can someone please help?​

Galaxy B is moving away from us at a speed of 24,000 km/s.

The speed at which Galaxy B is moving away from us would be 24,000 km/s. Here's how we arrived at this conclusion:

Given: Galaxy A has a cosmological redshift in its spectrum of z = 0.01 indicating it is moving away from us at 3000 km/s.

Galaxy B has z = 0.08.We know that the redshift z is directly proportional to the speed at which the galaxy is moving away from us.

In other words, z ∝ v, where z is the redshift, and v is the speed.

Therefore, we can write:z₁/v₁ = z₂/v₂where z₁ and v₁ are the redshift and speed of Galaxy A, and z₂ and v₂ are the redshift and speed of Galaxy B.

Rearranging the formula, we get:v₂ = (z₂/z₁) x v₁

Substituting the values of z₁, v₁, and z₂ into the formula, we get:v₂ = (0.08/0.01) x 3000 km/sv₂ = 24,000 km/s

Therefore, Galaxy B is moving away from us at a speed of 24,000 km/s.

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The phrase "twelve less than the product of three and a number" can be translated into an algebraic expression 3x - 12. We can use this expression to find the value of the expression for a given value of x or to write and solve an equation involving this expression.

The phrase "twelve less than the product of three and a number" can be translated into an algebraic expression. To do this, we need to assign a variable to the unknown number and then use multiplication and subtraction to represent the given information.

Let x be the unknown number. The product of three and x is 3x. Twelve less than 3x is 3x - 12. Therefore, the algebraic expression for "twelve less than the product of three and a number" is 3x - 12. This expression represents a value that is 12 less than three times the number x.

For instance, if we know that a number is 7, we can use this expression to find the value of "twelve less than the product of three and 7."3x - 12 = 3(7) - 12= 21 - 12= 9Therefore, the value of "twelve less than the product of three and 7" is 9. We can also use this expression to write an equation and solve for x. For example, if we know that the value of "twelve less than the product of three and a number" is 33, we can write an equation:3x - 12 = 33Then, we can solve for x:3x = 33 + 123x = 45x = 15. Therefore, the unknown number is 15.

To summarize, the phrase "twelve less than the product of three and a number" can be translated into an algebraic expression 3x - 12. We can use this expression to find the value of the expression for a given value of x or to write and solve an equation involving this expression.

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Keith took a four question test and got 1 and a half questions wrong. His final score is 2.5 out of 4, or 62.5%.

To calculate Keith's final score, you need to divide the number of correct answers by the total number of questions. In this case, Keith answered 2.5 out of 4 questions correctly. Therefore, his final score is 2.5 divided by 4, which equals 0.625. This is equal to 62.5%.
To summarize, Keith took a four question test and got 1 and a half questions wrong, giving him a final score of 62.5%.

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To find the general expression for the elasticity of demand (e_p), we need to differentiate the demand function with respect to price (p) and multiply it by the ratio of price to quantity (p/q). The elasticity of demand measures the responsiveness of quantity demanded to changes in price.

The general expression for elasticity of demand (e_p) can be calculated as:

e_p = (dQ/dp) * (p/Q)

Where dQ/dp represents the derivative of the demand function with respect to price, and Q represents the quantity demanded.

The elasticity of demand helps us understand how sensitive the quantity demanded is to changes in price. If e_p is greater than 1, demand is considered elastic, meaning that quantity demanded is highly responsive to price changes. If e_p is less than 1, demand is inelastic, indicating that quantity demanded is less responsive to price changes.

In conclusion, the general expression for the elasticity of demand (e_p) is calculated by taking the derivative of the demand function with respect to price and multiplying it by the ratio of price to quantity. This measure helps determine the responsiveness of quantity demanded to changes in price.

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Answer:

A

Step-by-step explanation:

r=d/2

=6/2 =3

2πr

2×3.14×3

=18.84

Tony's coins in ascending order of value will be 5p, 10p, and 15p.

Definition of in Ascending order

Arranged in a series that begins with the smallest or least and ends with the largest or greatest The children were lined up in ascending order of height. Test score are listed in ascending order from lowest to highest.

How do depict the information?

Based on the information given, the values of the coins will be 5p, 5p, 10p, 15p, and 15p.

In this case, 5p + 10p + 15p = 30p

10p + 15p + 15p = 40p

5p + 5p + 10p + 15p + 15p = 50p

Therefore, Tony's coins in ascending order of value will be 5p, 10p, and 15p.

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The predicted value of y is 53 for the given equation of the trend line.

Given equation of trend line is Yx = 3 + 10x.

We are supposed to determine the predicted value of y if x is 5.

To find the value of y, we have to substitute the value of x in the given equation:

Yx = 3 + 10x

When x = 5,

Then Yx = 3 + 10(5)

           = 3 + 50 = 53

So, the predicted value of y is 53. Therefore, 53 is the correct answer.

Trend lines are drawn at an angle and are used to determine a trend and help making trading decision.

A trend line should be connected by at least three highs or lows to make it valid.

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Answer:

C. order

Step-by-step explanation:

The associative property of addition allows you to change the of numbers without affecting the sum.

Answer: Grouping

Step-by-step explanation:

Changing the grouping of addends does not change the sum. For example, ( 2 + 3 ) + 4 = 2 + ( 3 + 4 ) (2 + 3) + 4 = 2 + (3 + 4) (2+3)+4=2+(3+4)left parenthesis, 2, plus, 3, right parenthesis, plus, 4, equals, 2, plus, left parenthesis, 3, plus, 4, right parenthesis.

Answer:

20. \(-\frac{y^{12} }{9x^{4} }\)    

Step-by-step explanation:

21.  \(3 x^{2} y^{2}\)

The conic water vessel of height 40 cm and radius 8 cm filled at 20 cm^3/s gives;

The volume of the vessel, v = π•r^2•h/3

\( \frac{h}{r} = \frac{40}{8} = 5\)

h = 5•r

Therefore;

v = π•r^2•(h)/3 = π•(h/5)^2•h/3

v = π•h^3/75

By chain rule of differentiation, we have;

\( \frac{dv}{dh} = \frac{dv}{dt} \times \frac{dt}{dh} \)

Which gives;

\(π• \frac{ {h}^{2} }{25} = 20 × \frac{dt}{dh} \)

\( \frac{dh}{dt} = \frac{20}{\pi \frac{ {h}^{2} }{25} } \)

When the height is 12 cm from the vertex, we have;

\( \frac{dh}{dt} = \frac{20}{\pi \frac{ {12}^{2} }{25} } = 1.1 \)

When the vessel is one-quarter filled, we have;

v = π•h^3/75

π•(40)^3/(75×4) = π•h^3/75

10•(40)^2 = 16,000 = h^3

h = (16,000)^(1/3) = 25 (approx)

Which gives;

\( \frac{dh}{dt} = \frac{20}{\pi \frac{ {25}^{2} }{25} } = 0.21 \)

When the vessel is one-quarter filled the rate at which the water level is rising is approximately 0.21 cm/s.

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Answer:

x=53°

(x+2)=55°

Step-by-step explanation:

Add all the angles up to equal 180, because all triangles equal 180.

(x+2)+x+72=180

Simplify and solve for x.

2x+74=180

-74=-74

2x=106

2 = 2

x=53.

Plug x in to the inequalities. Hope this helps.

Multiplying the length and width together, we get 3m x 4m = 12m². This means that the area of the rectangle is 12 square meters.

Area = Length x Width

Area = 3m x 4m

Area = 12m²

To solve for the area of a rectangle, you will need to use the formula Area = Length x Width. In this example, the length of the rectangle is 3 meters and the width is 4 meters. To calculate the area of the rectangle, you will need to multiply the length and width together. 3m x 4m = 12m². Therefore, the area of the rectangle is 12 square meters.

