Capture-recapture studies are common in ecology. One form of the study is conducted as follows. Suppose we have a population of N deer in a study area. Initially n deer from this population are captured, marked so that they can be identified as having been captured, and returned to the population. After the deer are allowed to mix together, m deer are captured from the population and the number k of these deer having marks from the first capture is observed.


Required:

Assuming that the first and second captures can be considered random selections from the population and that no deer have either entered or left the study area during the sampling period, what is the probability of observing k marked deer in the second sample of m deer?

Answer:

one answer

x = 2

Step-by-step explanation:

Answer:

Step-by-step explanation:

Sorry I can't explain how it is done. It is very difficult to explain on paper.

Answer:

sequence

Step-by-step explanation:

a sequence is essentially a set [group/list] of numbers, and each number has a specific placement [meaning that there is an order]

hope this helps!!

Answer: this, a set of number in an order, is called a sequence

fill in the blank: sequence

0.03 is closest to this rate in square meters per minute. The correct option is option (A)

Given that the area of a rectangular region is increasing at a rate of 20 square feet per hour. find which of the following is closest to this rate in square meters per minute.

Using 1 meter = 3.28 feet.

1 square foot is equal to (1/3.28)² square meters. Therefore, 1 square foot = 0.0929 square meters. Rate of change of area = 20 square feet per hour.

Therefore, Rate of change of area in square meters per minute

= (20/60) x (0.0929)

= 0.0303 = 0.03 (rounded to two decimal places).Therefore, the option (A) 0.03 is the closest rate to the given rate of change of area in square meters per minute.

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Answer:

Step-by-step explanation:

Slope is 0

Answer:The answer to the slope is 0.

There are 109,761 more writers with a bachelor's degree or higher than those with only some college experience and no degree.

From the given data, Percent of writers with some college experience but no degree = 12.4%

Percent of writers with a bachelor's degree or higher = 84.1%The percentage of writers without any college experience can be found by:

Percent of writers without any college experience = 100% - (12.4% + 84.1%)

Percent of writers without any college experience = 3.5%T

Total number of writers with some college experience but no degree = 12.4% of 153,000= 18,972

Total number of writers with a bachelor's degree or higher = 84.1% of 153,000= 128,733

Total number of writers without any college experience = 3.5% of 153,000= 5,355

Therefore, the number of writers with a bachelor's degree or higher than those with only some college experience and no degree is:

128,733 - 18,972 = 109,761

Hence, there are 109,761 more writers with a bachelor's degree or higher than those with only some college experience and no degree.

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The area of the regular polygon is approximately 177.8 square units.

To find the area of a regular polygon, we can use the formula:

Area = ½(apothem)(perimeter)

We know that a regular polygon has all sides and angles equal. Therefore, we can use the formula for the perimeter of a regular polygon:

Perimeter = number of sides × length of a side

We can use the Pythagorean theorem to find the length of a side:

(length of a side/2)² + (apothem)² = (perpendicular distance from the center to a side)²

(length of a side/2)² + (13.3)² = (16)²

(length of a side/2)² = 256 - 176.89

length of a side/2 ≈ 7.92

length of a side ≈ 15.84

Now that we have the apothem and the perimeter, we can use the formula for the area of a regular polygon:

Area = ½(13.3)(15.84×5) ≈ 177.8

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Answer: A linear equation in the form y = mx + b can be determined by examining the values in the table. To find the value of m, we can use the formula for the slope of a line, which is (y2 - y1) / (x2 - x1). Using the first and last values in the table, we can compute the slope as (7 - 15) / (4 - 0) = -1/4.

Therefore, the equation that represents the table is:

y = (-1/4) * x + b

We can use any of the given points to find the value of b. For example, using the point (1, 13), we can solve the equation to find b:

13 = (-1/4) * 1 + b

b = 14 - 1/4 = 13 3/4

Therefore, the final equation that represents the table is:

y = (-1/4) * x + 13 3/4

Answer:

r² = (2 - (-1))² + (1 - 4)² = 3² + (-3)² = 9 + 9 = 18

(x + 1)² + (y - 4)² = 18

The general form of the equation of the circle is `(x − h)² + (y − k)² = r²`, where the center of the circle is at `(h, k)` and the radius of the circle is `r`.

Given center: `(h, k) = (-1, 4)`Given solution point: `(x, y) = (2, 1)`Let the radius be `r`.

