The ratio of the measures of the angles of a quadrilateral is 2: 4: 6: 3 . Find the measures of the angles of the quadrilateral.

Answers

Answer 1

Answer:

48º, 96º, 144º and 72º respectively

Step-by-step explanation:


Related Questions

Find the equation of a line that passes through the points (3,2) and (5,6). Leave your answer in the form y = m x + c.

Answers

The equation of the line that passes through the points (3,2) and (5,6) is: y = 2x - 4

Given:

we have two points:

(3,2) and (5,6)

we are asked to find the equation of a line that passes through the points (3,2) and (5,6).

let the two points be:

(3,2) = (x₁,y₁)

(5,6) = (x₂,y₂)

we know the point slope form as:

y - y₁ = m(x-x₁)

to find slope:

m = y₂-y₁/x₂-x₁

m = 6-2/5-3

m = 4/2

m = 2

now take the point as :

y - 2 = 2(x-3)

y - 2 = 2x-6

y = 2x - 6 + 2

y = 2x - 4

Hence we get the equation of the line as y = 2x - 4.

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Jim Tree sells trees. The mean length of the trees purchased was 68 inches with a standard deviation of 10 inches. Jim wants to know what percent of his sales were more than 84 inches tall. He can use the standard normal distribution to help him.

Answers

Answer:

Follows are the solution to this question:

Step-by-step explanation:

Given value:

\(\to X = 84\\\\\to \mu = 68\\\\\to \sigma= 10\\\\\)

Using formula:

\(\bold{Z= \frac{X-\mu}{\sigma}}\)

    \(= \frac{84-68}{10}\\\\ = \frac{16}{10}\\\\=1.6\)

Calculating the percent of the sales which is less than or equal to 84 inches:

\(\to P(Z \leq 1.6)=0.9452\)

                      \(= 0.9452 \times 100\\\\ =94.52\% \approx 95.5\%\)

Calculating the remaining value \(100-94.5=5.5\%\) were more than 84 inches.

The sum of two rational numbers will always be

1) an irrational number

2) an integer

3) a rational number

4) a whole number

Answers

Answer:

3

Step-by-step explanation:

Adding two rationals is the same as adding two fractions, which will result in another fraction of this same form since integers are closed under addition and multiplication. So, adding two rational numbers produces another rational number.

Help pls!! Which would not be an enlargement or reduction of the letter below?

Help pls!! Which would not be an enlargement or reduction of the letter below?

Answers

Answer:

I would think J because they gained the same amount

,,,,,,,,,,,,,,,,,,,,,,,

,,,,,,,,,,,,,,,,,,,,,,,

Answers

Answer:

30

80-50

Step-by-step explanation:

Rectangle ABCD has verticies A(1, 2) B(4, 2) C(1, -2) and D(4, -2). A dialation with a scale factor of 6 and centered at the origin is applied to the rectangle. Which vertex in the dilated image has coordinates of (24, 12)
A’
B’
C’
D’

Answers

Answer:

  B’

Step-by-step explanation:

You want to know the vertex that has coordinates (24, 12) after dilation by a factor of 6 about the origin.

Dilation

When the center of dilation is the origin, the scale factor multiplies each coordinate value. Then the coordinates of the original point whose dilated location is (24, 12) is ...

  6(x, y) = (24, 12)

  (x, y) = (24, 12)/6 = (24/6, 12/6) = (4, 2) . . . . . . matches point B

The image point is B'.

Given v =(-12,-4), what are the magnitude and direction of v? Round the magnitude to the thousandths place and the direction to the nearest degree.
11.314; 18°
11.314; 198°
12.649; 18°
12.649, 198°

Answers

Step-by-step explanation:

Magnitude = sqrt ( (-12)^2 + (-4)^2 ) = sqrt 160 = 12.649

Angle = arctan(-4/-12) = 198 degrees

The Magnitude: 12.649 and Direction: 18° (option c).

To find the magnitude and direction of the vector v = (-12, -4), we can use the following formulas:

Magnitude (or magnitude) of v = |v| = √(vₓ² + \(v_y\)²)

Direction (or angle) of v = θ = arctan(\(v_y\) / vₓ)

where vₓ is the x-component of the vector and \(v_y\) is the y-component of the vector.

Let's calculate:

Magnitude of v = √((-12)² + (-4)²) = √(144 + 16) = √160 ≈ 12.649 (rounded to the thousandths place)

Direction of v = arctan((-4) / (-12)) = arctan(1/3) ≈ 18.435°

Since we need to round the direction to the nearest degree, the direction is approximately 18°.

So, the correct answer is:

Magnitude: 12.649 (rounded to the thousandths place)

Direction: 18° (rounded to the nearest degree)

The correct option is: 12.649; 18°

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Bonnie has a new beaded necklace. 12 out of the 48 beads on the necklace are blue. What percentage of beads on Bonnie's necklace are blue?

Write your answer using a percent sign (%).

Answers

25% of the beads are blue
25% of the beads are blue.

X+2-9x is an example of an____
expression

Answers

Isn’t it an algebraic expression?

To study this, you administer to your subjects a drink that is equivalent to three 12-ounce beers, followed by the equivalent of two cups of coffee. You then have your subjects complete a simulated driving task in which the drivers must follow a fixed speed limit while driving on a straight road. Wind periodically and randomly pushes the simulated vehicle right, left, or not at all. Motor control is measured in terms of the number of feet the car moves from the center of the driving lane, with 1 foot being the smallest unit on the scale.


Suppose the first subject scores 15 feet. Determine the real limits of 15.


a. The lower real limit is: ____________

b. The upper real limit is: __________

Answers

a. The lower real limit is 14.5.
b. The upper real limit is 15.5.


The formula for calculating real limits is Real Limit = Raw Score ± 0.5. The real limits can be used to determine if an individual's score is significantly different from the population mean. The real limits are computed to ensure that the distribution is symmetrical about the mean.  

In this case, the first subject's raw score is 15 feet. Therefore, the lower real limit is 14.5 (15 - 0.5), and the upper real limit is 15.5 (15 + 0.5). The score of 15 feet is considered normal if it falls between the real limits. However, if it falls outside of the real limits, it is considered significantly different from the population mean. Thus, the real limits are essential for analyzing the scores obtained in this study.

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in his study of the teams of "hotshots" who fight grass and forest fires, researcher matt desmond became a firefighter. this is an example of what type of research?

Answers

Participant observation research is a type of qualitative research where the researcher takes an active part in the activities of the people they are studying. In this case, Matt Desmond became a firefighter to better understand the teams of "hotshots" he was studying.

Participant observation research is a type of qualitative research where the researcher takes an active part in the activities of the people they are studying. This involves the researcher joining the group they are studying and taking part in their activities, such as conversations, rituals, and other activities. This allows the researcher to gain a more detailed and in-depth understanding of the group they are studying, as they can observe how they interact in their natural environment. In this case, Matt Desmond became a firefighter to better understand the teams of "hotshots" he was studying. By taking part in their activities, he was able to gain a better understanding of their culture, and the dynamics of working on a firefighting team. He was able to observe the team's behavior and reactions in a way that would not have been possible if he had not been part of the team. By taking part in the activities of the team, he was able to gain a more detailed and accurate picture of the team.

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Scientists were monitoring the temperature of a solution. It began at 63°F, and the temperature changed by 8°F over the course of 6 hours. Use this information to complete this statement. The final temperature of the solution was a minimum of °F and a maximum of °F.

Answers

Answer:

minimum = 55 F

Maximum = 71 F

Step-by-step explanation:

Change means it could either go down or up.

If it goes down by 8 then 63-8 = 55 F

If it goes up by 8 then 63 + 8 = 71 F

Hope this helps!

Answer:

Step-by-step explanation:

minimum 55

maximum 71

Monica wants to tie a ribbon around the trunk of an oak tree that has a circular trunk about 20 inches in diameter. not counting the ribbon needed to make a bow, about how many inches of ribbon are needed to just to reach around the tree? (round to the nearest inch)

Answers

If Monica wants to tie a ribbon around the trunk of Oak tree having diameter 20 inches , then the length of ribbon needed is 62.8 inches .

the diameter of the Oak tree that Monica tie a ribbon is = 20 inches ,

So , the radius of the Oak tree = 20/2 = 10 inches ,

the length of the ribbon that is needed to round the tree is the circumference of the circle ,

which is calculated as = 2πr ;

substituting the values of radius ,

we get ;

length = 2 × 3.14 × 10

= 62.8 inches .

Therefore , 62.8 inches of ribbon is required to reach around tree.

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please help me to solve this ​

please help me to solve this

Answers

5) all you have to do is calculate which would be 2.9166...
6) 65.898

Answer:

For 5

\( \frac{35}{12} \)

simplified

\( 2\frac{11}{12} \)

Step-by-step explanation:

Turn the mixed numbers into improper fractions, and turn two into a fraction

\( \frac{11}{3} + \frac{5}{4} - \frac{2}{1} \)

Then find the common denominator of all fractions

\( \frac{44}{12} + \frac{15}{12} - \frac{24}{12} \)

then do the expression

\( \frac{44}{12} + \frac{15}{12} \)

\( \frac{59}{12} - \frac{24}{12} \)

\( \frac{35}{12} \)

simplify

\( 2 \frac{11}{12} \)

write the slope intercept form of the equation of each line through the given points (4,-2) and (-5,3)

Answers

Answer + Explanation is in the photo attached
write the slope intercept form of the equation of each line through the given points (4,-2) and (-5,3)

The temps tire at 10 p.m in Michigan on January 2nd was -4.4 degrees . By 6am the next morning it had dropped 7.2 degrees . By 10am the temp afire rose 8.5 degrees . What was the temps tire at 10am that day?

Answers

Answer:

-3.1

Step-by-step explanation:

4.4+7.2= -11.6 -11.6-8.5= -3.1

Give the differential equation that has y=C1 sin(4x+C2) as its general solution. a) y'- 16y=0 b) y'-4y=0
c) y''-8y'+16y=0 d) y''+ 16y=0 e) y''- 16y = 0 f)None of the above.

Answers

The differential equation that has y=C1 sin(4x+C2) as its general solution is d) y''+ 16y=0.

Determine the differential equation,

To find the differential equation, we need to take the derivative of the general solution twice.

The first derivative of the general solution is:

y' = C1*4*cos(4x+C2)

The second derivative of the general solution is:

y'' = -C1*16*sin(4x+C2)

Substituting the general solution back into the second derivative gives us:

y'' = -16y

Rearranging the equation gives us the differential equation:

y''+ 16y=0

Therefore, the correct answer is d) y''+ 16y=0.

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Customers arrive (randomly) to a ticket window at 5 per minute, and service takes 10 seconds (deterministic), therefore the model is model is M/D/1 . Predict the average number of waiting on the queue(Lq). (round your answer with two decimal points)

Answers

Therefore, the average number of customers waiting in the queue (Lq) is approximately 4.17.

To predict the average number of customers waiting in the queue (Lq) in an M/D/1 queuing model, we can use Little's Law, which states that Lq = λ * Wq, where λ is the arrival rate and Wq is the average time a customer spends waiting in the queue.

In this case:

Arrival rate (λ) = 5 customers per minute

Service time (D) = 10 seconds = 10/60 = 1/6 minutes

To calculate the average time a customer spends waiting in the queue (Wq), we need to use the formula Wq = Ls / λ, where Ls is the average number of customers in the system.

In an M/D/1 queuing model, Ls can be calculated using the formula Ls = (λ²) / (μ * (μ - λ)), where μ is the service rate.

Since the service time is deterministic and given by D = 1/6 minutes, the service rate (μ) is the reciprocal of the service time: μ = 1/D = 6 customers per minute.

Now we can calculate Ls:

Ls = (λ²) / (μ * (μ - λ))

= (5²) / (6 * (6 - 5))

= 25 / 6

≈ 4.17

Finally, we can calculate Lq:

Lq = λ * Wq

= λ * (Ls / λ)

= Ls

≈ 4.17

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Consider the following initial value problem, in which an input of large amplitude and short duration has been idealized as a delta function. y′′+16π2y=4πδ(t−4)a) Find the Laplace transform of the solution.

Answers

The required answer is: Y(s) = (4πe^(-4s) + sy(0) + y′(0)) / (s² + 16π²)

To find the Laplace transform of the solution, we first need to solve the differential equation y′′+16π2y=4πδ(t−4) with the initial conditions. Using the Laplace transform, we have:

s^2 Y(s) - s y(0) - y'(0) + 16π^2 Y(s) = 4π e^(-4s)

Applying the initial conditions y(0) = y'(0) = 0, we have:

s^2 Y(s) + 16π^2 Y(s) = 4π e^(-4s)

Factoring out Y(s), we get:

Y(s) = (4π e^(-4s)) / (s^2 + 16π^2)

Now, we can use partial fraction decomposition to simplify the expression. We can write:

Y(s) = A/(s+4π) + B/(s-4π)

Solving for A and B, we get:

A = (4π e^(-16π)) / (8π) = (1/2) e^(-16π)

B = (-4π e^(16π)) / (-8π) = (1/2) e^(16π)

Therefore, the Laplace transform of the solution is:

Y(s) = (1/2) e^(-16π) / (s+4π) + (1/2) e^(16π) / (s-4π)
To find the Laplace transform of the solution for the given initial value problem:

y′′ + 16π²y = 4πδ(t - 4)

Step 1: Take the Laplace transform of both sides of the equation.

L{y′′ + 16π²y} = L{4πδ(t - 4)}

Step 2: Apply the linearity property of Laplace transform.

L{y′′} + 16π²L{y} = 4πL{δ(t - 4)}

Step 3: Use Laplace transform formulas for derivatives and delta function.

s²Y(s) - sy(0) - y′(0) + 16π²Y(s) = 4πe^(-4s)

Since the initial conditions are not provided, let's keep y(0) and y'(0) in the equation.

Step 4: Combine terms with Y(s).

Y(s)(s² + 16π²) = 4πe^(-4s) + sy(0) + y′(0)

Step 5: Solve for Y(s), the Laplace transform of the solution y(t).

Y(s) = (4πe^(-4s) + sy(0) + y′(0)) / (s² + 16π²)

This is the Laplace transform of the solution to the given initial value problem.

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find the average value of f over the given rectangle. f(x, y) = 5ey x + ey , r = [0, 6] ⨯ [0, 1]

Answers

The average value of f over the rectangle [0,6] x [0,1] is approximately 3.427.

The average value of a function f over a rectangle R is given by:

avg(f) = (1/Area(R)) * double integral of f over R

Here, f(x,y) = 5e^(yx) + e^y and R = [0,6] x [0,1]

The area of R is given by:

Area(R) = (6 - 0) * (1 - 0) = 6

So, the average value of f over R is:

avg(f) = (1/6) * double integral of f over R

We can evaluate the double integral using iterated integration. First, we integrate f with respect to y from 0 to 1, and then integrate the result with respect to x from 0 to 6:

integral of f(x,y) dy = integral of (5e^(yx) + e^y) dy

= (5x/2)e^(yx) + e^y + C

where C is the constant of integration.

Now, we integrate this result with respect to x from 0 to 6:

integral of [(5x/2)e^(yx) + e^y] dx = [(5/2) * integral of xe^(yx) dx] + integral of e^y dx

= [(5/2) * (1/y)e^(yx) - (5/2)(1/y^2)(e^(yx) - 1)] + ey + C

where C is another constant of integration.

Therefore, the average value of f over R is:

avg(f) = (1/6) * [(5/2) * (1/y)e^(yx) - (5/2)(1/y^2)(e^(yx) - 1) + ey] evaluated from y=0 to y=1 and x=0 to x=6

avg(f) = (1/6) * [(5/2) * (1/e^6 - 1) - (5/2)(1/e - 1/e^6) + e - 1]

avg(f) = (1/6) * [(5/2) * (1 - e^-6) - (5/2)(e^-1 - e^-6) + e - 1]

avg(f) = (1/6) * [(5/2) * (1 - e^-6 - e^-1 + e^-6) + e - 1]

avg(f) = (1/6) * [(5/2) * (1 - e^-1) + e - 1]

avg(f) ≈ 3.427

Therefore, the average value of f over the rectangle [0,6] x [0,1] is approximately 3.427.

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What is the Mean , Median , Mode , Range for
9,6,7,5,3​

Answers

Answer:

the mean is 6

the median is 6

the mode there is none

the range is 6.

Answer:

There is no mode. (they all appear once)

The lowest number is 3 and the highest is 9, so the range is 6.

The mean is the average, add them all up (30) and divide by the number of data sets (5). The average is 6.

