Can you use the associative property with subtraction?

\(\textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\[-0.35em] ~\dotfill\\\\ \sqrt{20^2-16^2}=PQ\implies 12=PQ \\\\\\ PS=\sqrt{12^2+5^2}\implies \boxed{PS=13}\)

Check the picture below.

Answer:

PS=13

Step-by-step explanation:

Answer:

.38

Step-by-step explanation:

sin is the opposite side from angle T over the hypotenuse.

5/13

Answer: f(0)=3/2, f(4)=7/2

Answer:

b and e

Step-by-step explanation:

Answer:

Original price= $150

Step-by-step explanation:

Giving the following information:

Sales pirce= $97.5

Sales discount= 35% decrease

To calculate the original price, we need to use the following formula:

Original price= sales price / (1 - discount)

Original price= 97.5 / 0.65

Original price= $150

The product of 5 × 5ab × 5, a, b is 125ab5 when written in its most Simple form

The expression 5 × 5ab × 5, a, b is equal to 125ab5. The reasoning is that when we multiply 5 by 5ab, we get 25ab, which we then multiply by 5 to get 125ab. Since a, b are variables, the product 125ab5 is the product of 5 × 5ab × 5, a, b, when written in its most simple form.

The expression 5 × 5ab × 5, a, b is an algebraic expression, which consists of numbers, variables, and operators. Variables are usually represented by letters or other symbols, while operators such as +, -, ×, ÷, ^ are used to indicate mathematical operations such as addition, subtraction, multiplication, division, and exponentiation. In algebra, expressions can be simplified by combining like terms, expanding brackets, and applying other rules of arithmetic.

The most simple form of an expression is the one that cannot be further simplified.In the given expression, 5 × 5ab × 5, a, b, we can see that the number 5 appears three times, so we can simplify the expression by multiplying the numbers together.

Similarly, we can multiply the variables a and b together to get the term ab. Finally, we write the result as 125ab5, which is the product of 5 × 5ab × 5, a, b, in its most simple form.

Therefore, the product of 5 × 5ab × 5, a, b is 125ab5 when written in its most simple form.

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The Polynomial x⁵ + x³ - 5 is divided by x - 2, the quotient is x⁴ + 3x³ + 6x² + 12x + 24, and the remainder is 48.

The quotient and remainder when the polynomial x⁵ + x³ - 5 is divided by x - 2, we can use polynomial long division. Here's the step-by-step process:

1. Write the dividend (x⁵ + x³ - 5) and the divisor (x - 2).

   x - 2 | x⁵ + x³ + 0x² + 0x - 5

2. Divide the first term of the dividend (x⁵) by the first term of the divisor (x) to get x⁴. Write x⁴ above the line. x⁴

   x - 2 | x⁵ + x³ + 0x² + 0x - 5

3. Multiply the divisor (x - 2) by the quotient term (x⁴) to get x⁵ - 2x⁴. Write this under the dividend and subtract it.  x⁴

  x - 2 | x⁵ + x³ + 0x² + 0x - 5

 - (x⁵ - 2x⁴)

3x⁴ + 0x³ + 0x² + 0x - 5

4. Bring down the next term (-5) from the dividend.

x⁴ + 3x³

x - 2 | x⁵ + x³ + 0x² + 0x - 5

- (x⁵ - 2x⁴)

3x⁴ + 0x³ + 0x² + 0x - 5

5. Divide the first term of the new dividend (3x⁴) by the first term of the divisor (x) to get 3x³. Write 3x³ above the line.

 x⁴ + 3x³

   x - 2 | x⁵ + x³ + 0x² + 0x - 5

 - (x⁵ - 2x⁴)

3x⁴ + 0x³ + 0x² + 0x - 5

6. Multiply the divisor (x - 2) by the new quotient term (3x³) to get 3x⁴ - 6x³. Write this under the new dividend and subtract it.

x⁴ + 3x³

x - 2 | x⁵ + x³ + 0x² + 0x - 5

- (x⁵ - 2x⁴)

3x⁴ + 0x³ + 0x² + 0x - 5

- (3x⁴ - 6x³)

6x³ + 0x² + 0x - 5

7. Repeat steps 4-6 until you have subtracted all terms.

x⁴ + 3x³ + 6x² + 12x + 24

x - 2 | x⁵ + x³ + 0x² + 0x - 5

- (x⁵ - 2x⁴)

3x⁴ + 0x³ + 0x² + 0x - 5

- (3x⁴ - 6x³)

6x³ + 0x² + 0x - 5

- (6x³ - 12x²)

12x² + 0x + 0

 - (12x² - 24x)

 24x + 0

- (24x - 48)

 48

8. The quotient is x⁴ + 3x³ + 6x² + 12x + 24, and the remainder is 48.

Therefore, when the polynomial x⁵ + x³ - 5 is divided by x - 2, the quotient is x⁴ + 3x³ + 6x² + 12x + 24, and the remainder is 48.

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Answer:

Step-by-step explanation:

In the Intermediate Phase of mathematics education, one topic that demonstrates a hierarchical and logical progression in patterns, functions, and algebra is the concept of "Linear Equations."

The topic of Linear Equations in the Intermediate Phase builds upon the foundation laid in earlier grades and serves as a stepping stone towards more advanced algebraic concepts. Here is an overview of the topic sequence and content area spread for Linear Equations:

Introduction to Variables and Expressions:

Students are introduced to the concept of variables and expressions, learning to represent unknown quantities using letters or symbols. They understand the difference between constants and variables and learn to evaluate expressions.

Solving One-Step Equations:

Students learn how to solve simple one-step equations involving addition, subtraction, multiplication, and division. They develop the skills to isolate the variable and find its value.

Solving Two-Step Equations:

Building upon the previous knowledge, students progress to solving two-step equations. They learn to perform multiple operations to isolate the variable and find its value.

Writing and Graphing Linear Equations:

Students explore the relationship between variables and learn to write linear equations in slope-intercept form (y = mx + b). They understand the meaning of slope and y-intercept and how they relate to the graph of a line.

Systems of Linear Equations:

Students are introduced to the concept of systems of linear equations, where multiple equations are solved simultaneously. They learn various methods such as substitution, elimination, and graphing to find the solution to the system.

Word Problems and Applications:

Students apply their understanding of linear equations to solve real-life word problems and situations. They learn to translate verbal descriptions into algebraic equations and solve them to find the unknown quantities.

The content area spread for Linear Equations includes concepts such as variables, expressions, equations, operations, graphing, slope, y-intercept, systems, and real-world applications. The progression from simple one-step equations to more complex systems of equations reflects a logical sequence that builds upon prior knowledge and skills.

By following this hierarchical progression, students develop a solid foundation in algebraic thinking and problem-solving skills. They learn to apply mathematical concepts and procedures in a systematic and logical manner, paving the way for further exploration of patterns, functions, and advanced algebraic topics in later phases of mathematics education.

Answer:

50 bats total

Step-by-step explanation:

To solve this problem, all one has to do is, set up a proportion, remember, a proportion is;

\(\frac{part}{whole} = \frac{percent}{100}\)

In this case;

\(\frac{hits}{total.bats} = \frac{percent}{100}\)

It is given that;

percent  - 60%

hits - 30

Now substitute in the values and solve;

\(\frac{30}{total.bats} = \frac{60}{100}\)

Solve, first simplify;

\(\frac{30}{total.bats} = \frac{3}{5}\)

Now use cross products;

150 = 3(total_bats)

Inverse operations;

150 = 3(total_bats)

/3      /3

50 = total_bats

Answer: X + 3

Step-by-step explanation:

Sum hints as to an addition statement and it specifies a variable X and the number 3 so the expression would be X + 3.

SUM MEANS ADDITION

HERE IT MEANS THE ADDITION OF x and 3

written as

\(x + 3\)

HOPE THIS HELPS

Answer:

1)  The functions are not inverses.

