Answer:
1000 kg
Explanation:
Force = mass x acceleration, Hence, mass = Force/acceleration
mass = 4000/4 = 1000 kg
A 2 000-kg sailboat experiences an eastward force of 4 500 N by the ocean tide and a wind force against its sails with magnitude of 1 500 N directed toward the northwest (45° N of W). What is the direction of the resultant acceleration?A. 27° N of WB. 58° N of WC. 27° N of ED. 17° N of WE. 17° N of E
The direction of the resultant acceleration is 17° North of West. The correct answer is D. The first step is to break down the forces into their horizontal and vertical components.
The eastward force from the ocean tide is purely horizontal, while the wind force has both horizontal and vertical components. To find the horizontal component, we use the cosine of the angle between the force and the horizontal axis:
1500 N * cos(45°) = 1060 N
To find the vertical component, we use the sine of the angle:
1500 N * sin(45°) = 1060 N
So the total horizontal force acting on the sailboat is:
4500 N + 1060 N = 5560 N
And the total vertical force is:
1060 N
To find the direction of the resultant acceleration, we can use trigonometry to find the angle that the acceleration vector makes with the horizontal axis. The tangent of this angle is equal to the vertical component of the acceleration divided by the horizontal component:
tan(θ) = 1060 N / 5560 N
θ = tan^-1(1060/5560) = 10.9°
Therefore, the direction of the resultant acceleration is 17° North of West. The correct answer is D.
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How are amplitude modulation and frequency modulation techniques similar?
O Both are used by cell phones to produce images.
O Both transform electrical signals into sound waves.
O Both modify the pulse of a carrier wave.
O Both are used by radio stations to transmit sound.
Answer:
D. Both are used by radio stations to transmit sound.
Explanation:
suppose someone would like to lease state-owned lands for oil and gas production. with whom should they negotiate?
If someone would like to lease state-owned lands for oil and gas production, they should negotiate with the appropriate government agency responsible for managing the lands.
In the United States, this agency is typically the Bureau of Land Management (BLM), which manages millions of acres of federal lands, including lands with potential for oil and gas development. The BLM offers competitive leasing programs that allow individuals and companies to bid on leasing rights for specific parcels of land. The leasing process typically involves submitting an application, conducting an environmental analysis, participating in a lease sale auction. Ultimately, negotiation and leasing of state-owned lands for oil and gas production is subject regulations and oversight by government agency responsible for managing lands.
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Which ball will push the cup a greater distance?
Answer:
Ball A will push the cup further : Letter C
Explanation:
The ball is at more of an angle and will get pulled down fast by gravity
A 250-kg moose stands in the middle of the railroad tracks in Sweden, frozen by the lights of an oncoming 10,000kg train traveling at 20m/s. Even though the engineer attempted in vain to slow the train down in time to avoid hitting the moose, the moose rides down the remaining track sitting on the train’s cowcatcher. What is the final velocity of the train and moose after the collision?
(Momentum & Impulse)
Answer:
The final velocity of the train and the moose after collision is approximately 19.51 m/s
Explanation:
The given mass of the moose, m₁ = 250 kg
The velocity of the moose, v₁ = 0
The mass of the oncoming train, m₂ = 10,000 kg
The velocity of the train, v₂ = 20 m/s
The velocity of the moose and the train after collision = v₃
By the principle of conservation of linear momentum, the total initial momentum before the collision = The total final momentum after collision
m₁·v₁ + m₂·v₂ = (m₁ + m₂)·v₃
Therefore, by substitution, we have;
250×0 + 10,000× 20 = (10,000 + 250) × v₃
200,000 = 10,250 × v₃
v₃ = 200,000/10,250 ≈ 19.51 m/s
The final velocity of the train and the moose after collision = v₃ ≈ 19.51 m/s
difference between sold and liquid
Explanation:
Solids have closely packed particles and vibrate about a fixed position, they also have a fixed volume.
liquid have close particles but which are able to move with a bit of kinetic energy, for this reason they have no fixed volume but take the volume of the container or vessel
the first qstn plsss
answer:
the first one
Explanation:
i think it is this one because 4k is bigger than 2k . also it is asking which one has the lager magnitude so it is the first one
How much work must be done to stop a 925-kg car
traveling at 95 km/h?
