Cara is hanging a poster that is 919191 centimeters (\text{cm})(cm)left parenthesis, start text, c, m, end text, right parenthesis wide in her room. The center of the wall is 180\,\text{cm}180cm180, start text, c, m, end text from the right end of the wall. If Cara hangs the poster so that the center of the poster is located at the center of the wall, how far will the left and right edges of the poster be from the right end of the wall?

Answer:

I think it's false

Step-by-step explanation:

Answer:

24.41

Step-by-step explanation:

a^2+b^2=c^2

14^2+20^2=c^2

196+400=596

14^2+20^2=24.41^2

Answer:

A . 36

Step-by-step explanation:

We are given a total of 176 interviewed by Oliver and a total of 140 interviewed by Jenny. To find how many more 10th graders than 9th graders were interviewed, subtract the totals given

176 - 140 = 36

This is how we came to the answer:

We are given 70% of the 10th-grade and 30% of the 9th-grade with a total of 176 for Oliver.

While we're given 75% of the 9th-grade class and 25% of the 10th-grade with a total of 140 interviewed by Jenny

Oliver's Interviewees

Firstly, let's find what the number of 9th-graders was interviewed by Oliver; find the percentage of the 9th-graders by the total;

70% of 176 =

\(\frac{70}{100} * \frac{176}{1}\)

Cross multiply

123.2 were 10-graders interviewed by Oliver

Now, to find the number of 9th-graders was interviewed by Oliver; find the percentage of the 9th-graders by the total;

30% of 176 =

\(\frac{30}{100} * \frac{176}{1}\)

Cross multiply

52.8 were 9th-graders interviewed by Oliver

Jenny's Interviewees

Firstly, let's find what the number of 9th-graders was interviewed by Jenney; find the percentage of the 9th-graders by the total;

75% of 140 =

\(\frac{75}{100} * \frac{140}{1}\)

Cross multiply

105 students were 9th-graders interviewed by Jenney.

Now, to find the number of 10th-graders was interviewed by Jenney; find the percentage of the 10th-graders by the total;

25% of 140 =

\(\frac{25}{100} * \frac{140}{1}\)

Cross multiply

35 students were 10th-graders interviewed by Jenney.

Total calculation

Use the results and sum them up by 9th-grade plus 9th-grade and 10th-grade plus 10-grade. Then subtract the amount gotten from 9th-grade away from the amount gotten from 10th-grade;

Oliver's 9th-grade = 52.8

Jenny's 9th-grade = 105

105 + 52.8 = 157.8

Oliver's 10th-grade = 123.2

Jenny's 10th-grade = 35

123.2 + 35 = 158.2

Total calculation: 158. 2 - 157.8 = 0.4

Oliver's Interviewees Percentage

Since we are given 30% of the 9th-grade class and 70% of the 10th-grade class, first, let's add the percentages. To do so, set it up as a fraction;

30% = \(\frac{30}{100}\) while, 70% = \(\frac{70}{100}\)

Now solve it;

\(\frac{30}{100} + \frac{70}{100}\)

Simplify; cancel bottom zero's;

\(\frac{30}{1} + \frac{70}{1}\)

Add the remaining numerators;

30 + 70 = 100

Which is 100%

Jenny's Interviewees Percentage

Since we're given 75% of the 9th-grade class and 25% of the 10th-grade, it will end up the same answer. I'll show you how; first, let's add the percentages. To do so, set it up as a fraction;

25% = \(\frac{25}{100}\) and, 75% = \(\frac{75}{100}\)

Now solve it;

\(\frac{25}{100} + \frac{75}{100}\)

Simplify; cancel bottom zero's

\(\frac{25}{1} + \frac{75}{1}\)

Add the remaining numerators;

25 + 75 = 100

Meaning 100%

Joaquin will need 1 and two fifths cups to make his famous chocolate chip cookies for his friend's birthday party

To solve this problem we will use a rule of three with the problem information:

5 people-------- 1/4 cup of butter

28 people -------- x

Applying the rule of three we get:

x = ( 28 people * 1/4 cup of butter) / 5 people

x = 1,4 cup of butter

x = 1 + 2/5 cup of butter = 1 and two fifths cups

It describes the proportionality of 3 known data and an unknown data. When you have more than 3 known facts that are involved in the proportionality, it is known as a compound rule. The rule of three is also known as a direct proportions.

