What is the structure formula of c10h18

Answers

Answer 1

Answer: I'm not 100% sure this is the formula but I hope it still helps! :)

Explanation:

Bornane; Cyclodecene; Decalin; Decynes. 1-Decyne; 2-Decyne; 3-Decyne; 4-Decyne; 5-Decyne, also known as dibutylethyne; Spirodecane


Related Questions

what conditions does bacteria need to grow in yogurt?

Answers

The temperature must be 108°F to 112°F for yogurt bacteria to grow properly. Too high a temperature inactivates bacteria; too low a temperature prohibits growth. Inhibitor substances such as detergent from dishes. Wash and rinse dishes well before making yogurt.

Find the enthalpy for a constant pressure calorimetry reaction where the reaction occurs in a 250ml aqueous solution. The temperature changes from 25.0c to 26.1 c

Assume that cool = 4.18j/gt

Answers

Answer:

\(\Delta H=1149.5J\)

Explanation:

Hello!

In this case, since the calorimeter contains a solution for which the specific heat is 4.18 J/g°C, which is equal to that of the water, we can also notice that the density is 1.00 g/mL and therefore the present mass is 250 g. In such a way, we compute the enthalpy change as shown below:

\(\Delta H=mC\Delta T\)

Thus, by plugging in the mass, specific heat and temperature change, we obtain:

\(\Delta H=250g*4.18\frac{J}{g\°C}(26.1\°C-25.0\°C)\\\\\Delta H=1149.5J\)

Best regards!

For each chemical reaction listed in the table below, decide whether the highlighted atom is being oxidized or reduced.
reaction
4 HF (9) + SiO₂ (s) → SiF4(9) + 2 H₂O(g)
2 Cl(aq) + 2 H₂O 2OH(aq) + H₂(g) + Cl₂(9)
-
H₂S(aq) + 2NaOH(aq) → Na₂S(aq) + 2 H₂O(
2 H₂(g) + O₂(g) 2 H₂O(g)
-
oxidized
O
O
O
highlighted atom is being...
O
reduced
O
O
O
neither oxidized
nor reduced
O
O
O
S

Answers

- In reactions 1 and 2, the highlighted atom (oxygen) is reduced.

- In reaction 3, the highlighted atom (sulfur) is neither oxidized nor reduced.

- In reaction 4, the highlighted atom (oxygen) is reduced.

In the given chemical reactions, we need to identify whether the highlighted atom is being oxidized or reduced. Let's analyze each reaction individually:

Reaction 1: 4 HF (g) + SiO₂ (s) → SiF₄ (g) + 2 H₂O (g)

In this reaction, the highlighted atom is oxygen (O). Oxygen in SiO₂ undergoes a change in oxidation state from -2 to 0 in SiF₄. Therefore, the highlighted atom (oxygen) is reduced.

Reaction 2: 2 Cl (aq) + 2 H₂O (l) → 2 OH (aq) + H₂ (g) + Cl₂ (g)

In this reaction, the highlighted atom is oxygen (O). Oxygen in H₂O undergoes a change in oxidation state from -2 to -1 in OH. Therefore, the highlighted atom (oxygen) is reduced.

Reaction 3: H₂S (aq) + 2 NaOH (aq) → Na₂S (aq) + 2 H₂O (l)

In this reaction, the highlighted atom is sulfur (S). Sulfur in H₂S undergoes a change in oxidation state from -2 to -2 in Na₂S. Therefore, the highlighted atom (sulfur) is neither oxidized nor reduced.

Reaction 4: 2 H₂ (g) + O₂ (g) → 2 H₂O (g)

In this reaction, the highlighted atom is oxygen (O). Oxygen in O₂ undergoes a change in oxidation state from 0 to -2 in H₂O. Therefore, the highlighted atom (oxygen) is reduced.

To summarize:

- In reactions 1 and 2, the highlighted atom (oxygen) is reduced.

- In reaction 3, the highlighted atom (sulfur) is neither oxidized nor reduced.

- In reaction 4, the highlighted atom (oxygen) is reduced.

It's important to note that oxidation and reduction involve changes in the oxidation state of atoms, indicating the gain or loss of electrons. The analysis above is based on the change in oxidation state of the highlighted atom in each reaction.

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Select the correct algebraic form for the equation to be used for this calculation.

n equals StartFraction R T over P V EndFraction.

n equals StartFraction P V over R T EndFraction.

n equals StartFraction R V over P T EndFraction.

Answers

Answer:

55.9 kPa

Explanation:

Whhat are the maximum number of molecules present in 10g of O2 gas at STP?

Answers

Of course, at STP, dioxygen is a gas, but 10.0 g is still 10.0 g. We could calculate its volume at STP, which is 22.4 L × its molar quantity, approx. 8⋅L . There are 1.51×1023molecules O2 in 10.0 g O2 .

I need help asap please help me

I need help asap please help me

Answers

Answer:

the answer is the third one the beak

An iceberg has a volume of 7655 cubic feet. What is the mass of the ice (in kg) composing the iceberg?

Answers

Taking into account the definition of density, the mass of ice is 198,773.6004 kg.

Definition of density

Density is a quantity that allows us to measure the amount of mass in a certain volume of a substance. Then, the expression for the calculation of density is the quotient between the mass of a body and the volume it occupies:

density= mass÷ volume

From this expression it can be deduced that density is inversely proportional to volume: the smaller the volume occupied by a given mass, the higher the density.

Mass of ice

In this case, you know that:

Density of ice= 0.917 g/cm³Volume= 7655 ft³≅ 2.1677×10⁸ cm³ (being 1 ft³= 28316.8 cm³)

Replacing in the definition of density:

0.917 g/cm³= mass÷ 2.1677×10⁸ cm³

Solving:

mass= 0.917 g/cm³ ×2.1677×10⁸ cm³

mass= 198,773,600.4 g= 198,773.6004 kg

In summary, the mass of ice is 198,773.6004 kg.

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How many grams of NaCl are needed to make 1.00 liter of a 3.00 M NaCl solution?
Explain your answer.

Answers

Do they have a Grapher anything

Which measurement occurs last when collecting data to determine the
percentage by mass of a solution?

Answers

mass percent = (mass of element in 1 mole of compound / mass of 1 mole of compound) x 100. The formula for a solution is:

mass percent = (grams of solute / grams of solute plus solvent) x 100. or.

mass percent = (grams of solute / grams of solution) x 100. The final answer is given as %.

Hope this helps!!

HỌ5,42
Homework Answered Due Today, 11:59 PM
.
A 5.60E1 g sample of water at 9.910E1 °C is placed in a constant pressure calorimeter. Then, 2.40E1 g of zinc metal at 2.10E1 °C is
added to the water and the temperature drops to 9.70E1 °C. What is the specific heat capacity of the zinc metal measured in this
experiment?

Answers

The specific heat capacity of the zinc metal, given that 2.40×10¹ g of zinc metal at 2.10×10¹ °C is added to the water is 0.27 J/gºC

How do i determine the specific heat capacity of the zinc?

First, we shall obtain the heat absorbed by the water when the zinc metal was added. This is shown below:

Mass of water (M) = 5.60×10¹ gInitial temperature (T₁) = 9.910×10¹ °CFinal temperature (T₂) = 9.70×10¹ °CChange in temperature (ΔT) = 9.70×10¹ - 9.910×10¹ = -2.1 °CSpecific heat capacity of water (C) = 4.184 J/gºC Heat absorbed by water (Q) =?

Q = MCΔT

= 5.60×10¹ × 4.184 × -2.1

= -492.0384 J

Now, we shall determine the specific heat capacity of the zinc metal. Details below:

Heat absorbed by water (Q) = -492.0384 JHeat released by metal (Q) = 492.0384 JMass of zinc metal (M) = 2.40×10¹ gInitial temperature (T₁) = 2.10×10¹ °CFinal temperature (T₂) = 9.70×10¹  °CChange in temperature (ΔT) = 9.70×10¹ - 2.10×10¹ = 76 °CSpecific heat capacity (C) = ?

Q = MCΔT

492.0384 = 2.40×10¹ × C × 76

492.0384 = 1824 × C

Divide both sides by 1824

C = 492.0384 / 1824

= 0.27 J/gºC

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help pleaseeeeeeeeeeee

help pleaseeeeeeeeeeee

Answers

The image that is shown contains an organized lesson content.

How do you organize a lesson content?

The following steps should be taken to organize a lesson plan;

Identify the objective: Start by defining the objective of the lesson and what you want your students to learn by the end of it. This will help you create a clear and focused lesson plan.

Gather materials and resources: Identify any materials, resources, or technology you will need for the lesson and gather them ahead of time.

Plan the structure: Determine the flow of the lesson, including any key concepts or ideas you want to cover, and how you will introduce and conclude the lesson.

Consider the pace: Decide on the pace of the lesson, taking into account the attention span of your students, and plan activities that will keep them engaged and on task.

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What is the SI unit of time?
OA.
second
OB.
minute
OC. hour
OD. day
Res

Answers

\(▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪\)

The correct choice is ~ A

S.I unit of time is Second

There are 3 reactions of Calcium Carbonate, CaCO₃, that can be formed in this particular problem:

Reaction 1: Calculate the ΔH₁
Reaction 2: ΔH₂ = -635.1 kJ
Reaction 3: ΔH₃ = 178.3 kJ

There are 3 reactions of Calcium Carbonate, CaCO, that can be formed in this particular problem:Reaction

Answers

ΔH₁ = ΔH₂ - ΔH₃

ΔH₁ = -635.1-(178.3) KJ

ΔH₁ = -813.4 KJ

A 35.00 mL sample of an H2SO4 solution of unknown concentration is titrated with a 0.1422 M KOH solution. A volume of 43.22 mL of KOH was required to reach the equivalence point.
What is the concentration of the unknown H2SO4 solution?

Answers

To know the end point we use phenolphthalein as indicator. End point is a point where completion of reaction happen. Therefore, the concentration of the unknown H\(_2\)SO\(_4\) solution is 0.11M.

What is titration?

Titration is a technique by which we know the concentration of unknown solution using titration of this solution with solution whose concentration is known.

According to the neutralization law,

M₁V₁=M₂V₂

where,

M₁ = molarity of  H2SO4 solution

V₁ = volume of  H2SO4 solution

M₂ = molarity of KOH solution

V₂ = volume of KOH solution

substituting all the given values we get

0.1422 M × 35.00 ml=M₂×43.22 mL

M₂= 0.11M

Therefore, the concentration of the unknown H\(_2\)SO\(_4\) solution is 0.11M.

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HQ5.40
Homework Answered Due Today, 11:59 PM
The reaction 3H₂(g) + N₂(g) → 2NH3(g) has an enthalpy of reaction of -92.6 kJ/mol. If 1 g of hydrogen and 2 g of nitrogen are
reacted, how much heat is produced (kJ)?

Answers

The amount of heat energy produced when 1 g of hydrogen and 2 g of nitrogen are reacted, is -6.61 KJ

How do i determine the heat energy produced?

First, we shall obtain the limiting reactant. Details below:

3H₂ + N₂ -> 2NH₃

Molar mass of N₂ = 28 g/molMass of N₂ from the balanced equation = 1 × 28 = 28 g Molar mass of H₂ = 2 g/molMass of H₂ from the balanced equation = 3 × 2 = 6 g

From the balanced equation above,

28 g of N₂ reacted with 6 g of H₂

Therefore,

2 g of N₂ will react with = (2 × 6) / 28 = 0.43 g of H₂

We can see that only 0.43 g of H₂ is needed in the reaction.

Thus, the limiting reactant is N₂

Finally, we the amount of heat energy produced. Details below:

3H₂ + N₂ -> 2NH₃ ΔH = -92.6 KJ

Molar mass of N₂ = 28 g/molMass of N₂ from the balanced equation = 1 × 28 = 28 g

From the balanced equation above,

When 28 grams of N₂ reacted, -92.6 KJ of heat energy were produced.

Therefore,

When 2 grams of N₂ will react to produce = (2 × -92.6) / 28 = -6.61 KJ

Thus the heat energy produced from the reaction is -6.61 KJ

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The first-order rate constant for the decomposition of N2O5
2N2O5(g)→4NO2(g)+O2(g)
at 70∘C is 6.82×10−3 s−1. Suppose we start with 2.70×10−2 mol of N2O5(g)
in a volume of 2.5 L
1) How many moles of N2O5 will remain after 7.0 min?
2)How many minutes will it take for the quantity of N2O5 to drop to 1.7×10−2 mol?
3)What is the half-life of N2O5 at 70 ∘C?

Answers

1) To calculate the number of moles of N2O5 that will remain after 7.0 min, we can use the first-order rate law equation:
ln([N2O5]t/[N2O5]0) = -kt

where [N2O5]t is the concentration of N2O5 at time t, [N2O5]0 is the initial concentration of N2O5, k is the rate constant, and t is the time. Rearranging this equation, we get:

[N2O5]t = [N2O5]0 * e^(-kt)

Plugging in the given values, we get:

[N2O5]t = (2.70×10^−2 mol) * e^(-6.82×10^−3 s^-1 * 7.0 min * 60 s/min) = 1.20×10^−2 mol

Therefore, 1.20×10^−2 mol of N2O5 will remain after 7.0 min.

2) To calculate the time it takes for the quantity of N2O5 to drop to 1.7×10−2 mol, we can rearrange the equation from part 1 and solve for t:

t = -ln([N2O5]t/[N2O5]0)/k

Plugging in the given values, we get:

t = -ln(1.7×10^-2 mol/2.70×10^-2 mol)/(6.82×10^-3 s^-1) = 9.5 min

Therefore, it will take 9.5 min for the quantity of N2O5 to drop to 1.7×10^-2 mol.

3) The half-life of a first-order reaction is given by:

t1/2 = ln(2)/k

Plugging in the given rate constant, we get:

t1/2 = ln(2)/(6.82×10^-3 s^-1) = 101.6 s

Therefore, the half-life of N2O5 at 70°C is 101.6 s.

100 POINTS!!!
12. What is the specific type of molecule shown below called?

13.An amino acid has an amino group (shown in blue), a carboxylic acid group (shown in red), and some kind of side chain (shown in green). What type of macromolecule is made from this molecule? (1 pt)

14 What is the main purpose of this macromolecule shown

100 POINTS!!! 12. What is the specific type of molecule shown below called?13.An amino acid has an amino

Answers

12. A monosaccharide is exactly the type of molecule shown below, which is a carbohydrate.

Carbohydrates are composed of carbon, hydrogen and oxygen in the ratio 1:2:1 in organic molecules. The simplest type of carbohydrate is a monosaccharide, which cannot be broken down further into smaller sugar molecules. They typically have three to seven carbon atoms and are composed of a single sugar molecule.

13. An amino acid is a special type of molecule that is shown in the description. The production and structure of proteins largely depend on amino acids, which are the basic components of proteins.

14. Nucleic acids are primarily used by living things to store and transmit genetic information. DNA (deoxyribonucleic acid) and RNA (ribonucleic acid), two types of nucleic acids, carry instructions necessary for the production of proteins as well as for the operation and growth of cells.

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PLEASE HELP...

Balance this nuclear reaction by supplying the missing nucleus. Replace each question mark with an appropriate integer or symbol.
Cf98249 + ? ⟶Db105260+410n

Answers

The balanced form of the nuclear equation is as follows; 249/98 Cf + 15/7 N⟶ 260/105 Db + 4(1/0) n.

What is a nuclear equation?

A nuclear equation is process such as the fission of an atomic nucleus, or the fusion of one or more atomic nuclei and/or subatomic particles in which the number of protons and/or neutrons in a nucleus changes.

According to this question, Californium element is a reactant to produce dubnium and a neutron as products.

However, the law of conservation of mass must be fulfilled by ensuring the mass and atomic numbers of elements in reactant and product side are the same.

249/98 Cf + 15/7 N⟶ 260/105 Db + 4(1/0) n

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Which of these describes a chemical property? A. the color of the substance B. the hardness of the substance C.how the substance behaves in the presence of an acid D. how the substance behaves in the presence of a magnet​

Answers

Answer:

C. How the substance behaves in the presence of an acid.

Explanation:

Have a great day

Chemical properties can be defined as the ones that describe a substance's ability to undergo chemical changes.

Physical properties can be defined as the ones that are measured and observed without actually changing the substance's identity.

Among the given options, the color, the hardness, and the behavior of a substance in the presence of a magnet are all examples of physical properties.

However, the behavior of a substance in the presence of an acid is an example of chemical property.

Hence, the correct answer is option c.

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HELP ME!!! Is it right? Or wrong

HELP ME!!! Is it right? Or wrong

Answers

Board line missing a carbon

Mean, median and mode are best described as which?
A. Qualitative and quantitative data
B. Measures of central tendency
C. Discrete and continuous data
D. Histogram, scatterplot and circle

Answers

Answer:

B. Measures of central tendency

Explanation:

Mean, median and mode are best described as measures of central tendency of a given data set.

Mean is the average of the samples given

Mode is the data point with the most frequent occurrence

Median is the data point that lies in the middle

All these parameters tells us how far a data point is from the middle or how close they are.

(a) Is x-ray spectrography or optical emission spectrography more suitable for (1) trace analysis? Xray spee is more plicated spectra?​

Answers

For trace analysis, X-ray spectrography is more suitable as it is more sensitive technique and gives finer emission spectrum.

What is emission spectrum?

Emission spectrum is defined as a spectrum of a chemical compound or substance composed of frequencies of electromagnetic radiation. Radiations which are emitted while electron make transition from higher to lower energy level.

Energy of photon is equal to the difference between the two energy states . There are many possible electronic transitions in an atom and every transition has a specific wavelength.

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Each molecule of an olefin has at least:
a
one double bond
b
two double bonds
c
three double bonds
d
two or more single bonds

Answers

A is the answer - olefin compound has a carbon double bond and four hydrogen single bonds.

Answer:

a.

Explanation:

One double bond.

For example ethene CH2=CH2

When liquids of a ph 5 and ph 2 mixed together, gives what ph value

Answers

Answer:

By mixing two solutions of differing pH values, the final pH of the mixed solution is going to be a function of the pH-, or the hydrogen ion (H+), of the lower pH solution, and the final volume. The hydrogen ion(H+) of the higher pH solution has little to no effect in the final pH value.

What is the molar mass of a compound that is 23.3 g and contains 3.23 moles?

Answers

Water because it’s molar mass

How many grams of carbon dioxide (CO2) are produced from the combustion of 13.00 g of CH4?

Answers

Answer:

35.68g CO2

Explanation:

we use the combustion equation with CH4:

CH4+ O2= CO2 + H2O

And then balance it:

CH4+ 2O2= CO2 + 2H2O

Using this equation we can use sociometry:

\(13g CH4*\frac{1molCH4}{16.032gCH4} *\frac{1mol CO2}{1molCH4} *\frac{44g CO2}{1mol CO2}=35.68g CO2\)

We know that  16.032 is how many grams there are in one mole of CH4 by adding the weights of the atoms (12 +1.008+1.008+1.008+1.008). These weights can be found on the periodic table. The same goes for the amount of grams per CO2.

The important thing about sociometry is to make sure your units cancel out until you are only left with the unit you want. If grams of CH4 is in the numerator, the next fraction you multiply by should have grams of Ch4 in the denominator. If moles of CO2 are in the numerator, the next fraction should have moles of CO2 in the denominator.  

If the potassium atoms could be lined up in a row, how many of them would it take to make a 1.00 ft row of potassium atoms?

Answers

If the potassium atoms could be lined up in a row, it would take to make a 1.00 ft row of potassium atoms is 5.45 × 10⁻⁸.

Potassium atom is represented by K with atomic number 19. It is a silvery white metal.

Given,

Radius = 280pm = 280 × 10⁻¹²m

Diameter = 2radius = 560× 10⁻¹²m = 560pm

We know that,

1 feet = 0.305m

So, number of potassium atoms that fits into the row,

1 feet = 0.305/560 × 10⁻¹²

1 feet = 5.45 × 10⁻⁸

Hence, it takes 5.45 × 10⁻⁸ atoms of potassium to make a 1 feet row.

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An atom is found to have 44 Protons.
What would be necessary to balance out the charge, making it a neutral atom?

Answers

For any component: Proton count equals atomic number

Number of protons plus number of electrons equals the atomic number.

The number of neutrons is equal to the atomic number-mass number.

What does atomic number mean?

The quantity of protons in an element's atom is known as the atomic number. The atomic number of krypton in our illustration is 36. This indicates that the nucleus of a ruthenium atom contains 36 protons.

Every atom of ruthenium has 44 protons, which is intriguing. A Ruthenium atom cannot exist if it does not have 44 protons. A distinct element is produced by changing the number of protons in an atom's nucleus. An atom of rhodium is produced, for instance, by taking one proton away from a krypton atom.

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Categorize each property as either physical or chemical.
Physical Properties
Chemical Properties
melting point
color
density
flammability
corrosiveness
electrical
reactivity with acids
hardness

Answers

Answer:

Physical properties are the properties of a substance that can observed and measured without altering the identity of the substance. Examples of physical properties according to the above question are color, hardness, malleability, electrical conductivity, density, melting point.

Chemical properties on the other hand are the properties of a substance that describes the ability of the substance to undergo chemical reactions based on its composition. Examples include reactivity with acids, flammability.

In other words, to identity a chemical property of a substance we check its ability to be change into a different state via chemical reaction. Rusting of iron is a good example of chemical property.

So therefore, categorizing the properties we have;

Physical properties                                             Chemical Properties

Melting point                                                                Flammability

Color                                                                        Reactivity with acids

Density                                                                       Corrosiveness

Electrical conductivity

Hardness

Answer:

Physical: Melting Point, Color, Conductivity, Boiling Point

Chemical: Susceptibility to rust, flammability

Explanation:

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What causes droughts?

1. Humans
2. Natural Events
3. Aliens from outer space
4. Like with many things about our planet it is caused by Humans and Nature

Answers

Answer:

The is 4. Like with many things about our planet it is caused by Humans and Nature, I belive because droughts can be caused by humans and nature.

Explanation: Humans cut trees down trees , which trigger droughts to happen. Also because when humans cut a widespread of trees down just for fuel, it can potentially reduce the soil's ability to hold water ... triggering droughts to happen. But also droughts can happen just by nature.

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