5. A 200 m long aluminum wire has the same resistance and cross-sectional area as a carbon wire. What is
the length of the carbon wire?
Answer:
=0.15m
Explanation:
l
C
=l
Al
ρ
C
ρ
Al
=200∗
3.5∗10
−5
2.65∗10
−8
what is the magnitude of the potential difference needed to give an alpha particle (composed of 2 protons and 2 neutrons) 324.0 kev of kinetic energy? (in kv)
The magnitude of the potential difference needed to give an alpha particle 324.0 keV of kinetic energy is 2.50 x 10^6 kV.
The magnitude of the potential difference needed to give an alpha particle 324.0 keV of kinetic energy is calculated using the formula KE=1/2mv^2. Here, m is the mass of the alpha particle (6.644 x 10^-27 kg) and v is its velocity.
Thus, we have 324.0 keV = (1/2) (6.644 x 10^-27 kg)[v^2].
Solving for v, we get v = 1.38 x 10^7 m/s.
The potential difference, V, can then be calculated using the formula
V = (mv^2)/(2e)
where e is the charge of the alpha particle (charge of two protons, or 4.803 x 10^-10 C).
Thus, V = (6.644 x 10^-27 kg)(1.38 x 10^7 m/s)^2/(2(4.803 x 10^-10 C)) = 2.50 x 10^6 kV.
Therefore, the magnitude of the potential difference needed to give an alpha particle 324.0 keV of kinetic energy is 2.50 x 10^6 kV.
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Not having to worry about your health, job, or being attacked are related to this level
of needs.
Answer:
This level of needs is known as safety needs. Safety needs are the need for security, stability, and protection from physical and emotional harm. These needs include physical safety, financial security, health and well-being, and protection from discrimination and harassment.
Explanation:
Please help me with this question
Answer:
5m
Explanation:
the amplitude of a wave is basically if you cut the wave in half horizontally and went from the half point to either the lowest or highest point of the wave. and the midpoint of wave A is 0 and u can either go up 5 to get to the highest point, or down 5 to get to the lowest point (;
When is the average velocity of an object equal to the instantaneous velocity? a. This is always true. b. This is never true. c. This is the case only when the velocity is constant. d. This is the case only when the acceleration is constant. e. This is the case only when the velocity is decreasing at a constant rate.
When is the average velocity of an object equal to the instantaneous velocity is C. This is the case only when the velocity is constant.
The instantaneous velocity of an object is equal to the average velocity of an object when the velocity is constant or when the acceleration is zero, this is the case only when the velocity is constant. When an object has a constant velocity, the instantaneous velocity of the object is equivalent to the average velocity of the object. This is true because the velocity of the object remains constant over time.
For example, if an object travels at a speed of 20 meters per second for a time period of 5 seconds, then the instantaneous velocity at the end of the 5 seconds is 20 meters per second, and the average velocity of the object over the 5 seconds is also 20 meters per second. This is because the velocity remained constant throughout the entire time period. Therefore, option c is correct, this is the case only when the velocity is constant.
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how much energy, in megaelectronvolts, is produced when 0.250 universal mass unit of matter is completely converted into energy?
The energy released when a mass m is completely converted into energy is given by the famous equation of Albert Einstein, E = mc^2, where c is the speed of light in vacuum.
To convert the mass of 0.250 universal mass units (u) into kilograms, we can use the conversion factor:
The when 0.250 universal mass unit of matter is completely converted into energy, it produces about 372.8 MeV of energy.
1 u = 1.66054 × 10^-27 kg
Therefore, the mass in kilograms is:
m = 0.250 u * 1.66054 × 10^-27 kg/u = 4.15135 × 10^-28 kg
Using the equation E = mc^2 and converting the result into megaelectronvolts (MeV), we get:
E = mc^2 / (1.60218 × 10^-13) MeV
E = (4.15135 × 10^-28 kg) * (299792458 m/s)^2 / (1.60218 × 10^-13 MeV/J)
E ≈ 372.8 MeV
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The higher the density, the
_____ compact the particles are within the object.
Answer:
more
Explanation:
the higher the density the more closely/tighter the particles in the object will be
How do you calculate velocity?
a) Distance divided by time.
b) Displacement dided by time.
c) Speed multiplied by
time.
d) Displacement divided by velocity.
Answer:
A
Explanation:
Answer:
Distance divided by time
Explanation:
water is know to boil at 100°C.A student boiled water and realised it's boiling point was 101°C.State two possible reasons
-- impurities in the water
-- air pressure is higher than standard
n a certain series rlc circuit, irms = 9.00 a, δvrms = 190 v, and the current leads the voltage by 38.0°. (a) what is the total resistance (in ω) of the circuit?
The total resistance of the circuit is approximately 21.11 Ω. To determine the total resistance (R) of the series RLC circuit, we can use the relationship between the current (I), voltage (V), and resistance.
To determine the total resistance (R) of the series RLC circuit, we can use the relationship between the current (I), voltage (V), and resistance:
V = I * R
Given:
Irms = 9.00 A (root mean square value of current)
δvrms = 190 V (root mean square value of voltage)
The current leads the voltage by 38.0°
First, we need to find the peak values of current (I_peak) and voltage (V_peak). Since the root mean square (rms) values are given, we can use the following relationship:
I_peak = Irms
V_peak = δvrms
Now, we can calculate the total resistance (R) using the peak values:
R = V_peak / I_peak
R = 190 V / 9.00 A
R ≈ 21.11 Ω
Therefore, the total resistance of the circuit is approximately 21.11 Ω.
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a potato cannon works by stuffing a potato into a long narrow tube, and igniting a flammable substance behind it. the potato is shot out of the cannon, and significant heat is released. if the fuel does 855j of work on the potato, and produces 1422j of heat, what is the change in internal energy of the fuel?
If the fuel does 855 J of work on the potato, and produces 1422 J of heat, the change in internal energy of the fuel is 567 J.
According to the first law of thermodynamics, the change in internal energy of a system is equal to the heat added to the system minus the work done by the system:
ΔU = Q - W
where ΔU is the change in internal energy, Q is the heat added to the system, and W is the work done by the system.
In this case, the fuel does 855 J of work on the potato and produces 1422 J of heat. Since the potato cannon and the fuel can be considered as a closed system, the change in internal energy of the system can be calculated as:
ΔU = Q - W
ΔU = 1422 J - 855 J
ΔU = 567 J
Therefore, the change in internal energy = 567 J.
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A 2 kg box slides down a frictionless ramp starting
from a height of 3 m. The slope of the ramp is 30°,
What is the box's momentum when it reaches the
bottom of the ramp?
Answers:
A) 15.3 kg•m/s down the ramp
B) 7.7 kg.m/s down the ramp
C) 5.5 kg•m/s down the ramp
D) 2.8 kg•m/s down the ramp
The box's momentum when it reaches the bottom of the ramp is 2.8 kg•m/s down the ramp.
What is the velocity of the box when it reaches the bottom?When the box reaches the bottom of the slope, its speed is v = (nh) n has a value. The block has gravitational potential energy when it briefly comes to rest at the top of the ramp and starts with kinetic energy at the bottom. However, some of that energy is lost due to frictional effort. You can use a free body diagram and Newton's second law to calculate the frictional force on the block. What will happen if you roll two cylinders of the same mass and diameter—one solid and one hollow—down a ramp is how this traditional physics textbook version of the problem is phrased. The solid one will eventually sink, is the solution.To learn more about velocity of the box refer to:
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Question 10 of 10
Two particles are separated by 0.38 m and have charges of 1.25 x 10-9C and
1.92 * 10-°C. Use Coulomb's law to predict the force between the particles if
the distance is doubled. The equation for Coulomb's law is F = kouse, and
the constant, k equals 9.00 x 109 Nm²/C2
A. -1,50x10-7N
B. -3.74 x 10-8N
C. 1,50 x 10-7N
D. 3.74 x 10-8N
SUBMIT
Answer:
Its d 3.74 x 10-8N
Explanation:
Answer: 3.74 x 10-8 N
Explanation:
PLEASE HELP RN
A cannon is fired horizontally at 251 m/s off of a 91 meter tall, sheer vertical cliff. How many
seconds
will have elapsed before the cannonball strikes the ground?
When the cannonball finally touches the ground, it will have been 1.94 seconds.
How much time will the cannonball take to land?We may disregard the answer t = -0.249 seconds since what we're interested in is what happens after the cannon is fired (i.e., when time t > 0). As a result, the cannonball reaches height h = 0 m and hits the earth at time t = 6.474 seconds.
Calculation:From the aforementioned query, the following information was discovered:Initial speed (u) equals 251 m/s.
Cliff height (h) equals 91 meters.
(s) is the horizontal distance.
The time it takes the gun to reach the earth will then be determined. This is attainable as follows:Cliff height (h) equals 91 meters.
Gravitational acceleration (g) equals 9.8 m/s2.
Time (t) =?
h = ½gt²
91 = ½ × 9.8 × t²
91 = 4.9 × t²
Divide both side by 4.9
t² = 91/4.9
Do both sides' square roots.
t = √(91/4.9)
t = 1.94 s
Finally, as indicated below, we will calculate the cannon ball's horizontal travel distance:Initial velocity (u) = 251 m/s
Time (t) = 1.94 s
Horizontal distance (s) =?
s = ut
s = 251 × 1.94 s
s = 486.94m.
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a pole-vaulter runs down a track, plants one end of the pole into the ground, and then jumps in the air while bending the pole. As the pole unbends, it creates force that launches the pole-vaulter up and over the bar using your knowledge of potential and kinetic energy, describe how the pole is like a spring.
When the pole is lifted, it could be able to supply energy to the pole - vaulter much like that of a spring that launches the pole vaulter upwards.
How does the pole vault work?We know that the pole vault is one of the popular sports especially in the Unites States. It is a competition that takes place even at the Olympic level and has a lot of athletes that do compete in the competition.
We know that as the pole unbends, it creates force that launches the pole-vaulter up and over the bar using your knowledge of potential and kinetic energy.
This implies that there are a series of energy conversions that do take place in the pole vault as it is in operation as we can see here. Thus, it is the series of the energy conversions that takes place in the pole vaulting that enables the athlete to be able to launch high in the game as we see.
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when is the acceleration of body is positive negative and zero?
Answer:
【 In vector form , if angle between velocity vector and acceleration vector is less than 90° and greater than 0° then it is positive acceleration and if it is less than 180° and greater than 90° then it is negative acceleration. If there is no acceleration vector then it is called zero acceleration. 】
a laser beam with wavelength λ = 550 nm hits a grating with n = 2750 grooves per centimeter.
Part (a) Express the grating spacing, d, in terms of n.
Part (b) Calculate the numerical value of d, in centimeters.
Part (c) Find the sin of the angle, θ2, at which the 2nd order maximum will be observed, in terms of d and λ.
Part (d) Calculate the numerical value of θ2 in degrees.
Grating spacing, d, is expressed as d = 1/n, where n is the number of grooves per centimeter. The numerical value of d is 1/2750 cm per groove.
In part (a), the relationship between the grating spacing, d, and the number of grooves per centimeter, n, is established as d = 1/n. This equation allows us to express the grating spacing in terms of the groove density.
In part (b), we convert the given value of n from grooves per centimeter to centimeters per groove. By reciprocating the value, we find that each groove occupies 1/2750 cm of space. Thus, the numerical value of d is determined as 1/2750 cm per groove.
The calculation helps us understand the physical spacing between adjacent grooves on the grating, providing a basis for further analysis in subsequent parts of the question.
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A car can accelerate from rest to a speed of 28 m/s in 20 s. What is the average acceleration of the car
Formula for acceleration:
\(a=\dfrac{V^f-V^I}{t}\)
acceleration(measured in m/s^2) = Final velocity(measured in m/s) - Initial velocity(measured in m/s) / time(measured in seconds)
__________________________________________________________
Given:
\(V^I=0m/s\) (rest)
\(V^f=28m/s\)
\(t=20s\)
\(a=?\)
__________________________________________________________
Finding acceleration:
\(a=\dfrac{V^f-V^I}{t}\)
\(a=\dfrac{28-0}{20}\)
__________________________________________________________
Answer:
\(\boxed{a=1.4m/s^2}\)
Calculate the force of gravity on a 55 kg person on the surface of the earth.
