Can someone plz help me it’s my last question plz (question 2)

Answer:

is it just the slope of those points? if so -3/4

Step-by-step explanation:

i think. if not correct me

Answer:

\(-\frac{3}{4}\)

Step-by-step explanation:

The slope of a line is given by:

\(m=\frac{\Delta y}{\Delta x}=\frac{y_2-y_1}{x_2-x_1}\)

Therefore, the slope of the line that passes through these points is:

\(m=\frac{-10-(-4)}{-12-(-20)}=\frac{-6}{8}=\fbox{$-\frac{3}{4}$}\).

Answer:

The answer is I don't know

The value of the equation x² - x + 3 is 37/9.

We have,

We can start by multiplying both sides of the equation by x:

2x - 3/x = x + 1

2x - 3 = x^2 + x

Rearranging and simplifying, we get:

x^2 - x + 3 = (2x - 3) + x^2

x^2 - x + 3 = x^2 + 2x - 3

-x + 3 = 2x - 3

5 = 3x

x = 5/3

Now we can substitute x into the equation x^2 - x + 3:

x^2 - x + 3 = (5/3)^2 - 5/3 + 3

x^2 - x + 3 = 25/9 - 15/9 + 27/9

x^2 - x + 3 = 37/9

Therefore,

The value of x² - x + 3 is 37/9.

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Answer:  The answer that I got was J.

The value of ∫ f(x) dx over the interval [3, 5] is 7. none of the option is correct.

To find the value of ∫ f(x) dx, we need to evaluate the integral of the function f(x) over a given interval. In this case, the function f(x) is defined piecewise:

f(x) = 2 for x < 3

f(x) = x - 1 for x ≥ 3

Let's find the integral of f(x) over a specific interval. We'll consider the interval [3, 5] for this example.

∫ f(x) dx = ∫ [2 for x < 3] + ∫ [x - 1 for x ≥ 3]

Since the lower limit of integration is 3, we'll consider the second part of the piecewise function for the interval [3, 5]:

∫ [x - 1 for x ≥ 3] = ∫ (x - 1) dx from 3 to 5

Now, let's evaluate this integral:

∫ (x - 1) dx = (\(1/2)x^2 - x\) evaluated from 3 to 5

= [\((1/2)(5)^2 - 5] - [(1/2)(3)^2 - 3\)]

= (1/2)(25 - 5) - (1/2)(9 - 3)

= (1/2)(20) - (1/2)(6)

= 10 - 3

= 7

Therefore, the value of ∫ f(x) dx over the interval [3, 5] is 7.

Since the given options for the answer are not specific to any interval, we cannot determine the exact value of the integral without knowing the interval. If there is a specific interval provided, we can evaluate the integral accordingly.

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Answer:

See below.

Step-by-step explanation:

Alexi originally has $43 in his bank account and deposits $7 per week.

Week 1: $50

Week 2: $57

Week 3: $64

Week 4: $71

Week 5: $78

The pattern is that it increased $7 every week starting from $43.

A pattern rule would be: y = 7x + 43 where x represents the number of weeks.

Answer:

Step-by-step explanation:

\(\dfrac{1}{a^{m}}=a^{-1}\\\\\\\dfrac{1}{5^{4}}=5^{-4}\)

Answer: If you look at the x axis 1 is less than $1 so if you follow the x axis to the right until you find a number of minutes that meets the y axis of $1 so x4, y1 that means  $.25 per minute if you divide 1 by 4. So 1 is the correct answer.

Step-by-step explanation:

1. Follow the x axis until the x and y axis meet. This is $1.00 on the y axis.

2. Then you would divide 1 by 4 and you get .25. Each minute would be $.25.

The measure of <YXP and <YZQ are 35 and 65 degrees respectively

Equilateral triangles are triangles that has equal sides and angles.

From the given diagram;

<YZQ + 90 + 25 = 180

<YZQ =180 -115

<YZQ = 65degrees

Determine the measure of <YXP

<YXP = 60 - 25 (XYZ is a 60degrees triangle)

<YXP = 35 degrees

Hence the measure of <YXP and <YZQ are 35 and 65 degrees respectively

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The sequence diverges because the value of the absolute common ratio r is greater than the 1.

A series is convergent if the series of its partial sums approaches a limit; that really is, when the values are added one after the other in the order defined by the numbers, the partial sums getting closer and closer to a certain number.

We have series:

9, 27, 81, 243....

The above series is a geometric progression with common ratio r is 3

\(\rm r =\dfrac{27}{9}\)

r = 3

We know the formula for a geometric sequence:

\(\rm S_n = 9(3)^n\)

\(\rm S_n = 3^{n+2}\)

A geometric series converges only if the absolute value of the common ratio:

r < 1  and

It diverges if the ratio ≥ 1

Here the value of r = 3 which is greater than the 1 so the sequence diverges.

Thus, the sequence diverges because the value of the absolute common ratio r is greater than the 1.

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Answer:

Fourteen thousand five hundred eight

Step-by-step explanation:

For the linear equations provided by the coordinates in the table;

The first equation of this system is y = -2x.

The second equation of this system is y = x - 3.

The solution to the system is (1, -2).

We have four points (-5,10), (-1,2), (0,0), and (11,-22) for first equation, and four points (-8,-11), (-2,-5), (1,-2), and (7,4) the second equation.

The slope (m) is given by the formula (y2 - y1) / (x2 - x1).

For the first line, we can use the points (-5,10) and (-1,2)

m1 = (2 - 10) / (-1 - (-5)) = -8/4 = -2.

the first equation is y = -2x

the second line, we can use the points (-8,-11) and (-2,-5)

m2 = (-5 - -11) / (-2 - -8) = 6/6 = 1.

the second line has a slope of 1,

the equation should have the form y = x + c.

To find c, we can use one of the points, for instance (-2,-5):

-5 = -2 + c => c = -5 + 2 = -3.

So, the second equation is y = x - 3.

the solution to the system, we need to find where the two lines intersect.

y = -2x

y = x - 3

Setting both equation equally

-2x = x - 3

=> 3x = 3

=> x = 1.

Substituting x = 1 into the first equation

y = -2(1) = -2.

the solution to the system of linear equation would be (1, -2).

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Option C best describes the limiting values of T and a under the conditions given. In this case, T represents tension and a represents acceleration.

Without the specific conditions mentioned, it is impossible to determine the exact limiting values of T and a. However, certain options can be ruled out based on common sense and physical laws. For example, option C (T=mg and a=0) is not possible as the tension in a string cannot be equal to the weight of an object. Option E (T=0 and a=[infinity]) is also not possible as a mass cannot have zero tension and infinite acceleration.

Based on these eliminations, the most reasonable options are A (T=0 and a=0) and D (T=[infinity] and a=g). In the former case, the object is not moving and there is no tension in the string. In the latter case, the object is in free fall and the tension in the string is negligible compared to the weight of the object.

However, it is important to note that the exact limiting values of T and a will depend on the specific conditions of the scenario, such as the mass of the object and the angle of the string.

Option C best describes the limiting values of T and a under the conditions given. In this case, T represents tension and a represents acceleration. When T=mg and a=0, it means that the tension in the system is equal to the gravitational force acting on the mass (mg) and the system is in equilibrium with no acceleration. This is a common scenario when an object is hanging from a rope or cable and not moving. The other options do not represent stable or realistic conditions for a physical system.

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Answer:

  3.  · (times)

Step-by-step explanation:

You want to know the operation that will give a binomial result from the expressions (3y^6 +4) and (9y^12 -12y^6 +16).

The like terms in the two expressions are 3y^6 and -12y^6, or +4 and +16. Combining these terms by addition or subtraction will not result in the elimination of either the y^6 term or the constant term. Hence addition or subtraction cannot result in a binomial.

We know that the sum of cubes is factored into the product of a binomial and a trinomial:

  a³ +b³ = (a +b)(a² -ab +b²)

Comparing this form to the given binomial and trinomial, we see that we can choose ...

  a = 3y^6

  b = 4

to make the given factors match exactly. That tells us their product will be a binomial sum:

  (3y^6 +4) × (9y^12 -12y^6 +16) = (3y^6)^3 +(4)^3 = 27y^18 +64

The operation "times" (·) will result in a binomial.

Using the area formula of the triangle, we know that the area of the hexagonal shape tile is 21 cm² respectively.

A hexagon is a six-sided polygon in geometry.

Any simple hexagon has 720° of internal angles in total.

In geometry, a hexagon is a six-sided polygon.

Each internal angle and the side length of a regular hexagon are both 120 degrees.

Hexagon is one of many nouns in science and mathematics that has Greek roots.

The concept of a six-sided shape is derived from the Greek word hexágnon, where the word gonia mean "angle."

This makes sense because a hexagon includes not only six sides, but also six angles, or vertices.

So, we know we have equilateral triangles:

Area = 1/2 * base * height

Insert values as follows:

Area = 1/2 * base * height

Area = 1/2 * 7 * 7

Area = 1/2 * 49

Area = 24.5 cm²

Then, the area of the hexagonal tile:

24.5 * 6 = 147 cm²

Then, 147/7 = 21 cm²

Therefore, using the area formula of the triangle, we know that the area of the hexagonal shape tile is 21 cm² respectively.

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A $1,000 initial investment in Bank ABC's CD would be worth $1,628.89 at maturity.  A $1,000 initial investment in Bank XYZ's CD would be worth $1,622.82 at maturity.