\(\textsf{2)} \quad g^{-1}(n)=&\dfrac{3}{8}n-\dfrac{7}{8}\)

\(\textsf{3)} \quad g^{-1}(x)&=\sqrt[3]{\dfrac{1}{2}-\dfrac{1}{2}x}\)

Step-by-step explanation:

The inverse composition rule states that if two functions are inverses of each other, then their compositions result in the identity function.

Given functions:

\(g(x) = 4 + \dfrac{7}{2}x \qquad \qquad f(x) = 5 - \dfrac{4}{5}x\)

Find g(f(x)) and f(g(x)):

\(\begin{aligned} g(f(x))&=4+\dfrac{7}{2}f(x)\\\\&=4+\dfrac{7}{2}\left(5 - \dfrac{4}{5}x\right)\\\\&=4+\dfrac{35}{2}-\dfrac{14}{5}x\\\\&=\dfrac{43}{2}-\dfrac{14}{5}x\\\\\end{aligned}\)                 \(\begin{aligned} f(g(x))&=5 - \dfrac{4}{5}g(x)\\\\&=5 - \dfrac{4}{5}\left(4 + \dfrac{7}{2}x \right)\\\\&=5-\dfrac{16}{5}-\dfrac{14}{5}x\\\\&=\dfrac{9}{5}-\dfrac{14}{5}x\end{aligned}\)

As g(f(x)) or f(g(x)) is not equal to x, then f and g cannot be inverses.

\(\hrulefill\)

To find the inverse of a function, swap the dependent and independent variables, and solve for the new dependent variable.

Calculate the inverse of g(n):

\(\begin{aligned}y &= \dfrac{8}{3}n + \dfrac{7}{3}\\\\n &= \dfrac{8}{3}y + \dfrac{7}{3}\\\\3n &= 8y + 7\\\\3n-7 &= 8y\\\\y&=\dfrac{3}{8}n-\dfrac{7}{8}\\\\g^{-1}(n)&=\dfrac{3}{8}n-\dfrac{7}{8}\end{aligned}\)

Calculate the inverse of g(x):

\(\begin{aligned}y &= 1-2x^3\\\\x &= 1-2y^3\\\\x -1&=-2y^3\\\\2y^3&=1-x\\\\y^3&=\dfrac{1}{2}-\dfrac{1}{2}x\\\\y&=\sqrt[3]{\dfrac{1}{2}-\dfrac{1}{2}x}\\\\g^{-1}(x)&=\sqrt[3]{\dfrac{1}{2}-\dfrac{1}{2}x}\\\\\end{aligned}\)

Answer:

1.

If the composition of two functions is the identity function, then the two functions are inverses. In other words, if f(g(x)) = x and g(f(x)) = x, then f and g are inverses.

For\(\bold{g(x) = 4 + \frac{7}{2}x\: and \:f(x) = 5 -\frac{4}{5}x}\), we have:

\(f(g(x)) = 5 - \frac{4}{5}(4 + \frac{7}{2}x)\\ =5 - \frac{4}{5}(\frac{8+7x}{2})\\=5 - \frac{2}{5}(8+7x)\\=\frac{25-16-14x}{5}\\=\frac{9-14x}{5}\)

\(g(f(x)) = 4 + (\frac{7}{5})(5 - \frac{4}{5}x) \\=4 + (\frac{7}{5})(\frac{25-4x}{5})\\=4+ \frac{175-28x}{25}\\=\frac{100+175-28x}{25}\\=\frac{175-28x}{25}\)

As you can see, f(g(x)) does not equal x, and g(f(x)) does not equal x. Therefore, g(x) and f(x) are not inverses.

Sure, here are the inverses of the functions you provided:

2. g(n) = (8/3)n + 7/3

we can swap the roles of x and y and solve for y to find the inverse of g(n). In other words, we can write the equation as y = (8/3)n + 7/3 and solve for n.

y = (8/3)n + 7/3

n =3/8*( y-7/3)

Therefore, the inverse of g(n) is:

\(g^{-1}(n) = \frac{3}{8}(n - \frac{7}{3})=\frac{3}{8}*\frac{3n-7}{3}=\boxed{\frac{3n-7}{8}}\)

3. g(x) = 1 - 2x^3

We can use the method of substitution to find the inverse of g(x). We can substitute y for g(x) and solve for x.

\(y = 1 - 2x^3\\2x^3 = 1 - y\\x = \sqrt[3]{\frac{1 - y}{2}}\)

Therefore, the inverse of g(x) is:

\(g^{-1}(x) =\boxed{ \sqrt[3]{\frac{1 - x}{2}}}\)

In order for the relationship zyx ~ wvu to be correct, the following conditions must be true:

Corresponding angles are congruent: The angles formed by matching vertices should have the same measures in both triangles. This ensures that the corresponding angles are equivalent.

Corresponding sides are proportional: The lengths of the sides that connect the corresponding vertices of the triangles should have a consistent ratio. This implies that the corresponding sides are proportional to each other.

These conditions are based on the definition of similarity between two triangles. If both the corresponding angles are congruent and the corresponding sides are proportional, then the triangles zyx and wvu are considered similar (denoted by ~).

Therefore, in order for zyx ~ wvu to be correct, the congruence of corresponding angles and the proportionality of corresponding sides must hold true.

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The volume of the solid generated by revolving the regions bounded by the curves and lines about the​ y-axis is  8.90 unit³.

Since the region is the one for  then the intersection we are interested on is x=1 as it can also be seen in the graph.

Where h(x) is the height of the shell which here is the distance between the parabola and the line, so  (since the line is on the top we subtract from it the parabola

Notice the limits of the integral are the x-axis (x=0) and the intersection of the parabola and the line that we found before (x=1)

We want the volume generated when the area bounded by the curves :

v = x2 v = 8 —7x , and

x = 0 for x > 0 is revolved about the y axis using the cylindrical shell method .

The intersection of y = x2 and y = 8 —7x is :

y= x2 = 8 — 7x x2 + 7x —8 = 0

(x + 8)(x — 1) = 0 x = —8 or

x = 1 .

We thus have for x > 0 the two curves intersect at x = 1 and y = 12 = 1 .

The limits for integration are --- 0 <x < 1 .

The upper curve is --- y2 = 8 —7x ,

and the lower curve is --- yi = x2 .

The height of the shell is --- h = y2 -yi = 8 —7x — x2 •

The radius of the shell is --- R = x •

\($$The surface area of the shell is :$$A=2 \pi \mathrm{Rh}=2 \pi x\left(8-7 x-x^2\right)=2 \pi\left(8 x-7 x^2-x^3\right) .$$The differential of volume which is the cylindrical shell is :$$\mathrm{dv}=\mathrm{Adx}=2 \pi\left(8 x-7 x^2-x^3\right) \mathrm{dx}$$\)

\($$We then have the volume of revolution is :$$\begin{aligned}v & =2 \pi \int_0^1\left(8 x-7 x^2-x^3\right) \mathrm{d} x \\& =2 \pi\left(4 x^2-\frac{7}{3} x^3-\frac{1}{4} x^4\right)_0^1 \\& =2 \pi\left[4\left(1^2-0^2\right)-\frac{7}{3}\left(1^3-0^3\right)-\frac{1}{4}\left(1^4-0^4\right)\right] \\& =2 \pi\left(4-\frac{7}{3}-\frac{1}{4}\right) \\& =2 \pi\left(\frac{48-28-3}{12}\right) \\& =2 \pi\left(\frac{17}{12}\right) ; \text { or, we have : } \\v & =\frac{17 \pi}{6} .\end{aligned}$$\)

17π/6 = 8.90 unit³

Thus, The volume of the solid generated by revolving the regions bounded by the curves and lines about the​ y-axis is  8.90 unit³.

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Answer:

D.Z

u see how they have line in between as well, shows that they are going by 5 so 2.0 and then 2.5

and if it was asking for -2.5 which is negative two point five, you would choose A.U

Step-by-step explanation:

you made a lot of typos in the text.

