Can you help me with writing a Autobiography​ .Please !!!

Answer:

guy above me is wrigth. If you have any doubts see the picture.

Step-by-step explanation:

Hope it helps and mark as brailiest pleasee

Answer:

3. 140 m³

4. 216 in.³

Step-by-step explanation:

Each solid is a prism. The volume for both follows the same formula:

volume = (area of the base) × height

Now we need to find the area of the base for each solid. The front face is the base of each solid. The height is the distance between the front face and the beck face.

3.

area of the base:

The base is an L shape that is made up of 2 rectangles.

area of front face = LW + lw =

= 6 m × 3 m + 2 m × 1 m

= 18 m² + 2 m²

= 20 m²

volume = area of base × height =

= 20 m² × 7 m

= 140 m³

4.

area of the base:

The base is an L shape that is made up of 2 rectangles.

area of front face = LW + lw =

= 6 in. × 3 in. + 4 in. × 9 in.

= 18 in.² + 36 in.²

= 54 in.²

volume = area of base × height =

= 54 in.² × 4 in.

= 216 in.³

The reason that the symbol '♣' represented in Mikal's proof is Angle - Angle - Side i.e AAS.

If two more triangles have equal sides and the angles are of equal measure, and if they can superimpose on each other then the Two ore triangles are said to be congruent.  

The AAS is one of the 5 congruency theorems. Angle - Angle - Side Criteria is also known as AAS Criteria.

Two triangles are said to be congruent if any two angles and the non-included side of one triangle match the corresponding angles and side of the second triangle.

Here we have

ΔABE and ΔCDE

From ΔABE and ΔCDE  

⇒  AB = CD    [ Sides ]

⇒ ∠ABE = ∠CDE = right angles = 90° [ Angles ]

⇒ ∠AEB = ∠CED = vertical angles theorem [ Angles ]

By the above information, we can conclude that the triangles ABE and CDE will follow the rule of Angle-Angle-Side congruency.

Therefore,

The reason that the symbol '♣' represented in Mikal's proof is Angle - Angle - Side i.e AAS.

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Complete Question:

Mikal is proving that AE ≅ CE . Triangles A B E and C D E are connected at point E. Angles A B E and E D C are right angles. The lengths of A C and D C are congruent. Which reason does the ♣ represent in Mikal’s proof? SAS SSS ASA AAS the

picture cut off the final answer AAS

Answer: AAS

Step-by-step explanation:

Answer:

yes because its not how much you walk if it is the same distance to the park, then yes. You walked the same distance to the park, however the dog ran more around, you were possibly following the dog so... yea.

Answer: It”ll take Emily five weeks to buy the sound system.

Answer:

5 weeks

Explanation:

Emily has already saved $74 and need to make 149 we know she makes $15 a week 15*5=75

75+74=149

so it would take 5 weeks for Emily to get a sound system.

Answer:

it's c

Can i be the brainlest?

(B) Yes, the vertical line traverses multiple points on the graph for every value of x.

Since y = 11 has y as the output variable in addition to the input value of 11, it is a function.

We need an input variable or constant and an output variable or constant in order to have a function.

Given that there is an input value of c and an output value of y, the expression y = c is a function.

For each value of the input variable c, we can state that y equals c.

Since the expression y = 11 has both an input value of 11 and an output variable named y, we can infer that it is a function.

When we graph the expression, y = 11 it passes through the point ( 11, 0 ) and is parallel to the x-axis

For every value of x the vertical line passes through more than one point.

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we have

5/x=15/24

solve for x

Multiply in cross

15*x=24*5

x=24*5/15

x=8

Answer:4673

Step-by-step explanation:

Answer:

This is your answer ☺️☺️☺️

Answer:

Step-by-step explanation:

5x+y-7=0 isolate y

y=-5x+7 (m=-5,b=7)

9x+7y-14=0

7y=14-9x ( divide both sides by 7)

y=-9x/7 +14/7

y=-9/7 + 2  (m=-9/7, b=2)

x+y=1000

4x+3y=3600 ( multiply the first equation by 3 to eliminate y)

3x+3y=3000

4x+3y=3600 ( subtract the two equations)

3x+3y-(4x+3y)=3000-3600

3x+3y-4x-3y=-600

-x=-600

x=600 ( substitute x in the equation)

x+y=1000

600+y=1000

y=1000-600=400

check : x+y=1000 , (600+400)=1000

check : 4x+3y=3600 = (4(600)+3(400))=2400+1200=3600

how many tickets are sold :

adults x=600/4=150

kids (y)=400/3=133 tickets+1 dollars left

unless( x represent kids then x=200, y represent adult = 100)

Answer:

\(\boxed{\mathrm{view \: explanation}}\)

Step-by-step explanation:

Question 1:

\(5x+y-7=0\)

Write in slope intercept form.

\(y=-5x+7 \\m=-5,b=7\\9x+7y-14=0\)

Write in slope intercept form.

\(7y=14-9x\\y=-9x/7 +14/7\\y=-9/7 + 2\\m=-9/7, b=2\)

Question 2:

\(x+y=1000\\4x+3y=3600\)

\(3x+3y=3000\\4x+3y=3600\\3x+3y-(4x+3y) = 3000-3600\\3x+3y-4x-3y=-600\\-x=-600\\x=600\)

\(x+y=1000\\600+y=1000\\y=1000-600=400\)

Tickets sold:

Adults:

\(x=600\)

Kids:

\(y=400\)

Answer:

Any elements that are in either H or W will be in the union of the sets

Step-by-step explanation:

Anytime that is asking for the union of two sets with the symbol (U) than it is asking you to figure out what elements are in either one of the two sets.

That means the Union would be in either set.

Therefore (Any elements that are in either H or W will be in the union of the sets)

(Also took the test)

The expression on the left with the values of the propositional variables that make the expression true. A. P ∧ ~Q - iv. P = false, Q = false, R = true (P is false and Q is false, so P ∧ ~Q is false).

B. ~(P ∧ Q) - i. P = false, Q = true, R = false (P is false and Q is true, so ~(P ∧ Q) is true)
C. P ∨ (Q ∧ ~R) - ii. P = true, Q = false, R = true (P is true, so P ∨ (Q ∧ ~R) is true regardless of the values of Q and R)
D. ~(~P ∨ ~Q) - iii. P = true, Q = true, R = false (P and Q are both true, so ~P ∨ ~Q is false, and therefore ~(~P ∨ ~Q) is true)
A. P ∧ ~Q is true when P = true, Q = false. So, it matches with ii. P = true, Q = false, R = true
B. ~(P ∧ Q) is true when P = false, Q = true. So, it matches with i. P = false, Q = true, R = false
C. P ∨ (Q ∧ ~R) is true when P = true, Q = true, R = false. So, it matches with iii. P = true, Q = true, R = false
D. ~(~P ∨ ~Q) is true when P = true, Q = true. So, it matches with iii. P = true, Q = true, R = false

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Answer:

1/2 1/6 1/6

Step-by-step explanation:

The line that is not another name for Q is RL

For a line to represent the point Q, the following must be true:

Using the above highlights,

Hence, the line that is not another name for Q is RL

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The models that represent a probability of 1/4 of pulling a red marble are given as follows:

A probability is calculated as the division of the desired number of outcomes by the total number of outcomes in the context of a problem/experiment.

After completing 12 trials, she pulled a red marble 3 times, hence the probability of pulling a red marble is given as follows:

3/12 = 1/4.

The other models with a probability of 1/4 are given as follows:

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Answer:

30% chance or \(\frac{3}{10}\)

Step-by-step explanation:

1, 2, 2, 3, 3, 3, 3, 4, 4, 5

The only numbers above 3 is 4, 4, and 5. There are 3 numbers greater than 3 and there are 10 total numbers, so the chance is \(\frac{3}{10}\) theoretical chance of getting a number GREATER than 3 or 30% chance.

Answer:

\(\frac{2(x+3)}{x+7}\)

Step-by-step explanation:

Given

\(\frac{2x^2-18}{x^2+4x-21}\) ← factorise numerator and denominator

2x² - 18 ( factor out 2 from each term )

= 2(x² - 9) ← difference of 2 squares

= 2(x - 3)(x + 3)

and

x² + 4x - 21 = (x + 7)(x - 3) , then

= \(\frac{2(x-3)(x+3)}{(x+7)(x-3)}\) ← cancel common factor (x - 3) on numerator/ denominator

= \(\frac{2(x+3)}{x+7}\)

The most appropriate measure of central tendency for the variable of marital status would be the mode. In this case, the most appropriate measure of central tendency for the variable of marital status would be the mode.

The mode is the value or category that appears most frequently in a dataset. Since marital status is a categorical variable with different categories (married, divorced, separated, widowed, never married, cohabitating), finding the mode would identify the most commonly occurring marital status among the study subjects.

Using the mode as a measure of central tendency in this scenario makes sense because it provides information about the most prevalent category or group within the dataset. This can be valuable when studying demographic data, as it helps to identify the dominant marital status among the subjects.

On the other hand, the median and mean are measures of central tendency typically used for numerical data rather than categorical data. The median represents the middle value in an ordered dataset, while the mean is the arithmetic average. These measures would not be appropriate for a categorical variable like marital status, as it does not involve numerical values that can be added or averaged.

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Answer:

electron = negative charge

proton = positive charge

neutron = neutral charge

nucleus = center of an atom

quark = small particle that make up protons and neutrons

Step-by-step explanation:

The agent must be designed to be able to navigate the hexagonal grid, identify when to push or pull a widget, and rotate in the appropriate direction to complete tasks. HExBOT is a term used to describe hexagonal robots designed to solve certain problems or perform specific tasks.

However, designing a HExBOT agent is not always easy, and there are several challenging aspects that must be considered when designing it. These include the hexagonal grid, the asymmetric cost of actions (pushing is more expensive than pulling a widget), and the rotation of the agent. The hexagonal grid is a challenging aspect of designing a HExBOT agent because it is not the traditional rectangular or square grid used in most robot designs. The hexagonal grid is more complex, and it requires the agent to be able to navigate through it while avoiding obstacles and staying on track.

Additionally, the hexagonal grid requires the agent to be able to rotate around a hexagon, which can be challenging for a robot designed for a rectangular grid.The asymmetric cost of actions is another challenging aspect of designing a HExBOT agent. Pushing a widget requires more energy and effort than pulling a widget, so the agent must be designed to take this into account. Additionally, the agent must be able to identify when it is more efficient to push or pull a widget, and it must be able to do so without wasting energy or time.

The rotation of the agent is also a challenging aspect of designing a HExBOT agent. The agent must be able to rotate around a hexagon, which is not always easy to do. Additionally, the agent must be able to identify when it needs to rotate and in which direction it needs to rotate to complete a task or avoid obstacles.In conclusion, designing a HExBOT agent can be challenging due to the hexagonal grid, the asymmetric cost of actions, and the rotation of the agent.

To overcome these challenges, the agent must be designed to be able to navigate the hexagonal grid, identify when to push or pull a widget, and rotate in the appropriate direction to complete tasks.

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Answer: False

Step-by-step explanation:

Researchers typically report the adjusted R-squared value in addition to the regular R-squared value, not because they lack confidence in the actual R-squared, but because the adjusted R-squared provides additional information about the goodness of fit of a statistical model. The regular R-squared value measures the proportion of the variance in the dependent variable that is explained by the independent variables in the model. However, it can be biased and increase as more predictors are added to the model, even if the additional predictors do not contribute significantly to the prediction.

The adjusted R-squared, on the other hand, takes into account the number of predictors in the model and penalizes the addition of irrelevant predictors. It provides a more conservative measure of the goodness of fit by adjusting for the number of predictors and the sample size. Researchers often use the adjusted R-squared to evaluate and compare different models with varying numbers of predictors or to assess the overall explanatory power of a model while considering its complexity.