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Answer:

y = 25 degrees

Step-by-step explanation:

We start with 115° and x -

115° + x = 180°

x = 180° - 115°

x = 65°

The sum of all of the angles of a triangle will always be 180 degrees -

x + y + 90° = 180°

We substitute x with 65° -

65° + y + 90° = 180°

y = 180° - 65° - 90°

y = 90° - 65°

y = 25°

The required rate of return (or minimum acceptable rate of return) is 20 percent. If the net cash flows are $15,000 per year for ten years, the total cash flow is $150,000. The project's cost is $47,500. We can now apply the net present value formula to determine whether or not the project is feasible.

Net Present Value (NPV) = Cash flow / (1 + r)^n - Cost Where, r is the discount rate, n is the number of years, and Cost is the initial outlay.

Net Present Value = 150000 / (1 + 0.20)^10 - 47500

Net Present Value = $67,482.22

Since the NPV is positive, the project is feasible. When calculating net present value, it's important to remember that a positive NPV implies that the project is expected to generate a return that exceeds the cost of capital, whereas a negative NPV indicates that the project is expected to generate a return that is less than the cost of capital, and as a result, it should be avoided.

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Answer:

x = 61°

Step-by-step explanation:

x+29+90 = 180 [This is because all angles in a triangle add up to 180°]

x = 180-29-90

x = 180-119

x = 61°

(a) Based on Khalid's results we would expect 52 purple candies and 130 blue candies in the bag.

(b) Lastly, we would expect 78 more blue candies than purple candies.

According to Khalid's results, 10% of the candies were purple, which means there were:

0.10 x 520 = 52 purple candies

Similarly, 25% of the candies were blue, which means there were:

0.25 x 520 = 130 blue candies

To find the difference between the number of blue and purple candies, we can subtract the number of purple candies from the number of blue candies:

130 - 52 = 78

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The function decreases on the intervals (-∞, -1) and (1.5, ∞).

Hence the decreasing intervals are given as follows:

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Answer:

8640

Step-by-step explanation:

Answer:

y = -1/2x + 5/2.

Step-by-step explanation:

If a line is perpendicular to another line, the slope of the line is the negative reciprocal of the other. In this case, the line is perpendicular to y = 2x + 3. That means the slope will be -1/2.

Now, we have y = -1/2x + c.

To solve for c, put in the points given.

2 = (-1/2) * 1 + c

c -1/2 = 2

c = 2 + 1/2

c = 4/2 + 1/2

c = 5/2

So, your final answer is that the equation of the line is y = -1/2x + 5/2.

Hope this helps!

Answer:

\(y = -\frac{1}{2} x+\frac{5}{2}\)

Step-by-step explanation:

Perpendicular => So, it would have a slope of negative reciprocal for this slope

Slope = m = -1/2

Now,

Point = (x,y) = (1,2)

So, x = 1, y = 2

Putting in the slope intercept equation to get c

=> \(y = mx+c\)

=> 2 = (-1/2)(1) + c

=> 2+1/2 = c

=> c = \(\frac{4+1}{2}\)

=> c = \(\frac{5}{2}\)

Now, Putting m and c in the slope-intercept equation:

=> \(y = mx+c\)

=> \(y = -\frac{1}{2} x+\frac{5}{2}\)

Answer:

It is a positive slope.

The slope is 2 over 4 (2/4) or 1/2.

The equation would be Y= 1/2x + 3.