Answer:
539 N
Explanation:
The force of gravity (also known as weight) on an object can be calculated using the formula:
F = m * g
where F is the force of gravity, m is the mass of the object, and g is the acceleration due to gravity.
For a 55 kg person on the surface of the earth, the acceleration due to gravity is approximately 9.8 m/s^2. Therefore, the force of gravity can be calculated as:
F = 55 kg * 9.8 m/s^2 = 539 N
So, the force of gravity on a 55 kg person on the surface of the earth is approximately 539 N.
How can surface tension be demonstrated at home or in the laboratory?
Using everyday objects like a paperclip or a cent, monitoring the development of droplets, or using a soap bubble, one can illustrate surface tension at home or in the lab.
How can surface tension be determined in a laboratory?With a force tensiometer and a Du Noüy ring or Wilhelmy plate, surface tension can be detected. Or you might use an optical tensiometer and the pendant drop technique.
How is surface tension measured using what equipment?A stalagmometer is a device used to calculate surface tension using the stalagmometric method. . A stactometer or stalogometer is another name for it. A hygrometer is a type of weather instrument used to gauge the humidity level in the air.
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Need a lot of help very and fustian to me
Using the free body diagram, let's determine the scenario the diagram illustrates.
From the free body diagram, we can see that the weight is acting on the object while the tension will be the force which supports the object.
The tension in this case, helps hang the object while the weight is the product of the mass of the object and the force of gravity acting on the object.
Tension can be defined as the pulling force transmitted through a rope or string.
Therefore, the best scenario which is represented by the free body diagram is a sign board supported by two strings.
ANSWER:
A signboard supported by
A helium balloon is filled to a volume of 27.7 l at 300 k. what will the volume of the balloon become if the balloon is heated to raise the temperature to 392 k?
We used Charles's Law to solve this problem and found that the volume of the balloon would increase to 36.14 L when heated to 392 K.
The volume of a gas can change when the temperature changes, assuming the pressure remains constant. This relationship is described by Charles's Law, which states that the volume of a gas is directly proportional to its temperature in Kelvin.
To solve this problem, we can use the formula V1/T1 = V2/T2, where V1 is the initial volume, T1 is the initial temperature, V2 is the final volume (what we are trying to find), and T2 is the final temperature.
We have,
V1 = 27.7 L
T1 = 300 K
T2 = 392 K
Using the formula, we can solve for V2:
V2 = V1 * (T2 / T1)
V2 = 27.7 L * (392 K / 300 K)
V2 = 27.7 L * 1.307
V2 = 36.14 L
Therefore, when the helium balloon is heated to a temperature of 392 K, the volume of the balloon will increase to approximately 36.14 L.
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Help! Which description includes a vector quantity?
a
The elevator moved upwards at 2.5m/s.
b
The box had a volume of 0.3m3.
c
The car moved at a speed of 24 m/s.
d
The desk had a mass of 47 kg.
Answer:
a
Explanation:
vector is size and direction
hope this works :)
what type of noise pollution escalated rapidly in the late 1990s
The type of noise pollution that escalated rapidly in the late 1990s was electronic noise pollution.
The late 1990s saw an alarming increase in electronic noise pollution, which is any unwanted or undesired sound caused by electronic devices and appliances. This type of noise pollution can range from the humming of air conditioning units to the buzzing of computer servers, and is one of the leading causes of environmental degradation.
As such, it is important for individuals, businesses, and government organizations to take proactive steps to reduce this type of noise pollution. By investing in sound-proofing measures and noise-canceling technology, we can ensure that our environment remains free of unwanted electronic noise pollution.
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Calculate the repulsion force between the two Arkon nuclei when the distance between them is 1x10-3μm (note that the Arkon nucleus contains 18 protons) (The electric charge of one electron is 1.6x10-19C) a. 7.4x10-8N
b. 2.7X10-30N c. 7.4X10-20N d. 7.4x10-14N
The repulsion force between the two Arkon nuclei when the distance between them is 1x10⁻³μm is approximately 7.4x10⁻¹⁴N. The correct option is d. 7.4x10⁻¹⁴N.
The formula for repulsion force between two Arkon nuclei when the distance between them is given by Coulomb's law. Coulomb's law states that the force between two point charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them. Mathematically, the law can be expressed as F=kq1q2/r²,
Where F is the force, q1 and q2 are the charges, r is the distance between the charges, and k is the Coulomb's constant.The electric charge of one electron is 1.6x10⁻¹⁹C.
Therefore, the charge of the Arkon nucleus with 18 protons = 18(1.6x10⁻¹⁹) C = 2.88x10⁻₈⁸ CThe force between the two Arkon nuclei can be calculated using the formula above.
F=kq1q2/r²
Substituting the values we have;F = (9x10⁹)(2.88x10⁻¹⁸ C)2/(1x10⁻³ m)2F ≈ 7.4x10⁻¹⁴ N. Therefore, the repulsion force between the two Arkon nuclei when the distance between them is 1x10-3μm is approximately 7.4x10⁻¹⁴N. The correct option is d. 7.4x10⁻¹⁴N.
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What type of energy is thermal energy? A. Sound energy B. Chemical energy C. Kinetic energy D. Nuclear energy
Answer:
kinetic energy
Explanation:
How could you increase the gravitational potential energy of an object without changing its mass and gravity?
A. Make the object larger
B. Raise the object farther off the ground
C. Lower the object towards the ground
D. Allow the object to roll on the ground
Answer:
B Raise the object farther off the ground
a)What is the current I 1 through the resistor R 2?
b) What is the the potential difference across each of the two resistors R2,R3?
In this given circuit, there are two resistors, R2 and R3 connected in series with a battery of 12 V as shown below;\(\Delta V = V = 12 V\)Let us first find the total resistance of the circuit.
Using the formula, resistances in series add up to give the total resistance of the circuit\(R_T = R_2 + R_3 = 8\ \Omega + 12\ \Omega = 20\ \Omega\)
Using Ohm's Law; the current through the circuit can be calculated as follows;
\(I_T = \frac{V}{R_T} = \frac{12\ V}{20\ \Omega} = 0.6\ A\)
Thus, the current through each of the resistors, R2 and R3 is the same and it is equal to the total current of the circuit;\(I_1 = I_2 = 0.6\ A\)
The potential difference across each of the two resistors, R2 and R3 is different because of the difference in resistance. Using Ohm's Law, the potential difference across each resistor can be calculated as follows;
\(\Delta V_2 = V_{R_2} = I_2 \cdot R_2 = 0.6\ A \cdot 8\ \Omega = 4.8\ V\)
\(\Delta V_3 = V_{R_3} = I_2 \cdot R_3 = 0.6\ A \cdot 12\ \Omega = 7.2\ V\)
Thus, the potential difference across resistor R2 is 4.8 V and across resistor R3 is 7.2 V.
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A man is pulling a cart having a mass of 2kg and an acceleration of 3 ms-2. Find the distance travelled by the cart if the work done is 20j
The cart travels approximately 3.33 meters when a man is pulling a cart having a mass of 2kg and an acceleration of 3 m/s².
To find the distance traveled by the cart, we'll use the work-energy theorem, which states that the work done on an object is equal to the change in its kinetic energy. The formula for work is:
Work = Force x Distance x cos(θ)
Since the man is pulling the cart, the angle (θ) between the force and the distance is 0 degrees, and cos(0) = 1.
So the formula simplifies to:
Work = Force x Distance
The force acting on the cart can be found using Newton's second law of motion:
Force = Mass x Acceleration
Given that the mass of the cart is 2 kg and its acceleration is 3 m/s², we can calculate the force:
Force = (2 kg) x (3 m/s²) = 6 N
Now we can find the distance traveled using the work done (20 J) and the force (6 N):
20 J = (6 N) x Distance
To solve for distance, divide both sides by 6 N:
Distance = 20 J / 6 N = 10/3 meters ≈ 3.33 meters
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Why did it take astronomers until 1838 to measure the parallax of the stars?.
Answer:What they did not count on is the immense distance to the stars, which made the shift so small it was not able to be detected until the 1830s. The first scientist to do so was Friedrich Bessel in 1838. The method that is used to measure distances to nearby stars is called trigonometric parallax, or sometimes, triangulation.
Explanation: