PLS HELP WILL AWARD BRAINLIEST ITS TIMES

Dave slides across a soccer field to try to kick a ball. He comes to a stop
because of friction. Which free-body diagram shows him while he is sliding?

a
b
c
d

The weight of the object in the newly heavenly body is 3000 N.

In science and engineering, the weight of an object is the pressure performed on the item due to gravity. a few widespread textbooks outline weight as a vector quantity, the gravitational pressure performed on the item. Others define weight as a scalar quantity, the significance of the gravitational pressure.

Given,

mass of earth = M

mass of new heavenly body = 12 M

the radius of the earth = r

the radius of the new heavenly body = 4r

mass of the object = m (mass always remains constant)

\(\frac{mM}{r^2}\)

using the formula of gravity,

G₁ = g\(\frac{mM}{r^2}\)

G₂ = g\(\frac{m12M}{4r^2}\)

comparing G₁  and G₂

G₁ = 1000 N given

G₁ / G₂ = M × 4r² /  12 M r²

G₂ = 1000 × 12 / 4

     = 3000 N

The measure of the pressure of gravity performing on a frame. The method for weight is given by using: w = mg. As weight is a force its SI unit is also the same as that of pressure, the SI unit of weight is Newton (N).

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The value of the other charge is -1.02 x 10-9 C. The potential at the midpoint between two point charges is equal to the sum of the potentials due to each charge.

In this case, the potential is 8.48 V and one of the charges is 1.02 x 10-9 C. Therefore, the potential due to the other charge must be -8.48 V. The charge of a point charge is equal to its potential multiplied by its distance from the midpoint. In this case, the distance is 1.11 m and the potential is -8.48 V. Therefore, the value of the other charge is -1.02 x 10-9 C.

The potential due to a point charge is given by the following equation:

V = kQ/r

where:

V is the potential in volts

k is Coulomb's constant (8.988 x 10^9 N m^2 C^-2)

Q is the charge in coulombs

r is the distance between the point charge and the point where the potential is being measured in meters

In this case, the potential is 8.48 V, the distance is 1.11 m, and the charge of one of the point charges is 1.02 x 10-9 C. Therefore, the charge of the other point charge is:

Q = -(8.48 V) / (1.11 m) * (8.988 x 10^9 N m^2 C^-2) = -1.02 x 10-9 C

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Answer:

So sorry I found the answer a while ago but forgot!

Explanation:

Answer:  Distance is a scalar quantity and direction is not applicable.  We can use graphs to depict an object's change in position over time.  Create a large number line in the classroom by taping index cards on the floor or wall 1 meter apart.

Explanation: I really hope that was helpful.

We can use Coulomb's law:

Let:

So:

Therefore, we need to decrease the distance by a factor of 9.

The spring constant of the spring is approximately 2356.44 N/m.

To solve this problem, we can use the principle of conservation of mechanical energy, which states that the total mechanical energy of a system is conserved when there are no non-conservative forces acting on it, such as friction.

Initially, the spring has potential energy stored in it due to its compression. When the spring is released, this potential energy is converted into kinetic energy as the spring expands and the mass attached to it begins to move upward.

At the highest point of its motion, all of the kinetic energy has been converted back into potential energy, with none lost due to non-conservative forces.

We can use the following equation to calculate the spring constant, k:

mgh = (1/2)kx^2

where m is the mass of the spring, g is the acceleration due to gravity, h is the maximum height reached by the mass, x is the initial compression of the spring, and k is the spring constant.

Substituting the given values, we get:

(1.5 kg)(9.81 m/s^2)(2.5 m) = (1/2)k(0.25 m)^2

Simplifying and solving for k, we get:

k = (3(9.81)(2.5))/(0.25)^2 = 2356.44 N/m

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Initial velocity of car is 0.

Final velocity of car is 36 km/h.

Time taken to attain final speed is 2 minutes.

What is the acceleration of car ?

v = u + at

First change the final velocity from km/h to m/s and also time to seconds.

[ To change km/h to m/s multiply by 5/18 ]

➙ Final velocity = 36(5/18) = 10 m/s.

[ 1 minutes = 60 seconds ]

➙ 2 minutes = 2(60) = 120 seconds.

Now, we have

v = 10 m/s.

u = 0 m/s.

t = 120 s.

Hence, the acceleration of car is 0.083 m/s².

➟ The rate of change of velocity is called acceleration. It is denoted by a.

➟ The velocity at which motion starts is termed as initial velocity. It is denote by u.

➟ The last velocity of an object after a period of time. It is denoted by v.

\(\boxed{\large{\bold{\blue{ANSWER~:) }}}}\)

By 1st Equation of motion

we know that,

\(\boxed{\large{\sf{v \: = u \: + a \: t}}}\)

according to the question,

\(10 = 0 + a \times 120\\\\a \: = \frac{10}{120}\\\\a \: = \frac{1}{12}\\\\a=0.083\: m {s}^{ - 2}\)

Therefore,

Acceleration of the car is 0.083 ms^-2

The see saw would move in the direction of the girl.

We know that the moment can be obtained as the product of the mass and the distance that have been covered. According to the principle of the moments. We know that the sum of the clockwise moments is equal to the sum of the anti clockwise moments.

In the case of see saw that we have here, we can see that it is moving towards the position of the girl and that would be the direction of the weight as shown in the figure that have been shown above.

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Answer:

Im not really sure lemme ask my friend he knows about this subject and when he gives me answer ill edit this

Explanation:

Answer:

i dont even know

Explanation:

I just dont know

Newton's third law states that if an object A exerts a force on object B, then object B must exert a force of equal magnitude and opposite direction back on object A.

Let:

A = Hammer

B = Nail

so:

Therefore:

The hammer exerts a force on the nail; the nail exerts a force on the hammer.

Answer: Electromagnetic radiation, such as solar flares and other forms of radiation in space, can disrupt communication tools on a spacecraft in several ways.

First of all, it can obstruct radio signals that the spacecraft uses to connect with Earth, resulting in a signal loss or a decline in the signal's quality. When the radiation disrupts the amplifiers and receivers, which are electronics that process the signals, this can occur.

The spacecraft's computer memory may experience single-event upsets (SEUs) as a result of electromagnetic radiation. A high-energy particle striking a memory cell results in a bit flip and a SEU, which can destroy data, cause software to crash, or create other issues.

The spacecraft's solar panels and other electrical components are susceptible to harm from electromagnetic radiation, which might impair power and communication.

Spacecraft designers frequently use shielding materials and redundant communication systems to reduce the impacts of electromagnetic radiation and make sure the spacecraft can keep operating even if one system fails.

Explanation:

The magnitude of the mean acceleration of the object is 15 m/s^2 when it moves from A to B where AB is a diameter.

Centripetal acceleration is a characteristic of an object's motion along a circular path. Centripetal acceleration applies to any item travelling in a circle with an acceleration vector pointing in the direction of the circle's center.

Given that: uniform speed of the object: v = 10 m/s.

Periodic time: T = 4 second.

Hence,  the magnitude of the centripetal acceleration of the object = 2πv/T

= (2π × 10)/4

= 15 m/s^2.

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Answer: 5. 10 ms-²

Explanation:

Answer: 5. 10 ms-²

Explanation: The magnitude of the mean acceleration of the object when it moves from A to B is equal to the angular acceleration multiplied by the radius of the circular track.

Therefore, the angular acceleration = (2π/T) = (2π/4) = (π/2) rad/s²

The radius of the circular track = 10 m

Therefore, the magnitude of the mean acceleration of the object when it moves from A to B = (π/2) x 10 = 10 ms-²

Answer:

1.  to relate the type of box material to the temperature of the air within the box

2. Question is incomplete

3. scatterplot

Explanation:

1. The only thing done differently in this experiment is the type of material used in making the boxes, hence the experiment must be about that. Before proceeding to answering this question, we must have this at the back of our minds.

We can gather from the experiment that the boxes are of the same size and were subjected to sunlight for an hour (the same time duration for both). Hence, the temperature of the air inside the box will only be affected by the type of material the box is made of since the boxes have the same size and were subjected to sunlight for the same duration.

From the options provided, the best description for this experiment is; to relate the type of box material to the temperature of the air within the box.

2. The question is incomplete. The value for speed/velocity needed to calculate the average time is missing.

However, the formula needed here is velocity = distance ÷ time

3. There are two variables in this experiment; distance and time

The type of graph that shows two variables on it (of the options provided) is the scatterplot.

The correct option is (b) We can measure radiative energy directly and infer thermal energy from models. Protostars do not lose all their gravitational potential energy to thermal energy, so we can derive the amount left for radiative energy.

In the case of a protostar, we can directly measure the radiative energy it emits through observations and measurements of its electromagnetic radiation. This includes studying the protostar's spectrum and intensity at different wavelengths. By analyzing the emitted radiation, astronomers can determine the amount of radiative energy being lost from the protostar's surface.