Answer:

The answer is D.

Step-by-step explanation:

Zero Power Property

Any number (except zero) raised to the zero power equals 1. Note: 0^0 is undefined.

Using algebraic symbols, we can write this rule as:

a^0 = 1

Answer:

please see answers below

Step-by-step explanation:

equation of a straight line is given by y= mx + c (where m is gradient-slope, c is y-axis intercept)

you have to measure the slope (change in y values ÷ change in x values).

you have to find where graph crosses the y-axis (y-axis intercept).

pick two sets of coordinates for each line (graph).

1) coordinates are (0,2) and (10,7).

slope = (change in y values ÷ change in x values)

= (7 - 2) / (10 - 0) = 5/10 = 1/2.

it crosses the y-axis at y = 2.

the equation is y = (1/2)x + 2.

2) coordinates are (0, -3) and (2, 5).

slope = (-3 - 5) / (0 - 2)

= -8 / -2

= +4

=4.

it crosses the y-axis at y = -3

the equation is y = 4x - 3

3) coordinates are (-1, 0) and (1, -2)

slope = (-2 - 0) / (1 - -1)

= -2 / (1 + 1)

= -2 /2

= -1 .

it crosses the y-axis at y = -1

the equation is y = -x - 1

4) coordinates are (-1, 2) and (0, -1)

slope = (-1 - 2) / (0  - -1)

= -3 / (0 + 1)

= -3/1

= -3.

it crosses the y-axis at y = -1

the equation is y = -3x - 1

5) coordinates are (4, 0) and (0, 2).

slope = (2 - 0) / (0 - 4)

= 2/-4

= -1/2

it crosses the y-axis at y = 2

the equation is y = -(1/2)x + 2

hope these answers help you. good luck

Answer:

8

Step-by-step explanation:

Based on the given conditions, formulate: 32 / 4 Cross out the common factor

Answer:

either b or c

Step-by-step explanation:

i think

The given linear transformation is invertible, and its inverse is T^⁻1(x1, x2, x3) = (x1, x2 + x3, 0).

To determine whether the linear transformation T(x1, x2, x3) = (x1 + x2 + x3, x2 + x3, x3) is invertible, we need to check if there exists an inverse transformation that undoes the effects of T. In this case, we can find an inverse transformation, T^⁻1(x1, x2, x3) = (x1, x2 + x3, 0).

To verify this, we can compose the original transformation with its inverse and see if it returns the identity transformation. Let's calculate T^⁻1(T(x1, x2, x3)):

T^⁻1(T(x1, x2, x3)) = T^⁻1(x1 + x2 + x3, x2 + x3, x3)

= (x1 + x2 + x3, x2 + x3, 0)

We can observe that the resulting transformation is equal to the input (x1, x2, x3), which indicates that the inverse transformation undoes the effects of the original transformation. Therefore, the given linear transformation is invertible, and its inverse is T^⁻1(x1, x2, x3) = (x1, x2 + x3, 0).

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The probability that none of the students in the second group have been called upon is approximately 0.9069.

What is the probability?

Probability is a mathematical concept that measures the likelihood or chance of an event occurring. It is expressed as a number between 0 and 1, with 0 indicating that an event is impossible, and 1 indicating that an event is certain.

Given by question.

There are initially 24 students in the class, and 6 of them have already been called upon. Therefore, there are 18 students who have not yet been called upon.

For the first group of three students, Alice can choose any three students out of the 24, which can be done in ${24 \choose 3} $ ways.

For the second group of three students, Alice can only choose from the 18 students who have not yet been called upon. There are ${18 \choose 3} $ ways to choose three students out of the remaining 18.

To find the probability that none of the students in the second group have been called upon, we need to count the number of ways that this can happen. Let's call the six previously called students A, B, C, D, E, and F.

There are ${\(\frac{18}{choose 3}\)} $ total ways to choose the second group of three students. Of those, we want to count the number of ways that do not include any of the six previously called students.

