There are 34 people on a bus.
21 people are getting off at the next stop.
Find the fraction of the people who are staying on the bus after the next stop.
Leave the fraction in its simplest form.

Answer: x = 18

Step-by-step explanation:

1) 100% - 54.5% = 45.5%.

2) 45.5/100 = 0.455.

3) 0.455 * X = 8.19g.

4) x = 8.19/0.455.

5) x = 18.

Answer:

(x-y)(x+y+z)

Step-by-step explanation:

\(x^{2} +xz-y^{2} -yz\\x^{2} -y^{2} +z(x-y)\\(x+y)(x-y)+z(x-y)\\(x-y)(x+y+z)\\\)

Answer:

(x - y)(x + y + z)

Step-by-step explanation:

Given

x(x + z) - y(y + z) ← distribute both parenthesis

= x² + xz - y² - yz ← rearrange

= x² - y² + xz - yz ← x² - y² can be factored as a difference of squares

= (x - y)(x + y) + z(x - y) ← factor out (x - y) from each term

=(x - y)(x + y + z)

The probability that a woman was wearing a belt given that she was also carrying a purse is 0.333 or 33.3%.

To find the probability that a woman was wearing a belt given that she was also carrying a purse, we need to use conditional probability.

We know that out of the 30 women observed, 18 were carrying purses and 6 were both carrying purses and wearing belts.

This means that the number of women carrying purses who were also wearing belts is 6.
Therefore, the probability that a woman was wearing a belt given that she was also carrying a purse is:
P(wearing a belt | carrying a purse) = number of women wearing a belt and carrying a purse / number of women carrying a purse
P(wearing a belt | carrying a purse) = 6 / 18
P(wearing a belt | carrying a purse) = 0.333
Given the information provided, we can determine the probability of a woman wearing a belt, given that she is also carrying a purse.

First, we need to find the number of women carrying a purse and wearing a belt, which is 6. There are 18 women carrying purses in total.
So, to find the probability, we will use the formula:
P(Belt | Purse) = (Number of women wearing belts and carrying purses) / (Number of women carrying purses)
P(Belt | Purse) = 6 / 18
P(Belt | Purse) = 1/3 or approximately 0.33
Therefore, the probability that a woman was wearing a belt, given that she was also carrying a purse, is 1/3 or approximately 0.33.

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I don't know I just need to answer this so I can get through the login-

Answer:

$408

Step-by-step explanation:

To determine the distance between two points in a rectangular coordinate system, we can use the distance formula. Given the coordinates of the points (4.8, 2.5) and (-3.2, 5.0), we can calculate the distance as follows:

Distance = √((x2 - x1)^2 + (y2 - y1)^2)

Plugging in the values, we get:

Distance = √((-3.2 - 4.8)^2 + (5.0 - 2.5)^2)

Simplifying further:

Distance = √((-8)^2 + (2.5)^2)

Distance = √(64 + 6.25)

Distance = √70.25

Distance ≈ 8.38 centimeters

Therefore, the distance between the points (4.8, 2.5) and (-3.2, 5.0) is approximately 8.38 centimeters.

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Step-by-step explanation:

Take two empty ice cream cups. Make a small hole at the bottom of each cup and pass a long thread through them. Tie a knot or match stick at each end of the thread so that the thread does not slip out through the holes. ... Thus, sound can travel through a solid

Answer:

The hyperbola has a vertical transverse axis of length 9 units and a central rectangle with dimensions 9 units by 4 units. Equation of hyperbola is \((x^2 / 20.25) - (y^2 / 4)\) = 1

To find the equation of a hyperbola with a vertical transverse axis and center at (0,0), we need to determine the values of the constants in the general equation. Given that the central rectangle is 9 units by 4 units, we can use this information to find the values we need.

The equation of a hyperbola with a vertical transverse axis and center at (0,0) has the form:

\((x^2 / a^2) - (y^2 / b^2)\) = 1

where 'a' is the distance from the center to each vertex along the transverse axis, and 'b' is the distance from the center to each vertex along the conjugate axis.

In this case, the transverse axis has a length of 9 units, which means the distance from the center to each vertex along the transverse axis is half of that, so a = 9/2 = 4.5 units.

The central rectangle has a width of 9 units, which is equal to 2a, so we can find 'b' using this information. Since the conjugate axis is perpendicular to the transverse axis, the distance from the center to each vertex along the conjugate axis is half of the width of the central rectangle, so b = 4/2 = 2 units.