Question 42 Marks: 1 Beta particles can be stopped by a few millimeters of aluminum.Choose one answer. a. True b. False
a. True. Beta particles are high-energy electrons or positrons that can be stopped by thin layers of materials such as aluminum, which can block them after a few millimeters.
Beta particles, which are high-energy electrons emitted from some radioactive elements, can be blocked by a few millimeters of aluminum. Aluminum is an effective shield because of its high atomic number and because it is a good conductor of electricity. The aluminum absorbs the beta particle, preventing it from traveling any further. In addition, because aluminum is a good conductor of electricity, it helps to dissipate the energy of the beta particle, diminishing its power.
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How do the sperm cells of nonvascular plants reach the egg cells during reproduction?
A.) The sperm cells are forcefully ejected from their capsules to hit the egg cells.
B.) The sperm cells are blown by the wind and land on the egg cells.
C.) The sperm cells swim to the egg cells through their watery surroundings.
Answer:
C.) The sperm cells swim to the egg cells through their watery surroundings.
a 5.4 kg cat and a 2.5 kg bowl of tuna fish are at opposite ends of the 4.0-m-long seesaw
The 3.6 kg cat must stand approximately 9.82 m to the left of the pivot to balance the seesaw.
Seesaw - A seesaw is a long, narrow board with a central pivot point, sometimes referred to as a teeter-totter. The centre of the board is where a seesaw's pivot point is located. The turning forces on either side of an item that is balanced on a pivot point must be equal to the turning force on the opposite side. The Seesaw makes use of Force ideas.To balance the seesaw, the total torque on both sides of the pivot must be equal. The torque is calculated by multiplying the weight (mass times gravity) of an object by its distance from the pivot.Let's denote the distance of the 5.4 kg cat from the pivot as \(\(d_{\text{cat}_1}\), the distance of the 2.2 kg bowl of tuna fish as \(\(d_{\text{bowl}}\)\), and the distance of the 3.6 kg cat (the unknown we're trying to find) as\(\(d_{\text{cat}_2}\).\)The torque equation can be set up as follows:\(\[ (5.4 \, \text{kg} \times 9.8 \, \text{m/s}^2) \cdot d_{\text{cat}_1} = (2.2 \, \text{kg} \times 9.8 \, \text{m/s}^2) \cdot d_{\text{bowl}} \]\)Simplifying the equation, we have:\(\[ d_{\text{cat}_2} = \frac{5.4 \times d_{\text{cat}_1}}{2.2} \]\)Substituting the given values, we get:\(\[ d_{\text{cat}_2} = \frac{5.4 \times 4.0}{2.2} \approx 9.82 \, \text{m} \]\)Therefore, the 3.6 kg cat must stand approximately 9.82 m to the left of the pivot to balance the seesaw.For more questions on seesaw
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Note: The question would be as
A 5.4 kg cat and a 2.2 kg bowl of tuna fish are at opposite ends of the 4.0-m-long seesaw. How far to the left of the pivot must a 3.6 kg cat stand to keep the seesaw balanced? Express your answer to two significant figures and include the appropriate units.
For the seesaw to be in rotational equilibrium, the mass of the cat (5.4 kg) should be equal to the mass of the bowl of tuna fish (2.5 kg).
To solve this problem, we can apply the principles of torque and rotational equilibrium.
Torque is the product of force and the perpendicular distance from the point of rotation (fulcrum) to the line of action of the force. In rotational equilibrium, the sum of torques acting on an object is zero.
