The minimum distance of the linear code is equal to the smallest number of linearly-independent columns of H, as it represents the smallest number of bit positions in which any two codewords differ.
To show that we can find the minimum distance of a linear code from a parity-check matrix H, we need to prove that the minimum distance is equal to the smallest number of linearly-dependent columns of H.
Let's assume we have a linear code with a parity-check matrix H of size m x n, where m is the number of parity-check equations and n is the length of the codewords.
The minimum distance of a linear code is defined as the smallest number of bit positions in which any two codewords differ. In other words, it represents the minimum number of linearly-independent columns of the parity-check matrix.
Now, let's consider the columns of the parity-check matrix H. Each column corresponds to a parity-check equation or a constraint on the codewords.
If there are two codewords that differ in exactly d bit positions, it means that there are d linearly-independent columns in H. This is because changing the values of those d bit positions will result in a non-zero syndrome or violation of the parity-check equations.
Conversely, if there are fewer than d linearly-independent columns in H, it means that there are more than d bit positions that can be changed without violating any of the parity-check equations. In other words, there exist codewords that differ in fewer than d bit positions.
Therefore, the minimum distance of the linear code is equal to the smallest number of linearly-independent columns of H.
In conclusion, we have shown that we can find the minimum distance of a linear code from a parity-check matrix H, and it is equal to the smallest number of linearly-dependent columns of H.
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Will make brainiest if 2 people answer :3
Answer:
1.6
Step-by-step explanation:
12.8/8 = 1.6
15.2/9.5 = 1.6
Scale factor = 1.6
I need help with this question PLEASE
2n+3n+9=-41
Answer:
2n+3n=5n = -41-9= 50
5n=50
n = 10
What are the answers to all the questions? Make sure to show your work and the check.
1. 34c = 68
Divide both sides by 34
C = 68/34
C = 2
2. D - 1/2 = 3/4
Add 1/2 to both sides
D = 3/4 + 1/2
D = 1 1/4
3. E + 52.5 = 81
Subtract 52.5 from both sides
E =81-52.5
E = 28.5
4. 18 = f/0.3
Multiply both sides by 0.3
F = 18 x 0.3
F = 5.4
Find the sum of the first 7 terms of the following series, to the nearest integer.
125,50, 20, ...
Answer:
\(r = 2.5 \\ sum = \frac{a( {r}^{n - 1} )}{r - 1} \\ = \frac{125( {2.5}^{7 - 1} )}{7 - 1} \\ = \frac{30517.6}{6} \\ = 5086.3\)
1-1=-5
Step by step process
Marco has two bags of candy. One bag contains three red lollipops and
2 green lollipops. The other bag contains four purple lollipops and five blue
lollipops. One piece of candy is drawn from each bag. What is the probability
of choosing a green lollipop and a purple lollipop?
The value of the probability of choosing a green lollipop and a purple lollipop is, 8 / 45
We have to given that;
One bag contains 3 red lollipops and 2 green lollipops.
And, The other bag contains four purple lollipops and five blue lollipops.
Hence, The probability of choosing a green lollipop is,
P₁ = 2 / 5
And, The probability of choosing a purple lollipop is,
P₂ = 4 / 9
Thus, The value of the probability of choosing a green lollipop and a purple lollipop is,
P = P₁ × P₂
P = 2/5 × 4/9
P = 8/45
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The formula for the speed of a tsunami in deep water is v=gh−−√ , where g is acceleration due to gravity, 9.8 m/s2 , and h is the depth of the ocean in meters. Use this formula to estimate the speed at which the tsunami that started with an earthquake in Sumatra struck Sri Lanka about 1550 km away. The Bay of Bengal is 4 km (4000 m) deep.
Answer:
v = 200 m/s
Step-by-step explanation:
The formula for the speed of a tsunami in deep water is given by :
\(v=\sqrt{gh}\)
Here,
g is acceleration due to gravity
h is the depth of the ocean in meters.
We need to find the speed at which the tsunami that started with an earthquake in Sumatra struck Sri Lanka about 1550 km away. The Bay of Bengal is 4 km (4000 m) deep.
It means we need to find v if h = 4000 m
So,
\(v=\sqrt{10\times 4000}\\\\v=200\ m/s\)
So, the speed of the tsunami is 200 m/s.
A large plot of land is shaped like a trapezoid, ABCD, where AB is parallel to CD, AB = 12 km and CD = 8 km. The diagonal BD of the trapezoid is equal to 10 km. The internal angle ABD is equal to 58º.
D 8 km С
D 10 km B
Angle B is 58
А 12 km B
Let a new point, H, be a point on AB closest to D.
(a) Calculate the distance from H to D.
(b) Calculate the length of AD.
(c) Calculate the size of the angle DÂB. A landowner estimates that the length of AD is equal to 11. 5 km.
(d) Calculate the percentage error in the landowner's estimate.
The landowner decides to install cone-shaped concrete bollards along the perimeter of the plot of land. The bollards are to be installed at a distance of 100 m from each other. The radius of the base of each bollard is 20 cm and the height of each bollard is 40 cm.
(e) Calculate the volume of one of the bollards. (f) Calculate the total volume of concrete needed to install all the bollards.
For the trapezoid:
a) distance is 8.48 kmb) length is 5.3 kmc) size of the angle DÂB is 70.46°d) percentage error is 71.64%e) volume is 0.0084 cubic metersf) total volume is 32700 m / 100 m/bollardHow to solve for a trapezoid?(a) To calculate the distance from H to D (HD), use trigonometry. We know that BD = 10 km and ∠ABD = 58º. Therefore, sine of ∠ABD equals to HD/BD.
So, HD = BD × sin(∠ABD)
= 10 km × sin(58º)
= 10 km × 0.8480 (rounded value of sin(58))
= 8.48 km
(b) To calculate the length of AD, we'll first calculate HB using the Pythagorean theorem, since ∆HBD is a right triangle:
HB = √(BD² - HD²)
= √((10 km)² - (8.48 km)²)
= √(100 km² - 71.83 km²)
= √(28.17 km²)
= 5.3 km
So, AD = AB - HB
= 12 km - 5.3 km
= 6.7 km
(c) To calculate the angle ∠DAB, use the law of cosines on ∆ABD:
cos(DAB) = (AD² + BD² - DB^2) / 2ADBD
= (6.7 km² + 10 km² - 10 km²) / (2 × 6.7 km × 10 km)
= (44.89 km²) / (134 km²)
= 0.3347
Therefore, ∠DAB = arccos(0.3347) = 70.46°.
(d) Given that the actual length of AD = 6.7 km, the landowner's estimate was 11.5 km. The absolute error is the difference between the estimated and actual value:
Absolute Error = |Estimated - Actual|
= |11.5 km - 6.7 km|
= 4.8 km
The percentage error is the absolute error divided by the actual value, multiplied by 100:
Percentage Error = (Absolute Error / Actual) × 100
= (4.8 km / 6.7 km) × 100
= 71.64%
(e) The volume V of a cone is given by the formula V = (1/3)πr²h. Given that the radius r = 20 cm = 0.2 m and height h = 40 cm = 0.4 m:
V = (1/3) × π × (0.2 m)² × 0.4 m
= 0.0084 cubic meters
(f) To calculate the total volume of concrete needed, know the number of bollards. The bollards are installed every 100 m along the perimeter of the plot. The perimeter P of a trapezoid is the sum of its sides:
P = AB + BC + CD + DA
= 12 km + BC + 8 km + 6.7 km
BC = √(BD² - CD²) = √((10 km)² - (8 km)²) = √(36) = 6 km (Using Pythagorean theorem).
So, P = 12 km + 6 km + 8 km + 6.7 km = 32.7 km = 32700 m
The number of bollards is P/spacing = 32700 m / 100 m/bollard
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find the gradient field of the function, f(x,y,z)=x2 4y2 4z2−1/2.