In summary, researchers report the adjusted R-squared value to address the limitations of the regular R-squared and to provide a more accurate assessment of the model's goodness of fit.

To find two nonnegative numbers x and y such that xy = 162 and 4x +2y is minimized, we need to use the concept of the Arithmetic-Geometric Mean.The main answer is:x = 9√2y = 9/√2

Explanation: Arithmetic-Geometric Mean: Let a and b be positive numbers.The Arithmetic Mean (AM) is a + b / 2. The Geometric Mean (GM) is √ab.The Arithmetic-Geometric Mean is the following:a_n = (a_n−1 + b_n−1) / 2  b_n = √a_n−1 * b_n−1  a_0 = a  b_0 = b

Let's solve the problem using the Arithmetic-Geometric Mean.√(4xy) = √(4 * 162) = 36xy/36 = 162/36xy = 9√2 * 9/√2xy = 81The numbers that will minimize 4x + 2y are 4x = 36, and 2y = 18. Therefore, x = 9√2, and y = 9/√2

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In a cross-country race with 30 runners, there are 4,060 different groups that can finish in the top 3 positions.

Use the concept of combination defined as:

Combinations are made by choosing elements from a collection of options without regard to their sequence.

Contrary to permutations, which are concerned with putting those things/objects in a certain sequence.

Given that,

There are 30 runners in a cross-country race.

The objective is to determine the number of different groups of runners that can finish in the top 3 positions.

To determine the number of different groups of runners that can finish in the top 3 positions:

Use combinations instead of permutations.

In this case:

Calculate the number of different groups,

Use the combination formula:

\(^nC_r = \frac{n!} { (r!(n - r)!)}\)

Here

we have 30 runners and want to select 3 for the top 3 positions.

Put the values into this formula:

\(^{30}C_3 = \frac{30!}{ (3!(30 - 3)!)}\)

Simplifying this expression, we get:

\(^{30}C_3 = \frac{30!}{ (3! \times 27!)}\)

Calculate the value:

\(^{30}C_3 = 4060\)

Hence,

There are 4,060 different groups of runners that can finish in the top 3 positions.

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The location of the coin next to the convex side of a thin spherical glass shell is 3.68 cm.

According to the question,

Radius of curvature : 19 cm

Size of image formed : 1.5cm

Distance of coin from glass shell : 6.5cm

The position of the coin placed next to the convex side of a thin spherical glass shell is calculated as follows;

1/d = 1/f - 1/d'

where;

d' is the position of the coin's image

d position of the coin

f is focal length

Focal length = r/2 =19/ 2 = 9.5 cm

=> 1/d = 1/9.5 - (-1/6.5)

=> 1/d = 1/9.5 + 1/6.5

=> 1/d = 0.1052 + 0.1538

=> 1/d = 0.259

=>d = 1/0.259

d = 3.86 cm

Thus, the position of the coin placed next to the convex side of a thin spherical glass shell is 3.86 cm.

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Answer:

-22

Step-by-step explanation:

First, you must find the values for f(-8) and g(2).  f(x) is the blue line so f(-8)=-2 because that is the value of y where x=-8.  g(x) is the pink dotted line so g(2)=-4 because that is the value of y where x=2.  Then, plug in and solve:

-3(-2)+7(-4)

6+-28

6-28

-22

Hope this helps!!

The equation for traveling x miles in the cab can be written as:

Cost = $0.60 + $0.14 * x. The cab charges $0.88 for a ride of 2 miles. And the cab charges $1.72 for a trip of 8 miles.

a. The equation for traveling x miles in the cab can be written as:

Cost = $0.60 + $0.14 * x

b. To find the number of miles for a cab ride that costs $0.88, we can set up the equation:

$0.88 = $0.60 + $0.14 * x

Subtracting $0.60 from both sides, we get:

$0.88 - $0.60 = $0.14 * x

$0.28 = $0.14 * x

Dividing both sides by $0.14, we find:

x = $0.28 / $0.14

x = 2 miles

Therefore, the cab charges $0.88 for a ride of 2 miles.

c. To calculate the cost of a trip of 8 miles, we can substitute x = 8 into the equation:

Cost = $0.60 + $0.14 * 8

Cost = $0.60 + $1.12

Cost = $1.72

Therefore, the cab charges $1.72 for a trip of 8 miles.

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1) The demand for good 1 is 10/(5√2) and the demand for good 2 is 50√2/2.

2) The demand for good 1 is e5 and the demand for good 2 is e2.

3) The tax revenue the government collects from the consumer is 0.16e5.

4) The demand for good 1 is m/p₁ and the demand for good 2 is m/p₂.

Question 1: If the consumer has the utility function u(x₁, x₂) = √(x₁x₂) and has an income of m = 10, the demand for the two goods can be found using the following equation:

MRSxy = Px/Py

Where MRSxy is the Marginal Rate of Substitution between goods x and y, Px and Py are the prices of goods x and y respectively.

Therefore, for this problem we have MRST1,2 = 1/5 and P₁ = 1, P₂ = 5. Solving for the demands x₁ and x₂, we get:

x₁ = 10/(5√2), x₂ = 50√2/2

Therefore, the demand for good 1 is 10/(5√2) and the demand for good 2 is 50√2/2.

Question 2: If the consumer has the utility function u(x₁, x₂) = 1/2 ln x₁ + 1/2 ln x₂ and has an income of m = 10, the demand for the two goods can be found using the same equation as in Question 1. In this case the MRST1,2, P₁, and P₂ are the same as in Question 1. Thus, solving for the demands x₁ and x₂, we get:

x₁ = e5, x₂ = e2

Therefore, the demand for good 1 is e5 and the demand for good 2 is e2. This is different than the demands found in Question 1, because the utility functions are different. The Square Root utility function in Question 1 implies that the consumer has diminishing marginal utility, whereas the Log utility function in Question 2 implies that the consumer has constant marginal utility.

Question 3: To find the tax revenue the government collects, we need to find the consumer's demand for good 1 before and after the imposition of the quantity tax. First, we find the demand for good 1 before the imposition of the tax, using the same equation as in Question 2. Thus, in this case the demand for good 1 is e5. Therefore, the quantity consumed before the tax is e5.

Now, let’s find the consumer’s demand for good 1 after the imposition of the tax, which is equal to the consumer’s demand before the tax multiplied by (1 - t), with t = 0.2. Therefore, the demand for good 1 after the tax is 0.8e5.

Since the quantity tax of 0.2 is imposed on the consumer’s demand for good 1, the tax revenue is equal to 0.2 * 0.8e5 = 0.16e5.

Thus, the tax revenue the government collects from the consumer is 0.16e5.

Question 4: If the consumer has a preference over good 1 and good 2 represented by the utility function u(x₁, x₂) = x₁ + x₂, given the prices of good 1 and 2 are p₁ and p₂ respectively, and the consumer has a income of m, the demand for the two goods can be found using the following equation:

MRSxy = p₁/p₂

Therefore, for this problem we have MRS1,2 = p₁/p₂. Solving for the demands x₁ and x₂, we get:

x₁ = m/p₁, x₂ = m/p₂

Therefore, the demand for good 1 is m/p₁ and the demand for good 2 is m/p₂.

Therefore,

1) The demand for good 1 is 10/(5√2) and the demand for good 2 is 50√2/2.

2) The demand for good 1 is e5 and the demand for good 2 is e2.

3) The tax revenue the government collects from the consumer is 0.16e5.

4) The demand for good 1 is m/p₁ and the demand for good 2 is m/p₂.

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Answer:

Step-by-step explanation:

\(Percentage of chocolate candy = \dfrac{12}{25}*100\\\\ = 12*4\\\\\)

= 48%