Calculate the [H3O+] of the following solutions: [OH-] = 1.0 x 10^-12 M

Answer:

B) The density changed.

C) The salt dissolved in the water.  

E) The salt and the water can still be separated into their individual molecules

Explanation:

A physical change is a change that occurs in a substance which affects only the physical properties of that substance such as color, density, boiling o melting point, etc. In a physical change, the substance retains its chemical composition and no new substances are formed. The changes that occur can as well be reversed.

A chemical change is a change that occurs in a compound which affects or alters the chemical properties of that substance, hence transforming the substance into an entirely new substance different from the original substance. The changes that occur in a chemical change are not easily reversible.

In the given experiment, addition of salt to water results in the following changes:

Density is a physical property of a substance, and as the dissolved salt can be easily recovered from the salt solution solution by evaporation followed by condensation, the changes observed are physical changes.

Answer:

\(m_X=128.44 a.m.u\)

Explanation:

Hello there!

In this case, since the average atomic mass of an element, when given the atomic mass and the percent abundance of the naturally occurring isotopes is computed as shown below for this unknown element:

\(m_X=126*0.22+128*0.34+130*0.44\)

Whereas the atomic mass of each isotope is multiplied by the percent abundancy; we obtain:

\(m_X=128.44 a.m.u\)

Best regards!

Considering the definition of atomic mass, isotopes and atomic mass of an element, the atomic mass of the element is 128.44 amu.

First of all, the atomic mass (A) is obtained by adding the number of protons and neutrons in a given nucleus of a chemical element.

The same chemical element can be made up of different atoms, that is, their atomic numbers are the same, but the number of neutrons is different. These atoms are called isotopes of the element.

On the other hand, the atomic mass of an element is the weighted average mass of its natural isotopes. In other words, the atomic masses of chemical elements are usually calculated as the weighted average of the masses of the different isotopes of each element, taking into account the relative abundance of each of them.

In this case, you know:

Then, the average mass of lithium can be calculated as:

126 amu×0.22 + 128 amu×0.34 + 130 amu×0.44= 128.44 amu

Finally, the atomic mass of the element is 128.44 amu.

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NaCl, HCl, ethanol and Ba(OH)2 is following sequence represents by following tests.

From. the above given data,

NaCl have PH 7 and higher in conductivity. As NaCl is neutral acid formed by the reaction of stong base and strong acid. When it dissolve in water, it dissociate to produce ions Na+ and Cl-. So, it have high conductivity.

Since, HCl is acidic in nature. So, it have PH less than 7. It means 2. It is also higer in conductivity. Thie can be explained on the basis that HCl dissolve in water to give H+ and Cl- strongly. Thus, it have high conductivity.

Etanol is neutral in nature. So, it have PH 7. It have no conductivity. Since, it is non electrolyte. When it allow to dissolve in water it don't dissolve into it and not produce ions. Do, it has no conductivity.

Ba(OH)2 is basic in nature. So it have PH greater than 7. Thus, fourth column represent Ba(OH)2. When it dissolve in water, it dissolve in water to produce Ba2+ and OH- ions. So, it is conductive in nature.

Thus, we concluded that NaCl, HCl, ethanol and Ba(OH)2 is following sequence represents by following tests.

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Given question is incomplete. Here is the correct option.

Explanation:

by the question,

load (L) = 160 N

load distance (LD)= 20m

Effort distance (Ed) = 8m

Effort (E) = ?

we know ,

by using Principle of lever,

\(l \times ld = e \times ed \\ 160 \times 20 = e \times 8 \\ e = \frac{160 \times 20}{8} \\ e = 400\)

therefore, the value of effort applied is 400N

The molecule must possess dipolar bonds, exhibit suitable vibrational frequencies, and be in a form that can be analyzed using IR spectroscopy in order to be studied in an IR spectrum.

To study a molecule in an infrared (IR) spectrum, several criteria need to be considered. Firstly, the molecule should have a dipole moment, meaning it must have a separation of positive and negative charges within the molecule.

This is because IR spectroscopy primarily detects vibrations of covalent bonds, which are associated with changes in dipole moment.Additionally, the molecule should have covalent bonds that can undergo vibrational modes within the range of the instrument. IR spectroscopy typically covers the frequency range of 4000 to 400 cm⁻¹, which corresponds to the energies of molecular vibrations.

The molecule should also be able to be vaporized or dissolved in a suitable solvent to generate a homogeneous sample for analysis. Gaseous or liquid samples are commonly used in IR spectroscopy.

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Answer:it has fixed quantity

Explanation:energy between chemical bonds is hard to measure

Answer:

It has a fixed quantity.

Explanation:

Answer:

A. Magnet has a north pole and south pole.

Explanation:

- A magnet has a north and south pole

- Magnets attract paper clips due to the metals present

- Magnetic fields are not visible

- North pole and south pole attract each other

Only the first statement is correct, the answer is (A).

The magnetic fields are repelling each other. The magnetic impact on flowing electric charges, electric currents, and magnetic substances is described by a magnetic field, which is a vector field, hence options D, D, B, A, and C are correct.

A force perpendicular to the charge's own velocity and the magnetic field acts on it while the charge is travelling through a magnetic field.

An area of space containing a magnet, electric current, or moving charged particle where any other magnet, electric current, or moving charged particle is subject to a magnetic force.

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Answer:

The volume of Component 1 is 36 cubic inches.

Explanation:

To calculate the volume of a composite solid, we need to determine the individual volumes of the different components and then add them together.

In this case, the composite solid consists of multiple components with the following dimensions:

Component 1:

Length: 4 inches

Width: 3 inches

Height: 3 inches

To find the volume of Component 1, we multiply the length, width, and height together:

Volume of Component 1 = Length x Width x Height = 4 in x 3 in x 3 in = 36 cubic inches

Therefore, the volume of Component 1 is 36 cubic inches.

Please provide the dimensions of the remaining components of the composite solid, and I will calculate the total volume by summing up the individual volumes.

Considering the Hess's Law, the enthalpy change for the reaction is 221.8 kJ/mol.

Hess's Law indicates that the enthalpy change in a chemical reaction will be the same whether it occurs in a single stage or in several stages. That is, the sum of the ∆H of each stage of the reaction will give us a value equal to the ∆H of the reaction when it occurs in a single stage.

In this case you want to calculate the enthalpy change of:

C₂H₄ (g) + 6 F₂ (g) → 2 CF₄ (g) + 4 HF (g)

which occurs in three stages.

You know the following reactions, with their corresponding enthalpies:

Equation 1: H₂ (g) + F₂ (g) → 2 HF (g)     ∆H° = -79.2 kJ/mol

Equation 2: C (s) + 2 F₂ (g) → CF₄ (g)     ∆H° = 141.3 kJ/mol

Equation 3: 2 C(s) + 2 H₂ (g) → C₂H₄ (g)     ∆H° = -97.6 kJ/mol

Because of the way formation reactions are defined, any chemical reaction can be written as a combination of formation reactions, some going forward and some going back.

First, to obtain the enthalpy of the desired chemical reaction you need one mole of C₂H₄ (g) on reactant side and it is present in first equation. Since this equation has one mole of C₂H₄ (g) on the product side, it is necessary to locate it on the reactant side (invert it).

When an equation is inverted, the sign of ΔH° also changes.

Now, you need 2 moles of CF₄ (g) on the product side. The second equation has 1 mole of CF₄ (g) on the product side, so it is necessary to multiply it by 2 to obtain 2 moles of CF₄ (g).

Since enthalpy is an extensive property, that is, it depends on the amount of matter present, since the equation is multiply by 2, the variation of enthalpy also.

Finally, you need 4 moles of  HF (g) on the product side. The first equation has 2 moles of  HF (g) on the product side, so it is necessary to multiply it by 2 to obtain 4 moles of the compound.

Since the equation is multiply by 2, the variation of enthalpy also is multiplied by 2.

In summary, you know that three equations with their corresponding enthalpies are:

Equation 1: 2 H₂ (g) + 2 F₂ (g) → 4 HF (g)     ∆H° = -158.4 kJ/mol

Equation 2: 2 C (s) + 4 F₂ (g) → 2 CF₄ (g)     ∆H° = 282.6 kJ/mol

Equation 3: C₂H₄ (g) → 2 C(s) + 2 H₂ (g)     ∆H° = 97.6 kJ/mol

Adding or canceling the reactants and products as appropriate, and adding the enthalpies algebraically, you obtain:

C₂H₄ (g) + 6 F₂ (g) → 2 CF₄ (g) + 4 HF (g)     ΔH°= 221.8 kJ/mol

Finally, the enthalpy change for the reaction is 221.8 kJ/mol.

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Answer:

TRUE

Explanation:

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The volume of 12 gas forms when 21 L Cl2 react at STP is 21 L.

To determine the volume of 12 gas (I assume you mean I2 gas) formed when 21 L of Cl2 reacts at STP (standard temperature and pressure), we need to use the ideal gas law equation.

The ideal gas law equation is given by:

PV = nRT

Where:

P = pressure

V = volume

n = number of moles

R = ideal gas constant

T = temperature

At STP, the pressure is 1 atm, and the temperature is 273.15 K.

From the balanced equation, we can see that the molar ratio between Cl2 and I2 is 1:1. So, if 21 L of Cl2 reacts, it will produce an equal volume of I2 gas.

Given that the volume of Cl2 is 21 L, we can assume the volume of I2 gas formed will also be 21 L.

Therefore, the volume of I2 gas formed is 21 L.

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We must utilize the reaction's equilibrium equation to determine the equilibrium concentrations:

Kc = [X][Y]/[XY]

replacing the specified values:

0.140 = (0.100+x)(0.100+x)/(0.500-x)

Expanding and condensing:

0.14 = (0.01 + 0.2x + x^2)/(0.5 - x)

0.07 - 0.14x = x^2 + 0.2x + 0.01

Changing the order and applying the quadratic formula to find x

x^2 + 0.34x - 0.06 = 0

x = 0.193 or -0.533

X cannot be negative because it denotes a change in concentration. Consequently, x = 0.193 M.

It is now possible to determine the equilibrium concentrations:

[XY] = 0.500 - x = 0.307 M

[X] = [Y] = 0.100 + x = 0.293 M

Therefore, the equilibrium concentrations of XY, X, and Y are 0.307 M, 0.293 M, and 0.293 M, respectively.

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Answer:

Br-CH2-CH(CH3)2-C(Cl)H-CH(CH3)2-CHO

Explanation:

The molecule has a total of 14 carbon atoms, 13 hydrogen atoms, and 1 bromine atom. The carbon atoms are arranged in a chain with a methyl group attached to the second carbon atom, a chlorine atom attached to the third carbon atom, and two methyl groups attached to the fourth carbon atom. The fifth carbon atom has a carbonyl group attached to it.

The molecule is an aldehyde, which means that it has a carbonyl group (C=O) at the end of the chain. The carbonyl group is polar, and the oxygen atom has a partial negative charge. The hydrogen atom has a partial positive charge. This polarity makes the aldehyde group susceptible to nucleophilic attack.

The bromine and chlorine atoms are both electrophilic, which means that they have a partial positive charge. This makes them susceptible to nucleophilic attack.

The methyl groups are non-polar and do not have any significant reactivity.

The molecule is a chiral molecule, which means that it has a mirror image that is not superimposable on itself. This is because the carbon atom with the carbonyl group is attached to four different groups.

The molecule is a liquid at room temperature and has a strong odor. It is used in a variety of products, including perfumes, flavorings, and plastics.

The IUPAC name of the amine shown is N-ethylbutan-1-amine.

The IUPAC name of an organic compound is a systematic way of naming organic chemical compounds as recommended by the International Union of Pure and Applied Chemistry (IUPAC).

It is a standard method to ensure that every organic compound has a unique name, which reflects its structure and the functional groups present in the molecule.

The IUPAC name usually consists of several parts, including the parent chain, substituent groups, and functional groups, arranged in a specific order according to a set of rules.

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The statement "Superficial zone chondrocytes can get compacted under physiological loading: a multiscale finite element analysis" is true.

Superficial zone chondrocytes are the most exposed to mechanical loading and are therefore at risk of being compacted under physiological loading. A multiscale finite element analysis can be used to model and predict the mechanical behavior of cartilage under physiological loading, allowing for a better understanding of the factors that affect its mechanical properties.

This means that chondrocytes in the superficial zone of cartilage are at risk of being compacted under the physiological loading that it experiences in everyday life. A multiscale finite element analysis can be used to model and predict the mechanical behavior of cartilage under physiological loading, allowing for a better understanding of the factors that affect its mechanical properties.

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Answer:

Option D: Cations

Explanation:

Do you need only one answer .

Answer:

It lights on fire

Explanation:

The friction sparks the match causing it to go on fire.

Answer:  \(H_2PO_4\) and \(H_3PO_4\)

Explanation:

According to the Bronsted-Lowry conjugate acid-base theory, an acid is defined as a substance which looses donates protons and thus forming conjugate base and a base is defined as a substance which accepts protons and thus forming conjugate acid.

For the given reaction:

\(H_2PO_4^-+H_2O\rightleftharpoons H_3PO_4+OH^-\)

Here, \(H_2O\) is loosing a proton, thus it is considered as an acid and after losing a proton, it forms \(OH^-\) which is a conjugate base.

Similarly , \(H_2PO_4^-\) is gaining a proton, thus it is considered as an base and after gaining a proton, it forms \(H_3PO_4\) which is a conjugate acid.

Thus \(H_2PO_4\) and \(H_3PO_4\) is a conjugate acid-base pair in the reaction represented by the equation below

The Bronsted-Lowry conjugate acid-base hypothesis defines an acid as a substance that loses protons and donates them to another chemical to produce conjugate base, and a base as a substance that takes protons to generate conjugate acid.

Thus, a proton is being lost, making it an acid, and once a proton is lost, a conjugate base is formed. Similar to that, is gaining a proton, making it a base, and then it produces a conjugate acid after gaining a proton.

The Brnsted-Lowry hypothesis, often known as the proton theory of acids and bases, is an independent theory of acid-base reactions that was put forth in 1923 by Johannes Nicolaus Brnsted and Thomas Martin Lowry.

This theory's central idea is that when an acid and a base interact, the acid creates its conjugate base and the base creates its conjugate acid by exchanging a proton (the hydrogen cation, or H+).

Thus, The Bronsted-Lowry conjugate acid-base hypothesis defines an acid as a substance that loses protons and donates them to another chemical to produce conjugate base, and a base as a substance that takes protons to generate conjugate acid.

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Answer:

yes of course due to attraction..

Answer: Loamy, sandy and clayey

Answer:

Sand, silt and clay

Explanation:

Soil can be classified into three primary types based on its texture – sand, silt and clay. However, the percentage of these can vary, resulting in more compound types of soil such as loamy sand, sandy clay, silty clay, etc.

Source: https://byjus.com/biology/types-of-soil/#:~:text=Soil%20can%20be%20classified%20into,clay%2C%20silty%20clay%2C%20etc.

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Happy Late Valentine's Day!

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1) Decrease in volume of water

2) Appearance of gases.

When an electric current is passed through the tap water, gas bubbles will be produced at the electrodes. At the cathode, where reduction takes place, hydrogen gas (H2) will be produced, and at the anode, where oxidation takes place, oxygen gas (O2) will be produced. These bubbles can be seen as they rise to the surface of the water.

As the electrolysis is in progress, it will be observed that the volume of the water in beaker will decrease.

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When two objects have the same mass and applied force to them then their acceleration will be the same. Therefore, option (B) is correct.

The acceleration of an object is described as the rate of change of velocity with respect to time. The acceleration is a vector parameter as it contains magnitude and direction. Acceleration is equal to the second derivative of position w.r.t. time and is equal to the first derivative of velocity of an object w.r.t. time.

According to Newton's second law of motion, acceleration is inversely proportional to the mass of the body.

F = ma

or, a = F/m

The acceleration depends upon two factors applied force and the mass of the object. If both factors are the same for an object then the acceleration will be the same.

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Answer:

Hello your question is incomplete attached below is the complete question

A) How the mass will be affected by chewing time

The chewing time is an independent variable while the mass of the gum is a dependent variable and would change with increase in chewing time as seen in the regular gum the average mass increase above the average sugar mass before chewing

B) how the chewing time necessary to lose significant mass

The chewing time is neccessary to lose significant mass as seen in the sugar free chewing gum because the more time the gum is chewed the lesser the mass due to the absence/lose of sugar

C) The role saliva play in the processing of gum in the mouth

The saliva mixes up with the sugar contained in the chewing gum to increase its mass as seen when you compare the mean mass value of sugar contained in the regular chewing gum with the mean mass value of the gum after chewing for some time i.e 3.58 < 5.03 , 4.09

Explanation:

we will make two assumptions in order to resolve the given problem

next we have to calculate the mean(average) mass of the Chewing gums for each time interval

Regular gum :

initial mean mass = 5.96

mean mass after 1 minute = 5.03

mean mass after 2 minutes = 4.09

next we calculate the mean mass of sugar in the regular gum  using this relationship :summation of( initial masses * 60/100 )/ 4 = 3.58  comparing it the the mass of the chewing gum at different time intervals i.e 1 minute and 2 minutes

sugar free gum :

initial mean mass = 2.98

mean mass after 1 minute = 2.59

mean mass after 2 minutes = 2.32

A) How the mass will be affected by chewing time

The chewing time is an independent variable while the mass of the gum is a dependent variable and would change with increase in chewing time as seen in the regular gum the average mass increase above the average sugar mass before chewing

B) how the chewing time necessary to lose significant mass

The chewing time is neccessary to lose significant mass as seen in the sugar free chewing gum because the more time the gum is chewed the lesser the mass due to the absence/lose of sugar

C) The role saliva play in the processing of gum in the mouth

The saliva mixes up with the sugar contained in the chewing gum to increase its mass as seen when you compare the mean mass value of sugar contained in the regular chewing gum with the mean mass value of the gum after chewing for some time i.e 3.58 < 5.03 , 4.09

The activation energy of this reaction is approximately -13.770 J/mol.

1. To graphically determine the activation energy, we need to plot two points. The given data points are:

  Point 1: (1, -1.275)

  Point 2: (2, 0.379725)

2. The rise is the change in the y-coordinate between the two points:

  Rise = y2 - y1 = 0.379725 - (-1.275) = 1.654725

3. The run is the change in the x-coordinate between the two points:

  Run = x2 - x1 = 2 - 1 = 1

4. The slope of the line formed by these two points can be calculated using the formula:

  Slope = rise / run = 1.654725 / 1 = 1.654725

5. The activation energy (Ea) can be determined using the equation:

  Ea = -R * slope

 Here, R is the ideal gas constant, which is approximately 8.314 J/(mol·K).

6. Plugging in the values:

  Ea = -8.314 * 1.654725 = -13.770 J/mol

Note that the activation energy is negative because it represents the energy difference between the reactants and the transition state (higher energy) in an exothermic reaction.

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Reagents that are entirely consumed by a chemical reaction are known as limiting reagents.

Thus, They are additionally known as limiting reactants or limiting agents. A predetermined quantity of reactants are necessary for the reaction to be completed, according to the stoichiometry of chemical reactions.

In the aforementioned reaction, 2 moles of ammonia are created when 3 moles of hydrogen gas react with 1 mole of nitrogen gas.

In most cases, this reactant dictates when the reaction will end. The reaction stoichiometry can be used to determine the precise quantity of reactant that will be required to react with another element. The limiting agent is determined by the mole ratio rather than the mass of the reactants.

Thus, Reagents that are entirely consumed by a chemical reaction are known as limiting reagents.

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The scenario in which as the climate warms, ice and snow melt making the climate hotter, which then melts more snow and ice is an example of positive feedback.

The correct option is A.

Positive feedback refers to a process in which an initial change or disturbance in a system leads to an amplification or reinforcement of that change.

Considering the scenario of climate change, the example provided earlier is a demonstration of positive feedback.

As the climate warms, ice and snow melt, reducing the reflective surface and exposing darker surfaces like land or water. These darker surfaces absorb more sunlight, which leads to further warming and more melting of ice and snow. This cycle continues, causing a self-reinforcing effect that amplifies the initial warming.

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