someone pls help me! ❤️❤️❤️

Answer:

8 x 8 =64 + 16 x 8 = 128 =$192

Step-by-step explanation:

Answer:

sure just bring the question and it will be answered

Answer:

60 seconds make 1 minute,60 minute make 1 hours.

Here are a few 4/1 , 8/2 , 12/3

4, 8/2, 12/3 are equal to 4, when simplified, which means they are equivalent in nature.

A fraction is defined as numerical representation for part of a whole which represents a rational number.

If the denominator is 1, the numerator can be taken as 4, so the fraction would become \(\frac{4}{1}\) = 4

If the denominator is 2, the numerator can be taken as 8, so the fraction would become \(\frac{8}{2}\) = 4

If the denominator is 3, the numerator can be taken as 12, so the fraction would become \(\frac{12}{3}\) = 4

Thus, 4, 8/2, 12/3 are equal to 4, when simplified, which means they are equivalent in nature.

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Answer:

y = -2x + 3

Step-by-step explanation:

The slope intercept equation of a straight line is \(y=mx+b\),

where m is the slope and b is the y-intercept.

Therefore, the slope of  \(y=4-2x\)  is -2.

If a line is parallel to another line, they have the same slope.

Therefore, the slope (m) of the new line is also -2.

Using the point-slope form of a linear equation, where m = -2 and

\((x_1,y_1)\) is a point on the line (2, -1):

\(\implies y-y_1=m(x-x_1)\)

\(\implies y+1=-2(x-2)\)

\(\implies y=-2x+3\)

Answer:

2325 mL

Step-by-step explanation:

Let x = total volume of the tank. When we fill 4/5 of water into the tank, the amount of water we have can be expressed by 4x/5. Then we only keep 1/3 of that amount (poured away 2/3 of the water), so the amount of water is 4x/15. Thus we set up the equation like this:

4x/15 = 620

4x = 9300

x = 2325

Thus the tank can contain a maximum of 2325 mL.

4.57438 to the nearest tenths place is 5.

The area of the Region bounded by y = √x, y = 2-x², and y = -√2x is $\frac{32}{15}$.

To find the area of the region bounded by y = √x, y = 2-x², and y = -√2x, we need to graph the equations and determine the points of intersection. Then we can integrate to find the area.

Firstly, we'll graph the equations and find the points of intersection:

y = √xy = 2-x²y = -√2xGraph of y = √x, y = 2-x², and y = -√2xWe need to solve for the points of intersection, so we'll set the equations equal to each other and solve for x:√x = 2-x²√x + x² - 2 = 0Let's substitute u = x² + 1:√x + u - 3 = 0√x = 3 - u

(Note: Since we squared both sides, we have to check if the solution is valid.)u = -2x²u + x² + 1 = 0 (substituting back in for u

)Factoring gives us:u = (1, -2)We can then solve for x and y:x = ±1, y = 1y = 2 - 1 = 1, x = 0y = -√2x = -√2, x = 2y = 0, x = 0Graph of y = √x, y = 2-x², and y = -√2x with points of intersection to find the area, we need to integrate.

The area is bounded by the x-values -1 to 2, so we'll integrate with respect to x:$$\int_{-1}^0 (2 - x^2) - \sqrt{x} \ dx + \int_0^1 \sqrt{x} - \sqrt{2x} \ dx$$

We can then simplify and integrate:$$\left[\frac{2x^3}{3} - \frac{2x^{5/2}}{5/2} + \frac{4}{3}x^{3/2}\right]_{-1}^0 + \left[\frac{2x^{3/2}}{3} - \frac{4x^{3/2}}{3}\right]_0^1$$$$= \frac{4}{3} + \frac{4}{3} - \frac{4}{15} + \frac{4}{3} - \frac{4}{3}$$$$= \frac{32}{15}$$

Therefore, the area of the region bounded by y = √x, y = 2-x², and y = -√2x is $\frac{32}{15}$.

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The amount at which the cards offer the same deal over the course of a year is a $2,333.33

Since credit card finance charge is the fee associated with using credit.