Then, using the distance formula, we can calculate the radius `r`.Distance between center and solution point is `r`i.e. `(x − h)² + (y − k)² = r²

Plugging in the values, we get:`(2 − (-1))² + (1 − 4)² = r²`

Solving for `r`, we get:`3² + (-3)² = r²`

⇒ 18 = r²

⇒ r = ±sqrt(18)`

The center of the circle is `(h, k) = (-1, 4)` and radius of the circle is `r = ±sqrt(18)`.

Hence, the equation of the circle in the general form is`(x − (-1))² + (y − 4)² = (±sqrt(18))²`

On simplifying, we get:`(x + 1)² + (y − 4)² = 18`Therefore, the required equation of the circle in the general form is `(x + 1)² + (y − 4)² = 18`.

Thus, the equation of the circle in the general form is `(x + 1)² + (y − 4)² = 18`.

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MN+NO=MO

Where N is the midpoint of MO

Therefore:

MN = NO

MN = 8

NO = 8

8 + 8 = MO

MO = 16

Now:

MO + OQ = MQ

If O is the midpoint of MQ:

MO = OQ

OQ = 16

Therefore:

MQ = 16 + 16 = 32

The probability that the card is greater than 2 but less than 9 is 6 / 13.

Probability is the branch of discrete mathematics. It is used for calculating how likely an event is to occur or happen.

P ( E )   =   Number of favourable outcomes / Total number of outcomes → 1

In an ordinary deck of cards,

                                                       Queen, King

As per the question,

A card is drawn from an ordinary deck and that is red.

⇒ Total number of red cards in an ordinary deck = 26 cards

∴   Total number of outcomes  = 26

The card that is greater than 2 but less than 9,

⇒ Number of cards that are greater than 2 but less than 9 in red suite = 12

∴  Number of favourable outcomes = 12

Substitute the values in 1,

P ( E )   =   Number of favourable outcomes / Total number of outcomes

            =  12 /26

P ( E )    =  6 / 13

Therefore, 6 / 13 is the probability that the card is drawn in a red suite greater than 2 but less than 9.

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The complete question is

A card is drawn from an ordinary deck and we are told that it is red. What is the probability that the card is greater than 2 but less than 9?

Answer:

0.45 miles per minute and 6.75

Step-by-step explanation:

27/60=0.45<-- Miles per minute

0.45x15=6.75<--Miles in 15 minutes

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The volume of the liquid in the bigger flask which is in the shape of the cone is V = 980π.

A cone is a recognizable three-dimensional geometric shape with a smooth and curving surface that is directed upward in mathematics. The

Greek word "konos," which denotes a peak or a wedge, is the source of the English word "cone."

The apex is the pointy end, while the base is the level area.

So, the volume of liquid in the bigger flask:

We know that the radius of the bigger flask is 14cm.

The liquid is filled to a height of 15cm.

The volume of cone formula: V = πr²h/3

Substitute values as follows:

V = πr²h/3

V = π(14)²15/3

V = π196*5

V = 980π

Therefore, the volume of the liquid in the bigger flask which is in the shape of the cone is V = 980π.

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The solution of the given system of equations is x = -4, y = 5 and z = 2 is the answer.

The system of equations given below:x + 2y + 3z = 11;2x + 4y + 5z = 21;3x + 5y + 6z = 27.

Here, we will solve this system of equations using inverse of the matrix method as follows:

We can write the given system of equations in matrix form as AX = B where, A = [1 2 3; 2 4 5; 3 5 6], X = [x; y; z] and B = [11; 21; 27].

The inverse of matrix A is given by the formula: A-1 = (1/ det(A)) [d11 d12 d13; d21 d22 d23; d31 d32 d33]  where,

d11 = A22A33 – A23A32 = (4 × 6) – (5 × 5) = -1,

d12 = -(A21A33 – A23A31) = -[ (2 × 6) – (5 × 3)] = 3,

d13 = A21A32 – A22A31 = (2 × 5) – (4 × 3) = -2,

d21 = -(A12A33 – A13A32) = -[(2 × 6) – (5 × 3)] = 3,

d22 = A11A33 – A13A31 = (1 × 6) – (3 × 3) = 0,

d23 = -(A11A32 – A12A31) = -[(1 × 5) – (2 × 3)] = 1,

d31 = A12A23 – A13A22 = (2 × 5) – (3 × 4) = -2,

d32 = -(A11A23 – A13A21) = -[(1 × 5) – (3 × 3)] = 4,

d33 = A11A22 – A12A21 = (1 × 4) – (2 × 2) = 0.

We have A-1 = (-1/1) [0 3 -2; 3 0 1; -2 1 0] = [0 -3 2; -3 0 -1; 2 -1 0]

Now, X = A-1 B = [0 -3 2; -3 0 -1; 2 -1 0] [11; 21; 27] = [-4; 5; 2]

Therefore, the solution of the given system of equations is x = -4, y = 5 and z = 2.

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Answer:

\( 2 - 4i\)

Step-by-step explanation:

\( \frac{10}{1 + 2i} \\ \\ = \frac{10}{1 + 2i} \times \frac{1 - 2i}{1 - 2i} \\ \\ = \frac{10(1 - 2i)}{ {1}^{2} - {(2i)}^{2} } \\ \\ = \frac{10 - 20i}{ {1} - {4i}^{2} } \\ \\ = \frac{10 - 20i}{ {1} - {4( - 1)} } \\ ( \because \: {i}^{2} = - 1) \\ \\ = \frac{10 - 20i}{1 + 4} \\ \\ = \frac{5(2 - 4i)}{5} \\ \\ = 2 - 4i\)

The homogeneous equation and a particular solution of the given nonhomogeneous equation is \(& y=c_1 e^{-2 x}+c_2 e^{2 x}-\frac{1}{2}\).

The given nonhomogeneous equation is y" - 4y = 2

We are given \($y_1=e^{-2 x}$\)

Let \($y_2=u y_1$\)

Non-homogeneous differential equations are simply differential equations that do not satisfy the conditions for homogeneous equations. In the past, we’ve learned that homogeneous equations are equations that have zero on the right-hand side of the equation.

The two most common methods when finding the particular solution of a non-homogeneous differential equation are:

\($$\begin{aligned}& y_2=u e^{-2 x} \\& y_2^{\prime}=u^{\prime} e^{-2 x}-2 u e^{-2 x} \\& y_2^{\prime \prime}=u^{\prime \prime} e^{-2 x}-2 u^{\prime} e^{-2 x}-2 u^{\prime} e^{-2 x}+4 u e^{-2 x} \\& y_2^{\prime \prime}=u^{\prime \prime} e^{-2 x}-4 u^{\prime} e^{-2 x}+4 u e^{-2 x}\end{aligned}$$\)

Substitute in \($y^{\prime \prime}-4 y=0$\), we get

\($$\begin{aligned}& u^{\prime \prime} e^{-2 x}-4 u^{\prime} e^{-2 x}+4 u e^{-2 x}-4 u e^{-2 x}=0 \\& u^{\prime \prime} e^{-2 x}-4 u^{\prime} e^{-2 x}=0 \\& e^{-2 x}\left(u^{\prime \prime}-4 u^{\prime}\right)=0 \\& u^{\prime \prime}-4 u^{\prime}=0 \\& u^{\prime \prime}=4 u^{\prime}\end{aligned}$$\)

Substitute \($$u^{\prime}=v$ and $u^{\prime \prime}=v^{\prime}$\), we get

\($$\begin{aligned}& v^{\prime}=4 v \\& \frac{d v}{d x}=4 v \\& \frac{1}{v} d v=4 d x\end{aligned}$$\)

Integrate both sides, we get

\($u=\frac{1}{4} C_1 e^{4 x}+C_2$$\)

put in \($y_2=u y_1$\)

\($$y_2=\left(\frac{1}{4} C_1 e^{4 x}+C_2\right) e^{-2 x}$$\)

Choose \($$C_1=4$ and $C_2=0$\), we get

\($$y_2=e^{2 x}$$\)

\($$\begin{aligned}& y_c=c_1 y_1+c_2 y_2 \\& y_c=c_1 e^{-2 x}+c_2 e^{2 x}\end{aligned}$$\)

Particular Solution

\($$\begin{aligned}& y_y=A \\& y_y{ }^{\prime}=0 \\& y_y{ }^{\prime \prime}=0\end{aligned}$$\)

Substitute in \($y^{\prime \prime}-4 y=2$\), we get

\($$\begin{aligned}& 0-4 A=2 \\& -4 A=2 \\& A=-\frac{1}{2} \\& \therefore y_y=-\frac{1}{2}\end{aligned}$$\)

General Solution

\($$\begin{aligned}& y=y_6+y_y \\& y=c_1 e^{-2 x}+c_2 e^{2 x}-\frac{1}{2}\end{aligned}$$\)

Therefore, the second equation is \(& y_{2} =c_1 e^{-2 x}+c_2 e^{2 x}-\frac{1}{2}\).

