CAN SOMEONE HELP I WILL GIVE BRAINLIST PLEASE!

CAN SOMEONE HELP I WILL GIVE BRAINLIST PLEASE!

Answers

Answer 1

Answer:

water, wind, ice, gravity

Explanation:


Related Questions

Express the dosage using the ratio format you prefer. (Use mg for milligrams and mL for an injectable solution that contains 250mg in each 0.6 mL 3. [-/3 Points] CURRENMEDMATH11 12.3.002. EP. Consider the following. A 40mg in 2.5 mL solution will be used to prepare a 26mg dosage. Calculate the dosage using ratio and proportion. Express your final answer in mL to the
40mg
mL

=
X mL
26mg


40x
X


=
=


mL

[-/1 Points] CURRENMEDMATH11 12.3.004. Calculate the dosage (in milliliters). Express your answer to the nearest tenth. Assess y A 36mg per 2 mL strength solution is used to prepare 22mg. mL

Answers

The dosage of 26mg can be prepared using approximately 1.625 mL of the 40mg in 2.5 mL solution.

The dosage of 22mg can be prepared using approximately 1.222 mL of the 36mg per 2 mL strength solution.

To calculate the dosage using ratio and proportion, we can set up a proportion based on the strength of the solution.

40mg in 2.5 mL solution will be used to prepare a 26mg dosage.

Let X represent the mL of the solution needed to prepare the 26mg dosage.

We can set up the proportion as follows:

40mg/2.5mL = 26mg/X mL

Cross-multiplying and solving for X, we have:

40mg * X mL = 2.5mL * 26mg

40X = 65

X = 65/40

X ≈ 1.625 mL

For the second question:

36mg per 2 mL strength solution is used to prepare 22mg.

Let Y represent the mL of the solution needed to prepare the 22mg dosage.

We can set up the proportion as follows:

36mg/2mL = 22mg/Y mL

Cross-multiplying and solving for Y, we have:

36mg * Y mL = 2mL * 22mg

36Y = 44

Y = 44/36

Y ≈ 1.222 mL

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The supports a variety of ecosystems and organisms, shapes, landforms , and influences climate

Answers

the supports are for the influences climate of the ecosystem

define the ecosystem ?

This article discusses the ecosystem and its various components. An ecosystem is a community or collection of living and nonliving creatures and their interactions with one another. They can be both natural and manufactured. Every ecosystem is made up of two parts: biotic components and abiotic components. Biotic components are all live species in an ecosystem, whereas abiotic components are non-living substances. These biotic and abiotic interactions keep the ecosystem in balance. Let's go through the ecosystem's components in depth.

An ecosystem is a geographical region in which plants, animals, and other species, as well as weather and scenery, coexist to produce a living bubble.

the supports are for the influences climate of the ecosystem

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8. Convert 161 millimeters into meters.

Answers

There are 1000 millimeters in a meter. To convert 161 millimeters to meters, we need to divide by 1000:

161 millimeters ÷ 1000 = 0.161 meters

Therefore, 161 millimeters is equal to 0.161 meters.

why was it important to ensure that the solute was completely dissolved in the cyclohexane before freezing the solution

Answers

It important to ensure that the solute was completely dissolved in the cyclohexane before freezing the solution because it affects the freezing point of the solution.

When a solute dissolves in a solvent, it reduces the solvent's freezing point, which implies the solution must be chilled to a lower temperature than the pure solvent in order to freeze. This is referred to as freezing point depression.

If the solute is not entirely dissolved in the solvent, the resultant solution may have a non-uniform composition, with greater concentrations of solute in certain places than in others. This might cause the freezing point of the solution to be lower than predicted, as well as the production of crystals or other solid particles, which can interfere with the experiment's accuracy.

Furthermore, if the solute is not entirely dissolved, the resultant solution may not be homogenous, and its characteristics may differ from one section of the sample to the next. This might result in inconsistencies and inaccuracies in the experiment.

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How many molecules is 6.11 moles of Zn?

Answers

The answer is 0.015295197308045

We assume you are converting between moles Zinc and gram. You can view more details on each measurement unit: molecular weight of Zinc or grams The molecular formula for Zinc is Zn

Find the unit rate for 306 mines in 10 hours
0.03 miles/hour
30.6 miles/hour
306 miles/hour
3,060 miles/hour

Answers

30.6 miles/hour. You just divide 306 by 10. hope this helps!

Autumn is a pet sitter who has been hired to watch Bailey, a shaggy border collie. Bailey’s owners tell Autumn that she does have epilepsy and even though she takes medication, Autumn might need to be prepared in case something happens. What kind of symptom would Autumn need to be looking out for? a.seizures b.twisting of the stomach c.excessive scratching d. Drooling

Answers

Autumn needs to look out for seizures in Bailey, the shaggy border collie, as it has been informed by Bailey's owners that Bailey has epilepsy and may require medication.

What is Seizures?

Seizures, also known as convulsions or fits, are sudden, abnormal, and excessive electrical discharges in the brain that can cause changes in behavior, sensation, and consciousness. Seizures can affect people of all ages and can occur due to various factors, such as genetic predisposition, brain injury, infections, metabolic disorders, drug and alcohol abuse, and withdrawal from certain medications.

Seizures are a common symptom of epilepsy, which is a neurological disorder that can cause abnormal electrical activity in the brain leading to seizures. During seizures, dogs may experience sudden and uncontrolled convulsions, loss of consciousness, and involuntary movements of limbs. Therefore, it is important for Autumn to be aware of these symptoms and take appropriate measures to ensure Bailey's safety and well-being.

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which of the following would be the least concentrated solution? group of answer choices 60.0 ml of a 7.6 m ch3oh diluted to 300. ml 230. g of ch3oh in 400. ml of solution 400 g of ch3oh in water to make 2kg of solution 6 mol of ch3oh in 6 l of solution

Answers

The least concentrated solution is 60.0 ml of 7.6 M \($\mathrm{CH_3OH}$\) diluted to 300 ml with a concentration of 1.52 M.

The least concentrated solution would be the one with the lowest amount of solute per unit volume of solution.

a) 60.0 ml of a 7.6 M \($\mathrm{CH_3OH}$\) diluted to 300 ml:

To calculate the concentration after dilution, we can use the formula \($C_1V_1$\)= \($C_2V_2$\), where \(C_1\) is the initial concentration, \(V_1\) is the initial volume, \(C_2\) is the final concentration, and \(V_2\) is the final volume.

\($C_1V_1$\) = \($C_2V_2$\)

(7.6 M) (60.0 ml) = \(C_2\) (300 ml)

\(C_2\) = 1.52 M

So, the final concentration is 1.52 M.

b) 230 g of \($\mathrm{CH_3OH}$\) in 400 ml of solution:

To calculate the concentration, we need to know the density of the solution, which is not given.

c) 400 g of \($\mathrm{CH_3OH}$\) in water to make 2 kg of solution:

First, we need to convert the mass of \($\mathrm{CH_3OH}$\) to moles:

400 g \($\mathrm{CH_3OH}$\) × (1 mol \($\mathrm{CH_3OH}$\)/32.04 g \($\mathrm{CH_3OH}$\)) = 12.5 mol \($\mathrm{CH_3OH}$\)

The total volume of the solution is 2 kg = 2000 ml.

Concentration = 12.5 mol / 2000 ml = 0.00625 M

d) 6 mol of \($\mathrm{CH_3OH}$\) in 6 L of solution:

Concentration = 6 mol / 6 L = 1 M

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Complete question:

Which of the following would be the least concentrated solution? Group of answer choices

a) 60.0 ml of a 7.6 M \($\mathrm{CH_3OH}$\) diluted to 300 ml

b) 230 g of \($\mathrm{CH_3OH}$\) in 400 ml of solution

c) 400 g of \($\mathrm{CH_3OH}$\) in water to make 2 kg of solution

d) 6 mol of \($\mathrm{CH_3OH}$\) in 6 L of solution

An atom of sodium-23 (Na-23) has a net charge of +1. Identify the number of protons, neutrons, and electrons in the atom.

Answers

Answer:

Explanation: Sodium has an atomic number of 11, so it has 11 protons. The atomic mass is 23, so there are 23 − 11 = 12 neutrons. The charge is +1, so there is 1 more proton than electrons, so there are 10 electrons

Explanation:

Energy and Matter Imagine a pool ball that bounces off of a bumper and slowly comes to a halt. Explain what happened at each point in terms of applied forces and energy transfers. ​

Answers

Answer:

The kinetic energy is transferred from the ball to the bumper. The bumper gives the same energy back and the ball eventually stopped due to friction of the ground.

Explanation:

Hope this y'all <3

When the ball hits/bounces off  the bumper kinetic energy is transferred between the bumper and the ball, while the slowing down is caused by surface friction ( applied force )

In the scenerio explained in the question there is an applied force between the surface and the pool ball, and an energy transfer occurring between the pool ball and the bumper.

When the pool ball hits the bumper;  Kinetic energy is transferred from the pool ball to the bumper When the pool ball bounces off the bumper: The Kinetic energy absorbed by the bumper is transferred from the bumper back pool ball.When the ball comes to a halt : The applied force ( frictional force ) between the ball and the surface causes the ball to come to a halt.

hence the applied force that cause the ball to come to a halt is friction while the energy transferred is Kinetic energy ( between the ball and bumper )

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Energy and Matter Imagine a pool ball that bounces off of a bumper and slowly comes to a halt. Explain

What happens to the hydrogen and oxygen molecules when they rearrange to from water.something must be recombined.How does this happen?

Answers

When the preexisting molecular links are broken and new bonds are created between oxygen and hydrogen atoms, hydrogen molecules react strongly with oxygen molecules.

The outcome is an explosive release of energy and the formation of water since the reaction's products are at a lower energy level than its reactants.

What kind of response takes place when water is created?

The most well-known instance of a synthesis reaction is the burning of hydrogen and oxygen to produce water.

What causes water to form?

Most of the water that was created was in the form of vapors, which mixed with cosmic dust on the way to the earth's surface. These water vapors condensed into oceans, seas, rivers, and lakes when the world first came into existence.

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Calculate the heat that must be supplied to
a 532 , stainless steel vessel containing 375 g
of water to raise its temperature from 35 C
to the boiling point of water 100°C. Cs. =0.51 J/g. degrees C
Answer in units of J.

Also what percentage of the heat is used to raise the temperature of the water?

Answers

Answer:

Q must be supplied = 119523.3~J

Explanation:

The law of conservation of energy can be applied to heat changes, i.e. the heat received/absorbed is the same as the heat released  

Q in = Q out  

Heat can be calculated using the formula:  

Q = mc∆T  

Q = heat, J  

m = mass, g  

c = specific heat, joules / g ° C  

∆T = temperature difference, ° C / K  

So from the question :

Q to the system(Q supplied) = Q water + Q steel vessel(Q gained)

Describe the changes to the coastline pictured above. Look particularly at North and South Monomy Island.

Answers

             Where is the picture?                                                                         

How many significant figures are in 20600?

Answers

There are 3 significant figures in 20600.

PLEASE HELP DUE TOMORROW!!!

PLEASE HELP DUE TOMORROW!!!

Answers

1. The new volume of the gas will be 58 L

2. The new volume will be 105.65 mL

3. The new temperature will be -15.49 °C

4. The final pressure will be 28.48 KPa

1. How do I determine the new volume of the gas?

The new volume of the gas can be obtained by using Charles' law equation as follow:

Initial temperature (T₁) = 265 KInitial volume (V₁) = 24 LNew temperature (T₂) = 642 KPressure = ConstantNew volume (V₂) =?

V₁ / T₁ = V₂ / T₂

24 / 265 = V₂ / 642

Cross multiply

265 × V₂ = 24 × 642

Divide both side by 265

V₂ = (24 × 642) / 265

New volume (V₂) = 58 L

2. How do I determine the new volume of the gas?

The following data were obtained from the question

Initial volume (V₁) = 250 mLInitial pressure (P₁) = 0.5 atmInitial temperature (T₁) = 50 °C = 50 + 273 = 323 KNew temperature (T₂) = 0 °C = 0 + 273 = 273 KNew pressure (P₂) = 1 atmNew volume (V₂) = ?

The new volume can be obtained by using the combined gas equation as follow:

P₁V₁ / T₁ = P₂V₂ / T₂

(0.5 × 250) / 323 = (1 × V₂) / 273

Cross multiply

323 × V₂ = 0.5 × 250 × 273

Divide both side by 323

V₂ = (0.5 × 250 × 273) / 323

New volume = 105.65 mL

3. How do i determine the new temperature?

The new temperature can be obtained by using the combined gas equation as follow:

Initial Volume (V₁) = 2.52 LInitial temperature (T₁) = 37 °C = 37 + 273 = 310 KInitial pressure (P₁) = 450 torr New pressure (P₂) = 600 mmHg = 600 torrNew volume (V₂) = 1.57 LNew temperature (T₂) =?

P₁V₁ / T₁ = P₂V₂ / T₂

(450 × 2.52) / 310 = (600 × 1.57) / T₂

Cross multiply

450 × 2.52 × T₂ = 310 × 600 × 1.57

Divide both side by (450 × 2.52)

T₂ = (310 × 600 × 1.57) / (450 × 2.52)

T₂ = 257.51 K

Subtract 273 to obtain answer in °C

T₂ = 257.51 - 273 K

New temperature = -15.49 °C

4. How do i determine the final pressure?Initial volume (V₁) = 0.450 LInitial temperature (T₁) = 25 °C = 25 + 273 = 298 KInitial pressure (P₁) = 47.81 KPaFinal volume (V₂) = 825 mL = 825 / 1000 = 0.825 LFinal temperature (T₂) = 52.5 °C = 52.5 + 273 = 325.5 KFinal pressure (P₂) = ?

The combined gas equation is given as follow:

P₁V₁ / T₁ = P₂V₂ / T₂

Inputting the given parameters, we obtained:

(47.81 × 0.45) / 298 = (P₂ × 0.825) / 325.5

Cross multiply

298 × 0.825 × P₂ = 47.81 × 0.45 × 325.5

Divide both sides by (345 × 150)

P₂ = (47.81 × 0.45 × 325.5) / (298 × 0.825)

Final pressure = 28.48 KPa

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Consider an airfoil in a flow of air, where far ahead of the airfoil (the freestream), the pressure, velocity, and density are 2116 lb/ft", 500 mi/h, and 0.002377 slug/ft®, respectively. At a given point A on the airfoil, the pressure is 1497 lb/ft. What is the velocity at point A? Assume isentropic flow. For air, ce = 6006 ft lb/slug°R.

Answers

The velocity at point A is 592.24 mi/h.

To find the velocity at point A, we can use the Bernoulli equation for isentropic flow:
P + 0.5ρv² = constant

Where P is pressure, ρ is density, and v is velocity. We can rearrange the equation to solve for velocity:
v = √[(2/ρ)(constant - P)]

We can use the given values for the freestream conditions to find the constant:
2116 lb/ft² + 0.5(0.002377 slug/ft³)(500 mi/h)² = constant
Converting 500 mi/h to ft/s:
500 mi/h * (5280 ft/mi) * (1 h/3600 s) = 733.33 ft/s

Plugging this back into the equation:
2116 lb/ft² + 0.5(0.002377 slug/ft³)(733.33 ft/s)² = constant
Constant = 2336.22 lb/ft²

Now we can plug in the values for point A to find the velocity:
v = √[(2/0.002377 slug/ft³)(2336.22 lb/ft² - 1497 lb/ft²)]
v = 868.58 ft/s

Converting back to mi/h:
v = 868.58 ft/s * (3600 s/h) * (1 mi/5280 ft) = 592.24 mi/h

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What mass (g) of NaN3 is required to provide 40.0 L of N2 at 25.0°C and 763 torr?

Answers

The needed mass of NaN3 is 71.175 grammes.

How much NaN3 must be produced in grammes?

As seen above, for every 2 moles of sodium azide that break down, 3 moles of nitrogen gas are created. This mole ratio will be helpful in figuring out how much NaN3 N a N 3 is required to make 10.0 cubic feet of N2 gas. Hence, to generate 10.0 cubic feet of N2 gas, 547 grammes of NaN3 are required.

What gas makes up the majority of an air bag that has been inflated by the NaN3 reaction?

The sodium azide, or NaN3, chemical would hold the key to the solution. Nitrogen gas, which may instantly inflate an airbag, is released when this chemical is ignited by a spark.

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Calculate the no. Of molecules in 0.1 moles of CO2.​

Answers

Explanation:

in \(\sf{CO_{2}}\) molecule mass=6+2×8=22gms

in \({ 22 ~gms\:molecule =Na} \)

\(\boxed{\sf {Na=6.022×{10}^{-23} } }\)

\({ 1gms\:molecule =\frac{Na}{22} } \)

\({0.1gms \:molecule =\frac{Na}{ 22}×100 }\)

so the answer of this questions is

\(\implies {\sf { \frac{6 .022×100}{22} } }\)

\(\implies{\sf { \frac{602.2}{22} } }\)

HELP ASAP.

Determine the length of time it would take for a banana slug to run a complete marathon.

Use the information below for guidance.

Question: How long would it take a slug to run a marathon, 26.2 miles?

Provide your answer in a time length that gives a value between 1 and 100. You'll need to decide whether that is minutes, days, years, or decades. The number needs to have a context (or have meaning) to you.

Here are some potentially useful conversion factors. There are multiple ways to solve this problem and you may not need all these conversion factors. You might also need some of your metric prefix conversions! Remember "King Henry died by drinking chunky milk". ●

Length 12 inch = 1 foot
1 inch = 2.54 cm
3 feet = 1 yard
5280 feet 1 mile
1760 yards = 1 mile

Time 1 min = 60 seconds
60 minutes = 1 hour
24 hours = 1 day
365.25 days = 1 year
10 years = 1 decade

Slug Travel Rate 0.0229 mm/s

Hints:
Consider starting with the length of the marathon, 26.2 miles.
Show all your work. Include both number and unit in each space.
Use the "fence posts" to organize your conversion factors to cancel units.​

Answers

It would take a banana slug approximately 1,029,863 minutes to run a complete marathon, which is equivalent to about 17,164 hours or approximately 714 days.

How to determine length of time?

To determine the length of time it would take for a banana slug to run a complete marathon of 26.2 miles, use the given information and conversion factors:

Given:

Slug Travel Rate: 0.0229 mm/s

Conversion Factors:

1 mile = 5280 feet

1 foot = 12 inches

1 inch = 2.54 cm

1 cm = 10 mm

1 second = 1 s

Now set up the conversions to cancel out the units and find the time:

26.2 miles × (5280 feet/1 mile) × (12 inches/1 foot) × (2.54 cm/1 inch) × (10 mm/1 cm) × (1 s/0.0229 mm) = X seconds

Calculating this value:

X = (26.2 × 5280 × 12 × 2.54 × 10) / (0.0229)

X ≈ 61,791,789.68 seconds

Now convert seconds to a time unit that has a value between 1 and 100. Let's choose minutes:

61,791,789.68 seconds × (1 min / 60 seconds) = Y minutes

Y ≈ 1,029,863.16 minutes

So, it would take a banana slug approximately 1,029,863 minutes to run a complete marathon, which is equivalent to about 1,029,863/60 ≈ 17,164 hours or approximately 714 days.

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A container at equilibrium contains the following concentrations: [Hz] - 0.30 M and [HI]
0.90 M. The equilibrium constant is equal to 6.0. What is the concentration of I2 at
equilibrium?
Hzig) + 1218 = 2 Hle)

Answers

Answer: The concentration of \(I_2\) at equilibrium is 0.45 M

Explanation:

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as \(K_c\)  

For the given chemical reaction:

\(H_2(g)+I_2(g)\rightarrow 2HI(g)\)

The expression for \(K_c\) is written as:

\(K_c=\frac{[HI]^2}{[H_2]^1[I_2]^1}\)

\(6.0=\frac{(0.90)^2}{(0.30)^1\times (I_2)^1}\)

\([I_2]=0.45M\)  

Thus concentration of \(I_2\) at equilibrium is 0.45 M

Using the table of average bond energies, estimate the energy needed to break the bonds of the reactants and the energy released when the products from for the reaction N2 + O2 –> 2NO. Note N2 has a triple bond and O2 and NO have double bonds.

Using the table of average bond energies, estimate the energy needed to break the bonds of the reactants

Answers

The energy that is released for the breaking of bonds is 229 kJ/mol.

What is the energy released?

We should be able to recall that the enthalpy of the reaction taken to be the energy that is evolved or absorbed in the reaction that is ongoing. We have to note that in the course of the reaction there would be the breaking and the making of bonds.

Now we know that;

The bond energy can be given as;

Sum energy of the broken bonds of reactants  - Sum of the energy of the formed bonds

Hence;

(945 + 498) - 2(607)

1443 - 1214

= 229 kJ/mol

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calculate the amount of F.A.S required to prepare 1000 ml of 0.1 molar standard solution of F.A.S

Answers

Answer:

Preparation and Standardization of 0.1 M Ferrous Ammonium...

Dissolve 40 g of ferrous ammonium sulfate in a previously cooled mixture of 40 ml of sulphuric acid and 200 ml of water.

Dilute with sufficient freshly boiled and cooled water to produce 1000 ml.

Standardize the solution in the following manner.

Explanation:

What is the relationship between the volume of a gas and the Kelvin temperature (at
constant pressure)?
They are the same.
They are inversely proportional to each other
They are directly proportional to each other.
They are independent of each other.

Answers

The second one I think

This element has 2 fewer protons than Titanium. What element is it?

Answers

Answer:

calcium.

Explanation:

because of

thanks

Select the correct answer. Sami was blowing soap bubbles in his room where the temperature was 23 °C and the pressure was constant. He blew a soup bubble of volume 45 mL. The bubble suddenly escaped from the window where the temperature outside was 12 °C. Explain what will happen to the soap bubble? The volume of the soap bubble will increase to 46.73 mL. The volume of the soap bubble will increase to 86.25 mL. The volume of the soap bubble will decrease to 23.47 mL. The volume of the soap bubble will decrease to 43.33 mL.​

Answers

Answer:Question

Select the correct answer. Sami was blowing soap bubbles in his room where the temperature was 23 °C and the pressure was constant. He blew a soup bubble of volume 45 mL. The bubble suddenly escaped from the window where the temperature outside was 12 °C. Explain what will happen to the soap bubble? The volume of the soap bubble will increase to 46.73 mL. The volume of the soap bubble will increase to 86.25 mL. The volume of the soap bubble will decrease to 23.47 mL. The volume of the soap bubble will decrease to 43.33 mL.​

Explanation:

Question

Select the correct answer. Sami was blowing soap bubbles in his room where the temperature was 23 °C and the pressure was constant. He blew a soup bubble of volume 45 mL. The bubble suddenly escaped from the window where the temperature outside was 12 °C. Explain what will happen to the soap bubble? The volume of the soap bubble will increase to 46.73 mL. The volume of the soap bubble will increase to 86.25 mL. The volume of the soap bubble will decrease to 23.47 mL. The volume of the soap bubble will decrease to 43.33 mL.​

A chemist runs the following decomposition reaction: C2H6 → 2 C + 3 H2
If she starts with 50.0 g of C2H6, how many grams of carbon will be made?

Answers

50.0g C2H6 • 1 mol C2H6 =
———-
30g. C2H6

1.66 mol C2H6 • 2 mol C
———— = 3.32 moles C
1 mole C2H6

3.33 mol C • 12 g. C
———— = **39.84 g C**
1 mol C

Answer: 39.84g C

Convert 8.84 g O₂ to moles. Round answer to the hundredths place.​

Answers

8.84 g of oxygen gas in moles is 0.276 moles.

How to calculate moles from mass?

The mass of a substance can be converted to moles using the following expression:

moles = mass ÷ molar mass

Moles of a substance refers to the base unit of amount of substance. It is the amount of substance of a system which contains exactly 6.02214076 × 10²³ elementary entities (atoms, ions, molecules, etc.).

molar mass of oxygen gas = 32g/mol

moles = 8.84g ÷ 32g/mol

moles = 0.276 moles

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If you need to produce 66 grams of carbon dioxide, how many liters of water vapor would you produce as a by product?

If you need to produce 66 grams of carbon dioxide, how many liters of water vapor would you produce as

Answers

The question requires us to calculate the amount of vapor water produced as a by-product when 66g of carbon dioxide are obtained from the combustion of propane.

Considering the combustion of propane (C3H8), we have the following reaction:

\(2C_3H_8+9O_2\to4CO_2+2CO_{}+8H_2O_{(v)}\)

IFrom the reaction, we can see that the stoichiometric relationship between C3H8 and water (H2O) is as follows:

2 mol C3H8 ---------- 8 mol H2O

Then, to calculate the amount of water produced as a by-product, we'll need to determine the amount of reactant needed to produce 66g of CO2.

Since the molar mass of CO2 is 44g/mol and considering the reaction written above, we can write:

2 mol C3H8 ---------- 4 mol CO2

x ---------- (66g/44g) = 1.5 mol CO2

Solving for x, we have that 0.75 mol of C3H8 are required to produce 66g of CO2.

Now, we calculate the amount of water that should be obtained from 0.75 mol of C3H8:

2 mol C3H8 ---------- 8 mol H2O

0.75 mol C3H8 ----- y

Solving for y, we have that 3 moles of water will be obtained as a by-product.

At last, we convert the calculated amount of vapor water into its volume considering the Standard Temperature and Pressure conditions (STP), where 1 mol of a gas corresponds to 22.4 L of the same gas:

1 mol vapor H2O ---------- 22.4 L vapor H2O

3 mol vapor H2O --------- z

Solving for z, we have that 67.2 L of vapor water will be obtained as a by-product when 66g of CO2 are produced from the combustion of propane.

what is the approximate ph of a 0.10 m solution of a weak acid that has a ka of 5 x 10-5 m?

Answers

2.7 is the approximate pH of a 0.10 m solution of a weak acid that has a ka of 5 x 10^-5 m.

5 x 10^-5 (0.1) = 5 x 10^-6

sqrt 5 x 10^-6 = 2.24 x 10-3

-log 2.24 x 10-3 = 2.7

pH, which originally stood for "potential of hydrogen," is a chemical scale used to quantify the acidity or basicity of an aqueous solution. Acidic solutions have a lower pH than basic or alkaline solutions. The pH of aqueous or other liquid solutions is a quantitative measure of their acidity or basicity.

The pH of a solution is a measure of its acidity or alkalinity, as well as its concentration of hydrogen ions. The pH scale often spans from 0 to 14. Aqueous solutions with a pH less than 7 at 25 ° C are acidic, whereas solutions with a pH more than 7 are basic or alkaline.

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Dental crown: Uranium-234 is used to make dental crowns appear brighter. The alpha decay of uranium-234 produces what isotope?

Answers

Answer:

Lithium has two naturally occurring isotopes. Lithium-6 has an atomic mass of 6.015 amu. Lithium-7 has an atomic mass of 7.016 amu. The average atomic mass of lithium is 6.941 amu.

Explanation:

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