Let's consider the seesaw as a rigid rod of length 4.0 m with a fulcrum in the middle. The cat's weight creates a clockwise torque, while the bowl of tuna fish creates a counterclockwise torque. The torques can be calculated using the formula:
Torque = Force * Distance
The cat's weight (force) is given by:
Force_cat = mass_cat * g
The distance of the cat from the fulcrum is half the length of the seesaw:
Distance_cat = 4.0 m / 2 = 2.0 m
Similarly, the bowl's weight (force) is given by:
Force_bowl = mass_bowl * g
The distance of the bowl from the fulcrum is also half the length of the seesaw:
Distance_bowl = 4.0 m / 2 = 2.0 m
For rotational equilibrium, the sum of torques is zero:
Torque_clockwise = Torque_counterclockwise
(mass_cat * g) * (2.0 m) = (mass_bowl * g) * (2.0 m)
Simplifying the equation:
mass_cat = mass_bowl
Therefore, for the seesaw to be in rotational equilibrium, the mass of the cat (5.4 kg) should be equal to the mass of the bowl of tuna fish (2.5 kg).
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How does a sound wave transfer energy to your ears ?
Answer:
A. Particles in air move in circles as the wave moves forward.
B. Particles in air move forward but not backward as the wave moves
forward.
C. Particles in air move up and down as the wave moves forward.
✔ D. Particles in air move forward and backward as the wave moves
forward.
Explanation:
The waves transfer energy from the source of the sound, e.g. a drum, to its surroundings. Your ear detects sound waves when vibrating air particles cause your ear drum to vibrate. The bigger the vibrations the louder the sound.
Answer:
Sound waves travel at 342 m/s through the air and faster through liquids and solids. The waves transfer energy from the source of the sound, e.g. a drum, to its surroundings. your ear detects sound waves when vibrating air particles cause your eardrum to vibrate. The bigger vibrations the louder the sound.
Explanation:
What is the force two changed objects exert on one another if they are 9 meters apart and one has a charge of 2.5 x 10^-6 C and the second has a charge 0f 4.5 x 10^-7 C
Answer:
The force exerted between the two charges is 0.0001248N
Explanation:
we will be using Columb's law to solve this problem.
Columb's law explains that the Force between two charged bodies is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.
Mathematically,
\(F = K\frac{Q_1 \times Q_2}{r^2}\)
WHere K = constant of proportionality = \(8.9875 \times 10^9 N m^2/c^2\)
\(F = 8.9875 \times 10^9 \times\frac{2.5 \times10^{-6} \times 4.5 \times 10^{-7}}{9^2}= 0.0001248N\)
The force exerted between the two charges is 0.0001248N
Predict how long it would take for an object to travel 5 m, if it is traveling at an average velocity of 2 m/s.
Answer:
-24650580. maybe I think
Can some one pls answer them asapppp
A) Oil B) Wood C) 0.02J D) 3g E) Gas
For the displacement field u(x,t)=u
i
e
i
with components given below, calculate the full three dimensional strain at the point p=e
1
+2e
2
+10e
3
u
1
=0.1x
1
x
2
u
2
=0.1x
2
+5
u
3
=500
The full three-dimensional strain tensor at the point
\(p = e_1 + 2e_2 + 10e_3\: is\: :\\epsilon =\left[\begin{array}{ccc}0.05x_2&0.05x_1&0\\0.05&0&0\\0&0&0\end{array}\right]\)
To calculate the full three-dimensional strain at the point \(p = e_1 + 2e_2 + 10e_3\), we need to find the components of the strain tensor \(\epsilon_m_n\).
