calcium react with oxygen to form .write a chemical balanced equation of the reaction.

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Answer:

43 protons

36 electrons

56 neutron

Explanation:

neutron is mass number minus proton number.

in a non neutral atom the electron is determined after minusing the charges or electron lost.

the number of proton obviously is 43

The combined Gas Law equation is represented by B) P1V1 / T1 = P2V2 / T2.

The combined gas law is the law that combines Charles’s law, Gay-Lussac’s law, and Boyle’s law.

Combined gas law can be mathematically expressed as

k = PV/T

Where,

P = pressure

T = temperature in kelvin

V = volume

K  = constant (units of energy divided by temperature)

When two substances are compared in two different conditions, the law can be stated as,

P1V1/T1 = P2V2/T2

Where,

P1 = initial pressure

V1 = initial volume

T1 = initial temperature

P2 = final pressure

V2= final volume

T2 = final temperature

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Answer:

f; core

Explanation:

the only one that makes sense

Considering the Hess's Law, the enthalpy change for the reaction is 221.8 kJ/mol.

Hess's Law indicates that the enthalpy change in a chemical reaction will be the same whether it occurs in a single stage or in several stages. That is, the sum of the ∆H of each stage of the reaction will give us a value equal to the ∆H of the reaction when it occurs in a single stage.

In this case you want to calculate the enthalpy change of:

C₂H₄ (g) + 6 F₂ (g) → 2 CF₄ (g) + 4 HF (g)

which occurs in three stages.

You know the following reactions, with their corresponding enthalpies:

Equation 1: H₂ (g) + F₂ (g) → 2 HF (g)     ∆H° = -79.2 kJ/mol

Equation 2: C (s) + 2 F₂ (g) → CF₄ (g)     ∆H° = 141.3 kJ/mol

Equation 3: 2 C(s) + 2 H₂ (g) → C₂H₄ (g)     ∆H° = -97.6 kJ/mol

Because of the way formation reactions are defined, any chemical reaction can be written as a combination of formation reactions, some going forward and some going back.

First, to obtain the enthalpy of the desired chemical reaction you need one mole of C₂H₄ (g) on reactant side and it is present in first equation. Since this equation has one mole of C₂H₄ (g) on the product side, it is necessary to locate it on the reactant side (invert it).

When an equation is inverted, the sign of ΔH° also changes.

Now, you need 2 moles of CF₄ (g) on the product side. The second equation has 1 mole of CF₄ (g) on the product side, so it is necessary to multiply it by 2 to obtain 2 moles of CF₄ (g).

Since enthalpy is an extensive property, that is, it depends on the amount of matter present, since the equation is multiply by 2, the variation of enthalpy also.

Finally, you need 4 moles of  HF (g) on the product side. The first equation has 2 moles of  HF (g) on the product side, so it is necessary to multiply it by 2 to obtain 4 moles of the compound.

Since the equation is multiply by 2, the variation of enthalpy also is multiplied by 2.

In summary, you know that three equations with their corresponding enthalpies are:

Equation 1: 2 H₂ (g) + 2 F₂ (g) → 4 HF (g)     ∆H° = -158.4 kJ/mol

Equation 2: 2 C (s) + 4 F₂ (g) → 2 CF₄ (g)     ∆H° = 282.6 kJ/mol

Equation 3: C₂H₄ (g) → 2 C(s) + 2 H₂ (g)     ∆H° = 97.6 kJ/mol

Adding or canceling the reactants and products as appropriate, and adding the enthalpies algebraically, you obtain:

C₂H₄ (g) + 6 F₂ (g) → 2 CF₄ (g) + 4 HF (g)     ΔH°= 221.8 kJ/mol

Finally, the enthalpy change for the reaction is 221.8 kJ/mol.

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Answer: D) Eight

Just pretend this part doesn't exist nope nothing to see here the answer is correct on edge2020 I swear on my brainly points

Answer:

d

Explanation:

The gas law that is calculated with the pressure and volume variables at a constant temperature is Boyle's Law. Boyle's Law states that the pressure (P) of a gas is inversely proportional to its volume (V) when temperature (T) is held constant.

Mathematically, it is expressed as P₁V₁ = P₂V₂, where P₁ and V₁ represent the initial pressure and volume, and P₂ and V₂ represent the final pressure and volume.According to Boyle's Law, if the volume of a gas is reduced while keeping the temperature constant, the pressure will increase proportionally.

Similarly, if the volume is increased, the pressure will decrease. This relationship holds as long as the temperature remains constant throughout the process. Boyle's Law is one of the fundamental gas laws and provides insights into the behavior of gases under changing pressure and volume conditions at a constant temperature.

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Answer:

762.60 g

Explanation:

In order to convert from moles of a substance into grams, we need to multiply the number of moles by the substance's molar mass:

With the above information in mind, we can use the data given by the problem and calculate how many grams are there in 12 moles of Cu:

Answer:

second law of thermodynamics

Explanation:

According to the second law of thermodynamics, the total entropy of a system and its surroundings always increases for a spontaneous process.

Entropy is defined as the degree of disorderliness of a system. The entropy of a system never remains constant. It either increases or decreases in a process. The total entropy is the sum of the entropy of the system and its surrounding. The total entropy must increase in a spontaneous process.

Thus, the implication of this law is that even, if the entropy of a system decreases, this must be compensated for by increase in entropy of the surroundings in order for the process to be spontaneous.

A chemical reaction in which electrons are transferred from one atom to another is an ionic bond.

The total transfer of certain electrons from one atom to another results in the formation of an ionic bond.

A negatively charged ion known as a cation results from an atom losing one or more electrons. An anion, an ion with a negative charge, is created when an atom gains one or more electrons.

Ionic bonds are formed for a number of reasons, one of which being the stark disparities in electronegativity between atoms, which draw other atoms near them for the exchange of electrons.

Thus,A chemical reaction in which electrons are transferred from one atom to another is an ionic bond.

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1.29×10²⁴ atoms are in 2.15 moles of water. Atom is also the smallest piece of substance with chemical element-like characteristics.

The smallest unit of matter that may be divided without producing electrically charged particles is the atom. It is also the smallest piece of substance with chemical element-like characteristics. As a result, the atom serves as the fundamental unit of chemistry.

Space makes up the majority of an atom. The rest is made up of a cloud of electrons that are negatively charged surrounding a nucleus that is positively charged made up of protons and neutrons. The behaviour of the electron in an atom can be compared to that of particles surrounding the nucleus.

number of atoms = number of moles ×6.022×10²³

                               = 2.15×6.022×10²³

                                = 1.29×10²⁴

Therefore, 1.29×10²⁴ atoms are in 2.15 moles of water.

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Answer:

replacement

Explanation:

Answer:

The biochemical properties of water are 1) chemical structure of water 2) water is a good solvent 3) hydrogen bonding. 4) sticky, wet water 5)the density of ice and water

Explanation:

hope the picture above make sense:)

Answer: 3 4 a noodles

Explanation: just is\(\lim_{n \to \infty} a_n \lim_{n \to \infty} a_n \lim_{n \to \infty} a_n \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \sqrt{x} x^{2} x^{2}\)

The electronic configuration of the chlorine atom can be written as 2, 8 , 7

The positioning of electrons within an atom's or molecule's orbitals is referred to as its electronic configuration. Around the atomic nucleus of an atom, electrons—negatively charged subatomic particles—occupy various energy levels or shells.

The electrons in an atom fill these energy levels or shells in a certain order in accordance with a series of laws known as the Aufbau principle, Pauli exclusion principle, and Hund's rule. Each energy level or shell has a maximum capacity for electrons.

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Answer:

true is correct

Polyester and Nylon are examples of synthetic materials called polymers. This statement is True.

Polymers are large molecules composed of repeating subunits called monomers, which are chemically bonded together. In the case of polyester, it is made from a polymer called polyethylene terephthalate (PET), while Nylon is made from polyamide monomers. These polymers are created through polymerization processes that combine smaller molecules to form long chains.

Synthetic polymers like polyester and nylon are widely used in various applications due to their desirable properties, such as strength, durability, and resistance to chemicals and moisture.

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55.03 moles of KCI are produced when 6743 grams of \(KClO_{3}\) decomposes

To determine the number of moles of KCl produced when 6743 grams of \(KClO_{3}\) decomposes, we need to use the concept of molar mass and the balanced chemical equation.

First, let's calculate the molar mass of \(KClO_{3}\)

The molar mass of potassium (K) is approximately 39.10 g/mol.

The molar mass of chlorine (Cl) is approximately 35.45 g/mol.

The molar mass of oxygen (O) is approximately 16.00 g/mol.

So, the molar mass of \(KClO_{3}\) is:

(39.10 g/mol) + (35.45 g/mol) + (3 * 16.00 g/mol) = 122.55 g/mol.

Now, we need to calculate the number of moles of \(KClO_{3}\):

Number of moles = Mass / Molar mass

Number of moles = 6743 g / 122.55 g/mol = 55.03 mol.

According to the balanced chemical equation:

2\(KClO_{3}\) -> 2 KCl + 3 O2,

we can see that for every 2 moles of \(KClO_{3}\), we obtain 2 moles of KCl.

Therefore, the number of moles of KCl produced will be equal to the number of moles of \(KClO_{3}\) since the ratio is 1:1. Thus, 55.03 moles of KCl will be produced.

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Answer:

To start, you need know that all a mole means is you have 6.022 x 1023 atoms of that type. So if I tell you I have a mole of nitrogen, then I have 6.022 x1023 nitrogen atoms. That ugly number is called Avogadro's Constant, NA

Explanation:

hy its isnt the correct answer but checkout the equation hope it help help

Answer:

The one above me is correct! I used it. But of course I had to write a little different to the person's sentences and draw a little differently in my own way.

Explanation:

If somehow you can't open the PDF (the comment on top of my comment) here I took a screenshot of it, if you need it! Good luck everyone :D

Answer:

yes

Explanation:

its not that hard to get

Answer: The mass concentration for a solution containing 45 g of calcium carbonate for 100 \(cm^{3}\) is 0.045 M.

Explanation:

Given: Mass of calcium carbonate = 45 g

Volume = \(100 cm^{3}\)

Convert \(cm^{3}\) into L as follows.

\(1 cm^{3} = 0.001 L\\100 cm^{3} = 100 cm^{3} \times \frac{0.001 L}{1 cm^{3}}\\= 0.1 L\)

Moles of calcium carbonate (molar mass = 100 g/mol) is as follows.

\(No. of moles = \frac{45 g}{100 g/mol}\\= 0.45 mol\)

Molarity is the number of moles of solute present in a liter of solution.

Hence, molarity (or mass concentration) of given solution is calculated as follows.

\(Molarity = \frac{no. of moles}{Volume (in L)}\\= \frac{0.45 mol}{0.1 L}\\= 0.045 M\)

Thus, we can conclude that the mass concentration for a solution containing 45 g of calcium carbonate for 100 \(cm^{3}\) is 0.045 M.

Answer:

400 mL

Explanation:

Boyle's Law: \(P_1*V_1 = P_2*V_2\)

Let x = the resulting volume

350 (200) = 700 (x)

x = 400 mL

If an equation includes 7(CrO₄)₂, the numbers of Cr's and O's atoms that are there are 14 and 56 respectively.

The number of atoms present in a chemical compound can be calculated by multiplying the subscript of the particular element by any coefficient.

According to this question, 7 moles of chromate with the chemical formula; (CrO₄)₂ is given. The number of oxygen and chromium atoms in this compound can be calculated as follows:

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The correct answer is A. Since the system is cooled, the reaction will try to generate heat to compensate for the loss.

According to Le Chatelier's principle, the system will shift in the direction that opposes the stress. In this case, cooling is the stress and the system will shift in the direction that produces heat.

Therefore, the reaction will shift to the right (products) to generate heat. This will cause the concentration of HI to increase, while the concentrations of H₂ and I₂ decrease, according to the stoichiometry of the reaction. Therefore, the correct answer is A. The reaction shifts to the right (products) and the concentration of HI increases.

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Answer: The reaction shifts to the left (reactants) and the concentrations of H^2 and I^2 increase is correct. (Answer C)

Answer:

To design a robot that propels itself across an ice rink using the same principles as rockets, I would start by considering the materials that would be suitable for use on ice. Some materials that might work well for this purpose include plastic, rubber, and certain types of metal, such as aluminum or stainless steel.

Explanation:

Answer:

Explanation:

Students learn about humankind’s search for life in outer space and how it connects to robotics and engineering. NASA is interested in sending exploratory missions to one of Jupiter’s moons, Europa, which requires a lot of preparatory research and development on Earth before it can happen. One robot currently being engineered as a proof of concept for a possible trip to explore Europa is the Icefin, which is an innovative robot that can explore under ice and in water, which are the believed conditions on Europa. This lesson provides students with intriguing information about far off (distance and time!) space missions and field robotics, and also sets up two associated robotics and arts integration activities to follow. The lesson can be used individually to provide new information to students, or as a precursor to the associated activities. A PowerPoint® presentation and worksheet are provided

Answer:

Explanation:

Let the products in the outlet streams be P(i.e. CH₃OH), Q(i.e. C₂H₅OH) and R(i.e. C₃H₇OH) respectively

Then the mass balance for CO, H and C₂H₅OH can be computed as follows:

For CO, The mass balance is;

100 - P - 3Q - 5R = 30    --- (1)

For H₂, The mass balance is;

100 - 2P - 3Q - 4R = 30    --- (2)

For C₂H₅OH, The mass balance is;

Q = 5    --- (3)

Replacing the value of equation(3) into equation (1) and (2); we have:

From equation (1):

100 - P - 3(5) - 5R = 30    --- (1)

100 - 15 - P - 5R = 30

85 - P - 5R = 30

85 - 30  = P + 5R

P + 5R = 55    ----- (4)

From equation (2):

100 - 2P - 3Q - 4R = 30    --- (2)

100 - 2P - 3(5) - 4R = 30

100 - 15 - 30 = 2P +4R

55 = 2P + 4R

2P + 4R = 55     ----- (5)

From equation (4) and (5); we have:

P + 5R = 55    ----- (4)

2P + 4R = 55     ----- (5)

From equation (4);

Let P = 55 - 5R

Then, replace P = 55 - 5R in equation (5)

2(55 - 5R) + 4R = 55  

110 - 10R + 4R = 55

110 - 6R = 55

6R = 110 - 55

6R = 55

R = 55/6

R = 9.17

Substitute, the value of R in equation (5); we have:

2P + 4R = 55

2P + 4(9.17) = 55

2P  = 55 - 4(9.17)

2P  = 55 - 36.68

2P  =  18.32

P = 18.32/2

P = 9.16

Therefore, the outlet stream rates are as follows:

                  Mass Feed Rate   ( mol/hr)               Molar ratio

CO                  30                                                    0.281

H₂                    30                                                   0.281              

CH₃OH            9.16                                                0.085

C₂H₅OH            5                                                   0.047

C₃H₇OH           9.17                                                0.086

CO₂                 23.34                                              0.219

Total:                106.67

1. Descending nephron loop - water moves out and solutes move in.

2. Ascending nephron loop - water is not removed, but solutes are removed.

3. Distal tubule and collecting duct - if adh is present, water and nacl move out.

The primary function of the Henle loop is to recover water and sodium chloride from urine. The amount of water needed to survive is decreased by the production of urine, which is produced and is much more concentrated than blood.

Water diffuses into the surrounding peritubular fluids in the descending limb of the nephron loop, leaving a tiny volume of highly concentrated tubular fluid. Reabsorbing water is necessary for this reduction to occur. Water and solutes cannot pass through the tick's ascending limb.

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