On the other hand, the thermal energy inside the protostar is not directly measurable. However, through theoretical models and calculations, scientists can infer the amount of thermal energy present in the protostar.

These models take into account parameters such as the protostar's mass, radius, temperature, and composition, among other factors. By considering the laws of conservation of energy and the physical processes occurring within the protostar, scientists can estimate the thermal energy content based on the observed radiative energy and other known properties of the star.

Therefore, we can directly measure the radiative energy emitted by the protostar and infer the thermal energy remaining inside the star using models and theoretical considerations.

Hence, b) We can measure radiative energy directly and infer thermal energy from models is the correct answer.

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Complete question :

The amount of thermal energy inside a protostar increases with time, even though the protostar is losing radiative energy from its surface. How can we tell how much radiative energy the protostar is losing and how much thermal energy remains in the star? Which type of energy can we measure and which type do we infer from the law of conservation of energy?

a. We can measure thermal energy directly and radiative thermal energy from models. Protostars do not lose all their gravitational potential energy via radiation, so we can derive the amount left for thermal energy.

b. We can measure radiative energy directly and infer thermal energy from models. Protostars do not lose all their gravitational potential energy to thermal energy, so we can derive the amount left for radiative energy.

c. We can measure radiative energy directly and infer thermal energy from models. Protostars do not lose all their gravitational potential energy via radiation, so we can derive the amount left for thermal energy.

d. We can measure thermal energy directly and infer radiative energy from models. Protostars do not lose all their gravitational potential energy to thermal energy, so we can derive the amount left for radiative energy.

\(\\ \sf\longmapsto Speed=\dfrac{Distance}{Time}\)

\(\\ \sf\longmapsto Time=\dfrac{Distance}{Speed}\)

\(\\ \sf\longmapsto Time=\dfrac{5000}{5}\)

\(\\ \sf\longmapsto Time=1000s\)

Answer:

If the mass of the Earth is increased by a factor of 2, then the Fgrav is increased by a factor of 2.

If the mass of the earth is increased by a factor of 3, then Fgrav is increased by a factor of 3.

If the mass of the earth is decreased by a factor of 4, then the Fgrav is decreased by a factor of 4

Explanation:

In order to solve this question, we must take into account that the force of gravity is given by the following formula:

\(F_{g0}=G \frac{mM_{E0}}{r^{2}}\)

So if the mass of the earth is increased by a factor of 2, this means that:

\(M_{Ef}=2M_{E0}\)

so:

\(F_{gf}=G \frac{2mM_{E0}}{r^{2}}\)

Therefore:

\(\frac{F_{gf}}{F_{g0}}=\frac{G \frac{2mM_{E0}}{r^{2}}}{G \frac{mM_{E0}}{r^{2}}}\)

When simplifying we end up with:

\(\frac{F_{gf}}{F_{g0}}=2\)

so if the mass of the Earth is increased by a factor of 2, then the Fgrav is increased by a factor of 2.

If the mass of the earth is increased by a factor of 3

So if the mass of the earth is increased by a factor of 2, this means that:

\(M_{Ef}=3M_{E0}\)

so:

\(F_{gf}=G \frac{3mM_{E0}}{r^{2}}\)

Therefore:

\(\frac{F_{gf}}{F_{g0}}=\frac{G \frac{3mM_{E0}}{r^{2}}}{G \frac{mM_{E0}}{r^{2}}}\)

When simplifying we end up with:

\(\frac{F_{gf}}{F_{g0}}=3\)

so if the mass of the Earth is increased by a factor of 3, then the Fgrav is increased by a factor of 3.

If the mass of the earth is decreased by a factor of 4

So if the mass of the earth is decreased by a factor of 4, this means that:

\(M_{Ef}=\frac{M_{E0}}{4}\)

so:

\(F_{gf}=G \frac{mM_{E0}}{4r^{2}}\)

Therefore:

\(\frac{F_{gf}}{F_{g0}}=\frac{G \frac{mM_{E0}}{4r^{2}}}{G \frac{mM_{E0}}{r^{2}}}\)

When simplifying we end up with:

\(\frac{F_{gf}}{F_{g0}}=\frac{1}{4}\)

so if the mass of the Earth is decreased by a factor of 4, then the Fgrav is decreased by a factor of 4.

Answer:

The radius of the new planet is ~2.04 * 10⁶ m, or 2,041,752 m.

Explanation:

We can use Newton's Law of Universal Gravitation:

Let's look at Newton's 2nd Law:

We can set these equations equal to each other:

The mass of the second mass (astronaut) cancels out. We are left with:

We are solving for the radius of the new planet, so we can rearrange the equation:

Substitute in our known values given in the problem (G = 6.67 * 10⁻¹¹ ; M = 7.5 * 10²³ ; a = 12).

The radius of the new planet is ~2.04 * 10⁶ m.

Answer:21

Explanation:every body said

The position of the mass as a function of time is given by x(t) = 0.4sin(3t + φ), where φ is the phase constant.

In this mass-spring system, the driving force applied to the mass is given by f(t) = 5sin(3t) N. The equation of motion for a mass-spring system without air resistance is given by the second-order linear differential equation:

\(m * d^2x/dt^2 + k * x = f(t)\)

where m is the mass (4.5 kg), k is the spring constant (0.5 N/m), and x(t) represents the displacement of the mass from the equilibrium position.

To solve the equation, we assume the solution to be of the form x(t) = A * sin(ωt + φ), where A is the amplitude, ω is the angular frequency, and φ is the phase constant. Substituting this solution into the equation of motion and comparing the coefficients of sin(ωt) on both sides, we can determine the values of A and φ.

Given that the displacement of the mass is 0.4 m, we can deduce that A = 0.4. The angular frequency ω is determined by ω = sqrt(k / m).

Plugging in the given values of k and m, we get ω = sqrt(0.5 / 4.5). With these values, we can now express the position of the mass as a function of time:

x(t) = 0.4sin(ωt + φ)

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A good leaving group favors SN1 reactions.

A good leaving group is defined as a species that is readily displaced from a substrate by a nucleophile. A good leaving group should have a low bond dissociation energy and be a stable species. In SN1 reactions, the rate-determining step involves the formation of a carbocation intermediate, which is why a good leaving group is favored in these reactions. The carbocation intermediate is stabilized by a good leaving group, which makes the reaction more favorable and increases the reaction rate.

In contrast, SN2 reactions are characterized by a direct attack of the nucleophile on the substrate without an intermediate step, and the rate of the reaction is determined by the concentration of both the substrate and the nucleophile. A good leaving group is less important in SN2 reactions since the reaction does not involve an intermediate species.

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Answer:

The bulb consumes electrical energy at the rate of 500 Watts

1 Watt = 1 Joule/sec  where the joule is the unit of energy

Electric energy is often expressed in kw-hrs

This means that 1 kilowatt of power is used for 1 hour

1 kw-hr = 1000 joules/sec * 3600 sec = 3.6E6 joules of energy

Data streams are continuous flows of data that can be used to capture, process, and analyze real-time information.

Data streams are typically handled by streaming data processing engines. These engines process and analyze the data as soon as it arrives, allowing for real-time insights and decision-making.

They are used to capture data from a variety of sources, such as sensors, web services, databases, and other online sources.

Data streams are handled in real-time, meaning that they are processed and analyzed as soon as they arrive.

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Answer:

Explanation:

Fascia is loose connective tissue that surrounds and interpenetrates all components of the human body including muscles, nerves, blood vessels, and organs. It provides structural integrity, serves as a matrix for intercellular communication, and is involved in biochemical and bioelectric signaling.

Answer:

Mass = 58.98 kg

Explanation:

Given the following data;

Velocity = 40.3 km/h to meters per seconds (m/s) = 40.3*1000/3600 = 11.19 m/s

Momentum = 660kgm/s

To find the mass;

Momentum can be defined as the multiplication (product) of the mass possessed by an object and its velocity. Momentum is considered to be a vector quantity because it has both magnitude and direction.

Mathematically, momentum is given by the formula;

\( Momentum = mass * velocity \)

Substituting into the equation, we have

660 = mass * 11.19

Mass = 660/11.19

Mass = 58.98 kg

According to the question,

We know,

→ \(Momentum = Mass\times Velocity\)

or,

→ \(Mass = \frac{Momentum}{Velocity}\)

By substituting the values, we get

             \(= \frac{660}{11.19}\)

             \(= 58.98 \ kg\)

Thus the above answer is right.

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Answer:

Saturn

Explanation:

Saturn has the most spectacular ring system, with seven rings and several gaps and divisions between them.

Answer: Eridani B2 appears only \(6.73\)×\(10^{-13}\) as bright as the sun.