Which choice has the least thermal energy?
A swimming pool full of cool water
b all the water in Earth's oceans
C cup of hot cocoa
d bathtub full of warm water

Answer:

a. 1.642 Ns/m b. 0.0294 N c. 5 × 10⁵ ms

Explanation:

a. Presuming the resistive force R = −bv, what is the value of b (N s/m)?

Using the equation of motion on the object,

W + R = ma where W = weight of the mass = mg where m =mass of marble = 3.00 g = 0.003 kg and g = acceleration due to gravity = 9.8 m/s² , R = resistive force = -bv where v = velocity and a = acceleration of marble.

So,

mg - bv = ma

At terminal speed, a = 0,

So, mg - bvt =m(0)

mg - bvt = 0

mg = bvt

b = mg/vt since terminal speed vt = 1.79 cm/s = 0.0179 m/s

So, b = 0.003 kg × 9.8 m/s²/0.0179 m/s

b = 0.0294 kgm/s² ÷ 0.0179 m/s

b = 1.642 Ns/m

b. What is the strength of the resistive force (N) when the marble reaches terminal speed?

Since the resistive force R = -bv, at terminal speed, vt

R = -bvt

R = -1.642 Ns/m × 0.0179 m/s

R = -0.0294 N

So, its strength is 0.0294 N

(c) How long in milliseconds does it take for it to reach a speed of 0.600vt?

Using mg - bv = ma where a = dv/dt,

mg - bv = mdv/dt

g - bv/m = dv/dt

separating the variables, we have

dv/(g - bv/m) = dt

Integrating, we have

∫dv/(g - bv/m) = ∫dt

(-b/m)/(-b/m) × ∫dv/ (g - bv/m) = ∫dt

1/(-b/m) ∫(-b/m)dv/(g - bv/m) = ∫dt

1/(-b/m) ㏑(g - bv/m) = t + C

㏑(g - bv/m) = -m/bt - mC/b

㏑(g - bv/m) = -m/bt + C'  (C' = -mC/b)

taking antilogarithm of both sides, we have

g - bv/m = exp(-m/bt + C')

g - bv/m = exp(-m/bt)expC'

g - bv/m = Aexp(-m/bt) (A = expC')

bv/m = g - Aexp(-m/bt)

v = mg/b - (Am/b)exp(-m/bt)

when t = 0, v = 0 (since the marble starts from rest)

0 = mg/b - (Am/b)exp(-m/b(0))

0 = mg/b - (Am/b)exp(0))

-mgb = -Am/b

A = g

v = mg/b - (mg/b)exp(-m/bt)

when v = 0.600vt = 0.600 × 0.0179 m/s = 0.01074 m/s

mg/b = 0.003 kg × 9.8 m/s²/1.642 Ns/m = 0.0179 m/s and m/b = 0.003 kg/1.642 Ns/m = 0.00183/s

So,v = mg/b - (mg/b)exp(-m/bt)

0.01074 m/s = 0.0179 m/s - (0.0179 m/s)exp[(-0.00183/s)t]

0.01074 m/s - 0.0179 m/s = - (0.0179 m/s)exp[(-0.00183/s)t]

-0.00716 m/s = - (0.0179 m/s)exp[(-0.00183/s)t]

exp[(-0.00183/s)t] = -0.00716 m/s/-0.0179 m/s

exp[(-0.00183/s)t] = 0.4

taking natural logarithm of both sides, we have

(-0.00183/s)t = ㏑(0.4)

(-0.00183/s)t = -0.9163

t = -0.9163/-0.00183

t = 500 s

t = 500 × 1000 ms

t = 5 × 100000

t = 5 × 10⁵ ms

The Sketch  of the figure will bear the parameters of the charge that lies   at (4,0,0)

Generally, the equation for is  mathematically given as

1)

Since both of the other points, "q1"<"q2," are on the x-axis, the third one must also be on the x-axis, and it must be close to the charge of lesser magnitude. off q1 by x cm

Now, forces on q3 due to q1

\(\vec{F}_{1}=\frac{k q_{1} q_{3}}{x^{2}} \hat{x}\)

Force on q3 due to q2

\(\vec{F}_{2}=\frac{k q_{2} q_{3}}{(6+x)^{2}}(-\hat{x})\)

\(\quad \vec{F}_{1}+\vec{G}_{2}=0$\)

\(&\frac{k q_{1} q_{3}}{x^{2}}-\frac{k q_{2} q_{3}}{(x+6)^{2}}=0 \\&\frac{2}{x^{2}}=\frac{8}{(x+6)^{2}} \Rightarrow \frac{x+6}{x}=\sqrt{\frac{8}{2}}=2 \\&x+6=2 x \Rightarrow x=6 \mathrm{~cm}\)

In conclusion, the charge lies at (4,0,0)

Read more about charge

https://brainly.com/question/19886264

#SPJ1

After solving the equation the mass of canoe is 36.3kg.

What is momentum principle?

First, according to the momentum principle, an object's momentum, which is determined by its mass and velocity, is changed by a net force. In physics, momentum is defined mathematically as the product of mass and velocity, as seen in the equation below:

p = m ×v

p = momentum, and m = mass.

velocity, or v

There is no unique symbol used exclusively for momentum when it comes to units. Instead, it is just the sum of the usual units for mass and velocity, respectively, kilogrammes (kg) and metres per second (m/s). Kilograms times metres per second (kg m/s) are the units used to measure momentum.

Mdog=M1=8.5Kg

Vi dog= Vi boat= V1=0m/s

Vf dog= Vf1=0.47m/s

Vf boat=Vf2=0.11m/s

Mboat=M2=?

The momentum is conserved and constant.

Δp=pf −pi=0

pf−pi =0

pf-pi

​M1V1f + M2V2f= M1Vi + M2Vi

​M1V1f + M2V2f= 0

M2V2f = - M1V1f

      M2= -M1V1f÷V2f

           = -8.5× -0.47÷0.11

           =36.3Kg

To learn more about momentum principle
https://brainly.com/question/7538238
#SPJ4

The mass of the canoe is 36.3Kg

Define mass of an object.

The amount of matter a thing contains, or its mass, is a measure of the object's inertial attribute. An object's weight is a measurement of the force of gravity acting on it or the force required to hold it up.

Mass of the dog:

M1 = 8.5kg

Velocity of the dog:

V1  = 0.47m/s

Velocity of the canoe:

V2 = −0.17 m/s

mass of canoe :

M2 ?

Since the dog and boat are initially at rest, their combined motion is zero.

When the dog paddles alongside the canoe, both the dog and the canoe reach their respective speeds. But because to momentum conservation, their overall momentum stays constant.

Δp=pf −pi=0

pf = pi

​M1V1f + M2V2f= M1Vi + M2Vi

​M1V1f + M2V2f= 0

M2V2f = - M1V1f

     M2= -M1V1f÷V2f

          = -8.5× -0.47÷0.11

         =36.3Kg

To learn more about momentum use link below:

https://brainly.com/question/1042017

#SPJ4

The Falcon 9 rocket is so important in today's space exploration world because It's a reusable rocket and has saved money by being reused over 60 times already.

option D.

The Falcon 9 rocket, is developed by SpaceX, and it holds  a significant importance in today's space exploration world due to several key features and achievements, and some of the importance include the following;

From the given options, we can conclude that the Falcon 9 rocket is so important in today's space exploration world because It's a reusable rocket and has saved money by being reused over 60 times already.

Learn more about space exploration here: https://brainly.com/question/27325845

#SPJ1

a.) the ball was going up at 0.95 seconds and coming down at 4.58 seconds

b.) the distance of the wall from the plate is 34 m

Given that a ball player hits a home run, and the ball just clears the wall which is 22.0 m high. The ball is hit at an angle of 37.0" with a velocity of 45.0 m/s.

Since the ball is hit at an angle of 37.0 degrees, We need to find the vertical and horizontal component of the velocity.

\(U_{y}\) = 45 Sin 37 = 27.08 m/s

\(U_{x}\) = 45 cos 37 = 35. 94 m/s

Let us first calculate the maximum height reached.

\(V^{2}\) = \(U_{y} ^{2}\) - 2gH

At maximum height, V = 0

0 = \(27.08^{2}\) - 2 x 9.8H

19.6H = 733.3

H = 733.33/19.6

H = 37.4 m

If the ball is hit from a height of 0.750 m above the ground,

(a) To calculate the time the ball stays in the air until it  clears the wall while on its way down, we will use the formula below.

h =  \(U_{y}\)t - 1/2g\(t^{2}\)

Substitute for all the parameters

22 - 0.75 = 27.08t - 0.5 x 9.8 x \(t^{2}\)

21.25 = 27.08t - 4.9\(t^{2}\)

4.9\(t^{2}\) - 27.08t + 21.25

We will use quadratic formula

a = 4.9

b = - 27.08

c = 21.25

t =  \(\frac{-b+/- \sqrt{b^{2} - 4ac } }{2a}\)

t = \(\frac{27.08 +/- \sqrt{27.08^{2} - 4 * 4.9 * x^{2} 21.25 } }{2 * 4.9}\)

t = \(\frac{27.08 +/-\sqrt{733.3 - 416.5} }{9.8}\)

t = \(\frac{27.08 +/- 17.8}{9.8}\)

t = 44.88/9.8 or 9.28 / 9.8

t = 4.58 s  or 0.95 s

This means that the ball was going up at 0.95 seconds and coming down at 4.58 seconds

(b) The distance of the wall from home plate will be the range which is

R = \(U_{x}\)t

R = 35.94 x 0.95

R = 34.143 m

Therefore, the distance of the wall from the plate is 34 m approximately

Learn more about projectile here: https://brainly.com/question/4441382

Answer:

A ball hits the ground and the ground pushes up on it

Explanation:

Newton's third law basically states that for every action, there's a reaction.

a ball hitting the ground would be the action. the ground pushing up on it with the same force is the reaction.

Hope this Helps!!! :)

The order of magnitude of the given physical quantities would be  B < E < D < C

In positional notation, significant figures refer to the digits in a number that is trustworthy and required to denote the amount of something, also known as the significant digits, precision, or resolution.

Here, the order of magnitude of the following physical quantities is as follows

B.The mass of the Moon’s atmosphere: 25,000 kg ⇒ 10 ⁴

C.The mass of Earth: 5.97×10²⁴ kg ⇒ 10²⁴

D.The mass of the Moon is 7.34×10²² kg⇒ 10²²

E.The Earth-Moon distance (semi-major axis): 3.84×108 m ⇒  10⁸

Thus, the order of magnitude of the given physical quantities would be  B < E < D < C

Learn more about significant figures here

brainly.com/question/14359464

#SPJ1

Answer:

The rate of evaporation and the rate of condensation are the same.

Explanation:

I checked it myself on PennFoster

Hope This Helps!

Answer:

Boiling water is an example of a physical change and not a chemical change because the water vapor still has the same molecular structure as liquid water.

(credits to lumenlearning)

Explanation:

Answer:

boiling of water forms steam which can be further condensed to form water again, thus this change is a temporary and reversible change

Answer:

Explanation:

Oh sorry I thought I knew this one I guess not but you can prob look it up on safari

The total power received by the antenna is 2.14 × 10^-14 W, and  a source at a distance of 17000 ly would need to emit a power of 1.35 × 10^-26 W to provide a signal that could be detected by the radio telescope.

A radio wave is a type of electromagnetic wave with a frequency between about 3 kHz and 300 GHz. Radio waves are used for a variety of purposes, including communication, broadcasting, and radar. They are produced by oscillating electrical charges, and can travel through air and other materials, including space.

Radio waves are characterized by their frequency and wavelength. The frequency of a radio wave is the number of cycles per second, measured in hertz (Hz). The wavelength is the distance between two adjacent peaks of the wave, and is inversely proportional to the frequency. Radio waves with lower frequencies have longer wavelengths, while those with higher frequencies have shorter wavelengths.

Radio waves can be generated by a variety of sources, including antennas, electrical circuits, and certain types of electronic devices. They are used for communication between devices, such as radios and cell phones, as well as for broadcasting television and radio signals. Radio waves are also used for remote sensing, including radar and satellite communication.

Here in the Question,

(a) The power per unit area received by the antenna is given by:

P/A = 0.95 pW / 6.1 × 10^17 m^2

The total power received by the antenna is equal to the power per unit area multiplied by the area of the antenna:

P = (P/A) × π(0.5d)^2

where d is the diameter of the antenna. Substituting d = 380 m, we get:

P = (0.95 pW / 6.1 × 10^17 m^2) × π(0.5 × 380)^2

P = 2.14 × 10^-14 W

Therefore, the total power received by the antenna is 2.14 × 10^-14 W.

(b) To find the power of a source at 17000 ly distance that could provide such a signal, we need to consider the power spreading over the surface of a sphere with a radius of 17000 ly. The power density of the signal decreases with the square of the distance from the source, so the power received by the antenna from a source at a distance of 17000 ly is:

P = P0 × (d0 / d)^2

where P0 is the power emitted by the source, d0 is the distance from the source to the antenna (i.e., 17000 ly), and d is the diameter of the antenna.

Substituting the values given, we get:

P = (0.95 pW / 6.1 × 10^17 m^2) × π(0.5 × 380)^2 × (17000 × 9.461 × 10^15 m / 380 m)^2

P = 1.35 × 10^-26 W

Therefore, a source at a distance of 17000 ly would need to emit a power of 1.35 × 10^-26 W to provide a signal that could be detected by the radio telescope.

To learn more about the Doppler effect click:

https://brainly.com/question/3795295

#SPJ2

The vector with a magnitude of 5 and in the direction of the vector 4i - 3j + k is approximately (20/√26)i + (-15/√26)j + (5/√26)k.

The given vector can be normalized before being multiplied by the desired magnitude. This is how to locate the vector:

The vector that has been provided should be normalized by dividing each of its components by its magnitude. The Pythagorean theorem can be used to determine the magnitude of the vector 4i - 3j + k:

Magnitude = √(4² + (-3)² + 1²) = √(16 + 9 + 1) = √26

Normalize the vector by dividing each component by the magnitude:

Normalized vector = (4/√26)i + (-3/√26)j + (1/√26)k

Multiply the normalized vector by the desired magnitude:

To obtain a vector with a magnitude of 5, multiply each component of the normalized vector by 5:

Desired vector = 5 * ((4/√26)i + (-3/√26)j + (1/√26)k)

Simplifying the expression gives:

Desired vector ≈ (20/√26)i + (-15/√26)j + (5/√26)k

So, the vector with a magnitude of 5 and in the direction of the vector 4i - 3j + k is approximately (20/√26)i + (-15/√26)j + (5/√26)k.

Learn more about Pythagorean theorem here : brainly.com/question/28981380

#SPJ1

The final amount of pressure caused by the force is 90 N/m².

Initial amount of force, F₁ = 22 x 10³ N

Initial amount of pressure produced, P₁ = 110 N/m²

Final amount of force exerted, F₂ = 18 x 10³ N

Pressure is defined as the amount of force acting on an object per unit area of the object.

So, we can say that the force and pressure are directly proportional.

F ∝ P

So, F₁/P₁ = F₂/P₂

Therefore, the final amount of pressure caused by the force is,

P₂ = F₂P₁/F₁

P₂ = 18 x 10³x 110/22 x 10³

P₂ = 18/0.2

P₂ = 90 N/m²

To learn more about pressure, click:

https://brainly.com/question/8033367

#SPJ1

The work was done on the gas. and internal energy of the gas will be -13459 J and -21649 J.

When energy is moved from one store to another, work is completed. Work done on the gas is taken as -ve.

Given data;

Initial pressure(P₁)=1.0 bar

The initial volume, V₁=0.4m³

Final pressure(P₂) =1.4 bar.  

work is done on the gas., W=?(-ve)

Heat release= - 8.1 kJ

Change in the internal energy of the gas., ΔE

During the compression process, PV=C

P₁V₁=P₂V₂

1.0 bar × 0.4m³= 1.4 bar ×V₂

V₂=0.285 m³

\(\rm W=P_1V_1ln\frac{V_2}{V_1} \\\\\ \rm W=1.0 \times 0.4 ln\frac{0.285}{0.4} \\\\\ W=-13549 \ J\)

The work done on the gas will be -13459 J.

The internal energy is found as;

ΔE=q+w

ΔE= -8.1 ×10³ -13549

ΔE=-21649 J

Hence, work was done on the gas. and internal energy of the gas will be -13459 J and -21649 J.

To learn more about the work done by gas refer to;

https://brainly.com/question/12539457

#SPJ1

Given data:

The height of object is h₀=10.0 cm.

The object distance is u=6 cm.

The image distance is v=-2.00 cm.(negative because the image is behind the mirror)

The focal length can be calculated by the mirror's formula as,

Thus, the focal length of the mirror is -3.00 cm.

The statement that is NOT true is "the spaces between the particles increased.

option D.

If we consider the solids and liquids, when the temperature increases the molecules gain energy and start moving in all directions. This expands the substance and the volume of the substance increases.

Similar, when the ball is heated, the volume of the ball increases due to thermal expansion.

As the temperature increases, the average kinetic energy of the particles within the ball also increases, causing them to move faster.

However, the spaces between the particles do not necessarily increase. In fact, the expansion of the ball occurs due to the particles themselves moving farther apart, but the intermolecular spacing within the ball remains relatively constant.

Learn more about thermal expansion here: https://brainly.com/question/1166774

#SPJ1

The net charge enclosed by the outer surface before Q was introduced is 1530 \text{ nC}$$. The charge Q is 847 \text{ nC}$$. After Q is introduced, the charge on the inner surface of the conductor is -847 \text{ nC}$$.The charge on the outer surface of the conductor is  2377 \text{ nC}$$.

(a) The net charge enclosed by the outer surface before Q was introduced can be found using Gauss's Law:

$$\oint \vec{E} \cdot d\vec{A} = \frac{Q_{enc}}{\epsilon_0}$$

Since the electric field is uniform and directed outward, we can simplify this to:
$$E \cdot 4\pi r² = \frac{Q_{enc}}{\epsilon_0}$$

Plugging in the given values for E and r:
$$475 \cdot 4\pi (0.32)² = \frac{Q_{enc}}{8.85 \times 1\(0^{-12}\)}$$

Solving for Qenc:
$$Q_{enc} = 475 \cdot 4\pi (0.32)² \cdot 8.85 \times 1\(0^{-12}\)

= 1.53 \times 1\(0^{-9}\)\text{ C}

= 1530 \text{ nC}$$

(b) The charge Q can be found by comparing the electric field before and after it was introduced:
$$E_{before} - E_{after} = \frac{Q}{4\pi \epsilon_0 r²}$$

Plugging in the given values:
$$475 - 212 = \frac{Q}{4\pi (8.85 \times 1\(0^{-12}\)) (0.32)²}$$

Solving for Q:
$$Q = (475 - 212) \cdot 4\pi (8.85 \times 1\(0^{-12}\)) (0.32)²

= 8.47 \times 1\(0^{-10}\) \text{ C}

= 847 \text{ nC}$$

(c)After Q is introduced, the charge on the inner surface of the conductor will be equal and opposite to Q, so:

$$Q_{inner} = -Q = -847 \text{ nC}$$

(d) The charge on the outer surface of the conductor will be equal to the net charge enclosed by the outer surface, which is the sum of the original charge and Q:

$$Q_{outer} = Q_{enc} + Q =

1530 + 847

= 2377 \text{ nC}$$

More questions on charges: https://brainly.com/question/13296423

#SPJ11

Answer peek a boo

Explanation:

Answer:

v is the velocity of a object

Answer:

At that time, she was in the southern hemisphere

Explanation:

She is witnessing the southeastern trade breeze because the cloud is passing from east to west and she is also witnessing a storm from the southeast.

Because of the Coriolis effect, which deviates the atmosphere in the left-hand side of the southern hemisphere and generates a southeastern wind, this wind did not blow directly from south to east.

Answer: C

Explanation: i have played sports in my life now i am no physics person but in order to follow the rules you have  to be a team player. and a part of being a team player is being positive and so b=a*d  

The final speed of the runner at the end of the race is zero, since the runner's acceleration is zero for the rest of the race.

To solve this problem, we can use the following kinematic equation:

v = u + at

Where:

First, we can calculate the distance covered during the first 5.2 seconds of acceleration, using the equation:

s = ut + 0.5at^2

Where s is the distance, u is the initial velocity (zero in this case), a is the acceleration (1.9 m/s^2), and t is the time (5.2 s):

s = 0 + 0.5(1.9)(5.2)^2 = 52.73 m

Next, we can calculate the time for the rest of the race, which is the total time minus the initial 5.2 seconds of acceleration:

t' = t - 5.2 s

The final velocity can then be calculated using the same equation as before, but with a = 0 and t = t':

v = u + at' = 0 + 0(t') = 0

Learn more about speed of runner here: https://brainly.com/question/14101278

#SPJ1

The mass of each object is 0.004 kg, to the nearest kg.

What is mass?

The mass is a measure of the amount of matter an object contains. It is typically measured in units of kilograms (kg) or grams (g). The mass of an object is distinct from its weight, which is the force exerted on an object by gravity and is measured in units of newtons (N) or pounds (lb).

The mass of an object will remain the same, regardless of its location in the universe, while its weight will vary depending on the strength of the gravitational force acting on it.

To find the mass of each object, we can use the formula for gravitational force: F = G * (m1 * m2) / r^2.

By substituting in the given values and solving for m1 or m2, we get:

F = G * (m1 * m2) / r^2

2.67 x 10^-10 N = (667 x 10^-11 N-m^2/kg^2) * (m1 * m2) / (10 m)^2

m1 = m2 = (2.67 x 10^-10 N * (10 m)^2) / (667 x 10^-11 N-m^2/kg^2)

m1 = m2 = 0.004 kg

The mass of each object is 0.004 kg, to the nearest kg.

To learn more about mass:

https://brainly.com/question/28021242

#SPJ1

Answer:

Explanation:

A) The output force required to lift a 15 kg object would be equal to the weight of the object, which is given by:

Output force = Weight of object = m * g

where m is the mass of the object and g is the acceleration due to gravity. Assuming that g is equal to 9.81 m/s^2, we have:

Output force = 15 kg * 9.81 m/s^2 = 147.15 N

Therefore, the output force required to lift a 15 kg object would be 147.15 N.

B) In this case, the input force is the force that you are pushing down with the lever, which is given as 20 N.

C) The mechanical advantage of the ramp is given by the ratio of the output force to the input force. In this case, the output force is the weight of the object (40 N) and the input force is the force that you are pushing with (10 N). Therefore, the mechanical advantage of the ramp would be:

Mechanical advantage = Output force / Input force = 40 N / 10 N = 4

So, the ramp multiplies your force by a factor of 4.

Note that in all of these calculations, we have assumed that the system is ideal and that there are no losses due to friction or other factors. In practice, these losses will reduce the mechanical advantage of the system and make it more difficult to lift or move objects.

Answer:

24.2 m/s

Explanation:

Mass is irrelevant in this situation....

Displacement:  ( to find time)

 x = xo + vo t - 1/2 at^2

 30= 0   + 0  - 1/2 (9.8)t^2

              t = 2.47 seconds

Velocity:

vf = a t   = 9.8 (2.473)  = 24.2 m/s

The magnitude of the magnetic force on a proton is 1.68 ✕ 10^−16 N, directed towards the negative y-direction. The magnitude of the magnetic force on an electron is also 1.68 ✕ 10^−16 N, but directed towards the positive y-direction.

Begin by using the formula for the magnetic force on a charged particle moving in a magnetic field:

F = q * v * B * sin(θ)

where F is the magnetic force, q is the charge of the particle, v is the velocity of the particle, B is the magnetic field strength, and θ is the angle between the velocity vector and the magnetic field vector.

For a proton, the charge is +e, where e is the elementary charge (1.6 ✕ 10^−19 C). The velocity of the proton is given as 3.99 ✕ 10^5 m/s in the positive x-direction. The magnetic field strength is 2.93 ✕ 10^−8 T in the positive z-direction.

The angle θ between the velocity vector and the magnetic field vector is 90 degrees since the velocity is perpendicular to the magnetic field.

Substituting the values into the formula, we get:

F_proton = (+e) * (3.99 ✕ 10^5 m/s) * (2.93 ✕ 10^−8 T) * sin(90°)

F_proton ≈ 1.68 ✕ 10^−16 N

Since the proton has a positive charge, the magnetic force is directed opposite to the direction of electron flow, which is in the negative y-direction.

Repeat the steps for an electron, but note that the charge is -e. The direction of the force on an electron will be opposite to that of a proton.

F_electron = (-e) * (3.99 ✕ 10^5 m/s) * (2.93 ✕ 10^−8 T) * sin(90°)

F_electron ≈ -1.68 ✕ 10^−16 N

The force on an electron is also 1.68 ✕ 10^−16 N, but directed towards the positive y-direction.

Remember to consider the proper units and take into account the directions of charge, velocity, and magnetic field when calculating the magnetic force on a charged particle.

For more such questions on magnetic force, click on:

https://brainly.com/question/13277365

#SPJ8

The water pressure at the bottom of the 54-m-high water tower is

pressure of water at a certain depth is calculated using the formula

Pressure, P = height * density * acceleration due to gravity

density of water is given by = 1000 kg/m³

acceleration due to gravity is given by = 9.82 m/s²

the given height, at the bottom of the 54-m-high water tower  = 54 m

Pressure = 1000 kg/m³ *  9.82 m/s² * 54 m

Pressure = 530280 N/m²

Pressure = 0.53 M N/m²

Pressure = 0.53 M Pa

The pressure at the bottom of the 54-m-high water tower is 0.53 MPa

The unit of pressure used here is Pa which is equal to N/m² other unit include pound - force foot

1 N/m² = 0.73756 pound-force foot

530280 N/m² = 530280 * 0.73756 = 391113.32 pound-force foot

Learn more about pressure of water at:

https://brainly.com/question/24827501
#SPJ4

Answer:

Explanation:

1/v - 1/u = 1/f

given, f = 0.3 m, u = -0.4m

so, 1/v - 1/-0.4 = 1/0.3

or, 1/v = 1/0.3 - 1/0.4 = 1/1.2

v = 1.2 m

now, differentiating 1/v - 1/u = 1/f with respect to t,

-1/v² dv/dt + 1/u² du/dt = 0

or, dv/dt = (v/u)² du/dt

putting, du/dt = 0.01 m/s , v = 1.2 m and u = -0.4 m

so, dv/dt = (1.2/-0.4)² × 0.01

= 0.09 m/s

hence, speed of image with respect to lens is 0.09 m/s .

from formula of magnification

magnification, m = v/u

differentiating with respect to time both sides,

dm/dt = (u dv/dt - vdu/dt)/u²

= (-0.4 × 0.09 - 1.2 × 0.01)/(-0.4)²

= (-0.036 - 0.012)/0.16

= -0.048/0.16

= -0.3 m/s

hence, magnitude of rate of change of lateral magnification is 0.3 m/s