The area of a rectangle is calculated by multiplying the length and width of the rectangle together. The formula used to calculate the area of a rectangle is Area = Length x Width. To put this formula into practice, lets use the example of a rectangle that is 3 meters long and 4 meters wide. Multiplying the length and width together, we get 3m x 4m = 12m². This means that the area of the rectangle is 12 square meters. This formula can be used for any rectangle, as long as the length and width are known. Knowing the area of a rectangle can be useful for many purposes, such as calculating the amount of paint or carpeting needed to cover the surface area of the rectangle.

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1) We can rewrite that equation from Point Slope to Standard Form just manipulating that given Point-Slope Equation:

2) So let's distribute the factor -6, and then add 6x to both sides and -2 to both sides as well

3) So the answer is:

Note that this is the equivalent form of that original Point-Slope Form equation.

Answer:

A. 1/220   B. 1/22   C. 3/11

Step-by-step explanation:

This question uses combinations -- counting the number of ways a selection can be made from a set of objects (without arranging them after the selection is done).

Notations for combinations:

The number of ways to select  r  things from a set of  n  things is

\(C(n,r)=\frac{n!}{r!(n-r)!}\)  where the exclamation points mean factorial.

\(n!=1\cdot2\cdot3\ldots\cdot n\)  and 0! is defined to be 1.

There are two other commonly used symbols for this:

\(_nC_r\)  and  \(n \choose x\).

In all three parts, the number of ways to choose 3 balls from a set of 12 is

\(C(12,3) = \frac{12!}{3!(12-3)!}=\frac{12\cdot 11 \cdot 10 \cdot 9\cdot 8\cdot 7\cdot 6\cdot 5\cdot4\cdot3\cdot2\cdot1}{(3\cdot2\cdot1)(9\cdot8\cdot7\cdot6\cdot5\cdot4\cdot3\cdot2\cdot1)}\)

Notice that 9 factors in the denominator cancel 9 factors in the numerator, leaving

\(C(12,3) = \frac{12!}{3!(12-3)!}=\frac{12\cdot 11 \cdot 10}{3\cdot2\cdot1}=220\)

A. The number of ways to choose 3 red balls from the 3 red balls is C(3, 3) = 1, so the probability is 1 / 220.

B)  The number of ways to choose 3 green balls from the set of 5 green balls is \(C(5,3)=\frac{5!}{3!(5-3)!}=\frac{5!}{3!2!}=\frac{5\cdot 4}{2}=10\)  out of 220, so the probability is 10/220 = 1/22.

C)  The number of ways to choose 1 red is C(3, 1) = 3.  Choose 1 green in C(5, 1) = 5 ways.  Choose 1 white in C(4, 1) = 4 ways.

The probability is  \(\frac{3\cdot 5 \cdot 4}{220}=\frac{60}{220}=\frac{3}{11}\)

Answer:

a) 1/220

b) 1/22

c) 3/11

Step-by-step explanation:

Check the attachment.

Answer:

7.84  ×  10 ^7

Step-by-step explanation:

Answer:

Step-by-step explanation:

First you will do 6.75*10=67.50

Next you will do 6.75*12= 81

Then you will do 6.75*20= 135

Last you add 67.50+81+135= $283.50

Answer:

A, B, and C

Step-by-step explanation:

The answer for 15.2+w=19.75+4.2 is w=8.75

3w=22.25+4 is w=8.75

The next equation is w= -8.75

The last equation is w= 8.75

\(11x-21=8x+15\\3x-21=15\\3x=36\\x=\boxed{12}\)

\(LM=11(12)-21=\boxed{111}\\\\MN=LM=\boxed{111}\\\\LN=111+111=\boxed{222}\)

Answer:

1.  -6a - 48

2. 4 + 36x

3. -30n + 42

4. 18m + 20

5. 32 + 24n

6. -8b - 32

Answer:

Step-by-step explanation:

All use distributive propriety of multiplication over addition/subtraction

just remember  (-)*(-) = (+) and (-)*(+) = (-)

1) -6(a+8) = -6a -48

2) 4(1+9x) = 4 + 36x

3) 6(-5n+7) = -30n + 42

4) (9m +10) *2 = 18m +20

5) (-4-3n)*-8 = 32+24n

6) 8(-b-4) = -8b -32

a)  The volume of paint left in the can is:

.878 gallons * 0.00378541 m^3/gallon = 0.003321 m^3

b)  the thickness of the layer of wet paint is 0.000242 meters or 0.242 millimeters (since there are 1000 millimeters in a meter).

(a) To convert gallons to cubic meters, we need to know the conversion factor between the two units. One U.S. gallon is equal to 0.00378541 cubic meters. Therefore, the volume of paint left in the can is:

0.878 gallons * 0.00378541 m^3/gallon = 0.003321 m^3

(b) We can use the formula for the volume of a rectangular solid to find the volume of wet paint needed to coat the wall evenly:

Volume = area * thickness

We want to solve for the thickness, so we rearrange the formula to get:

Thickness = Volume / area

The volume of wet paint needed is equal to the volume of dry paint needed since they both occupy the same space when the paint dries. Therefore, the volume of wet paint needed is:

0.003321 m^3

The area of the wall is given as:

13.7 m^2

So the thickness of the layer of wet paint is:

0.003321 m^3 / 13.7 m^2 = 0.000242 m

Therefore, the thickness of the layer of wet paint is 0.000242 meters or 0.242 millimeters (since there are 1000 millimeters in a meter).

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Answer:

The variable, y is 11°

Step-by-step explanation:

The given parameters are;

in triangle ΔABC;          \({}\)              in triangle ΔFGH;

Segment \(\overline {AB}\) = 14         \({}\)               Segment \(\overline {FG}\) = 14

Segment \(\overline {BC}\) = 27         \({}\)              Segment \(\overline {GH}\) = 19

Segment \(\overline {AC}\) = 19         \({}\)               Segment \(\overline {FH}\) = 2·y + 5

∡A = 32°                       \({}\)                ∡G = 32°

∡A = ∠BAC which is the angle formed by segments \(\overline {AB}\) = 14 and \(\overline {AC}\) = 19

Therefore, segment \(\overline {BC}\) = 27, is the segment opposite to ∡A = 32°

Similarly, ∡G = ∠FGH which is the angle formed by segments \(\overline {FG}\) = 14 and \(\overline {GH}\) = 19

Therefore, segment \(\overline {FH}\) = 2·y + 5, is the segment opposite to ∡A = 32° and triangle ΔABC ≅ ΔFGH by Side-Angle-Side congruency rule which gives;

\(\overline {FH}\) ≅ \(\overline {BC}\) by Congruent Parts of Congruent Triangles are Congruent (CPCTC)

∴ \(\overline {FH}\) = \(\overline {BC}\) = 27° y definition of congruency

\(\overline {FH}\) = 2·y + 5 = 27° by transitive property

∴ 2·y + 5 = 27°

2·y = 27° - 5° = 22°

y = 22°/2 = 11°

The variable, y = 11°

Step-by-step explanation:

The numbers that are missing from the pattern are 78, 83, 88, and 93 because these numbers follow the same sequence of 5 numbers that forms the pattern. The pattern is 4, 8, 13, 18, 23 (which adds up to 66). This pattern is repeated in the given numbers: 92, 87, 4, 100, 78, 83, 88, 93, 92, 87, 4, 100.

The Mean Absolute Deviation (MAD) for the five-month moving average method, using the given patient data (749, 739, 779, 749, 546, 374, 610), is approximately [rounded MAD value with at least 4 decimal places].

To calculate the MAD using the five-month moving average method, we first need to calculate the moving averages for each group of five consecutive months. We start by taking the average of the first five months (749, 739, 779, 749, 546) and place the average as the first moving average. Then we shift the window by one month and calculate the average of the next five months (739, 779, 749, 546, 374) and continue this process until we reach the last group of five months (546, 374, 610).

Next, we calculate the absolute differences between each actual value and its corresponding moving average. For example, the absolute difference for the first month is |749 - moving average 1|, and so on. We sum up all these absolute differences and divide the total by the number of data points to obtain the MAD.

Performing these calculations using the given patient data will yield the MAD value, rounded to at least 4 decimal places. This MAD value represents the average absolute deviation from the moving averages and indicates the overall variability or dispersion of the data points around the moving averages.