The strain tensor εₘₙ can be calculated using the formula:
εₘₙ = (0.5) * (∂uₘ/∂xₙ + ∂uₙ/∂xₘ)
Given the displacement field u(x, t) with components:
u₁ = 0.1x₁x₂
u₂ = 0.1x₂ + 5
u₃ = 500
We can calculate the components of the strain tensor as follows:
\(\epsilon_1_1 = (1/2) * (\delta u_1/\delta x_1 + \delta u_1/\delta x_1)\\= (1/2) * (0.1x_2 + 0)\\= 0.05x_2\)
\(\epsilon_1_2 = (1/2) * (\delta u_1/\delta x_2 + \delta u_2/\delta x_1)\\= 0.05x_1\)
\(\epsilon _1_3 = (1/2) * (\delta u_1/∂x_3 + \delta u_3/\delta x_1)\\= (1/2) * (0 + 0)\\= 0\)
\(\epsilon_2_1 = (1/2) * (\delta u_2/\delta x_1 + \delta u_1/\delta x_2)\\= (1/2) * (0 + 0.1)\\= 0.05\)
ε₂₃ = (1/2) * (∂u₂/∂x₃ + ∂u₃/∂x₂)
= (1/2) * (0 + 0)
= 0
ε₃₁ = (1/2) * (∂u₃/∂x₁ + ∂u₁/∂x₃)
= (1/2) * (0 + 0)
= 0
ε₃₂ = (1/2) * (∂u₃/∂x₂ + ∂u₂/∂x₃)
= (1/2) * (0 + 0)
= 0
ε₃₃ = (1/2) * (∂u₃/∂x₃ + ∂u₃/∂x₃)
= (1/2) * (0 + 0)
= 0
Therefore, the full three-dimensional strain tensor at the point
\(p = e_1 + 2e_2 + 10e_3\: is\: :\\epsilon =\left[\begin{array}{ccc}0.05x_2&0.05x_1&0\\0.05&0&0\\0&0&0\end{array}\right]\)
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A sound wave takes 0.2 seconds to travel 306 meters.
What is the speed of sound in this material? Through
which of the materials in Figure 24.23 is the wave
traveling?
Answer:
1530 m/s
Explanation:
Given that :
Speed = distance / time
Travel time take = 0.2 s
Distance covered = 306 metres
The speed of sound in the material :
Speed = distance / time = 306 m / 0.2
Speed = 1530 m/s
if air that had a temperature of 20°c and 8.6 g/kg of water vapor is cooled to 5°c and 5g/kg of water vapor, then warmed to 25°c, what will be its water vapor content?
To solve this problem, we can use the concept of relative humidity. The relative humidity (RH) of air is defined as the ratio of the partial pressure of water vapor in the air to the saturation pressure of water vapor at the same temperature, expressed as a percentage. Mathematically, we can write:
RH = (Pv/Ps) x 100%
where Pv is the partial pressure of water vapor, Ps is the saturation pressure of water vapor at the same temperature, and the factor of 100% is used to express the result as a percentage.
Let's use this formula to solve the problem step by step:
We are given that the air has a temperature of 20°C and a specific humidity (i.e., the mass of water vapor per unit mass of dry air) of 8.6 g/kg. We can use a psychrometric chart or a calculator to find that the saturation pressure of water vapor at 20°C is about 2.34 kPa.
Using the definition of relative humidity, we can find the partial pressure of water vapor in the air:
RH = (Pv/Ps) x 100%
8.6 = (Pv/2.34) x 100%
Pv = 0.204 kPa
So the partial pressure of water vapor in the air at 20°C is 0.204 kPa.
We are told that the air is cooled to 5°C and its specific humidity decreases to 5 g/kg. We can repeat the same calculation as before to find the new partial pressure of water vapor:
RH = (Pv/Ps) x 100%
5 = (Pv/0.87) x 100% (The saturation pressure of water vapor at 5°C is about 0.87 kPa.)
Pv = 0.0435 kPa
So the partial pressure of water vapor in the air at 5°C is 0.0435 kPa.
Finally, we are told that the air is warmed back up to 25°C. We can use the same saturation pressure value as before (2.34 kPa) to find the new specific humidity:
RH = (Pv/Ps) x 100%
(Pv/2.34) x 100% = RH at 25°C
RH at 25°C = RH at 20°C
So the relative humidity remains constant during the warming process. Therefore, the partial pressure of water vapor in the air at 25°C is:
Pv = RH at 25°C x Ps
= RH at 20°C x Ps
= (0.204/2.34) x 2.34
= 0.204 kPa
Thus, the partial pressure of water vapor in the air at 25°C is the same as at 20°C, and its specific humidity is given by:
specific humidity = Pv/(p - Pv) = 0.204/(101.3 - 0.204) = 0.00202 kg/kg
Therefore, the water vapor content of the air at 25°C is 0.00202 kg of water vapor per kg of dry air.
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HElp ASAP! Select all examples of vectors.
a
Force
b
Speed
c
Velocity
d
Acceleration
e
Magnitude
f
Momentum
Answer:
A . Force
C . Velocity .
D . Acceleration .
A plane heads due north at 85 km/h and is being blown due west at 45 km/h. How would you calculate the resultant velocity of the plane?
Group of answer choices
Since the two velocity components are perpendicular we can calculate the resultant velocity using the Kinematic equation. Since the two velocity components are perpendicular we can calculate the resultant velocity using the Pythagorean theorem. Since the two velocity components are parallel we can calculate the resultant velocity using the Pythagorean theorem. Since the two velocity components are parallel we can calculate the resultant velocity using the cosine function
To calculate the resultant velocity of the plane, we would:
Since the two velocity components are perpendicular we can calculate the resultant velocity using the Pythagorean theorem. Since the two velocity components are parallel we can calculate the resultant velocity using the Pythagorean theorem.Thus, the correct options are B and C.
To calculate the resultant velocity of the plane, we need to use the Pythagorean theorem, which states that the square of the hypotenuse of a right-angled triangle is equal to the sum of the squares of the other two sides. The two velocity components of the plane, 85 km/h and 45 km/h, are perpendicular to each other, so we can use the Pythagorean theorem to find the resultant velocity.
The equation for the Pythagorean theorem is:
c² = a² + b²
Where c is the hypotenuse, and a and b are the other two sides. In this case, the hypotenuse is the resultant velocity, and the other two sides are the two velocity components of the plane.
So, the equation becomes:
resultant velocity² = (85 km/h)² + (45 km/h)²
resultant velocity² = 7225 + 2025
resultant velocity² = 9250
resultant velocity = √9250
resultant velocity = 96.17 km/h
Therefore, the resultant velocity of the plane is 96.17 km/h.
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What is Unit and standard unit?
Answer:
The standard quantity with which we carry out the measurement of any physical quantity of the same kind is called a unit.
an adiabatic open feedwater heater in an electric power plant mixes 0.2 kg/s of steam at 100 kpa and 160°c with 10 kg/s of feedwater at 100 kpa and 50°c to produce feedwater at 100 k
Finally, we can solve for the specific enthalpy of the feedwater at 100°C and conclude that the feedwater at 100°C is the desired outcome.
An adiabatic open feedwater heater in an electric power plant is a device that mixes steam and feedwater to produce feedwater at a specific temperature. In this case, 0.2 kg/s of steam at 100 kPa and 160°C is mixed with 10 kg/s of feedwater at 100 kPa and 50°C to produce feedwater at 100°C.
To solve this problem, we can use the principle of energy conservation. The energy gained by the feedwater is equal to the energy lost by the steam.
First, we need to determine the specific enthalpy of the steam and feedwater at their respective temperatures and pressures. We can use steam tables to find these values.
For the steam, at 100 kPa and 160°C, the specific enthalpy is h1.
For the feedwater, at 100 kPa and 50°C, the specific enthalpy is h2.
Next, we can use the mass flow rate of the steam and feedwater to calculate the energy gained by the feedwater.
Energy gained by feedwater = mass flow rate of feedwater * (specific enthalpy of feedwater at 100°C - specific enthalpy of feedwater at 50°C)
Now, we can equate the energy gained by the feedwater to the energy lost by the steam.
Energy lost by steam = mass flow rate of steam * (specific enthalpy of steam at 100°C - specific enthalpy of steam at 160°C)
Since the process is adiabatic (no heat transfer), the energy lost by the steam is equal to the energy gained by the feedwater.
Setting the two equations equal to each other, we can solve for the specific enthalpy of the feedwater at 100°C.
mass flow rate of feedwater * (specific enthalpy of feedwater at 100°C - specific enthalpy of feedwater at 50°C) = mass flow rate of steam * (specific enthalpy of steam at 100°C - specific enthalpy of steam at 160°C)
Finally, we can solve for the specific enthalpy of the feedwater at 100°C and conclude that the feedwater at 100°C is the desired outcome.
Please note that I cannot provide an exact numerical answer without the specific values of the specific enthalpy at different temperatures. However, by following the steps outlined above, you should be able to determine the specific enthalpy of the feedwater at 100°C.
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Astronomers can now report that active star formation was going on at a time when the universe was only 20% as old as it is today. When astronomers make such a statement, how can they know what was happening inside galaxies way back then
Answer:
First, as you may know, the light travels at a given velocity.
In vaccum, this velocity is c = 3x10^8 m/s.
And we know that:
distance = velocity*time
Now, if some object (like a star ) is really far away, the light that comes from that star may take years to reach the Earth.
This means that the images that the astronomers see today, actually happened years and years ago (So the night sky is like a picture of the "past" of the universe)
Also, for example, if an astronomer sees some particular thing, he can apply a model (a "simplification" of some phenomena that is used to simplify it an explain it) and with the model, the scientist can infer the information of the given thing some time before it was seen.
The astronomers could know what was happening inside galaxies way back then by the fact that;
they examine the spectra of galaxies (or the overall colors of galaxies) with the highest redshifts they can find
Astronomers Measure the wavelength of the light that is stretched, so the light is seen as 'shifted' towards the red part of the spectrum by using spectroscopy. This measure is also called redshift.
This invokes a ray of light through a triangular prism that splits the light into various components known as spectrum.
The way the astronomers could use this concept to know what was happening in the galaxies before is by examining the spectra of galaxies that have the highest redshifts.
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017 (part 2 of 2) 10.0 points
Leaving the distance between the 313 kg and
the 536 kg masses fixed, at what distance from
the 536 kg mass (other than infinitely remote
ones) does the 39.3 kg mass experience a net
force of zero?
Answer in units of m.
The distance of 39.3 kg mass from 536 kg mass will be .0567d to have zero force of attraction.
What is Gravitational Force ?The force of attraction between any two bodies is inversely proportional to the square of the distance between them and directly proportional to the product of their masses.
If the cannon is fired after being filled with gunpowder, the following situations could occur.
The gun will fall to Earth in a projectile motion if its speed is low.The cannonball will continue to circle the Earth in a constant orbit if, at that precise height, its speed is equal to the orbital speed.The cannonball maintains an elliptical orbit around the Earth if its speed is more than the orbital velocity but insufficient to escape from it, that is, lower than the Earth's escape velocity.The projectile departs the Earth on a parabolic or hyperbolic trajectory if the speed is equal to escape velocity or greater.The masses are
m₁ = 313 kg
m₂ = 536 kg
m = 39.3 kg
So as per sum if the distance between m₁ and m₂ is d and distance between m and m₂ is s then
The gravitational force between m₁ and m is equal to gravitational force between m and m₂.
\(\frac{G*m\x_{1} *m }{(d-s)\x^{2} } =\frac{G*m\x_{2} *m }{s\x^{2} }\)
⇒ m₁* s² = m₂ * (d-s)²
⇒313s² = 536d² - 1072ds + 536s²
⇒223s² + 536d² - 1072ds = 0
⇒ s = 0.567d
The distance of 39.3 kg mass from 536 kg mass will be .0567d to have zero force of attraction.
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Two vectors of magnitude 3 units and 4 units are at an angle 60degree between them. Find the magnitude of their difference
The magnitude of the difference amongst the two vectors is sqrt (13) units.
Let's call the two vectors A and B. We can use the Law of Cosines to find the magnitude of their difference:
|A - B|^2 = |A|^2 + |B|^2 - 2|A||B|cosθ
where θ is the angle between the two vectors.
Substituting the given values, we get:
|A - B|^2 = (3) ^2 + (4) ^2 - 2(3)(4) cos60°
Simplifying, we get:
|A - B|^2 = 9 + 16 - 12
|A - B|^2 = 13
Taking the square root of both sides, we get:
|A - B| = sqrt (13)
Therefore, the magnitude of the difference between the two vectors is sqrt (13) units.
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rank the light intensity, from largest to smallest, at the point p in the figures.
The light intensity from largest to smallest ranking will be :B > D > A=C > E. where the area is measured on the plane perpendicular to the direction .
In physics, the intensity is the amount of energy that is transmitted per unit area, and the area is measured on a plane perpendicular to the direction that the energy equation will propagate. I = P/ 4(d2), with P denoting power. Let power of 1 bulb equal = P where I = intensity, d = distance at which the intensity must be determined.
case A = I = P / (1) (1) 1 = P case with 2 = P In the situation B = I = 2P/(0.5)2 = 8P C = I = 4P / (2) (2) ^2 = P case Case (1)2 = 3P: D = I = 3P E = I = 2P /(1.5) (1.5) ^2 = 0.8 P
B > D > A=C > E will be the order of light intensity, from greatest to least.
rank the light intensity, from largest to smallest, at the point p in the figures?
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7. Charges flow through wires because of differences in electric
Charges flow through wires because of differences in electric potential, also known as voltage.
What is electric potential?When two points in a circuit have different electric potentials, such as when a battery is connected to a wire, the higher potential at one end of the wire produces an electric field. The electric charges are forced to travel in the direction of lower potential by the force of this electric field. Electrons, which are the most common charges, pass across the wire to produce an electric current.
The force that propels the charges is the electric potential difference, or voltage. It may be described as the "pressure" or "push" that causes the charges to flow through the circuit. The larger the potential difference and voltage, the more force is applied to get the charges to flow.
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How does temperature change from planets to planets in our solar system?
The further a planet is from the Sun, the colder its surface temperatures tend to be. Venus is an exception, since it has the highest surface temperature in our solar system due to its close closeness to the Sun and its thick atmosphere.
What was the temperature of the solar system when the planets first formed?The inner planets are rocky, whereas the outer planets are gaseous, which can be attributed to the early solar system's temperature. The solar system's temperature increased as the gases came together to create a protosun. Temperatures in the inner solar system reached 2000 K, whilst in the outer solar system, it was only 50 K.
The quantity of heat received is just one of many intricate aspects that go into determining the temperature.
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a person riding in an elevator stands on a metric scale. if the mass of the person is 60.0 kg and the elevator accelerates upward with an acceleration of 4.90 m/s2, what is the reading on the scale?
The reading on the scale is 882.6 N when the elevator accelerates upwards with an acceleration of 4.90 m/s².
Given that the mass of a person is 60.0 kg and the elevator accelerates upwards with an acceleration of 4.90 m/s², we have to determine the reading on the scale.
Let F be the force exerted by the scale on the person. Then, by Newton's second law of motion, the net force acting on the person is Fnet= m * a
where m = 60.0 kg is the mass of the person and a = 4.90 m/s² is the acceleration of the elevator. Hence, the net force acting on the person is given by;
Fnet = 60.0 kg * 4.90 m/s²
Fnet = 294.0 N
Therefore, the scale reading is equal to the force exerted by the scale on the person. Since the elevator is accelerating upwards, the force exerted by the scale on the person is greater than the weight of the person, which is the force of gravity acting on the person.
The force of gravity acting on the person is given by;
Fg = m * g, where g = 9.81 m/s² is the acceleration due to gravity. Hence, the force of gravity acting on the person is given by;
Fg = 60.0 kg * 9.81 m/s²Fg = 588.6 N
Therefore, the scale reading is given by the sum of the force of gravity acting on the person and the net force acting on the person;
F = Fg + Fnet
F = 588.6 N + 294.0 N
F = 882.6 N
Thus, the reading on the scale is 882.6 N when the elevator accelerates upwards with an acceleration of 4.90 m/s².
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Which is an example of a chemical change?
A)
glass melts in a furnace
B)
liquid water boils into steam
newspaper decays in a landfill
D)
rain condenses and falls from water vapor in a cloud
Answer:
c
Explanation:
this is because of the fact that the chemical make up of the object is changed. chemical reactions must include a change in substance.
Answer:
the answer is c
Explanation:
a b and d all are phycical changes, only the apearence changes not the chemical makeup