kg of fishmeal (M = 1000 kg), you would need 3000 kg of pasta. To determine the amount of pasta required to produce 1000 kg of fishmeal, we need to consider the mass balance of the process. Let's break down the steps involved:

A. Extraction of fish oil:

The pasta obtained from the extraction stage contains 20% flour and 80% water. To calculate the amount of pasta, we need to determine the mass of flour and water in the pasta. Let's assume the total mass of the pasta is P kg.

Mass of flour = 20% of P = 0.2P kg

Mass of water = 80% of P = 0.8P kg

b. Drying of pasta:

During the drying stage, the pasta is dried in a rotary drum, resulting in fishmeal with 40% humidity. This means that the final fishmeal will contain 60% dry matter.

Let's assume the mass of the dried fishmeal is M kg.

Mass of dry matter = 60% of M = 0.6M kg

Since the dry matter in the fishmeal comes from the flour in the pasta, we can equate the mass of dry matter to the mass of flour:

0.6M kg = 0.2P kg

To produce 1000 kg of fishmeal, we want to find the corresponding value of P:

0.6M = 0.2P

P = (0.6M) / 0.2

P = 3M

Therefore, to produce 1000 kg of fishmeal (M = 1000 kg), you would need 3000 kg of pasta.

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81.3 g H₃PO₃

Math

Pre-Algebra

Order of Operations: BPEMDAS

Chemistry

Atomic Structure

Stoichiometry

Step 1: Define

[RxN - Unbalanced] PCl₃ + H₂O → HCl + H₃PO₃

↓

[RxN - Balanced] PCl₃ + 3H₂O → 3HCl + H₃PO₃

[Given] 53.6 g H₂O

[Solve] x g H₃PO₃

Step 2: Identify Conversions

[RxN] 3 mol H₂O → 1 mol H₃PO₃

[PT] Molar Mass of H - 1.01 g/mol

[PT] Molar Mass of O - 16.00 g/mol

[PT] Molar Mass of P - 30.97 g/mol

Molar Mass of H₂O - 2(1.01) + 16.00 = 18.02 g/mol

Molar Mass of H₃PO₃ - 3(1.01) + 30.97 + 3(16.00) = 82.00 g/mol

Step 3: Stoich

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

81.3023 g H₃PO₃ ≈ 81.3 g H₃PO₃

18.0 grams of water is formed when 1 mole of HCl reacts completely with 1 mole of NaOH.

Assume that:

n = number of moles

m = mass of substance

M = molar mass

Looking at the equation:

HCl + NaOH--->NaCl+H2O

Hydrogen = 1.0 g/mol

Oxygen = 16.0 g/mol

Therefore the molar mass (M) of  H2O is 18 g/mol.

Last step, find the mass (m) of water.

The formula of finding mass of substance (m) is:

m= M*n

[m = 1.0 moles × 18.0 g/mol = 18.0 grams]

Therefore 18.0 grams of water is formed when 1 mole of HCl reacts completely with 1 mole of NaOH.

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Answer:

1) contraction

2) 1.54 liters

3) 150°C

4) The gas expands proportionally to the increase in temperature

5) false

6) true

7)pentane

8) it has a boiling point around 35°

Explanation: