Someone pls help me if u do tysm i have khan academy’s all due tmr ahh

The normal curve with a mean of 0 and standard deviation of 1 is called (D)  the z-value.

Therefore, the normal curve with a mean of 0 and standard deviation of 1 is called (D)  the z-value.

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To calculate cumulative cash surplus/ deficit we need to consider cash flows during quarter, including sales, purchases, accounts receivable, accounts payable, cash expenses, taxes,  initial cash,loan balances.

Calculate the total cash inflows from sales for Q1: $46,000 (Q1 sales) * 71% (purchases as a percentage of next quarter's sales) = $32,660.

Calculate the total cash outflows for Q1: $1,500 (monthly cash expenses) * 3 months + $400 (monthly taxes) * 3 months = $5,700 + $1,200 = $6,900.

Calculate the net cash flow from accounts receivable: $32,660 (total cash inflows from sales) - $12,200 (accounts receivable balance at the beginning of Q1) = $20,460.

Calculate the net cash flow from accounts payable: $48,000 (Q2 sales projection) * 45 days / 30 days = $72,000 (purchases for Q2) - $14,800 (accounts payable balance at the beginning of Q1) = $57,200.

Calculate the net cash flow from short-term borrowing: Since the short-term loan balance is zero at the beginning of Q1 and there is no mention of additional borrowing, the net cash flow from short-term borrowing is zero.

Calculate the net cash flow for Q1: Net cash flow = Cash inflows - Cash outflows = $20,460 (net cash flow from accounts receivable) - $6,900 (total cash outflows) + $57,200 (net cash flow from accounts payable) = $70,760.

Calculate the cumulative cash surplus/deficit at the end of Q1: Cumulative cash surplus/deficit = Initial cash balance + Net cash flow - Minimum cash balance = $280 (initial cash balance) + $70,760 (net cash flow) - $250 (minimum cash balance) = $71,790.

Therefore, the cumulative cash surplus (deficit) at the end of Q1, prior to any short-term borrowing, is $71,790.

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The functions f(x) = -3x + 4 and f(x) = x + 1 are bijections.

A bijection is a function that is both injective (one-to-one) and surjective (onto). In other words, for a function to be a bijection, each input value must have a unique output value, and every output value must have a corresponding input value.

Let's analyze each function given:

1. f(x) = -3x + 4:

This function is a linear equation with a slope of -3. Since the coefficient of x is non-zero, the function is one-to-one. Also, as the range of this function spans all real numbers, it is onto. Therefore, f(x) = -3x + 4 is a bijection.

2. f(x) = -3²² + 7:

This function is a constant function, which means it has a fixed output value for all input values. It is not one-to-one since multiple inputs can yield the same output. Thus, f(x) = -3²² + 7 is not a bijection.

3. f(x) = 2 + 1² + 2:

This function is a constant function as well and does not vary with the input value x. Similar to the previous function, it is not one-to-one and fails to be a bijection.

4. f(x) = x + 1:

This function is a simple linear equation with a slope of 1. It is one-to-one since each input value corresponds to a unique output value. Additionally, the range of the function spans all real numbers, making it onto. Therefore, f(x) = x + 1 is a bijection.

In summary, the functions f(x) = -3x + 4 and f(x) = x + 1 are the bijections among the given options.

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Answer:

0.191

Step-by-step:

0.022 + 0.169 = 0.191.

Answer:

Step-by-step explanation:

The 2 angles shown are corresponding angles and congruent, hence

23x - 5 = 21x + 5 ( subtract 21x from both sides )

2x - 5 = 5 ( add 5 to both sides )

2x = 10 ( divide both sides by 2 )

x = 5

Answer:

Matthew drank 4 more glasses of water than Nicole: equation

Four more glasses of water than Nicole: expression

Step-by-step explanation:

We can model "Matthew drank 4 more glasses of water than Nicole" as an equation as follows:

\(m=n+4\)

However, "Four more glasses of water than Nicole" is only an expression. It doesn't include an equality.

supersciencestudy is correct, an equation must include an equality.

Answer:

accept length

accept breadth

Area=length *breadth

we multiply the length of a rectangle by the width of the rectangle.

The probability that a randomly selected college student will find a parking spot in the library parking lot in less than 3 minutes is found as  `0.7475`. Hence, the option D is correct.

The length of time it takes a college student to find a parking spot in the library parking lot follows a normal distribution with a mean of 2.5 minutes and a standard deviation of 0.75 minute.

We are supposed to find the probability that a randomly selected college student will find a parking spot in the library parking lot in less than 3 minutes.

So, we need to find `P(x < 3)` where `x` is the time taken to find a parking spot in the library parking lot.

Now, z-score will be

`z = (3 - 2.5)/0.75

= 0.67`

By looking at the z-score table, the probability that corresponds to z = 0.67 is 0.2514.

Therefore,

`P(x < 3) = P(z < 0.67)

= 0.2514 + 0.5

= 0.7514

≈ 0.7475 (approx)`

So, the correct option is `0.7475`. Hence, the answer is option D.

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Answer:

False

Step-by-step explanation:

if it helped u please mark me a brainliest :))

Answer:

False

Step-by-step explanation:

if it helped u please mark me a brainliest :))

The coordinates of the vertices of the image of the trapezoid are A'(x, y) = (- 4, 1), B'(x, y) = (- 2, 1), C'(x, y) = (- 5 / 2, 5 / 2) and D'(x, y) = (- 7 / 2, 5 / 2).

In this question we have a representation of a trapezoid, whose image has to be generated by a kind of rigid transformation known as dilation, whose equation is described below:

P'(x, y) = O(x, y) + k · [P(x, y) - O(x, y)]

Where:

If we know that k = 1 / 2, A(x, y) = (- 5, - 2), B(x, y) = (- 1, - 2), C(x, y) = (- 2, 1), D(x, y) = (- 4, 1), O(x, y) = (- 3, 4), then the coordinates of the vertices of the image are:

Point A'

A'(x, y) = O(x, y) + k · [A(x, y) - O(x, y)]

A'(x, y) = (- 3, 4) + (1 / 2) · [(- 5, - 2) - (- 3, 4)]

A'(x, y) = (- 3, 4) + (1 / 2) · (- 2, - 6)

A'(x, y) = (- 3, 4) + (- 1, - 3)

A'(x, y) = (- 4, 1)

Point B'

B'(x, y) = O(x, y) + k · [B(x, y) - O(x, y)]

B'(x, y) = (- 3, 4) + (1 / 2) · [(- 1, - 2) - (- 3, 4)]

B'(x, y) = (- 3, 4) + (1 / 2) · (2, - 6)

B'(x, y) = (- 3, 4) + (1, - 3)

B'(x, y) = (- 2, 1)

Point C'

C'(x, y) = O(x, y) + k · [C(x, y) - O(x, y)]

C'(x, y) = (- 3, 4) + (1 / 2) · [(- 2, 1) - (- 3, 4)]

C'(x, y) = (- 3, 4) + (1 / 2) · (1, - 3)

C'(x, y) = (- 3, 4) + (1 / 2, - 3 / 2)

C'(x, y) = (- 5 / 2, 5 / 2)

Point D'

D'(x, y) = O(x, y) + k · [D(x, y) - O(x, y)]

D'(x, y) = (- 3, 4) + (1 / 2) · [(- 4, 1) - (- 3, 4)]

D'(x, y) = (- 3, 4) + (1 / 2) · (- 1, - 3)

D'(x, y) = (- 3, 4) + (- 1 / 2, - 3 / 2)

D'(x, y) = (- 7 / 2, 5 / 2)

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Probability of D2 being sunny = 0.78.

On day 1, which is called D1, the probability of sunny is 0.9. It is also given that a sunny day follows a sunny day with 0.8 chance, and a sunny day follows a rainy day with 0.6 chance.

Therefore, we need to find the chances that D2 is sunny.

There are two possibilities for D2: either it can be a sunny day, or it can be a rainy day.

Now, Let us find the probability of D2 being sunny.

We have the following possible cases for D2.

D1 = Sunny; D2 = Sunny

D1 = Sunny; D2 = Rainy

D1 = Rainy; D2 = Sunny

D1 = Rainy; D2 = Rainy

The probability of D1 being sunny is 0.9.

When a sunny day follows a sunny day, the probability is 0.8.

When a sunny day follows a rainy day, the probability is 0.6.

Therefore, the probability of D2 being sunny is given by the formula:

Probability of D2 being sunny = (0.9 × 0.8) + (0.1 × 0.6) = 0.72 + 0.06 = 0.78.

Therefore, the probability that D2 is sunny are 0.78 or 78%.

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9514 1404 393

Answer:

  a) $15,779.70

  b) $13,679.70

  c) $210.92

Step-by-step explanation:

a) When tax is added, the total cost is ...

  total = price × (1 +tax rate)

  total = $14,775 × 1.068 = $15,779.70

__

b) The amount financed is the difference between the total cost and the down payment.

  financed = total - down35

  financed = $15,779.70 -2100 = $13,679.70

__

c) The monthly payment is found using the amortization formula. It can also be found using any of a number of financial calculators, spreadsheets, or apps.

  A = P(r/12)/(1 -(1 +r/12)^-n) . . . . annual rate r, n monthly payments, principal P

  A = $13,679.70(0.035/12)/(1 -(1 +0.035/12)^-72) ≈ $210.92

The correct option of the given question is option (c)  fissure.

When coding the phrase "supravesical fissure of urinary bladder," the main term to reference in the index is c. fissure.

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The main term to reference in the index when coding the phrase "supravesical fissure of urinary bladder" is c. fissure.

In medical coding, the index is typically organized alphabetically based on the main terms or significant words within medical terminology. In this case, "fissure" is the main term that represents the specific condition or anatomical feature being coded.

The other terms, such as "urinary," "bladder," and "supravesical," provide additional context but are not the primary focus when searching for the appropriate code in the index.

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Answer:

The total resulting gallons of water is 4,000 gallons

The concentration of the resulting solution is 2.625% salinity

Step-by-step explanation:

The salinity of the fresh water from the Mississippi River Delta = 0%

The salinity  of the water from the Gulf of Mexico = 3 1/2%

Therefore, if 1,000 gallons of river water mixes with 3,000 gallons from the Gulf, we have;

The total resulting gallons of water = 1,000 + 3,000 = 4,000 gallons

The total resulting gallons of water = 4,000 gallons

The concentration of the resulting solution is found as follows;

The concentration of the resulting solution = (3 × 3 1/2)/400 × 100 = 2.625%

The concentration of the resulting solution = 2.625% salinity.

Answer:

The Answer is 11 and -1

Step-by-step explanation:

This factring unit can be tricky! Think about it this way. A prime number, such as 11 and 7 can only be factored with 1 and their own numbers. so 11 times -1 is 11 plus -1 is 10. Hope this helps and good luck!

Answer:

The answer is 16

Step-by-step explanation:

I did the test

Answer:

Answer is 16

I just did the test its right i swear.

We know that, the trigonometric relationship -

sin(x) = C.O/ h

where,

C.O = opposite leg

h = hypotenuse

using these values in the equation we have -

sin(20) = 5/c

c = 5/sin(20)

c = 14.61

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Disclaimer : The diagram for the question is attached.

Here's a more detailed explanation: To determine if a graph is a function, you can use the vertical line test. The vertical line test states that if you can draw a vertical line that intersects the graph in more than one place, then the graph is not a function.

Determining whether a graph represents a function is an important concept in mathematics, especially in algebra and calculus. A function is a set of ordered pairs where each input is associated with exactly one output.

So, if you take a ruler or a straight edge and place it vertically on the graph, and it intersects the graph in two or more points, then the graph is not a function. This is because if two points in the graph have the same x-value, they must have different y-values, since functions can only have one output for each input.

On the other hand, if you place a vertical line anywhere on the graph and it intersects the graph in only one point, then the graph is a function.

It's also important to remember that a function must also pass the horizontal line test, which means that no horizontal line can intersect the graph in more than one place.

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Therefore, visually interpreting histograms can be a powerful tool for data analysis, but it is important to be aware of their strengths and limitations.

Histograms are an effective way to display data graphically. They are used to show how often certain values or ranges of values appear in a data set. Visual interpretation of histograms has many strengths and limitations. Some of the strengths of visually interpreting histograms are that they are easy to read and understand, they provide a clear picture of how the data is distributed, and they can help identify outliers or gaps in the data. However, some of the limitations of visually interpreting histograms are that they can be influenced by the number of bins chosen, the way the data is grouped, and the choice of the scale used. Therefore, it is important to carefully consider these factors when interpreting a histogram. In conclusion, visually interpreting histograms can be a powerful tool for data analysis, but it is important to be aware of their strengths and limitations.

Therefore, visually interpreting histograms can be a powerful tool for data analysis, but it is important to be aware of their strengths and limitations.

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The following statements are true:

The red light is reflected.

The blue light is absorbed.

When white light, which consists of a combination of all visible colors, illuminates the book with a red cover, the red light component in the white light is reflected by the book cover. As a result, we perceive the book to be red since that is the color of light being reflected back to our eyes.

On the other hand, the blue light component in the white light is not reflected by the red book cover. Instead, it is absorbed by the cover, which means the material of the book cover absorbs the blue light and does not reflect it back. Consequently, we do not see the blue light, and the book still appears to be red.

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Positive curve graphs will be upward-sloping.

Negative curve graphs will be downward-sloping.

Both graphs in the first image attached below, show curves sloping upward from left to right. As with upward-sloping straight lines, we can say that generally the slope of the curve is positive. While the slope will differ at each point on the curve, it will always be positive.

In the graphs in the second image attached, both of the curves are downward sloping. Straight lines that are downward sloping have negative slopes; curves that are downward sloping also have negative slopes. The slopes change from point to point on a curve, but all of the slopes along these two curves will be negative.

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Straight lines that are downward sloping have negative slopes; curves that are downward sloping also have negative slopes. The slopes change from point to point on a curve, but all of the slopes along these two curves will be negative.

Answer:

\(4(x - 3)(x - 1)(x + 2)\)

Step-by-step explanation:

hope it helps uh <3

Answer:

120

Step-by-step explanation:

GIVE ME THE BRAINLEST POINTS NOW

Answer:

x = 120

Step-by-step explanation:

All three angles are marked as equal. There are two ways to find x.

Method one

Find the supplement to x

Let the supplement to x be y

y + y + y = 180

3y = 180                 Divide by 3

y = 180/3

y = 60

=================

A straight line has an angle of 180 degrees.

x + y = 180             Substitute y = 60 into the equation

x + 60 = 180          Subtract 60

x = 180 - 60

x = 120

Method 2

The two angles not connect to x are called remote interior angles. These two angles are equal to x.

x = 60 + 60

x = 120

Answer:

6.24 pounds

Step-by-step explanation:

12 x .52 = 6.24 pounds

Answer:

The answer would be 6.24lb

Step-by-step explanation:

I took the k12 test

Answer:

g(x)=x

4

+3x

3

−x

2

−3x

Step-by-step explanation:

If the model's p-value is less than 0.05, we rule out the null hypothesis and declare it to be significant.

Using the R software.

R codes : d=read.table('data.csv',header=T,sep=',')

head(d)

attach(d)

fit=lm(Heart.Rate~Age+Weight+Height)

summary(fit)

fit2=lm(Heart.Rate~Age+Weight)

summary(fit2)

R outputs:

> d=read.table('data.csv',header=T,sep=',')

> head(d)

Heart Rate Age Weight Height

1         85  60    201     67

2        102  48    263     59

3         67  58    167     69

4         58  58    109     60

5         75  40    135     62

6         70  27    144     64

> attach(d)

> fit= lm(Heart.Rate~Age+Weight+Height)

> summary(fit)

Call:

lm(formula = Heart.Rate ~ Age + Weight + Height)

Residuals:

   Min       1Q   Median       3Q      Max

-21.1662  -7.9919   0.3377  10.3521  25.4165

Coefficients:

          Estimate Std. Error t value Pr(>|t|)

(Intercept) -2.86211   36.23799  -0.079   0.9377

Age          0.45993    0.21595   2.130   0.0428 *

Weight       0.12192    0.04841   2.519   0.0183 *

Height       0.59428    0.50119   1.186   0.2464

Significant codes:  0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1

Residual standard error: 13.15 on 26 degrees of freedom

Multiple R-squared:  0.2841, Adjusted R-squared:  0.2015

F-statistic: 3.439 on 3 and 26 DF,  p-value: 0.03137

> fit2=lm(Heart.Rate~Age+Weight)

> summary(fit2)

Call:

lm(formula = Heart.Rate ~ Age + Weight)

Residuals:

  Min      1Q  Median      3Q     Max

-26.126  -9.851   1.049  10.328  22.284

Coefficients:

          Estimate Std. Error t value Pr(>|t|)

(Intercept) 36.63974   14.36802   2.550   0.0168 *

Age          0.45122    0.21744   2.075   0.0476 *

Weight       0.12065    0.04876   2.474   0.0199 *

Significant codes:  0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1

Residual standard error: 13.25 on 27 degrees of freedom

Multiple R-squared:  0.2454, Adjusted R-squared:  0.1895

F-statistic:  4.39 on 2 and 27 DF,  p-value: 0.02235

a) Multiple linear regression equation :

y hat =  -2.862    +   0.460 X1  +    0.122 x2    +   0.594 x3

b) F =   3.439 on 3 and 26 DF,

p-value: 0.03137

We reject the null hypothesis and determine that the model is significant because the p-value is less than 0.05.

c) Heart rate is highly linked with the variable whose p-value is less than that variable. Heart rate and fluctuating weight are strongly connected in this instance.

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40 black socks should be added to the suitcase( i.e., option h )

Let's take x = black socks added by Jamal

Based on the given condition, we have

\(\frac{10}{10 + x}\) = 1/5

Here x ≠ -10

Because to define the fraction, the denominator should not be 0.

Now we need to find the value of x,

\(\frac{10}{10 + x}\) = 1/5

50 = 10 + x

x = 40

Therefore 40 socks should Jamal add to the suitcase.

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