I have to go to dinner so maybe let someone else help with the median? The median is the middle, so you have to order them and find the middle. Hope it helped!

(NO LINKS, HELP ASAP!) Ill give brainliest to decent answer and 20+ points. !!

Wilson did a survey to find the average shoe size of the students in his class. He asked the following question:

What is the shoe size of the tallest student in the class?

Is Wilson's question a statistical question, and why or why not?

A) No, because it does not anticipate variability in students' shoe sizes
B) No, because it does not ask a question that can be answered correctly
C) Yes, because it asks a question that can be answered correctly
D) Yes, because it anticipates variability in students' shoe sizes

Answers

Answer:

A

Step-by-step explanation:

A statistical question is that question which can have different answers. Like - what is the height of girls in a class?

Here, Wilson's question will have only one answer as the show size is a simple number. A tallest student will be only one, nut mutiple different answers, so the answer is A!

Answer:

A) No, because it does not anticipate variability in students' shoe sizes

Step-by-step explanation:

he is asking the shoe size for only the tallest kid in the class, you cant base the average of the class off of the tallest kid you have to ask multiple people their shoe sizes.

Use an appropriate series in (2) in section 6.1 to find the Maclaurin series of the given function. Write your answer in summation notation. xe^8x. a) Σn=0 to [infinity] (8^n * x^(n+1))/n! b) Σn=0 to [infinity] (x^n)/(8^n * n!) c) Σn=0 to [infinity] (8^n * x^n)/n! d) Σn=0 to [infinity] (x^n)/(n!)

Answers

The Maclaurin series of \(xe^{8x}=\frac{\sum^\infty_0(8^n * x^n)}{n!}\)

What is the Maclaurin series?

The Maclaurin series is a special case of the Taylor series expansion, where the expansion is centered around x = 0. It represents a function as an infinite sum of terms involving powers of x. The Maclaurin series of a function f(x) is given by:

\(f(x) = f(0) + f'(0)x +\frac{ (f''(0)x^2}{2!} + ]\frac{(f'''(0)x^3)}{3! }+ ...\)

To find the Maclaurin series of the function f(x) = \(xe^{8x}\), we can start with the general formula for the Maclaurin series expansion:

\(f(x) = \frac{\sum^\infty_0(f^n(0) * x^n) }{ n!}\)

where\(f^n(0)\) represents the nth derivative of f(x) evaluated at x = 0.

Let's determine the appropriate series for the function \(f(x) = xe^{8x}\) from the given options:

a) \(\frac{\sum^\infty_0(8^n * x^{n+1})}{n!}\)

b) \(\frac{\sum^\infty_0(x^n )} {8^n*n!}\)

c)\(\sum^\infty_0(8^n * x^n)/n!\)

d)\(\frac{\sum^\infty_0(x^n )} {n!}\)

Comparing the given options with the general formula, we can see that option (c) matches the required form:

f(x) = \(=\frac{\sum^\infty_0(8^n * x^n)}{n!}\)

Therefore, the Maclaurin series of \(f(x) = xe^{8x}\) can be written as:

f(x) = \(=\frac{\sum^\infty_0(8^n * x^n)}{n!}\)

Option (c) is the correct series to represent the Maclaurin series of \(xe^{8x}.\)

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At batting practice Alexis hit 8 balls out of 15 into the outfield. Which equation below can be
used to determine the percentage of balls hit into the outfield?

At batting practice Alexis hit 8 balls out of 15 into the outfield. Which equation below can beused to

Answers

The percentage of ball that hit into the outfield would be represented by the equation = 15/8 = X/100. That is A.

How to calculate the percentage of balls the hit the outfield?

The total number of balls that that where present at the battling practice by Alexis = 15.

The number of balls that hit into the outfield = 8

The number of balls that hit outside the outfield = 15-8= 7

The percentage (x) of the balls that are outside the outfield;

X = 8/15 × 100/1

x ×15 = 8 × 100

15/8 = X/100.

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Please help with this problem!!

Functions f, g, and h are defined as follows: () = − 2, () = 2^2 − 1, and ℎ() =
2^3 + 4.

(a) Find the inverse of function g(x).
(b) Find f(h(-2))
(c) Find g(f(5))

Answers

Answer:

Step-by-step explanation:

f −1 (x)= 3x−2

f, start superscript, minus, 1, end superscript, left parenthesis, x, right parenthesis, equals, start fraction, x, minus, 2, divided by, 3, end fraction.

Solve the problems.

Which equation has the same number of solutions as 9(4x + 2) = 7(5x - 8) + x?

A 17x + 2 - 9x = 4(3x – 3) C 3(8x - 12) = 5(3x + 9) + 9x

B 2108 + 9) = ? (12x + 8) D (18x + 10) = 3(3x + 2) - 1

Answers

The equation 9(4x + 2) = 7(5x - 8) + x has no solutions.

The equation 9(4x + 2) = 7(5x - 8) + x can be simplified to 36x + 18 = 35x - 56 + x.
To solve this equation, we need to combine like terms.

We start by subtracting 35x from both sides to get:
36x + 18 - 35x = -56 + x.
Simplifying further, we have:
x + 18 = -56 + x.
Now, we subtract x from both sides to eliminate it from one side of the equation:
x + 18 - x = -56 + x - x.
Simplifying, we get:
18 = -56.
Now, we see that this equation leads to a contradiction.

The left side of the equation is a constant value of 18, while the right side is a constant value of -56.

Since these two values are not equal, there are no values of x that satisfy the equation.
Therefore, the equation 9(4x + 2) = 7(5x - 8) + x has no solutions.

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What point on the number line is two-fifths of the way from the point −9 to the point 17? −3.8 1.4 3.2 6.6

Answers

The point on the number line that is two-fifths of the way from -9 to 17 is 1.4.

To find the point that is two-fifths of the way from -9 to 17 on the number line, we need to calculate the distance between these two points and then determine two-fifths of that distance.

The distance between -9 and 17 can be calculated by subtracting -9 from 17:

Distance = 17 - (-9)

               = 17 + 9

               = 26

Now, we need to find two-fifths of this distance:

Two-fifths of the distance = (2/5) * 26 = (2 * 26) / 5 = 52 / 5 = 10.4

To find the point, we add 10.4 to -9:

Point = -9 + 10.4 = 1.4

Therefore, the point on the number line that is two-fifths of the way from -9 to 17 is 1.4.

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What is the quotient of 1.728 x 109 and 4.8 x 106 expressed in scientific
notation?

Answers

Answer:

3.7018867924 × \(10^{-1}\)

Step-by-step explanation:

First you want to find what these two numbers are, then you divide, then you put that answer in scientific notation.

1.728(109) = 188.352

4.8(106) = 508.80

Now we divide :

188.352 ÷ 508.80 = 0.37018867924

That's a crazy decimal, but luckily because of scientific notation we can make it look a lot simpler.

0.37018867924 =  3.7018867924 × \(10^{-1}\)

This should be right. Please comment if you are confused and want more detail.

What is the quotient of \(1.728*10^9 and, 4.8*10^6\) expressed in scientific notation?

\(\frac{1.728*10^9}{4.8*10^6}\)  Divide

\(\frac{1.728}{4.8} * \frac{10^9}{10^6}\) Divide numbers and 10's separately.

\(0.36*10^3\) Subtract exponents.

\((3.6*10^-^1 )*10^3\) Rewrite as a number bigger than 1

\(3.6*(10^-^1*10^3)\) Associate

       The answer is

\(3.6*10^2\) Add exponents

What is the quotient of 1.728 x 109 and 4.8 x 106 expressed in scientificnotation?

What is the value of x in the equation 0.3x = 12?

Answers

Answer:

You divide 0.3 by 12 if you don’t want a decimal do it the other way around the answer is x=40

Step-by-step explanation:

The value of x that satisfies the equation 0.3x = 12 is 40.

We have,

To find the value of x in the equation 0.3x = 12, we need to isolate x on one side of the equation.

We can do this by dividing both sides of the equation by 0.3, which will cancel out the coefficient of x on the left side:

(0.3x) / 0.3 = 12 / 0.3

Simplifying this equation gives:

x = 40

Thus,

The value of x that satisfies the equation 0.3x = 12 is 40.

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Find the value of b.

A. 57
B. 123
C. 50
D. 61.5

Find the value of b.A. 57B. 123C. 50D. 61.5

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