Write the chemical equation for the autoionization of water and label the conjugate
acid-base pairs.

Explanation:

Word Equation

Barium Chloride + Sodium Chromate = Sodium Chloride + Barium Chromate

1 mole of aqueous Barium Chloride [BaCl2] reacts with 1 mole of aqueous Sodium Chromate [Na2CrO4] to form 2 moles of aqueous Sodium Chloride [NaCl] and 1 mole of solid Barium Chromate [BaCrO4]

Treatment variable actually produced the differences observed in the dependent variable, then the experiment can be said to be internally valid.

To determine whether research is sound, look at its internal validity. It is correlated with the number of confounding factors your experiment contains. Internal validity is high if confounding factors are kept out of an experiment; it is lower the more confounding there is. Your experiment would have a high level of internal validity in an ideal scenario. You could then be very confident that your experiment's outcomes were driven by just one independent variable.

Correct question:If the researcher can show that the experimental or treatment variable actually produced the differences observed in the dependent variable, then the experiment can be said to be which of the following?

a. internally valid

b. extraneously valid

c. externally valid

d. laboratory valid

e. none of these

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Answer:

0.0964, I worked out the moles of barium hydroxide and divided this by two and then divided that by the volume of nitric acid

Explanation:

Answer:

0.258 mol/dm3

Explanation:

Ba(OH)2 + 2HNO3 ---------> Ba(NO2)2 +2H2O

1 : 2 : 1 : 2

0.00645 : 0.0129 : 0.00645 : 0.0129

Moles of Nitric Acid

Moles=Concentration X Volume(dm3)

0.600 X 0.0215

=0.0129 mol

Concentration= Moles/ Volume(dm3)

0.00645/0.025

= 0.258 mol/dm3

Answer:

0.127M

Explanation:

Molarity of a solution = number of moles (n) ÷ volume (V)

Molar mass of Mg(NO3)2 = 24 + (14 + 16(3)}2

= 24 + {14 + 48}2

= 24 + 124

= 148g/mol

Using the formula, mole = mass/molar mass, to convert mass of Mg(NO3)2 to mole

mole = 14g ÷ 148g/mol

mole = 0.095mol

Volume = 750mL = 750/1000 = 0.75L

Molarity = 0.095mol ÷ 0.75L

Molarity = 0.127M

Answer:

Monosaccharide

Explanation:

Apples contain high levels of fructose, which is a monosaccharide.

Any gross error during measuring can cause the deviation in the correct value of %w/w. This can be occurred from any carelessness or error in calculating or the presence of any impurities.

This category of measuring mistakes includes the most typical error, human error in the measurement. For instance, the person getting the reading from the instrument's meter may interpret 23 as 28. Gross mistakes can be avoided by employing the following two relevant measures:

We can decrease the obvious mistakes by increasing the number of experimenters. If each researcher takes a separate reading at various points, we can minimize the large mistakes by averaging multiple readings.

Presence of any impurities, reading error, weight loss by carelessness etc . can lead to incorrect value of %w/w.

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We can determine the following based on the provided information:

Metal nitrate A is a compound that, when heated, transforms into colourless gas, brown gas B, and a metal oxide with a yellowish brown hue. B. C: Colourless petrol C. B: Brown petrol C. D: Compound D, a yellow precipitate produced by the reaction of potassium iodide with an aqueous solution of compound A.

We may deduce that A is probably lead nitrate (Pb(NO3)2) because lead is frequently used in soldering alloys and the metal contained in A is utilised in an alloy for soldering purposes.

Identifications:

Lead nitrate, or Pb(NO3)2,

N2O: Nitrogen dioxide

B: Carbon (CO)

D: PbI2, or lead iodide.

Thus, this can be concluded regarding the given scenario.

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Your question seems incomplete, the probable complete question is:

A metal nitrate A on heating gives a yellowish brown coloured metal oxide along with brown gas B and a colourless gas C. An aqueous solution of A on reaction with potassium iodide forms a yellow precipitate of compound D. Identify A, B, C and D. Also, identify the types of reactions taking place. Metal present in A is used in an alloy which is used for soldering purposes.

Answer:

A small amount of chemical splashes in Frank's eye. What should happen next? Frank should go to the eyewash station while his lab partner tells the teacher what happened.

Explanation:

Brainlist

The mass (in grams) of sodium carbonate, Na₂CO₃ required to produce 85 grams of barium carbonate, BaCO₃ is 45.7 grams

First, we shall observe the balanced equation to obtain useful information. This is shown below:

Na₂CO₃ + BaSO₄ -> BaCO₃ + Na₂SO₄

From the balanced equation above,

197 g of BaCO₃ were obtained from 106 g of Na₂CO₃

With the above information, we can obtain the mass of sodium carbonate, Na₂CO₃ required to produce 85 grams of barium carbonate, BaCO₃. This is illustrated below:

From the balanced equation above,

197 g of BaCO₃ were obtained from 106 g of Na₂CO₃

Therefore,

85 g of BaCO₃ will be obtain from = (85 × 106) / 197 = 45.7 g of Na₂CO₃

Thus, we can conclude from the above calculation that the mass of sodium carbonate, Na₂CO₃ required is 45.7 grams

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Answer:

\(T_{eq}=28.9\°C\)

Explanation:

Hello!

In this case, since it is observed that hot cadmium is placed in cold water, we can infer that the heat released due to the cooling of cadmium is gained by the water and therefore we can write:

\(Q_{Cd}+Q_{W}=0\)

Thus, we insert mass, specific heat and temperatures to obtain:

\(m_{Cd}C_{Cd}(T_{eq}-T_{Cd})+m_{W}C_{W}(T_{eq}-T_{W})=0\)

In such a way, since the specific heat of cadmium and water are respectively 0.232 and 4.184 J/(g °C), we can solve for the equilibrium temperature (the final one) as shown below:

\(T_{eq}=\frac{m_{Cd}C_{Cd}T_{Cd}+m_{W}C_{W}T_{W}}{m_{Cd}C_{Cd}+m_{W}C_{W}}\)

Now, we plug in to obtain:

\(T_{eq}=\frac{37.60g*0.232\frac{J}{g\°C}*100.00\°C+25.00g*4.184\frac{J}{g\°C}*23.0\°C}{37.60g*0.232\frac{J}{g\°C}+25.00g*4.184\frac{J}{g\°C}}\\\\T_{eq}=28.9\°C\)

NOTE: since the density of water is 1g/cc, we infer that 25.00 cc equals 25.00 g.

Best regards!

Answer:

Los carbohidratos se pueden dividir en tres grupos: monosacáridos, ejemplo, glucosa, fructosa, galactosa; disacáridos, ejemplo, sacarosa (azúcar de mesa), lactosa, maltosa; polisacáridos, ejemplo, almidón, glicógeno (almidón animal), celulosa.

espero que te ayude

Answer:

Explanation:

The exothermic reaction between iron and oxygen that produces rust can generate heat, which can be utilized to create portable hand-warmers. By using a chemical reaction that produces rust, heat can be released, which can then be harnessed and packaged into a small, portable device that can be used to warm hands during cold weather. This is a common application of the exothermic reaction between iron and oxygen, and can be found in many commercially available hand-warmers.

The other options listed in the question are not relevant to the exothermic reaction between iron and oxygen that produces rust. Creating rusty fenders for a car is not a desirable outcome, as it would result in unsightly and potentially damaging rust on the car's exterior. Creating cooling headbands is not related to the exothermic reaction between iron and oxygen that produces rust. Creating non-rusting machines is also not related to this reaction, as the reaction specifically produces rust as a byproduct.

3a) To calculate the mole fraction of B (Xb) in the vapor, we use the formula:

Xb = (PB / Ptotal)

where PB is the vapor pressure of B, and Ptotal is the total vapor pressure of the mixture.

First, we need to find the total vapor pressure of the mixture:

Ptotal = PA + PB

PA is not given, but we can calculate it using the fact that the mixture is 58% A and 42% B:

Xa = 0.58

Xb = 0.42

Xa + Xb = 1 (since they are the only two components)

PA = (Ptotal - PB) * Xa / Xb

Substituting the given values:

PB = 759 torr

Xb = 0.42

Ptotal = PA + PB = (810 - 759*0.58/0.42) + 759 = 862.71 torr

Now we can calculate Xb:

Xb = PB / Ptotal = 759 / 862.71 = 0.8797 or 0.88 (rounded to 2 decimal places)

b) To solve this problem, we need to use Raoult's Law, which states that the partial pressure of a component in the vapor phase is equal to the vapor pressure of the pure component multiplied by its mole fraction in the liquid phase:

Pb = Xb * PB°

We know that the mole fraction of B (Xs) in the vapor is 0.62, so the mole fraction of A (Xa) must be:

Xa = 1 - Xb = 1 - 0.62 = 0.38

The sum of the partial pressures of A and B is 780 torr, so we can write:

PA + Pb = 780

Substituting Pb from the Raoult's Law equation:

PA + Xb * PB° = 780

We also know that the vapor pressure of pure B (PB°) is 727 torr, so we can solve for Xb:

Xb = (780 - PA) / PB°

We still need to find PA. To do this, we use the fact that the total vapor pressure of the mixture is the sum of the partial pressures of A and B:

Ptotal = PA + Pb = PA + Xb * PB°

Substituting the given values:

Xb = 0.62

PB° = 727 torr

Ptotal = 780 torr

Solving for PA:

PA = Ptotal - Xb * PB° = 780 - 0.62 * 727 = 326.26 torr

Now we can calculate Xb:

Xb = (780 - PA) / PB° = (780 - 326.26) / 727 = 0.637 or 0.64 (rounded to 2 decimal places)

The vapor becomes richer in the component with the lower boiling point after each condensation-vaporization cycle in a fractional distillation. This is because the vapor that is condensed has a higher concentration of the lower boiling point component than the original mixture, and the vapor that is vaporized from the condensed liquid has an even higher concentration of the lower boiling point component.

The adiabatic process in fractional distillation refers to the fact that the process is carried out without the exchange of heat with the surroundings. This is important because the boiling point of a liquid depends on its pressure and temperature, and any heat added or removed from the system can affect the temperature and pressure, and thus the boiling points, of the components

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Answer:

C₁₃H₁₈O₂

Explanation:

Empirical formula is the simplest ratio in moles of the elements presents in the compound. Assuming a basis of 100g, we need to convert the mass of each element to moles and, find the ratio of each of these:

Moles C:

75.69g * (1mol / 12.01g) = 6.3 moles of C

Moles H:

8.80g * (1mol / 1.01g) = 8.7 moles of H

Moles O:

15.51g * (1mol / 16g) = 0.97 moles of O

The ratio dividing in the moles of O -Because is the element with the lower amount of moles-:

C = 6.3mol / 0.97mol = 6.5

H = 8.7mol / 0.97mol = 9

O = 0.97mol / 0.97mol = 1

As the ratio must be in whole-numbers, multiplying in 2:

C = 13;

H = 18

O = 2

And empirical formula is:

Answer: C₁₃H₁₈O₂

Question: Ibuprofen, an aspirin substitute, has the mass percent composition: C 75.69%;

H 8.80%; O 15.51%. Calculate the empirical formula of ibuprofen.

Answer:

I believe it is a positive quantity such as water has 4.14 j/oC it is always positive it is the energy needed to raise the temperature by 1 degree celsius

Explanation:

we would need 2625.13 grams (or 2.62513 kilograms) of NaCl.

To calculate the mass of NaCl required to produce a 26.4 mol/L solution with a 1.7 L volume, we need to use the formula that relates the mass of solute, moles of solute, and molarity:Molarity (M) = moles of solute / liters of solution Rearranging this formula, we get:moles of solute = Molarity (M) x liters of solutionWe can use this formula to find the moles of NaCl needed:moles of NaCl = 26.4 mol/L x 1.7 L = 44.88 molNow, we can use the molar mass of NaCl to convert from moles to grams. The molar mass of NaCl is 58.44 g/mol:mass of NaCl = moles of NaCl x molar mass of NaClmass of NaCl = 44.88 mol x 58.44 g/mol = 2625.13 gTo produce a 26.4 mol/L solution with a 1.7 L volume.

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Answer:

The number of these organisms in the soil would decrease.

Explanation:

Answer:

Metamorphic rocks are the rocks that arise from the conversion of existing rock types in a process called metamorphism, means changing of forms. Metamorphic rocks are formed from the other rocks that are changing because of heat or pressure applied. One of this example is the Earth movements that causing rocks to deeply bury or squeezed which will make the rocks heated and put under great pressure. They are not melting but the minerals they are containing are changed chemically that will form metamorphic rocks. Sometimes other rocks are formed when the others are close to some molten magma and getting heated.

If im wrong correct me

Answer:

That is the Atomic mass

Explanation:

The element symbol is S, Element name is sulfur, and

Atomic number is 16

Answer:

Atoms of the same element can have different numbers of neutrons.

Explanation:

This statement is true because atoms of the same element have the same number of protons, which determines the element's atomic number. However, they can have different numbers of neutrons, which gives rise to different isotopes of that element. These isotopes have the same number of protons, but different numbers of neutrons, leading to different atomic weights. So, while the number of protons is fixed for a particular element, the number of neutrons can vary.

Cuso4 + NaoH -》cu(oH)2 +Na2So4

Cuso4 + 2NaoH -》cu(oH)2 +Na2So4

Explanation:

this is balanced equation

The identity of a cation solution that produces a mix of red and yellow colors in a flame test, but appears red when viewed through a cobalt filter, can be attributed to the presence of the strontium (Sr) cation.

During a flame test, different metal cations emit characteristic colors due to the excitation of electrons and their subsequent emission of light. Strontium, in particular, is known to produce a vibrant red color in flame tests.

The presence of both red and yellow colors indicates the possibility of multiple metal cations in the solution. While the specific metal responsible for the yellow color is uncertain, it could potentially be sodium or another metal that emits a yellow flame.

When the flame is viewed through a cobalt filter, which absorbs yellow wavelengths of light, the yellow color is filtered out, resulting in only the red color being observed. Since strontium is known for its distinctive red flame color and its emission is not affected by the cobalt filter, it is likely the metal cation responsible for the observed red color. Therefore, based on these characteristics, the identity of the cation solution is most likely strontium (Sr).

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Answer:

Still 30°−60°−90°

Explanation:

Angles do not change if rotated.

Angles do not change they can only rotate in a circular motion if the angles in a 30°−60°−90° triangle after it is rotated clockwise at 45°.

The angles are the distance between two lines that are attached at one point and they can vary in shapes like triangle and square or circle and rectangle.

The square has the handle of equality for all the sides rectangle has two opposite side angles equal and the circle It has only one angle triangle consisting of 3 angles which are fixed and cannot be changed.

Therefore, if the angles in a 30°−60°−90° triangle after it is rotated clockwise at 45°Angles do not change they can only rotate in a circular motion.

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The atomic mass of sulfur trioxide (SO3) is 82 amu.

Sulfur trioxide (SO3) has one sulfur atom and three oxygen atoms.

The atomic mass of sulfur can be calculated by subtracting the total mass of the oxygen atoms in sulfuric acid (3 x 16 amu) from the mass of sulfuric acid (98 amu) and then subtracting the mass of the remaining oxygen atom:

The atomic mass of sulfur is 34 amu.

To find the atomic mass of sulfur trioxide, we add the atomic masses of one sulfur atom and three oxygen atoms:

Therefore, the atomic mass of sulfur trioxide (SO3) is 82 amu.

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Answer:

C. They are used in skin thermography to detect blockage of veins.

Explanation:

Liquid crystals are not typically used in skin thermography to detect blockage of veins. Skin thermography usually relies on infrared imaging to detect and analyze variations in skin temperature, which can indicate potential health issues. Liquid crystals are commonly used in temperature sensors, display technologies (such as in the dial of analog watches), and can be employed in electrical circuits to find potential failure points.

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Answer:

C. \(Ca_3(PO_4)_2\)  will precipitate out first

the percentage of \(Ca^{2+}\)remaining =  12.86%

Explanation:

Given that:

A solution contains:

\([Ca^{2+}] = 0.0440 \ M\)

\([Ag^+] = 0.0940 \ M\)

From the list of options , Let find the dissociation of \(Ag_3PO_4\)

\(Ag_3PO_4 \to Ag^{3+} + PO_4^{3-}\)

where;

Solubility product constant Ksp of \(Ag_3PO_4\) is \(8.89 \times 10^{-17}\)

Thus;

\(Ksp = [Ag^+]^3[PO_4^{3-}]\)

replacing the known values in order to determine the unknown ; we have :

\(8.89 \times 10 ^{-17} = (0.0940)^3[PO_4^{3-}]\)

\(\dfrac{8.89 \times 10 ^{-17}}{(0.0940)^3} = [PO_4^{3-}]\)

\([PO_4^{3-}] =\dfrac{8.89 \times 10 ^{-17}}{(0.0940)^3}\)

\([PO_4^{3-}] =1.07 \times 10^{-13}\)

The dissociation  of \(Ca_3(PO_4)_2\)

The solubility product constant of \(Ca_3(PO_4)_2\)  is \(2.07 \times 10^{-32}\)

The dissociation of \(Ca_3(PO_4)_2\)   is :

\(Ca_3(PO_4)_2 \to 3Ca^{2+} + 2 PO_{4}^{3-}\)

Thus;

\(Ksp = [Ca^{2+}]^3 [PO_4^{3-}]^2\)

\(2.07 \times 10^{-33} = (0.0440)^3 [PO_4^{3-}]^2\)

\(\dfrac{2.07 \times 10^{-33} }{(0.0440)^3}= [PO_4^{3-}]^2\)

\([PO_4^{3-}]^2 = \dfrac{2.07 \times 10^{-33} }{(0.0440)^3}\)

\([PO_4^{3-}]^2 = 2.43 \times 10^{-29}\)

\([PO_4^{3-}] = \sqrt{2.43 \times 10^{-29}\)

\([PO_4^{3-}] =4.93 \times 10^{-15}\)

Thus; the phosphate anion needed for precipitation is smaller i.e \(4.93 \times 10^{-15}\) in \(Ca_3(PO_4)_2\) than  in  \(Ag_3PO_4\)  \(1.07 \times 10^{-13}\)

Therefore:

\(Ca_3(PO_4)_2\)  will precipitate out first

To determine the concentration of \([Ca^+]\) when  the second cation starts to precipitate ; we have :

\(Ksp = [Ca^{2+}]^3 [PO_4^{3-}]^2\)

\(2.07 \times 10^{-33} = [Ca^{2+}]^3 (1.07 \times 10^{-13})^2\)

\([Ca^{2+}]^3 = \dfrac{2.07 \times 10^{-33} }{(1.07 \times 10^{-13})^2}\)

\([Ca^{2+}]^3 =1.808 \times 10^{-7}\)

\([Ca^{2+}] =\sqrt[3]{1.808 \times 10^{-7}}\)

\([Ca^{2+}] =0.00566\)

This implies that when the second  cation starts to precipitate ; the  concentration of \([Ca^{2+}]\) in the solution is  0.00566

Therefore;

the percentage of \(Ca^{2+}\)  remaining = concentration remaining/initial concentration × 100%

the percentage of \(Ca^{2+}\) remaining = 0.00566/0.0440  × 100%

the percentage of \(Ca^{2+}\) remaining = 0.1286 × 100%

the percentage of \(Ca^{2+}\)remaining =  12.86%

Answer:

23.4 milliliters

Explanation:

Note 1: This answer assumes that the volume of CuNO3 is negligible
Note 2: CuNO3 can't be produced in any meaningful quantities and can't be obtained by the average chemist, maybe you meant Cu(NO3)2 instead?

From the definition of molarity, molarity = moles / volume
the number of moles is the number of grams divided by the molar mass, or
2.47 divided by 125.55 which is 0.01967

The M and moles is known so volume can be found.

0.82 = 0.01967 / volume
0.82 * volume = 0.01967
volume = 0.01967 / 0.82 = 0.023988 liters = 23.4 milliliters

The lattice energy of MX is 459.2 kJ/mol.

The lattice energy (ΔH° lattice) of an ionic compound is the energy released when one mole of the solid is formed from its constituent gaseous ions under standard conditions. The lattice energy is calculated using the Born-Haber cycle, which involves several steps including atomization, ionization, dissociation, and sublimation energies.

The lattice energy is related to the Coulombic attraction between the oppositely charged ions in the solid. To calculate the lattice energy for MX, we can use the following equation:

ΔH° lattice = ΔH° sub + ΔH° ion + ΔH° diss + ΔH° formation

where ΔH° sub is the sublimation energy of M(s), ΔH° ion is the first ionization energy of M(g), ΔH° diss is the dissociation energy of X2(g), and ΔH° formation is the enthalpy of formation of MX(s).

Using the given data, we can calculate each of these values and substitute them into the equation to obtain the lattice energy. The final answer should be in units of kJ/mol.

ΔH° sub (M) = 107.3 kJ/mol

ΔH° ion (M) = 577.5 kJ/mol

ΔH° diss (X2) = 242 kJ/mol

ΔH° formation (MX) = -467.6 kJ/mol

ΔH° lattice = 107.3 + 577.5 + 242 + (-467.6) = 459.2 kJ/mol

As a result, MX has a lattice energy of 459.2 kJ/mol.

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