Calculate the root mean square velocity of the nitrogen molecules, in meters per second (m/s). Do not include the unit of measure in your answer.

Answer:  

t = 1.27 x 10⁹ s  

Explanation:  

First, we will find the volume of the wire:

Volume = V = AL  

where,  

A = Cross-sectional area of wire = πr² = π(1 cm)² = π(0.01 m)² = 3.14 x 10⁻⁴ m²  

L = Length of wire = 150 km = 150000 m  

Therefore,    

V = 47.12 m³

Now, we will find the number of electrons in the wire:  

No. of electrons = n = (Electrons per unit Volume)(V)  

n = (8.43 x 10²⁸ electrons/m³)(47.12 m³)  

n = 3.97 x 10³⁰ electrons  

Now, we will use the formula of current to find out the time taken by each electron to cross the wire:

\(I =\frac{q}{t}\)  

where,  

t = time = ?  

I = current = 500 A  

q = total charge = (n)(chareg on one electron)  

q = (3.97 x 10³⁰ electrons)(1.6 x 10⁻¹⁹ C/electron)  

q = 6.36 x 10¹¹ C  

\(500\ A = \frac{6.36\ x\ 10^{11}\ C}{t}\\\\t = \frac{6.36\ x\ 10^{11}\ C}{500\ A}\)

Therefore,

t = 1.27 x 10⁹ s

Please find attached photograph for your answer.

Hope it helps.

Do comment if you have any query.

Answer:

A is the load in the diagram

Answer:

i think the answer is A

Answer:

the water will float over mercury and the steel ball will be in it's respected place

The acceleration of the combined mass of Maggie and her snowmobile will be 1.072 meters per second square.

If the acceleration is constant throughout the motion. Then the equation of the motion is given as,

v = u + at

Where 'v' is the final velocity, 'u' is the initial velocity, 't' is the time, and 'a' is the acceleration.

In an attempt to chase her brother Jason, she accelerates from 6.6 m/s to 25.9 m/s in a time of 18.0 seconds.

Then the acceleration is calculated as,

25.9 = 6.6 + a(18)

18a = 19.6

a = 1.072 meters per second square

The acceleration of the combined mass of Maggie and her snowmobile will be 1.072 meters per second square.

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The average acceleration of the motorcycle over the given distance is approximately 9.39 m/s².

To calculate the average acceleration of the motorcycle, we can use the formula:

Average acceleration = (final velocity - initial velocity) / time

First, let's convert the final velocity from km/h to m/s since the distance is given in meters. We know that 1 km/h is equal to 0.2778 m/s.

Converting the final velocity:

Final velocity = 78 km/h * 0.2778 m/s = 21.67 m/s

Since the motorcycle starts from rest (initial velocity is zero), the formula becomes:

Average acceleration = (21.67 m/s - 0 m/s) / time

To find the time taken to reach this velocity, we need to use the formula for average speed:

Average speed = total distance/time

Rearranging the formula:

time = total distance / average speed

Plugging in the values:

time = 50 m / 21.67 m/s ≈ 2.31 seconds

Now we can calculate the average acceleration:

Average acceleration = (21.67 m/s - 0 m/s) / 2.31 s ≈ 9.39 m/s²

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Answer:

30°

Explanation:

The law of reflection tells us that when a ray of light hits and then gets reflects off a surface, the angle of incidence is equal to the angle of reflection.

Mathematically, from the law of reflection,

θ(i) = θ(r)

Also,

θ(i) + θ(r) = 2θ(i).......since θ(i) = θ(r)

θ(i) + θ(r) = 22 + 2(4)

θ(i) + θ(r) = 22 + 8

θ(i) + θ(r) = 30°

Therefore, the new angle between the incident and reflected beams will then be 30°

Answer:

I don't think so because if Ape was the same weight as george I don't

think he can hold him but maybe so let's say he could hold his own ape then Yes I think he could make it to the ledge Now I think they could make it to the ledge which was half the size.

Sorry if this sounded weird English is my 2nd language Oh and if this helped please give brainiest thank you <3

Answer:

Marine geologists learn about the rocks and geologic processes of the ocean basins.

The magnitude of the electric field at a point directly between the two balls is\(-2.81 \times 10^6 N/C\)

The electric field magnitude is the strength of the electric field in a certain region or at a point. It is usually measured in units of volts per meter (V/m). The electric field is a vector quantity that represents the force exerted by an electric field on a charged particle, such as an electron. It is defined by the equation E = F/q, where E is the electric field magnitude, F is the force exerted on the particle, and q is the charge of the particle.

The electric field magnitude can be calculated by measuring the force applied to a charged particle in a certain region and then dividing it by the charge of the particle.

Calculation of Electric field magnitude

The electric field equation, which states that the electric field is equal to the constant \(k (8.99 \times 10^9 Nm^2/C^2)\) times the charge \((3.80 nC + -7.40 nC = -3.60 nC)\) divided by the distance between the two balls \((32.5 cm)\) squared.

Electric field =\(kQ/r^2\)

\(r = 32.5 cm\\Q = 3.80 nC + -7.40 nC = -3.60 nC\\k = 8.99 \times 10^9 Nm^2/C^2\\Electric field = (8.99 \times 10^9 Nm^2/C^2)(-3.60 nC)/(32.5 cm)^2\\Electric field = -2.81 \times 10^6 N/C\)

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Answer:

a) 103.176 m / min

b) 1751.28 meters

Explanation:

Given:-

- Emma's and Lily's velocities ( E(t) and L(t) ) are given as functions respectively:

                         \(E(t) = \frac{7510}{t^2-7t + 80.22} \\\\L ( t ) = 12t^3*e^-^0^.^5^t\)

- Where, E ( t ) and L ( t ) are given in m / min

- Both run for a total time of 15 minutes in the same direction along the straight track defined by the absolute interval:

                         ( 0 ≤ t ≤ 15 ) mins                  

- It is known that Emma is 10 meters ahead of Lily at time t = 0.

Find:-

a) Find the value of \(\frac{1}{6}*\int\limits^8_2 {E(t)} \, dt\) using correct units, interpret the meaning of

b) What is the maximum distance between Emma and Lily over the time interval 0 ≤ t ≤ 15?  

Solution:-

- The average value of a function f ( x ) over an interval [ a , b ] is determined using calculus via the following relation:

                          \(f_a_v_g = \frac{1}{b-a}\int\limits^a_b {f(x)} \, dx\)

- The first part of the question is asking us to determine the average velocity of Emma over the time interval of ( 2 , 8 ). Therefore, ( E_avg ) can be determined using the above relation:

                         \(E_a_v_g = \frac{1}{8 - 2}*\int\limits^8_2 {E(t)} \, dt\\\\E_a_v_g = \frac{1}{6}*\int\limits^8_2 {E(t)} \, dt\\\)

- We will evaluate the integral formulation above to determine Emma's average velocity over the 2 ≤ t ≤ 8 minute range:

                         \(E_a_v_g = \frac{1}{6}*\int\limits^8_2 {\frac{7510}{t^2 - 7t + 80.22} } \, dt\\\\E_a_v_g = \frac{1}{6}*37550\int\limits^8_2 {\frac{1}{50t^2 - 350t + 4011} } \, dt\\\\\)

- Complete the square in the denominator:

                          \(E_a_v_g = \frac{1}{6}*37550\int\limits^8_2 {\frac{1}{(5\sqrt{2}*t - \frac{35}{\sqrt{2} })^2 + \frac{6797}{2} } } \, dt\\\\\)

- Use the following substitution:

                          \(u = \frac{5*(2t - 7 )}{\sqrt{6797} } \\\\\frac{du}{dt} = \frac{10}{\sqrt{6797} } \\\\dt = \frac{\sqrt{6797}}{10}.du\)

- Substitute the relations for (u) and (dt) in the above E_avg expression.

                          \(E_a_v_g = \frac{1}{6}*37550\int {\frac{\sqrt{6797} }{5*(6797u^2 + 67997) } } \, du\\\\E_a_v_g = \frac{1}{6}*37550*\frac{1}{5\sqrt{6797}} \int {\frac{1 }{(u^2 + 1) } } \, du\)

- Use the following standard integral:

                          \(arctan(u) = \int {\frac{1}{u^2 + 1} } \, du\)

- Evaluate:

                         \(E_a_v_g = \frac{1}{6}*37550*\frac{1}{5\sqrt{6797}}* arctan ( u ) |\)

- Apply back substitution for ( u ):

                        \(E_a_v_g = \frac{1}{6}*[\frac{75100* arctan ( \frac{5*(16 - 7 )}{\sqrt{6797} } )}{\sqrt{6797} } - \frac{75100* arctan ( \frac{5*(4 - 7 )}{\sqrt{6797} } )}{\sqrt{6797} } ]\\\\\)

- Plug in the limits and find Emma's average velocity:

                        \(E_a_v_g = 151.82037*[arctan (0.54582 ) - arctan ( -0.18194 ) ]\\\\E_a_v_g = 103.176 \frac{m}{min}\)

Answer: Emma's average speed over the interval ( 2 ≤ t ≤ 8 ) is 103.179 meters per minute.

- The displacement S ( E ) of Emma from time t = 0 till time ( t ) over the absolute interval of  0≤t≤15 is given by the relation:

                    \(S (E) = S_o + \int\limits^t_0 {E(t)} \, dt\\\\S ( E ) = 10 + \frac{75100*arctan( \frac{5*(2t - 7 )}{\sqrt{6797} }) }{\sqrt{6797} } |_0^t\\\\S ( E ) = 10 + [ \frac{75100*arctan( \frac{5*(2t - 7 )}{\sqrt{6797} }) }{\sqrt{6797} } - \frac{75100*arctan( \frac{5*(0 - 7 )}{\sqrt{6797} }) }{\sqrt{6797} } ]\\\\S ( E ) = \frac{75100*arctan( \frac{5*(2t - 7 )}{\sqrt{6797} }) }{\sqrt{6797} } + 375.71098\\\)

- The displacement S ( L ) of Lily from time t = 0 till time ( t ) over the absolute interval of  0 ≤ t ≤ 15 is given by the relation:

                    \(S (L) = \int\limits^t_0 {L(t)} \, dt\\\\S (L) = \int\limits^t_0 ({12t^3 *e^-^0^.^5^t } )\, .dt\\\)

 Apply integration by parts:

  \(S ( L ) = 24t^3*e^-^0^.^5^t - 64*\int\limits^t_0 ({e^-^0^.^5^t*t^2} \,) dt\\\)

 Re-apply integration by parts 2 more times:

 \(S ( L ) = -24t^3*e^-^0^.^5^t + 64*[ -2t^2*e^-^0^.^5^t - 2\int\limits^t_0 ({e^-^0^.^5^t*t} \,) dt ]\\\)             \(S ( L ) = -24t^3*e^-^0^.^5^t + 64*[ -2t^2*e^-^0^.^5^t - 2*( -2t*e^-^0^.^5^t - (4e^-^0^.^5^t - 4 ) ]\\\\\)    

\(S ( L ) = e^-^0^.^5^t* ( -24t^3 -128t^2+ 256t + 512) - 512 \\\)

- The distance between Emma and Lily over the time interval 0 < t < 15 mins can be determined by subtracting S ( L )  from S ( E ):

                    \(S = S ( E ) - S ( L )\\\\S = \frac{75100*arctan( \frac{5*(2t - 7 )}{\sqrt{6797} }) }{\sqrt{6797} } - e^-^0^.^5^t* ( -24t^3 -128t^2+ 256t + 512) + 887.71098\\\)

- The maximum distance ( S ) between Emma and Lily is governed by the critical value of S ( t ) for which function takes either a minima or maxima.

- To determine the critical values of the function S ( t ) we will take the first derivative of the function S with respect to t and set it to zero:

              \(\frac{dS}{dt} = \frac{d [ S(E) - S(L)]}{dt} \\\\\frac{dS}{dt} = E(t) - L(t) \\\\\frac{dS}{dt} = \frac{7510}{t^2 - 7t+80.22} - 12t^3*e^-^0^.^5^t = 0\\\\( 12t^5 - 84t^4 + 962.64t^3) *e^-^0^.^5^t - 7510 = 0\\\\t = 4.233 , 11.671\)

- We will plug in each value of t and evaluate the displacement function S(t) for each critical value:

If a swimmer swims the 50m length of a swimming pool in 15.91 second and makes the return swim in 18 seconds then the swimmer's average speed for the full swim is 2.948 metres per second.

To find the swimmer's average speed for the full swim, we need to calculate the total distance swum and the total time taken.
The swimmer swam the 50m length of the pool twice, once in 15.91 seconds and once in 18 seconds. So the total distance swum is 50m + 50m = 100m.
The total time taken is the sum of the time taken for each length: 15.91 seconds + 18 seconds = 33.91 seconds.
To find the swimmer's average speed, we divide the total distance by the total time:
Average speed = total distance ÷ total time
= 100m ÷ 33.91 seconds
= 2.948 metres per second
Therefore, the swimmer's average speed for the full swim is 2.948 metres per second. This is a relatively fast speed, but it's important to note that the swimmer's speed may vary depending on their stroke technique, physical fitness, and other factors. Nonetheless, it's an impressive achievement for the swimmer to complete the full 100m in under 34 seconds.

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Answer:

The correct answer is option A: 3.00 × 10^(-11) m.

Explanation:

To find the wavelength of a gamma ray with a frequency of about 10^19 s^(-1), we can use the equation:

wavelength = speed of light / frequency

Given:

Speed of light (c) = 3.00 × 10^8 m/s

Frequency (f) = 10^19 s^(-1)

Substituting the values into the equation:

wavelength = (3.00 × 10^8 m/s) / (10^19 s^(-1))

To simplify the expression, we can rewrite the denominator as (1 / 10^(-19)) s:

wavelength = (3.00 × 10^8 m/s) / (1 / 10^(-19)) s

To divide by a fraction, we multiply by its reciprocal:

wavelength = (3.00 × 10^8 m/s) × (10^(-19) s)

Applying the properties of exponents, we can add the exponents when multiplying with the same base:

wavelength = 3.00 × 10^(-11) m

Therefore, the wavelength of the gamma ray is approximately 3.00 × 10^(-11) m.

The weight of 15N should be hung at a distance of 4/3 units from the fulcrum, on the opposite side of the bar to a weight of 20N.

The fulcrum is attained equilibrium when the principle of moments is equal to zero. The principle of momentum is defined as the body is said to be balanced when the clockwise movement about the point is equal to the anticlockwise movement about the same point.

When a weight of 15N is hung on the bar, it produces an anticlockwise movement with the same magnitude, opposes the clockwise moment produced by the weight of 20N on the fulcrum.

To find the distance (d) at which the 15N weight should be hung, the distance from the 20N weight to the fulcrum is 1 unit.

20×1 = 15×d

d = 20/15

  =4/3 m

Thus, the weight of 15N should be hung by the distance of 4/3 units from the fulcrum, on the opposite side of the bar having the weight of 20N, to make the fulcrum to be at equilibrium.

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Answer:

I believe the answer is 62.25 N

Explanation:

You just multiply 7.5 and 8.3 and you get 62.25

Answer:

62.25N or 62.25 newtons

Explanation:

F=ma where F is the force in newtons, m is the mass in kilograms (kg), and a is the acceleration

m=7.5kg

a=8.3m/s^2

Therefore, F=ma=7.5*8.3=62.25N

The amount of force is 62.25N or 62.25 newtons

Answer:

I believe it is true hope that helps

Answer:

The sugars produced by photosynthesis can be stored, transported throughout the tree, and converted into energy which is used to power all cellular processes. Respiration occurs when glucose (sugar produced during photosynthesis) combines with oxygen to produce useable cellular energy.

Explanation:

I think this is correct lol.

Answer:240 meters

Explanation:60×4

Answer:

The car will stop moving

Explanation:

If a balanced force is applied to the car in motion, the car will stop accelerating and remain stationary because all the forces acting on the car are equal.

Also, you can say, since a balanced force is applied, the net force or resultant force on the car is zero. According to Newton's second law of motion, an object will move in the direction of the applied force. When the resultant force on the object is zero, it means the object will not move.

If both runner A and runner B start the race together, they will 1.125 m apart at the finish of the race

v = d / t

v = Velocity

d = Distance

t = Time

d = 4.5 m

For runner A,

t = 4.5 min

v = 4.5 / 4.5

v = 1 m / min

For runner B,

t = 6 min

v = 4.5 / 6

v = 0.75 m / min

Runner A finished the race first at 4.5 min. At that time the runner B will have covered,

0.75 = d / 4.5

d = 0.75 * 4.5

d = 3.375 m

Difference in distances = 4.5 - 3.375

Difference in distances = 1.125 m

Therefore, they will 1.125 m apart at the finish of the race

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Answer:

Explanation:

To find the current flowing in the circuit, we can use Ohm's Law and Kirchhoff's circuit laws.

Ohm's Law states that the current (I) flowing through a circuit is equal to the voltage (V) divided by the resistance (R):

I = V / R

In this case, the voltage (V) is the electromotive force (EMF) of the current source, which is 14 V. The total resistance (R) in the circuit is the sum of the internal resistance (r) and the resistances of the two resistors (R1 and R2):

R = r + R1 + R2

Given that the internal resistance (r) is 1Ω and each resistor (R1 and R2) has a resistance of 3Ω, we can substitute these values into the equation:

R = 1Ω + 3Ω + 3Ω = 7Ω

Now we can calculate the current (I):

I = V / R = 14 V / 7Ω = 2 A

Therefore, the current flowing in the circuit is 2 Amperes.

Velocity = distance / time  = 300m / 100s

            = 3 m/s

Velocity is the direction at which an object is moving and serves as a measure of the rate at which its position is changing as seen from a specific point of view and as measured by a specific unit of time (for example, 60 km/h northbound).

A physical vector quantity called velocity must have both a magnitude and a direction in order to be defined.

Speed is the scalar absolute value (magnitude) of velocity; it is a coherent derived unit whose quantity is measured in metres per second (m/s or m/s1) in the SI (metric system).

Therefore, Velocity = distance / time  = 300m / 100s

            = 3 m/s

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ANSWER:

1800 cm³

STEP-BY-STEP EXPLANATION:

Initial volume (V1) = 600 cm³

We know that the pressure is reduced to one-third of the initial pressure, therefore:

The volume would be 1800 cm³

The heat transfer in the winds, the earths oceans and the earths mantle are as a result of the rising and falling of heat, water and hot magma respectively.

This is referred to as a process of heat transfer which occurs in fluid substances such as gas and liquids and ensures uniform distribution of the heat content.

Heat transfer which is characterized by heat rising and the cool air falling results in the formation of wind while the rising and cooling of warm water results in the formation of the earth's ocean through the various types of precipitation which is experienced.

Convection currents arise from the convection process and ensures that energy is transferred from one place to another. This makes sure the heat transfer is achieved and uniformly distributed between the substances involved.

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Answer:

Fission reactors are used to generate electricity, but fusion is not yet practical enough to be used

Explanation:

The nuclear fission process a nucleus of a 235U heavy atom is bombarded with neutrons and disintegrates into two smaller nuclei, releasing some neutrons and energy, which can be used to generate electricity.

In the process of nuclear fusion the union of light nuclear produces heavier nuclei, this process is still in the experimental phase and there are no commercial reactors for the production of electricity.

Checking the different statements is correct :

Fission reactors are used to generate electricity, but fusion is not yet practical enough to be used

Nuclear fission reactors are used to generate electricity, but fusion is not yet practical enough to be used.

Nuclear reactions are reactions which involves changes in the nucleus of atoms which produces large amounts of energy known as nuclear energy.

The two types of nuclear reactions are:

Nuclear fission reactors are used to generate electricity, but fusion is not yet practical enough to be used.

Therefore, nuclear reactions produce energy by means of fission reactions.

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The temperature remains constant while the substance is changing state.The correct answer is option C.

When a substance undergoes a change of state, such as melting, boiling, or condensing, the temperature of the substance remains constant during the phase transition. The process of changing state requires the absorption or release of heat energy without a change in temperature.

For example, when a solid is heated, its temperature increases until it reaches the melting point. At this point, the substance starts to change from a solid to a liquid, but the temperature remains constant until all the solid has melted.
The absorbed heat energy is used to break the intermolecular forces holding the particles together, rather than increasing the kinetic energy of the particles.

Similarly, during the process of condensation or freezing, a substance releases heat energy as it changes state. This released energy is used to form intermolecular forces and convert the substance from a gas to a liquid or a liquid to a solid. The temperature remains constant until the phase transition is complete.
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1 Therefore, the kinetic frictional force experienced by the block on the incline is 6.784 N.

2 The magnitude of the velocity of the block at point B is approximately 5.11 m/s.

1. The formula for the kinetic frictional force is given by f = μN, where μ is the coefficient of kinetic friction and N is the normal force. Since the block is on an incline, the normal force can be calculated as N = mg * cos(θ), where θ is the angle of inclination.

N = 4 kg * 9.8 m/s² * cos(30°) = 33.92 N

f = 0.2 * 33.92 N

= 6.784 N

2. Potential energy at point A = mgh, where h is the vertical height of the incline.

Potential energy at point A = 4 kg * 9.8 m/s² * 3 m * sin(30°)

= 58.8 J

The work done by friction is given by W = f * d, where d is the distance traveled along the incline (3 m).

Work done by friction = 6.784 N * 3 m = 20.352 J

Since the work done by friction is negative (opposite to the direction of motion), the total work done on the block is:

Total work = Potential energy at A - Work done by friction

Total work = 58.8 J - 20.352 J = 38.448 J

According to the work-energy theorem, this work done on the block is equal to the change in its kinetic energy. Therefore, we have:

38.448 J = 0.5 * 4 kg * B²

Solving for B, we find:

B = √(38.448 J / (0.5 * 4 kg)) ≈ 5.11 m/s

Therefore, the magnitude of the velocity of the block at point B is approximately 5.11 m/s.

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