I assume your meant the following :

the sum of two numbers is eight.

one number is four less than the other number.

the numbers : x, y

x + y = 8

x = y - 4

we use the second equation in the first :

y - 4 + y = 8

2y - 4 = 8

2y = 12

y = 6

x = y - 4 = 6 - 4 = 2

The perimeter of the given shape as represented in the task content is; 29 cm.

It follows from the task content that the perimeter of the given shape on the centimeter grid as required is to be determined.

Since each grid line has 1cm as it's length;

The perimeter of the shape is the sum of all side lengths of the shape;

Perimeter, P = 6+2+3+2+2+1+3+2+2+2+2+1

P = 29 cm

Hence, the perimeter of the shape is; 29 cm.

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Answer:

Refer to the step-by-step explanation.

Step-by-step explanation:

Come up with a monomial expression and solve it.

A monomial expression is an algebraic expression that consists of a single term. It is an expression that can contain variables, constants, and non-negative integer exponents, but there should be no addition or subtraction between different terms.

Here are a few examples of an monomial expression:

\(\hrulefill\)

Let's work with the monomial expression, 3x²y³z.

To solve this expression, I assume you would like to evaluate it for specific values of the variables x, y, and z. So let x=3, y=2, and z=1.

Plug these values into the expression:

3x²y³z

=> 3(3)²(2)³(1)

=> 3(9)(8)(1)

=> 27(8)(1)

=> 216(1)

=> 216

Thus, the expression is solved.

Step-by-step explanation:

At first, solve in brackets

Here, when we multiply 'minus' with 'minus', we get 'plus' as the answer

Answer:

1

Step-by-step explanation:

(-9 + 8)²

calculate

= ( -1 )²

multiply 1 by 1

when you multiply both negative the result would be positive: (-) × (-) = (+)

= 1

so, the answer is 1

The value of f'(x) at x = 1 is 1 for first order derivative of x^x^3.

A derivative in calculus is the rate of change of a quantity y with respect to another quantity x. It is also termed the differential coefficient of y with respect to x. Differentiation is the process of finding the derivative of a function.

Given that, x^x^3 and we have to find the first order derivative with respect to x and then find the value at x = 1.

Let's proceed to solve this question accordingly.

let f(x) = x^x^3

The first order derivative = f'(x) = d/dx(x^x^3)

First apply the generalized power rule, then we have

= x^x^3.d/dx(ln(x)x^3)

Applying the power rule, we get

= x^x^3 (d/dx(x^3).ln(x)+x^3.d/dx(ln(x)))

= x^x^3 (3x^2 ln(x) +x^3.1/x)

= x^x^3 (3x^2ln(x) +x^2)

On simplifying, we will get

= x^x^3+2(3ln(x)+1)

f'(x) = d/dx(x^x^3) = x^x^3+2(3ln(x)+1)

Now, at x = 1, we get

f'(x) = d/dx(x^x^3) = x^x^3+2(3ln(x)+1) = 1

Therefore, f'(x) = d/dx(x^x^3) = x^x^3+2(3ln(x)+1) = 1 is the required answer.

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Answer:

Both are not possible because they are both not teaching the 0 like any normal graph should

Step-by-step explanation:

Answer:

so the one on the right would be consistent and independent because they intersect and are not the same line. They have different y- intercepts and different slopes

Answer:

\(3(.7)^{x}\)

Step-by-step explanation:

If the slope is less than one but greater than zero, the graph will result in an exponential decay.

Option 2) f(x) = 3(0.7)ˣ shows exponential decay

In mathematics, exponential decay describes the process of reducing an amount by a consistent percentage rate over a period of time. It can be expressed by the formula y=a × (b)ˣ wherein y is the final amount, a is the original amount, b is the decay factor, and x is the amount of time that has passed, where 0<b<1

Given:

Option 1 )  f(x)=0.6(2ˣ) is not showing exponential decay because the value of b is greater than 1 thus it instead represents exponential growth.

Option 2) f(x) = 3(0.7)ˣ shows exponential decay because the value of b is less than 1

Similarly in Option 3) and 4) the value of b does not lie in the interval (0,1) and therefore they don't represent exponential decay.

Hence, the correct option is 2

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Answer:

Step-by-step explanation:

8.008.009

Answer:

Step-by-step explanation:

The angle framed by the line of sight and the horizontal (line from observer and object vertical point) is known as angle of elevation. It can be estimated from the known values of height and distance of the object. In other words, Angles of elevation or inclination are angles above the horizontal

on solving the provided question, we can say that by equation we Consequently, he will sell 16 automobiles at this price.

A number, a variable, or a mix of both, combined with certain operation symbols, make up an expression. An equal sign is used to denote the separation of two expressions in an equation.

Here,

Given: Number of cars sell in a day = 12

Price of a car =\($23,000\)

For each $300 price reduction dealer can sell two more cars per day.

Solution: Let there be x unit 300 price reduction

2x unit increase in sale of car

\(|R(x)=(15000-300x)(12+2x)\)

Cost

\(|C(x)=1000+12000 (12+2x)\)

Profit

\(|P(x)=(15000-300x)(12+2x)-1000+12000 (12+2x)\\15000(12+2x)–12000 (12+2x)-300x(12+2x)-1000\\=180000-144000+30000x-24000x -3600x -600-1000\\=36000+2400x-600 = P'(x)=-1200x +2400 = P"(x)=-1200\)

For critical points

\(P'(x)=0= -1200x + 2400=0= x=2\)

Since P"(x) <0at x = 2it is max profit 12+2x=12+2(2)=16

16cars per day he will sell

\(Price = 15000-300*16 = $10200\)

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Answer:

0

Step-by-step explanation:

x < 4 means all numbers less than 4, excluding 4 itself.

4.5 > 4.

5 > 4.

so 0 is the solution

Answer:

4

Step-by-step explanation:

interval notation ( negative infinity, 4)

9514 1404 393

Answer:

  (a)  -4

Step-by-step explanation:

The picture is fuzzy, but perhaps you want to evaluate ...

  \(-1\left|\dfrac{2}{3}-4\right|\div\dfrac{5}{6}=-1\left|-\dfrac{10}{3}\right|\div\dfrac{5}{6}\\\\=-\dfrac{10}{3}\div\dfrac{5}{6}=-\dfrac{20}{6}\div\dfrac{5}{6}=-\dfrac{20}{5}=\boxed{-4}\)

After answering the provided question, we can conclude that The slope answer is not listed as a choice, but this is the correct equation.

In mathematics, slope is the slope of the regression of a line or curve. It is a measure of the degree to which a function's y-value varies once the x-value changes. A line's slope is usually expressed as a letter m and is able to be calculated as follows: m = (y2 - y1) / (x2 - x1) (x1, y1) and (x2, y2) is some two important points on the line. The slope of a line can be favorable, negative, equal to 0, or unknown. A positive slope means the line rises up from left to right, whereas a slope means the line falls back from left to right.

To find the equation of the line passing through the point (4,-5) with slope 2, we can use the point-slope form of the equation of a line.

y - y1 = m(x - x1)

y - (-5) = 2(x - 4)

y + 5 = 2x - 8

y = 2x - 13

y = 2x - 13

The answer is not listed as a choice, but this is the correct equation.

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First, to find the new function that will have a horinzontal stretch with a factor of 5, we just need to substitute the values of x in the function by x/5 (we divide by 5 because it is a stretch. If it was a compression, we would multiply by 5):

Then, to find the new function with a reflection in the y-axis, we just need to substitute the values of x by -x (the minus sign will cause a reflection in the y-axis):

So the final function, starting from the function f(x) = √x, that will have a horizontal stretch with a factor of 5, followed by a reflection in the y-axis, is the function above.

The graph of the function y = -2x + 1/3 is added as an attachment

From the question, we have the following parameters that can be used in our computation:

y = -2x + 1/3

The above function is a linear function that has been transformed as follows

Next, we plot the graph using a graphing tool by taking not of the above transformations rules

The graph of the function is added as an attachment

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