can someone help me !!!

Answer: does this help you?

Step-by-step explanation:

Answer:

928/65

Step-by-step explanation:

They played 16 games each summer. 16 divided by 3.25 is 32/65. 29 runs is 928/65. Sorry I couldn't help you with much.

It might be wrong.

The width of the rectangular walkway is 3 feet around.

The walkway has a uniform width around the rectangle.

Let the width of walkway be x

The total length of the garden and walkway will be (12+2x) feet

The total width of the walkway and garden would be (8+2x) feet

Area of the garden and the walkway together are 252 square

Let’s express this mathematically:

(8+2x)(12+2x) = 252

Let’s open the brackets;

96+ 16x+ 24x + 4x^2 = 252

4x^2 + 40x + 96 = 252

4x^2 + 40x + 96-252 = 0

4x^2 + 40x - 156 = 0

Let’s divide all through by 10. We have;

x^2 + 10x -39 = 0

X^2 +13x-3x-39 = 0

x(x + 13) -3(x+ 13) = 0

(x-3)(x + 13) = 0

x -3 = 0 or x + 13 = 0

x = 3 or -13

We ignore x = -13 since width cannot be negative in size

Therefore, the width of the rectangular walkway is 3 feet around.

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Answer:

338

Step-by-step explanation:

X - 115  = 223

Add 115 to both the sides

X - 115 + 115 = 223 + 115

x = 338

Answer:

338

Step-by-step explanation:

x - 115 =223

Collect terms

x = 223 + 115

x = 338

Hope this helps you!

pls mark as brainlest ans

Bye!

Step-by-step explanation:

6/2*(2+1)

6/2*3

18/2

9ans..

Answer:

74 wheels

Step-by-step explanation:

there would be 74 wheels because 13 * 2 + 12 * 4 = 74

Answer:

t=7

Step-by-step explanation:

Collect like terms

7t+7t=102-4

14t=98

t = 98/14

t=7

Answer:

t = 7

Step-by-step explanation:

Equation

7t + 4 = 102 - 7t

Solution

7t + 4 = 102 - 7t                       Add 7t to both sides

7t + 7t +4 = 102 - 7t  + 7t         Combine

14t + 4 = 102                            Subtract 4 from both sides

14t + 4 - 4 = 102 - 4

14t =98                                Divide by 14

14t / 14 =98/14

t =7

Hence, The correct answers in the boxes. she used 124.6 centimeters of string in all.

Given that Iris made 7 bracelets and used x centimeters of string. And, she used 17.8 centimeters of string for each bracelet.Now, let us write an equation to solve this problem.Let us assume that the total length of string used by Iris = y centimetersTherefore, the equation is:y = 7 × 17.8

We know that Iris made 7 bracelets. And she used 17.8 centimeters of string for each bracelet.

Therefore, total length of string used by Iris = 7 × 17.8 = 124.6 cm

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Answer:

1+1???????? 1+1=2. :/

Answer:

N = {13,15,17,19} the answer 21 tho

Step-by-step explanation:

The natural numbers greater than 11 and less than 21 are 12 ,13,14,15,16,17,18,19 and 20

Answer:

\( \frac{5}{2} = 2.5 \\ \frac{1}{4} = 0.25 \\ \frac{1}{2} = 0.5 \\ \frac{8}{10} = 0.8 \\ 0.25 < 0.5 < 0.8 < 2.5\)

A better method to determine the more popular sport is by conducting a comprehensive, unbiased survey with a random sample

a. Concluding that baseball is more popular than soccer based on a poll at a championship event is not valid due to potential sample bias, self-selection bias, limited sample size, and question phrasing.

b. A better method to determine the more popular sport is by conducting a comprehensive, unbiased survey with a random sample of students in a neutral setting, using clear and unbiased questions that allow for all preferences

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Answer:

\(y=3\cos(\frac{8}{7}x)+2\)

Step-by-step explanation:

Recall

We are given that the amplitude is \(a=3\) and that the equation of the midline is \(d=2\). Since we know the period to be \(\frac{7\pi}{4}\), we need to solve for \(b\) by setting up the equation \(\frac{7\pi}{4}=\frac{2\pi}{|b|}\):

\(\frac{7\pi}{4}=\frac{2\pi}{|b|}\\\\7\pi b=8\pi\\\\b=\frac{8}{7}\)

Hence, our cosine function will be \(y=3\cos(\frac{8}{7}x)+2\). See the attached graph for a visual.

The scale factor was used for each dilation are-

A transformation that changes the size of a figure is called a dilatation. This indicates that the preimage as well as image are similar and have been scaled up or down, respectively.

A dilatation that results in a reduction (imagine shrinking) or an enlargement (think stretching) produces a smaller or larger image, respectively.

Part a: For ΔABC

Length AB = 2 units

Length A'B' = 4 units

A'B' = 2 *AB

Thus,  For ΔABC - scale factor = 2

Part b: For ΔDEF -

Length DF = 2 units

Length D'F' = 1  units

D'F' = 1/2 DF

Thus, For ΔDEF - scale factor = 1/2

Part c: For ΔGHJ -

Length GH = 3 units

Length G'H' = 1  units

G'H' = 1/3 GH

Thus,  For ΔGHJ - scale factor = 1/3

Part d: For ΔKML -

Length KM = 2 units

Length K'M' = 6  units

K'M' = 3*KM

Thus, For ΔKML - scale factor = 3

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ANSWER

1/6 or 0.167 inches per minute

EXPLANATION

We want to find the constant rate of change of the water level.

To do this, we have to find the difference in water level, find the time taken, then divide the former by the latter.

Difference in water level is:

D = 28 - 13 = 15 inches

The time difference is:

H M

2 : 30

- 1 : 00

1 : 30

That is 1 hour 30 minutes.

In minutes, that is:

(60 * 1) + 30 = 60 + 30 = 90 mins

So, the constant rate of change of water level is:

That is the constant rate of change of water level.

Answer:

We need 1600 squares with a width of 6 feet to cover the entire field without any gaps nor overhangs.

Step-by-step explanation:

The number of squares required to cover the field is equal to the area of the field divided by the area of a square:

\(n = \frac{A}{l^{2}}\) (1)

Where:

\(n\) - Quantity of squares, in feet.

\(A\) - Area of the field, in square feet.

\(l\) - Length of each square, in feet.

If we know that \(A = 57600\,ft^{2}\), then we have the following hyperbolic function:

\(n = \frac{57600}{l^{2}}\)

Now we plot the function with the help of graphing tools, whose result is presented below. Please notice that quantity of squares must be an integer and we need 1600 squares with a width of 6 feet to cover the entire field without any gaps nor overhangs.

d) about 39.07% of the chicks weigh between 196 and 317.

To answer these questions, we can use the provided five-number summary and apply the concepts of quartiles and percentiles.

a. To find the percentage of chicks weighing more than 196, we need to calculate the percentage above the first quartile (Q1). The first quartile (Q1) represents the 25th percentile, meaning 25% of the chicks weigh less than or equal to Q1.

The percentage of chicks weighing more than 196 is therefore:

100% - 25% = 75%

Therefore, about 75% of the chicks weigh more than 196.

b. Similarly, to find the percentage of chicks weighing more than 263, we need to calculate the percentage above the median. The median represents the 50th percentile, so 50% of the chicks weigh less than or equal to the median.

The percentage of chicks weighing more than 263 is:

100% - 50% = 50%

Therefore, about 50% of the chicks weigh more than 263.

c. To find the percentage of chicks weighing more than 317, we need to calculate the percentage above the third quartile (Q3). The third quartile (Q3) represents the 75th percentile, meaning 75% of the chicks weigh less than or equal to Q3.

The percentage of chicks weighing more than 317 is:

100% - 75% = 25%

Therefore, about 25% of the chicks weigh more than 317.

d. To find the percentage of chicks weighing between 196 and 317, we need to calculate the percentage between the first quartile (Q1) and the third quartile (Q3). The difference between the first quartile and the third quartile represents the interquartile range (IQR).

The percentage of chicks weighing between 196 and 317 is the percentage within the IQR:

Q3 - Q1 = 315 - 197 = 118

Percentage within the IQR = (118 / (Max - Min)) * 100

                           = (118 / (410 - 108)) * 100

                           = (118 / 302) * 100

                           ≈ 39.07%

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The value of  integral sin (x^2+y^2)dA is 2π(cos(9) - cos(64)).

To evaluate this integral using polar coordinates, we first need to express the region R in terms of polar coordinates. In polar coordinates, the equation of a circle with radius r is given by r^2 = x^2 + y^2. So, the region R can be expressed as 3 < or = r < or = 8.

Now, we can express the integral in polar coordinates:

∫∫R sin (x^2+y^2)dA = ∫θ=0 to 2π ∫r=3 to 8 sin (r^2) r dr dθ

We integrate first with respect to r, then with respect to θ:

∫θ=0 to 2π ∫r=3 to 8 sin (r^2) r dr dθ

= ∫θ=0 to 2π [-cos(64) + cos(9)] dθ

= 2π(cos(9) - cos(64))

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Answer:

say how can I help you bro

Answer:

\(x\leq -2\)

Step-by-step explanation:

Solve for x:

\(-4x+20\geq 28\)

Subtract 20 on both sides

\(-4x\geq 8\)

Flip the sign and multiply both sides by -4

\(16x\leq -32\)

Divide by 16

\(x\leq -2\)

Answer:

81.6

Step-by-step explanation:

divide 136 by 5 when you get the answer to that you multiply by 3 and that's your answer

Answer:

81.6

Step-by-step explanation:

Divide than multiply

Answer:

Step-by-step expla

The statistical technique that combines results of a large number of studies is called meta-analysis.

It means that you will take data from various sources, such as studies, combine them together, and then create this mixture of various results that you can use in your own research. If something occurs often in those studies, it means that it is good and reliable information.

Answer:

To the lump sum needed to be invested to receive $10,000 in 10 years at 6.6% interest compounded daily, we can use the present value formula:

PV = FV / (1 + r/n)^(n*t)

where PV is the present value or the initial investment, FV is the future value or the amount we want to end up with, r is the annual interest rate in decimal form, n is the number of times the interest is compounded per year, and t is the time in years.

Plugging in the numbers, we get:

PV = 10000 / (1 + 0.066/365)^(365*10)

= 4874.49

Therefore, the lump sum needed to be invested is about $4,874.49.

(a) The graph of f(x) is increasing on the intervals (-∞, 0) and (2, ∞), and decreasing on the interval (0, 2).

(b) The local maximum occurs at x = 0 and the local minimum occurs at x = 2.

(c) The graph of f(x) is concave up on the interval (1, ∞) and concave down on the interval (-∞, 1).

(d) The point of inflection occurs at x = 1.

(a) To find the intervals on which the graph of f(x) is increasing or decreasing, we need to analyze the sign of the derivative of f(x).

Step 1: Find the derivative of f(x).

f'(x) = d/dx(x³ - 3x²) = 3x² - 6x

Step 2: Set the derivative equal to zero and solve for x to find critical points.

3x² - 6x = 0

Factor out common terms:

3x(x - 2) = 0

This gives two critical points: x = 0 and x = 2.

Step 3: Determine the sign of the derivative in different intervals.

We choose test points within each interval and evaluate the derivative at those points.

Test x = -1:

f'(-1) = 3(-1)² - 6(-1) = 3 + 6 = 9 (positive)

Test x = 1:

f'(1) = 3(1)² - 6(1) = 3 - 6 = -3 (negative)

Test x = 3:

f'(3) = 3(3)² - 6(3) = 27 - 18 = 9 (positive)

Based on these results, we can determine the intervals of increasing and decreasing.

Intervals of increasing: (-∞, 0) and (2, ∞)

Intervals of decreasing: (0, 2)

(b) Local extrema occur at the critical points of the function. From part (a), we found the critical points x = 0 and x = 2.

To determine if these critical points are local extrema, we can analyze the sign of the derivative around these points.

For x = 0:

f'(-1) = 9 (positive) to the left of 0

f'(1) = -3 (negative) to the right of 0

Since the derivative changes sign from positive to negative, x = 0 is a local maximum.

For x = 2:

f'(1) = -3 (negative) to the left of 2

f'(3) = 9 (positive) to the right of 2

Since the derivative changes sign from negative to positive, x = 2 is a local minimum.

(c) To find the intervals of concavity for the graph of f(x), we need to analyze the sign of the second derivative, f''(x).

Step 1: Find the second derivative of f(x).

f''(x) = d/dx(3x² - 6x) = 6x - 6

Step 2: Set the second derivative equal to zero and solve for x to find any inflection points.

6x - 6 = 0

6x = 6

x = 1

Step 3: Determine the sign of the second derivative in different intervals.

Test x = 0:

f''(0) = 6(0) - 6 = -6 (negative)

Test x = 2:

f''(2) = 6(2) - 6 = 6 (positive)

Based on these results, we can determine the intervals of concavity.

Intervals of concave up: (1, ∞)

Intervals of concave down: (-∞, 1)

(d) The point of inflection occurs at x = 1 since the second derivative changes sign from negative to positive at that point.

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Answer:

D is the answer

Step-by-step explanation:

EDGE 2020