The hydrogen ion concentration of this sulfuric acid solution is 6.309 × 10⁻⁴ M (or 0.0006309 M), rounded to 3 significant figures.
The pH of a solution is defined as the negative logarithm of the hydrogen ion concentration, expressed in moles per liter. Mathematically, this can be represented as pH = -log[H+].
To calculate the hydrogen ion concentration of a sulfuric acid solution with a pH of 3.21, we can rearrange this equation to solve for [H+].
pH = -log[H+]
10^(-pH) = [H+]
Plugging in the given pH value of 3.21, we get:
10⁻³ ≅ 6.309 × 10⁻⁴
Therefore, the hydrogen ion concentration of this sulfuric acid solution is 6.309 × 10⁻⁴M (or 0.0006309 M), rounded to 3 significant figures.
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The volume of a gas is directly proportional to its temperature (in Kelvin) at constant
pressure. What does this mean?
As one increases, the other will increase at the same rate. The graph will show a
straight line.
As one increases, the other will decrease at the same rate. The graph will show a
straight line.
As one increases, the other will decrease at the same rate. The graph will show a
inverse line.
As one increases, the other will increase at the same rate. The graph will show an
inverse line.
Answer: A
Explanation:
As one increases the other goes in a straight line. It is called a direct proportionality. Forms a linear graph.
What role do wolves play in the tundra?
Answer:
predator
Explanation:
Wolves, arctic foxes, and snowy owls are predators in the tundra.
What volume will 218 mol H2 occupy at 1.82 atm and 22°C?
Therefore, at 1.82 atm and 22°C, 218 mol of H2 will fill a volume of 888 L.
What mass of hydrogen would fill 22.4 l?1 mole of any gas will take up 22.4 L of space at Standard Temperature and Pressure (STP). The quantity may be determined using the Ideal Gas Law and a balanced chemical equation.
The ideal gas law can be used to resolve this issue:
PV = nRT
The temperature must first be converted to Kelvin by adding 273.15:
T =22°C+273.15
= 295.15 K
After that, we may enter the following values:
P = 1.82 atm
n = 218 mol
R = 0.0821 L·atm/mol·K (gas constant)
So the equation becomes:
V = nRT / P
V = (218 mol)(0.0821 L·atm/mol·K)(295.15 K) / (1.82 atm)
V = 888 L.
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Starting with 0.3500 mol CO(g) and 0.05500 mol COCl2(g) in a 3.050 L flask at 668 K, how many moles of CI2(g) will be present at equilibrium?
CO(g) + Cl2(g)》COCl2(g)
Kc= 1.2 x 10^3 at 668 K
At equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.
1: Write the balanced chemical equation:
\(C_O\)(g) + \(Cl_2\)(g) ⟶ \(C_OCl_2\)(g)
2: Set up an ICE table to track the changes in moles of the substances involved in the reaction.
Initial:
\(C_O\)(g) = 0.3500 mol
\(Cl_2\)(g) = 0.05500 mol
\(C_OCl_2\)(g) = 0 mol
Change:
\(C_O\)(g) = -x
\(Cl_2\)(g) = -x
\(C_OCl_2\)(g) = +x
Equilibrium:
\(C_O\)(g) = 0.3500 - x mol
\(Cl_2\)(g) = 0.05500 - x mol
\(C_OCl_2\)(g) = x mol
3: Write the expression for the equilibrium constant (Kc) using the concentrations of the species involved:
Kc = [\(C_OCl_2\)(g)] / [\(C_O\)(g)] * [\(Cl_2\)(g)]
4: Substitute the given equilibrium constant (Kc) value into the expression:
1.2 x \(10^3\) = x / (0.3500 - x) * (0.05500 - x)
5: Solve the equation for x. Rearrange the equation to obtain a quadratic equation:
1.2 x \(10^3\) * (0.3500 - x) * (0.05500 - x) = x
6: Simplify and solve the quadratic equation. This can be done by multiplying out the terms, rearranging the equation to standard quadratic form, and then using the quadratic formula.
7: After solving the quadratic equation, you will find two possible values for x. However, since the number of moles cannot be negative, we discard the negative solution.
8: The positive value of x represents the number of moles of \(Cl_2\)(g) at equilibrium. Substitute the value of x into the expression for \(Cl_2\)(g):
\(Cl_2\)(g) = 0.05500 - x
9: Calculate the value of \(Cl_2\)(g) at equilibrium:
\(Cl_2\)(g) = 0.05500 - x
\(Cl_2\)(g) = 0.05500 - (positive value of x)
10: Calculate the final value of \(Cl_2\) (g) at equilibrium to get the answer.
Therefore, at equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.
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How would doubling the height of an object change the object's potential
energy?
A. The potential energy would not change.
B. The potential energy would double.
C. The potential energy would decrease by half.
D. The potential energy would increase by a factor of 4.
SUBMIT
ayudaaaaa por favorrr
Answer:
por favorrr you dummy
Explanation:
The early periodic table grouped elements based on similar properties. Which element would be grouped with sodium using this principle.
A. Magnesium
B. Zinc
C.Potassium
D. Sulfur
Answer:
C.Potassium
Explanation:
As we know that Potassium is a mineral also at the same time it is an electrolyte. It helps for muscles work involves the muscles so that the heartbeat and breathing could be controlled.
Now as per the periodic table on an early basis that depends upon the similar properties so the element that should be grouped with the sodium is Potassium
hence, the option c is correct
According to the early periodic table the element that has been grouped together with Na has been Potassium. Thus, option C is correct.
The early periodic table has been consisted of the elements that has been arranged based on the increasing order of the atomic mass. The grouping of the elements has been performed based on the similarities with the elements.
The sodium has been the electrolyte that has been responsible for maintaining the electrolyte balance in the human body. The sodium has been the smaller size element with being highly reactive.
The element that has also been small size with high reactive, and has been able to maintain the body electrolyte balance has been Potassium.
Thus, according to the early periodic table the element that has been grouped together with Na has been Potassium. Thus, option C is correct.
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(c) 45 g C,H, react with 45 g Cl₂ according to the equation:
Cl₂ + C6H6 C6H5Cl + HCI. What is the limiting reactant? What mass of HCI will be produced?
-
In the given reaction, the limiting reactant is C₆H₆ (benzene).
To determine the limiting reactant as well as calculate the mass of HCl produced, compare the moles of each reactant.
The number of moles for each reactant:
Molar mass of Cl₂ = 35.5 g/mol + 35.5 g/mol = 71 g/mol
Moles of Cl₂ = mass of Cl₂ / molar mass of Cl₂
= 45 g / 71 g/mol
= 0.634 moles of Cl₂
Molar mass of C₆H₆ (benzene) = 12 g/mol + 6(1 g/mol) = 78 g/mol
Moles of C₆H₆ = mass of C₆H₆ / molar mass of C₆H₆
= 45 g / 78 g/mol = 0.577 moles of C₆H₆
Determine the stoichiometry between Cl₂ and HCl:
Cl₂ + C₆H₆ → C₆H₅Cl + HCl
Here, we can see that 1 mole of Cl₂ produces 1 mole of HCl.
Thus, the limiting reactant is C₆H₆ (benzene).
Calculate the mass of HCl produced:
Molar mass of HCl = 1 g/mol + 35.5 g/mol = 36.5 g/mol
Moles of HCl produced = moles of C₆H₆ = 0.577 moles
Mass of HCl produced = moles of HCl produced × molar mass of HCl
Mass of HCl produced = 0.577 moles × 36.5 g/mol
≈ 21.04 g
Therefore, approximately 21.04 grams of HCl will be produced.
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Determine the oxidation number of sodium in Na202
Answer:
+1
Explanation:
Na₂O₂
NOTE: the oxidation number of oxygen is always –2 except in peroxides where it is –1.
Thus, we can obtain the oxidation number of sodium (Na) in Na₂O₂ as illustrated below:
Na₂O₂ = 0 (oxidation number of ground state compound is zero)
2Na + 2O = 0
O = –1
2Na + 2(–1) = 0
2Na – 2 = 0
Collect like terms
2Na = 0 + 2
2Na = 2
Divide both side by 2
Na = 2/2
Na = +1
Thus, the oxidation number of sodium (Na) in Na₂O₂ is +1
The pressure of a gas will ? when the volume is decreased and will ? when the absolute temperature is decreased.
Answer:
Explanation:
Pressure and volume are indirectly related.
Pressure and temperature are directly related.
so first ? is increase
2nd ? is decrease
A diprotic weak base ( B ) has pb values of 3.722 ( pb1 ) and 6.514 ( pb2 ). Calculate the fraction of the weak base in each of its three forms ( B , BH+ , BH2+2 ) at pH 8.984 .
B=
BH+=
BH2+2=
A diprotic weak base (B) has pb values of 3.722 (pb1) and 6.514 (pb2). The pH at which the dissociation of the first and second proton of a diprotic weak base is equal to its pKb1 and pKb2 values respectively. The pH at which the concentration of all the three forms of the base (B, BH+ and BH22+) is equal is given by the midpoint pH, pKb1 and pKb2, and is calculated using the equation:pH = 1/2 (pKb1 + pKb2)
The value of pH at which the fraction of the weak base in each of its three forms (B, BH+, and BH22+) can be calculated using the equation:B = [B]/([B] + [BH+] + [BH22+])BH+ = [BH+]/([B] + [BH+] + [BH22+])BH22+ = [BH22+]/([B] + [BH+] + [BH22+])Here, pH = 8.984, and pKb1 and pKb2 are 3.722 and 6.514 respectively. The midpoint pH can be calculated as follows:pH = 1/2 (pKb1 + pKb2)8.984 = 1/2 (3.722 + 6.514)8.984 = 5.118Concentration of base (B), protonated base (BH+), and doubly protonated base (BH22+) can be calculated as:B = [B]/([B] + [BH+] + [BH22+])BH+ = [BH+]/([B] + [BH+] + [BH22+])BH22+ = [BH22+]/([B] + [BH+] + [BH22+])Let's calculate the concentrations of each form one by one.B = [B]/([B] + [BH+] + [BH22+])pH = 8.984pKb1 = 3.722pKb2 = 6.514The fraction of the weak base in its unprotected form (B) is calculated using the following equation:[B] = B * ( [H+]/[OH-]) / (Kb1 + [H+]/Kb1 + Kb2 + [H+]2/Kb1*Kb2)Here, H+ = 10-pHOH- = 10-pKw/pH = 10-14/8.984Kb1 = 10-pKb1Kb2 = 10-pKb2Substituting the values in the above equation, we get:[B] = 0.2603At pH 8.984, the fraction of the weak base in its unprotected form (B) is 0.2603.BH+ = [BH+]/([B] + [BH+] + [BH22+])The fraction of the weak base in its singly pronated form (BH+) is calculated using the following equation:[BH+] = Kb1 * [B] * ( [H+]/[OH-]) / (Kb1 + [H+]/Kb1 + Kb2 + [H+]2/Kb1*Kb2)Substituting the values in the above equation, we get:[BH+] = 0.6687At pH 8.984, the fraction of the weak base in its singly protonated form (BH+) is 0.6687.BH22+ = [BH22+]/([B] + [BH+] + [BH22+])The fraction of the weak base in its doubly protonated form (BH22+) is calculated using the following equation:[BH22+] = Kb1*Kb2 * [B] * ( [H+]2/[OH-]2) / (Kb1 + [H+]/Kb1 + Kb2 + [H+]2/Kb1*Kb2)Substituting the values in the above equation, we get:[BH22+] = 0.0710At pH 8.984, the fraction of the weak base in its doubly protonated form (BH22+) is 0.0710.Finally, the fractions of the weak base in its three forms are:B = 0.2603BH+ = 0.6687BH22+ = 0.0710For such more question on fraction
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Which phenomenon best explains the miscibility of heptane (CH3CH2CH2CH2CH2CH2CH3) in pentane (CH3CH2CH2CH2CH3)
The phenomenon that best explains the miscibility of heptane in pentane is that both are non-polar compounds.
Solubility of compoundsSolubility is defined as the ability of a solute or substance to dissolve in a given solvent and at a particular temperature.
Heptane is a straight-chain alkane hydrocarbon that contains 7 carbon atoms. It is a non polar solvent.
Pentane is also a straight-chain alkane hydrocarbon that contains 5 carbon atoms. It is also a non- polar solvent.
Both pentane and heptane are non-polar because the atoms in their molecules share electrons equally. They are able to dissolve each other because they are alike.
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What volume of 0.900% w/v saline solution can be prepared from 0.300 L of a 3.00% w/v saline solution available in stock?
Percentage denotes a quantity per million ( ppm, where a part for a solution is a unit of mass (g, g, g, kg, et.) or capacity (L, mL, L, etc.). The quantity expressed in percent solutions
What stage is a solution in?
When the solvent makes up a significant portion of the combination, as is frequently the case, the solution typically has the condition of the solvent. The concentration of a solution, which measures how much solute is present in a specific volume of solution or solvent, is one crucial parameter. When water is one of the solvents, the phrase "aqueous solution" is used.
What material is dissolving in the solution to create a solution?
A solute is the material that dissolves in a solvent to create a solution. It is less prevalent in the solution than the solvent. A solvent is a substance that is present in a solution that dissolves a solute. It is more prevalent than the solute in solution. If we use a saltwater solution.
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How many atoms are in 12 g of Carbon-12 (12C)?
There are approximately 6.022 × 10^23 atoms in 12 grams of Carbon-12 (12C).
The number of atoms in a given amount of a substance can be calculated using Avogadro's number, which represents the number of atoms or molecules in one mole of a substance. Avogadro's number is approximately 6.022 × 10^23.
Carbon-12 is a specific isotope of carbon, with an atomic mass of 12 atomic mass units (amu). One mole of Carbon-12 has a mass of 12 grams. Since one mole of any substance contains Avogadro's number of particles, in the case of Carbon-12, it contains 6.022 × 10^23 atoms.
Therefore, if we have 12 grams of Carbon-12, which is equal to one mole, we can conclude that there are approximately 6.022 × 10^23 atoms in this amount of Carbon-12.
In summary, 12 grams of Carbon-12 contains approximately 6.022 × 10^23 atoms. Avogadro's number allows us to relate the mass of a substance to the number of atoms or molecules it contains, providing a fundamental concept in chemistry and enabling us to quantify and understand the microscopic world of atoms and molecules.
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Application: Address incorrect information and explain correct reasoning " Atomic radius increases with increasing atomic number and mass" Explain WHY this misconception is incorrect Explain what factors affect and increase in atomic radius. Use and CAPITALIZE the terms ATOMIC RADIUS, PERIOD, GROUP, PERIODIC TABLE, ENERGY LEVEL and PROTONS
Atomic radius increases with atomic number and mass only on moving down the group while it decreases on moving along a period.
On moving down the group, atomic radius increases as a new shell is successively added along each group and mass only increases because with each element there is an increase in number of protons which leads to the increase in mass.
While, moving across a period, atomic radius decreases as electrons are added to the same shell and due to the inter-electronic repulsions the atom tends to shrink.
Factors which lead to an increase in atomic radius are:
1)Number of protons
2)Number of shells
3)Shielding effect
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What volume of water (in mL) is required to prepare a 3.000 M solution by dissolving 43.83 g of of NaCl.
Select one:
a. 250.0 mL
b. 2500.0 mL
c. 2.50 mL
d. none of these
e. 25.0 mL
Answer:
Option A. 250 mL
Explanation:
From the question given above, the following data were obtained:
Molarity of NaCl = 3 M
Mass of NaCl = 43.83 g
Volume of water =..?
Next, we shall determine the number of mole in 43.83 g of NaCl. This can be obtained as follow:
Mass of NaCl = 43.83 g
Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol
Mole of NaCl =?
Mole = mass/molar mass
Mole of NaCl = 43.83/58.5
Mole of NaCl = 0.749 mole
Next, we shall determine the volume of water required to prepare the solution as follow:
Mole of NaCl = 0.749 mole
Molarity of NaCl = 3 M
Volume of water =..?
Molarity = mole /Volume
3 = 0.749 /volume
Cross multiply
3 × volume = 0.749
Divide both side by 3
Volume = 0.749/3
Volume = 0.25 L
Finally, we shall convert 0.25 L to millilitres (mL). This can be obtained as follow:
Recall:
1 L = 1000 mL
Therefore,
0.25 L = 0.25 L × 1000 mL / 1 L
0.25 L = 250 mL
Therefore, 0.25 L is equivalent to 250 mL.
Thus, the volume of water needed to prepare the solution is 250 mL
Which ketone in each pair is more reactive?
a. 2-heptanone or 4-heptanone,
b. bromomethyl phenyl ketone or chloromethyl phenyl ketone
Answer:
a. 2-heptanone is more reactive than 4-heptanone
b. chloromethyl phenyl ketone is more reactive than bromomethyl phenyl ketone
Explanation:
The reactivity of the carbonyl compound (ketone ) is affected by the steric effect. The steric effect is a hindrance that occurs in the structure or reactivity of a molecule, which is affected by the physical size and the proximity of the adjacent parts of the molecule.
Between 2-heptanone or 4-heptanone, 2-heptanone is more reactive than 4-heptanone. This is because 2-heptanone is less affected by the steric hindrance, unlike the 4-heptanone.
Similarly, the reactivity of the carbonyl compound (ketone) is also affected by the polarity on the carbon compound, which is associated with how electronegative the substituent attached is to the carbonyl compound. From the periodic table, the electronegativity of the Halogen family decreases down the group. Therefore chlorine is more electronegative than bromine.
As such, chloromethyl phenyl ketone is more reactive than bromomethyl phenyl ketone.
Q16. Choose whether this is a physical or chemical change. *
cream
being
whipped
Because air puffs up the cream as it is whipped, there is a physical change even though the ingredients are still cream and air.
What is physical change ?Physical modifications are those that affect a chemical substance's form but not its chemical content. Physical changes may normally be used to separate compounds into chemical elements or simpler compounds, but they cannot be used to separate mixtures into their component compounds.
Liquid cream is extensively combined with small air bubbles to form the foam colloid known as whipped cream. Because milk is transformed from a colloid (cream) to a solid (butter) without changing its chemical makeup, turning milk into butter is a physical transformation. This change in the body can be undone.
Thus, there is a physical change even though the ingredients are still cream and air.
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Heredity Lab Report Instructions:
In the Heredity lab, you investigated how hamsters inherit traits from their parents. Record your observations in the lab report below. You will submit your completed report.
Name and Title: Include your name, instructor's name, date, and name of lab.
Objective(s): In your own words, what was the purpose of this lab?
Hypothesis: In this section, please include the if/then statements you developed during your lab activity.
These statements reflect your predicted outcomes for the experiment.
Test One: If I breed a short fur, FF female with a short fur, Ff male, then I will expect to see (all short fur; some short and some long fur; all long fur) offspring.
Test Two: If I breed a short fur, Ff female with a short fur, Ff male, then I will expect to see (all short fur; some short and some long fur; all long fur) offspring.
Test Three: If I breed a long fur, ff female with a long fur, ff male, then I will expect to see (all short fur; some short and some long fur; all long fur) offspring.
Procedure: The procedures are listed in your virtual lab. You do not need to repeat them here.
Please be sure to identify the test variable (independent variable) and the outcome variable (dependent variable) for this investigation. Remember, the test variable is what is changing in this investigation.
The outcome variable is what you are measuring in this investigation.
Test variable (independent variable): Outcome variable (dependent variable): Data: Record the data from each trial in the data chart below. Be sure to fill in the chart completely. Test One Parent 1: FF Parent 2: Ff Phenotype ratio: ________ : ________ short fur : long fur Test Two Parent 1: Ff Parent 2: Ff Phenotype ratio: ________ : ________ short fur : long fur Test Three Parent 1: ff Parent 2: ff Phenotype ratio: ________ : ________ short fur : long fur Conclusion: Your conclusion will include a summary of the lab results and an interpretation of
For Test One, phenotype ratio is Short fur : Long fur = 2 : 0; For Test Two, the phenotype ratio is Short fur : Long fur = 3 : 1; For Test Three, the phenotype ratios will be Short fur : Long fur = 0 : 2
What are the phenotype ratios from the test crosses?For Test One:
Parent 1: FF (homozygous dominant for short fur)
Parent 2: Ff (heterozygous for short fur)
The Punnett square for this cross will give the following genotype ratios:
FF : Ff = 1 : 1
And the corresponding phenotype ratios will be:
Short fur : Long fur = 2 : 0 or 100% short fur
For Test Two:
Parent 1: Ff (heterozygous for short fur)
Parent 2: Ff (heterozygous for short fur)
The Punnett square for this cross will give the following genotype ratios:
FF : Ff : ff = 1 : 2 : 1
And the corresponding phenotype ratios will be:
Short fur : Long fur = 3 : 1 or 75% short fur and 25% long fur
For Test Three:
Parent 1: ff (homozygous recessive for long fur)
Parent 2: ff (homozygous recessive for long fur)
The Punnett square for this cross will give the following genotype ratios:
ff : ff = 1 : 0
And the corresponding phenotype ratios will be:
Short fur : Long fur = 0 : 2 or 100% long fur
For this investigation, the test variable is the breed of hamster and the outcome variable is the phenotype of the hamster.
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How many grams of lead will be produced if 2.54g of PbS is burned with 1.88g of O2? write the equation
If 2.54 g of PbS is burned with 1.88 g of O2, approximately 2.20 grams of Pb will be produced.
The balanced equation for the reaction of lead sulfide (PbS) with oxygen (O2) to produce lead (Pb) and sulfur dioxide (SO2) is as follows:
2PbS + 3O2 -> 2Pb + 2SO2
From the balanced equation, we can see that the stoichiometric ratio between PbS and Pb is 2:2 or 1:1. This means that for every 1 mole of PbS, 1 mole of Pb is produced.
To calculate the number of moles of PbS, we need to divide the given mass (2.54 g) by its molar mass:
Molar mass of PbS = 207.2 g/mol (Pb) + 32.07 g/mol (S) = 239.27 g/mol
Moles of PbS = 2.54 g / 239.27 g/mol = 0.0106 mol
Since the stoichiometric ratio between PbS and Pb is 1:1, the number of moles of Pb produced is also 0.0106 mol.
To calculate the mass of Pb, we multiply the number of moles by its molar mass:
Molar mass of Pb = 207.2 g/mol
Mass of Pb = 0.0106 mol x 207.2 g/mol = 2.20 g
This calculation is based on the stoichiometric ratio between PbS and Pb, where 1 mole of PbS produces 1 mole of Pb. By converting the given mass of PbS to moles and then multiplying by the molar mass of Pb, we can determine the mass of Pb produced.
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Pretty easy question if you know science. 20 Points
A piece of nickel at 25 °C is dropped into a glass of water at 25 °C. Which statement is correct?
Heat will flow from the nickel to the water in the glass.
Heat will flow from the water in the glass to the nickel.
There will be no transfer of heat from the nickel to the water in the glass.
The final temperature of water and nickel will be 0 °C.
Answer:
C.
Explanation:
because the heat From the nickel and the heat from the water are the same.
As a piece of nickel at 25 °C is dropped into a glass of water at 25 °C, there will be no transfer of heat from the nickel to the water in the glass.
To answer the question, we need to know what heat transfer is.
What is heat transfer?This is the flow of heat energy from one body to another over a temperature gradient.
Heat transfer between Nickel at 25 °C and water at 25 °C.
Since a piece of nickel at 25 °C is dropped into a glass of water at 25 °C, there is no temperature gradient, since, both bodies are at the same temperature. Thus, no heat is transferred from the nickel to the water.
So, as a piece of nickel at 25 °C is dropped into a glass of water at 25 °C, there will be no transfer of heat from the nickel to the water in the glass.
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In the original mixtures, test tube 1 contained magnesium and a zinc compound, and test tube 2 contained zinc
and a magnesium compound. A similar relationship exists between test tubes 3 and 4 and between test tubes 5
and 6. Compare what took place in each corresponding pair of test tubes. What general conclusion can you draw?
Answer:
Magnesium in tube 3 and copper in tube 5 became compounds
If each of the test tubes contained a less reactive compound and a more reactive element or less reactive element and more reactive compound , in first case chemical change of displacement reaction will occur while in second case no reaction will occur as zinc exists as an element.
What is chemical change?Chemical changes are defined as changes which occur when a substance combines with another substance to form a new substance.Alternatively, when a substance breaks down or decomposes to give new substances it is also considered to be a chemical change.
There are several characteristics of chemical changes like change in color, change in state , change in odor and change in composition . During chemical change there is also formation of precipitate an insoluble mass of substance or even evolution of gases.
There are three types of chemical changes:
1) inorganic changes
2)organic changes
3) biochemical changes
During chemical changes atoms are rearranged and changes are accompanied by an energy change as new substances are formed.
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FeO+ PdF2 ---> FeF2+PdO balance please worth 50 points
Answer: FeO
Explanation:
Answer:
This is not worth 50 points liar
Explanation:
Three structural isomers have the formula C5H12.C5H12. Draw and name the isomers using IUPAC names. Draw the isomer with five carbon atoms in main chain.
Answer:
Explanation:
Answer in attached file .
What is the total number of peaks due to singly charged ions in the complete mass
spectrum of chlorine, Cl2
?
A Two
B Three
C Four
D Five
Five is the total number of peaks due to singly charged ions in the complete mass spectrum of chlorine, \(Cl_{2}\)
How many peaks do \(Cl_{2}\)'s molecular ions have?
The mass spectra of compounds with a single chlorine atom show two molecular ion peaks. This is because there are two isotopes of chlorine, 35Cl and 37Cl.
The molecular ion and fragment ions will both have peaks in the mass spectrum. When a mass spectrum is interpreted, a specific molecule can be located, confirmed, or its quantity can be calculated. the base summit of a mass spectrum's tallest (strongest) peak, caused by the ion with the highest relative abundance
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Five is the total number of peaks due to singly charged ions in the complete mass spectrum of chlorine, \(Cl_{2}\).
How many peaks do 's molecular ions have?
The mass spectra of compounds with a single chlorine atom show two molecular ion peaks. This is because there are two isotopes of chlorine, 35Cl and 37Cl.
The molecular ion and fragment ions will both have peaks in the mass spectrum. When a mass spectrum is interpreted, a specific molecule can be located, confirmed, or its quantity can be calculated. the base summit of a mass spectrum's tallest (strongest) peak, caused by the ion with the highest relative abundance
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If your equation includes 7(CrO4)2, how many Cr's are there?
If your equation includes 7(CrO4)2, how many O's are there?
If an equation includes 7(CrO₄)₂, the numbers of Cr's and O's atoms that are there are 14 and 56 respectively.
How to calculate number of atoms?The number of atoms present in a chemical compound can be calculated by multiplying the subscript of the particular element by any coefficient.
According to this question, 7 moles of chromate with the chemical formula; (CrO₄)₂ is given. The number of oxygen and chromium atoms in this compound can be calculated as follows:
Chromium = 7 (coefficient) × 2 = 14 atomsOxygen = 7 (coefficient) × 8 = 56 atomsLearn more about no of atoms at: https://brainly.com/question/14190064
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Where are the metals located on the periodic table? the nonmetals?
Answer:
The metals are located on the left and the non-metals are located on the right.
Explanation:
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What is the unit of force
Answer:
the unit of force is newton represented with symbol "N"
PLEASE ANSWER True or False: When adding reactions together to get a desired reaction you must also add their enthalpies to get the enthalpy of that desired reaction.
Answer:
true
Explanation:
Chlorofluorocarbons such as CCl2F and CCI,F, have been linked to ozone depletion in Antarctica. In 1994, these gases were found in quantities of 261 and 509 parts per trillion by volume (World Resources Institute, World resources 1996-97). Compute the molar concentration of these gases under conditions typical of (a) the mid-latitude troposphere (10 °C and 1.0 atm) and (b) the Antarctic stratosphere (200 K and 0.050 atm). Hint: The composition of a mixture of gases can be described by imagining that the gases are separated from one another in such a way that each exerts the same pressure. If one gas is present at very low levels it is common to express its concentration as, for example, ‘x parts per trillion by volume Then the volume of the separated gas at a certain pressure is x x 10-2 of the original volume of the gas mixture at the same pressure. For a mixture of perfect gases, the volume of each separated gas is proportional to its partial pressure in the mixture and hence to the amount in moles of the gas molecules present in the mixture.
Answer:
a) molarity of CCl3F = 1.12 × 10^-11 mol/dm³
Molarity of CCl2F2 = 2.20 × 10^-11 mol/dm³
B) molarity of CCL3F = 7.96 × 10 ^-13 mol/dm³
Molarity of CCl2F2 = 1.55 × 10^-12 mol/dm³
Explanation:
Using the ideal gas equation:
PV = nRT
Further explanations are found in the attachment below.