Can you please help
4x^2-11x+7
Answers
Related Questions
A stop sign casts a shadow as shown in the
figure. How tall is the light pole to the nearest
tenth of a foot?
Answers
The answer of the given question based on the right angle triangle is , the height of the light pole to the nearest tenth of a foot is 9.3 feet.
What is Right angle triangle?A right-angled triangle, also known as a right triangle, is a triangle that has one angle equal to 90 degrees. The side opposite right angle is called hypotenuse, and other two sides is called legs. The leg opposite to a particular acute angle is known as the opposite side, and the leg adjacent to it is known as the adjacent side.
The Pythagorean theorem is a fundamental theorem that applies to all right-angled triangles. It states that square of hypotenuse of right-angled triangle is equal to sum of squares of its two legs
To determine the height of the light pole, we can use similar triangles.
Let's call height of light pole be "x". Then we have:
(height of stop sign) / (length of stop sign's shadow) = (height of light pole)/(length of light pole's shadow)
Substituting the given values, we have:
8/12 = x/14
Simplifying this equation, we get:
x = (8/12) * 14 = 9.33 feet
Therefore, the height of the light pole to the nearest tenth of a foot is 9.3 feet.
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Prove that if f′(x)=g′(x) for all x in (a,b), then there is a constant C such that f(x)=g(x)+C on (a,b). [Hint: Apply the Constant Function, Theorem to h(x)=f(x)−g(x).]
Answers
We have proven that if f′(x) = g′(x) for all x in (a, b), then there exists a constant C such that f(x) = g(x) + C on (a, b).
To prove that if f′(x) = g′(x) for all x in (a, b), then there is a constant C such that f(x) = g(x) + C on (a, b), we can make use of the Constant Function Theorem. The Constant Function Theorem states that if a function h(x) has derivative equal to zero on an interval (a, b), then h(x) must be a constant on that interval.
Let h(x) = f(x) - g(x). We want to show that h(x) is a constant on (a, b). Taking the derivative of h(x), we have h'(x) = f'(x) - g'(x).
Given that f'(x) = g'(x) for all x in (a, b), we have h'(x) = 0 for all x in (a, b). By the Constant Function Theorem, this implies that h(x) is a constant on (a, b).
Let's denote this constant by C. Therefore, we have h(x) = C for all x in (a, b), which implies f(x) - g(x) = C. Rearranging the equation, we get f(x) = g(x) + C.
Hence, we have proven that if f′(x) = g′(x) for all x in (a, b), then there exists a constant C such that f(x) = g(x) + C on (a, b).
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Which of the following statements are true? If P(E) = 0 for event E, then E= 0. If E = 0, then P (E) = 0. If Ej U E2 = 1, then P (Ei) + P(E2) = 1. If P (E1) + P(E2) = 1, then E1 U E2 = 12. If El n E2 = 0 and E1 U E2 12, then P (E1) +P(E2) = 1. If P (E1) + P(E2) = 1, then Ein E2 = 0 and E1 U E2 = 1. +
Answers
If P(E1) + P(E2) = 1, then E1 n E2 = 0 and E1 U E2 = 1. The above statement is also true.
E1 U E2 = 1 means either E1 or E2 can occur. E1 n E2 = 0 means the events are mutually exclusive, meaning that they cannot happen at the same time.
The following statements that are true are the following:
If E = 0, then P(E) = 0.If P(E1) + P(E2) = 1, then E1 U E2 = 1.If P(E1) + P(E2) = 1, then E1 n E2 = 0 and E1 U E2 = 1.The probability is a measure of the likelihood of an event happening. An event with a probability of 0 means that the event cannot happen. Therefore, if P(E) = 0 for event E, then E = 0.
Therefore, If E = 0, then P(E) = 0. The above statement is true. If E = 0, it is the same as stating that event E can not happen. Thus, there is no chance of P(E).
Therefore, P(E1) + P(E2) = 1, then E1 U E2 = 1. The above statement is true as well. Here, E1 U E2 means the probability of both E1 and E2 occurring. Hence, it is the sum of the probability of E1 and E2, which is equal to 1.
It means that one of the events has to happen, or both events have to happen.
Hence, if P(E1) + P(E2) = 1, then E1 n E2 = 0 and E1 U E2 = 1. The above statement is also true.
E1 U E2 = 1 means either E1 or E2 can occur. E1 n E2 = 0 means the events are mutually exclusive, meaning that they cannot happen at the same time.
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i need help i don’t understand this
Answers
Answer:
145°
Step-by-step explanation:
180 - 35 = 145
145°
YOU WILL GET 50 OR 100 POINTS TO THE FIRST PERSON TO ANWSER!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! Antonio circled 72, 78, 84, and 90 on a hundreds chart. If Antonio continues his pattern, what two numbers will be next in the pattern?
Answers
Answer:
96, 102Step-by-step explanation:
We can observe the numbers 72, 78, 84, 90 form an arithmetic sequence with common difference of 6.
It can be continued by adding 6 to the last number:
90 + 6 = 9696 + 6 = 10272,78,84,90..are in AP
a=72d=6\(\\ \rm\longmapsto a_5=72+4(6)=72+24=96\)
\(\\ \rm\longmapsto a_6=72+5(6)=72+30=102\)
y = 2/3x - 1
y = -x + 4
Answers
Answer:
What is the question. Are you looking for a system solution?
Suppose K⊆Rn is compact, f:K→R is continuous, and ϵ>0. Show that there is a number A>0 such that
|f(x)−f(y)|≤A∥x−y∥+ϵ,∀x,y∈K.
Answers
By using the concept of compact set, it can be proved that
|f(x)−f(y)|≤A∥x−y∥+ϵ,∀x,y∈K.
What is compact set?
A set K is said to be compact if every open cover of K has a finite subcover.
Let K⊆Rn is compact f:K→R is continuous, and ϵ>0
Let there exist \(x_n, y_n\) ∈ K such that |f(\(x_n\))−f(\(y_n\))| > n∥\(x_n\)−\(y_n\)∥+ϵ,
Since K is compact there is a subsequence \(x_{nk}\) and \(y_{nk}\) of \(x_n, y_n\) respectively such that \(x_{nk}\) converges to x and \(y_{nk}\) converges to y.
So, |f(\(x_{nk}\))−f(\(y_{nk}\))| > \(n_k\)∥\(x_{nk}\)−\(y_{nk}\)∥+ϵ,
Since f is continuous,
We can write
|f(x)−f(y)| > \(n_k\)∥x - y∥+ϵ,
This is true for infinite many \(n_k\)
So ||x - y|| = 0
|f(x) - f(y)| > ϵ, a contradiction since f is continuous
So, there is a number A>0 such that
|f(x)−f(y)|≤A∥x−y∥+ϵ,∀x,y∈K.
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Please help math i need help
Answers
Answer:
Step-by-step explanation:
Malaki constructed \overline{CG}
CG
start overline, C, G, end overline parallel to \overline{AB}
AB
start overline, A, B, end overline through point CCC.
Which of the following statements best justifies why \overleftrightarrow{CG}
CG
C, G, with, \overleftrightarrow, on top is parallel to \overleftrightarrow{AB}
AB
A, B, with, \overleftrightarrow, on top?
Choose 1 answer:
Choose 1 answer:
(Choice A)
A
Lines perpendicular to the same transversal are parallel.
(Choice B)
B
Lines with supplementary same-side angles are parallel.
(Choice C)
C
Lines with congruent alternate interior angles are parallel.
(Choice D)
D
Lines with congruent corresponding angles are parallel.
Answers
Answer: Lines with congruent corresponding angles are parallel.
CG is parallel to AB because Lines with congruent corresponding angles are parallel.
How to define transverse lines?From the given image, we see that there is a transverse line cutting across lines AB and CG.
Now, from transverse line theorem we know that If two parallel lines are cut by a transversal, the corresponding angles are congruent. If two lines are cut by a transversal and the corresponding angles are congruent, the lines are parallel.