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we have that

the landing area is a square

so

the area of a square is

A=b^2

and the perimeter is equal to

P=4b

we have

b=16.5 ft

A=16.5^2=272.25 ft2

P=16.5(4)=66 ft

Step-by-step explanation:

Step-by-step explanation:

Probability is the ratio of number of success/ total outcomes

So let calculate each probability

We have six total outcomes here in each scenario.

P(5)=1/6

P(1 or 2)=2/6=1/3

P(odd number )=3/6=1/2

P(not 6)= 5/6

Also

P(not 6)=1-P(6)=5/6

P(even number)=3/6=1/2

P(1,2,3,4)=4/6=2/3

Answer:

https://nrckids.org/CFOC/Infant_Toddlers

Step-by-step explanation:

The volume of the large emerald with a mass of 982.7 grams and a density of 2.76 is approximately 355.62 cubic centimeters.

Density is defined as the mass per unit volume. To find the volume, we can use the formula:

Density = Mass / Volume

Rearranging the formula, we get:

Volume = Mass / Density

Substituting the given values, we have:

Volume = 982.7 grams / 2.76

Calculating this, we find:

Volume ≈ 355.62 cubic centimeters

Therefore, the volume of the large emerald is approximately 355.62 cubic centimeters.

This means that if the emerald is shaped like a perfect cube, each side would measure approximately 7.07 centimeters (since the volume of a cube is given by side^3).

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Answer: below

Domain: (0,1,2)

Range: (15,18,21)

Step-by-step explanation: Domain is possible input values while range is possible output values. So if it is for 0 minutes it will be 15 degrees, 1 minute 18 degrees because 15 + 3( 0 or 1 or 2 etc.). And for 2 minutes it would be 21 degrees. This could go on forever in a graph but I picked 3 simple points, 0, 1, and 2 minutes.

Hope this helps!

The real-world problem involving a related set of two equations is given below:

Problem: Cost of attending a concert  is made up of base price and variable price per ticket. You are planning to attend a concert with your friends and want to know the number of tickets to purchase for lowest overall cost.

The related set of two equations are:

Equation 1: The total cost (C) of attending the concert is given by:

The equation C = B + P x N,

where:

B  = the base price

P  = the price per ticket,

N = the number of tickets purchased.

Equation 2: The maximum budget (M) a person have for attending the concert is:

The  equation M = B + P*X

where:

X = the maximum number of tickets a person can afford.

So by using the values of B, P, and M, you can be able to find the optimal value of N that minimizes the cost C while staying within your own budget M. so, you can now determine ticket amount to minimize costs and stay within budget.

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Answer: \(D. 6\sqrt{x} 2\) is the answer

Step-by-step explanation:

Answer:

I think 3/6

Step-by-step explanation:

3:6=3/6

Step-by-step explanation:

Hint :- FH is total length of the line. And FG is the length of the line till point G. We need tos subtract the total length and Length of FG

GH = FH - FG

GH = 15 - 9.7

GH = 5.3 cm

Answer:

GH = 5.3 mm

Step-by-step explanation:

the full length of the line is 15 mm

and FG = 9.7 mm Then GH= 15 - FG

= 15- 9.7 = 5.3

you can think of it like a rope with 15 mm length if you cut ✂️ 9.7 mm u will have 5.3 left

Answerh

Step-by-step explanation:

huh

Answer:

4

Step-by-step explanation:

The average rate of change of f(x) in the closed interval [ a, b ] is

\(\frac{f(b)-f(a)}{b-a}\)

Here [ a, b ] = [ 0, 4 ] , thus

f(b) = f(4) = - 4² + 8(4) - 4 = - 16 + 32 - 4 = 12

f(a) = f(0) = - 4 , then

average rate of change = \(\frac{12-(-4)}{4-0}\) = \(\frac{12+4}{4}\) = \(\frac{16}{4}\) = 4