Now we have the values of 'a' and 'b', so we can plug them into the equation to obtain the final equation of the hyperbola:

\((x^2 / (4.5^2)) - (y^2 / 2^2)\) = 1

Simplifying, we get:

\((x^2 / 20.25) - (y^2 / 4)\) = 1

Therefore, the equation of the hyperbola with a vertical transverse axis and center at (0,0), based on the given information, is:

\((x^2 / 20.25) - (y^2 / 4)\) = 1

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The degrees of freedom for a chi-square goodness-of-fit test are calculated as the number of categories minus 1.

Suppose we wish to determine if an ordinary-looking six-sided die is fair, or balanced, meaning that each face has a probability of 1/6

of arrival on top when the die is tossed. We could toss the die dozens, maybe hundreds, of times and compare the actual number of times each face arrival on top to the scheduled number, which would be 1/6

of the total number of tosses. We would not expect each number to be exactly 1/6 of the total, but it should be close.

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Answer:

$1718.22

Explanation:

For interest compounded continuously, we can use the following equation:

Where A is the amount after t years, P is the principal and r is the interest rate.

So, replacing A = $2500, r = 5% = 0.05, and t = 7.5 years, we get:

Now, we need to solve for P, so

Therefore, the principal is $1718.22

The Bayesian odds of QA to QS given that a bug was found is 0.22:1.

Let P(Ar) and P(St) be the proportions of biomes sent to Arstotzka and Stardew respectively, which is 0.32 and 0.68 respectively.

Let P(bug|QA) and P(bug|QS) be the probabilities of finding a bug given that a biome was sent to QA and QS respectively, which is 0.13 and 0.55 respectively.

The probability of finding a bug is given by:P(bug) = P(bug|QA) × P(QA) + P(bug|QS) × P(QS)

Substituting the values, we get:P(bug) = 0.13 × 0.32 + 0.55 × 0.68= 0.4164

Let A be the event that a biome was sent to Arstotzka, and B be the event that a bug was found.

Then, we need to find the Bayesian odds of QA to QS given that a bug was found, which is given by:

Bayesian odds = (P(A|B) / P(St|B)) × (1 - P(A) / P(St))

Substituting the values, we get:

Bayesian odds = (P(B|A) × P(A) / P(B|St) × P(St)) × (1 - P(A) / P(St))P(B|A) = P(A ∩ B) / P(A) = P(B|A) × P(A) / P(bug) = (0.13 × 0.32) / 0.4164 = 0.0998

P(B|St) = P(St ∩ B) / P(St) = P(B|St) × P(St) / P(bug) = (0.55 × 0.68) / 0.4164 = 0.9022

P(A|B) = P(B|A) × P(A) / P(B) = (0.13 × 0.32) / 0.4164 = 0.0998 / 0.4164 = 0.2398

P(St|B) = P(B|St) × P(St) / P(B) = (0.55 × 0.68) / 0.4164 = 0.9022 / 0.4164 = 2.1688

Bayesian odds = (P(A|B) / P(St|B)) × (1 - P(A) / P(St))= (0.2398 / 2.1688) × (1 - 0.32 / 0.68)= 0.22:1

Therefore, the Bayesian odds of QA to QS given that a bug was found is 0.22:1.

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the exact values of the six trigonometric functions of the angle are:

sin(theta) = 3/5
cos(theta) = 4/5
tan(theta) = 3/4
csc(theta) = 5/3
sec(theta) = 5/4
cot(theta) = 4/3

We can determine the exact values of the six trigonometric functions of the angle using the coordinates of the point (4,3) on the terminal side of the angle.

First, we can find the distance r from the origin to the point (4,3) using the Pythagorean theorem:

r = sqrt(4^2 + 3^2) = 5

Next, we can use the coordinates of the point (4,3) to determine the sign of the x and y coordinates. Since the x coordinate is positive and the y coordinate is positive, we know that the angle is in the first quadrant.

Using the definitions of the six trigonometric functions, we can now determine their exact values:

sin(theta) = y/r = 3/5
cos(theta) = x/r = 4/5
tan(theta) = y/x = 3/4
csc(theta) = r/y = 5/3
sec(theta) = r/x = 5/4
cot(theta) = x/y = 4/3

Therefore, the exact values of the six trigonometric functions of the angle are:

sin(theta) = 3/5
cos(theta) = 4/5
tan(theta) = 3/4
csc(theta) = 5/3
sec(theta) = 5/4
cot(theta) = 4/3
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If 29% of foreign visitors to the U.S. were from Canada in 2000, we can assume that 29% of the 150000 foreign guests at the hotel were also from Canada. To find out how many guests that would be, we can multiply 150000 by 0.29 (which is the decimal form of 29%).