Thus, we can conclude that CG is parallel to AB because Lines with congruent corresponding angles are parallel.
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In ΔEFG, g = 34 inches, e = 72 inches and ∠F=21°. Find the area of ΔEFG, to the nearest square inch.
Answers
The area of triangle EFG, to the nearest square inch, is approximately 1061 square inches.
To find the area of triangle EFG, we can use the formula:
\(Area = (1/2) \times base \times height\)
In this case, the base of the triangle is FG, and the height is the perpendicular distance from vertex E to side FG.
First, let's find the length of FG. We can use the law of cosines:
FG² = EF² + EG² - 2 * EF * EG * cos(∠F)
EF = 72 inches
EG = 34 inches
∠F = 21°
Plugging these values into the equation:
FG² = 72² + 34² - 2 * 72 * 34 * cos(21°)
Solving for FG, we get:
FG ≈ 83.02 inches
Next, we need to find the height. We can use the formula:
height = \(EF \times sin( \angle F)\)
Plugging in the values:
height = 72 * sin(21°)
height ≈ 25.52 inches
Now we can calculate the area:
\(Area = (1/2) \times FG \times height\\Area = (1/2)\times 83.02 \times 25.52\)
Area ≈ 1060.78 square inches
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Three integers have a mean of 9 a median of 9 and a range of 10
Find the three integers
Answers
Since the mean of the three integers is 9, we know that (x + y + 9)/3 = 9. This equation simplifies to x + y = 0.
Since the range of the three integers is 10, we know that the difference between the largest and smallest integers is 10. The largest integer is 9 + (10/2) = 14 and the smallest integer is 9 - (10/2) = 4.
We can now set up the following system of equations to find the values of x and y:
x + y = 0
4 <= x, y <= 14
The only solution to this system of equations is x = 7 and y = -7. Therefore, the three integers are 4, 7, and 9.
1. there are 18 mathematics majors and 325 computer science majors at a college. a) in how many ways can two representatives be picked so that one is a mathematics major and the other is a computer science major? b) in how many ways can one representative be picked who is either a
Answers
a) two representatives be picked in 5850 ways so that one is a mathematics major and the other is a computer science major. b) one representative be picked in 343 ways who is either a mathematics major or a computer science major.
Product Rule: If one event occurs in m ways and a second event occurs in n ways, the number of ways the two events occur in the sequence is m×n ways.
Sum Rule: If an event occurs either in m ways or in n ways (non-overlapping), the number of ways the event can occur is m+n ways.
according to the question,
Mathematics majors =18 and Computer science majors = 325
A. We need to use the product rule because the first event is picking up a Mathematics major and the second event is picking up a computer science major.
= 18 x 325
= 5850
B. Here sum rule is applicable because the event is picking up a mathematics major or a computer science major.
= 18 + 325
= 343
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(complete question)
there are 18 mathematics majors and 325 computer science majors at a college. a) in how many ways can two representatives be picked so that one is a mathematics major and the other is a computer science major? b) in how many ways can one representative be picked who is either a mathematics major or a computer science major.
if g(x)=lnx and f is a differentiable function of x, which of the following is equivalent to the derivative of f(g(x)) with respect to x ?
a. f'(1/x)
b. f'(x)/x
c.f' (In x)
d. f'(In x)/x
Answers
The derivative of f(g(x)) with respect to x is f'(1/x).
What are Derivatives?The term derivative refers to a type of financial contract whose value is dependent on an underlying asset, group of assets, or benchmark.
Given that, g(x)=ln x
Differentiation of ln x = 1/x
Hence, The derivative of f(g(x)) with respect to x is f'(1/x).
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Carson needs 3 quarts of water to make fruit punch, but has only a 1-cup measuring cup. She knows there are 2 cups in 1 pint, and 2 pints in 1 quart. How can Carson find the number of cups of water she needs to make the punch.
FAST
Answers
Answer:
12
Step-by-step explanation:
3 quarts is 6 pints
6 pints is 12 cups
if there is 4 cups in a quart then 4x3=12
223
can be thought of as a whole number and a fraction.
Complete the statements below to show the number of wholes and the fractional part that make up 223
.
Answers
The second statement is the most commonly used way of writing 223 as a combination of a whole number and a fraction, but there are many other ways to express it.
What is a fraction ?
A fraction is a mathematical concept used to represent a part of a whole. It is represented by two numbers separated by a line, called a fraction bar or a solidus. The number above the line is called the numerator, and the number below the line is called the denominator
223 can be written as:
223 wholes and 0/1 as the fraction
222 wholes and 1/1 as the fraction
221 wholes and 2/1 as the fraction
...
0 wholes and 223/1 as the fraction
Note that
Therefore, the second statement is the most commonly used way of writing 223 as a combination of a whole number and a fraction, but there are many other ways to express it.
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The triangle on the right is a scaled copy of the triangle on the left. Identify the scale factor. Express your answer as a whole number or fraction in simplest form.
First triangle
15
15
second triangle
45/2
45/2
Answers
Answer: 3
Step-by-step explanation:
The scale factor is the ratio of corresponding side lengths of the two triangles.
In the given triangles, the length of the corresponding sides of the triangles are:
For the first triangle:
Side A = 15 units
Side B = 15 units
For the second triangle:
Side A = 45/2 units
Side B = 45/2 units
To find the scale factor, we can divide the length of one side of the second triangle by the corresponding length of the first triangle.
For example, we can use Side A:
Scale factor = (length of Side A of the second triangle) / (length of Side A of the first triangle)
Scale factor = (45/2) / 15
Scale factor = (45/2) * (1/15)
Scale factor = 3/2
Since the two triangles are scaled copies of each other, the scale factor should be the same for all corresponding sides.
Thus, the scale factor is 3 (in simplest form).
Which quadrilaterals have all of the properties of a parallelogram?
A)rhombus, kite, and trapezoid
B)rhombus, rectangle, and square
C)rhombus, kite, and square
D)rhombus, trapezoid, and rectangle
Answers
the answer is b. rhombus, rectangle, and square
hope this helps.
Find the domain and range of the following rational function. Use any notation. f(x)=(3)/(x-1) f(x)=(2x)/(x-4) f(x)=(x+3)/(5x-5) f(x)=(2+x)/(2x) f(x)=((x^(2)+4x+3))/(x^(2)-9)
Answers
Domain and Range of the given rational functions are:Given rational function f(x) = 3/(x-1)The denominator of f(x) cannot be zero.x ≠ 1 Therefore the domain of f(x) is {x | x ≠ 1}
The range of f(x) is all real numbers except zero.Given rational function f(x) = (2x)/(x-4)The denominator of f(x) cannot be zero.x ≠ 4 Therefore the domain of f(x) is {x | x ≠ 4}The range of f(x) is all real numbers except zero.Given rational function f(x) = (x+3)/(5x-5)The denominator of f(x) cannot be zero.5x - 5 ≠ 0x ≠ 1 Therefore the domain of f(x) is {x | x ≠ 1}The range of f(x) is all real numbers except 1/5.Given rational function f(x) = (2+x)/(2x)The denominator of f(x) cannot be zero.x ≠ 0 Therefore the domain of f(x) is {x | x ≠ 0}The range of f(x) is all real numbers except zero.Given rational function f(x) = (x^2+4x+3)/(x^2-9)For the denominator of f(x) to exist,x ≠ 3, -3
Therefore the domain of f(x) is {x | x ≠ 3, x ≠ -3}The range of f(x) is all real numbers except 1, -1. Function Domain Rangef(x) = 3/(x-1) {x | x ≠ 1} All real numbers except zerof(x) = (2x)/(x-4) {x | x ≠ 4} All real numbers except zerof(x) = (x+3)/(5x-5) {x | x ≠ 1} All real numbers except 1/5f(x) = (2+x)/(2x) {x | x ≠ 0} All real numbers except zerof(x) = (x^2+4x+3)/(x^2-9) {x | x ≠ 3, x ≠ -3} All real numbers except 1, -1
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can yall help me with this
Answers
In solving the following fraction, step (A) (4/7) × (-2/-1) is wrong and the correct step should be (4/7) × (-2/1).
