Can someone pls help me Pls

The quadratic function graphed is defined as follows:

y = x² - 10x + 9.

We are given the roots for each function, hence the factor theorem is used to define the functions.

The function is defined as a product of it's linear factors, if x = a is a root, then x - a is a linear factor of the function.

From the graph, the roots are given as follows:

x = 1 and x = 9.

Hence the function as a product of it's linear factors is defined as follows:

y = a(x - 1)(x - 9)

y = a(x² - 10x + 9).

When x = 5, y = -16, hence the leading coefficient a is obtained as follows:

-16 = a(5² - 10(5) + 9)

-16a = -16

a = 1.

Thus the function is:

y = x² - 10x + 9.

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Answer:

21

Step-by-step explanation:

63/3

21

I'm going to be honest, I don't know how to show the work. You wouldn't do long division because it doesn't go into decimals.

Answer:76

Step-by-step explanation:

):!/

Answer:

c

Step-by-step explanation:

Answer:

133 m^2

Step-by-step explanation:

to find are of a circle it’s r^2 times pi

6^2 x pi

36 pi

113 m^2

Hopes this helps please mark brainliest

Answer:

Answer C is correct

Step-by-step explanation:

The formula to find the area of a circle is:

A = πr²

Here,

r => radius = 6m

Let us find the area of the circle.

A = πr²

A = 3.14 × 6 × 6

A = 113.04 m²

Approx. = 113m²

Answer:

$20 per square foot

Step-by-step explanation:

\(8.2x-3.7x=90 \\ \\ 4.5x=90 \\ \\ x=20\)

\(~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$2000\\ r=rate\to 7\%\to \frac{7}{100}\dotfill &0.07\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{semi-annually, thus twice} \end{array}\dotfill &2\\ t=years\dotfill &25 \end{cases} \\\\\\ A = 2000\left(1+\frac{0.07}{2}\right)^{2\cdot 25}\implies A=2000(1.035)^{50} \implies A \approx 11169.85\)

Explanation:

The horizontal component is found using cos fxn

80 x cos 20 =  75.2 pounds

Answer:

x=22.8 inches

I think T__T

Step-by-step explanation:

YES... SOMETHING I KNOW!

Use Pythagorean theroy

say 42.7=a

48.4=b

x=c

the formula is: a^2+c^2=b^2

so: 42.7^2+x^2=48.4^2

if we simplify:=1823.29+x^2=2342.56

then:519.27=x^2

It says, round to the nearest TENTH

x=22.787497

so then x would be

22.80

Here are the correct matches to the expressions to their solutions.

The GCF of 28 and 60 is 4.

(-3/8)+(-5/8) = -4/4 = -1.

-1/6 DIVIDED BY 1/2 = -1/6 X 2 = -1/3.

The solution of 0.5 x = -1 is x = -2.

The solution of 1/2 m = 0 is m = 0.

-4 + 5/3 = -11/3.

-2 1/3 - 4 2/3 = -10/3.

4 is not a solution of -4 < x.

1. The GCF of 28 and 60 is 4.

The greatest common factor (GCF) of two numbers is the largest number that is a factor of both numbers. To find the GCF of 28 and 60, we can factor each number completely:

28 = 2 x 2 x 7

60 = 2 x 2 x 3 x 5

The factors that are common to both numbers are 2 and 2. The GCF of 28 and 60 is 2 x 2 = 4.

2. (-3/8)+(-5/8) = -1.

To add two fractions, we need to have a common denominator. The common denominator of 8/8 and 5/8 is 8. So, (-3/8)+(-5/8) = (-3 + (-5))/8 = -8/8 = -1.

3. -1/6 DIVIDED BY 1/2 = -1/3.

To divide by a fraction, we can multiply by the reciprocal of the fraction. The reciprocal of 1/2 is 2/1. So, -1/6 DIVIDED BY 1/2 = -1/6 x 2/1 = -2/6 = -1/3.