The gradient field of a function is a vector field that points in the direction of the maximum increase of the function. In the case of f(x,y,z) = x^2/4 + y^2/4 + z^2 - 1/2, the gradient field is given by <x/2, y, 2z>.
The gradient of a scalar field is a vector field that points in the direction of the maximum rate of increase of the scalar field, and its magnitude represents the rate of increase.
To find the gradient field of f(x,y,z), we first calculate the partial derivatives of f with respect to x, y, and z. The partial derivative of f with respect to x is 2x/4y2/4z2, the partial derivative of f with respect to y is -x2/2y3/4z2, and the partial derivative of f with respect to z is -x2/4y2/2z3/2. The gradient of f is then given by the vector field (2x/4y2/4z2)i - (x2/2y3/4z2)j - (x2/4y2/2z3/2)k, where i, j, and k are the unit vectors in the x, y, and z directions, respectively. This vector field represents the direction and magnitude of the maximum rate of increase of f at any point in space.
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the scatter plot below the relationship between the number of pets that people have and average amiunt they spend at the pet store each month. Based on the equation of the trend line, how much would expect someone who has 9 pets to spend at the pet store each month?
$225 is the amount that would expect someone who has 9 pets to spend at the pet store each month
How to solve for the amountWe have the equation of the line as
MX + B
When we have 4, 100
We will put the values in the line formula so that :
100 = m *4
solve for the value of m
m = 100 / 4
m = 25
Given that the value of m = 25
y = 25 x
we have that how much would expect someone who has 9 pets to spend at the pet store each month?
hence the value of x is given as 9
y = 25 x 9
y = 25 x 9
y = $225
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Which equation is quadratic in form?
a.6(x + 2)2 + 8x + 2 + 1 = 0
b.6x4 + 7x2 – 3 = 0
c.5x6 + x4 + 12 = 0
d.x9 + x3 – 10 = 0
Answer:
d. x9 + x3 – 10 = 0
Tính (x+1)^3-x(x-2)^2-1
Answer:
\(7x^2-x\)
Step-by-step explanation:
This function models the height, f(x), in feet, of a ball x seconds after it is tossed into the air.
LaTeX: f\left(x\right)=-16x^2+48x+64
f
(
x
)
=
−
16
x
2
+
48
x
+
64
Which statement describes the ball 1.2 seconds after it is tossed into the air?
Group of answer choices
Answer:
Step-by-step explanation:
Given the height of the object covered by the ball modeled by the function;
h(x) = -16x^2 + 48x + 64
To determine the height covered by the ball after 1.2 secs, we will simply substitute x = 1.2s into the formula and find h(x) as shown;
h(1.2) = -16(1.2)^2 + 48(1.2) + 64
h(1.2) = -16(1.44) + 48(1.2) + 64
h(1.2) = -23.04 + 57.6 + 64
h(1.2) = 98.56m
This means that the ball have covered 98.56m in 1.2sseconds
Answer:
The Answer is D. 25ft
Step-by-step explanation:
Taking the quiz rn hope this helps:)
3.
A local town has a population of 3,500 people and has grown by 2.5% each year. Write an exponential function that models the total population p after t years.
The exponential function that models the total population p after t years is p = 3,500 x 1.025^t.
What is the exponential?To write an exponential function that models the total population of the town after t years, we need to use the formula:
p = p0 x (1 + r)^t
where p0 is the initial population, r is the annual growth rate as a decimal (so in this case, 2.5% = 0.025), and t is the number of years.
In this case, we know that the initial population is 3,500, and the annual growth rate is 2.5%, or 0.025. So we can substitute these values into the formula to get:
p = 3,500 x (1 + 0.025)^t
Simplifying this expression gives:
p = 3,500 x 1.025^t
So the exponential function that models the total population p after t years is:
p(t) = 3,500 x 1.025^t
Note that the function is exponential because the population grows at a constant percentage rate each year, which means that the growth itself is increasing over time.
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can the pythagorean theorem be used for any triangle
Answer:
No, only for right angle Δ
Step-by-step explanation:
It is only used for right angle triangles
Using π = 3.14, what is the circumference of a circle with a diameter of 28 units?
Round your answer to the nearest hundredth.
rexs pizza is currently have a special for delivery orders pizzas are $8 each and the delivery charge is $1.75 Write an equation for the total cost
Answer:
8x + 1.75 = y
Step-by-step explanation:
Read the question and look for key words.
In this questions the key words are Each and Total.
x is for each pizza purchased and y is total cost.
The delivery charge is a one time charge so no need to add a letter because people don't buy more than one delivery charge.
Hope this helps!
Order these from least to greatest: .25, 3/8, 7/12, 5/16, .5
A student at a four-year college claims that mean enrollment at four-year colleges is higher than at two-year colleges in the United States. Two surveys are conducted. Of the 35 four-year colleges surveyed, the mean enrollment was 6,193 with a standard deviation of 598. Of the 35 two-year colleges surveyed, the mean enrollment was 4,305 with a standard deviation of 572. Test the student's claim at the 0.01 significance level.
At a significance level of 0.01, we can confidently state that the student's claim is true.
The hypothesis in this question can be stated as follows:
Null Hypothesis: H0: μ1 = μ2 (There is no difference between the mean of four-year college enrollment and two-year college enrollment.)
Alternative Hypothesis: H1: μ1 > μ2 (Mean enrollment of four-year colleges is greater than the mean enrollment of two-year colleges in the United States.)
The significance level (α) is given as 0.01, which represents the probability of rejecting the null hypothesis when it is actually true.
To calculate the test statistic, we can use the formula:
z = ((X1 - X2) - (μ1 - μ2)) / √((σ1² / n1) + (σ2² / n2))
Substituting the given values:
z = ((6193 - 4305) - (0)) / √((598² / 35) + (572² / 35))
z = 10.33
Since this is a right-tailed test, we need to compare the test statistic with the critical value. At a significance level of 0.01, the critical value is 2.33.
The calculated test statistic (10.33) is greater than the critical value (2.33). Therefore, we reject the null hypothesis and conclude that there is enough evidence to support the claim that the mean enrollment at four-year colleges is higher than at two-year colleges in the United States.
In conclusion, at a significance level of 0.01, we can confidently state that the student's claim is true. The mean enrollment at four-year colleges is higher than at two-year colleges in the United States.
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Eyes Spinal Cord Brain All of these are part of which organ system? A) circulation B) digestive C) nervous D) skeletal
Answer:
C) nervous
In this organelle, carbon dioxide and water are converted to _________ and oxygen.
~glucose
Step-by-step explanation:
please explain this in steps please friends
Answer:
See below
Step-by-step explanation:
The LHS and RHS are exactly the same, so the equality is true.
The associate property of addition says that
\(\boxed{a+(b+c)=(a+b)+c}\)
In order to make the addition of fractions, the denominators should be same. So we can write three fractions as one.
\(\dfrac{1}{2} +\left(\dfrac{2}{3}+\dfrac{3}{4} \right )\)
\(\dfrac{1}{2} +\dfrac{2}{3}+\dfrac{3}{4}\)
\(\dfrac{1\cdot 6 }{2\cdot 6} +\dfrac{2 \cdot 4}{3 \cdot 4}+\dfrac{3 \cdot 3 }{4 \cdot 3}\)
\(\dfrac{ 6 }{12} +\dfrac{8}{12}+\dfrac{9 }{12}\)
\(\dfrac{ 23 }{12}\)
Answer:
You gotta give me (us) more to work with homie.
Step-by-step explanation:
If I have more of a picture with it I could possibly help but all there is a barely readable and legible nonsense equation. Sorry :(
What measure of center would you use for a bimodal histogram? and why?
Answer:
Unless you have a good reason to use mode or median, like bimodal distributions or heavily skewed data, the best measure to use is the mean. SPSS Tips: Vocabulary: Measures of Central Tendency - Numbers that represent the average or typical score obtained from measurements of a sample.
For transition matrix P= ⎣
⎡
0
1−p
0
0
1−p
0
0
0
p
0
1
0
0
p
0
1
⎦
⎤
determine the probability of absorption from state 1 into state 3. Here Q=[ 0
1−p
1−p
0
] and (I−Q)=[ 1
p−1
p−1
1
] and R=[ p
0
0
p
]. Usinf the basic formula for inverses of 2×2 matrices (I−Q) −1
= 2p−p 2
1
[ 1
1−p
1−p
1
] and (I−Q) −1
R= 2p−p 2
1
=[ p
p(1−p)
p(1−p)
p
]= 2−p
1
[ 1
1−p
1−p
1
] The probability of absorption from 1 to 3 is 1−p
1
. 3.53 When an NFL football game ends in a tie, under sudden-death overtime the two teams play at most 15 extra minutes and the team that scores first wins the game. A Markov chain analysis of sudden-death is given in Jones (2004). Assuming two teams A and B are evenly matched, a four-state absorbing Markov chain is given with states PA : team A gains possession, PB : team B gains possession, A : A wins, and B : B wins. The transition matrix is where p is the probability that a team scores when it has the ball. Which team first receives the ball in overtime is decided by a coin flip. (a) If team A receives the ball in overtime, find the probability that A wins.
If team A receives the ball, the probability that A win is given by (1-q)/(2-q).
For transition matrix P, we have;
P= ⎣ ⎡ 0 1−p 0 0 1−p 0 0 0 p 0 1 0 0 p 0 1 ⎦⎤
From the transition matrix P, we can determine the probability of absorption from state 1 into state 3 as follows:
I-Q =\([ 1 p-1 1-p 1 ](I-Q)^{-1}\)
R = 2-p[ 1 p-1 1-p 1 ]\({p 0 \choose 0 p}\)
=\([ \frac{p}{2-p} \frac{1-p}{2-p}]\)
Therefore, the probability of absorption from states 1 to 3 is 1-p/2-p, which simplifies to (2-p)/2-p.
The four-state absorbing Markov chain is given with states
PA: team A gains possession,
PB: Team B gains possession,
A: A wins, and B: B wins.
The transition matrix is given by;
P = [q 1-q 0 0 1-q q 0 0 0 0 1 0 0 0 0 1]
From the matrix, if team A receives the ball in overtime, we find the probability that A wins as follows:
The probability of absorption from state PA to state A is 1, while the probability of absorption from state PA to state B is 0.
Therefore; P(A|PA) = 1,
P(B|PA) = 0
The probability of absorption from state PB to state B is 1, while the probability of absorption from state PB to state A is 0.
Therefore;
P(B|PB) = 1,
P(A|PB) = 0
Let P_A be the probability of winning for team A, then the probability of winning for team B is given by;
\(P_B = 1 - P_A\)
From the transition matrix, the probability that team A wins when it starts with the ball is given by;
P(A|PA) = qP(A|PA) + (1-q)P(B|PA)
We know that P(A|PA) = 1 and
P(B|PA) = 0
Therefore;
1 = q + (1-q)
\(P_B1\) = q + (1-q)
\((1-P_A)1 = q + 1 - q - P_A + q\)
\(P_AP_A = \frac{1-q}{2-q}\)
Therefore if team A receives the ball, the probability that A win is given by (1-q)/(2-q).
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PLS HELP PLS I WILL GIVE BRAINLIST
Which punctuation mark goes in the space?
My sister stole a bunch of my things ______ my pants, shoes, and jackets.
Group of answer choices
None
Comma ,
Dash -
Colon :
Semi-Colon ;
Period.
Which punctuation mark goes in the space?
My sister stole a bunch of my things ______ except my favorite blanket.
Group of answer choices
None
Comma ,
Dash -
Colon :
Semi-Colon ;
Period.
Which punctuation mark goes in the space?
My sister stole a bunch of my things ______ because she's rude to me.
Group of answer choices
None
Comma ,
Dash -
Colon :
Semicolon ;
Which punctuation mark goes in the space?
My sister ____ who is rude to me, stole a bunch of my things.
Group of answer choices
None
Comma ,
Dash -
Colon :
Semicolon ;
Which punctuation mark goes in the space?
My sister stole my favorite thing ______ my jacket.
Group of answer choices
None
Comma ,
Dash -
Colon :
Semicolon ;
Period.
Which punctuation mark goes in the space?
If my sister steals one more of my things ______ I'm going to never talk to her again.
Group of answer choices
None
Comma ,
Dash -
Colon :
Semicolon ;
Which punctuation mark goes in the space?
I'm going to tell my dad ______ my mom - if my sister steals more of my things.
Group of answer choices
None
Comma ,
Dash -
Colon :
Semicolon
Which punctuation mark goes in the space?
My sister stole a bunch of my things ______ I'm going to tell my dad.
Group of answer choices
None
Comma ,
Dash -
Colon :
Period.
Which punctuation mark goes in the space?
My sister stole a bunch of my things ______ my dad will punish her for me.
Group of answer choices
None
Comma ,
Dash -
Colon :
Semicolon ;
Which punctuation mark goes in the space?
My sister stole a bunch of my things like ______ my pants, shoes, and jackets.
Group of answer choices
None
Comma ,
Dash -
Colon :
Semicolon ;
Answer:
1.colon
2. semicoln
3. comma
4. none
5. dash
6. comma
7. i am not sure but i think is a colon
8.comma
9. semicoln
10. dash
Step-by-step explanation:
You use colon when listing out something.
Sorry, I am not sure about this answer
What is the range of the given function?
{(-2, 0), (-4, -3), (2, -9), (0, 5), (-5, 7)}
{x | x = -5, -4, -2, 0, 2}
{y l y = -9, -3, 0, 5, 7}
O (x | x = -9, -5, -4, -3, -2, 0, 2, 5, 7}
O tyl y = -9, -5, -4, -3, -2, 0, 2, 5, 7}
Answer:
{-9, -3, 0, 5, 7}
Step-by-step explanation:
Well, you already have the relation of the function. The domain of a function are its x coordinates and the range are all the y coordinates:
0, -3, -9, 5, 7
We write them in ascending order:
-9, -3, 0, 5, 7
And this way we get the range
It is important to check if the coordinates you are given can form a function. In this case they do, but in other cases they might not.
If you have coordinates where for example there are two equal values of x but the y is different in both, for example (1, 2) and (1, 5), this cannot be a function because y can be on two possible destinations for the same value of x.
need help ty I’ll give brainliest
Answer:
120
Step-by-step explanation:
all angles of a triangle add up to 180. 180-15-45= 120.
:D
brainliest pls
Given :
Measure of an angle = 15°
Measure of the second angle = 45°
Let the measure of the third angle be x.
We know that :
▪︎Sum of all angles of a triangle = 180°[angle sum property]
Which means :
\( =\tt 15 + 45 + x = 180\)
\( =\tt 60 + x = 180\)
\( =\tt x = 180 - 60\)
\(\hookrightarrow\color{plum}\tt \: x = 120°\)
Thus, the measure of the third angle = 120°
Since the sum of all these angles is equivalent to 180°[15+45+120=180] we can conclude that we have found out the correct measure of the third angle.
Therefore, the correct option is (C) 120
show that log ab×log ba =1
Answer:
See below for proof.
Step-by-step explanation:
Given:
\(\log_ab \times \log_ba=1\)
To prove the given equation, begin by changing the base of the two logs so that they have the same base.
\(\boxed{\textsf{Change of base}: \quad \log_pr=\dfrac{\log_xr}{\log_xp}}\)
Change the base of both logs to x by using the change of base formula:
\(\implies \log_ab=\dfrac{\log_xb}{\log_xa}\)
\(\implies \log_ba=\dfrac{\log_xa}{\log_xb}\)
Substitute into the equation:
\(\implies \log_ab \times \log_ba=\dfrac{\log_xb}{\log_xa} \times \dfrac{\log_xa}{\log_xb}\)
\(\textsf{Apply the fraction rule} \quad \dfrac{a}{c}\times \dfrac{b}{d}=\dfrac{a \times b}{c \times d}:\)
\(\implies \dfrac{\log_xb \times \log_xa}{\log_xa \times \log_xb}\)
Apply the commutative property of multiplication to the numerator:
\(\implies \dfrac{\log_xa \times \log_xb}{\log_xa \times \log_xb}\)
Cancel the common factor logₓb:
\(\implies \dfrac{\log_xa}{\log_xa}\)
\(\textsf{Apply the fraction rule} \quad \dfrac{n}{n}=1:\)
\(\implies \dfrac{\log_xa}{\log_xa}=1\)
Hence proving that:
\(\log_ab \times \log_ba=1\)In one calculation:
\(\begin{aligned}\implies \log_ab \times \log_ba & =\dfrac{\log_xb}{\log_xa} \times \dfrac{\log_xa}{\log_xb}\\\\&=\dfrac{\log_xb \times \log_xa}{\log_xa \times \log_xb}\\\\&=\dfrac{\log_xa \times \log_xb}{\log_xa \times \log_xb}\\\\&=\dfrac{\log_xa}{\log_xa}\\\\&=1\end{aligned}\)
Geometry. Math nation section 3
∠g and ∠h are complementary angles and ∠g and ∠h are acute angles are true statements from the given information
Two angles are given.
∠g = (2x-90)°
∠h = (180-2x)°
We have to find the statement which is true about the angles g and h.
If both angles are greater than zero.
Complementary angles add up to 90 degrees
i.e., ∠g and ∠h are complementary if ∠g + ∠h = 90°.
Substituting the given values:
∠g + ∠h
= (2x-90)° + (180-2x)° = 90°
Thus, ∠g and ∠h are complementary angles.
and both the angles are less than 90 degrees so we can tell that angles ∠g and ∠h are acute.
So the statement ∠g and ∠h are acute angles is also true
Hence, ∠g and ∠h are complementary angles and ∠g and ∠h are acute angles are true statements
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Carlos has four notes in his wallet: $5, $10, $20, and $50. He takes out two notes at random.
There are six possible pairs of notes. List them.
b Find the probability that:
i. one of the notes is $5 ii. the total value of the notes is more than $50.
Answer:
5 and 10
5 and 20
5 and 50
10 and 20
10 and 50
20 and 50
1/4 for 5$
1/4 for 50$
community college faculty is negotiating a new contract with the school board. The distribution of faculty salaries is skewed right by several faculty members who make over $100,000 per year. If the faculty impression that they deserve higher sales should they a r e the meanor median of their current salaries? A. The faculty should use the mean to make their argument. The mean will be higher than the median since the mean is influenced by the few extremely high res.B. The faculty should use the mean to make o rgument. The man will be lower than the median since it will be henced by the few high salariesC. The faculty should use the median to make their argument. The median will be higher than the mean since the media is unced by the high e s D. The faculty should use the median to make their argument. The median will be lower than me since the means i nced by the extremely histories
Option D. The faculty should use the median to make their argument. The median will be lower than the mean since the mean is influenced by the few extremely high salaries.
Mean is the average of any data set whereas the median is the middle value we get after arranging the data in ascending order.
So for example, if the salaries of any 5 faculty members are as follows:
$10,000 , $50,000 , $80,000 , $150,000 , $160,000
Mean= (10,000+50,000+80,000+150,000+160,000) / 5
Mean= $90,000
Median= (5+1) / 2
Median= 6/2
Median= 3rd value
As the data is already arranged in ascending order, Median is $80,000
Hence, if the faculty want to give the community the impression that they deserve higher salaries, they should advertise the median of their current salaries.
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