What are fractions?Any number of equal parts is represented by a fraction, which also represents a portion of a whole. A fraction, such as one-half, eight-fifths, or three-quarters, indicates how many components of a particular size there are when stated in ordinary English.There are three main categories of fractions in mathematics. 'Proper fractions, incorrect fractions, and mixed fractions are these three types. The expressions with a numerator and a denominator are called fractions.So, the wrong step will be:
(4/7) ÷ (-1/2)Then, the next step should be:
(4/7) × (-2/1)But, the steps it is given as:
(4/7) × (-2/-1)Which makes the error.
Therefore, in solving the following fraction, step (A) (4/7) × (-2/-1) is wrong and the correct step should be (4/7) × (-2/1).
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If f is a differentiable function at a point 'a' and f′(a)=0 then which of the following is true. A. -f' (a) = lim h -->0 f(a)-f(a-h)/h. B. 1/2f' (a) = lim h -->0 f(a+2h)-f(a-h)/2h C. f' (a) = lim h -->0 f(a+2h)-f(a)/h. D. none of these
Answers
The correct option is B.
We know that if a function is differentiable at a point 'a', then it is also continuous at that point.
Option A is the formula for the one-sided derivative, which only holds if f'(a) exists and is finite. Since f'(a) is given to be non-zero, option A cannot be true.
Option C has a denominator of h, which means it is the formula for the one-sided derivative as h approaches 0. Again, since f'(a) is non-zero, option C cannot be true.
Option B is the formula for the two-sided derivative, which is valid even if function f'(a) is non-zero. Therefore, option B is true.
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Three angles are complementary. One angle is double the smallest angle. The largest angle is
triple the smallest angle. Find the measures of
the three angles.
Answers
Answer:
Step-by-step explanation:
A+B+C = 90°
A ≤ B ≤ C
C = 3A
B = 2A
A+B+C = A + 2A + 3A = 6A = 90°
A = 15°
B = 2A = 30°
C = 3A = 45°
Which segment is parallel to ED?
Answers
Answer:
AB
Step-by-step explanation:
The segments that are parallel need to be in the same direction ( up and down)
The segments that are parallel are FH, AB, GC
Answer:
AB
Step-by-step explanation:
since is a cube all of the angles are 90 degees and this only possibel whn the line That a vertical a parrelllt to each other
Jack paid $64.32 for 8 books. How much
did he pay per book?
Answers
Answer:
$8.04
Step-by-step explanation:
Answer:
$8.04
I hope this helps!!!
Simplified awnser
1/2 a2 - 3 x b + 2c
Answers
The given expression is a simplified algebraic equation: (1/2) * a^2 - 3b + 2c. It represents a combination of variables a, b, and c with their respective coefficients.
What is an Algebraic Equation?Utilizing symbols and operations, an algebraic equation illustrates the equivalence or inequivalence of two expressions. These generated expressions may hold variables that have varying values.
The premise centered around calculus is to arrive at a solution by acquiring the correct value(s) of these variable(s), ultimately fulfilling the outlined specification in the problem. Algebraic equations can range from uncomplicated linear problems to elaborate polynomials and trigonometric functions.
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A sequence starts at 200 and 30 is subtracted each time . 200 , 170, 140 ...
What are the first two numbers in the sequence that are less than zero ?
Answers
Answer:
-10 & -40
Step-by-step explanation:
the last number before you get to 0 when continuing the -30 trend is 20. 20-30= -10. Then to get the next number simply subtract 30 again to get -40. Therefore, your answers are -10 & -40.
Answer:
-10 and - 40
Step-by-step explanation:
If 30 is subtracted.
30×6= 180
200-180=20
20-30= - 10
-10-30= - 40.
.:the first two numbers less than zero are. - 10 AND - 40
According to the figure given here,
(i) what is the sum of BÔC and CÔD ?
(ii) what is the complement of BÔC ?
(iii) what is the magnitude of AÔD ?
(iv) what is the sum of AÔD and DÔE?
(v) what is the supplement of DÔE ?
(vi) what is the complement of DÔE ?
Answers
Answer:
(i) 90°
(ii) CÔD
(iii) AÔD = 110°
(iv) 180°
(v) AÔD
(vi) AÔB
Step-by-step explanation:
Two angles are said to be complementary if they add up to 90°.
Complementary angles can either be adjacent or non-adjacent.
Two Angles are said to be supplementary if they add up to 180°.
Complementary angles can either be adjacent or non-adjacent.
(i) BÔC + CÔD = 25 + 65 = 90°
(ii) BÔC = 25°
Therefore the complementary angle measures 90 - 25 = 65°
So the complement of BÔC is CÔD
(iii) AÔD = 20 + 25 + 65 = 110°
(iv) AÔD + DÔE = 110 + 70 = 180°
(v) DÔE = 70°
Therefore the supplementary angle measures 180 - 70 = 110°
So the supplement of DÔE is AÔD
(vi) DÔE = 70°
Therefore the complementary angle measures 90 - 70 = 20°
So the complement of DÔE is AÔB
#1
<BOC+<COD=25+65=90#2
Let the complement be x
x=90-25=75#3
<AOD=20+25+65=110#4
<AoD+<DOE=110+70=180°#5
x=90-70=20Need Help ASAP!!!
Find the sine of G
Answers
Answer:
≈0.68
Step-by-step explanation:
with what u have u can get \(cos G^{-1}\)
so it will be equal \(\sqrt43\)/9 =43°13'49.75"
now u can get the sine
sin 43°13'49.75" ≈ 0.68
can someone help me, please?
Answers
Answer:
24
Step-by-step explanation:
Those ticks on both lines mean they are equal lengths, meaning both are 24.
Johanna bought 17 items at the college bookstore. The items cost a total of $41.50. The pens cost $0.50 each, the notebooks were $4.00 each, and the highlighters cost $1.50 each. She bought 3 more notebooks than highlighters. How many of each item did she buy?
Answers
The answer to the given word problem is as follows. From the calculations: Johanna purchased
4 pens, 8 notebooks, and 5 highlighters.What is a word problem?A word problem is a few phrases that describe a real-life scenario in which an issue must be solved using a mathematical computation.
The calculations is given as follows:
Step 1 - First, let's define the variables to represent the unknowns.
Let p = number of pens
Let n = number of notebooks
Let h = number of highlighters
p + n + h = 17 ......................... 1 (purchased 17 items)
.5p + 4n + 1.5h = 41.5 ...................2 (total cost $41.50)
n = h+3 ................................3 (3 more notebooks than highlighters)
Step 2...............Solve for P in equation 1
P = 17 - n - h..................4
Recall that in equation 3,
n = h + 2
If we make n the subject of the expression, we have:
n = h+ 3
Substituting that into equation 4, we have
p = 17 - (h+3) - h
p = 17 -2h - 3 ..................5
Going back to equation 2, let's substitute n with h+3 and replace p with 17 -2h - 3
.5(17 -2h - 3) + 4 (h+3) + 1.5h = 41.5
To remove all decimals, we can multiply all with 10 to get:
5(170-20h -30) + 40(10h +30) + 15h = 415
Expand all brackets and we have:
850 - 100h - 150 + 400h + 1200 + 15h = 415
Collect like terms
-100h + 400h + 15h = 415-850+150-1200
315h = -1485
h = -1485/315
h = -4.71
Since a physical item cannot be negative, we utilize the absolute value which is:
h = 4.71
h \(\approx\) 5 highlighter
Recall that
n = h + 3
Hence
n = 5 +3 = 8 notebooks
Recall that
p + n + h = 17
Hence we have
p + 8 + 5 = 17
p = 17 -8 - 5
p = 17 - 13
P = 4 pens.
Hence Johanna purchased
4 pens, 8 notebooks and 5 highlighters.
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if you travel 100 miles at 60mph how long does your journey take?
Answers
Answer:
The correct answer is 100 minutes or 1 hour and 40 minutes
Step-by-step explanation: