Which refers to the continuous release of nuclear energy caused when one fission reaction triggers more nuclear reactions?
-fusion reaction
-trigger effect
-energy effect
-chain reaction

The missing species of the nuclear reaction obtained is ³⁰₁₅P

The missing species of the equation can be obtain as follow:

Now, we can obtain the value of x, y and Z as follow:

²⁷₁₃Al + ⁴₂He -> ʸₓZ + ¹₀n

For x

13 + 2 = x + 0

15 = x

x = 15

For y

27 + 4 = y + 1

31 = y + 1

Collect like terms

y = 31 - 1

y = 30

For Z

ʸₓZ => ³⁰₁₅Z

From the period table, the element with atomic number of 15 is phosphorus, P. Thus, we have

ʸₓZ => ³⁰₁₅Z => ³⁰₁₅P

Therefore, we can write the complete equation as:

²⁷₁₃Al + ⁴₂He -> ³⁰₁₅P + ¹₀n

Thus, the missing species is ³⁰₁₅P

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Answer:

afgiknvdeyiknvxwtuinvdruincdyukn

Answer:

Large; small.

Explanation:

A telescope can be defined as an optical instrument or device which comprises of a curved mirror and lenses used for viewing distant objects i.e objects that are very far away such as stars and other planetary bodies. The first telescope was invented by Sir Isaac Newton.

To have the highest magnification in a telescope, the focal length of the objective lens should be large and the focal length of the eyepiece lens should be small.

This ultimately implies that, the eyepiece lens has a small focal length while the objective lens has a large focal length.

The time will be the same for both horizontal and vertical component. The initial speed is 10.7 m/s

Speed is a distance travel per time taken. It is a scalar quantity and it is measured in m/s

Given that a person standing at the edge of a seaside cliff kicks a rock horizontally of the cliff from a height of 52 m and it lands a distance of 35 m from the base of the cliff.

The rock will move vertically downward with initial velocity = 0. The time taken will be constant. That is, same horizontally.

Let us first calculate the time by using the formula

h = ut + 1/2gt²

Where

Substitute all the necessary parameters into the formula

52 = 0 + 1/2 × 9.8 × t²

52 = 4.9t²

t² = 52/4.9

t² = 10.6

t = √10.6

t = 3.26 s

The speed at which the rock was initially kicked can be found by

R = Ut

35 = U × 3.26

U = 35/3.26

U = 10.7 m/s

Therefore, rock was initially kicked at a speed of 10.7 m/s

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(1) The acceleration of the car is determined as 17.42 m/s².

(2) The acceleration of the crate is determined as 8.89 m/s².

The acceleration of the car is calculated from the net force acting on the car.

∑F = ma

F - Ff = ma

F - μW = ma

where;

m = W/g

m = (9320)/(9.8)

m = 951.02 kg

2(9320) - 0.222(9320) = 951.02a

16,570.96 = 951.02a

a = 17.42 m/s²

F - μW = ma

F - μmg = ma

302 - 0.75(18.6 x 9.8) = 18.6a

165.29 = 18.6a

a = 8.89 m/s²

Thus, the acceleration of the car is determined as 17.42 m/s².

The acceleration of the crate is determined as 8.89 m/s².

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it is not advisable to use small values of i in performing an experiment of refraction light using triangular prism because it is likely that the refracted ray will not be accurately measured at all.

The term refraction has to do with the bending of light at the interface between two media. We now that this refraction takes place in a glass block, a triangular prism or a lens. It also takes place in nature in the sense of having a mirage.

Now, it is not advisable to use small values of i in performing an experiment of refraction light using triangular prism. This is because, if a small value is used for the incident ray i, it is likely that the refracted ray will not be accurately measured at all.

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Explanation:

The gravitational force between two objects when they are placed at some distance is given by :

\(F=G\dfrac{m_1m_2}{d^2}\)

Where

G is universal gravitational constant

m₁ and m₂ are masses

d is the distance between masses

The gravitational force is directly proportional to the product of masses and inversely to the square of the distance between them. It would mean that if the mass of the objects increases, the force will increase while if the distance is increased, the force between objects will decrease.

Answer:

2.18 miles per hour

Explanation:

Given:

A hiker walks 7.7 miles to the east in 3.6 hours.

A hiker walks 2.1 miles to the west in 2.4 hours

To find: magnitude of average velocity during the trip

Solution:

Total distance = 7.7 + 2.1 = 9.8 miles

Total Time = 2.1 + 2.4 = 4.5 hours

Average velocity = Total distance ÷ Total Time =\(\frac{9.8}{4.5}=2.18\) miles per hour

Answer:  C. the motion of a spacecraft under gravitational influence.