4. The solution of 0.5 x = -1 is x = -2.

To solve an equation, we can isolate the variable on one side of the equation and then solve for the variable. In this case, we can isolate x by dividing both sides of the equation by 0.5. This gives us x = -1 / 0.5 = -2.

5. The solution of 1 m = 0 is m = 0.

To solve an equation, we can isolate the variable on one side of the equation and then solve for the variable. In this case, we can isolate m by dividing both sides of the equation by 1. This gives us m = 0 / 1 = 0.

6. -4 + 5/3 = -11/3.

To add a fraction and a whole number, we can convert the whole number to a fraction with the same denominator as the fraction. In this case, we can convert -4 to -4/3. So, -4 + 5/3 = -4/3 + 5/3 = -11/3.

7. -2 1/3 - 4 2/3 = -10/3.

To subtract two fractions, we need to have a common denominator. The common denominator of 1/3 and 2/3 is 3. So, -2 1/3 - 4 2/3 = (-2 + (-4))/3 = -6/3 = -10/3.

8. 4 is not a solution of -4 < x.

The inequality -4 < x means that x must be greater than -4. The number 4 is not greater than -4, so it is not a solution of the inequality.

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Answer:

9/10

Step-by-step explanation:

1. Find the least common denominator for the fractions

2. The lcd is 30

3. If 6 x 5 is 30 then you have to multiply 1 x 5 also

4. Multiply 5 x 6 also multiply 2 x 6

5. Multiply 3 x 10 also multiply 1 x 10

6. you get 27/30 when you add 5/30, 12/30, and 10/30.

7. Simplify 27/30 you get 9/10

Answer:

9/10

Step-by-step explanation:

Hello!

The easiest way to break this problem down is to ad up all of the parts, but to do that they need the same denominator!

our fractions are

1/6

2/5

1/3

Now we need to find a common multiple that these numbers have!

lets start with 6

6, 12, 18, 24, 30

Now 5

5, 10, 15, 20, 25, 30

Now 3

3, 6, 9, 12, 15, 18, 21, 24, 27, 30

They all have 30 in common!

So now we convert them so their denominator is 30!

We do this by multiplying the numerator by whatever we multiplied the denominator by to get 30!

1/6 = 1x1 6x5 = 5/30

2/5 = 2x6 5x6= 12/30

1/3 = 1x10 3x10 =10/30

Now we add!

5+12+10= 27

27/30

Now we simplify this equation

27/3= 9 30/3 = 10

9/10

So she has read 9/10 of her book!

Hope this helps!^^

Answer:

The correct answer is B. With a t statistic of 1.4789 and P-value of 0.173292, fail to reject the null hypothesis that prices have not changed.

Explanation:

To determine whether there has been a significant change in prices, we need to perform a two-sample t-test with the null hypothesis that the mean difference between before and after prices is zero.

We can calculate the sample mean and standard deviation of the difference in prices as follows:

Mean difference = (0.30 - 0.31 + 0.26 + 0.04 + 0.06 + 0.14 - 0.09 - 0.02 - 0.04 + 0.07) / 10 = 0.022

Standard deviation = sqrt([sum of (differences - mean difference)^2] / (n - 1)) = sqrt((0.09 + 0.0961 + 0.0004 + 0.0016 + 0.0036 + 0.0196 + 0.0081 + 0.0004 + 0.0016 + 0.0049) / 9) = 0.112

where 'differences' are the differences between the before and after prices and 'n' is the sample size (which is 10 in this case).

Using these values, we can calculate the t statistic as:

t = (mean difference - 0) / (standard deviation / sqrt(n)) = 0.022 / (0.112 / sqrt(10)) = 1.4789

where 0 is the null hypothesis mean (i.e., no change in prices).

To determine the P-value, we need to use a two-tailed t-test with 9 degrees of freedom (n - 1). From a t-table with 9 degrees of freedom and a significance level of 0.05, the critical values are -2.306 and 2.306.

Since the calculated t statistic (1.4789) falls within this range, we fail to reject the null hypothesis that the mean difference between before and after prices is zero. This means that there is not enough evidence to suggest that the new owner has significantly changed the prices.

Therefore, the correct answer is B. With a t statistic of 1.4789 and P-value of 0.173292, fail to reject the null hypothesis that prices have not changed.

Hope this helps! Sorry if it doesn't. If you need more help, ask me! :]

Answer:

The slope of line 1 is -4/3.

The slope of line 2 is 2/3.

Line 1 is neither parallel nor perpendicular to line 2.

Step-by-step explanation:

firstly we find slope using two point formula .

The lines are said to be parallel when their slopes are equal.The lines are said to be perpendicular when the product of their slope is -1. Hence, line 1 is neither parallel nor perpendicular to line 2.

Answer:

y-1= -1/3(x+3)

Step-by-step explanation:

y-y1=m(x-x1)

y-1=m(x+3)

the slope is rise over run

the slope is -1/3

Answer:

y - 1 = 3/2 (x + 3)

Step-by-step explanation:

To find the equation of a line parallel to the given line and passing through the point (-3, 1), we can use the point-slope form of a linear equation. The point-slope form is given by:

y - y₁ = m(x - x₁)

Where (x₁, y₁) is the given point and m is the slope of the line.

First, let's calculate the slope of the given line using the two points (-2, -4) and (2, 2):

slope = (y₂ - y₁) / (x₂ - x₁)

= (2 - (-4)) / (2 - (-2))

= 6 / 4

= 3/2

Since the line we want to find is parallel to the given line, it will have the same slope. Therefore, the slope (m) of the new line is also 3/2.

Now we can substitute the values into the point-slope form using the point (-3, 1):

y - 1 = (3/2)(x - (-3))

y - 1 = (3/2)(x + 3)

The equation in point-slope form of the line parallel to the given line and passing through the point (-3, 1) is:

y - 1 = 3/2 (x + 3)

Answer:

y=2x+3

Step-by-step explanation:

y=mx+b

Answer:

y=$3 + $2x.

Step-by-step explanation:

y=3+2x. Make a table, at week 1 Nate has $2 + the $3 he started with. At week 2, Nate has $4 plus the $3 he started with.  And so on.  Plug the number of weeks in for x and solve for y for the total at any number of weeks given.

Answer:

part A:

\(\sf AB^2 = (-2-1)^2 + (1+3)^2\)

\(\sf AB^2 =25\)

\(\sf AB =5\)

\(\sf AC^2 = (2-1)^2 + (4+3)^2\)

\(\sf AC^2 = 50\)

\(\sf AC = 5\sqrt{2}\)

\(\sf BC^2 = (2--2)^2 + (4-1)^2\)

\(\sf BC^2 = 25\)

\(\sf BC = 5\)

Two sides are equal in the triangle of 5. Its an isosceles triangle.

part B:

if right angle triangle, then use the formula:

short side² + short side² = long side²

( 5√2 )² + 5² = ( 5√2 )²

75 = 50

Therefore, its not a right angle triangle.

Answer:

\(\begin{aligned}x &= 16\sqrt3 \\ &\approx 27.7\end{aligned}\)

Step-by-step explanation:

We can see that the longer leg (a) of a right triangle is half of the circle's radius. Since we are given the other two sides of the triangle (shorter leg and hypotenuse), we can solve for the length of the longer leg using the Pythagorean Theorem:

\(a^2 + b^2 = c^2\)

↓ plugging in the given values

\(a^2 + 2^2 = 14^2\)

↓ subtracting 2² from both sides

\(a^2 = 14^2 - 2^2\)

\(a^2 = 196 - 4\)

\(a^2 = 192\)

↓ taking the square root of both sides

\(a = \sqrt{192\)

↓ simplifying the square root

\(a = \sqrt{2^6 \cdot 3\)

\(a = 2^{\, 6 / 2} \cdot \sqrt3\)

\(a = 2^3\sqrt3\)

\(a = 8\sqrt3\)

Now, we can solve for the radius (x) using the fact that the longer leg of the triangle is half of it.

\(a = \dfrac{1}{2}x\)

↓ plugging in the a-value we solved for

\(8\sqrt3 = \dfrac{1}2x\)

↓ multiplying both sides by 2

\(\boxed{x = 16\sqrt3}\)

The total distance Tracy traveled was 15,000 feet assuming each unit represents 1,000 feet.

The total distance is the sum of all the distance between stops.

Partial distances:

However, the real distance would be 10.63 units based on the locations in the grid.

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Answer:

1/3  , only one solution

Step-by-step explanation:

3x-1 = 1-3x

3x-1 = -3x+1

6x-1 = 1

6x = 2

x = 1/3

Answer:

Infinitely many solutions.

Step-by-step explanation:

\(3x+1-3(x-1)=4\\\\3x+1-1-3(x-1)=4-1\\\\3x-3(x-1)=3\\\\3x-3x-3=3\\\\\boxed{3=3}\)

Hope this helps.

The number of tiles needed to cover the surface area of the box excluding the bottom is: 1,046 tiles.

The surface area of a box is the area surrounding all its faces. A box has 6 rectangular faces. Therefore, the total surface area of the box equals the sum of all 6 rectangular faces.

SA = 2(lw + lh + hw), where:

The image attached below shows the box Dmitri wants to cover. Since the bottom of the box would be excluded, therefore:

The surface area to be covered = surface area of the box - area of the bottom rectangular face

The surface area to be covered = 2(lw + lh + hw) - (l)(w)

l = 26

w = 15

h = 8

Substitute

The surface area to be covered = 2(l×w + lh + hw) - (l)(w) = 2·(15·26+8·26+8·15) - (26)(15) =

The surface area to be covered = 1436 - 390 = 1,046 cm

Area of one tile = 1 cm square

Number of tiles needed = 1,046/1

Number of tiles needed = 1,046 tiles.

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9514 1404 393

Answer:

Step-by-step explanation:

1. The graph (red) shows the only real zeros to be -1 and 2. When the corresponding factors are divided from the function, the remaining factor is the quadratic (x^2 +1), which has only complex roots. The quadratic is graphed in green.

The linear factorization is ...

  f(x) = (x +1)(x -2)(x -i)(x +i)

The roots are -1, 2, -i, +i.

__

2. The graph (blue) shows the zeros are 1, 3, 4.

You observe that the sum of coefficients is zero, so x=1 is a root. Factoring that out gives the quadratic (x^2 -7x +12), which you recognize factors as

  (x -3)(x -4) . . . zeros of 3 and 4

__

I have attached a spreadsheet that does synthetic division. There are web sites that will do this, too. The tables shown correspond to f1(x)/(x-2) and f2(x)/(x-1). When you fill in the zero and coefficients, the built-in formulas do the rest.

9514 1404 393

Answer:

real: -1, 2; complex: +i, -i

1, 3, 4

Step-by-step explanation:

1. The graph (red) shows the only real zeros to be -1 and 2. When the corresponding factors are divided from the function, the remaining factor is the quadratic (x^2 +1), which has only complex roots. The quadratic is graphed in green.

The linear factorization is ...

 f(x) = (x +1)(x -2)(x -i)(x +i)

The roots are -1, 2, -i, +i.

__

2. The graph (blue) shows the zeros are 1, 3, 4.

You observe that the sum of coefficients is zero, so x=1 is a root. Factoring that out gives the quadratic (x^2 -7x +12), which you recognize factors as

 (x -3)(x -4) . . . zeros of 3 and 4

__ The tables shown correspond to f1(x)/(x-2) and f2(x)/(x-1).

To find the perimeter of the regular polygon, that in this case is a pentagon, multiply 5 by the sidelength of the pentagon, it means 5 times 3.

The perimeter of the polygon is 15in

Answer:

hi how to use a app i am new

Expression given:

Procedure:

0. Solving for ,x: ,multiplying both sides by 2

Substracting both sides by x

There are $2224.12 need to deposit in an account in order to have $3000 in five years.

What is future value?

Future value is the worth of a financial asset or investment on a specific future date. In other words, future value is the amount of money an investment will be worth, assuming a specific rate of return, after a specific amount of time (interest rate).

Given:

Future value = FV = $3000

Number of years = t = 5

Interest rate = r = 6% = 0.06

Compounding period = n = 12

We have to find the present value form given problem.

Consider, the Future value formula,

\(FV = PV(1 + \frac{r}{n})^n^*^t\)

Plug the values in the above formula.

\(3000 = PV(1+\frac{0.06}{12})^1^2^*^5\\ 3000 = PV(1+0.005)^6^0\\3000 = PV(1.005)^6^0\\PV = 2224.11658\)

PV = $2224.12

Hence, there are $2224.12 need to deposit in an account in order to have $3000 in five years.

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Aircraft A has 312 seats.

Let's assume that Aircraft B has x seats.

According to the given information, Aircraft A has 105 more seats than Aircraft B. So, the number of seats in Aircraft A can be expressed as x + 105.

The total number of seats in both aircraft is 519, which can be represented by the equation:

x + (x + 105) = 519

Simplifying this equation, we have:

2x + 105 = 519

Subtracting 105 from both sides, we get:

2x = 414

Dividing both sides by 2, we find:

x = 207

Therefore, Aircraft B has 207 seats.

To find the number of seats in Aircraft A, we substitute the value of x back into the expression x + 105:

Aircraft A = 207 + 105 = 312

Hence, Aircraft A has 312 seats.

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The statement which best describes the data given is C) The data can be modeled by a quadratic function.

Given a data,

The numbers of customers that visited a store each hour for several hours after the store opened at 8 am are shown in the table.

It is clear that the number of customers increases to 18 for the first 4 hours and then decreases to 0 after 9 hours.

So this data cannot be modeled by a linear function or an exponential function.

Also since the number of customers arriving is not constant, this cannot be expressed as constant function.

So it is quadratic function.

Hence the correct option is c.

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1.Bricks and timber purchased for construction. (Debit: Bricks - Rs 60,000, Debit: Timber - Rs 35,000, Credit: Bank - Rs 95,000)

2.Transfer of Rs 13,000 to fixed deposit account. (Debit: Fixed Deposit - Rs 13,000, Credit: Current Account - Rs 13,000)

3.Appointment of Mr. S.N. Rao as Accountant. (Debit: Salary Expense - Rs 300, Debit: Security Deposit - Rs 1,000, Credit: Accountant - Rs 300)

4.Goods sold to Shruti with discounts. (Debit: Accounts Receivable - Shruti - Rs 80,000, Credit: Sales - Rs 80,000)

5.Goods purchased from Richa with discounts. (Debit: Purchases - Rs 60,000, Credit: Accounts Payable - Richa - Rs 60,000)

6.Goods sold to Shilpa with discounts and received payment. (Debit: Accounts Receivable - Shilpa - Rs 50,000, Credit: Sales - Rs 50,000)

7.Goods sold to Garima with discounts and received partial payment. (Debit: Accounts Receivable - Garima - Rs 1,00,000, Credit: Sales - Rs 1,00,000)

8.Purchase of land with additional charges. (Debit: Land - Rs 2,00,000, Debit: Brokerage Expense - Rs 2,000, Debit: Registration Charges - Rs 15,000, Credit: Bank - Rs 2,17,000)

9.Proprietor took goods and cash for personal use. (Debit: Proprietor's Drawings - Rs 65,000, Credit: Goods - Rs 25,000, Credit: Cash - Rs 40,000)

10.Goods sold to Charu with profit and discount. (Debit: Accounts Receivable - Charu - Rs 1,20,000, Credit: Sales - Rs 1,20,000)

11.Rent paid for the building. (Debit: Rent Expense - Rs 60,000, Credit: Bank - Rs 60,000)

12.Goods sold to Sunil with profit and discount. (Debit: Accounts Receivable - Sunil - Rs 24,000, Credit: Sales - Rs 24,000)

13.Purchased goods from Nanda and supplied to Helen. (Debit: Purchases - Rs 1,000, Debit: Accounts Payable - Nanda - Rs 1,000, Credit: Accounts Receivable - Helen - Rs 1,300, Credit: Sales - Rs 1,300)

14.Purchased goods from Rohit and Sons and supplied to Madan. (Debit: Purchases - Rs 2,700, Credit: Accounts Payable - Rohit and Sons - Rs 2,700, Debit: Accounts Receivable - Madan - Rs 3,000, Credit: Sales - Rs 3,000)

Here are the journal entries for the given transactions:

1. Bricks and timber purchased for construction:

Debit: Bricks (Asset) - Rs 60,000

Debit: Timber (Asset) - Rs 35,000

Credit: Bank (Liability) - Rs 95,000

2. Transfer to fixed deposit account:

Debit: Fixed Deposit (Asset) - Rs 13,000

Credit: Current Account (Asset) - Rs 13,000

3. Appointment of Mr. S.N. Rao as Accountant:

Debit: Salary Expense (Expense) - Rs 300

Debit: Security Deposit (Asset) - Rs 1,000

Credit: Accountant (Liability) - Rs 300

4. Goods sold to Shruti:

Debit: Accounts Receivable - Shruti (Asset) - Rs 80,000

Credit: Sales (Income) - Rs 80,000

5. Goods purchased from Richa:

Debit: Purchases (Expense) - Rs 60,000

Credit: Accounts Payable - Richa (Liability) - Rs 60,000

6. Goods sold to Shilpa:

Debit: Accounts Receivable - Shilpa (Asset) - Rs 50,000

Credit: Sales (Income) - Rs 50,000

7. Goods sold to Garima:

Debit: Accounts Receivable - Garima (Asset) - Rs 1,00,000

Credit: Sales (Income) - Rs 1,00,000

8.Purchase of land:

Debit: Land (Asset) - Rs 2,00,000

Debit: Brokerage Expense (Expense) - Rs 2,000

Debit: Registration Charges (Expense) - Rs 15,000

Credit: Bank (Liability) - Rs 2,17,000

9. Goods and cash taken away by proprietor:

Debit: Proprietor's Drawings (Equity) - Rs 65,000

Credit: Goods (Asset) - Rs 25,000

Credit: Cash (Asset) - Rs 40,000

10. Goods sold to Charu:

Debit: Accounts Receivable - Charu (Asset) - Rs 1,20,000

Credit: Sales (Income) - Rs 1,20,000

Credit: Cost of Goods Sold (Expense) - Rs 80,000

Credit: Profit on Sales (Income) - Rs 40,000

11. Rent paid for the building:

Debit: Rent Expense (Expense) - Rs 60,000

Credit: Bank (Liability) - Rs 60,000

12. Goods sold to Sunil:

Debit: Accounts Receivable - Sunil (Asset) - Rs 24,000

Credit: Sales (Income) - Rs 24,000

Credit: Cost of Goods Sold (Expense) - Rs 20,000

Credit: Profit on Sales (Income) - Rs 4,000

13. Goods purchased from Nanda and supplied to Helen:

Debit: Purchases (Expense) - Rs 1,000

Debit: Accounts Payable - Nanda (Liability) - Rs 1,000

Credit: Accounts Receivable - Helen (Asset) - Rs 1,300

Credit: Sales (Income) - Rs 1,300

14. Goods received from Rohit and Sons and supplied to Madan:

Debit: Purchases (Expense) - Rs 2,700 (after 10% trade discount)

Credit: Accounts Payable - Rohit and Sons (Liability) - Rs 2,700

Debit: Accounts Receivable - Madan (Asset) - Rs 3,000

Credit: Sales (Income) - Rs 3,000

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