Brian is making a cake for his friend's birthday. He combines the ingredients for the cake and then pours the batter into two pans and bakes them for 45 minutes in the oven. While the pans are in the oven, he combines butter, sugar, and milk and mixes them together to make the icing. What type of changes created the cake and the icing?

A. Both the icing and the cake are formed by physical changes.
B. Both the icing and the cake are formed by chemical changes.
C. The icing is formed by a chemical change and the cake is formed by a physical change.
D. The cake is formed by a chemical change and the icing is formed by a physical change.

Answers

Answer 1

Answer:

it’s D.The cake is formed by a chemical change and the icing is formed by a physical change

Explanation:

It’s because when the cake was baking there was nothing physical about it so it was a chemical change the icing is formed by a physical change because all you did was mix three ingredients together

Answer 2

The type of changes that created the cake and the icing is;

Option D; The cake is formed by a chemical change and the icing is formed by a physical change.

 

This is about understanding type of changes in chemistry.

Physical change is defined as a change that affects the form of a compound or element but it doesn't affect its' chemical composition.Meanwhile, chemical change is defined as a change that affects the composition of a compound and a new substance is formed.

Now, for brian's cake he has combined raw ingredients into two pans and bakes the cake. For the cake to be baked, it means the ingredients mixed have changed from liquid to solid and also a new substance has been formed. Thus, we can say that the cake was formed from chemical change.

Meanwhile, the icing was formed by physical change because it did not undergo any chemical process and no new substance was formed as only butter, sugar and milk were mixed together.

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Related Questions




Cocoa beans are subjected to three processes during the manufacture of chocolate: cleaning, roasting, and 'nibbing'. Bags of cocoa beans are first cleaned, then cleaned beans are roasted, then roasted

Answers

Beans are processed through 'nibbing'. During the nibbing process, the roasted cocoa beans are crushed and ground into a paste called cocoa mass or cocoa liquor.

This cocoa mass can then be further processed to separate the cocoa solids from the cocoa butter, which is the fat component of the cocoa bean. The separated cocoa solids and cocoa butter are used in the production of chocolate. Pure cocoa mass (cocoa paste) in solid or semi-solid form is known as chocolate liquor. It includes about equal amounts of cocoa butter and solid cocoa, much like the cocoa beans (nibs) from which it is made. It is made from fermented, dried, roasted, and separated from their skins cocoa beans. To make cocoa mass (cocoa paste), the beans are pulverised.

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True or False? Some solids after mixing with other solids can be distinguished from each other

Answers

Answer:

True

Explanation:

Depends of the size and comparison

true, it all depends on the sizes


Write the symbol for every chemical element that has atomic number greater than 11 and atomic mass less than 24.8

Answers

Answer: You would write elements in period 1, 2, 3, and period 4 but you would stop at chromium

Explanation: It would have been too long for me to write every symbol

please rank these 1 to most effective and 3 to least, it's for my final exam.​

please rank these 1 to most effective and 3 to least, it's for my final exam.

Answers

The rank based on the effect of the given factors on the calcification rate is as follows;

Add Ca²⁺Lower CO₂Add CO₃²⁻

What is calcification rate?

Calcification rate is the rate at which organisms such as corals, mollusks, and algae secrete calcium carbonate to form their hard skeletons or shells.

The calcification rate is influenced by various environmental factors such as temperature, pH, and the availability of calcium and carbonate ions.

Considering the effect of the given factors on the calcification rate;

Adding Ca²⁺ will be the most effective as it will increase the calcium carbonate saturation state, which can lead to increased calcification rates.Lowering CO₂ levels will be moderately effective, as it will also increase the saturation state, but to a lesser extent compared to adding Ca²⁺.Adding CO₃²⁻ will be the least effective, as it may not increase the saturation state enough to significantly improve calcification rates.

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A metal alloy is made by mixing Metal A and Metal B. If 100kg of the mixture contains 60% by mass of metal A and 40% by Mass of metal & Calculate the density of the metal alloy Give density of Metal A as 9000 kgm 3 and density of Metal B as 6000 kgm 3)

Answers

Answer:

The density of the metal alloy is 7,496.25 kg/m^3 (rounded to 7,496 kg/m^3).