To count this, we can use the principle of inclusion-exclusion. There are ${\(\frac{12}{choose 3}\)} $ ways to choose three students from the 12 remaining students who have not been called upon yet. However, this counts the cases where one or more of the six previously called students are also chosen.

To count the cases where exactly one of the previously called students is chosen, we can choose one of the six previously called students in ${6 \choose 1} $ ways, and then choose two of the remaining 12 students in ${\(\frac{12}{choose 3}\)} $ ways. Therefore, there are ${6 \choose 1} {\(\frac{12}{choose }\)} $ ways to choose three students where exactly one of the previously called students is chosen.

Similarly, there are ${\(\frac{6}{choose 2}\)} {\(\frac{6}{choose 1}\)} {\(\frac{6}{choose 0}\)} $ ways to choose three students where exactly two of the previously called students are chosen, and ${6 \choose 3} {12 \choose 0} $ ways to choose three students where all three of the previously called students are chosen.

Therefore, the number of ways to choose three students from the remaining 18 students where none of the previously called students are chosen is:

$${\(\frac{18}{choose 3}\)} - {\(\frac{6}{choose 1}\)} {\(\frac{12}{choose 2}\)} + {\(\frac{6}{choose 2}\)} {\(\frac{6}{choose 1}\)} {\(\frac{6}{choose 0}\)} - {\(\frac{6}{choose 3}\)} {\(\frac{12}{choose 0}\)} $$

Plugging in the values, we get:

$${\(\frac{18}{choose 3}\)} - {\(\frac{6}{choose 1}\)} {\(\frac{12}{choose 2}\)} + {\(\frac{6}{choose 2}\)} {\(\frac{6}{choose 1}\)} {\(\frac{6}{choose 0}\)} - {\(\frac{6}{choose 3}\)} {\(\frac{12}{choose 0}\)} = 7140 - 5940 + 540 - 20 = 740$$

Therefore, the probability that none of the students in the second group have been called upon is:

\(\frac{$$}{740}\)} {{\(\frac{18}{choose 3}\)}} = \frac {740}{816} = frac {185}{204} \approx. 0.9069$$

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Answer:

y=32.5÷5

Step-by-step explanation:

the 32.5 lbs of meat is distributed between 5 lions so 32.5÷5=y

Answer:

please see photo attached for detailed analysis.

Answer:

If the statement is true, lines a and b are parallel

Step-by-step explanation:

This is due to lines intersecting with line m at identical angles.

b) To find the joint density of the minimum and maximum of the U_i's, we can use the following approach:

Let M = min(U_1, U_2, U_3, U_4, U_5) and let X = max(U_1, U_2, U_3, U_4, U_5). Then we have:

P(M > m, X < x) = P(U_1 > m, U_2 > m, U_3 > m, U_4 > m, U_5 > m, U_1 < x, U_2 < x, U_3 < x, U_4 < x, U_5 < x)

Since the U_i's are independent and uniformly distributed on (0,1), we have:

P(U_i > m) = 1 - m, for 0 < m < 1

P(U_i < x) = x, for 0 < x < 1

Substituting these expressions, we get:

P(M > m, X < x) = (1 - m)^5 * x^5

Therefore, the joint density of M and X is:

f(M,X) = d^2/dm dx (1-m)^5 * x^5 = 30(1-m)^4 * x^4, for 0 < m < x < 1.

c) To find P(R > 0.5), we need to find the probability that the distance between the minimum and maximum of the U_i's is greater than 0.5. We can use the following approach:

P(R > 0.5) = 1 - P(R <= 0.5)

Now, R <= 0.5 if and only if the difference between the maximum and minimum of the U_i's is less than or equal to 0.5. Therefore, we have:

P(R <= 0.5) = P(X - M <= 0.5)

To find this probability, we can integrate the joint density of M and X over the region where X - M <= 0.5:

P(R <= 0.5) = ∫∫_{x-m<=0.5} f(M,X) dm dx

The region of integration is the triangle with vertices (0,0), (0.5,0.5), and (1,1). We can split this triangle into two regions: the rectangle with vertices (0,0), (0.5,0), (0.5,0.5), and (0,0.5), and the triangle with vertices (0.5,0.5), (1,0.5), and (1,1). Therefore, we have:

P(R <= 0.5) = ∫_{0}^{0.5} ∫_{0}^{m+0.5} 30(1-m)^4 * x^4 dx dm + ∫_{0.5}^{1} ∫_{x-0.5}^{x} 30(1-m)^4 * x^4 dm dx

Evaluating these integrals, we get:

P(R <= 0.5) ≈ 0.5798

Therefore,

P(R > 0.5) = 1 - P(R <= 0.5) ≈ 0.4202.

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Step-by-step explanation:

x= 0 y= 3

y= mx+ b

b= 3

x= 0 y = 3

x= 2 y= 1

1= 2m+ 3

2m = -2

m= -1

y = -x + 3

In terms of pi means to include pi in your answer. In other words, don't use 3.14 or 22/7 for pi.

Answer:

(6,24)

Step-by-step explanation:

Hope this helped you!! If 4 times 4 is 16 then 6 times 4 is 24 babes...

Answer:

The answer wound be C. {-6, -5, -4, 4, 5, 6}.

Step-by-step explanation:

For g(x) = 1:

|x| - 3 = 1

|x| = 4

The equation |x| = 4 has two solutions: x = 4 and x = -4.

For g(x) = 2:

|x| - 3 = 2

|x| = 5

The equation |x| = 5 has two solutions: x = 5 and x = -5.

For g(x) = 3:

|x| - 3 = 3

|x| = 6

The equation |x| = 6 has two solutions: x = 6 and x = -6.

Now, we have six possible values for x: 4, -4, 5, -5, 6, and -6. Therefore, the domain of g(x) = |x| - 3, given that the range is {1, 2, 3}, is {-6, -5, -4, 4, 5, 6}.

Answer:jh

43

Step-by-step explanation:

Trust meTrust meTrust me ps

Y-intercept is P(0, 6). Then equation of the line which is perpendicular to y=4x-5 and passing through P is : x + 4y = 28.

The equations are

⇒5x+3y−35=0

⇒2x+4y−28=0

By cross multiplication

⇒ [3×(−28)−4×(−35)]x​ = [−35×2−(−28)×5]y​ = [5×4−2×3]1

​⇒ −84+140x​ = −70+140y​ = 20−61

​⇒ 56x = 70y​ = 141

⇒ 56x​ = 141​ ⇒14x=56⇒x=4

⇒ 70y​ = 141​ ⇒14y=70⇒y=5

⇒x=4,y=5

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y = -2x - 9 ----------- 1

y = 3x + 1 -------------- 2

Step 1

Substitute y from equation 1 to equation 2.

y = -2x - 9

3x + 1 = -2x - 9

Step 2

Collect like terms

3x + 2x = - 9 - 1

5x = -10

Step 3

Divide through by 5

x = -10/5

x = -2

Step 4

Substitute x in equation 2 to find y.

y = 3x + 1

y = 3(-2) + 1

y = -6 + 1

y = -5

So the solution is (-2, -5)

Answer:4 PCs and 8 Macs

Step-by-step explanation:

They consists of equations and unknown variables. There are 4 PCs and 8 Mac in the room

They consists of equations and unknown variables

Let the number of PCs be x

Let the number of Mac be y

If Mke has 12 computers, then;

x + y = 12

If there are two Macs for every PC in his classroom, then;

y = 2x

Substitute

x + 2x = 12

3x = 12

x = 4

Recall y = 2x

y = 2(4)

y = 8

There are 4 PCs and 8 Mac in the room

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