Explanation:

A is Metallurgy, B is Biology, C is astro-physics, I am not sure what D is, but it's   safe to say it's not physics, E, micro-biology, and the study of radiation. C is the only one involving physics.

Answer:

c

Explanation:

Answer:

b

Explanation:

Answer:

Two small objects with masses m and M are originally a distance r apart and the gravitational force on each has a magnitude F. The second object had

Answer:

To find the net charge on the sphere using electric flux, we can use the formula:  

Φ = Q/ε0

Where Φ is the electric flux, Q is the charge, and ε0 is the permittivity of free space.  

Given that the electric field 20 cm from the center of the sphere is N/C and points radially inwards, we can use the formula for electric field due to a charged sphere to find the charge on the sphere:

E = kQ/r^2  

Where E is the electric field, k is Coulomb's constant, Q is the charge, and r is the distance from the center of the sphere.  

Substituting the given values, we get:  

20 = (1/4πε0)(Q)/(0.2)^2  

Solving for Q, we get:  

Q = (20)(0.2)^2(4πε0)  

Q = 0.64πε0 C  

Now, substituting this value of Q in the formula for electric flux, we get:  Φ = Q/ε0 = (0.64πε0)/(ε0) = 0.64π C  

Therefore, the net charge on the sphere is 0.64π C.

Answer:

Maximum height, h = 3062.5m

Total time of flight, T = 49.49secs or 50secs approx.

Range, R = 12250m

Explanation:

Given data:

U = 350m/s

Angle = 45°

Assume g = 10m/s

At the greatest height, v = 0

Therefore,

V^2 = U^2 sin^2 × angle - 2×g×h

Substituting values:

0^2 = 350^2 sin^2 (45) - 2 × 10 × h

Let h = maximum height reached

Rearranging gives:

350^2 sin^2(45) = 2 x 10 x h

h = 350^2 sin^2(45)/2×10

h = 122500 x 0.5/20

h = 61250/20

h = 3062.5m

2)Total time of flight, T

T = 2U sin(angle)/g

= 2x350 sin(45)/10

= 494.9747/10

= 49.49secs or 50sec approx.

3) Range of projectile, R

R = U^2 sin2(angle)

= 350^2 sin2 (45)

= 122500 x 1/10

= 12250m

Answer:

there usually in lower parts so they don't fall

Explanation:

Explanation:

(a) The graph of Force vs. Stretch for the given spring can be represented by a straight line passing through the origin with a slope equal to the spring constant. The equation of the line is:

Force = Spring constant × Stretch

F = kx

where k = 200 N/m and x is the stretch of the spring in meters. The graph is shown below:

Force vs. Stretch graph for a spring with k = 200 N/m

(b) When a mass of 0.8 kg hangs from the spring, it experiences a force due to gravity equal to:

F = m × g = 0.8 kg × 10 m/s² = 8 N

Since the spring is in equilibrium, the force exerted by the spring must be equal and opposite to the force due to gravity. Therefore, the stretch of the spring is given by:

F = kx

x = F/k = 8 N / 200 N/m = 0.04 m

The point corresponding to this stretch is marked on the graph as shown below:

Force vs. Stretch graph with a point for a hanging mass of 0.8 kg

(c) The potential energy stored in the spring when it is stretched from zero to 0.06 meters can be calculated using the formula:

U = (1/2) k x²

U = (1/2) × 200 N/m × (0.06 m)² = 0.36 J

(d) The work done to stretch the spring from 0.1 meters to 0.16 meters can be calculated by finding the area under the Force vs. Stretch graph between these two stretches. This represents the change in potential energy of the spring due to the stretching. The work done is given by:

W = ΔU = U₂ - U₁

where U₁ and U₂ are the potential energies of the spring at stretches of 0.1 m and 0.16 m, respectively.

Using the formula for potential energy, we have:

U₁ = (1/2) k x₁² = (1/2) × 200 N/m × (0.1 m)² = 1 J

U₂ = (1/2) k x₂² = (1/2) × 200 N/m × (0.16 m)² = 2.56 J

Therefore, the work done is:

W = ΔU = U₂ - U₁ = 2.56 J - 1 J = 1.56 J

The area under the graph representing this work is shown below:

Force vs. Stretch graph with shaded area representing work done

Answer:

4000 Nm^-2

Explanation:

Dude that "zam" drove me away, anyway:

Given:

Force on the large piston (F1) = 4000 N

Cross-sectional area of the large piston (A1) = 1 m²

Cross-sectional area of the small piston (A2) = zam (let's assume zam represents the area in square meters)

According to Pascal's law, the pressure exerted on the large piston (P1) is equal to the pressure exerted on the small piston (P2):

P1 = P2

Pressure is defined as force divided by area:

P1 = F1 / A1

P2 = F2 / A2

Since P1 = P2, we can equate the two expressions:

F1 / A1 = F2 / A2

Rearranging the equation to solve for F2, the force on the small piston:

F2 = (F1 / A1) * A2

Substituting the given values:

F2 = (4000 N / 1 m²) * zam

Now, to calculate the pressure exerted on the small piston (P2), we can divide the force by the area:

P2 = F2 / A2

Substituting the values we obtained:

P2 = [(4000 N / 1 m²) * zam] / zam

The area "zam" cancels out in the equation, leaving us with:

P2 = 4000 N/m²

Therefore, the pressure exerted on the small piston is 4000 N/m².

To determine the effort required on the small piston, we need to know the area of the small piston. Once we have that information, we can substitute it into the equation for F2 to calculate the effort required

Answer:

19

Explanation:

I legit did this and it took 19.

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Answer:

Explanation:

4 is right

Explanation: Magma is molten rock found below the earth's surface. ... On the other hand, if the rocks are under greater pressure, they will require higher temperatures to melt. Melting of rocks typically occurs in the lower lithosphere or upper asthenosphere. The earth gets hot pretty quickly as you dig down from the earth's surface.

In a DC generator, the generated electromotive force (emf) is directly proportional to the rotational speed of the generator's armature and the strength of the magnetic field within the generator.

This relationship is described by the equation for the generated emf in a DC generator:

Emf = Φ * N * A * Z / 60

Where:

Emf is the generated electromotive force (in volts),

Φ is the magnetic flux density (in Weber/meter^2\(meter^2\) or Tesla),

N is the number of turns in the armature winding,

A is the effective area of the armature coil (in square meters),

Z is the total number of armature conductors, and

60 is a constant representing the conversion from seconds to minutes.

From this equation, we can see that the generated emf is directly proportional to the magnetic flux density (Φ) and the product of the number of turns (N), effective area (A), and the total number of armature conductors (Z). This means that increasing any of these factors will result in a higher generated emf.

The magnetic flux density (Φ) can be increased by using stronger permanent magnets or increasing the strength of the field windings in the generator.

The number of turns (N) and the effective area (A) are design parameters and can be optimized for a specific generator. Increasing the number of turns or the effective area will result in a higher generated emf.

Similarly, the total number of armature conductors (Z) can be increased to enhance the generated emf.

By controlling and optimizing these factors, the generated emf in a DC generator can be increased, resulting in higher electrical output. However, it is important to note that there are practical limits to these factors based on the design and construction of the generator.

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Answer:

10m above initial height

Explanation:

let acceleration due to gravity = 9.8 m/s/s

v final = v initial - time • gravity

0 = 14m/s - t • 9.8m/s/s

t = 1.43 seconds to reach max height

distance = 1/2 • acceleration • time^2

distance = 1/2 • 9.8 • 1.43^2

distance = 10 meters above initial height

Answer:

During heat flow, much of the energy is dissipated and cannot be used for useful work.

Explanation:

Which of the following statements is true?

During heat flow, much of the energy is lost.

During heat flow, energy is converted to matter.

During heat flow, much of the energy is dissipated and cannot be used for useful work.

As a result, a homogeneous rigid disc rotating about a fixed centre O is defined as ap = 33i - 12k m/s².

At time t, where,  are constants, a rigid body spins about a fixed axis with variable angular velocity equal to (t). Its final rotational angle before stopping is. Not to worry!

We must apply the following formula to determine ap:

ap = app + aO + × rOP × (× × rOP + × vOP)

First, we need to find app:

app = aQ + × rPQ + × × rPQ × (× × rPQ + × vPQ)

where aQ is the acceleration of point Q, rPQ is the vector from P to Q, and vPQ is the velocity of Q relative to P.

Using the given values, we get:

aQ = -a2 = 3k

rPQ = [12, -3]

vPQ = vQ - vP = [-33 + 36, 0 + 12] = [-3, 12]

× × rPQ = 0

× vPQ = [0, 0, 12]

× × rPQ × × vPQ = [0, 0, 0]

× × rPQ × (× × rPQ + × vPQ) = [0, 0, 0]

Therefore, app = aQ + × rPQ = [36, -9]

Next, we need to find aO:

aO = × × rOP = [0, 0, -12]

Finally, we can calculate ap:

ap = app + aO + × rOP × (× × rOP + × vOP)

= [36, -9, 0] + [0, 0, -12] + [-3, 9, 0]

= [33, 0, -12]

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Answer:

the acceleration of the girl is 8 m/s² in opposite direction.

Explanation:

Given;

mass of the girl, m₁ = 30kg

mass of the boy, m₂ = 40 kg

acceleration of the boy, a₂ = 6 m/s²

let acceleration of the girl = a₁

Apply Newton's third law of motion;

the force exerted by the girl is equal  in magnitude  to the force exerted by the boy but in opposite direction.

F₁ = -F₂

m₁a₁ = -m₂a₂

30a₁ = -(40 x 6)

30a₁ = -240

a₁ = -240 / 30

a₁ = -8 m/s² (the negative sign shows that the acceleration is in opposite direction)

Thus, the acceleration of the girl is 8 m/s² in opposite direction.

The two phase changes that occurred in making the skillet are solid to liquid and liquid to solid.

Phase refers to a homogeneous form of a substance that is physically distinctive.

Two phase changes occurred in making the skillet as follows;

1) When the mixture of cast iron and steel metal was placed in the furnace at 1500°C, a phase change from solid to liquid occurs as molten cast ion is formed.

2) The second phase change occurs when the molten cast iron dries up in the mold. This is a change from liquid to solid phase.

Hence, the two phase changes that occurred in making the skillet are solid to liquid and liquid to solid.

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Answer:

(a) The angular frequency ($\omega$) of a spring/mass system with a force constant ($k$) and a mass ($m$) can be found using the formula:

\omega = \sqrt{\frac{k}{m}}

Plugging in the values given, we get:

\omega = \sqrt{\frac{90 N/m}{8.15 kg}} \approx 3.18 \text{ rad/s}

Therefore, the angular frequency of the spring/mass system is approximately 3.18 rad/s.

(b) The period ($T$) of a spring/mass system can be found using the formula:

T = \frac{2\pi}{\omega}

Plugging in the value of $\omega$ we found in part (a), we get:

T = \frac{2\pi}{3.18\text{ rad/s}} \approx 1.98 \text{ s}

Therefore, the period of the spring/mass system is approximately 1.98 s.

The distance of the focal point from the center of the lens is -16.4 cm.

Using the thin lens equation to relate the object distance, image distance, and focal length:

1/f = 1/q - 1/p

where f is the focal length, q is the image distance, and p is the object distance.

Since the image is real and inverted, q is negative:

1/f = -1/q - 1/p

Given that the image is 0.89 times the size of the object, which means that the height of the image is 0.89 times the height of the object:

h'/h = -q/p

Substituting -q = 38.5 cm and h'/h = 0.89:

0.89 = 38.5 cm/p - q/p = 38.5 cm/p + 1/q

Solving for p in terms of q:

0.89q = 38.5 cm p + q

0.89q = (38.5 cm + 1)q

0.89 = 39.5 cm/q

q = 44.38 cm

Now, solving for f:

1/f = -1/q - 1/p

1/f = -1/44.38 cm - 1/p

1/f = (-1 - p)/44.38 cm

f = 44.38 cm/(-1 - p)

Acknowledging the lens equation that:

1/f = 1/p + 1/q

1/f = 1/p - 1/44.38 cm

1/p = 1/f + 1/44.38 cm

p = 44.38 cm/(1/f + 1/44.38 cm)

Substituting this expression for p into the earlier expression for f:

f = 44.38 cm/(-1 - 44.38 cm/(1/f + 1/44.38 cm))

Simplifying and evaluating:

f ≈ -16.4 cm

Therefore, the distance of the focal point from the center of the lens is approximately 16.4 cm.

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We can conclude that greater the force, greater will be the distance travelled by it.

The distance travelled in kinematics is the total path length traced out by the body throughout its motion.

Given is to compare the distance traveled by the toy car when pushed by the weakest force and when pushed by the strongest force​.

Assume the mass of the toy car be {m} kg. Now, we know that -

F = ma

a = F/m

For the weakest force, we can write that the weakest force is very very less than the strongest force. We can write -

F{weak} <<< F{strong}

a \(\alpha\) F

Greater the force, greater is the acceleration and vice - versa.

We know -

a = d²x/dt²

So, greater the force, greater will be the distance travelled by it.

Therefore, we can conclude that greater the force, greater will be the distance travelled by it.

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Doppler radars work by using radio waves that bounce off objects and thus the object can be tracked.

Doppler radars work by emitting a beam of energy from an antenna known as radio waves. The energy they release when they collide with airborne objects scatters in all directions, with some of it returning directly to the radar.

The quantity of energy returned to the radar increases with object size. We can now perceive raindrops in the atmosphere because of this.

The amount of time it takes for the energy beam to be delivered and returned to the radar also gives us the object's distance.

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