Answers
Answer:
its going up so in that case its positive
Step-by-step explanation:
if it is going down it is negative
Related Questions
negative sixteen plus the quotient of a number and -4 is -3
Answers
Answer:
The number is 76
Step-by-step explanation:
The expression quantity negative two thirds times x minus 6 end quantity minus quantity negative 14 plus one sixth times x end quantity.
Answers
The simplifies expression is -5x/6 - 8
The expression "quantity negative two thirds times x minus 6 end quantity minus quantity negative 14 plus one sixth times x end quantity" represents:
-(2/3)x - 6 - ( -14 + (1/6)x)
The process of simplifying an expression involves reducing the expression to its simplest form, making it easier to understand and manipulate. To simplify an expression, we combine like terms by adding or subtracting the coefficients.
We need to simplify this expression into its simplest form.
Thus,
-(2/3)x - 6 - ( -14 + (1/6)x) equals,
= -2x/3 - 6 +14 - x/6
= -(4+1)x/6 - 8
= -5x/6 - 8
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Solve for g
g/3 + 18 = 20
Answers
The value of g in g/3 + 18 = 20 is 6.
What is equation?Two expressions with variables or integers are said to be equal when they are declared to be in an equation. Equations are questions at their core, and attempt to methodically find the answers to these questions have been the inspiration for the development of mathematics.
Given:
The equation, g / 3 + 18 = 20,
g / 3 = 20 - 18
g = 2 × 3
g = 6
Therefore, the value of g in g/3 + 18 = 20 is 6.
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Utility and Choice Consider the following utility functions. Assume x 1
≥0,x 2
≥0. U 1
(x 1
,x 2
)=(x 1
+4x 2
) 2
U 2
(x 1
,x 2
)=5x 1
3
x 2
4
U 3
(x 1
,x 2
)=x 1
(x 2
+2)
U 4
(x 1
,x 2
)=max{x 1
,x 2
}
U 5
(x 1
,x 2
)=min{3x 1
+x 2
,x 1
+3x 2
}
In your answers, label all intercepts, kinks, coordinates, slopes, and axes. Give an answer to the following two questions for each of the first three utility functions above: 1. Derive an expression for the Marginal Utility of each good. 2. Compute the Marginal Rate of Substitution at the bundle (2,4).
Answers
To derive the expression for the Marginal Utility (MU) of each good in the given utility functions, we need to take the partial derivatives of the utility functions with respect to each good. Let's calculate the MU for each good in the first three utility functions:
1. Utility function U1(x1,x2) = (x1 + 4x2)^2:
To find the MU of x1, we differentiate U1 with respect to x1 while treating x2 as a constant:
MU1(x1,x2) = 2(x1 + 4x2) * 1 = 2(x1 + 4x2)
To find the MU of x2, we differentiate U1 with respect to x2 while treating x1 as a constant:
MU2(x1,x2) = 2(x1 + 4x2) * 4 = 8(x1 + 4x2)
2. Utility function U2(x1,x2) = 5x1^3 * x2^4:
To find the MU of x1, we differentiate U2 with respect to x1 while treating x2 as a constant:
MU1(x1,x2) = 15x1^2 * x2^4
To find the MU of x2, we differentiate U2 with respect to x2 while treating x1 as a constant:
MU2(x1,x2) = 20x1^3 * x2^3
3. Utility function U3(x1,x2) = x1 * (x2 + 2):
To find the MU of x1, we differentiate U3 with respect to x1 while treating x2 as a constant:
MU1(x1,x2) = x2 + 2
To find the MU of x2, we differentiate U3 with respect to x2 while treating x1 as a constant:
MU2(x1,x2) = x1
Next, let's compute the Marginal Rate of Substitution (MRS) at the bundle (2,4) for each utility function. MRS measures the rate at which a consumer is willing to substitute one good for another while maintaining the same level of utility.
1. Utility function U1(x1,x2) = (x1 + 4x2)^2:
The MRS is given by the ratio of the marginal utilities:
MRS(x1,x2) = MU1(x1,x2) / MU2(x1,x2)
Substituting the values x1 = 2 and x2 = 4 into the expressions for MU1 and MU2 derived earlier, we get:
MRS(2,4) = [2(2 + 4(4))] / [8(2 + 4(4))]
Simplifying the expression, we have:
MRS(2,4) = 12 / 48 = 1/4
2. Utility function U2(x1,x2) = 5x1^3 * x2^4:
Similarly, the MRS is given by the ratio of the marginal utilities:
MRS(x1,x2) = MU1(x1,x2) / MU2(x1,x2)
Substituting the values x1 = 2 and x2 = 4 into the expressions for MU1 and MU2 derived earlier, we get:
MRS(2,4) = (15(2^2)(4^4)) / (20(2^3)(4^3))
Simplifying the expression, we have:
MRS(2,4) = 960 / 1280 = 3/4
3. Utility function U3(x1,x2) = x1 * (x2 + 2):
The MRS is given by the ratio of the marginal utilities:
MRS(x1,x2) = MU1(x1,x2) / MU2(x1,x2)
Substituting the values x1 = 2 and x2 = 4 into the expressions for MU1 and MU2 derived earlier, we get:
MRS(2,4) = (4 + 2) / 2 = 3/2
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What is the value of 5/6+(-4/9)-(-2)
Answers
Eli is exploring a career choices. After randomly surveying 40 companies,he determines that the annual median salary for a computer tech Ian is 72,000. Which two statements are valid inferences for this situation
Answers
Answer:
The answer is A 50% of computer technicians earn more than $72,000 annually. Step-by-step explanation:
dont have 1 i cheated
Answer:
a and c
Step-by-step explanation:
Tatiana is playing a video game. She earns 25 points when she completes Level 1. Each time she completes a level, she earns three times as many points as the previous level.
How many points will Tatiana earn when she completes Level 7?
Answers
Answer:
18,225
Step-by-step explanation:
L1=25
L2=75
L3=225
the pattern is (25)* 3^(n-1)
L1=3^0*25 = 25
L2=3^1*25 = 3* 25 = 75
L3=3^2*25 = 9* 25 = 225
.
.
L7=3^6*25 = 729* 25 = 18,225
Solve for the variable shown. Round answers to the nearest hundredth if needed.
Answers
Answer and Step-by-step explanation:
Question 4:
We need to solve for y, so we need to use the cosine trig function, which is adjacent divided by hypotenuse.
\(cos(21) = \frac{y}{18}\\\\18(cos(21)) = y = 16.8\\\\\\\)
Question 5:
We need to use the sine trig function, which is opposite divided by hypotenuse.
\(sin(43) = \frac{31}{x} \\\\x = \frac{31}{sin(43)} = 45.45\)
#teamtrees #WAP (Water And Plant)
Berkeley Bowl Cherry Tomatoes (for Q6-7) Berkeley Bowl sells cherry tomatoes to local fast food restaurants. The diameter of a tomato is on average 26 mm, with a standard deviation of 3 mm. The upper and lower specifications limits that they are given are, respectively, 32 mm and 20 mm. Q6. What percentage of their tomatoes are within the specification limits? Q7. What should the standard deviation of their process be for their process to be half of the Six Sigma Quality?
Answers
Q6: Approximately 68.3% of the cherry tomatoes sold by Berkeley Bowl fall within the specified diameter limits of 20 mm to 32 mm.
Q7: To achieve half of the Six Sigma Quality, the standard deviation of the process should be approximately 0.22 mm for Berkeley Bowl's cherry tomatoes.
In Q6, we can use the concept of the normal distribution to determine the percentage of tomatoes within the specification limits. Since the average diameter is 26 mm and the standard deviation is 3 mm, we can assume a normal distribution and calculate the percentage of tomatoes within one standard deviation of the mean. This corresponds to approximately 68.3% of the tomatoes falling within the specified limits.
In Q7, achieving Six Sigma Quality means that the process has a very low defect rate. In this case, half of the Six Sigma Quality means reducing the variability in diameter to half the acceptable range.
The acceptable range is 32 mm - 20 mm = 12 mm. To achieve half the range, the standard deviation should be approximately half of 12 mm, which is 6 mm. Since the standard deviation is given as 3 mm, the process would need to be improved to reduce the standard deviation to approximately 0.22 mm for it to meet half of the Six Sigma Quality.
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Which represents the equation 6 x + 3 y = 12 when solved for y?
y = negative 2 x + 4
y = 2 x + 4
y = negative 2 x minus 4
y = 2 x minus 4
Answers
Answer:
y=(-x+2)
Step-by-step explanation:
6x+3y=12
6x+3y-6x=12-6x Subtracting 6x from both sides
3y=12-6x Simplifying
3y/3=12/3-6x/3 Divide both sides by 3
y=(-x+2) Simplifying
Answer:
the answer is C. y=2x+4
have a good day <3
remember to take care of yourself :)
Step-by-step explanation:
which property is illustrated for all expressions a and b if a=b then b=a
Answers
Answer:
Symmetric property
MARKING BRAINLEIST BUT PLS BE QUICK
Answers
Answer:
A. \(\frac{81m^{4} }{n{4} }\)
College Graduates Starting Salaries. According to the National Association of Colleges and Employers, the 2015 mean starting salary for new college graduates in health sciences was $51,541. The mean 2015 starting salary for new college graduates in business was $53,901 (National Association of Colleges and Employers website). Assume that starting salaries are normally distributed and that the standard deviation for starting salaries for new college graduates in health sciences is $11,000. Assume that the standard deviation for starting salaries for new college graduates in business is $15,000
Answers
The mean starting salary for new college graduates in health sciences was $51,541, and the mean starting salary for new college graduates in business was $53,901. (National Association of Colleges and Employers website).
Starting salaries for new college graduates in health sciences and business are normally distributed with standard deviations of $11,000 and $15,000, respectively.
In the context of salary distributions, the mean represents the average or central value of the salaries, while the standard deviation measures the variability or spread of the salaries around the mean.
It is important to note that the assumption of normal distribution allows us to make certain statistical inferences and calculations.
For example, we can estimate the proportion of graduates earning salaries within specific ranges, calculate the probability of earning a certain salary, or compare salaries between different groups.
The standard deviations of $11,000 and $15,000 indicate that there is more variability in starting salaries for new college graduates in business compared to health sciences.
This means that the salaries in the business field are more spread out, with a wider range of values, while the salaries in the health sciences field are relatively less variable and more tightly clustered around the mean.
Overall, these statistics provide valuable information about the starting salaries for college graduates in health sciences and business, allowing for comparisons and analysis of the salary distributions in these fields.
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6. In a basketball game, Anton made 5 shots in 7 tries. What is the ratio of the
number of tries to the number of shots he missed?
A. 7:2
B. 7:5
C. 5:7
D. 5:2
Answers
Answer:
A 7:2
Step-by-step explanation:
write down the value of 9 and a half?
Answers
The value of 9 and a half will be 9 1/2.
What is an expression?Expression simply refers to the mathematical statements which have at least two terms which are related by an operator and contain either numbers, variables, or both.
In this case, addition, subtraction, multiplication, and division are all possible mathematical operations. As an illustration, the expression x + y has the terms x and y with an addition operator between them.
Here, we want to find the value of 9 and half. This will be:
= 9 + 1/2
= 9 1/2
The value is 9 1/2.
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I WILL GIVE YOU BRAINLIEST,5 STARS, AND THANKS.(P.S. AT LEAST TWO PEOPLE GIVE ANSWER SO I CAN GIVE BRAINLIEST)
Answers
Answer:
A
Step-by-step explanation:
the other options have a common difference
Answer:
A is not arithmetic series
Step-by-step explanation:
In B,C and D there is arithmetic series as a2-a1=a3-a2
In A. there is no such series.....
Tlaloc pumped up 56 balls. He pumped up 5 dodge balls for every 9 other balls.
Answers
Answer:
What do you need from this question? Its not asking anything.
Step-by-step explanation:
who can help me please ?
Answers
*how do u do the explanation thingy*
the following table represents the number of tickets purchased at a movie theater and cost of purchase.
the number of tickets purchased varies directly with the total costs of the purchase. determine the constant variation
1) $24.00
2)$0.17
3)12.00
4)$6.00
Answers
Answer:
4)$6.00
Step-by-step explanation:
If you set up an equation you can plug in all of the answer choices and try to find which one will make the equation true. Try using the equation x(2)=12 or x(4)=24 or x(6)=36 or x(8)=48. Any of them will work if you just plug in $6.00 but you can also try the other answers to be sure.
Answer:
its D. $6.00
Step-by-step explanation:
Which expression is equivalent to sqrt10/4sqrt8
Answers
Answer:
i think it is the third one.
Step-by-step explanation:
Answer:
first choice: ⁴√200 / 2
Step-by-step explanation:
√10 / ⁴√8 = ((√10)*(⁴√2)) / ((⁴√2³)*(⁴√2))
= (⁴√100 * ⁴√2) / (⁴√2⁴)
= ⁴√200 / 2
What equations are associated with the different types of variation?
How do you know which to use?
Answers
Answer:
A
Step-by-step explanation:
David then withdrew that money and put it into another bank account with a rate of 5% interest compounded annually. How much money worth of interest did David gain after 4 years?
Answers
David gained approximately $2,155.06 in interest after 4 years.
How to solveBy utilizing the compound interest formula A = P(1 + r/n)^(nt), one can determine the future value of an investment or loan, inclusive of its added interest.
Variables to consider include the initial deposit (P), annual interest rate (r as a decimal), frequency at which it is compounded per year (n) and time (t).
This specific scenario assimilates a principal amount of $10,000 with an annual interest rate of 5% compounded yearly for four years, resulting in an accrued balance of roughly $12,155.06.
Therefore, David gained approximately $2,155.06 in interest after 4 years.
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If David deposited $10,000 into a bank account with a 5% interest rate compounded annually, how much interest did he gain after 4 years?
Solve for h.
-3/4 - h + 1/3h - 2 = -4/3h -3
Answers
Answer:
h = -3/8
Step-by-step explanation:
-3/4 - h + 1/3h - 2 = -4/3h -3
combine like terms
-2 = -8/4
-3 = -12/4
-2/3h - 11/4 = -4/3h -12/4
2/3h - 11/4 = -12/4
2/3h = -1/4
8/12h = -3/12
8h = -3
h = -3/8
If the variation in the process is due to common causes alone, the process is said to be:
Select one:
a. out of control.
b. in statistical control.
c. in pre-control.
d. out of capability.
Answers
If variation in a process results from common causes alone, the process is said to be in statistical control.
When talking about control charts, being in-control means your process is exhibiting common cause variation and is predictable.
Variation due to the inherent variability in a system of operation is called. special or assignable causes.
Industrial control systems are used by a discipline known as industrial process control in continuous manufacturing processes to produce at a level of consistency, economy, and safety that is impossible to achieve exclusively through manual human control. Process control systems make guarantee that industrial activities are carried out efficiently, dependably, and with as little fluctuation as is practical. They are installed in industrial settings to guarantee throughput, quality, yield, and energy efficiency. Ensure that work is done profitably and safely according to established procedures.
Therefore,
If variation in a process results from common causes alone, the process is said to be in statistical control.
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Nora loves to play the bridge builders video game, where players gain and lose points by building safe and unsafe bridges. in level 1, nora earned 16 points because her bridge passed inspection. then, she lost 25 points because part of her bridge collapsed! what was nora's score at the end of level 1?
Answers
Answer:
-9
Step-by-step explanation:
16-25=-9
Answer: -9
Step-by-step explanation:
It is assumed that approximately 15% of adults in the U.S. are left-handed. Consider the probability that among 100 adults selected in the U.S., there are at least 30 who are left-handed. Given that the adults surveyed were selected without replacement, can the probability be found by using the binomial probability formula with x counting the number who are left-handed? Who or why not?
Yes, because the 100 adults represent less than 5% of the U.S. adult population, the trials can be treated as independent.
Answers
Answer: -25
Step-by-step explanation:
If M=1,000,P=2.25, and Y=2,000, what is velocity? a. 2.25 b. 4.5 c. 2 d. None of the above is true
Answers
Answer:d
Step-by-step explanation:
The answer is d. None of the above is true.
To calculate velocity, we need to use the equation:
Velocity = M * P / Y
Given:
M = 1,000
P = 2.25
Y = 2,000
Plugging in the values:
Velocity = 1,000 * 2.25 / 2,000
Simplifying:
Velocity = 2.25 / 2
The result is:
Velocity = 1.125
Therefore, the correct answer is: d. None of the above is true.
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Jillian exercises 4 times a week she runs 2 miles each morning and bikes in the evening if she exercises a total of 28 miles for the week how many miles does she bike each evening
Answers
Answer:
5 miles
Step-by-step explanation:
Total miles Jillian runs in a week = 4 x 2 miles = 8 miles
Total miles she bikes each week = total miles in a week - total miles Jillian runs in a week
28 miles - 8 miles = 20 miles
Miles she bikes in a week =20/4 = 5 miles
Directions: Simplify the following by subtracting the exponents.
1. r6 __ r 2. s5t4 ____ s2t3 3. q2r2s ____ qrs 4. x3y6z _____ x2y2z 5. m7n3o _____ m2n2o 6. x4 ___ x 7. z3 ___ z5 8. a3b2 _____ ab2 9. d4f3 _____ df 10. mn2 _____ mn2 11. c5d6 ______ c4d3 12. b8c4d2 ________ b5c4d2 13. xy ___ xy 14. s2t4 _____ st 15. m2n2 ______ m4n4
Answers
Simplifying expressions with exponents involves applying these basic rules and being careful with the signs and operations involved.
r6 ÷ r = r6-1 = r5
s5t4 ÷ s2t3 = s5-2t4-3 = s3t
q2r2s ÷ qrs = q2-1r2-1s-1 = qr
x3y6z ÷ x2y2z = x3-2y6-2z-1 = xy4z-1
m7n3o ÷ m2n2o = m7-2n3-2o-1 = m5n1o-1 = m5o/n
x4 ÷ x = x4-1 = x3
z3 ÷ z5 = z3-5 = z-2
a3b2 ÷ ab2 = a3-1b2-2 = ab
d4f3 ÷ df = d4-1f3-1 = d3f2
mn2 ÷ mn2 = m1n2-2 = 1/n
c5d6 ÷ c4d3 = c5-4d6-3 = cd3
b8c4d2 ÷ b5c4d2 = b8-5c4-4d2-2 = b3d-2
xy ÷ xy = 1
s2t4 ÷ st = s2-1t4-1 = st3
m2n2 ÷ m4n4 = m2-4n2-4 = 1/m2n2
To simplify expressions of the form aⁿ ÷ aᵐ , we subtract the exponents and keep the base, a. If there are multiple bases with exponents, then we simplify each term separately. In some cases, we can also use rules of fractions or negative exponents to further simplify the expression.
It's important to note that whenever we divide two variables with the same base, we can subtract their exponents and write it as a single variable with the base raised to the difference between the exponents. If the variables have different bases, we cannot simplify them further.
Overall, simplifying expressions with exponents involves applying these basic rules and being careful with the signs and operations involved.
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two concentric circles have radii 11 and 22 two points on the outer circle are chosen independently and uniformly at random. what is the probability that the chord joining the two points intersects the inner circle?
Answers
Answer: Two concentric circles have radii $1$ and $2$. Two points on the outer circle are chosen independently and uniformly at random. What is the probability that the chord joining the two points intersects the inner circle?
$\textbf{(A)}\ \frac{1}{6}\qquad \textbf{(B)}\ \frac{1}{4}\qquad \textbf{(C)}\ \frac{2-\sqrt{2}}{2}\qquad \textbf{(D)}\ \frac{1}{3}\qquad \textbf{(E)}\ \frac{1}{2}\qquad$
Solution
Let the center of the two circles be $O$. Now pick an arbitrary point $A$ on the boundary of the circle with radius $2$. We want to find the range of possible places for the second point, $A'$, such that $AA'$ passes through the circle of radius $1$. To do this, first draw the tangents from $A$ to the circle of radius $1$. Let the intersection points of the tangents (when extended) with circle of radius $2$ be $B$ and $C$. Let $H$ be the foot of the altitude from $O$ to $\overline{BC}$. Then we have the following diagram.
[asy] scale(200); pair A,O,B,C,H; A = (0,1); O = (0,0); B = (-.866,-.5); C = (.866,-.5); H = (0, -.5); draw(A--C--cycle); draw(A--O--cycle); draw(O--C--cycle); draw(O--H,dashed+linewidth(.7)); draw(A--B--cycle); draw(B--C--cycle); draw(O--B--cycle); dot("$A$",A,N); dot("$O$",O,NW); dot("$B$",B,W); dot("$C$",C,E); dot("$H$",H,S); label("$2$",O--(-.7,-.385),N); label("$1$",O--H,E); draw(circle(O,.5)); draw(circle(O,1)); [/asy]
We want to find $\angle BOC$, as the range of desired points $A'$ is the set of points on minor arc $\overarc{BC}$. This is because $B$ and $C$ are part of the tangents, which "set the boundaries" for $A'$. Since $OH = 1$ and $OB = 2$ as shown in the diagram, $\triangle OHB$ is a $30-60-90$ triangle with $\angle BOH = 60^\circ$. Thus, $\angle BOC = 120^\circ$, and the probability $A'$ lies on the minor arc $\overarc{BC}$ is thus $\dfrac{120}{360} = \boxed{\textbf{(D)}\: \dfrac13}$.
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