calculate the speed of sound on a day when a 2350 hz frequency has a wavelength of 0.315 m.

Answer:

1) It expresses the rate (top speed) at which it can move with time.

2) P = 20 W

3) h = 18 km

Explanation:

1) Power is the rate of transfer of energy.

⇒ Power = \(\frac{Energy(or workdone)}{Time}\)

i.e P = \(\frac{E}{t}\)

Thus a car's engine power is 44000W implies that the engine of the car can propel the car at this rate. This expresses the rate (top speed) at which it can move with time.

2) m = 400g = 0.4 kg

    t = 20 s

h = 100m

g = 10 m/\(s^{2}\)

P = \(\frac{mgh}{t}\)

  = \(\frac{0.4*10*100}{20}\)

  = \(\frac{400}{20}\)

P = 20 W

3) u = 600 m/s

   g = 10 m/\(s^{2}\)

From the third equation of free fall,

\(V^{2}\) = \(U^{2}\) - 2gh

V is the final velocity, U is the initial velocity, h is the height.

0 = \((600)^{2}\) - 2 x 10 x h

0 = 360000 - 20h

20h = 360000

h = \(\frac{360000}{20}\)

  = 18000

h = 18 km

The maximum height of the bullet would be 18 km.

Given:

The mass of the car is m = 1725 kg

The initial velocity of the car is

The final velocity of the car is

The time is t = 4.4 s

To find the applied force.

Explanation:

The force can be calculated by the formula

Here, a is the acceleration.

The acceleration can be calculated as

On substituting the values, the force applied will be

Thus, the applied force is 3527.625 N

The conditions that must be satisfied for momentum to be conserved in a system are; The total external force acting on a system must be zero. In other words, the net force on the system must be zero.

If there is no net force on the system, the momentum of the system will remain constant with time.The mass of the system must remain constant with time. If the mass of the system is changing with time, the momentum of the system will also change with time. Therefore, it is essential to keep the mass of the system constant.

The collision must be elastic. In an elastic collision, the total kinetic energy of the system is conserved, and the momentum of the system is conserved. In other words, the system behaves as if there were no external forces acting on it. If the collision is not elastic, the total kinetic energy of the system will not be conserved. Instead, some of the kinetic energy will be converted into other forms of energy, such as thermal energy or sound energy.If the above three conditions are satisfied, the momentum of the system will be conserved.

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Answer:

B

Explanation:

The voltage at the inverting terminal is 7.5 V. V out is -12.5 V. The current flowing through R4 is 0.5 mA.

Given that Vn, Vout, and lout for the circuit shown below and op amp is ideal.In the circuit, current I2 flows through the 2.5 kΩ resistor.

Therefore, the voltage drop across the 2.5 kΩ resistor is given by,

Vn = I2 x R2Vn = 3 mA x 2.5 kΩ = 7.5 V

Therefore, the voltage at the inverting terminal is 7.5 V.

Since op-amp is assumed to be ideal, no current flows into the inverting and non-inverting terminals.

Therefore, current through R3 is given by,

I3 = (Vn - Vout) / R3=> Vout = Vn - I3 x R3=> Vout = 7.5 V - 4 mA x 5 kΩ=> Vout = - 12.5 V

Therefore, Vout is -12.5 V.

Let's calculate the current flowing through R4:

This current will also flow through the 5 kΩ resistor.

Let lout be the current flowing through R4.

Therefore, current through the 5 kΩ resistor is also lout.

Now, I4 + lout = I3=> I4 = I3 - lout=> I4 = 4 mA - lout

Also, I4 = (5 V - Vout) / R4=> 4 mA - lout = (5 V - (-12.5 V)) / 5 kΩ=> 4 mA - lout = 3.5 mA=> lout = 0.5 mA

Therefore, lout is 0.5 mA.

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Explanation:

Given:

Speed of sound = 1400 m/s

Total time taken = 0.4 seconds

To find:

The depth of water

Solution:

As it take 0.4 seconds for the burst to reach the seabed and return (both ways), we can deduce that it takes 0.2 seconds to reach the seabed (one way).

This is because the speed of sound is a constant.

Now, to find the depth, we use the equation

Speed = Distance/Time

Here, we know the values of speed (1400 m/s) and time (0.2 seconds). Distance is the depth of the water, which we need to find. Let the distance be x.

Therefore

1400 = x/0.2

x = 1400 * 0.2

x = 280 m

We get the depth as 280 metres.

Feel free to ask me if you didn't understand any part.

Hope this helps! :D

Answer:

Gravitational Energy

h₂ = P/ρ₂g = 85299.2 Pa/(1000 kg/m³ × 9.8 m/s²) = 85299.2 Pa/9800 kg/m ²s² = 8.7 m

About 4.5 trillion years ago, gravity brought together spinning gas and debris to create Mercury, the small planet closest to the Sun. Mercury has a solid crust, a steep slope, and a central core, just like its sibling terrestrial planets.

Calculation

The pressure due to the mercury of height h = 64 cm = 0.64 m is

P = ρ₁gh₁ where ρ₁ = density of mercury = 13600 kg/m³

P = 13600 kg/m³ × 9.8 m/s² × 0.64 m = 85299.2 Pa

Since this is the same pressure for the water,

P = ρ₂gh₂ where ρ₂ = density of water = 1000 kg/m³ and h₂ = height of

water

h₂ = P/ρ₂g = 85299.2 Pa/(1000 kg/m³ × 9.8 m/s²) = 85299.2 Pa/9800 kg/m ²s² = 8.7 m

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Mars has a thin atmosphere unlike Venus hence their surface temperature varies despite both Mars and Venus having atmospheres with mostly Carbon Dioxide

Venus and Mars are the solar system's planets, and their temperatures differ. Mars has a thin atmosphere that cannot withstand much heat.

Mars is the fourth planet in the solar system, also known as the red planet . It contains less oxygen gas than carbon dioxide. It is has a thin atmosphere and is made up of various gases.

Unlike Venus, Mars' thin atmosphere cannot retain heat and instead radiates it back into space. Venus has a thick atmosphere. It traps heat and raises the surface temperature. Mars' atmospheric particles cannot store energy and thus vary in temperature.

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Answer:

acceleration is zero m/s²

Explanation:

It is given that the train travels at constant speed (i.e speed does not change)

If speed does not change, then the train is neither accelerating or decelerating (i.e acceleration is zero)

The half-life of a first-order reaction is a constant that is related to the rate constant for the reaction: t1/2 = 0.693/k.

It is used in life-science laboratories in applications in which lower energy beta emissions are advantageous such as DNA sequencing. P can be used to label nucleotides. It is less energetic than 32P, giving a better resolution.

Phosphorus 33 is an artificial radioactive element. It is produced with a low yield by the neutron bombardment of phosphorus 31 (stable). The phosphorus 33 has a radioactive period of 25.3 days.

Phosphorus-33 atom is the radioactive isotope of phosphorus with relative atomic mass 32.971725, half-life of 25.34 days and nuclear spin (1)/2.

Phosphorus was discovered by the German merchant Hennig Brand in 1669.

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Comparing the sizes of stars, such as Star S and Star W, can be challenging due to several factors like distance, angular size, and evolutionary stage.

Distance: The first major challenge is accurately determining the distance to the stars. Without knowing the precise distances, it becomes difficult to accurately assess their sizes.

Angular Size: Stars appear as point sources of light in the sky due to their immense distances from Earth. This means that their sizes cannot be directly observed.

Evolutionary Stage: Stars evolve over time, and their sizes change as they progress through different stages of their life cycle.

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Answer:

47.2m

Explanation:

Free fall motion is motion in which the only force acting on the body is gravity.

A free-falling object is one that moves only due to the effect of gravity, and its motion is defined by Newton's second law of motion. We can use algebra to calculate the acceleration of a free-falling particle.

The student should launch the sphere at 2v₀, for the sphere will land at approximately 1.41D, which is in the 3 point zone

The given parameter are;

The distance covered by the sphere when launched at height, H = D

The velocity with which the ball reaches D = v₀

The current available height of launcher= H/2

The available velocities = v₀, and 2v₀

Now,

From H = ut + (1/2)gt², where, initial velocity of the vertical motion of the ball, u = 0

we know;

H = (1/2)gt²

Therefore, the time it takes the ball to drop from H, t = √(2H/g)

The distance, D = v₀ × √(2H/g)

When the height is H/2, we get;

t = √(2H/(2g)) = √(H/g)

Thus, the distance covered, D₁ = v₀ × √(H/g)

Therefore, D = (√2) × v₀ × √(H/g) = (√(2))D₁

Now, D₁ = D/(√2) ≈ 0.71D

D₁ ≈ 0.71D

At speed 2v₀, we have;

D₂ = 2v₀ × √(H/g) = √2 × v2 × v₀ × √(H/g) = √2 × v₀ × √(2H/g) = √2D₁ ≈ 1.41D

D₂ ≈ 1.41D

The 2 point zone = D/2 < x < D = 0.5D < x < D (Position D₁ ≈ 0.71D is located here)

The 3 Point Zone =  D < x < 3D/2 = D < x < 1.5D (Position D₂ ≈ 1.41D is located here)

Given that at D₂, the ball lands in the 3 Point Zone, the student should launch the sphere at the speed, 2v₀, so that the ball will land at D₂ ≈ 1.41D,  which is in the 3 Point Zone

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The complete question is as follows:

A group of students prepare for a robotic competition and build a robot that can launch large spheres of mass M in the horizontal direction with variable speed and from a variable vertical position and a fixed horizontal position x=0.

The robot is calibrated by adjusting the speed at which the sphere is launched and the height of the robot’s sphere launcher. Depending on where the spheres land on the ground, students earn points based on the accuracy of the robot. The robot is calibrated so that when the spheres are launched from a vertical position y=H and speed v0, they consistently land on the ground on a target that is at a position x=D. Positive directions for vector quantities are indicated in the figure.

When the students arrive at the competition, it is determined that the height of the sphere launcher can no longer be adjusted due to a mechanical malfunction. Therefore, the spheres must be launched at a vertical position of y=H2. However, the spheres may be launched at speed v0 or 2v0.

Question: In a clear response that may also contain diagrams and/or equations, describe which speed, v0 or 2v0, the students should launch the sphere at so that they earn the maximum number of points in the competition.

The rocket's height when it was initially launched is 311 meters above sea level.

The rocket's height, in meters above sea level, is described by the equation h = -4.9t^2 + 286t + 311. To determine the rocket's height after 7 seconds, we substitute t = 7 into the equation and solve for h. Additionally, to find the height when the rocket was initially launched, we substitute t = 0 into the equation and calculate h.

To find the rocket's height after 7 seconds, we substitute t = 7 into the equation h = -4.9t^2 + 286t + 311:

h = -4.9(7)^2 + 286(7) + 311

h = -4.9(49) + 2002 + 311

h = -240.1 + 2002 + 311

h = 2072.9 meters

Therefore, the rocket's height after 7 seconds is 2072.9 meters above sea level.

To determine the height when the rocket was initially launched, we substitute t = 0 into the equation:

h = -4.9(0)^2 + 286(0) + 311

h = 0 + 0 + 311

h = 311 meters

Hence, the rocket's height when it was initially launched is 311 meters above sea level.

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→ The charge in electron charge Q(e) is equal to the charge in coulombs Q(C) times 6.24150975⋅1018:

1C = 6.24150975⋅10¹⁸e

Q(e) = Q(C) × 6.24150975 × 10¹⁸

Q(e) = 96,500 × 6.24150975 × 10¹⁸

Q(e) = 6.02305690875 × 10²³

which is round off to

→ 6.03 × 10²³ electrons

Answer:

Balanced

Explanation:

If a stationary object is staying still (in this case it's the ball) all of the forces acting upon it are balanced. If an object moving has balanced forces, it would move in the same direction at the same speed until a different outside force interrupts the equilibrium.

Hope this helps :)

This question involves the concepts of Newton's Second Law and Balanced Force.

The forces acting upon the ball are "Balanced".

According to Newton's Second Law whenever an unbalanced force is applied on an object, it produces an acceleration in the object in the direction of the force itself. This acceleration is directly proportional to the magnitude of the force and inversely proportional to the mass of the object.

Since, the ball is at rest and not moving. Hence, it has no acceleration and no unbalanced force is applied on it. The weight of the ball is balanced by the normal reaction provided by the table. Therefore, the forces acting on the ball are Balanced Forces.

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23.38 ° to the positive x-axis

Explanation

Step 1

draw the vectors

Step 2

add the vectors, ( component to component)

so

a) get the components of V1

b) components of V2

c) add

so, the magnitude of the displacement is

finally, the direction

as we have a rigth triangle

let

opposite side= 12.9

adjacent side=23.8

Now, use the tan function to find the angles

so

therefore, the direction of the resultant is

23.38 ° to the positive x-axis

I hope this helps you

The speed of sound in the pipe is 150m/s and that found to be enhanced when air column is 150 mm long.

a two-pronged metal tool used for tuning musical instruments and determining standard pitch that produces a set tone when struck.

ΔL = 150mm => 0.15m = λ/2

               =>  λ = 2 x 0.15 => 0.3 m

The velocity of sound => frequency x wavelength

                                         500hz x 0.3 m  => 150m/s

The length of a tuning fork's prongs determines the pitch it produces. Each fork has a stamp that says the note it makes (for example, A) and the frequency in Hertz (e.g. 440 Hz). Higher pitch (frequency) noises are produced by shorter prongs than by longer prongs.

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Answer:

12V

Explanation:

from the formula, I=V/R

V=IR

V=24x0.50

Voltage difference in a circuit = 12V

Answer:

thank you

Explanation:

Split up the two given velocity vectors into horizontal and vertical components.

Plane:

p = (100 km/h) (cos(90°) i + sin(90°) j ) = (100 km/h) j

Its direction is given, 90° relative to east.

Traveling for 3 hours with this velocity results in a displacement of

p * (3 h) = (300 km/h) (3h) j = (900 km) j

meaning that this velocity contributes to a north-facing displacement of 900 km.

Wind:

w = (30 km/h) (cos(315°) i + sin(315°) j ) ≈ (21.2 km/h) i + (-21.2 km/h) j

Its direction is also given, 315° relative to east.

After 3 h, this velocity contributes to a displacement of

w * (3h) ≈ (63.6 km) i + (-63.6 km) j

meaning if the plane had no velocity of its own but somehow stayed in the air, the wind would have pushed it about 63.6 km south and 63.6 km east, which translates to a net displacement of

√((63.6 km)² + (-63.6 km)²) = 90 km

due southeast.

Putting everything together, your table displacement table should read:

.                       |   wind   |   plane

velocity           |   30      |   100       ...   km/h

direction         |   90°     |   315°      ...   relative to east

x                      |   63.6   |   0           ...   km

y                      |  -63.6   |   900      ...   km

The resultant vector is the sum of these, r = p + w :

r ≈ (21.2 km/h) i + (78.8 km/h) j

After 3 h, the resultant displacement is

r * (3h) ≈ (63.6 km) i + (236.4 km) j

with magnitude

√((63.6 km)² + (236.4 km)²) ≈ 244.8 km

and direction θ such that

tan(θ) ≈ (236.4 km) / (63.6 km)

θ ≈ arctan(3.714) ≈ 74.9°

So the resultant table should read

xnet             |   63.6 km

ynet             |   236.4 km

magnitude   |   244.8 km

theta            |   74.9° relative to east

To obtain the characteristic function of a diode, you should use a device-level simulation. This type of simulation models the physical behaviour of the diode and allows you to analyze its characteristics, such as its current-voltage relationship.

A device-level simulation is a type of computer-aided design tool used to model the physical behaviour of electronic devices, such as diodes. It enables the analysis of the device's characteristics, such as its current-voltage relationship, which is essential for understanding its behaviour in electronic circuits. The simulation uses mathematical models that describe the underlying physical processes and material properties of the diode. This allows engineers to optimize the design of the diode and predict its behaviour under different conditions before actually building a physical prototype. In the case of diodes, the simulation can provide the characteristic function, which is a mathematical representation of the diode's response to different input voltages.

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The stopper travels approximately 4.5 meters horizontally before hitting the ground.

We can use conservation of energy to solve this problem. At the highest point of the stopper's motion, all of its energy is in the form of potential energy, and at the lowest point (when it hits the ground), all of its energy is in the form of kinetic energy.

The potential energy of the stopper at the highest point is:

Ep = mgh

where m is the mass of the stopper, g is the acceleration due to gravity, and h is the height above the ground. Plugging in the values given in the problem, we get:

Ep = (0.150 kg) * (9.81 m/s²) * (2.3 m) ≈ 3.2 J

At the lowest point, all of the potential energy has been converted to kinetic energy:

Ek = (1/2) * mv²

where v is the speed of the stopper just before it hits the ground. Since the stopper is released from rest, we can use conservation of energy to equate the potential energy at the highest point to the kinetic energy just before hitting the ground:

Ep = Ek

mgh = (1/2) * mv²

Solving for v, we get:

v = √(2gh)

where h is the height from which the stopper was released. Plugging in the values given in the problem, we get:

v = √(2 * 9.81 m/s² * 2.3 m) ≈ 6.6 m/s

Now we can use the time it takes for the stopper to fall to the ground to calculate the horizontal distance it travels. The time is given by:

t = √(2h/g)

Plugging in the values given in the problem, we get:

t = √(2 * 2.3 m / 9.81 m/s²) ≈ 0.68 s

During this time, the stopper travels a horizontal distance given by:

d = vt

Plugging in the values we just calculated, we get:

d = (6.6 m/s) * (0.68 s) ≈ 4.5 m

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The five pillars of safety are engineering, encouragement, enforcement, and evaluation. Your strategy to ensure that you promote a safe environment and workplace should heavily emphasize education.

By exercising your intellect beforehand, you may be able to save a life or at least lessen someone else's suffering. The three fundamental Cs are check, call, and care.

A Framework for Aligning the 14 Process Safety Management Elements. To prevent the release of extremely hazardous substances, it is essential to use related techniques to managing hazards, although it might be difficult to put Process Safety Management's operational goals into effect.

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The break-even price for the call option is $206. This means that if the price of the underlying asset (e.g., stock) is above $206 at expiration, the option will be profitable. If the price of the underlying asset is below $206, the option will be unprofitable.

To calculate the break-even price for a call option, you need to add the premium paid for the option to the strike price.

In this case, you purchased one 200 call option for a premium of $6. The strike price of the option is 200.

The break-even price can be calculated as follows:

Break-even price = Strike price + Premium

Break-even price = 200 + 6

Break-even price = 206

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Answer:

A E and F are the correct answers

Explanation:

Answer:

A E F are correct

Explanation:

Han and Greedo are at the rear and front of a relativistic train travelling at speed in opposite directions. In the frame of reference of the train (S'), Han is located at x' = 0, and Greedo is at x' = L'.

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Answer:

The person should exercise 150 minutes

Explanation:

Recall that the Lorentz factor must be applied to the relationship between the elapsed time (T) of the clock at rest (time measured on Earth), and the elapsed time (T') measured by the clock in the frame moving at 0.8 c. The equation becomes:

\(T'=\frac{T}{\sqrt{1-(\frac{0.8\,c}{c})^2 } } \\T'=\frac{90\,min}{\sqrt{1-0.8^2} } \\T'=150\,\,min\)

The position of John at time of 4.35 s is -1.13 m

From the given chart;

The average acceleration is calculated as follows;

The position of John at time, t = 4.35 s is calculated as follows;

\(x(t) = ut + \frac{1}{2} at^2\\\\x(4.35) = (-2 \times 4.35) \ + \ 0.5\times 0.8\times( 4.35)^2\\\\x(4.35) = -8.7 \ + \ \ 7.569\\\\x(4.35) = - 1.13 \ m\)

Thus, the position of John at time of 4.35 s is -1.13 m

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The star is moving away from Earth at a velocity of 1.8 x 106 m/s.

The Doppler Effect describes the shift in wavelength of a wave when the source is moving in relation to the observer. The shift can be observed in sound waves, light waves, and other waves.

The Doppler Effect can be used to determine the velocity of objects moving away from an observer, as in the case of stars moving away from Earth.

The velocity of a star moving away from Earth can be determined using the equation:

v = Δλ/λ x c, Where v is the velocity of the star, Δλ is the shift in wavelength of the spectral line, λ is the wavelength of the spectral line measured in the lab on Earth, and c is the speed of light (3.00 x 108 m/s).

In this case, the shift in wavelength of the spectral line is Δλ = 500.3 nm - 500 nm = 0.3 nm.

The wavelength of the spectral line measured in the lab on Earth is λ = 500 nm.

Plugging in these values to the equation above: v = Δλ/λ x cv = (0.3 nm / 500 nm) x (3.00 x 108 m/s) = 1.8 x 106 m/s.

Therefore, velocity of star 1.8 x 106 m/s.

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