The formula to calculate the value of a CD after a specific duration at a specific interest rate compounded annually is given by:

A = P(1 + r/n)^(nt)

where P is the principal,

r is the annual interest rate,

n is the number of times compounded per year,

t is the number of years, and

A is the value of the CD at maturity.

Here, we need to calculate the value of a $1,000 initial investment in each bank's CD at maturity.

Let's calculate the value of a $1,000 investment in Bank ABC's CD.

P = $1,000

r = 5.0% compounded annually

t = 10 years

n = 1

We have all the values; let's put them in the formula and solve:

A = $1,000(1 + 0.05/1)^(1x10)A = $1,628.89

Therefore, a $1,000 initial investment in Bank ABC's CD would be worth $1,628.89 at maturity.

Let's calculate the value of a $1,000 investment in Bank XYZ's CD.

P = $1,000

r = 4.95% compounded daily

t = 10 years

n = 365

We have all the values; let's put them in the formula and solve:

A = $1,000(1 + 0.0495/365)^(365x10)A = $1,622.82

Therefore, a $1,000 initial investment in Bank XYZ's CD would be worth $1,622.82 at maturity.

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Answer:

Reflecting a function over any axis can be complicated if you do not know the proper way to do it, so I am going to use examples to show you.

If f(x)=x is your normal function, then flipping it across the y-axis would look like f(x)=-x.

Step-by-step explanation:

Placing a - sign before the X will make it flip across the y-axis. After the X, and it flips across the X-axis.

Answer:

X=67.5

Step-by-step explanation:

3X + X=4X

4X+90=360

4X=360-90

4X=270

X=67.5

Answer:

67.5

Step-by-step explanation:

total=360 degrees

360 - 90 = 270

3x + x = 4x

270 = 4x

270/4=67.5

x = 67.5

Answer:

answer D

Step-by-step explanation:

hello,

\(f(x)=-5^x-4 \ and \ g(x)=-3x-2\\(f-g)(x)=f(x)-g(x)=-5^x-4+3x+2=-5^x+3x-2\)

hope this helps

The value of function (f - g) (x) is,

⇒ 5ˣ + 3x - 2

A relation between a set of inputs having one output each is called a function. and an expression, rule, or law that defines a relationship between one variable (the independent variable) and another variable (the dependent variable).

Given that;

Functions are,

⇒ f (x) = - 5ˣ - 4

⇒ g (x) = - 3x - 2

Hence, We get;

The value of function (f - g) (x) is,

⇒ (f - g) (x)

⇒ f (x) - g(x)

⇒ (5ˣ - 4) - (- 3x - 2)

⇒ 5ˣ - 4 + 3x + 2

⇒ 5ˣ + 3x - 2

Thus, The value of function (f - g) (x) is,

⇒ 5ˣ + 3x - 2

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In the inter-quartile graph , the data is contained in about 75% of the total (IQR).

A sort of graph used to show numerical data visually is the box-and-whisker plot. In this graph, the inter-quartile range (IQR) of the data is shown as a rectangular box, and the median is shown as a line extending from the box. The minimum and maximum values of the data are indicated by the whiskers extending from the box. It is clear from the box-and-whisker plot's information that roughly 75% of the data falls inside the inter-quartile range. The first quartile (Q1) is subtracted from the third quartile to determine the IQR (Q3). The median of the lower half of the data is the lower quartile (Q1), and the median of the higher half is the upper quartile (Q3). The dispersion of the middle half of the data is thus indicated by the IQR. When evaluating data, having this knowledge is crucial since it makes it easier to see any outliers or numbers outside the IQR.

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The complete question is

considering the attached box-and-whisker plot, what percent of data lies within the inter-quartile range (iqr) and find the data?

Answer:

258.39 m^2

Step-by-step explanation:

Solve for the rectangle:

18 • 12= 216

Now solve for the 3 semi circles:

A = 3.14(3)^2= 28.26/2 = 14.13 •3 = 42.39

Add up the areas:

216 + 42.39 = 258.39

The tables that reprsesent a linear function is (d)

From the question, we have the following parameters that can be used in our computation:

The table of values

A table of value that is a linear function is a table that has a constant rate

i.e. as x changes, y changes constantly

Using the above as a guide, we have the following:

In table (d) x changes constantly by 1 and y constantly changes by -2

Hence, the table is table (d)

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Answer:

n

Step-by-step explanation:

m/n = 0

=> m = 0 × n

=> m = 0

n + 0 = n

Answer:

d

Step-by-step explanation:

add them all up then divide by 5

Answer:

246

Step-by-step explanation:

Given that,

→ what is 492 divided by 2 ?

In mathematical form,

→ 492 ÷ 2

→ 246 {final answer}

Hence, the answer is 246.