Calculate the international/military completion times. (Express your answer using a whole number. Round to the nearest minute) An IV started at 0546 to complete in 4 hr 20 min

Answer:

Its 8

Step-by-step explanation:because u add then divide and subtract

There are 13 diamonds in the deck (as well as other colors). Since there are 52 cards, the probability of getting a diamond on the first draw is 13/52. After the first card is drawn, all that's left are his 12 diamonds. Therefore, the probability of drawing a diamond is 12/51 (note that he has only 51 cards left after pulling/removing the first card since there are no replacement cards). The overall probability is the product of two possibilities. The odds of drawing diamonds from the original deck are 13/52 times the odds of drawing diamonds from his remaining 51 cards. Assuming the first card drawn is a diamond, 12/51.

P=13/52*12/51=1/4*4/17=1/17.

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Answer:

\(A' = (-4,4)\)

Step-by-step explanation:

Given

\(A = (-2,2)\)    \(B = (1,3)\)       \(C = (1,0)\)

\(k =2\) --- scale factor

Required

Determine A'

This is calculated as:

\(A' = A * k\)

\(A' = (-2,2) * 2\)

\(A' = (-2 * 2,2 * 2)\)

\(A' = (-4,4)\)

Answer:

\(d(t) = -23t +556\)

Step-by-step explanation:

Assuming the hurricane continues on the same path at the same speed means the relationship between speed and time will be linear. This means our function can be written in slope-intercept form, \(y=mx+b\). For our function, it will be written as \(d(t)=mt+b\), where t is time, d is distance, m is the slope of the line, and b is the y-intercept. We can solve for slope by using the formula \(\frac{y_{2}-y_1 }{x_2-x_1}\), where x2 and x1 are the times 8 and 3, respectively, and y2 and y1 are the distances 372 and 487, respectively. This gives us a slope of -23.

We can solve for b by inputting the values we've been given and using algebra.

\(d(t)=mt+b\\487 =-23(3)+b\\487=-69+b\\b=556\)

This gives us the equation \(d(t) = -23t +556\)

Something to note, since we let 3:00 pm and 8:00 pm be the values x=3 and x=8, 12:00 pm would be x=0, and values in the morning would be negative, like 9:00 am would be x=-3.

Solving for all value of x (x - 1)/(x - 4) = -6/x has two solutions which are: x = -8 and x = 3.

Solve for all values of x.

x-1/x-4 = -6/x

In order to solve the given   equation we can start by simplifying the equation by cross-multiplying:

x(x - 1) = -6(x - 4)

Expand

x^2 - x = -6x + 24

x^2 + 5x - 24 = 0

Solve this quadratic equation by factoring or using the quadratic formula:

(x + 8)(x - 3) = 0

For x = -8

(x-1)/(x-4) = (-8-1)/(-8-4) = -9/-12 = 3/4

-6/x = -6/-8 = 3/4

x = -8

For x = 3

(x-1)/(x-4) = (3-1)/(3-4) = -2

-6/x = -6/3 = -2

x =3

So,

x = -8 or x = 3

Therefore the value of x = -8 and x = 3.

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(a) The rectangles represent a left sum.

(b) Since the height of the rectangles is more than the height of the graph, it is called the upper estimate.

(c) The value of n is 3.

(d) The value of Δx is 2.

(e) The value of the integral \(\(\int_{0}^{6}g(x)dx\)\) is 72.

Integrals are the values of the function that are discovered during the integration process. When all the small data are combined, problems with displacement and motion, area and volume, and other issues arise.

a) Left end points: g(0)Δx + g(2)Δx + g(4)Δx

   Right endpoints: g(2)Δx + g(4)Δx + g(6)Δx= (g(2) + g(4) + g(6))²

b) Since the height of the rectangles is more than the height of the   graph, it is called the upper estimate.

c) The value of n is given byΔx = (b - a)/n2

= (6 - 0)/n2

= 6/nn

= 6/2n = 3

d) Each sub-interval length is given by

Δx = 2 - 0

Δx = 2

e) g(x) = x²\(\(\int_{0}^{6}g(x)dx\)\)

=\(\(\int_{0}^{6}x^{2}dx\)\)

= [x³/3]₀⁶

= 6³/3 - 0

= 72

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The complete question is as follows:

The SQL aggregate function that gives the arithmetic mean for a specific column is `AVG()`.

SQL (Structured Query Language) aggregate functions are functions that operate on a set of values and return a single value as a result. These functions are used in SQL queries to perform calculations on groups of rows in a database table.

There are several common aggregate functions in SQL, including:

1. `COUNT()` - returns the number of rows in a table or the number of non-null values in a specific column.

2. `SUM()` - calculates the sum of values in a specified column.

3. `AVG()` - calculates the average value of values in a specified column.

4. `MAX()` - returns the maximum value in a specified column.

5. `MIN()` - returns the minimum value in a specified column.

Aggregate functions are typically used with the `GROUP BY` clause in SQL queries to group the data based on one or more columns and then apply the aggregate function to each group.

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The SQL aggregate function for calculating the arithmetic mean of a specific column is AVG.

The SQL aggregate function that gives the arithmetic mean for a specific column is AVG.

For example, if you have a table called 'students' with a column called 'grades', you can use the AVG function in SQL to calculate the average grade:

SELECT AVG(grades) FROM students;

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Answer:

An object's initial position

The initial velocity of an object

The time an object was in motion

The acceleration of an object

Step-by-step explanation:

That equation is used to solve for an object's final position.

Answer:

It is 1024

Step-by-step explanation:

If you substitute y within the x, you will be able to simplify what the equation is (which is the first one)

Answer:

C

Step-by-step explanation:

0.5 red : 1 blue

1 red : 2 blue

1.5 red : 3 blue

2 red : 4 blues

2.5 red : 5 blue

3 red : 6 blue

3.5 red : 7 blue

4 red : 8 blue

(per every half a red, there is one whole blue)

C has 4 red and 8 blue

0.5 red x 8 blue = 4 red

1 blue x 8 blue = 8 blue

Answer:

\(y=\frac{3}{4} x+3\)

Step-by-step explanation:

Answer:

x < 3

Step-by-step explanation:

\(\frac{-x}{-}\)<\(\frac{3}{-}\)

x< -3

Using the line plot, we can see that 13 persons talk less than 60 minutes on their phonse.

Here we have a line plot, each one of the points represents a person that talks a given amount of time in the phone.

Here we just need to count the number of points that are before the number 60 in the horizontal axis.

Then we can see:

10 ---> 2 points.

20 ---> 4 points.

40 ---> 4 points.

50 ---> 3 points

Adding that we have a total of 13 points, so there are 13 persons that talk less than 60 minutes per day.

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Answer:

x=-16

Step-by-step explanation:

−2(x+14)+1=5

Step 1: Simplify both sides of the equation.

−2(x+14)+1=5

(−2)(x)+(−2)(14)+1=5(Distribute)

−2x+−28+1=5

(−2x)+(−28+1)=5(Combine Like Terms)

−2x+−27=5

−2x−27=5

Step 2: Add 27 to both sides.

−2x−27+27=5+27

−2x=32

Step 3: Divide both sides by -2.

−2x

−2

=

32

−2

x=−16

Answer:

x=−16

Answer:

-2(x + 14) + 1 = 5

-2x - 28 + 1 = 5

-2x - 27 = 5

-2x = 32

x = -16

Answer:

0.33

Step-by-step explanation:

5.11-3.79=1.32

1.32÷4=0.33

After solving the equation, the price of each postcard will be equal to $0.33.

The four fundamental operations of arithmetic are addition, subtraction, multiplication, and division of two or even more items.

Included in them is the study of integers, especially the order of operations, which is important for all other areas of mathematics, notably algebra, data management, and geometry.

As per information in the question,

Price of greeting card = $3.79

Total cost of greeting card as well as greeting card is $5.11

Let the price of each postcard is x.

Then, the equation will be,

$3.79 + 4x = $5.11

4x = $5.11 - $3.79

x = 1.32/4

x = $0.33

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the remaining soup at Adya's place is 24/114 liters As per the given ratio.

The ratio can be defined as the number that can be used to represent one quantity as a percentage of another. Only when the two numbers in a ratio have the same unit can they be compared. Ratios are used to compare two objects.

Given, Adya makes 9/38 liters of soup for a party. The guests eat 3/57 liters.

Since the total soup was 9/38 liters

Thus,

Remaining soup at Adya = 9/38 -3/57

LCM of 38 and 57 are 114

Remaining soup at Adya = 27/114 - 6/114

Remaining soup at Adya = 27/114 liters

Therefore, the remaining soup at Adya's place is 24/114 liters.

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Answer:

wouldnt it be y=4?

Step-by-step explanation:

Answer:

Step-by-step explanation:

Let M(x,y) be the median of ΔABC through A to BC.M will be the midpoint of BC.x1​=5,y1​=3x2​=3,y2​=−1By midpoint formula, x=(x1​+x2​)/2∴x=(5+3)/2=8/2=4By midpoint formula, y=(y1​+y2​)/2∴y=(3+(−2))/2=2/2=1Hence the co-ordinates of M are (4,1).By diatnce formula, d(AM)=[(x2​−x1​)2+(y2​−y1​)2]​x1​=7,y1​=−3x2​=4,y2​=1

Answer:

The equations that have infinitely many solutions are;

Explanation:

For an equation to have infinitely many solutions, the left-hand side of the equation and the right side of the equation must be equivalent/equal.

That means that the expression before the equal sign must be equivalent to the expression after the decimal.

such as;

From the given equation, the equations that have their left and right sides equivalent are;

Therefore, the equations that have infinitely many solutions are;

The optimal solution is X1 = 15, X2 = 20, and X3 = 16. The profit can increase to $612 if the profit for X2 increases to $24. The profit will increase by $4 if the right-hand side of constraint 3 is increased by 10 units. The profit will decrease by $12.5 if the right-hand side of constraint 2 is decreased by 5 units, but the higher bound on this decrease is $0.

The original LP problem can be constructed by looking at the "Solution" and "Dual" rows of the table. The "Solution" row shows the values of the decision variables in the optimal solution. The "Dual" row shows the dual values of the constraints. The dual value of a constraint is the amount by which the objective function can increase if the constraint is relaxed by one unit.

The constraints with slack are constraints 1 and 3. These constraints are not binding in the optimal solution, which means that they could be relaxed without changing the value of the objective function. The slack for constraint 1 is 52, which means that 52 units of the resource represented by constraint 1 are unused in the optimal solution. The slack for constraint 3 is 50, which means that 50 units of the resource represented by constraint 3 are unused in the optimal solution.

The optimal solution is computed by setting the decision variables equal to the values in the "Solution" row and then solving the resulting system of equations. In this case, the system of equations is:

X1 + X2 + X3 = 210

4X1 + 2X2 = 200

2X1 + 5X3 = 170

Solving this system of equations yields X1 = 15, X2 = 20, and X3 = 16.

If the profit for X2 increases to $24, then the dual value of constraint 2 will increase to 4. This means that the objective function can increase by $4 if constraint 2 is relaxed by one unit. In other words, if we increase the right-hand side of constraint 2 by one unit, then the optimal solution will change and the profit will increase by $4.

If the right-hand side of constraint 3 is increased by 10 units, then the dual value of constraint 3 will increase by $10. This means that the objective function can increase by $10 if constraint 3 is relaxed by one unit. In other words, if we increase the right-hand side of constraint 3 by 10 units, then the optimal solution will not change and the profit will increase by $10.

If the right-hand side of constraint 2 is decreased by 5 units, then the dual value of constraint 2 will decrease by 2.5. This means that the objective function will decrease by $2.5 if constraint 2 is relaxed by one unit. However, the dual value of constraint 2 is also bounded below by 0. This means that the profit can only decrease by $2.5 if constraint 2 is relaxed by one unit.

In conclusion, the bounds of the right-hand-side values and the dual prices are related to the feasibility of the solutions. If the right-hand side value of a constraint is less than the dual price of that constraint, then the constraint is infeasible. If the right-hand side value of a constraint is equal to the dual price of that constraint, then the constraint is binding in the optimal solution. If the right-hand side value of a constraint is greater than the dual price of that constraint, then the constraint is not binding in the optimal solution.

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Answer:

J’ (-3,0)

Step-by-step explanation:

Right = x + 1 = -4 + 1 = -3

down = y-4 = 4-4 = 0

9514 1404 393

Answer:

  (4, -7)

Step-by-step explanation:

Maybe you want the solution to this system of equations.

About the easiest way to obtain it is to use a graphing calculator.

   (x, y) = (4, -7)

_____

Additional comment

Since one of the equations gives an expression for y, it is a simple matter to substitute that for y in the other equation.

  4x +(-2x +1) = 9

  2x = 8 . . . . . . . . . . subtract 1 and simplify

  x = 4

  y = -2(4) +1 = -7 . . . use the first equation to find y

Based on the line of best fit, the approximate maximum depth of a lake that has 31 miles of shoreline is; 142.968 ft

The line of best fit is defined as a straight line which is drawn to pass through a set of plotted data points to give the best and most approximate relationship that exists between such data points.

Now, we are given a table of values that shows the total shoreline in miles which will be represented on the x-axis and then the maximum depth of several area lakes which will be represented on the y-axis.

However, when the geologist found the graph, she arrived at an equation of best fit as;

y = 4.26x + 10.908.

Thus, for 31 miles of shoreline, the approximate maximum depth is;

Approximate maximum depth = 4.26(31) + 10.908.

Approximate maximum depth = 142.968 ft

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Answer:

143 feet

Step-by-step explanation:

its technically 142 and change but edmentum rounds up

The distance from -4 to 1 is 5 units.

The correct number line and expression to find the distance from -4 to 1 are:

Number line: -4 -3 -2 -1 0 1

Expression: |-4 - 1|

To find the distance, we subtract the smaller number (-4) from the larger number (1) and take the absolute value:

|-4 - 1| = |-5| = 5

Therefore, the distance from -4 to 1 is 5 units.

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The correct answer is D. $2.75 / $3.24

To determine how much you should expect to pay for gas in Philadelphia versus Cleveland, we need to compare the transportation expenses in both cities. Based on the given data, the transportation expenses are as follows:

Philadelphia: $117

Cleveland: $106

To calculate the expected gas prices, we need to consider the transportation expenses relative to the national average. The formula to find the expected gas price is:

Expected Gas Price = National Average * (Transportation Expense / National Average)

National Average for gas = $2.59

For Philadelphia:

Expected Gas Price in Philadelphia = $2.59 * ($117 / 92) ≈ $3.30

For Cleveland:

Expected Gas Price in Cleveland = $2.59 * ($106 / 78) ≈ $3.51

Comparing the expected gas prices, we find that:

A. $3.03 / $2.75: This option does not match the expected gas prices in Philadelphia and Cleveland.

B. $1.95 / $2.59: This option does not match the expected gas prices in Philadelphia and Cleveland.

C. $2.34 / $2.75: This option does not match the expected gas prices in Philadelphia and Cleveland.

D. $2.75 / $3.24: This option matches the expected gas prices in Philadelphia and Cleveland.

Therefore, the correct answer is:

D. $2.75 / $3.24

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The function round(price, 0) is used to round a given number (in this case, the price) to a specified number of decimal places (in this case, 0). When you use round(24.95, 0), the function will round the price to the nearest whole number. In this scenario, 24.95 will be rounded up to 25, not 24.

Yes, that is correct. The function round(price,0) rounds the price to the nearest whole number. In this case, 24.95 is rounded down to 24. However, it's important to note that this function always rounds to the nearest whole number, so if the price was 24.5 it would also round down to 24, whereas if the price was 24.6 it would round up to 25. It's also worth mentioning that there are other rounding functions that can be used to round to different levels of precision, such as rounding to the nearest tenth or hundredth.

Overall, rounding is an important tool in many areas of math and statistics, as it allows us to simplify numbers and make calculations easier to work with.
 

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Answer:

D

Step-by-step explanation:

The area of a rectangle is given by the formula:

\(A=\ell w\)

So, we are given that the area is:

\(x^3-5x^2+3x-15\)

And the width is:

\(x^2+3\)

And we want to find the length. To do so, first substitute the expressions into the equation:

\(x^3-5x^2+3x-15=(x^2+3)\ell\)

Thus, to find the length, divide by (x²+3):

\(\displaystyle \ell = \frac{x^3-5x^2+3x-15}{x^2+3}\)

We can factor the numerator:

\(x^3-5x^2+3x-15\)

From the first two terms, factor out a x².

From the third and fourth terms, factor out a 3:

\(=x^2(x-5)+3(x-5)\)

Combine:

\(=(x^2+3)(x-5)\)

Putting this back:

\(\displaystyle \ell = \frac{(x^2+3)(x-5)}{x^2+3}\)

Cancel:

\(\ell =x-5\)

Hence, our answer is D.

Answer:

D on Edge 2021 ;))

Step-by-step explanation:

A design that has two conditions with different participants in each condition is independent groups design. Hence option a) independent groups design is correct.

The student question refers to a design where there are two conditions with different participants in each condition.

An independent groups design, also known as a between-subjects design, involves comparing two or more groups of participants who are not the same individuals.

In this type of design, each participant is exposed to only one level of the independent variable.

The groups are formed independently of each other, and any differences between them can be attributed to the manipulation of the independent variable.

An independent groups design: Identify the research question and the independent variable. Form two or more groups of participants, ensuring that they are independent of each other.

Manipulate the independent variable for each group, ensuring that each participant is exposed to only one level of the variable.

Option b is wrong because repeated measures design involves testing the same participants under different conditions or at different times.

Option c is wrong because solomon four-group design is a complex design involving four groups with two groups receiving a pretest, and two groups not receiving a pretest.

Option d is wrong because the pretest-posttest design involves assessing participants before and after a treatment or intervention.

The correct option is a) independent groups design.

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