Credit card issuers use the finance charges to minimize non-payment risks and earn some profits for extending credit to cardholders.

Data and Calculations:

                  Card A         Credit B

APR              20.8%               24.6%

Annual fee  $60                   $0

To calculate the balance required, the required equation is

= 22%x + $40 = 24.6%x

Where x = required balance

Thus,

= 0.208x + $60 = 0.246x

= $60 = 0.03x (0.246x- 0.208x )

= 0.03x = $60

x = $60 /0.03

x = $2,333.33

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The coordinates of point B are (-3, 17).

The given equation is M = I₁ + I₂ = 31 + 32.

Now let's substitute in our given values:

(-2, 2) = ((-5 + x₂) / 2, (-5 + 2 + y₂) / 2)

We will now set up two equations to solve for our two unknowns, x₂ and y₂:

Equation 1: (-5 + x₂) / 2 = -4

Multiply both sides by 2:

-5 + x₂ = -8

Add 5 to both sides:

x₂ = -3

This gives us the x-coordinate of point B.

Equation 2: (-5 + 2 + y₂) / 2 = 7

Simplify:

(-3 + y₂) / 2 = 7

Multiply both sides by 2:

-3 + y₂ = 14

Add 3 to both sides:

y₂ = 17

This gives us the y-coordinate of point B.

Therefore, the coordinates of point B are (-3, 17).

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Answer:câu B

Step-by-step explanat

v  iorìtoọnggfbgbhbfhgbgfbngfyturtgrvbgntrhfhrefngvfdhrrfvbnfgthgm  :

Answer:

3.868.000.000

=3 868.000.000

=3, 868.000.000

=3, 868 × 10⁹

Answer:

-2,951,389

Step-By-Step Explanation:

63(4)+89-45(58+256²)

63(4)+89-45(58+65536)

63(4)+89-45(58+65536)

63(4)+89-45(65,594)

252+89-45(65,594)

252+89-2,951,730

-2,951,389

Answer:

32/3 servings

Step-by-step explanation:

4 / (3/8) =

(4/1) x (8/3) =

32/3

Answer:

-12x+3y-36

Step-by-step explanation:

-6(2x+2)+3(y-8)

-12x-12+3y-24

-12x+3y-36

Answer:

-12x+(-12)+(3y-24)

-12x-12+3y-24

-12x+3y-36

Answer:

8 months

Step-by-step explanation:

because it's right just trust me

Answer:

8 months

Step-by-step explanation:

right on edge nuity <3

Answer:

-------------------------

Given two legs of a right triangle and we need to find the hypotenuse.

Use Pythagorean theorem:

The matching choice is C.

Answer:

6w = 30

Step-by-step explanation:

We should know that the 30 inches of framing material were used to frame the four sides of the rectangle.

The perimeter of the rectangle is what we should be considering, whenever we are dealing with frames.

This is 2 X (length + width)

From the questions, we can get the dimensions of the rectangle using clues from the various statements made.

From the statement"a rectangular painting length more than twice the width" we can see that the

L = 2w ------------------------- equation 1

substituting this value into the formula for the perimeter of the rectangle we have

30 = 2(2w + w)

30 = 6w

w= 5

from equation 1

L =2 X (5) = 10

Hence, we can set up the equation

6w = 30

However, the closest option to what we have is option D

6w + 6 = 30 - 4

complete question:

Lisa is framing a rectangular painting. The length is three more than twice the width. She uses 30 inches of framing material. What is the length of the printing? Write an equation and solve

Answer:

D.6w + 6 = 30 = 4

Step-by-step explanation:

perimeter = 30 inches

width = w

length = 2w + 3

perimeter of a rectangle = 2l + 2w

where

w = width

l = length

Therefore,

perimeter of a rectangle = 2(2w + 3) + 2w

perimeter of the rectangle = 4w + 6 + 2w

perimeter = 6w + 6

recall

perimeter = 30 inches

6w + 6 = 30

6w = 24

divide both sides by 6

w = 24/6

w = 4

Answer:

D: 13

I hope you understand, I am not that good at explaining. And I am not completely sure with my answer, but I think it's correct.

9514 1404 393

Answer:

  4.5

Step-by-step explanation:

The value of x that makes f(x) = -3 is ...

  4/3x -9 = -3

  4/3x = 6 . . . . . . add 9

  x = 6(3/4) = 18/4 = 9/2 = 4.5 . . . . multiply by 3/4

f^-1(-3) = 4.5

Answer:

Step-by-step explanation:

C

The statement about sampling variability is "the larger the sample size of marbles, the closer the sample proportion of red marbles will be to the true proportion of red marbles in the jar".

A mathematical assessment of two numbers is called a proportion. If two sets of provided numbers rise or fall in the same relation, then the ratios are said to be directly proportional to each other.

Students are selecting marbles from a large jar of blue and red marbles in an exercise.

Students will compute the proportion of red marbles in their sample. The closer the sample percentage of red marbles is to the genuine proportion of red marbles in the jar, the greater the sample size of the marble's sampling variability.

Thus, the larger the sample size of marbles, the closer the sample proportion of red marbles will be to the true proportion of red marbles in the jar.

Hence, the correct answer would be an option (C).

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It is given that a tree casts 35m long shadow and at the same time a pole casts a shadow 7m tall.The pole is 4.5m tall.

So make 2 similar triangles as follows:

As both shadows are cast at the same time, the angle is essentially the same.

Hence the height of tree is 22.5m.

As, a is block diagonal, with diagonal blocks of size \(m_1 \times m_1\), \(m_2 \times m_2\), \(\dots\), \(m_k \times m_k\), respectively. So,  if a commutes with d, then it must be block diagonal.

Let's suppose that d is a diagonal matrix with repeated diagonal entries grouped contiguously, i.e.,

d = \(\begin{pmatrix} D_1 & 0 & 0 & \cdots & 0 \ 0 & D_1 & 0 & \cdots & 0 \ 0 & 0 & D_2 & \cdots & 0 \ \vdots & \vdots & \vdots & \ddots & \vdots \ 0 & 0 & 0 & \cdots & D_k \end{pmatrix}\),

where \(D_1, D_2, \dots, D_k\) are scalars and appear with frequencies \(m_1, m_2, \dots, m_k\), respectively, so that \(m_1 + m_2 + \dots + m_k = n\), the size of the matrix.

Suppose that \(a\) is a matrix that commutes with d, i.e., ad = da.

Then, for any \(i \in {1, 2, \dots, k}\), we have

\(ad_{ii} = da_{ii}\)

Here, \(d_{ii}\) denotes the \(i$th\) diagonal entry of d, i.e., \(d_{ii} = D_i\) for \(i = 1, 2, \dots, k\). Since d is diagonal, \(d_{ij} = 0\) for \(i \neq j\), and

hence

\(ad_{ij} = da_{ij} = 0\)

for all \(i \neq j\).

Therefore, a is also diagonal, with diagonal entries \(a_{ii}\), and we have

\(a = \begin{pmatrix} a_{11} & 0 & 0 & \cdots & 0 \ 0 & a_{11} & 0 & \cdots & 0 \ 0 & 0 & a_{22} & \cdots & 0 \ \vdots & \vdots & \vdots & \ddots & \vdots \ 0 & 0 & 0 & \cdots & a_{kk} \end{pmatrix}\)

Thus, a is block diagonal, with diagonal blocks of size \(m_1 \times m_1\), \(m_2 \times m_2\), \(\dots\), \(m_k \times m_k\), respectively.

Therefore, if a commutes with d, then it must be block diagonal.

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The given rational function has a vertical asymptote at x = 12, and the

graph has x and y-intercept at the negative x and y-axis.

Response:

(a) The point (5, -2) is not on the graph

(b) f(x) = -1

(c) If f(x) = 2, x = 30

(d) Domain = (-∞, 12) ∪ (12, ∞)

(e) x-intercept is at x = -6, which is the point (-6, 0)

(f) The y-intercept is at y = -0.5, which is the point (0, -0.5)

(g) A zeros of f, is x = -6

The possible given function is presented as follows;

\(f(x) =\mathbf{\dfrac{x + 6}{x - 12}}\)

(a) When x = -2, we have;

\(f(-2) = \dfrac{(-2) + 6}{(-2) - 12} = \dfrac{4}{-14} = \mathbf{-\dfrac{2}{7}}\)

Therefore;

The point (\(-\frac{2}{7}\), -2) is on the graph, which gives;

(b) If x = 3, we have;

\(f(3) =\mathbf{ \dfrac{3 + 6}{3 - 12}} = \dfrac{9}{-9} =-1\)

(c)  If f(x) = 2, we have;

\(f(x) =2 = \mathbf{ \dfrac{x + 6}{x - 12}}\)

2·(x - 12) = x + 6

2·x - x = 6 + 2 × 12 = 30

x = 30

(d) The  domain which is the list of possible x-values, which is expressed as follows;

Domain; -∞ < x < 12, and 12 < x < ∞

Which gives;

(e) The x-intercepts are;

\(0 = \mathbf{ \dfrac{x + 6}{x - 12}}\)

(f) The y-intercept

\(At \ the \ y-intercept, \ f(x) = \dfrac{0 + 6}{0 - 12} = -\dfrac{1}{2} = \mathbf{ -0.5}\)

(g) The zeros of the graph, f, are the points at which the graph crosses the x-axis which at the point x = -6

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Answer:

The system has a solution at (-20,-2).

Step-by-step explanation:

To find the solution of the system, you need to find where the two equations intersect, or are equal to each other. You may do this with a calculator, but I find it much easier using a graphing software online, like Desmos.

Once I graphed these two equations, I found that they intersected each other at the point (-20,-2), so the system has ONE solution.

At x=-20, both equations have y=-2.

**I would also like to note that the second equation, y will ALWAYS equal -2, so you're really just finding where the first equation equals that as well.**

\(~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$45700\\ r=rate\to 12\%\to \frac{12}{100}\dotfill &0.12\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{quarterly, thus four} \end{array}\dotfill &4\\ t=years\dotfill &2 \end{cases}\)

\(A = 45700\left(1+\frac{0.12}{4}\right)^{4\cdot 2}\implies A=45700(1.03)^8 \implies A \approx 57891.39 \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{earned interest}}{57891.39~~ - ~~45700} ~~ \approx ~~ \text{\LARGE 12191.39}\)

Using translation concepts, we have that:

A translation is represented by a change in the function graph, according to operations such as multiplication or sum/subtraction either in it’s definition or in it’s domain. Examples are shift left/right or bottom/up, vertical or horizontal stretching or compression, and reflections over the x-axis or the y-axis.

On the translation of △ABC to △A′B′C′, the rule applied to the vertices is:

(x,y) -> (x + 4, y).

Hence it was translated 4 units right.

On the translation of △A′B′C′​ to △A′′B′′C′', the rule is given by:

(x,y) -> (-y,x).

Hence it was rotated 90 degrees counterclockwise about the origin.

The triangle keeps the same size after the translations, hence:

Because the transformations are both rigid, the pre-image and the image are congruent.

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The measure of angle ADC in the geometric system is equal to 55°.

In this question we find a geometric system formed by a quadrilateral and an angle vertical to a vertex of the quadrilateral. Angle CDE is supplementary to angles EDF and ADC. Two angles are supplementary whose sum of measures equals 180°. Therefore:

m ∠ CDE + m ∠ EDF = 180°

(2 · x + 1) + (x - 7) = 180°

3 · x - 6 = 180°

3 · x = 186°

x = 62

m ∠ CDE = 2 · x + 1

m ∠ CDE = 2 · 62 + 1

m ∠ CDE = 125°

m ∠ ADC = 180° - 125°

m ∠ ADC = 55°

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