Calculate the components of the following projectile's velocity
1. v = 35 m/s 0 = 15° vx =, vy=
2. v = 35 m/s 0 = 30° vx = , vy=
3. v= 35 m/s 0 = 45° vx = ,vy=

Answers

Answer 1

Projectile motion is the motion of an object thrown (projected) into the air. After the initial force that launches the object, it only experiences the force of gravity. The object is called a projectile, and its path is called its trajectory. As an object travels through the air, it encounters a frictional force that slows its motion called air resistance. Air resistance does significantly alter trajectory motion, but due to the difficulty in the calculation, it is ignored in introductory physics.

the components of the following projectile's velocity into X- the axis and Y - axis

1. vx = 35 cos15°  and vy sin15°

2. vx = 35 cos30° and vy sin30°

3. vx = 35 cos45° and vy sin45°

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Related Questions

Suppose you needed to push a 1,500-N sofa up a frictionless ramp with a 30° angle. How much force would you have to apply to the sofa?Show your work below.

Answers

Answer:

1299N

Explanation:

GIven data

Weight W= 1500N

Angle Ф= 30°

The applied force up the frictionless ramp is gotten by applying the formula below

F= WcosФ

substitute

F=1500 cos 30

F = 1500*0.8660

F= 1299N

Hence the applied force is 1299N

An airplane is traveling 200 mph south. You get up and walk down the aisle at 1 mph north. Your resultant velocity is

Answers

199 mph south
using the formula 200 - 1 = 199 mph south

An uncharged spherical conductor hangs by an insulating thread. You bring a negatively charged rod near
from the left side. The net charge on the hanging conductor’s left side is (choose one):

a. Positive

b. Negative

c. Neutral

Answers

Answer:

Positive

This type of charging is called charging by induction

In this the uncharged body gets the opposite type of charge.

when a negatively charged rod is bring near uncharged spherical conductor it attracts positive charge and repels negative charges

so In left side all positive charges appears and in right side all negetive

Types of methods of charging

Charging by contact charging by rubbing charging by induction.

Nathan is standing 2 feet away from a plane mirror. Hiva is standing 5 feet further than
Nathan in comparison to the mirror. The distance between Nachan and Hiva's image is:

Answers

Answer:

They are standing 3 feet away from each other

Explanation:

If Nathan Is standing 2 feet away from the mirror. Then Hiva is standing 7 feet away from the mirror is she is standing 5 feet further than him. They are standing 3 feet away from each other.

The intensity of the distributed lood acting on the beams 25 kN/m.) Determine the magnitude of reaction at Express your answer to three significant figures and include the appropriate units O ? N Value Units Submit Request Answer Figure Part 6 1 of 1 Delane te zand y components of reaction all sing scalar notation Express your answers using three significant figures separated by a comma HV AED vec ?

Answers

The magnitude of reaction at the beam due to the distributed load of 25 kN/m is 625 N.

What is the magnitude of reaction to the distributed load?

The magnitude of reaction at the beam can be determined by calculating the total force exerted by the distributed load. In this case, the distributed load is given as 25 kN/m. To find the magnitude of reaction, we multiply the distributed load by the length of the beam.

Therefore, the magnitude of reaction is 25 kN/m multiplied by the length of the beam in meters. By performing the calculation, we obtain the value of 625 N as the magnitude of reaction at the beam due to the distributed load. This represents the total force exerted by the distributed load on the beam.

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a dockworker applies a constant horizontal force of 76.0 n to a block of ice on a smooth horizontal floor. the frictional force is negligible. the block starts from rest and moves a distance 10.0 m in a time of 5.30 s .(a)What is the mass of the block of ice?----- I found this to be 56.9kg and got it right.(b)If the worker stops pushing at the end of 4.30 s, how far does the block move in the next 4.20s ? ------ I tried using [distance=0.5at^2] but it says its wrong. how do you do this question?

Answers

a) The mass of the block of ice is 56.9kg

b) If the worker stops pushing at the end of 4.30 s, The distance the block moves in the next 4.20s is 9.96m

Explanation:

a) The given data are:

F = 76.0 N, t = 5.30 s, V = ?, u = 0, a = ?, d = 10.0 m, μ = 0

We know that:

F = ma

where

F is the force applied to the object

m is its mass

a is the acceleration produced by the force

We need to find the mass of the block so we can find its acceleration.

Using F = ma and substituting the values given, we have:76.0 = ma a = 76.0/m

We know that:

d = ut + 1/2at²

where

d is the distance covered by the object

u is its initial velocity, t is time

a is the acceleration of the object since it has been given that the block starts from rest.

u = 0 => d = 1/2at² = (76/m)(5.30/2)² = 14.0 m

Dividing by d = 10.0

we have:

10/14 = 1/1.4 = m/76m = (1/1.4) × 76 = 54.3 kg

Rounding to one decimal place, the mass of the block is 56.9 kg.

b) When the worker stops pushing the block, the force applied is zero so the acceleration of the block becomes zero too.

From 0 s to 4.30 s, the block has travelled a distance of:

d₁ = ut + 1/2at² = (0)(4.30) + (1/2)(76/m)(4.30)² = 69.5/m m

From 0 s to 5.30 s, the block travelled a distance of d = 10.0 m

Therefore, from 4.30 s to 5.30 s, the block travelled:

d - d₁ = 10.0 - 69.5/m

Substituting the value of m, we get:

d - d₁ = 10 - 69.5/56.9 = 9.96 m

Thus, the distance the block moves in the next 4.20 s is 9.96 m.

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The passage helps the reader to draw conclusions about which character's perspective? ºAlec ºAlice ºAlec's father ºAlec's mother

Answers

Answer:

I think it might be A: Alec but tell me if I'm wrong

Explanation:

Answer:

a

Explanation:

i did it on e d g e n u i t y

relative to sphere at the speed of sphere Z is _ m/s

relative to sphere at the speed of sphere Z is _ m/s

Answers

We are given that a sphere Z moves with a relative speed of 1 m/s with respect to sphere X which moves at 5 m/s. Let's draw the velocity vectors of the spheres:

Where:

\(\begin{gathered} v_x=\text{ velocity of sphere x} \\ v_z=\text{ velocity of sphere z} \end{gathered}\)

From the relative velocity equation we have:

\(v_z=v_r+v_x\)

Where:

\(v_r=\text{ velocity of z relative to x}\)

Since we are given the relative velocity we can plug in the values to get the velocity of "z":

\(\begin{gathered} v_z=1\frac{m}{s}+5\frac{m}{s} \\ \\ v_z=6\frac{m}{s}_{} \end{gathered}\)

Now, we do the same but now using the sphere Y:

Now, we use the relative velocity equation for these velocities:

\(v_z=v_r+v_y\)

In this case, we have that:

\(v_r=\text{ velocity of z with respect to y}\)

Now, we subtract the velocity of "y" from both sides:

\(v_z-v_y=v_r\)

Substituting the values:

\(6\frac{m}{s}-2\frac{m}{s}=v_r\)

Solving the operations:

\(4\frac{m}{s}=v_r\)

Therefore, the velocity of "Z" relative to "Y" is 4 m/s.

relative to sphere at the speed of sphere Z is _ m/s
relative to sphere at the speed of sphere Z is _ m/s

Predict the brightness on the distant screen if the path difference is exactly one wavelength λ (or any integer d sin θ number of wavelengths)? Explain your reasoning

Answers

If the path difference is exactly one wavelength, the screen will be at maximum brightness.

The brightness on a distant screen depends on the interference of light waves. If the path difference between two light waves is an integer number of wavelengths, then the waves will be in phase and constructively interfere, leading to maximum brightness on the screen.

If the path difference is exactly one wavelength (or any integer multiple of a wavelength), the light waves will have a phase difference of zero and will reinforce each other to produce maximum brightness.

This phenomenon is known as constructive interference and occurs when the crests of two light waves coincide.

Constructive interference produces the brightest regions on the screen and is an important aspect of many optical systems and applications, including diffraction gratings, holography, and interferometry.

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If mass of an empty 7.0 mL pycnometer is 10.2g and the mass of the same pycnometer with an unknown liquid is 21.8g. Determine the density of the unknown liquid to ONE DECIMAL PLACE in g/mL.

Answers

The formula for calculating density is expressed as

Density = mass/volume

From the information given,

mass of empty pycnometer = 10.2

mass of the same pycnometer with an unknown liquid is 21.8.

Mass of unkown liquid = 21.8 - 10.2 = 11.6

volume of unknown liquid = 7

Thus,

Density = 11.6/7

Density = 1.7 g/ml

A hot air balloon is rising with an acceleration of 3 m/sec2. The basket of the balloon has a mass of 260 kg. There are 3 people in the basket each with a mass of 70 kg. What is the tension in the cable holding the basket?

Answers

Answer: \(6016\ N\)

Explanation:

Given

Mass of basket is \(M=260\ kg\)

Mass of each person in the basket \(m=70\ kg\)

Acceleration of balloon is \(a=3\ m/s^2\)

Tension of the cable causes the bucket and 3 men to move upward with  \(a=3\ m/s^2\)

So, we can write

\(\Rightarrow T-[260+3\times 70]g=[260+3\times 70]a\\\Rightarrow T=[260+3\times 70](a+g)\\\Rightarrow T=[260+210](3+9.8)\\\Rightarrow T=470\times 12.8\\\Rightarrow T=6016\ N\)

a billiard ball travels 23 cm in the positive direction, hits the cushion and rebounds in the negative direction, and finally comes to rest 7.5 cm behind its original position.

Answers

The billiard ball involves relaxation 80 cm

Displacement refers to the space among the very last and the preliminary role. Hence the displacement of the ball can be the distinction among the preliminary and the very last displacement.

Let the preliminary role be 0

Final role = 8 cm

So the distinction among preliminary role and very last role = 0 - 88 cm

So the billiard ball involves relaxation 80 cm at the back of its orbital role.

What is displacement thickness in boundary layer theory?

The displacement thickness for the boundary layer is described as the gap the floor could need to pass withinside the y-course to lessen the glide passing via way of means of a extent equal to the actual impact of the boundary layer.

The distance from the boundary floor where the rate reaches 99% of the mainstream speed is used as an arbitrarily defined measure of the thickness of the boundary layer indicated by the symbol.

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Suppose a weight of 1 kg is attached to an oscillating spring with friction constant b=7 and stiffness constant k=6. Suppose the external forces on the weight are: F ext

(t)=−6te −3t
+e −3t
. y ′′
+7y ′
+6y=−6te −3t
+e −3t
a) Show y(t)=te −3t
is a possible position function for this weight. y ′1
+7y ′
+6y=−6tc −3t
+e −3t
r 2
+7r+6=0
(r+a)(r+1)
e −6t
e −t
y=1e −4t
+1e −t
y ′
=−61)e −4t
+Ae t
y ′
=−609e −4t
+e −+
(6,6e −4t
)+Me −t

b) Find a general equation for all possible position functions. y=Ae −6t
+AC 2
=−6+e 3t
+e −3t
(10 points) c) Find the exact motion equation for this weight if its initial position is y(0)=3, and its initial velocity is v(0)=y ′
(0)=

Answers

a) y(t) = te⁻³ᵗ is a possible position function.

b) General equation: y(t) = C₁e^(-2t) + C₂e^(-3t) + t(e^(-3t))(At + B).

c) Exact motion equation: y(t) = (23/5)e^(-2t) - (8/5)e^(-3t) + t(e^(-3t))(At + B), with initial conditions y(0) = 3 and v(0) = -7.

a) To show that y(t) = te⁻³ᵗ is a possible position function, we substitute it into the differential equation:

y(t) = te⁻³ᵗ

y'(t) = e⁻³ᵗ - 3te⁻³ᵗ

y''(t) = -6e⁻³ᵗ + 9te⁻³ᵗ

Substituting these expressions into the differential equation, we have:

-6e⁻³ᵗ + 9te⁻³ᵗ + 7(e⁻³ᵗ - 3te⁻³ᵗ) + 6(te⁻³ᵗ) = -6te⁻³ᵗ - e³ᵗ

Simplifying this equation, we find that both sides are equal, thus confirming that y(t) = te⁻³ᵗ is a possible position function.

b) The general equation for all possible position functions can be written as:

y(t) = C₁e^(-2t) + C₂e^(-3t) + t(e^(-3t))(At + B)

c) Given the initial conditions y(0) = 3 and y'(0) = v(0) = -7, we substitute these values into the general equation and solve for the constants:

3 = C₁ + C₂

-7 = -2C₁ - 3C₂

Solving these equations, we find C₁ = 23/5 and C₂ = -8/5.

The exact motion equation for the weight is:

y(t) = (23/5)e⁻²ᵗ - (8/5)e⁻³ᵗ + t(e⁻³ᵗ)(At + B)

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Suppose a weight of 1 kg is attached to an oscillating spring with friction constant b = 7 and stiffness constant k = 6. Suppose the external forces on the weight are: Fₑₓₜ(t) = - 6te⁻³ᵗ - e³ᵗ

y" + 7y' + 6y = - 6te⁻³ᵗ - e³ᵗ

a) Show y(t) = te⁻³ᵗ is a possible position function for this weight.

b) Find a general equation for all possible position functions.

c) Find the exact motion equation for this weight if its initial position is y(0) = 3, and its initial velocity is v(0) = y'(0) = -7.

The pycnocline of the oceans is usually found at depths exceeding 2000 m. group startstrue or false

Answers

The answer is False.

The correct statement is :

The pycnocline of the oceans is usually situated between the mixed layer and the deep layer.

What is Pycnocline?

The layer or cline in a body of water where the density gradient is the greatest is called a pycnocline. Breaking waves, temperature and salinity variations, wind, the Coriolis effect, and tides brought on by the gravitational attraction of celestial bodies are only a few of the forces that contribute to the generation of an ocean current. Additionally, flows and vertical profiles in the ocean are impacted by the physical characteristics of a pycnocline driven by density gradients. These alterations are related to the movement of heat, salt, and nutrients through the ocean, and upwelling is regulated by pycnocline diffusion.

The upper and lower water are separated below the mixed layer by a permanent density gradient, or pycnocline, which prevents vertical transit. This division affects the water and marine life in significant biological ways.

However, shear-induced turbulence in oceans causes vertical mixing over a pycnocline, a common occurrence. This mixing is crucial to the movement of nutrients.

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The pycnocline of the oceans is usually found at depths exceeding 2000 m. group starts False

The correct statement is :

The pycnocline of the oceans is usually situated between the mixed layer and the deep layer.

What is Pycnocline?

The layer or cline in a body of water where the density gradient is the greatest is called a pycnocline. Breaking waves, temperature and salinity variations, wind, the Coriolis effect, and tides brought on by the gravitational attraction of celestial bodies are only a few of the forces that contribute to the generation of an ocean current.

Additionally, flows and vertical profiles in the ocean are impacted by the physical characteristics of a pycnocline driven by density gradients. These alterations are related to the movement of heat, salt, and nutrients through the ocean, and up welling is regulated by pycnocline diffusion.

The upper and lower water are separated below the mixed layer by a permanent density gradient, or pycnocline, which prevents vertical transit. This division affects the water and marine life in significant biological ways.

However, shear-induced turbulence in oceans causes vertical mixing over a pycnocline, a common occurrence. This mixing is crucial to the movement of nutrients.

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how did galileo figure out that a falling object accelerates

Answers

Galileo conducted experiments by rolling balls down inclined planes at different angles and observed that the acceleration of the ball was constant and not dependent on the mass of the ball.


Galileo was an Italian astronomer and physicist who conducted experiments to understand the motion of objects. He was the first to develop the law of inertia, which states that objects at rest will remain at rest unless acted upon by an external force. To understand how falling objects accelerate, he conducted experiments by rolling balls down inclined planes at different angles.

Galileo observed that the acceleration of the ball was constant and not dependent on the mass of the ball. This observation led him to conclude that all objects in a vacuum fall at the same rate and that the acceleration of a falling object is constant.

Galileo's experiments and observations paved the way for the development of the laws of motion by Sir Isaac Newton. Newton's laws of motion are still used today to understand and describe the motion of objects.

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Mr. Chowder ties an eraser to a string and swings it in a circle with a radius of 0.974 meters. The eraser makes 127 revolutions in a minute. Determine its acceleration (in m/s/s).

Answers

The acceleration of the eraser is 169.19 m/s².

What is centripetal acceleration?

A body travelling in a circle has centripetal acceleration. Due to the fact that velocity is a vector quantity (i.e., it has both a magnitude and a direction), when a body travels in a circle, its direction is continually changing, which causes a change in velocity, which results in an acceleration.

Given that angular velocity of the eraser: ω = 127 rpm

= 126×2π/60 radian/second

= 13.2 radian/second.

radius of the circle: r = 0.974 meter.

Hence, its centripetal acceleration is = ω²r

= 13.2×13.2×0.974 m/s²

=169.19 m/s².

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Write an algorithm that calculate the time a train need to arrive at a detination given peed and ditance

Answers

An algorithm that calculates the time a train needs to arrive at a destination given speed and distance \(Time=\frac{Distance}{Speed}\).

What is Speed?

The amount of the shift in approach per unit of time or the size of the displacement over time for an object can be used to describe speed, which would be a scalar quantity in everyday language and kinematics.

The maximum speed that can be maintained when a period grows closer to zero is the starting speed.

By dividing the object's distance traveled by the duration of the interval, the mean pace of the object for the given period is calculated. Speed and velocity are not always the same thing.

The algorithm to calculate the time required will be,

Let the distance covered by the train is D and the speed of the train be S.

Then, the time taken by the train will be,

T = D/S

Here, D is the distance and S is the speed.

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Can anyone answer this question its a science question NO LINKS !!!!
Energy is the ability to do work or cause
change
friction
explosions
events

Answers

Answer:

change

Explanation:

Energy can be defined as the ability (capacity) to do work or cause change in a system.

The Law of Conservation of Energy states that energy cannot be destroyed but can only be transformed or converted from one form to another.

Energy is the ability to do work or cause change.

Basically, the various forms of energy are solar energy, electrical energy, chemical energy, thermal energy, wind energy, nuclear energy etc.

The two (2) main types of energy are;

a. Gravitational potential energy (GPE): it is an energy possessed by an object or body due to its position above the earth.

b. Kinetic energy (KE): it is an energy possessed by an object or body due to its motion.

Furthermore, the mechanical energy of a physical object or body is the sum of the potential energy and kinetic energy possessed by the object or body.

Mathematically, it is given by the formula;

Mechanical energy = G.P.E + K.E

a 2000 kg meteorite has a speed of 80 m/s just prior to colliding with earth and getting buried. what is the recoil speed of earth? (mass of earth

Answers

a 2000 kg meteorite has a speed of 80 m/s just prior to colliding with earth and getting buried.  the recoil speed of earth is  2.67*10^(-20) m/s

2000*80=(5.98*10^24+2000)v

v=2.67*10^(-20) m/s

Recoil speed may be calculated using a straightforward equation according to the law of conservation of momentum, which is a result of Newton's Laws of Motion. It is based on the mass of the recoiling body and the mass and velocity of the body that was expelled.

According to Newton's Third Law, every applied force produces an equal and opposite response. The collision of a fast car with a brick wall is a typical illustration used to teach this law. The wall is pulled against by the car, which in turn is pulled against by the wall, crushing the car.

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In which scenario will the two objects have the least gravitational force between them? A. Mass of object 1 = 12 kg Mass of object 2 =12 kg Distance between objects =1.5 m B. Mass of object 1 =15 kg Mass of object 2 = 12 kg Distance between objects =1.5 m DC. Mass of object 1 = 15 kg Mass of object 2= 12 kg Distance between objects = 0.5 m ()D. Mass of object 1 =12 kg Mass of object 2=12 kg Distance between objects = 0.5 m​

Answers

If both objects have a mass of 12 kg and are separated by 1.5 m, scenario A would have the least gravitational pull on them. (option-a)

The gravitational pull between any two objects is determined by both their masses and their separation from one another. The force of gravity is directly proportional to the product of the masses and inversely proportional to the square of the distance between the objects, according to Newton's law of universal gravitation.

We must choose the scenario with the least gravitational force among the ones provided. Let's examine each instance:

A. The weights of the first and second objects are each 12 kg, and their separation is 1.5 m.

B. Mass of object 1 = 15 kg, Mass of object 2 = 12(option-a)

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hello I need help with this question. I started it but am confused

hello I need help with this question. I started it but am confused

Answers

Given:

The mass on the table is,

\(m=1.0\text{ kg}\)

The hanging mass is,

\(M=1.5\text{ kg}\)

THe coefficient of friction is,

\(\mu=0.20\)

let the acceleration of the whole system is a (for the hanging mass it is downward and for the mass on the table it is rightward). the tension towards The fixed point of the pulley is T.

we can write,

\(Mg-T=Ma\ldots.\ldots..\ldots\ldots.(1)\)\(ma=T-\mu mg\ldots.\ldots.\ldots..\ldots..(2)\)

Adding these equations we get,

\(\begin{gathered} (M+\mu m)g=(M+m)a \\ a=\frac{(M+\mu m)g}{M+m} \end{gathered}\)

Substituting the values we get,

\(\begin{gathered} a=\frac{(1.5+0.20\times1.0)9.8}{1.5+1.0} \\ =6.67m/s^2 \end{gathered}\)

Hence the acceleration is 6.66 m/s^2.

A 10 kg block sits on a level surface, and a horizontal force of 50 N is applied to the block. If the coefficient of static friction between the block and the surface is 0.75, does the block move? If not, how great a force would be required to move the block?

Answers

The block will not move.

The amount of force that would be required to move the block is 73.5 N

What is force?

Force can be defined as the product of mass and acceleration.

The S.I unit of force is Newton (N)

For the block to move, The horizontal force applied to the block but be greater than the static friction of the floor on the block.

F > F'F = Force applied to the block = 50 N.F' = mgμ................. Equation 1

Where:

F = Frictional force,m = mass of the blockg = acceleration due to gravity of the blockμ = coefficient of static friction of the block.

From the question,

Given:

m = 10 kgg = 9.8 m/s²μ = 0.75

Substitute these values into equation 1

F' = (10×9.8×0.75) = 73.5 N.

Comparing F and F', It can be seen that

F < F'

There, The block will not move.

The amount of force that would be required to move the block is 73.5 N

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an object is rolling without slipping. what percentage of its total kinetic energy is its translational kinetic energy if the object is (a) a uniform sphere, (b) a uniform cylinder, or (c) a hoop?

Answers

When the object is a sphere of Radius R and mass M the 60% of its total kinetic energy is its translational kinetic energy.

What is a kinetic energy?

The kinetic energy of an object is termed as the energy it posses because of its motion.

What is translational kinetic energy?

The translational kinetic energy is the energy required to move or accelerate the object from its position of rest.It is described as the effort required to move a mass-determined body from rest to the indicated velocity.

The moment of inertia of the object will be⇒I =2/3MR2

Sphere is rolling without slip ,v=Rω (v= speed of centre of mass and ω is angular speed)

Translational KE =1/2Mv2

Rotational KE = 1/2Iω2=1/2(2/3MR2)x(V/R)2=1/3Mv2

Total KE= 1/2Mv2 +1/3Mv2 =5/6 Mv2

Now % of Translational Energy= 1/2Mv2 ÷ 5/6 Mv2 x100 = 60%

Hence, when the object is a sphere of Radius R and mass M the 60% of its total kinetic energy is its translational kinetic energy.

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Why are materials liquids at higher temperatures in terms of Gibbs free energy

Answers

The reason why materials become liquids at higher temperatures can be explained in terms of Gibbs free energy.

At higher temperatures, the entropy or disorder of the material increases, which leads to a decrease in Gibbs free energy. In other words, the system becomes more energetically favorable in the liquid state than in the solid state, resulting in a phase transition from solid to liquid. This is due to the fact that in the liquid state, the molecules have more freedom of movement and can occupy a greater number of microstates, which leads to an increase in entropy and a decrease in Gibbs free energy. Therefore, as the temperature increases, the Gibbs free energy of the liquid state becomes lower than that of the solid state, resulting in a phase transition from solid to liquid.

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6. The bat hits a ball. What is the
reaction force?

Gravity the puling the ball down


The ball hits the bat


Air resistance slowing the ball down

Answers

Answer:

The ball hits the bat

Explanation:

.......

which element on the periodic table has the largest atomic number?

Answers

Answer:

Oganesson

Oganesson has the highest atomic number and highest atomic mass of all known elements. The radioactive oganesson atom is very unstable, and since 2005, only five (possibly six) atoms of the isotope 294Og have been detected.

Explanation:

here the file attached

here the file attached

Answers

Answer:

A

Explanation:

Amplitude = height of the wave = 1

Wavelength = 3

They are slightly shifted.

The first statement is the correct one.  Don't make me type the whole thing out.

Explain why pulleys are in the lever family.

Answers

Answer:

The leverage or mechanical advantage of pulleys is less obvious, but you can "gang" multiple pulleys together into two sets (blocks) and run the ropes back and forth between the two sets to increase the number of lengths of rope running between them. One end of the rope is connected (fixed) to one of the blocks, and you get to pull on the other end after it is passed back and forth between the blocks of pulleys. This is sometimes called a block and tackle arrangement. With a hook on each side of the block set, you can move a heavy load much like levers do, by multiplying the force. You have to pull more rope just like you have to move a lever more on one side of the fulcrum as compared to the other. When you get all the rope pulled out that you can, you can not move the load anymore because you have become "two-blocked" which means the two blocks are together. Credits to: Moin Khan

You toss a ball straight up in the air. Immediately after you let go of it, what force or forces are acting on the ball? For each force you name,
(a) state whether it is a contact force or a long-range force and
(b) identify the agent of the force.

Answers

a) Gravity: This is a long-range force and the agent of the force is the Earth. b) Air Resistance: This is a contact force and the agent of the force is the air molecules. c) Normal Force: This is a contact force and the agent of the force is the ground.

What is Air Resistance?

Air resistance, also known as drag, is a type of frictional force that acts upon objects when they move through a fluid, such as air or water. Air resistance occurs when the air molecules surrounding an object collide with the object’s surface, resulting in a resistive force that opposes the object’s motion. The magnitude of air resistance is dependent on the object’s shape, size, mass, speed, and altitude. Objects with a large surface area, such as parachutes, are more affected by air resistance than objects with a smaller surface area. Air resistance increases with an object’s speed and is stronger at higher altitudes, where the air is thinner. The effects of air resistance can be seen in everyday objects, such as an airplane or a car, and can be reduced by altering an object’s shape or by decreasing its speed.

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is oxegen abiotic or biotic

Answers

Answer:

Oxygen is abiotic

Explanation:

Oxygen is abiotic because it’s non living
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