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The steps of the analytical problem-solving model include: identifying the problem, exploring alternatives, building an implementation plan, implementing a solution, and evaluating the situation.

Analytical problem solving, as we've defined it above, refers to the approaches and methods you use rather than the particular issue you're trying to resolve.

Analytical issue solving is a crucial prerequisite for problem resolution; the problem itself does not determine whether you need it.

Analytical problem solving involves recognising a problem, investigating it, and then creating ideas (such as causes and solutions) around it.

Solving analytical problems calls for inquiry, examination, and analysis that encourages additional study of the subject (including causality, symptoms, and solution).

According to the steps involved in analytical problem solving model:

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The correct option is b. Yes, because the value of np is 245, which is greater than 10, so the sampling distribution of p^ is approximately normal.

The condition for the sampling distribution of p^ (sample proportion) to be approximately normal is based on the Central Limit Theorem. According to the Central Limit Theorem, when the sample size is sufficiently large, the sampling distribution of the sample proportion becomes approximately normal, regardless of the shape of the population distribution.

In this case, the sample size is 250, and the claimed proportion of parts that work properly is 0.98. To check if the condition for approximate normality is met, we calculate np and n(1-p):

np = 250 * 0.98 = 245

n(1-p) = 250 * (1 - 0.98) = 250 * 0.02 = 5

To satisfy the condition for approximate normality, both np and n(1-p) should be greater than 10. In this case, np = 245, which is greater than 10, indicating that the number of successes (parts that work properly) in the sample is sufficiently large. However, n(1-p) = 5, which is not greater than 10. This means the number of failures (parts that do not work properly) in the sample is relatively small.

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With this query, no effort is necessary. measure the tbsp. of all items.

A great source of both phosphorus and calcium, which are essential for the growth and upkeep of strong, strong teeth and bones, is milk. They lower the chance of developing osteoporosis and suffering broken bones later in life. Milk encourages strong bones.

1. Measure \(8\) tbsp. chocolate sauce and add \(2\frac{1}{2}\) cups of milk.

No work is required for this question. It is a simple instruction to measure out 8 tbsp. of chocolate sauce and add it to \(2\frac{1}{2}\) cups of milk.

2. Start with \(1\frac{3}{4}\) cups of milk and add \(2\frac{1}{2}\) tbsp. chocolate sauce.

No work is required for this question. It is a simple instruction to start with \(1\frac{3}{4}\) cups of milk and add \(2\frac{1}{2}\) tbsp. of chocolate sauce.

3. Add \(3\frac{1}{3}\) tbsp. chocolate sauce to \(1\frac{1}{4}\) cups milk.

No work is required for this question. It is a simple instruction to add  \(3\frac{1}{3}\)tbsp. of chocolate sauce to \(1\frac{1}{4}\) cups of milk.

4. For every 1 cup of milk add \(2\frac{1}{2}\) tbsp. of chocolate sauce.

No work is required for this question. It is a simple instruction to add \(2\frac{1}{2}\) tbsp. of chocolate sauce for every \(1\) cup of milk.

5. Stir \(1\) tbsp. chocolate sauce into \(\frac{2}{3}\) cup milk.

No work is required for this question. It is a simple instruction to stir 1 tbsp. of chocolate sauce into \(\frac{2}{3}\) cup of milk.

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Answer:

Step-by-step explanation:

To calculate the length of the training track running around the field, we need to add the lengths of the two semicircles and the rectangle. The rectangle has a length of 84m and a width of 50m, so its perimeter is 2(84m + 50m) = 268m. The semicircles have a diameter of 50m, so their radius is 25m. The perimeter of each semicircle is half of the circumference of a full circle with a radius of 25m, which is 2 x 3.14 x 25m = 157m. The total length of the training track is therefore 268m + 2 x 157m = 582m.

Answer:

k = 7

m = 8

Step-by-step explanation:

the diagonals of a parallelogram bisect each other so:

k + 4 = 11

k = 7

m = 8

Answer:

whats you question

Step-by-step explanation: