Calculate the final ph of a solution made by the addition of 10 ml of a 0.5 m naoh solution to 500 ml of a 0.4 m ha originally at ph = 5.0 (pka = 5.0) neglect the volume change.

Answer:

Molarity=number of moles÷volume(L)

Answer:

It’s 3

Explanation:

The 10g of water at 150°C would need to lose 4184 J of energy to reach 50°C.

To calculate the energy needed for 10g of water at 150°C to reach 50°C, we need to use the specific heat capacity of water and the formula:

Q = mcΔT

where Q is the energy needed, m is the mass of water, c is the specific heat capacity of water, and ΔT is the change in temperature.

1. Since the water is not in the solid phase, there is no energy in the solid phase.

2. Since the water is not undergoing a melting/fusion transition, there is no energy in the melting/fusion transition.

3. The energy in the liquid phase is given by:

Q = mcΔT = 10g x 4.184 J/g°C x (50°C - 150°C)

 = -4184 J (negative sign indicates a loss of energy)

4. Since the water is not undergoing a vaporization/condensation transition, there is no energy in the vaporization/condensation transition.

5. Since the water is not in the gas phase, there is no energy in the gas phase.

6. The total energy needed is the sum of the energies in each phase, which is -4184 J

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Answer:

1

atom of

Cu

has a mass of

1.055

×

10

−

22

g

.

It is important to allow the level of solvent to drop below the level of the sand before adding in your sample mixture because if the sample mixture is added before the level of solvent drops below the sand, the sample may mix with the sand causing the resulting solution to be contaminated with sand particles.

Contamination of the solution will impact the accuracy and precision of the analysis.

To prevent this contamination from occurring, the level of solvent should be allowed to drop below the sand before adding the sample mixture. This ensures that the sample will be dissolved in the solvent without interference from sand particles. This practice is especially important in analytical chemistry when trying to obtain precise and accurate results.

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To calculate the following for test tube 1 and test tube 2:

1. The number of moles of copper(II) sulfate used:

Test tube 1: 0.2 g of copper(II) sulfate was used, which is equivalent to 0.001255 moles (0.2 g / 159.60 g/mol).
Test tube 2: 0.4 g of copper(II) sulfate was used, which is equivalent to 0.002510 moles (0.4 g / 159.60 g/mol).

2. The heat absorbed by the water, in joules:

Test tube 1: Q = (10.0 g) x (4.186 J/g°C) x (20.0°C) = 837.2 J

Test tube 2: Q = (10.0 g) x (4.186 J/g°C) x (30.0°C) = 1257.9 J

3. The change in internal energy of the copper(II) sulfate:
Since the energy released by the copper(II) sulfate is absorbed by the water, the change in internal energy of the copper(II) sulfate is equal to the negative of the heat absorbed by the water.
Test tube 1: ΔU = -837.2 J
Test tube 2: ΔU = -1257.9 J
4. The reaction enthalpy, in joules/mole:
The reaction enthalpy can be calculated using the formula ΔH = ΔU + PΔV, where PΔV represents the work done by the system. Assuming that the reaction was carried out at constant pressure (i.e., atmospheric pressure), PΔV can be approximated to zero, and thus the reaction enthalpy is equal to the change in internal energy.
Test tube 1: ΔH = -837.2 J / 0.001255 mol = -666,876 J/mol
Test tube 2: ΔH = -1257.9 J / 0.002510 mol = -500,357 J/mol
Therefore, the results can be recorded in the following table:

|           | Moles of CuSO4 used | Heat absorbed by water (J) | Change in internal energy (J) | Reaction enthalpy (J/mol) |
|-----------|---------------------|-----------------------------|---------------------------------|---------------------------|
| Test tube 1 | 0.001255            | 837.2                       | -837.2                          | -666,876                 |
| Test tube 2 | 0.002510            | 1257.9                      | -1257.9                         | -500,357                 |

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The pressure of \(N_{2}\) will rise under the given conditions. And, Yes, it is possible to reverse this tendency by adding \(H_{2}\). The minimum pressure of H2 required to reverse the tendency is 0.01 atm.

The reaction involved is: \(N_{2}\)(g) + 3\(H_{2}\)(g) ⇌ 2\(NH_{3}\)(g)  Hence, when \(H_{2}\) is added to the above system, the \(N_{2}\) and  \(H_{2}\)  will react to produce \(NH_{3}\). This reaction will reduce the amount of \(N_{2}\) present in the system, causing the pressure of \(N_{2}\) to decrease. Therefore, by adding \(H_{2}\)  , we can change the tendency of \(N_{2}\) pressure from rise to fall.To calculate the minimum pressure of  \(H_{2}\)  required to reverse the tendency, we have to use the equilibrium constant, Kp. The expression for Kp for the above reaction is: Kp =( \(NH_{3}\)) / p(\(N_{2}\)) p3( \(H_{2}\) )

At equilibrium, Kp = 1.7 × 104 at 1126 °C.Now, we will solve for the minimum pressure of \(H_{2}\)   needed to reverse the tendency. Let's assume that the pressure of \(N_{2}\) has increased by x atm. Therefore, the new pressure of \(N_{2}\) will be (0.0406 + x) atm. At equilibrium, we have:

p2(\(NH_{3}\) ) / p(\(N_{2}\)) p3( \(H_{2}\) ) = 1.7 × 104

On substituting the given values and simplifying, we get:

p2(\(NH_{3}\)) / p(N2) = 6.39 × 10-5

Now, p2(\(NH_{3}\)) = 5.97 atm, and p(\(N_{2}\)) = (0.0406 + x) atm.

On substituting these values, we get:5.97 / (0.0406 + x) = 6.39 × 10-5

Solving for x, we get:x = 0.00579 atm ≈ 0.01 atm (rounded to 2 significant digits)Therefore, the minimum pressure of \(H_{2}\)   required to reverse the tendency is 0.01 atm.

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Yes, using only the p, v, and t values, the Clapeyron solution in thermodynamics may be used to compute the energy of vaporization at a particular temperature.

Reaction equation are symbolic depictions of chemical reactions where the reactants and products are stated in relation to the following chemical formulae.

What is an equations and a chemical reaction? In a chemical change, bonds between molecules of the reagent are destroyed and new bonds between molecules of the product are established to create a new substance. A chemical formula is nothing more than a statement of fact that represents how reactants generate products.

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Lightning protection systems utilize materials, including copper-clad steel, solid copper, and stainless steel, chosen for their specific properties and characteristics making them lightning protection apps.

Lightning protection systems are designed to safeguard structures and people from the destructive forces of lightning strikes. The materials used in these systems play a crucial role in dissipating and redirecting the electrical energy of lightning safely. Copper-clad steel is a popular choice for lightning rods and conductors due to its combination of strength and conductivity.

The steel core provides mechanical strength, while the copper coating ensures excellent electrical conductivity. Solid copper is another common material used in lightning protection systems. Copper has exceptional electrical conductivity and is highly resistant to corrosion, making it an ideal choice for applications where longevity and conductivity are vital. Additionally, stainless steel, known for its durability and corrosion resistance, is utilized in lightning protection systems, particularly for grounding components and structural connections.

By using these materials strategically within lightning protection systems, the risk of damage from lightning strikes can be minimized by providing effective paths for lightning current to safely follow, reducing the potential for destructive electrical surges.

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We are going to assume that the gas mentioned behaves like an ideal gas. The equation that describes the behavior of an ideal gas is as follows:

Where,

P is the pressure of the gas, 358kPa

V is the volume of the gas, 14.0L

R is the gas constant, 8.31 L kPa/mol K

T is the temperature of the gas, 269K

Now, we will clear the number of moles, n.

We replace the known data:

Answer: In the sample of gas there are 2.24 moles

Answer:

Helium (He), neon (Ne), and argon (Ar), as group 18 elements, have outer electron shells that are full or satisfy the octet rule. This makes them highly stable as single atoms. Because of their non-reactivity, they are called the inert gases or noble gases.

Explanation:

can i get brainliest

Answer:

Explanation:

doing this for  point hope you find out tho

The gravity of the earth is denoted by the symbol 'g'. Here there is no change in the weight of the pencil as it falls from 10 m to the ground.

The acceleration acquired by an object due to the gravitational force is defined as the acceleration due to gravity. It is generally denoted by the symbol 'g'. Its standard value is 9.8 m/s².

The value of 'g' is not affected by the mass. The factors affecting its value are earth's shape, altitude and depth of the earth's surface. So during the free fall of a pencil there is no air resistance on it.

Thus the weight of the pencil will not change.

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Total pressure = 4.9 atm

Partial pressure of neon =  3.4 atm

Partial pressure of oxygen = 1.5 atm

We know that the partial pressure could be obtained as the product of the mole fraction and the total pressure thus we have to obtain the total pressure by the use of the partial pressures.

For the number of moles of helium;

P = 101.3 kPa or 0.99 atm

T =  25ºC or 298 K

V =  27 L

n = PV/RT = 0.99 atm * 27 L/0.082 *  298 K = 26.73/24.44 = 1.1 moles

Number of moles of oxygen

P = 101.3 kPa or 0.99 atm

T =  25ºC or 298 K

V =  12 L

n = PV/RT = 0.99 atm * 12 L/0.082 *  298 K =11.88 /24.44 = 0.5 moles

Total number of moles = 1.1 moles + 0.5 moles = 1.6 moles

Total pressure is obtained from;

nRT/V

= 1.6 moles * 0.082 * 298/8

= 4.9 atm

Partial pressure of neon = 1.1 moles/1.6 moles * 4.9 atm = 3.4 atm

Partial pressure of oxygen = 0.5 moles/1.6 moles * 4.9 atm = 1.5 atm

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The compound formed when magnesium oxide reacts with water is magnesium hydroxide (Mg(OH)₂).

Magnesium oxide (MgO) is an ionic compound consisting of magnesium cations (Mg²⁺) and oxide anions (O²⁻). When it reacts with water (H₂O), the oxygen atom in water attracts the magnesium cation, leading to the formation of magnesium hydroxide.

The reaction can be represented as follows:

MgO + H₂O → Mg(OH)₂

In the resulting compound, magnesium hydroxide, there are two hydroxide ions (OH-) for every magnesium ion (Mg²⁺). The chemical formula Mg(OH)₂ represents this ratio.

Magnesium hydroxide is an alkaline compound and is commonly used as an antacid to treat heartburn and indigestion. It is also used in various industrial applications.

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The balanced equation for this reaction is: 2Mg + \(Cl_{2}\) → \(2MgCl_{2}\).

Based on this, the classification of the reaction is (d) single replacement.

The given chemical equation is:

Mg(s) + \(Cl_{2}\)(g) → \(MgCl_{2}\)(s)

In this reaction, magnesium metal (Mg) reacts with chlorine gas (\(Cl_{2}\)) to form solid magnesium chloride (\(MgCl_{2}\)).

During the reaction, the magnesium atoms lose electrons to form magnesium ions with a +2 charge, while the chlorine molecules gain electrons to form chloride ions with a -1 charge. These ions then combine to form the ionic compound, magnesium chloride.

Based on the type of reaction, this can be classified as a synthesis reaction, where two or more substances combine to form a single, more complex substance.

Therefore, option (b) - synthesis is the correct classification for the given chemical reaction.

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The breakdown of a 22-carbon fatty acid through aerobic metabolism via beta-oxidation and the citric acid cycle provides a substantial amount of energy in the form of ATP, allowing cells to perform various vital functions.

The approximate energy yield through aerobic metabolism of a 22-carbon fatty acid involves a series of major reactions within the mitochondria of cells. The process is known as beta-oxidation, and it generates acetyl-CoA molecules that enter the citric acid cycle (also known as the Krebs cycle) to produce ATP.

First, the 22-carbon fatty acid undergoes a series of four reactions in the beta-oxidation pathway. Each cycle of beta-oxidation removes a two-carbon acetyl-CoA molecule from the fatty acid chain, generating one molecule of NADH and one molecule of FADH2 in the process. These high-energy electron carriers will later enter the electron transport chain to produce ATP.

After the beta-oxidation process, the resulting acetyl-CoA molecules enter the citric acid cycle. In this cycle, each acetyl-CoA molecule is oxidized, leading to the production of three molecules of NADH, one molecule of FADH2, and one molecule of GTP (which can be converted to ATP). These electron carriers (NADH and FADH2) will transfer their electrons to the electron transport chain for ATP synthesis.

Finally, the electron transport chain, located in the inner mitochondrial membrane, utilizes the high-energy electrons from NADH and FADH2 to pump protons across the membrane. This establishes an electrochemical gradient that drives ATP synthesis through oxidative phosphorylation. The exact number of ATP molecules generated depends on several factors, but on average, the complete oxidation of a 22-carbon fatty acid yields approximately 129 molecules of ATP.

Overall, the breakdown of a 22-carbon fatty acid through aerobic metabolism via beta-oxidation and the citric acid cycle provides a substantial amount of energy in the form of ATP, allowing cells to perform various vital functions.

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A solution is 0.20 m ba(oh)2(aq). 0.040 moles of hcl(aq) must be added to neutralize 100.0 ml of the solution

number of moles of Ba(OH)2 = molarity * volume of solution in L

number of moles of Ba(OH)2 = 0.20 * 0.10 L = 0.020 mole

Ba(OH)2   +   2H+  ---->  Ba^2+   +   2H2O

from the balanced equation we can say that

1 mole of Ba(OH)2 requires 2 mole of H+ so

0.020 mole of Ba(OH)2  will require

= 0.020 mole of Ba(OH)2 *(2 mole of H+ / 1 mole of Ba(OH)2)

= 0.040 mole of H+

Therefore, the number of moles of H+ required are 0.040 mol

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Answer:

Carbon

Explanation:

9 When 0.1 mol of atoms of an element reacts with chlorine, there is an increase in mass of 7.1 g. The element could be carbon.

Shape Formula Variables

Cube V=s3 s is the length of the side.

Right Rectangular Prism V=LWH L is the length, W is the width and H is the height.

Prism or Cylinder V=Ah A is the area of the base, h is the height.

Answer:

Aluminum atoms are in 3.78 g of aluminum

02214076x10^23)8.4367659370640769254888x10^22 atoms, therefore there are 8.4367659370640769254888x10^22 atoms of Aluminum(Al) present in 3.78 grams of Aluminum(Al).

Explanation:

The enthalpy change for the reaction CaCO3 (s) -> CaO (s, graphite) + O2 (g) is 571.6 kJ.

The enthalpy of the reaction CaCO3 (s) -> CaO (s, graphite) + O2 (g) can be calculated by summing the enthalpies of the individual reactions involved. The given information provides the enthalpy change for the decomposition of CaCO3 (s) and the combustion of C (s) to form CO2 (g). By combining these reactions, the enthalpy change for the overall reaction can be determined.

The given reactions are:

CaCO3 (s) -> CaO (s) + CO2 (g) (H = 178.1 kJ)

C (s, graphite) + O2 (g) -> CO2 (g) (H = -393.5 kJ)

To calculate the enthalpy change for the reaction CaCO3 (s) -> CaO (s, graphite) + O2 (g), we need to subtract the enthalpy change of reaction 2 from the enthalpy change of reaction 1. Since the enthalpy change is an extensive property, we can subtract the enthalpies directly:

ΔH = H(reaction 1) - H(reaction 2)

= 178.1 kJ - (-393.5 kJ)

= 178.1 kJ + 393.5 kJ

= 571.6 kJ

Therefore, the enthalpy change for the reaction CaCO3 (s) -> CaO (s, graphite) + O2 (g) is 571.6 kJ.

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Answer:

0.086

Explanation:

got it on acellus

The mass of the dry solute recovered from the given data is 0.086 g.  Option C

To determine the mass of the dry solute recovered, we need to subtract the mass of the boat from the mass of the boat with the dry solute.

Given the data provided:

Boat Mass: 0.730 g

Boat + Solution: 0.929 g

Boat + Dry: 0.816 g

To find the mass of the dry solute, we subtract the boat mass from the boat + dry mass:

Mass of Dry Solute = (Boat + Dry) - (Boat Mass)

Mass of Dry Solute = 0.816 g - 0.730 g

Mass of Dry Solute = 0.086 g

Therefore, the correct answer is c) 0.086 g.

The mass of the dry solute recovered from the given data is 0.086 g. It is important to note that the mass of the dry solute is obtained by subtracting the mass of the boat from the mass of the boat with the dry solute, as the boat mass represents the weight of the empty boat or container used in the experiment.

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Answer:

Anions are larger than their corresponding neutral atoms

A mutagen is a chemical or physical agent capable of inducing changes in DNA, leading to mutations.

Mutagens can alter the genetic material by causing changes in the DNA sequence, such as substitutions, deletions, insertions, or rearrangements. These changes can result in the formation of new alleles or the disruption of normal gene function.

Examples of mutagens include certain chemicals, such as certain pesticides, tobacco smoke, and certain chemotherapy drugs. Physical agents like ionizing radiation (e.g., X-rays, gamma rays) and ultraviolet (UV) radiation from the sun or tanning beds can also induce DNA mutations.

It is important to note that not all mutagens are harmful. Some mutations can be beneficial, leading to genetic variation and adaptation in populations, while others may have detrimental effects, such as contributing to the development of diseases like cancer.

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It is crucial to maintain a constant temperature because the incubator will work with living things. Additionally, these samples are quite delicate.

Designing materials for use in engineering applications at high temperatures requires consideration of thermal stability. The ability of an alloy to maintain ductility and toughness during prolonged temperature exposure can be referred to as this property.

Several growth restrictions are present for organisms developing at low temperatures: nucleic acid structures become much more solid, membrane fluidity diminishes, enzyme reaction rates slow down, affinity of transport and uptake systems declines.

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Answer:

its B

Explanation:

this is pretty obvious since I know about this and did it already.

I Hope this helps!

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Factors such as the lack of arable land and the scarcity of water make agriculture less productive in India.

India has a large area of degraded and infertile land, which limits the ability of farmers to produce crops. Soil degradation is caused by factors such as deforestation, overgrazing, and soil erosion.

India is facing an increasingly serious water shortage, which affects agriculture in many regions. Lack of access to water for irrigation is a major limiting factor for crop production.

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2. Coal

It is non renewable energy source.

Answer: the answer would be coal

Explanation: hoped this helped!