Can someone please help ASAP marking brainliest

Answer:

there are 5 letters in all and 2 c's.. 2/5 2 out of every 5 times

It takes approximately 180.19 hours for the geostationary satellite to travel a distance of 200,000 km.

To determine the time it takes for the geostationary satellite to travel a certain distance, we can set up a proportion using the given information.

The geostationary satellite is positioned 35,800 km above Earth's surface, and it takes 24 hours to complete one orbit. The radius of Earth is approximately 6,400 km.

Let's set up the proportion:

(Orbit Time in hours) / (Orbit Distance in km) = (Time to Travel 200,000 km) / (Distance of 200,000 km)

Using the given information:

24 hours / (2π * (35,800 km + 6,400 km)) = (Time to Travel 200,000 km) / 200,000 km

Simplifying the expression:

24 hours / (2π * 42,200 km) = (Time to Travel 200,000 km) / 200,000 km

To find the time it takes to travel 200,000 km, we can rearrange the proportion:

(Time to Travel 200,000 km) = (24 hours / (2π * 42,200 km)) * 200,000 km

Calculating the expression:

(Time to Travel 200,000 km) = (24 hours * 200,000 km) / (2π * 42,200 km)

(Time to Travel 200,000 km) ≈ 180.19 hours

Therefore, it takes approximately 180.19 hours for the geostationary satellite to travel a distance of 200,000 km.

By setting up a proportion using the given information, we determined that the geostationary satellite takes approximately 180.19 hours to travel a distance of 200,000 km. This calculation was based on the known orbit time of 24 hours and the satellite's position above Earth's surface, along with the radius of Earth.

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The dimensions that yield the box with the largest volume are 5√2 inches by 5√2 inches by 5√2 inches.

To maximize the volume of the box, we need to determine the dimensions that will use up all 100 square inches of material while maximizing the volume of the box. Let the length, width, and height of the box be denoted by x, y, and z, respectively.

From the given information, we know that the surface area of the box is 2(xy + xz + yz) = 100, which simplifies to xy + xz + yz = 50.

The volume of the box is V = xyz, so we need to find the maximum value of V subject to the constraint xy + xz + yz = 50.

We can use Lagrange multipliers to solve this optimization problem. Let

f(x, y, z) = xyz

g(x, y, z) = xy + xz + yz - 50

The Lagrangian function is

L(x, y, z, λ) = f(x, y, z) - λg(x, y, z) = xyz - λ(xy + xz + yz - 50)

Taking partial derivatives with respect to x, y, z, and λ and setting them equal to zero, we get the following system of equations:

yz - λ(y + z) = 0

xz - λ(x + z) = 0

xy - λ(x + y) = 0

xy + xz + yz - 50 = 0

Solving this system of equations yields

x = y = z = 5√2

Therefore, the dimensions that yield the box with the largest volume are 5√2 inches by 5√2 inches by 5√2 inches.

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Answer:

fb=7 units

Step-by-step explanation:

Answer:

If they’re both equal to each other in length and both pentagons, then I think the answer is 7 units.

Answer:

0.45

Step-by-step explanation:

You divided 2.25 by 5

The binary and decimal form of 5613base 10 in base 8​ is  (5613)₁₀ = (12755)₈

While decimal numbers use the 10 digits 0, 1, 2, 3, 4, 5, 6, 7, and 9, octal numbers only use the eight digits 0, 1, 2, 3, 4, and 5.

5613 / 8 = 701, leaving only 5.

8 divided by 701 equals 87, leaving 5 as the remainder.

87 / 8 = 10, leaving a value of 7.

10/8 = 1, leaving 2 as the undetermined number.

1/8 equals 0, hence the final result is 1.

The remaining numbers are put together in reverse order to provide the required Octal number, which is 12755.

Therefore,(5613)₁₀ = (12755)₈

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To solve the time-independent Schrödinger equation for a centered infinite square well with a delta-function barrier in the middle, we'll consider the region between -L/2 to L/2, where L is the width of the well.

The Schrödinger equation for this system is:d^2ψ/dx^2 + (2m/h^2)(E - V(x))ψ = 0 where d^2ψ/dx^2 is the second derivative of the wave function ψ with respect to x, m is the mass of the particle, h is the reduced Planck's constant, E is the energy, and V(x) is the potential function.Inside the well, the potential function is V(x) = 0, and the wave function satisfies:d^2ψ/dx^2 + (2m/h^2)Eψ = 0

The general solution for ψ inside the well is given by:

ψ(x) = A sin(kx) + B cos(kx)where A and B are constants to be determined, and k = √(2mE)/h.

Now, for the region where the delta-function barrier exists, we assume the potential function is V(x) = Aδ(x), where A is a constant and δ(x) is the Dirac delta function. To solve this region, we use the boundary conditions:

Continuity of ψ at x = -L/2 and x = L/2:

ψ(-L/2) = ψ(L/2)

Discontinuity in the derivative of ψ at x = 0:

dψ/dx|(x=0+) - dψ/dx|(x=0-) = (2m/h^2)Aψ(0).By imposing these boundary conditions and solving the resulting equations, we can determine the constants A, B, and the energy E, which correspond to the eigenstates of the system.Please note that the explicit solution depends on the specific form of the potential function and the boundary conditions imposed. If you provide more details or specific values for the potential function or boundary conditions, I can assist you further in solving the Schrödinger equation for the centered infinite square well with a delta-function barrier.

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Answer:

A my dude. good luck!!!!!

Answer:

A

Step-by-step explanation:

AC = 5

DF = 15

5 x 3 = 15

BC = 3

EF = 9

3 x 3 = 9

Do you see the pattern? So as you can see the difference between Triangle ABC and DEF is the multiply/divide 3 so if you want to find DE then you should set it up as:

\(\frac{4}{3}\) = \(\frac{DE}{9}\)  and to check if its right if you solve it you get \(\frac{4}{3}\) = \(\frac{12}{9}\)

and as you see \(\frac{12}{9}\) and \(\frac{4}{3}\) are literally the same thing just you need to simplify \(\frac{12}{9}\)

Answer:

\( { \tt{x + y + 2 = 0}} \\ y = - x - 2 \\ \\ { \tt{x + y - 2 = 0}} \\ y = - x + 2 \\ \\ { \tt{x - y - 2 = 0}} \\ - y = - x + 2 \\ y = x - 2\)

Answer:

4/11, 3, 17/5, 3.421, 3.48

Step-by-step explanation:

4/11 = 0.36363636(repeating)

17/5 = 3.4

4/11 is the smallest given that is is not even 1

3 is smaller than 17/5, an easy way to know that is to simply 17/5 where it equals 3.4

17.5 or 3.4 is slightly smaller than 3.421, it is exactly 0.021 smaller than 3.421

3.421 is smaller than 3.48

least is 4/11 and greatest is 3.48, the in between numbers are all placed correctly in the answer section

Answer:

The answers from least to greatest are 3.36, 3.4, 3.421, 3.48

Step-by-step explanation:

17/5= 3 2/5, 3 2/5 = 3.4

3 4/11 = 3.36

3.421 stays the same

3.48 stays the same

I hope this helps and have a wonderful day!

The probability of the random variable Z being less than -3.10 is obtained using the Standard Normal Distribution table.

a) To find the probability (P(Z < -3.10)) for a standard normal random variable Z, we can use a standard normal distribution table or a calculator.

Using a standard normal distribution table, we look up the value -3.10 and find the corresponding probability. The table typically provides the cumulative probability up to a given value. Since we want (P(Z < -3.10)), we need to find the probability for -3.10 and subtract it from 1.

The probability (P(Z < -3.10)) is approximately 0.000968.

b) To find the probability (P(Z < 1.28)) for a standard normal random variable Z, we can again use a standard normal distribution table or a calculator.

Using a standard normal distribution table, we look up the value 1.28 and find the corresponding probability. This probability represents (P(Z < 1.28)) directly.

The probability (P(Z < 1.28)) is approximately 0.89973.

c) The probability (P(Z > 0)) for a standard normal random variable Z represents the area under the standard normal curve to the right of 0.

Since the standard normal distribution is symmetric around 0, the area to the left of 0 is 0.5. Therefore, the area to the right of 0 is also 0.5.

Hence, (P(Z > 0)) is 0.5.

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Answer:

5

Step-by-step explanation:

angles A and D are congruent, 10 times 5 = 50

Answer:

B

Step-by-step explanation:

if its less than 1 it shrinks

The correct statement is; Pentagon M’N’P’Q’R is smaller than pentagon MNPQR because the scale factor is smaller than 1.

The ratio between comparable measurements of an item and a representation of that thing is known as a scale factor in arithmetic.

If a polygon is dilated by a scale factor = k

Rule to be followed as;

(x, y) → (kx, ky)

Here, k = Scale factor

If 0 < k < 1, size of the image will be reduced.

Similarly, k > 1, size of the image will be enlarged.

We are given that Pentagon MNPQR is dilated with the origin as the center of dilation to form an image M'N'P'Q'R'.

Rule used for the transformation,

(x, y) → (1/4x, 1/4y)

Here, the scale factor through which MNPQR has been dilated is 1/4.

Since, scale factor is between zero and 1/4, size of M'N'P'Q'R' will be reduced.

Therefore, the size of pentagon M'N'P'Q'R' will be 1/4 smaller than pentagon MNPQR.

Option (2) is the answer.

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Answer: 88°

Step-by-step explanation:

We know that the ratio of ∠DCB : ∠ACD is 3:1. In other words, ∠DCB is \(\frac{3}{3+1}\), or \(\frac{3}{4}\) of the whole angle (i.e., ∠ACB), while ∠ACD is \(\frac{1}{4}\) of the whole angle.

To easily find ∠ACB, which is the sum of both angles, we can add up all the angles of \(\triangle ABC\) and set it equal to 180°.

\(m\angle A + m\angle B + m\angle ACB = 180\\75+53+m\angle ACB=180\\128+m\angle ACB=180\\m\angle ACB=52\)

From here, we can calculate ∠BCD by multiplying the value of ∠ACB by three-fourths.

\(m\angle BCD = \frac{3}{4}(m\angle ACB)\\m\angle BCD = \frac{3}{4}(52)\\m\angle BCD = 39\)

Similar to what we did to get the measure of ∠ACB, we can add up all the angles measures of \(\triangle DBC\) to get the measure of ∠BDC.

\(m\angle B + m\angle BDC + m\angle BCD = 180\\53+m\angle BDC + 39= 180\\92+ m\angle BDC=180\\m\angle BDC = 88\)

The measure of ∠BDC is 88°.

The mass of the decoration is 200 kg and for each passenger car is 550 kg

From the question, we have the following parameters that can be used in our computation:

These can be represented as

(6, 3500) and (4, 2400)

The slope of the above points represent the mass of each passenger car

This is calculated as

Slope = Difference in mass/Difference in number of cars

So, we have

Slope = (3500 - 2400)/(6 - 4)

Evaluate

Slope = 550

When there are no passenger cars in the train, we have

(0, Mass of decoration)

Using the slope formula, we have

Slope = (Mass of decoration - 3500)/(0 - 6)

So, we have

Slope = (Mass of decoration - 3500)/(-6)

This gives

(Mass of decoration - 3500)/(-6) = 550

Cross multiply

Mass of decoration - 3500 = -3300

Add 3500 to both sides

Mass of decoration = 200

Hence, the mass of decoration is 200 kg

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Answer: (below)

Step-by-step explanation:

1) n/6 + 6 = -3

2) 2n + 5 = 27

3) n/2 - 10 = 5

Answer:

38

Step-by-step explanation:

Substitute values for x,y,z into the equation:

2(8-1+3+1(8+1))

Simplify:

2(19)

Solve:

38

The score needed on the final exam to achieve a C grade is 79.33, rounded to 2 decimal places.

Homework is worth 30% of the grade, which is also a significant portion. The average homework score is 90, which means the average of all homework scores is 90.

Test reviews are only worth 5% of the grade, so they have the smallest impact on the overall average. The average test review score is 72, which means the average of all test review scores is 72.

Finally, the final exam is worth 15% of the grade, and we need to find out what score is needed on the final exam to achieve a C grade, which is 72%.

To calculate the overall average, we can use the weighted average formula.

Overall Average = (Tests Average x 0.5) + (Homework Average x 0.3) + (Test Reviews Average x 0.05) + (Final Exam Score x 0.15)

Substituting the values we know, we get:

Overall Average = (59 x 0.5) + (90 x 0.3) + (72 x 0.05) + (Final Exam Score x 0.15)

Simplifying this equation, we get:

Overall Average = 29.5 + 27 + 3.6 + (Final Exam Score x 0.15)

Overall Average = 60.1 + (Final Exam Score x 0.15)

To get a C grade, the overall average needs to be 72%. So we can set up an equation and solve for the Final Exam Score:

72 = 60.1 + (Final Exam Score x 0.15)

Solving for Final Exam Score, we get:

Final Exam Score = (72 - 60.1) / 0.15

Final Exam Score = 79.33

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Answer:

2

Step-by-step explanation:

2

Answer: A

Step-by-step explanation:

In a chi-square test for independence, the null hypothesis is that the two variables are independent in the population.

The null hypothesis states that there is no association or relationship between the two variables being tested. This means that any observed relationship in the sample data is due to chance and not a true relationship in the population. the null hypothesis assumes that there is no difference in the distribution of the variables across the categories or levels being compared.

To test this hypothesis, we calculate the chi-square statistic, which measures the difference between the observed and expected frequencies. If the calculated chi-square value is large enough to reject the null hypothesis, we conclude that there is evidence of a relationship between the variables. In summary, the null hypothesis in a chi-square test for independence is that the two variables being tested are independent in the population. This implies that there is no relationship or association between them.

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Answer:

y= -2x+1

Step-by-step explanation:

i hope this helps :)

Option a. The car is 115.47 feet from the building is correct for the given right triangle.

A trigonometric formula known as the rule of sines connects any triangle's sides and angles. It claims that for all three sides of a triangle, the ratio of the length of one side to the sine of the angle opposite that side is the same. In other words, if a triangle has angles A, B, and C opposing its sides and sides a, b, and c, then:

If a/sin(A) = b/sin(B) = c/sin(C), then

If some of the other sides and angles of a triangle are known, this formula can be used to solve for those unknown sides or angles. However, it is restricted to triangles and calls for the measurement of at least one angle and one side's length.

The situation can be depicted as a right triangle, with building 200 feet, the angle of depression is 30 degrees.

Now,

tan(30) = opposite/adjacent = 200/distance

distance = 200/tan(30) ≈ 115.47 feet

Hence, option a. The car is 115.47 feet from the building is correct for the given right triangle.

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a) To determine the speed at which the large truck is approaching the stopped bus, we need to find the derivative of the distance function with respect to time.

1. Taking the derivative of d(t) with respect to t, we have:

d'(t) = d(t) / dt = (1/2) * (0.22 + (1.2 - 100t)^2)^(-1/2) * (-2) * (1.2 - 100t) * (-100)

2. Simplifying this expression, we get: d'(t) = 100 * (1.2 - 100t) / √(0.22 + (1.2 - 100t)^2)

3. Substituting the given values (t = 0), we can calculate the speed at which the truck is approaching the bus:

d'(0) = 100 * (1.2 - 100 * 0) / √(0.22 + (1.2 - 100 * 0)^2)

     = 100 * 1.2 / √(0.22 + 1.2^2)

     ≈ 100 * 1.2 / √(0.22 + 1.44)

     ≈ 100 * 1.2 / √1.66

     ≈ 100 * 1.2 / 1.288

     ≈ 93.17 km/h

Therefore, the speed at which the large truck is approaching the stopped bus is approximately 93.17 km/h.

b) To determine when the truck stops approaching the bus, we need to find the time at which the derivative of the distance function becomes zero.

1. Setting d'(t) = 0, we can solve for t: 100 * (1.2 - 100t) / √(0.22 + (1.2 - 100t)^2) = 0

Simplifying the equation, we have: 1.2 - 100t = 0

2.Since time is measured in hours, we convert this to minutes:

0.012 hours * 60 minutes/hour = 0.72 minutes

Therefore, the truck will stop approaching the bus after approximately 0.72 minutes.

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The equation of the path of the parabola is y = a(x - 13)² + 27

Given data ,

To represent the path of Al's toss, we can assume that the path is a parabolic trajectory.

The equation of a parabola in vertex form is given by:

y = a(x - h)² + k

where (h, k) represents the vertex of the parabola

Now , the balloon was released from the 10-yard line and landed at the 16-yard line, we can determine the x-values for the vertex of the parabola.

The x-coordinate of the vertex is the average of the two x-values (10 and 16) where the balloon was released and landed:

h = (10 + 16) / 2 = 13

Since the height of the balloon reached 27 yards, we have the vertex point (13, 27)

Now, let's substitute the vertex coordinates (h, k) into the general equation:

y = a(x - 13)² + k

Substituting the vertex coordinates (13, 27)

y = a(x - 13)² + 27

To determine the value of 'a', we need another point on the parabolic path. Let's assume that the highest point reached by the balloon is the vertex (13, 27).

This means that the highest point (13, 27) lies on the parabola

Substituting the vertex coordinates (13, 27) into the equation

27 = a(13 - 13)² + 27

27 = a(0) + 27

27 = 27

Hence , the equation representing the path of Al's toss is y = a(x - 13)² + 27, where 'a' can be any real number

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For the curve \(x^{2} +xy+y^{2} = 27\) , the line tangents to the curve at the x intercepts of the curve are parallel .

The Slope of tangent line to a function at any point is denoted by \(\frac{dy}{dx}\) .

The Curve is given as ⇒\(x^{2} +xy+y^{2} = 27\) ;

On differentiating both sides of the curve with respect to "x"  ,

we get ;

the slope of the line as ⇒ \(Slope = \frac{dy}{dx} = -\frac{2x+y}{x+2y}\) ;

Now for the  x- intercepts , the value \(y = 0 ,\)

On substituting \(y=0\) in the curve \(x^{2} +xy+y^{2} = 27\) ,

we get ;

\(x^{2} +x(0)+0^{2} =27\)

On simplifying further ,

we get ;

\(x=\pm 3\sqrt{3}\) ;

So , the two x intercepts of the curve are \((3\sqrt{3},0)\) and \((-3\sqrt{3},0)\) ;

to find the slopes , we substitute the values in the slope equation .

On substituting the values in the slope equation ,

we get ;

\(Slope_{(3\sqrt{3} ,0)} = -\frac{2(3\sqrt{3}) +9}{3\sqrt{3} +2(0)}\) = \(-2\)  and

\(Slope_{(-3\sqrt{3} ,0)} = -\frac{2(-3\sqrt{3}) +9}{-3\sqrt{3} +2(0)}\) = \(-2\).

we see that the slope at both the intercepts is same ,

Therefore , the lines tangents of the curve at the x intercepts are parallel .

The given question is incomplete , the complete question is

Consider the curve defined by \(x^{2} +xy+y^{2} = 27\) . Determine whether the lines tangent to the curve at the x - intercept of the curve are parallel .

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Answer:

1. Clear parentheses on both sides of the inequality and collect like terms.

2. Add or subtract terms so the variable is on one side and the constant is on the other side of the inequality sign.

3. Multiply and divide by whatever constants are attached to the variable.

Step-by-step explanation:

Hope this helps    :)

Rhian scored more in the Math test than in the English test because she had a higher percentage

An equation is an expression that shows the relationship between two or more numbers and variables.

Given that: In the Maths test, Rhian scored 14 out of 17, hence:

Mark percentage = (14 / 17) * 100% = 82.35%

In the English test, Rhian scored 31 out of 39, hence:

Mark percentage = (31 / 39) * 100% = 79.49%

Rhian scored more in the Math test.

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do you know where is India

becz I am an Indian

Answer:

2,49/4,10/9

Step-by-step explanation:

\(1.\sqrt{4} =2\\2.\sqrt{x} =3+\frac{1}{2} =\frac{7}{2} \\x=\frac{49}{4} \\3.\sqrt{x} =3+\frac{1}{3} =\frac{10}{3} \\x=\frac{100}{9}\)

1. The set of sophomores at your school who are not taking discrete mathematics: A ∩ Bᶜ.
2. The set of sophomores taking discrete mathematics in your school: A ∩ B.
3. The set of students at your school who either are sophomores or are taking discrete mathematics: A ∪ B.
4. The set of students at your school who either are not sophomores or are not taking discrete mathematics: Aᶜ ∪ Bᶜ.

1. The set of sophomores at your school who are not taking discrete mathematics can be represented symbolically as A - B. This means that we take all the elements in set A (sophomores) and subtract the elements in set B (students taking discrete mathematics) from it, which gives us the set of sophomores who are not taking discrete mathematics.

2. The set of sophomores taking discrete mathematics in your school can be represented symbolically as A ∩ B. This means that we take the intersection of sets A and B, which gives us the set of students who belong to both sets A and B. In this case, it gives us the set of sophomores taking discrete mathematics.

3. The set of students at your school who either are sophomores or are taking discrete mathematics can be represented symbolically as A ∪ B. This means that we take the union of sets A and B, which gives us the set of all students who belong to either set A or set B (or both). In this case, it gives us the set of all sophomores and all students taking discrete mathematics.

4. The set of students at your school who either are not sophomores or are not taking discrete mathematics can be represented symbolically as U - (A ∩ B). This means that we take the complement of the intersection of sets A and B from the universal set U. In other words, we take all the elements in the universal set U and subtract the elements that belong to both sets A and B, which gives us the set of all students who either are not sophomores or are not taking discrete mathematics.

1. The set of sophomores at your school who are not taking discrete mathematics: A ∩ Bᶜ. This represents the intersection of set A (sophomores) and the complement of set B (students not in discrete mathematics).

2. The set of sophomores taking discrete mathematics in your school: A ∩ B. This represents the intersection of set A (sophomores) and set B (students in discrete mathematics).

3. The set of students at your school who either are sophomores or are taking discrete mathematics: A ∪ B. This represents the union of set A (sophomores) and set B (students in discrete mathematics).

4. The set of students at your school who either are not sophomores or are not taking discrete mathematics: Aᶜ ∪ Bᶜ. This represents the union of the complement of set A (students not in the sophomore class) and the complement of set B (students not in discrete mathematics).

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