This gives us a predicted number of 43,500 guests from Canada.
In 2000, about 29% of foreign visitors to the U.S. were from Canada. If a particular hotel had 150,000 foreign guests in one year, to predict how many were from Canada, you would multiply the total number of foreign guests by the percentage of visitors from Canada.

In this case, 150,000 guests * 0.29 (29%) equals 43,500. Therefore, you would predict that approximately 43,500 guests at the hotel were from Canada.

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The percent of total monthly net income for the monthly living expenses and fixed expenses is 60%, the monthly share of annual expenses is $3,000 and the total your three percents is 120%.

A challenge problem is a task or question that requires a significant amount of thought, analysis, and problem-solving skills to solve. It often involves complex scenarios, calculations, or decision-making processes, and may require the use of multiple skills or disciplines to arrive at a solution.

To calculate the percentage of the Penders' total monthly net income that goes towards monthly living expenses and fixed expenses, we need to know the actual amounts of their monthly living and fixed expenses, as well as their total monthly net income. Let's assume that the Penders have a total monthly net income of $5,000, and their monthly living expenses and fixed expenses add up to $3,000.

The percentage of their total monthly net income that goes towards monthly living expenses and fixed expenses can be calculated as follows:

$3,000 (monthly living expenses and fixed expenses) ÷ $5,000 (total monthly net income) x 100% = 60%

Therefore, 60% of the Penders' total monthly net income goes towards monthly living expenses and fixed expenses.

To calculate the monthly share of annual expenses, we need to know the total amount of their annual expenses. Let's assume that their annual expenses add up to $36,000. The monthly share of their annual expenses can be calculated as follows:

$36,000 (annual expenses) ÷ 12 (number of months in a year) = $3,000 (monthly share of annual expenses)

To total the three percents, we add the percentage of their total monthly net income that goes towards monthly living expenses and fixed expenses (60%) to the percentage of their monthly share of annual expenses (which is also 60%, since $3,000 is 60% of $5,000). This gives us a total of 120%.

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Answer:

The market equilibrium price is approximately $36.43 per barrel.

Step-by-step explanation:

To find the market equilibrium price, we need to set the quantity supplied (QS) equal to the quantity demanded (QD) and solve for the price (P).

Given:

QS = -250 + 7P

QD = 260 - 7P

Setting QS equal to QD:

-250 + 7P = 260 - 7P

Now, let's solve for P:

Add 7P to both sides:

-250 + 7P + 7P = 260 - 7P + 7P

Combine like terms:

14P - 250 = 260

Add 250 to both sides:

14P - 250 + 250 = 260 + 250

Simplify:

14P = 510

Divide both sides by 14:

14P/14 = 510/14

Simplify:

P = 36.43

The market equilibrium price can be found by setting the quantity supplied (QS) equal to the quantity demanded (QD) and solving for the price (P) that satisfies this condition.

In the given scenario, the supply function is QS = -250 + 7P, and the demand function is QD = 260 - 7P. To find the equilibrium price, we set QS equal to QD:

-250 + 7P = 260 - 7P

Simplifying the equation, we get:

14P = 510

Dividing both sides by 14, we find:

P = 36.43

Therefore, the market equilibrium price is approximately $36.43 per barrel. At this price, the quantity supplied and quantity demanded will be equal, resulting in a state of equilibrium in the perfectly competitive domestic crude oil market.

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Answer:

38 kids on each team about.

I am Not 100% sure but I hope this Helps!

So D.

Model is same shape as original with scale factor 2:9.

Ratio of

a. Surface area of model and original is 4:81.

b. Height of model and original is 2:9.

c. Volume of model and original is 8:243.

As given,

Scale factor (a: b)=2:9

Ratio of model and original for

a. Surface area =a²: b²

                         =4:81

b. Height=a :b

              =2:9

c. Volume=a³ :b³

                =8:243

Therefore, model is same shape as original with scale factor 2:9.

Ratio of model and original for

a. Surface area is 4:81.

b. Height  is 2:9.

c. Volume is 8:243.

The complete question is :

A designer builds a model of a canoe. the finished model is exactly the same shape as the original, but smaller. the scale factor is 2:9.

(a) find the ratio of the surface area of the model to the surface area of the original. (b) find the ratio of the height of the model to the height of the original. (c) find the ratio of the volume of the model to the volume of the original.

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The probability that a standard normal random variable, Z, is between -1.65 and 1.82 can be found by subtracting the cumulative probability at -1.65 from the cumulative probability at 1.82.

To find the cumulative probability, you can use a standard normal distribution table or a calculator. The cumulative probability at -1.65 is 0.0495, and the cumulative probability at 1.82 is 0.9656.

So, the probability that Z is between -1.65 and 1.82 is 0.9656 - 0.0495 = 0.9161.

In other words, the probability of Z being between -1.65 and 1.82 is approximately 0.9161.

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Answer:

4

Step-by-step explanation:

9 divided by 36

Answer:

4 words/minute

Step-by-step explanation:

Since we need words per minute, we divide the number of words by the number of minutes.

words/minute = (36 words)/(9 minutes) = 4 words/minute

Answer: the perimeter of the polygon is 29cm

Step-by-step explanation:

Answer:

here you go

Step-by-step explanation:

The percent of change from 8,000 to 6,000 can be calculated using the formula:

�������;�ℎ����=���;�����−���;��������;�����×100Percent;change=Old;ValueNew;Value−Old;Value×100

Substituting the given values, we get:

�������;�ℎ����=6,000−8,0008,000×100Percent;change=8,0006,000−8,000×100

Therefore, there is a decrease of 20% from 8,000 to 6,000.

Answer:  decreases 6000 to 8000 = 33.33

x-    

6000−50005000×100 = 20%

Step-by-step explanation:hope that helps have a great day and stay safe (;

a) The random process of a constant T and the random X(t) stationary zero-mean process is E[Y(t)] = 0, b) autocovariance of Y(t) is R YY (t1, t2) = R XX (t1 - t2 + T) - R XX (t1 - t2 - T), c) Y(t) is wide-sense stationary.

(a) To find the value of E[Y(t)]:

The given random process is Y(t) = X(t + T) - X(t - T)

The mean of this random process is,

Therefore,E[Y(t)] = E[X(t + T) - X(t - T)] = E[X(t + T)] - E[X(t - T)]

Since X(t) is a stationary zero-mean process,

E[X(t + T)] = E[X(t - T)] = 0

Hence, E[Y(t)] = 0

(b) To find R YY (t1, t2) in terms of RXX (τ)

The autocovariance of Y(t) is R YY (t1, t2) = E[Y(t1)Y(t2)]

The autocovariance of Y(t) can be expressed as R YY (t1, t2) = E[[X(t1 + T) - X(t1 - T)][X(t2 + T) - X(t2 - T)]]

Expanding the above expression,

We have,

R YY (t1, t2) = E[X(t1 + T)X(t2 + T)] - E[X(t1 + T)X(t2 - T)] - E[X(t1 - T)X(t2 + T)] + E[X(t1 - T)X(t2 - T)]

This is equal to R YY (τ) = R XX (τ + T) - R XX (τ - T)

Therefore, in terms of RXX(τ),

                                     R YY (t1, t2) = R XX (t1 - t2 + T) - R XX (t1 - t2 - T)

(c) Is the random process Y(t) wide-sense stationary? Why?

The mean of Y(t) is E[Y(t)] = 0 (found in (a)).

To show that the process is wide-sense stationary, we have to show that R YY (t1, t2) depends only on the time difference (t1 - t2).

Substituting the expression for R YY (t1, t2) from (b),

We have, R YY (t1, t2) = R XX (t1 - t2 + T) - R XX (t1 - t2 - T)

As R XX (τ) is a function of τ = t1 - t2, R YY (t1, t2) is a function of t1 - t2.

Hence, Y(t) is wide-sense stationary.

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Answer:

270 per year so 6 years is 1620 and add that with 6000=7620

Ms. Yamagata needs to buy at least 2628 6-inch tiles to cover the floor of her rectangular bathroom.

To determine the least number of 6-inch tiles Ms. Yamagata needs to buy to cover her 9 feet long and 73 feet wide bathroom floor, follow these steps:

1. Convert the dimensions of the bathroom to inches, as the tiles are measured in inches:
  9 feet * 12 inches/foot = 108 inches long
  73 feet * 12 inches/foot = 876 inches wide

2. Determine the total area of the bathroom in square inches:
  Area = length * width = 108 inches * 876 inches = 94,608 square inches

3. Calculate the area of a single 6-inch tile:
  Area = length * width = 6 inches * 6 inches = 36 square inches

4. Divide the total area of the bathroom by the area of a single tile to find the least number of tiles needed:
  Number of tiles = total area / tile area = 94,608 square inches / 36 square inches ≈ 2,628.56

Since Ms. Yamagata cannot buy a fraction of a tile, she needs to buy at least 2,629 6-inch tiles to cover her bathroom floor.

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THE ANSWER IS

?????

36

Answer:

Step-by-step explanation:

METHOD 1:

\(\begin{array}{ccc}27&-&75\%\\\\x&-&100\%\end{array}\qquad|\text{cross multiply}\)

\((75)(x)=(27)(100)\\\\75x=2700\qquad|\text{divide both sides by 75}\\\\x=36\)

METHOD 2:

\(n\)-a number

\(p\%=\dfrac{p}{100}\\\\75\%=\dfrac{75}{100}=0.75\)

75% of a number is 27:

\(0.75\cdot n=27\qquad|\text{divide both sides by 0.75}\\\\n=36\)

Question 1-

To determine which two points would a line of fit go through to best fit the data on the scatter plot, we need to visually analyze the pattern of the data points and choose two points that the line would pass through to represent the overall trend.

Without the actual scatter plot provided, I am unable to directly analyze it. However, based on the given answer choices:

A. (1,9) and (9,5)

B. (1,9) and (5,7)

C. (2,7) and (4,3)

D. (2,7) and (6,5)

Since I don't have the scatter plot, I cannot accurately determine which points would best fit the data. I would recommend carefully reviewing the scatter plot and selecting the two points that seem to represent the general trend or pattern of the data. The two points that form a line that closely follows the general direction of the data points would be the best choices.

Question 2-

To determine the slope of the relationship between the number of hours Laila danced, x, and the money she raised, y, we need to examine the graph and calculate the slope using the formula:

Slope = (change in y) / (change in x)

However, since the graph is not provided, it is not possible to directly calculate the slope. However, we can still evaluate the given answer choices based on their explanations:

A. The slope is 1/4, which means that the amount the student raised increases by $0.75 each hour.

B. The slope is 4, which means that the amount the student raised increases by $4 each hour.

C. The slope is 12, which means that the student will finish raising money after 12 hours.

D. The slope is 20, which means that the student started with $20.

From the explanations provided, it seems that option B would be the most reasonable choice. A slope of 4 would indicate that for each additional hour Laila danced, she raised $4. However, without the actual graph, it is challenging to confirm the accuracy of the answer choice or its real-world interpretation.

Certainly, there is a significant difference in the mean amount of e.coli bacteria detected by the two methods for this type of beef. This can be supported statistically by conducting a hypothesis test.

           The null hypothesis (\(H_0\)) is that there is no significant difference in the mean amount of E. coli bacteria detected by the two methods. The alternative hypothesis (\(H_a\)) is that there is a significant difference in the mean amount of e.coli bacteria detected by the two methods.

          The two-sample t-test can be used to test the hypothesis. The t-test compares the means of two independent groups and determines whether they are significantly different. The t-test assumes that the two samples are normally distributed and have equal variances.

          If the sample sizes are large, then the t-test can still be used even if the samples are not normally distributed.

          The formula for the t-test is:

                   \(t = (x_1 - x_2) / [s^2(1/n_1 + 1/n_2)]\)

       Where:

                     \(x_1\) = the sample mean for method 1

                     \(x_2\) = the sample mean for method 2

                     \(s^2\) = the pooled variance of the two samples

                     \(n_1\) = the sample size for method 1

                     \(n_2\) = the sample size for method 2

        The t-value can then be compared to the critical value of  \(t\) for the desired level of significance (usually 0.05).

         If the t-value is greater than the critical value of \(t\), then the null hypothesis can be rejected and it can be concluded that there is a significant difference in the mean amount of E. coli bacteria detected by the two methods.

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Answer:

F

Step-by-step explanation:

La respuesta es f porque la tasa vigente en el lado x es por 2 y la tasa vigente en el lado y es por 12.

A 95% confidence interval for percent of american adults who believe in aliens:  (0.6578, 0.7822)

In this question we have been given that in a survey conducted on an srs of 200 american adults, 72% of them said they believed in aliens

We need to find the 95% confidence interval for percent of american adults who believe in aliens.

95% confidence interval = (p ± z√[p(1 - p)/n])

Here, n = 200

p = 72%

p = 0.72

And the z-score for 95% confidence interval is 1.960

The upper limit of interval would be,

(p + z√[p(1 - p)/n])

= 0.72 + 1.960 √[0.72(1 - 0.72)/200]

= 0.72 + 1.960 √[(0.72 * 0.28)/200]

= 0.72 + 1.960 √0.001008

= 0.72 + 0.0622

= 0.7822

The lower limit of interval would be,

(p - z√[p(1 - p)/n])

= 0.72 - 1.960 √[0.72(1 - 0.72)/200]

= 0.72 - 1.960 √[(0.72 * 0.28)/200]

= 0.72 - 1.960 √0.001008

= 0.72 - 0.0622

= 0.6578

Therefore, a 95% confidence interval = (0.6578, 0.7822)

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