Calculate the weight of the following objects on earth (assume g=10 N/kg)
a) 12kg
b) 500g
c) 20g

Answers

Answer 1

Answer:

Memorize this and you'll be able to do ALL of these:  1  kg = 1,000 g

So if you have some grams, divide the number by 1,000 to get kilograms.

1,000 g = 1.000 kg

500 g = 0.500 kg

100 g = 0.100 kg

50 g = 0.050 kg

20 g = 0.020 kg

10 g = 0.010 kg

Explanation:


Related Questions

Helicopter rescue winch-men must dangle a metal wire below them so that it always touches the ground or water surface first. This discharges __________ __________ that may have built up on the helicopter. What two words complete the sentence?

Answers

Answer:

static electricity

Helicopter rescue winch-men must dangle a metal wire below them so that it always touches the ground or water surface first. This discharges static electricity that may have built upon the helicopter.

What is static electricity?

Static electricity is a familiar electric phenomenon in which charged particles are transferred from one body to another. For example, if two objects are rubbed together, especially if the objects are insulators and the surrounding air is dry, the objects acquire equal and opposite charges.

What is static electricity caused by?

Static electricity is generated by friction between two insulating materials. When the materials are rubbed together, electrons are removed from atoms within the materials, giving rise to a static electric charge.

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For Each Of The Following Scenarios Described Where A Molecule Or Ion Is Moving From One Side Of A Membrane To The Other, Select The Method By Which The Molecule Or Ion Is Moving. Each Answer Can Be Used More Than Once, Or Not At All. A. Simple Diffusion B. Facilitated Diffusion By A Channel Protein C. Facilitated Diffusion By A Carrier/Transport Protein

Answers

For Each Of The Following Scenarios Described Where A Molecule Or Ion Is Moving From One Side Of A Membrane To The Other, Option A is correct answer.

Scenario A: Oxygen moving across a plasma membrane Answer: A. Simple Diffusion Scenario B: Glucose moving across a plasma membrane Answer: C. Facilitated Diffusion By A Carrier/Transport Protein Scenario C: Sodium moving across a plasma membrane Answer: B. Facilitated Diffusion By A Channel Protein Scenario D: Water moving across a plasma membrane Answer: A. Simple Diffusion : Simple diffusion allows the nonpolar and small molecules to pass through the plasma membrane without any assistance of proteins. In facilitated diffusion, larger polar molecules or ions move across the membrane through the help of transport proteins. Transport proteins are of two types, channel and carrier proteins. Channel proteins provide an open path for the molecules to move whereas carrier proteins hold the molecules to move across the membrane and change their shape.

Option A is correct answer.

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What will be the fundamental frequency and first three overtones for a 26cm long organ at 20°C if it is open ( at 20°C, the speed of sound in air is 343m/s)

Answers

Explanation:

The frequency of an organ pipe if it is open is given by :

\(f=\dfrac{nv}{2l}\)

v is speed of sound in air is 343 m/s at 20°C

For fundamental frequency, n = 1

\(f=\dfrac{1\times 343}{2\times 0.26}\\\\f=659.61\ Hz\)

First overtone frequency,

\(f_1=2f\\\\f_1=2\times 659.61\\\\f_1=1319.22\ Hz\)

Second overtone frequency,

\(f_2=3f\\\\f_2=3\times 659.61\\\\f_2=1978.83\ Hz\)

Third overtone frequency

\(f_3=4f\\\\f_3=4\times 659.61\\\\f_3=2638.44\ Hz\)

Hence, this is the required solution.

the graph below shows the speed of an object during a 10 s time interval. In which of the following time intervals is the speed of the object was constant?
a. between 6 s and 8 s
b. between 2 s and 4 s
c. between 0 s and 2 s
d. between 2 s and 5 s

the graph below shows the speed of an object during a 10 s time interval. In which of the following time

Answers

Answer:

b. between 2 s and 4 s

Explanation:

2-4 was both 3m/s

An object of mass m = 4.0 kg is moving along a horizontal, frictionless surface with a speed vo = 5.0 m/s. It then comes in contact with a spring which has a spring constant k = 40,000 N/m and is initially in equilibrium. What is ∆x, the maximum distance the spring compresses? (A) 0.25 cm (B) 6.00 cm (C) 5.00 cm (D) 0.05 cm (E) 2.25 cm

Answers

The maximum distance the spring compresses is A) 0.25 cm or 2.5 × 10^-3 m.

The initial kinetic energy of the object is converted into elastic potential energy stored in the spring when it comes in contact with the spring. At the maximum compression, all the kinetic energy is converted into elastic potential energy.

The maximum compression of the spring is given by the equation ∆x = (mv^2)/(2k), where m is the mass of the object, v is its initial velocity, and k is the spring constant.

Plugging in the given values, we get ∆x = (4.0 kg × (5.0 m/s)^2)/(2 × 40,000 N/m) = 2.5 × 10^-3 m = 0.25 cm. Therefore, the maximum distance the spring compresses is 0.25 cm or 2.5 × 10^-3 m. The correct answer is (A).

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Give me right solution with clear calculations
. Tourists arrive at the Manila Zoo at a rate of 250 vehicles per hour. But before entering the zoo, the vehicles must get a brochure and pay the entrance fee at the single entrance booth. If the vehicles can be serviced at a rate of 400 vehicles per hour, determine the percentage of time that the operator of the single entrance booth will be free.
Note: Round off your answers to the nearest thousandths. Only include the numeric value of vour answer without the unit (i.e. 0.123).

Answers

The percentage of time the operator of the single entrance booth will be free is approximately 38.462%.

To determine the percentage of time that the operator of the single entrance booth will be free, we need to calculate the service rate and the arrival rate. The service rate is given as 400 vehicles per hour, and the arrival rate is 250 vehicles per hour. The percentage of time the operator will be free can be calculated using the formula:

Free time percentage = (Service rate - Arrival rate) / Service rate * 100

Substituting the given values into the formula:

Free time percentage = (400 - 250) / 400 * 100

= 150 / 400 * 100

= 0.375 * 100

= 37.5%

Rounding off the answer to the nearest thousandths, the percentage of time the operator of the single entrance booth will be free is approximately 38.462%.

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When a car reaches a stop at the top of a hill, kinetic energy is transforms into what energy?

Answers

Answer:

to potentialenergy

explanation :a potential energy is stored energy or it oesn't get in moving body

What is the mass amount of a Proton and a Neutron?

Answers

The masses amount of a proton and neutron are 1.0087 and 1.0073 amu respectively.

What is a Proton?

This is defined as  sub atomic particle which is positively charged and is present in the nucleus while the neutron is also a particle present in the nucleus but has a neutral charge.

Electrons on the other hand are found outside the nucleus and are negatively charged. It is the sub atomic particle which is actively involved in a chemical reaction.

The masses of neutron and proton are 1.0087 and 1.0073 amu respectively and was discovered by scientists thereby making it the most appropriate choice.

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New theories usually don’t start “from scratch.” For example, the modern model of the atom is the result of new information added to the cloud model. What is the main difference between the cloud model of the atom and the modern model? Group of answer choices Only the modern model includes protons. The cloud model does not include neutrons. Electrons move in specific orbits in the modern model. Electrons exist in a cloud around the nucleus in the cloud model.

Answers

Answer:

Electrons move in specific orbits in the modern model.

Explanation:

I'm still learning so, and D is not the answer.

The main difference between the cloud model of the atom and the modern model is that electrons exist in a cloud around the nucleus in the cloud model.

New theories usually don’t start “from scratch.” For example, the modern model of the atom is the result of new information added to the cloud model.

What is the main difference between the cloud model of the atom and the modern model?

Only the modern model includes protons. NO. Protons were discovered by Rutherford and are part of both models.The cloud model does not include neutrons. NO. Neutrons, discovered by Chadwick, are part of both models.Electrons move in specific orbits in the modern model. NO. Electrons in the modern model move in diffuse areas known as orbitals.Electrons exist in a cloud around the nucleus in the cloud model. YES.

The main difference between the cloud model of the atom and the modern model is that electrons exist in a cloud around the nucleus in the cloud model.

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a hurricane has a maximum sustained surface wind speed of ______ km (74 mi) per hour or higher.

Answers

A hurricane is a tropical cyclone that develops over warm waters and has a maximum sustained surface wind speed of 120 kilometers (74 mi) per hour or higher.

What's the hurricane?

Hurricanes are classified according to the Saffir-Simpson Hurricane Wind Scale, which ranges from Category 1 to Category 5, with Category 5 being the most severe.

These powerful storms can cause widespread damage to infrastructure, homes, and businesses, as well as pose a significant threat to human life.

In addition to high winds, hurricanes can also produce heavy rainfall, storm surges, and tornadoes.

It is important for individuals living in hurricane-prone areas to prepare for the potential impact of these storms by having a plan in place and staying informed of any updates from local authorities.

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I NEED HELP ANSWER FAST WILL GIVE BRAINLY!!!!!!!


knowing the atomic number will also tell you what about an atom?

Answers

Answer:

the number of protons.

Explanation:

the atomic number is the number of protons in the nucleus of an atom. the number of protons Define the identity of an element.

Find the potential difference between point a and point b for the situation shown below. Here ε1​=12.0 V,ε2​=9.27∨ and R1​=3.73Ω,R2​=6.24Ω, and R3​=2.08Ω. va​−V

Answers

Va and Vb are on opposite sides of the 6.24Ω resistor, so the potential difference across the resistor is negative. The circuit given in the figure below is a combination of parallel and series combinations of resistors and sources, which can be easily solved with the help of Kirchhoff's law and Ohm's law.

Solution:

First, let us label the points that are not known. Let Va be the voltage potential at point a, and Vb be the voltage potential at point b.

Voltage potential of point b:

Vb = ε2

Since the voltage source ε2 is directly connected to point b, the voltage potential of point b will be equal to the voltage provided by the source ε2 which is 9.27V.

Voltage potential of point a:

To find the voltage potential at point a, we first need to find the current through the 6.24Ω resistor (R2) since this resistor is connected between points a and b. To find the current flowing through the resistor R2 we need to use Ohm's law:

V = IR

IR = V/R2

Since the two branches are in parallel, the voltage across them will be the same as shown below:

Va - Vb = V1

V1 = i2R2

i2R2 = (ε2 - Va)R2/R1

i1 = (ε1 - Va)/[R1 + (R2R3/R1)]

Therefore, the potential difference between point a and point b is:

Va - Vb = 4.8218V - 9.27V

= -4.4482V

Va and Vb are on opposite sides of the 6.24Ω resistor, so the potential difference across the resistor is negative.

Therefore, the potential at point b is higher than the potential at point a.

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Since many wavelengths of light are measured in nanometers, it's useful to know that planck's constant (h) multiplied with the speed of
light (c) is equal to 1240 eVnm.
This is useful, as E = hf, or otherwise written as E= .
With this information in mind, solve the following:
A photon has 1.6 eV of energy. What is the wavelength of this photon?
O a
410 nm
Ob
775 nm
Ос
1984 nm
Od
306 nm

Answers

Answer:

E = h f      and since f = c / λ     we have E = h c / λ

Thus  λ = h c / E

Also, 1 ev = 1.6E-19 C

λ = 6.63E-34 * 3.0E8 / (1.6 * 1.6E-19)

λ = 6.63 * 3.0 / (1.6 * 1.6) * E-7

λ = 7.77E-7 = 777 nanometers

(B) is correct

Nora rides a bicycle for 5 min on a curvy road at a constant speeed of 10 m/s . Describe noras ride in terms of speed , velocity, and acceleration

Answers

Given:

The time period for which Nora rides the bicycle, t=5 min

The speed of the bicycle, s=10 m/s

To find:

The description of the ride.

Explanation:

The speed is a scalar quantity and has only magnitude. The velocity and acceleration are vector quantities and have magnitude and direction.

When the bicycle is traveling on a curved path at a constant speed, there will be an acceleration acting on it which keeps it on its path. This acceleration is called the centripetal acceleration.

The centripetal acceleration changes only the direction of the velocity and not the magnitude. Thus the speed will be constant. But the velocity will be changing at a constant acceleration.

How much acceleration is given to a 45 kg child with a 630 N push on a swing?

Answers

Hii :))

Force = mass × acceleration

630 = 45 × acceleration

630/45 = acceleration

14 m/s² = acceleration

DRAIOCHT ♡◇♡◇

What is the mass and weight of an object on the surface of the moon, if on the earth its mass is 12kg.

Answers

The mass and weight of object on moon is 0.0138kg  and 0.0229kg .

Since force is a vector quantity, we must consider the direction in which it acts. There are two main types of frictional force: static force (Fst) and sliding force (Fsl). Normal forces (FN) produce these forces acting perpendicular to the direction of motion, although they act in the opposite direction to the object's motion.

It is equivalent to the weight of the object plus the extra weight. For example, pushing down on a block of wood on a table increases the normal force and thus the frictional force.

me=12Kg

ge=10

gm=10/6= 1.66

M=?

me ge =M gm

M=me ge/gm

M=120/1.66

M=0.0138kg

W=mg =0.0138 x 10kg

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The grocery store is 20 miles away
from where you live. You drive your
car and it takes .5 hours to get there.
What was your rate of speed?

Answers

Answer:

40mph

Explanation:

20miles  .5 miles away if you go 20 mph you get there in a hour soo if you double to 40 mpg you get there in 0.5

Answer:

40 mph

Explanation:

you went 20 miles in half a hour, multiply twenty by 2 and you get 40

How is the answer D?

How is the answer D?

Answers

The graph that corresponds to 0.1 s in one complete cycle is graph D.

option D is the correct answer.

What is the period of a wave?

The period of a wave is the time for a particle on a medium to make one complete vibrational cycle. Period, being a time, is measured in units of time such as seconds, hours, days or years.

Also, the period of a wave is the amount of time it takes for a wave to complete one wave cycle or wavelength.

From the given parameter, the coil rotates 10 times in one second. The period of the coil is calculated as;

Period = 1 s / 10

Period = 0.1 s

From the graphs, the only option that has one complete cycle in one second is option D.

Check option D, half cycle is 0.05 s and one full cycle is 0.1 s.

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an excited nucleus emits a gamma-ray photon with an energy of 2.70 mev . part a what is the photon’s energy in joules? express your answer in joules.What is the photon's frequency? Express your answer in hertz.

Answers

The photon's energy in joules is 4.32 x \(10^{-13\) J, and its frequency is 6.53 x \(10^{20\) Hz.


To convert the energy of the gamma-ray photon from MeV to joules, use the conversion factor:

1 MeV = 1.602 x \(10^{-13\) J.

Multiply the given energy by this factor:

2.70 MeV x 1.602 x \(10^{-13\) J/MeV = 4.32 x \(10^{-13\) J.

To find the frequency, use the Planck's equation:

E = hν,

where

E is energy,

h is Planck's constant (6.63 x \(10^{-34\) J s), and

ν is the frequency.

Rearrange the equation to solve for frequency:

ν = E/h.

Substitute the energy in joules: ν = (4.32 x \(10^{-13\) J) / (6.63 x \(10^{-34\) J s) = 6.53 x \(10^{20\) Hz.

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The frequency of the gamma-ray photon is 6.53 x \(10^{20\) Hz.

The energy of a gamma-ray photon can be converted from electronvolts (eV) to joules (J) using the conversion factor:

1 eV = 1.602 x \(10^{-19\)J

Therefore, the energy of the gamma-ray photon with an energy of 2.70 MeV (mega-electronvolts) can be calculated as follows:

E = 2.70 MeV x 1,000,000 eV/1 MeV x 1.602 x \(10^{-19\) J/eV

E = 4.33 x \(10^{-13\) J

So the energy of the gamma-ray photon is 4.33 x \(10^{-13\) J.

The frequency of the gamma-ray photon can be calculated using the equation:

E = hf

where E is the energy of the photon, h is Planck's constant (6.626 x 10^-34 J s), and f is the frequency of the photon. Rearranging this equation to solve for f, we get:

f = E/h

Substituting the value of E we just calculated and the value of h, we get:

f = (4.33 x\(10^{-13\) J)/(6.626 x \(10^{-34\) J s)

f = 6.53 x \(10^{20\) Hz

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A meter stick hurtles through space at a speed of 0. 95c relative to you, with its length perpendicular to the direction of motion. You measure its length to be equal to.

Answers

Answer:

Explanation:

Caty  ,  Use   the relativity formula for length.  ( they teach this in H.S. ? )  it's from my Modern Physics in college, A 300 level class  

L = \(L_{0}\)\(\sqrt{1-\frac{v^{2} }{c^{2} } }\)

L = 3  \(\sqrt{1-\frac{.95^{2} }{1^{2} } }\)

L = 0.9367496998  meters

L = 0.94 meters approx

How far could you speed walk in 10 minutes? Use your speed from the 20m test to calculate the answer.

my speed is 13.63.​

Answers

Answer:

Explanation:

Given parameters:

Time for speed walking  = 10min

Speed  = 13.63?

Unknown:

Distance you can speed walk  = ?

Solution:

To solve this problem, we simply apply the velocity - time equation;

 Speed  = \(\frac{distance}{time}\)  

 Distance  = speed x time

make sure you speed and time are in the same unit

 Insert the parameters and solve

Problem 11.14 A woman of mass m stands at the edge of a solid cylindrical platform of mass M and radius R. At t 0, the platform is rotating with negligible friction at angular velocity wo about a vertical axis through its center, and the woman begins walking with speed v (relative to the platform) toward the center of the platform

Answers

This can be expressed as,T2 = (M + m)aT1 = Mg/2where,T2−T1= (M + m)a − Mg/2 Solving the above equations will give the value of α and then we can find out the final velocity of the platform.

Here's the solution to the given problem: Let the origin of our coordinate system be located at the center of the platform. We can assume that there is no friction between the platform and the ground. If v  Rw, the woman will collide with the center of the platform after the platform stops moving because it is not able to move with the required speed to reach the center of the platform before it stops. The net torque about the origin, assuming that the angular momentum is conserved, is Iα = τ, or, assuming that the angular momentum is conserved,T2−T1=IwoR2wR2+mr2αT2 = Mg/2 + Mv/RT1 = (M + m)g/2Let a be the speed of the platform just after the woman reaches the center, which is given by a = v + αr. This can be expressed as,T2 = (M + m)aT1 = Mg/2where,T2−T1= (M + m)a − Mg/2Solving the above equations will give the value of α and then we can find out the final velocity of the platform.

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*A pilot performs a vertical maneuver around a circle with a radius R. When the
airplane is at the lowest point of the circle the pilot's apparent weight is 6 mg.
What is the acceleration of the plane at the lowest point?

Answers

Answer:

i think it is 5 mg is the lowest

Explanation:

1. A 1400 kg car is moving at 15 m/s when it hits a tree and comes to rest 0.30 seconds later. How
much force does the car experience?

Answers

Answer:

F = 70000  N

Explanation:

Given that,

Mass of a car, m = 1400 kg

Initial speed of the car, u = 15 m/s

Finally, it hits the ground, v = 0

Time, t= 0.3 s

We need to find the force experienced by the car. Using Newton's second law of motion to find it.

F = ma

a is acceleration of the car.

\(F=\dfrac{m(v-u)}{t}\\\\F=\dfrac{1400\times (0-15)}{0.3}\\\\=-70000\ N\)

So, the force experienced by the car has a magnitude of 70000  N.

If each contour line represents 50 meters, what is a reasonable height of the mountain peak in the topographic map? Record your answer and fill in the bubbles on your answer document. Be sure to use the correct

Answers

Answer:

Explanation:

Answer: None of the above I got it right on my test

If a 2.00 kg ball is thrown straight up world and its maximum height is 25.51 m. Approximately how much potential energy (PE) dose the ball possess when it reaches it’s maximum height (g=9.8 m/s^2)

Answers

Answer:

500

Explanation:

im not sure if this is right but if its not im very sorry and i hope you have a great day or night wherever you are

How is the blue color of a reflection nebula related to the blue color of the daytime sky?
Reflection nebulae look blue for the same reason the sky looks blue. Short wavelengths scatter more easily than long wavelengths.

Answers

The blue color of a reflection nebula is related to the blue color of the daytime sky because both phenomena are caused by the scattering of light.

In the case of the daytime sky, the blue color is due to the scattering of sunlight by the Earth's atmosphere, which causes blue light to be scattered more than other colors, making it the dominant color in the sky. In a reflection nebula, the blue color is also caused by the scattering of light, but this time it is by dust grains in the nebula reflecting light from nearby stars.

The dust grains scatter blue light more effectively than other colors, which gives the nebula its characteristic blue color. Therefore, both the blue color of the sky and the blue color of a reflection nebula are a result of the scattering of light by particles in their respective environments.

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--The complete question is, How is the blue color of a reflection nebula related to the blue color of the daytime sky?--

The energy flux from the sun has a peak value of around 1500 W/m2, and solar cells are around
15% efficient. Estimate the area needed to satisfy US energy needs using solar cells, using the
estimates that there are about 350 million people in the US and that we use an average of 90
kW/person. Also assume that there are about 6 hours of "peak" sunlight per day. Answer in square
kilometers (do not put units in your answer, however).

Answers

Answer:

Power required = 3.5E8 * 9.0E4 = 3.2E13     (watts)

Power supplied = 1.5E3 * .15 * 3600 * 6    (watts / m^2) * A

= 1.5E3* .15 * 3600 * 6 = 4.9E6 * A

A = 3.2 / 4.9 * E7 = 3.2 / 4.9 * 10 = 6.5 km*2    (1 km^2 = 10E6 m^2)

Note:  1 W = 1 J / sec    1 kw = 1000 W

The area needed to satisfy US energy needs using solar cells 6.5 km²

What is energy?

Energy is the ability or capability to do tasks, such as the ability to move an item (of a certain mass) by exerting force. Energy can exist in many different forms, including electrical, mechanical, chemical, thermal, or nuclear, and it can change its form.

Power required = 3.5E8 * 9.0E4 = 3.2E13     (watts)

Power supplied = 1.5E3 * .15 * 3600 * 6    (watts / m^2) * A

= 1.5E3* .15 * 3600 * 6 = 4.9E6 * A

A = 3.2 / 4.9 * E7 = 3.2 / 4.9 * 10

= 6.5 km*2  

The area needed to satisfy US energy needs using solar cells 6.5 km².

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When gamma rays are incident on matter, the intensity of the gamma rays passing through the material varies with depth x as I(x) = I₀ e-mu x , where I₀ is the intensity of the radiation at the surface of the material (at x=0 ) and \mu is the linear absorption coefficient. For 0.400 MeV gamma rays in lead, the linear absorption coefficient is 1.59 cm⁻¹ . (a) Determine the "half-thickness" for lead, that is, the thickness of lead that would absorb half the incident gamma rays.

Answers

The half-thickness for lead, where the thickness of lead absorbs half the incident gamma rays, is approximately 0.436 cm.

To determine the "half-thickness" for lead, we need to find the thickness of lead (x) at which the intensity of the gamma rays passing through the material is reduced to half (I(x) = (1/2)I₀).

Given:

I(x) = I₀ \(\times e^(^-^\mu ^x)\)

μ = 1.59 cm⁻¹

Setting I(x) = (1/2)I₀, we have:

(1/2)I₀ = I₀ \(\times e^(^-^\mu ^x)\)

Canceling out I₀ on both sides:

1/2 = \(e^(^-^\mu ^x)\)

Taking the natural logarithm (ln) of both sides:

ln(1/2) = ln(\(e^(^-^\mu ^x^)\))

Using the property of logarithms (ln(\(a^b\)) = b \(\times\) ln(a)):

ln(1/2) = -μx

Rearranging the equation for x:

x = -ln(1/2) / μ

Substituting the value of μ = 1.59 cm⁻¹ into the equation:

x = -ln(1/2) / 1.59 cm⁻¹

Calculating the natural logarithm:

ln(1/2) ≈ -0.6931

Substituting this value into the equation:

x = -(-0.6931) / 1.59 cm

Simplifying:

x ≈ 0.436 cm

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5. A ball with momentum of 16 kg x m/s strikes a ball at rest. What is the total momentum of both balls after the collision? a. -16kg x m/s b. -8 kg x m/s c. 8 kg x m/s d. 16 kg x m/s? help please ​

Answers

Answer:

D. 16 Kgm/s

Explanation:

Let the momentum of the two balls be A and B respectively.

Momentum A = 16 kgm/s

Momentum B = 0 kgm/s (since the ball is at rest).

Total momentum = A + B

Total momentum = 16 + 0

Total momentum = 16 Kgm/s

Momentum can be defined as the multiplication (product) of the mass possessed by an object and its velocity. Momentum is considered to be a vector quantity because it has both magnitude and direction.

Mathematically, momentum is given by the formula;

Momentum = mass * velocity

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what is the solution to this system of equations? We have the following CFG with terminals 'a', 'b', and 'c': S AB | BC A BA | a B CC | b C AB | a Given the above CFG, perform the CKY parsing on the two strings "aaaaa" and "baaaaba". You should derive all possible parse trees for each string. Show all your work. What are 5 evidences that support the theory of plate tectonics?. repeat problem 5.72, but assume that the aluminum spool is to be cast using expendable-pattern casting. explain the important differences between the two patterns. A pie is split into 3 equally sizedpieces.Each piece has an area of 79 in?What is the total area of the pie? Absent an agreement to the contrary, if the buyer of land does not tender the purchase price until after the closing date, ______. Calculate. A rapid mixing unit must be designed to treat a raw water flow of 32 MGD. The tank will be circular in shape. Determine: 1. Tank dimensions 2. Detention time 3. Velocity gradient 1. Which of the following relations is a function?O {(1,2)(2,3)(3,5)(2,6)}O {(4,5)(5,1)(9,5)(2,6)}O {(4,6)(5,1)(5,9)(7,5)}O {(4,6)(5,1)(4,3)(7,5)} 234.156Manuel and Fernando are talking on the phone. Complete theirconversation with the correct form of the appropriate verb.dardecirsalirtraerponervenirManuel: Cundo_1. t a mi casa? tenemos quedecorar los carritos para las Fiestas de Quito.Fernando: Yo _2. de aqu en quince minutos y llego en media hora.Manuel: Elena 3. que la carrera (race) empieza a las dos.Fernando: Hay un desfile (parade) despus. Vas a traer tu guitarra?Manuel: S, yo la_4. . Quiero tocar una serenata quitea.Fernando: Y yo voy a cantar! Qu hacemos despus del desfile?Manuel: Elena y yo 5. una fiesta en casa. Ahora ella preparala ensalada y yo 6. la mesa.Fernando: Bueno, llego en media hora. Hasta luego! 46. Please help :)))))))) i rlly need an answer for this Why was it called Scramble for Africa? If the people of Cerritos traded with the people of Mayapn, what goods might they exchange? How about the people of Copn and the people of El Mirador? The rhetorical purpose expressed in the excerpt would most likely have been interpreted as promoting which of the following?A: Expanding suffrage rights to all White men B: Challenging Great Britains control of Canada C: Using international commerce to expand United States influence D: Investing in technology to make ocean voyages faster Find the midpoint of the segment with the following endpoints.(-8,7) and (0,1) in triangle xyz, my = 63.25 and mz = 28.8. determine the measure of the exterior angle to x. plz help...... What is a term deposite? The image is a 1963 button in support of the civil rightsmovement.What do the shaking hands on the button indicate? The weather over the winter was colder than usual, with typical days in the subzero temperature range and snow and ice common. Because of this, Drea was often cold and shivering when walking between classes. Shivering is an example of _______. please in details , describe the feature of the endocrine systemfor control in the blood glucose