Answer:
30 km/h
Explanation:
V=S:t
speed=length:time
150:5=30
Which of the following statements about height and strength gains is true?
In boys, the strength spurt occurs about a year after their height spurt.
O In girls, the strength spurt occurs about a year after their height spurt.
O In boys, the spurts in height and strength tend to occur synchronously.
O In girls, the height spurt occurs about a year after their strength spurt.
The statement that is true about height and strength is that In boys, the strength spurt occurs about a year after their height spurt
What is puberty?Puberty is the transformational change that occur between childhood and adulthood. It is a stage of maturity
Height of a person is the distance from the feet of a person to the peak or his head.
Strength is the ability of a person to be very strong and can do vigorous things.
Therefore, The statement that is true about height and strength is that In boys, the strength spurt occurs about a year after their height spurt.
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03: Hook's law suggests that F is directly proportional to -x, how much true you have found this statement in your experiment? Explain any differences.
Hooke's Law can be given as follows sometimes:
The restoring force of a spring is equal to the spring constant multiplied by the displacement from its normal position:
F = -kx
Where, F = Restoring force of a spring (Newtons, N)
k = Spring constant (N/m)
x = Displacement of the spring (m)
The negative sign relates to the direction of the applied force and by convention, the minus or negative sign is present in F = -kx. The restoring force F is directly proportional to the displacement (x), according to Hooke's law. When the spring is compressed, the displacement (x) is negative. It is zero when the spring is at its original length and positive when the spring is extended.
Practically, Hooke's Law is applicable only within a limited frame of reference, and through experimenting, this statement proves to be true. Because materials cannot be compressed beyond a certain size or expanded beyond a certain size without some permanent deformation or change of their original state.
The law only applies under some conditions such as a limited amount of force or deformation. Factually, many materials will noticeably deviate from Hooke's law even before those elastic limits are reached.
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A rock is thrown straight down from a cliff with an initial velocity of 10.0 m/s. Its final velocity when it strikes the water below is 115 m/s. How long is the rock in flight?
The time of the rock in flight is 10.71 s.
What is time of flight?This is the total time taken for an object or a projectile to return back to the same plane at which it was projected.
To calculate the time of the rock in flight, we use the formula below.
Formula:
v = u+gt............. Equation 1Where:
v = Final final velocityu = Initial velocityt = time of the rock in flight. g = acceleration due to gravitymake t the subject of the equation
t = (v-u)/g.................... Equation 2
From the question,
Given:
u = 10 m/sv = 115 m/sg = 9.8 m/s².Substitute these values into equation 2
t = (115-10)/9.8t = 105/9.8t = 10.71 sHence, the time of the rock in flight is 10.71 s.
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The rock was in the flight for 11.7 s
Time of flightThis is defined as the total time spent by an object in air.
Determination of the height of the cliffFrom the question given above, the following data were obtained:
Initial velocity (u) = 10 m/sFinal velocity (v) = 115 m/sAcceleration due to gravity (g) = 9.8 m/s²Height of cliff (h) =?v² = u² + 2gh
115² = 10² + (2 × 9.8 × h)
13225 = 100 + 19.6h
Collect like terms
13225 – 100 = 19.6h
13125 = 19.6h
Divide both side by 19.6
h = 13125 / 19.6
h = 669.64 m
How to determine the time of flight Acceleration due to gravity (g) = 9.8 m/s²Height of cliff (h) = 669.64 mTime of flight (t) =?h = ½gt²
669.64 = ½ × 9.8 × t²
669.64 = 4.9 × t²
Divide both side by 4.9
t² = 669.64 / 4.9
Take the square root of both side
t = √(669.64 / 4.9)
t = 11.7 s
Thus, the rock was in the flight for 11.7 s
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You are piloting a small airplane in which you want to reach a destination that is 750 km due north of your starting location. Once you are airborne, you find that (due to a strong but steady wind) to maintain a northerly course you must point the nose of the plane at an angle of 22 west of true north. From previous flights on this route in the absence of wind, you know that it takes you 3.14 h to make the journey. With the wind blowing, you find that it takes 4.32 h. A fellow pilot calls to ask you about the wind velocity (magnitude and direction). What is your report? FYI so you can check yourself the answers are 101 km/h at 62 degrees east of south.
Answer:
v_wind = 101.46 km / h , θ = 61.8
Explanation:
This is a velocity composition exercise.
Let's do the problem in parts. Let's start by knowing the speed of the plane without air.
v = d / t
v = 750 / 3.14
v = 238.85 km / h
This is the speed of the plane relative to the Earth and it does not change.
In the second part, when there is wind, the travel time is greater than when there is no wind, therefore the wind delays the plane. To be more general, suppose that the wind has two components vₓ and \(v_{y}\)
Let's use trigonometry to find the components of the plane's speed
cos θ = v_N / v
sin θ = v_W / v
v_N = v cos θ
v_W = v sin θ
let's calculate
V _N = 238.85 cos 22 = 221.46 km / h
v_W = -238.85 sin 22 = -89.47
the negative sign is because the plane is going west and the positive sign is the east direction.
As it indicates that the destination of the avine is towards the north, the x component of the wind must be
vₓ - v_W = 0
vₓ = v-w
vₓ = 89.47 km / h
in the direction to the East.
Now let's analyze the component of the wind in the Nort-South direction,
Indicate the travel time, let's calculate the speed that the component must have the speed of the plane
v_total = d / t
v_total = 750 / 4.32
v_total = 173.61 km / h
This is the final speed of the plane, which can be written
v_total = v_n - vy
vy = v_n - v_total
vy = 221.46 - 173.61
vy = 47.85 km
this component is directed towards the south
Let's use the Pythagorean Theorem, to find the magnitude
v_wind² = vₓ² + vy²
v_wind = √ (89.47² + 47.85²)
v_wind = 101.46 km / h
the address will then be found using trigonometry
θ = Vy / vx
θ = tan⁻¹ (vy / vx)
θ = tan⁻¹1 (47.85 / 89.47)
θ = 28.14
Therefore, the magnitude of the wind speed is 101.5 km / h and its direction is 28º south of the East, to give this value
90- θtea = 90- 28.2
θ = 61.8
East of South
The magnetic field through a circular loop of radius r = 15 cm varies with time, as shown. The direction of the field is perpendicular to the loop. What is the magnitude of the induced emf, ε1, in millivolts, at time t1 = 1.0ms?
B=0I2R(at centre of loop), B = 0 I 2 R(at centre of loop), where R is the loop's radius, gives the magnetic field strength at the loop's centre.
How does the magnetic field change as the loop's radius increases?The magnetic field strength diminishes with increasing radius. Radius of the loop has an inverse relationship with magnetic field intensity.
With its plane normal to an external field of magnitude 5.0102T, a circular coil with a radius of 10 cm and 16 turns that is carrying a current of 0.75 A is at rest. The coil is unrestricted in its ability to rotate around an axis in a plane perpendicular to the field direction.
Hence, the integral around any circle's diameter that is centred on a wire.
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Read each question carefully. Show all your work for each part of the question. The parts within the question may not have equal weight. A satellite of mass mis orbiting Earth in a stable circular orbit of radius R. The mass and radius of Earth are Mg and Rg respectively. Express your answers to parts (a) (b), and (c) the following in terms of m. R. Mg. Rg and physical constants, as appropriate (a) Derive an expression for the speed of the satellite in its orbit. (b) Derive an expression for the total mechanical energy of the satellite-Earth system in its orbit. (c) Derive an expression for the period of the satellite's orbit. (d) The satellite is replaced with a similar satellite that has twice the mass. The new satellite is placed into the same orbit as the original satellite. Is the new satellite's orbital speed greater than, less than or equal to the original satellite's orbital speed? -Greater thanLess than Equal to Justify your answer. (e) The original satellite can be placed in many different circular orbits of radius r. On the axes, sketch a graph of the mechanical energy E of the satellite-Earth system as a function of the orbital radius r.(f) On the figure, sketch the path the satellite will follow after the collision with the meteorite.
a) v = , √G Mg/(R+Rg) , b) ) Em = - ½ m G M/(R+Rg), c) T = 2π √(R+Rg)³
d) New satellite speed is equal to the original satellite's orbital speed.
a) For this exercise we must use Newton's second law with the gravitational force
F = ma
G mMg/(R+Rg)² = m a
The acceleration of the satellite is centripetal
a = v²/(R+Rg)
We substitute
G mMg/(R+Rg)² = m v²/(R+Rg)
G Mg/(R+Rg) = v²
v = √G Mg/(R+Rg)
The distance is from the center of the earth
b) Mechanical energy is the sum of kinetic energy plus potential energy
Em = K + U
Em = ½ m v² - G m M / (R + Rg)
We substitute the expression for the velocity
Em = ½ m G Mg/(R+Rg) - G Mg/(R+Rg)
Em = - ½ m G Mg/(R+Rg)
c) As the orbit is circulating, the velocity modulus is constant
v = d / t
In a complete orbit the distance traveled of the circle is
d = 2π (R + Rg)
Where time is called period
v = 2π (R + Rg)
T = 2π (R + Rg) / v
We substitute the speed value
T = 2π (R + Rg) √(R + Rg)/GMg
T = 2π √(R+Rg)³/GMg
d) V orbital is independent on mass of satellite, so new satellite speed is Equal. more about
e) & f) File attached.
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1. What is the function of a lightning rod?
2. How is charge build-up reduced on airplanes?
3. Why is a ground strap a necessary safety feature when transferring fuel?
4. What are three different methods for reducing charge build-up in clothes dryers?
5. What are four different methods for reducing charge build-up in a computer room with a carpet?
Answer: 1. The function of a lightning rod is to protect buildings, structures, and people from lightning strikes by providing a path of least resistance for the electrical current to follow, directing it safely into the ground instead of through the structure or people.
2. Charge build-up is reduced on airplanes through various methods, such as using conductive materials in the airplane's structure, applying anti-static coatings on the airplane's surface, and installing static discharge wicks or similar devices on the airplane's trailing edges, which provide a way for any accumulated charge to safely dissipate into the air.
3. A ground strap is a necessary safety feature when transferring fuel because it provides an electrical connection between the fuel container and the receiving container, allowing any static charge to safely dissipate into the ground. Without a ground strap, the static charge could build up and potentially ignite the fuel.
4. Three different methods for reducing charge build-up in clothes dryers are: (1) using dryer sheets or fabric softeners, which can help neutralize static charges on the clothes, (2) adding a damp cloth to the dryer, which can help dissipate static charges, and (3) using metal dryer balls, which can physically separate clothes and prevent them from rubbing against each other and creating static charges.
5. Four different methods for reducing charge build-up in a computer room with a carpet are: (1) using conductive flooring or carpet tiles that can help dissipate static charges, (2) using anti-static mats or wrist straps for personnel who work in the room, (3) using air ionizers or humidifiers, which can help neutralize static charges in the air, and (4) grounding all equipment and devices in the room to prevent the buildup of static charges.
Explanation:
I hope this helps!
Which TWO statements describe the ocean floor giving brainliest please help
Answer:
A and B.
Explanation:
Answer C is wrong - there are no tall trees underwater
Answer D is wrong, there are mountain chains underwater due to plate tectonics.
One molecule of dinitrogen tetroxide contains...
A.
four nitrogen atoms and four oxygen atoms.
B.
two nitrogen atoms and four oxygen atoms.
C.
four nitrogen atoms and two oxygen atoms.
D.
two nitrogen atoms and two oxygen atoms.
Answer:
C
Explanation:
C is correct
Ok!
151617
A hiker with a skin surface area of 1.3 m² is protected from hypothermia (the cold) by a close-fitting sleeping bag 30 mm thick. If her skin temperature is 34°C and she can safely lose 85 W of heat by conduction through the sleeping bag, what is the lowest outside temperature for which the sleeping bag provides adequate protection? Ignore heat losses due to convection or radiation. Coefficient of thermal conductivity of the sleeping bag = 0.019 Wm¹¹°C-¹
Answer: The lowest outside temperature for which the sleeping bag provides adequate protection is approximately 89.61°C below the hiker's skin temperature of 34°C.
Explanation:
To find the lowest outside temperature for which the sleeping bag provides adequate protection, we need to determine the rate of heat loss through conduction and compare it to the heat loss the hiker can safely tolerate.
The rate of heat loss through conduction can be calculated using the formula:
Q = (k * A * ΔT) / d
Where:
Q is the rate of heat transfer (in Watts)
k is the coefficient of thermal conductivity (0.019 Wm¹¹°C-¹ in this case)
A is the surface area (1.3 m² in this case)
ΔT is the temperature difference (in this case, the difference between the skin temperature and the outside temperature)
d is the thickness of the sleeping bag (30 mm, which needs to be converted to meters by dividing by 1000)
Let's plug in the values:
Q = (0.019 * 1.3 * ΔT) / (30 / 1000)
The hiker can safely lose 85 W of heat, so we can set up the equation:
85 = (0.019 * 1.3 * ΔT) / (30 / 1000)
To solve for ΔT, we can rearrange the equation:
ΔT = (85 * (30 / 1000)) / (0.019 * 1.3)
ΔT ≈ 89.61°C
7. A girl pushes her little brother on his sled with a force of 300. N for 750. m. How much work is this if the force of friction acting on the sled is (a) 200. N. (b) 300. N?
Answer:
a) 75000Joules
b) 0Joules
Explanation:
Workdone = Force * Distance
Given
distance= 750m
Force = 300N
a) If the frictional force = 200N
The Total force = 300N - 200N = 100N
Work done = 100 * 750
Workdone = 75,000Joules
Hence the workdone if the force of friction is 200N is 75,000Joules
b) If the frictional force = 300N
The Total force = 300N - 300N = 0N
Work done = 0* 750
Workdone = 0Joules
Hence the workdone if the force of friction is 300N is 0Joules i.e no work will be done on the sled
A motorcycle stoop is at a traffic light, when the light turns green, the motorcycle accelerates to a speed of 78 km/h over a distance of 50 m. What is the average acceleration of the motorcycle over this distance?
The average acceleration of the motorcycle over the given distance is approximately 9.39 m/s².
To calculate the average acceleration of the motorcycle, we can use the formula:
Average acceleration = (final velocity - initial velocity) / time
First, let's convert the final velocity from km/h to m/s since the distance is given in meters. We know that 1 km/h is equal to 0.2778 m/s.
Converting the final velocity:
Final velocity = 78 km/h * 0.2778 m/s = 21.67 m/s
Since the motorcycle starts from rest (initial velocity is zero), the formula becomes:
Average acceleration = (21.67 m/s - 0 m/s) / time
To find the time taken to reach this velocity, we need to use the formula for average speed:
Average speed = total distance/time
Rearranging the formula:
time = total distance / average speed
Plugging in the values:
time = 50 m / 21.67 m/s ≈ 2.31 seconds
Now we can calculate the average acceleration:
Average acceleration = (21.67 m/s - 0 m/s) / 2.31 s ≈ 9.39 m/s²
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If 10 waves pass one dock every 16.0 seconds, determine the frequency of the wave.
The frequency of the wave is 0.625 waves per second, calculated by dividing the number of waves (10) by the time (16.0 seconds).
To determine the frequency of a wave, you need to divide the number of waves (in this case, 10) by the time it takes for those waves to pass a certain point (in this case, a dock) within 16.0 seconds.
Frequency is usually measured in Hertz (Hz), which represents the number of cycles or events per second. So, to find the frequency, we calculate 10 waves / 16.0 seconds = 0.625 waves per second or 0.625 Hz.
This means that every second, 0.625 waves pass by the dock, giving you the frequency of the wave.
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what is magnetic flux thru a closed surface
Answer: Zero
Explanation:
Gauss's law states that the total magnetic flux through a closed surface is equal to zero. Because the magnetic field lines are in continuous loops, so all closed surfaces have magnetic field lines coming out, hence the net magnetic flux is zero.
Please match the units with the type of measurement.
1.Distance
2.Power
3.Energy
4.Resistance
5.Force
1. Watt
2. Ohm
3. Lightyear
4. Newton
5. Joule
Answer:
1distance --------- lightyear
2power------------- watt
3energy ----------- joule
4resistance ------ Ohm
5Force---------------- Newton
Explain what differentiates the Earth’s crust and lithosphere.
Answer:
What is the difference between the crust and lithosphere? The crust (whether continental or oceanic) is the thin layer of distinctive chemical composition overlying the ultramafic upper mantle. ... The lithosphere is the rigid outer layer of the Earth required by plate tectonic theory.
Explanation:
Hope this helps!
Answer:
a thin layer
Explanation:because
The crust (whether continental or oceanic) is the thin layer of distinctive chemical composition overlying the ultramafic upper mantle. ... The lithosphere is the rigid outer layer of the Earth required by plate tectonic theory.
it is better to sell used paper then to burn them
Answer:
Using sold paper is better than to burn it because burning paper may cause pollution.
Explanation:
Hope it will help ^_^
Chloe puts 2 equal-sized marbles in a graduated cylinder containing 50 cm3 of water. The water level rises up to 70 cm3. What is the volume of each marble?
A glass marble has an average volume of about 2 cm3. When discussing the volume of a marble, you want to know how much space the object occupies.
What is the volume of each marble?
Because the volume of each marble must be 0.05 because the amount of water decreases by 0.05 times the number of marbles. Essentially, the volume is equal to the product of the shape's area and height. Volume equals base area multiplied by height.Finding the volume of an object can help us determine how much water is needed to fill that object, such as how much water is needed to fill a bottle, aquarium, or water tank.Volume is a measurement of an object's capacity. For example, the volume of a cup is 100 ml if it can hold 100 ml of water up to the brim. Volume is also the amount of space occupied by a three-dimensional object.To learn more about volume refers to:
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Why does ice float on water?
Explanation:
Ice floats on water because it's alil water compacted into 1 shape which is heavier, ice is also a solid at 1st so solid things also can float on water
cheese is made of cheese
Cheese is made of casein protein, which is originally made from milk and is high in protein. The texture of the cheese is determined by the quality of the milk, so cow's milk cheese differs from goat's milk cheese.
What is a dairy product?
Diary products are made from milk, such as cheese, curd, yogurt, etc., but all of them have different nutrients. The quality of these dairy products depend upon the quality of the milk, as some milking animals have a higher concentration of fats in their milk than other animals. These dairy products are used in different industrial sectors, such as for making ice cream, chocolate, and different food products.
Hence, cheese is made up of casein proteins that are present in the milk.
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Derrick crawls 4 feet south, and then turns east and crawls 6 feet.
What distance did he cover?
What was his displacement?
Displacement is a vector quantity. The distance and displacement of the given object are 10 ft and 7.07 ft respectively.
Distance:
It can be defined as the change in position of the object. It is a scalar quantity.
Displacement = 4+6
Displacement = 10 ft
Displacement:It can be defined as the vector change in position overall change in position.It is a vector quantityVector quantity is the quantities that have both magnitude and direction.\(\rm Dislacement =\sqrt { 4^2 +6^2}\\\\ \rm Dislacement = 7.07 ft\)
Therefore, the distance and displacement of the given object are 10 ft and 7.07 ft respectively.
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You perform an experiment to measure the speed of a car over time. The
results are shown in the graph below.
Speed (m/s)
30
25-
20
15
10
5
0+
O
5
10
A. 24 m/s
B. 22 m/s
15
Time (s)
What was the speed of the car after 20 seconds?
C. 20 m/s
D. 30 m/s
20
25
The speed of the car after 20 seconds are 20 m/s.
What is the speed ?The speed of an object is a measure of how quickly the object is moving in a particular direction. It is typically measured in units such as meters per second (m/s). Speed is a scalar quantity, which means it is only concerned with the magnitude of the velocity (or speed) and not the direction
The graph shows that the speed of the car was 20 m/s after 20 seconds.
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The resistance RT of a platinum varies with temperature T(°C), as measured on the constant-volume gas thermometer according to the equation RT = Ro(1+AT+BT^2). Where A = 3.8×10^-3°C^-1 and B = -5.6×10^-7°C^-2. Calculate the temperature that would be on indicated on a platinum thermometer, when the gas scale reads 200°C.
The resistance indicated by the platinum thermometer at 200°C is 1.648 times the reference resistance Ro at 0°C.
The given equation is RT = Ro(1+AT+BT²), where A = 3.8×10⁻³°C⁻¹ and B = -5.6×10⁻⁷°C⁻². To determine the temperature that would be indicated on a platinum thermometer when the gas scale reads 200°C, we will have to use the given formula. RT = Ro(1+AT+BT²) .....(i)We know that the gas scale reads 200°C. Therefore, we can substitute T = 200°C in equation (i).RT = Ro (1 + A × 200 + B × 200²) = Ro (1 + 0.76 - 0.112) = Ro (1.648)Thus, the resistance that the platinum thermometer would indicate is 1.648 times the reference resistance Ro at 0°C. This is the solution to the problem.In summary, The given equation is RT = Ro(1+AT+BT²), where A = 3.8×10⁻³°C⁻¹ and B = -5.6×10⁻⁷°C⁻². To determine the temperature that would be indicated on a platinum thermometer when the gas scale reads 200°C, we substituted T = 200°C in equation (i) to get RT = Ro (1 + A × 200 + B × 200²) = Ro (1 + 0.76 - 0.112) = Ro (1.648).For more questions on thermometer
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Lab Report Sun, Earth, and Moon Models It’s time to complete your Lab Report. Save the lab to your computer with the correct unit number, lab name, and your name at the end of the file name (e.g., U5_ Lab_SunEarthAndMoonModels_Alice_Jones.doc). Introduction 1. What was the purpose of the investigation? Type your answer here: 2. What causes the bright part of the moon to appear bright? Type your answer here: Experimental Methods 1. What materials did you use to create your model? Type your answer here: 2. Describe how you created your model. Type your answer here: Develop a Model 1. Show your model and the relationships between the components. Include labeled pictures or diagrams that describe causal accounts for the phases of the moon and eclipses. Type your answer here: Use a Model 1. Use your model to predict the relative positions of the earth, sun, and moon when the moon is full. Type your answer here: 2. Use your model to explain why a lunar eclipse does not occur every month when there is a full moon. Type your answer here:
1. The purpose of the investigation was to study the relationship between the Sun, Earth, and Moon.
2. The bright part of the moon appears bright due to the reflection of sunlight.
Introduction: The purpose of the investigation was to study the relationship between the Sun, Earth, and Moon. By creating models of the three celestial bodies, we aimed to understand how their movements and positions influence the phases of the moon and eclipses.The bright part of the moon appears bright due to the reflection of sunlight. As sunlight hits the moon's surface, it bounces back and reflects into space. This reflected light is what we see as the bright part of the moon.
Experimental Methods: To create our model, we used a lamp to represent the Sun, a ball to represent the Earth, and a smaller ball to represent the Moon. We also used a ruler, tape, and a protractor to measure distances and angles.We created our model by placing the lamp at one end of a table, the Earth in the middle, and the Moon at the other end. We attached the Moon to a string and moved it around the Earth to simulate the Moon's orbit around the Earth.
Develop a Model: Our model consists of a lamp, a ball, and a smaller ball on a string. The lamp represents the Sun, the ball represents the Earth, and the smaller ball on the string represents the Moon. As the Moon moves around the Earth, it goes through phases, from a new moon to a full moon and back again.We used diagrams and pictures to label the components of our model and describe causal accounts for the phases of the moon and eclipses.
Use a Model: When the Moon is full, it is in a direct line with the Earth and the Sun. Using our model, we can predict that the Moon would be directly opposite the Sun in the sky during a full moon. A lunar eclipse does not occur every month when there is a full moon because the Moon's orbit around the Earth is tilted at an angle of about 5 degrees to the Earth's orbit around the Sun. Therefore, the Moon is not always in a direct line with the Earth and the Sun during a full moon, which is necessary for a lunar eclipse to occur.
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What principle of fitness means that if you stop exercising your fitness level will decrease?
A.
Reversibility
B.
Overload
C.
Specificity
D.
Individuality
Answer:
A. Reversibility
Explanation:
Because if you don't progress then you do the opposite, you reverse.
Sorry if my explanation is confusing it made sense in my head i just didn't know how to put it.
hope this help. ;)
Answer:
A. Reversibility
Explanation:
imagine that the blue light and orange light from the source were blocked. what color would how be present in the spectrum of light observed
Everything but blue & orange would now be present in the spectrum of light observed.
Spectrum refers to a range of different wavelengths of electromagnetic radiation. Electromagnetic radiation is a form of energy that travels through space and includes different types such as radio waves, microwaves, infrared radiation, visible light, ultraviolet radiation, X-rays, and gamma rays. Each type of electromagnetic radiation has a different wavelength and frequency, and together they make up the electromagnetic spectrum.
The concept of spectrum is used in a variety of fields, including physics, astronomy, and telecommunications. The spectrum of electromagnetic radiation is essential for many technologies, such as radios and televisions, cell phones, and medical imaging devices, as they all rely on the transmission and reception of specific wavelengths of electromagnetic radiation.
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Complete Question: -
Imagine that the blue light and orange light from the source were blocked. What color(s) would now be present in the spectrum of light observed?
U WILL GET 25 POINTS PLEASE HELP
Your car is initially at rest when your hit that gas and the car begins to accelerate at a rate of 2.857 m/s/s. The acceleration lasts for 15.5 s. What is the final speed of the car and how much ground does it cover during this acceleration?
Answer:
Hopefully, this is right.
Explanation:
Answer is 5.43.
1
A manufacturer of garden syringes is testing a new range of
plastic syringes with variable size nozzles. The nozzles can be
removed and replaced with another nozzle of a different size.
The syringe used in these tests is shown in Figure 1.
Figure 1
2
3
4
piston
This is the method used:
1 Attach a 0.5 mm diameter nozzle onto the syringe.
Fill the syringe with 150 ml of water.
Press the piston into the syringe.
Measure the distance the water flows from the end
of the nozzle.
nozzle
5
Records the results in a table.
6 Repeat with other sizes of nozzle.
Name a piece of apparatus that could be used to take
measurements in these tests.
Four long wires are each carrying 6.0 A. The wires are located
at the 4 corners of a square with side length 9.0 cm. All of
these wires are carrying current out of the page. The
magnetic field (in T) at one corner of the square is:
Answer:
\(B_T=2.0*10^-5[-\hat{i}+\hat{j}]T\)
Explanation:
To find the magnitude of the magnetic field, you use the following formula for the calculation of the magnetic field generated by a current in a wire:
\(B=\frac{\mu_oI}{2\pi r}\)
μo: magnetic permeability of vacuum = 4π*10^-7 T/A
I: current = 6.0 A
r: distance to the wire in which magnetic field is measured
In this case, you have four wires at corners of a square of length 9.0cm = 0.09m
You calculate the magnetic field in one corner. Then, you have to sum the contribution of all magnetic field generated by the other three wires, in the other corners. Furthermore, you have to take into account the direction of such magnetic fields. The direction of the magnetic field is given by the right-hand side rule.
If you assume that the magnetic field is measured in the up-right corner of the square, the wire to the left generates a magnetic field (in the corner in which you measure B) with direction upward (+ j), the wire down (down-right) generates a magnetic field with direction to the left (- i) and the third wire generates a magnetic field with a direction that is 45° over the horizontal in the left direction (you can notice that in the image attached below). The total magnetic field will be:
\(B_T=B_1+B_2+B_3\\\\B_{T}=\frac{\mu_o I_1}{2\pi r_1}\hat{j}-\frac{\mu_o I_2}{2\pi r_2}\hat{i}+\frac{\mu_o I_3}{2\pi r_3}[-cos45\hat{i}+sin45\hat{j}]\)
I1 = I2 = I3 = 6.0A
r1 = 0.09m
r2 = 0.09m
\(r_3=\sqrt{(0.09)^2+(0.09)^2}m=0.127m\)
Then you have:
\(B_T=\frac{\mu_o I}{2\pi}[(-\frac{1}{r_2}-\frac{cos45}{r_3})\hat{i}+(\frac{1}{r_1}+\frac{sin45}{r_3})\hat{j}}]\\\\B_T=\frac{(4\pi*10^{-7}T/A)(6.0A)}{2\pi}[(-\frac{1}{0.09m}-\frac{cos45}{0.127m})\hat{i}+(\frac{1}{0.09m}+\frac{sin45}{0.127m})]\\\\B_T=\frac{(4\pi*10^{-7}T/A)(6.0A)}{2\pi}[-16.67\hat{i}+16.67\hat{j}]\\\\B_T=2.0*10^-5[-\hat{i}+\hat{j}]T\)
Calculate the volume of a parallelepiped with sides give as a = ( 7,2 , 4 ) , b = ( 4,7 , 6 ) and c = ( 3,4 , 7 )
The volume of the parallelepiped is 83 cubic units.
The volume of a parallelepiped with sides give as a = ( 7,2 ,4 ) , b = ( 4,7 ,6 ) and c = ( 3,4 ,7 ).
The volume of a parallelepiped with adjacent sides a, b, and c is given by the scalar triple product (a × b) · c.
First, need to calculate the cross product of vectors a and b
a × b =
\(\left[\begin{array}{ccc}i &j&k\\7&2&4\\4&7&6\end{array}\right]\)
= (2 × 6 - 4 × 7) i - (7 × 6 - 4 × 4) j + (7 × 7 - 2 × 4) k
= -8 i - 26 j + 45 k
Now, calculate the scalar triple product
(a × b) · c = (-8)(3) + (-26)(4) + (45)(7) = 83
Therefore, the volume of the parallelepiped is 83 cubic units.
To know more about parallelepiped here
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