Explanation:

The given information from the exercise is:

- Metal alloy mass (m): 100kg

- Mass of metal A (mA): 60kg

- Mass of metal B (mB): 40kg

- Density of metal A (dA): 9,000 kg/m^3

- Density of metal B (dB): 6,000 Kg/m^3

1st) With the values of mass and density of each metal, we have to calculate the volume of each metal:

• Volume metal A:

\(\begin{gathered} V_A=\frac{m_A}{d_A} \\ V_A=\frac{60kg}{9,000\frac{kg}{m^3}} \\ V_A=6.67*10^{-3}m^3 \end{gathered}\)

• Volume metal B:

\(\begin{gathered} V_B=\frac{m_B}{d_B} \\ V_B=\frac{40kg}{6,000\frac{kg}{m^3}} \\ V_B=6.67*10^{-3}m^3 \end{gathered}\)

The volume of metal A and metal B is 6.67x10^-3 m^3. So, we have to add them to obtain the total volume of the metal alloy:

\(\begin{gathered} V=V_A+V_B \\ V=0.00667m^3+0.00667m^3 \\ V=0.01334m^3 \end{gathered}\)

2nd) Now we can calculate the metal alloy density, replacing the values of Volume (V) and the metal alloy mass (100kg) in the density formula:

\(\begin{gathered} d=\frac{m}{V} \\ d=\frac{100kg}{0.01334m^3} \\ d=7.496.25\frac{kg}{m^3} \end{gathered}\)

So, the density of the metal alloy is 7,496.25 kg/m^3 (rounded to 7,496 kg/m^3).

select the single best answer. which element in the following set would you expect to have the lowest ie3? a. Na
b. Mg
c. Al
d. B
e. Li

Answers

The answer would be Li.

The element with the lowest ionization energy is the one with the largest atomic radius. Therefore, the answer would be e. Li, as it has the largest atomic radius in the set provided.

The ionization energy is a measure of the capability of an element to enter into chemical reactions requiring ion formation or donation of electrons. It is also generally related to the nature of the chemical bonding in the compounds formed by the elements

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In an experiment between 26.4 grams of Mg and O,, Mgo is produced. The percent
yield was 90%. Determine the actual yield of magnesium oxide.

Answers

Answer:

39.6 g

Explanation:

The equation of the reaction is;

2Mg(s) + O2(g) --------> 2MgO(s)

To obtain the limiting reactant;

Number of moles in 26.4 g of Mg = 26.4g/24 g/mol = 1.1 moles

If 2 moles of Mg yields 2 moles of MgO

1.1 moles of Mg yields 1.1 * 2/2 = 1.1 moles of MgO

Number of moles in 26.4 g of O2 = 26.4 g/32g/mol = 0.825 moles

If 1 mole of O2 yields 2 moles of MgO

0.825 moles of O2 yields 0.825 moles * 2/1 = 1.65 moles of MgO

Hence Mg is the limiting reactant.

Theoretical yield of MgO = 1.1 moles of MgO * 40 g/mol = 44 g

Percent yield = 90%

Percent yield = actual yield/theoretical yield * 100

Actual yield = Percent yield * theoretical yield/100

Actual yield = 90 * 44/100

Actual yield = 39.6 g

In the previous step, you determined
0.25 mol HCI reacts. The molar mass
of Mg is 24.31 g/mol.
What mass of Mg is required?


PLEASE HELP ASAP

In the previous step, you determined0.25 mol HCI reacts. The molar massof Mg is 24.31 g/mol.What mass

Answers

Approximately 3.04 grams of magnesium would be required to react with 0.25 moles of hydrochloric acid.

To determine the mass of Mg required, we need to use the balanced chemical equation for the reaction between hydrochloric acid (HCl) and magnesium (Mg):

2HCl + Mg → MgCl2 + H2

From the balanced equation, we can see that 2 moles of HCl react with 1 mole of Mg. Therefore, if 0.25 mol of HCl reacts, we would need half of that amount, which is 0.125 mol of Mg.

To calculate the mass of Mg required, we need to multiply the number of moles of Mg by its molar mass. The molar mass of Mg is given as 24.31 g/mol. Therefore, the mass of Mg required can be calculated as follows:

Mass of Mg = Number of moles of Mg × Molar mass of Mg

Mass of Mg = 0.125 mol × 24.31 g/mol

Mass of Mg = 3.04 g

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Professor Nimbus is concerned about climate change, and thinks that removing water vapor from the atmosphere is the best way to weaken the greenhouse effect. Nimbus proposes that we could build a giant machine that removes half of the atmosphere's water vapor. They say because water vapor is such a strong greenhouse gas we would only have to run the machine once and this will solve the climate problem, even as carbon dioxide, methane, and nitrous oxide concentrations continue to rise and cause global warming.
In 3-4 sentences, determine whether Professor Nimbus' reasoning is correct and explain your answer.

Answers

Professor Nimbus' reasoning is not correct.

While water vapor is indeed a greenhouse gas, it plays a complex and dynamic role in the Earth's climate system. Removing half of the atmosphere's water vapor would have significant and detrimental consequences for the planet. Water vapor is intricately connected to various natural processes and is an essential component of the Earth's hydrological cycle.

Additionally, addressing climate change requires comprehensive and multifaceted approaches that include reducing greenhouse gas emissions, transitioning to renewable energy sources, and implementing sustainable practices across various sectors, rather than focusing solely on one greenhouse gas.

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How far i a houe in New York if it take you 5 hour to get there and your average peed i 20 km per half hour?

Answers

Using  Speed, distance and time relation, the distance is 400 kilometers.

Distance is the sum of an object's movements, regardless of direction. Distance can be defined as the amount of space an object has covered, regardless of its starting or ending position.

The International System of Units defines a metre as the distance unit. It's interesting to note that many other derived units or quantities, such as volume, area, acceleration, and speed, may be constructed using this as the basic unit and a few formulae.

20 kilometers per hour is the speed per half-hour.

Speed in kilometers per hour: 40 × 2 = 80

Distance x time = speed

Distance = Time × Speed

= 80 × 5

= 400 miles

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in ionic bonds will the alkaline earth metals lose or gain electrons, how many?

Answers

In ionic bonds, alkaline earth metals will lose two electrons to achieve a stable octet configuration.

Alkaline earth metals belong to Group 2 of the periodic table and have two valence electrons. They tend to lose these two electrons to achieve a stable electron configuration, forming ions with a +2 charge.

This is because alkaline earth metals have two valence electrons in their outermost shell, and losing these electrons will result in a full shell and a more stable configuration.

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A group of 6 students was asked, "How many hours did you watch television last week?" Here are their responses.
7,9,4,13,13,16
Find the mean number of hours for these students.
If necessary, round your answer to the nearest tenth.

Answers

Answer:

10.3

Explanation:

What is the solubility of nitrogen gas (in mol/L) at 25°C?

Answers

Answer:

26 c i the write answers. please accept

How does the jet stream over the United States change by season?

Answers

Jet streams are always changing: moving to higher or lower altitudes, breaking up, and shifting in flow, depending on the season and other variables, such as energy coming from the sun. Air north of a jet stream is typically colder, while air to the south is usually warmer

What do you understand by the terms radial node and nodal plane, as applied to AO wavefunctions? Illustrate your answer using the 2s and 2p AOs. Explain why radial nodes arise from the radial part of the wavefunction, whereas nodal planes arise from the angular part of the wavefunction

Answers

In the context of atomic orbital (AO) wavefunctions, the terms "radial node" and "nodal plane" refer to different aspects of the wavefunction's behavior.

A radial node is a region in the AO wavefunction where the probability of finding an electron is zero along the radial direction. In other words, it represents a spherical shell where the electron is unlikely to be found. The number of radial nodes is determined by the principal quantum number (n) of the orbital. For example, the 2s orbital has one radial node, while the 2p orbital has no radial nodes.

On the other hand, a nodal plane is a flat plane within the AO wavefunction where the probability of finding an electron is zero along a particular direction. It represents a surface that divides the orbital into two regions of opposite phases. The number of nodal planes is determined by the angular quantum numbers (l and m) of the orbital. For example, the 2s orbital has no nodal planes, while the 2p orbital has one nodal plane (the xz or yz plane).

Radial nodes arise from the radial part of the wavefunction because they depend on the distance from the nucleus. The radial part determines the distribution of the electron density as a function of distance, and the nodes correspond to regions where the density drops to zero.

On the other hand, nodal planes arise from the angular part of the wavefunction because they depend on the orientation and shape of the orbital. The angular part describes the angular distribution of the electron density around the nucleus, and the nodal planes correspond to regions where the phase of the wavefunction changes sign.

In summary, radial nodes are related to the distance from the nucleus and arise from the radial part of the wavefunction, while nodal planes are related to the orientation and shape of the orbital and arise from the angular part of the wavefunction. The 2s orbital has one radial node and no nodal planes, while the 2p orbital has no radial nodes and one nodal plane.

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Why are the highest oxidation state of the transition metal stabilised in the oxide and fluoride compond?

Answers

Answer:

Following are the solution to the given question:

Explanation:

Its maximum oxidation zone is exceptionally stable and has the greatest ability to charge density, while fluoride and oxide ions are the largest particles with the largest durability of charge.

Or it might be assumed as oxygen and fluorine are the system particle atoms that have the highest electron number of metals.

Alcohols/Phenols/Thiols
Draw the functional groups that are characteristic of alcohols, phenols, and mercaptans (thiols)
List the name and use of a consumer product which incorporates an alcohol, phenol, or thiol. Describe the role that it plays in the product. Make sure to list all resources used.

Answers

Alcohol is used as an antiseptic, phenol is used as an antimicrobial agent, and thiol used as an conditioning or washing of hair as a shampoo.

One example of a consumer product that incorporates an alcohol is mouthwash. Mouthwash often contains alcohol as a solvent for other ingredients and as an antiseptic to kill bacteria in the mouth. The alcohol also helps to dry the mouth, which can be helpful for people with a dry mouth. In the product, alcohol acts as a solvent for the other ingredients, such as flavorings and antiseptics, and helps to distribute these ingredients evenly throughout the mouth. It also has antiseptic properties, which helps to kill bacteria in the mouth and freshen breath.

Another example of a consumer product that incorporates a phenol is soap. Soap often contains phenols as an antimicrobial agent. Phenols are added to soap to kill bacteria and other microorganisms on the skin, helping to prevent the spread of infections and illnesses.

In soap, phenols play the role of an antimicrobial agent, killing bacteria and other microorganisms on the skin and helping to prevent the spread of infections and illnesses.

A third example of a consumer product that incorporates a thiol is shampoo. Shampoo often contains thiols, such as cysteine, as a conditioning ingredient. Thiols can help to improve the feel of hair and make it easier to manage and style.

In shampoo, thiols play the role of a conditioning ingredient, improving the feel of hair and making it easier to manage and style.

Sources:

Alcohol in Mouthwash

Phenols in Soap

Thiols in Shampoo

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A wave with a smaller wavelength has _______ energy than one with a larger wavelength.

Answers

A wave with a smaller wavelength has more energy than one with a larger wavelength.
Required Answer :-

A wave with a smaller wavelength has UV radiation energy than one with a larger wavelength.

Additional information :-

It is harmful rays as a continuous effect on humans can cause skin and eye disorders. ... A large amount of UV rays comes from the sun is absorbed by the ozone layer in the atmosphere. Some other sources of UV rays are black lights, mercury lamps, and tanning lights.

Uses of UV Rays

The UV light is found in nature from sunlight and the application of sunlight is present in every field. It is present in both commercial and industrial purposes. Generally, it is used in purifying air, water treatment, skin treatment, indoor gardening, things identifying, and more uses by UV lamps.

The UV rays are used in a wide range, ranging from medical therapy to photography.

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how many atoms are there in 6.2 grams of silver​

Answers

100546 billion trillion

For each complex, determine the number of d electrons in the metal ion. [Fe(CN)6]3-, [Fe(CN)6]4-, [Co(NH3)6]2+, [CoF6]3-, [Mn(H2O)6]2+

Answers

d electrons in [Fe(CN)6]3- is 5, d electrons in [Fe(CN)6]4- is 4, d electrons in [Co(NH3)6]2+ is 7, d electrons in [CoF6]3- is 6 and d electrons in [Mn(H2O)6]2+ is 5 etc.

To determine the number of d electrons in the metal ion for each complex, we need to identify the metal and its corresponding oxidation state. The d electrons are located in the d orbitals of the metal.

a) [Fe(CN)6]3-

In this complex, the metal is Fe (iron) and it has a charge of 3-. Iron has an oxidation state of +3 in this complex.

b) [Fe(CN)6]4-

Similar to the previous complex, the metal is Fe and it has a charge of 4-. Iron has an oxidation state of +4 in this complex. Iron in the +4 oxidation state has a d⁴ electronic configuration.

c) [Co(NH3)6]2+

In this complex, the metal is Co (cobalt) and it has a charge of 2+. Cobalt in the +2 oxidation state has a d⁷ electronic configuration.

d) [CoF6]3-

In this complex, the metal is Co and it has a charge of 3-. Cobalt in the +3 oxidation state has a d⁶ electronic configuration.

e) [Mn(H2O)6]2+

In this complex, the metal is Mn (manganese) and it has a charge of 2+. Manganese in the +2 oxidation state has a d⁵ electronic configuration.

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3. A substance which is made up of two are more different
elements chemically combined is known as

A. an atom
B. a substance
C. a compound
D. a molecule

Answers

Answer:

Im pretty sure it c

Explanation:

Answer:
C. A Compound

Neon and argon are both in Group 18 of the periodic table. Which property do they most likely share (
O silver color
O strong odor
O metallic texture
O low or no reactivity

Answers

Explanation:

low or no reactivity ....

Neon and argon are both in Group 18 of the periodic table. The property that they are most likely to share is low or no reactivity. The correct option is d.

What are argon and neon?

A chemical element found in the periodic table is argon. It is the third most common gas in the atmosphere and has an atomic number of 18.

In the periodic table, neon is a chemical element. It is a monatomic, noble gas with the atomic number 10 that is found in the environment.

Although a few liquid molecules do rise to the top, the vast majority stay close to the bottom. Furthermore, the molecules in the gas phase move more swiftly than those in the liquid phase.

Therefore, the correct option is d, low, or no reactivity regarding the mutual property of argon and neon.

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two aqueous solutions of mgso4 and bai2 are mixed. write out what major chemical species will be present in the solution. include physical states of matter.

Answers

two aqueous solutions of mgso4 and bai2 are mixed.double decomposition reactions  will be present in the solution.

MgSO4(aq) + BaI2 (aq) ---------> BaSO4 (s) + MgI2 (aq),When one mole of aqueous magnesium sulphate reacts with one mole of aqueous barium iodide, one mole of solid baryte and one mole of magnesium iodide are formed. This is a reaction with two displacements. After separating all soluble compounds into their ions.Mg2+ (aq) + SO42- (aq) + Ba2+ (aq) +2I- (aq). =BaSO4(s) + Mg2+(aq) + 2I- (aq). Only species involved in the reaction are included in the balanced net ionic equation. It can be found by removing ions from both the reactant and product sides of the ionic equation Ba2+ (aq) + SO4 2- (aq) = BaSO4. When one mole of aqueous magnesium sulphate interacts with one molarity of hydrophilic barium iodide, one mole of solid models are currently and one molarity of magnesium iodide are formed.This is a double decomposition reaction

After separating all stable salts into their ions.

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Please show how you solved :)
What is oxygen solubility at 10m depth below sea level, 25 deg
C, 30 g/L salinity?

Answers

The solubility of oxygen at 10m depth below sea level, 25 degrees Celsius, and 30 g/L salinity is approximately 6.59 mg/L.

To calculate the solubility of oxygen at a specific depth below sea level, temperature, and salinity, we can refer to the oxygen solubility tables. The solubility of oxygen can vary depending on these factors.

1. Begin by identifying the given parameters:
  - Depth: 10m below sea level
  - Temperature: 25 degrees Celsius
  - Salinity: 30 g/L

2. Use the given parameters to locate the corresponding values in the oxygen solubility table.

3. The solubility of oxygen at a depth of 10m below sea level, 25 degrees Celsius, and 30 g/L salinity is typically around 6.59 mg/L.

Therefore, the solubility of oxygen at 10m depth below sea level, 25 degrees Celsius, and 30 g/L salinity is approximately 6.59 mg/L.

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The oxygen solubility at 10m depth below sea level, 25°C, and 30 g/L salinity is approximately 1538 mol/L.

To calculate the oxygen solubility at a specific depth below sea level, temperature, and salinity, we can use the solubility formula.

The solubility of a gas decreases with increasing temperature and salinity, and increases with increasing pressure.

Here's how you can calculate the oxygen solubility at 10m depth below sea level, 25°C, and 30 g/L salinity:

1. Determine the pressure at 10m depth below sea level: -

The pressure at sea level is approximately 1 atmosphere (atm).

The pressure increases by approximately 1 atm for every 10 meters of depth.

Therefore, at 10m depth, the pressure is approximately 2 atm.

2. Convert the temperature to Kelvin: -

To convert from Celsius to Kelvin, add 273 to the temperature.

25°C + 273 = 298 K.

3. Use the solubility formula:

The solubility of oxygen in water can be calculated using Henry's law:

S = k * P * C.

S is the solubility of oxygen in moles per liter (mol/L).

k is the Henry's law constant for oxygen in water at a specific temperature and salinity.  

P is the partial pressure of oxygen in atmospheres (atm).

C is the concentration of oxygen in moles per liter (mol/L).

4. Look up the Henry's law constant for oxygen at 25°C and 30 g/L salinity:

The Henry's law constant for oxygen at 25°C and 30 g/L salinity is approximately 769 L*atm/mol.

5. Calculate the solubility:  

S = (769 L*atm/mol) * (2 atm) * (1 mol/L). - S ≈ 1538 mol/L.

Therefore, the oxygen solubility at 10m depth below sea level, 25°C, and 30 g/L salinity is approximately 1538 mol/L.

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Lipids (also known as fats) have two types of monomers called

Answers

Fats are large molecules made of two types of molecules, glycerol and some type of fatty acid.

In the burning food investigation where you are trying to find out which food contains the most energy - what is the independent variable? *

Answers

Answer:

sorry but i dont know it but you can ask me other things

2. Which of the following statement(s) are true about the atoms of any element?
A. The number of protons in an atom of an element is unique to each element.
B. The number of protons and neutrons in an atom of an element is unique to each eleme
C. A proton is an atom of one element that is identical to a proton in an atom of another
D. The number of protons in an atom of an element is the same for all elements.

Answers

Answer:

Explanation:B..the number of protons and neutrons are unique.

What is 13.48cm+7.6cm rounded to the correct number of significant figures?

Answers

The lowest amount of significant figures has to be what the answer is...

7.6cm is 2 sig figs where 13.48 is 4, so the answer can only really be as precise as the smallest one (7.6)

7.6 + 13.48 = 21.08cm

Put it into 2 sig figs makes it
=21 cm (2s.f) <— don’t forget to write 2 sig figs next to it because otherwise it is a false answer

in an experiment, 4.14 g of phosphorus combined with chlorine to produce 27.8 g of a white solid compound. (a) what is the empirical formula of the compound? (b) assuming that the empirical and molecular formulas of the compound are the same, what is its name?

Answers

PCL₅ is the empirical formula of the compound.

Phosphorous pentachloride is it's if empirical formula and molecular formula are assumed to be the same.

Empirical formula is the lowest relative ratios of atoms that are present in a molecule or compound. It shows the simplest ratio and not the actual number of atoms hence should not be confused with molecular formula.

quantity of phosphorus : 4.14g

quantity of white compound after combining with chlorine : 27.8g

therefore quantity of chlorine = 27.8g - 4.14g => 23.66g

Molecular weight of Phosphorus: 30.97g

Molecular weight of Chlorine: 35.45g

For no. of moles= given weight / molecular weight

Moles of phosphorus= 4.14g / 30.97 => 0.1337 moles

Moles of Chlorine= 23.66g / 35.45 => 0.6674 moles

For empirical formula, we divide with the smaller entity i.e. 0.1337

Phosphorus: 0.1337 / 0.1337 => 1

Chlorine: 0.6647 / 0.1337 => 5

hence the empirical formula is PCL₅

Name of the compound : Phosphorus pentachloride

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How many moles are in 1.50 x 10^23 atoms of F?

(2 decimal places)

Answers

Explanation:

a) 0.4998 mol

b) 0.249 mol

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