How many significant figures are in the number 1.89 ' 10³?
A. 3
B. 1
C. 4
D. 5
E. 2

Answer:

Feldspars

Explanation:

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One of the pieces of evidence of the big bang theory where that celestial objects are scattered in the universe because of an explosion that supports the idea of the big bang.

The big bang is how astronomers explain the way the universe began.

The evidence that I've gathered from the widget that demonstrates that the universe is expanding is that galaxies and other celestial objects are moving away from each other, which is also one of the evidence of the big bang theory where the celestial objects are scattered in the universe because of an explosion that supports the idea of the big bang.

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Answer:

the molecular formula of the compound is N9O9.

Explanation:

To determine the molecular formula of the compound, we need to know the empirical formula mass of NO. The empirical formula of NO indicates that the compound contains one nitrogen atom and one oxygen atom.

The empirical formula mass of NO can be calculated as:

Empirical formula mass = atomic mass of N + atomic mass of O

Empirical formula mass = 14.01 + 16.00

Empirical formula mass = 30.01

The mass of the compound is given as 276. We can use this information along with the empirical formula mass to calculate the factor by which the empirical formula should be multiplied to obtain the molecular formula.

Factor = Molecular mass / Empirical formula mass

Factor = 276 / 30.01

Factor = 9.198

The molecular formula can be obtained by multiplying the empirical formula by this factor:

Molecular formula = Empirical formula x Factor

Molecular formula = NO x 9.198

Molecular formula = N9O9

Therefore, the molecular formula of the compound is N9O9.

Answer:

1.2 cm^3

Explanation:

5.74 grams of a something occupies a volume of 1.2 cm^3 .

The ratio of argon-40 to potassium-40 two half-lives after the rock has formed is 7:1.

The half-life of a radioactive compound tells us the time needed for half of the atoms of any compound to go through the radioactive decay.

We know that, half-life of potassium-40 is 1.25 billion years because this is how long it takes for half of the number of atoms which are present in the sample to decay to argon-40.

The half-life of potassium-40 which decays by the beta emission is 1.28 × 10⁹ years. The half-life of potassium-40 which decays by the positron emission is 1.19 × 10¹⁰ years.

40 K which naturally occurs decays to the stable 40 Ar which is 11.2%, It happens by the capture of electron and by positron emission. It gets decayed to stable 40 Ca (88.8%) by emission of negatrons. Half-life of 40 K 1.25 x 10⁹ years.

The dating method of potassium-argon is specifically useful in determining the Lava age.

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The correct answer to the given question is option c) Metals.

What were the materials used during the 1960s?

The materials used during the 1960s included metals, ceramics, glasses, semiconductors, polymers, and elastomers.

The 1960s were a period of significant technological advances.

A number of new and innovative materials emerged during this time that would shape the world for decades to com. Metals were the second most used material during the 1960s. During this time, there was significant demand for materials that could withstand high temperatures and pressures, as well as resist wear and tear and corrosion .Metals were used for a wide range of applications, including the construction of aircraft, automobiles, and other machinery.

They were also used in the production of electronic components, such as resistors and capacitors, and for the manufacture of a wide range of consumer goods, from kitchen utensils to jewellery. Metals remain a critical material in today's world, with a wide range of applications in industries ranging from aerospace and automotive to electronics and construction.

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By considering the concept of Faraday's constant and Avogadro's number we can say that one mole of hydrogen is ionized at 13.598V, removing around 6.022 × 10²³ electrons.

To determine the number of electrons removed when ionizing one mole of hydrogen using 13.598V, we can use the formula:

N = (1 mole) * (Avogadro's number)

where N represents the number of particles (in this case, electrons) in one mole of the substance.

Avogadro's number is approximately 6.022 × 10²³ particles/mol.

Therefore, the number of electrons removed can be calculated as:

N = (1 mole) * (6.022 × 10²³ particles/mol)

= 6.022 × 10²³ electrons

Thus, when ionizing one mole of hydrogen using 13.598V, approximately 6.022 × 10²³ electrons are removed.

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Answer:

5.4

Explanation:

V1=5.0

T1=25+ 273=298

V2= z(unknown)

T2=5+273=278

V1/T1 =V2/T2

V2=V1T2/T1

=5*298/278

=5.4

Answer:

1) H - hydrogen - 1.100797

2) HE - helium - 4.00260

3) LI - lithum -6.941

Explanation:

On the periodic table the mass of carbon is reported as 12.01 amu. This is the average atomic mass of carbon. No single carbon atom has a mass of 12.01 amu, but in a handful of C atoms the average mass of the carbon atoms is 12.01 amu.

Answer:

122.74024999999999

Explanation:

Answer:

\(\boxed {\boxed {\sf About \ 123 \ grams \ of \ Mg}}\)

Explanation:

To convert from moles to mass, we need to use the molar mass of the element. This can be found on the Periodic Table. It tells us the grams of magnesium in 1 mole of magnesium.

Use the molar mass as a fraction or ratio.

\(\frac{ 24.305 \ g \ Mg}{1 \ mol \ Mg}\)

Multiply by the given number of moles (5.05)

\(5.05 \ mol \ Mg *\frac{ 24.305 \ g \ Mg}{1 \ mol \ Mg}\)

The moles of magnesium will cancel each other out.

\(5.05 *\frac{ 24.305 \ g \ Mg}{1 }\)

The denominator of 1 can be ignored to create a simple multiplication problem.

\(5.05 *24.305 \ g \ Mg\)

\(122.74025 \ g \ Mg\)

The original measurement (5.05 moles) has 3 significant figures. Therefore we must round our answer to the 3 sig figs. For the number we calculated, that is the ones place.

The 7 in the tenth place tells us to round the 2 to a 3.

\(\approx 123 \ g \ Mg\)

There are about 123 grams of magnesium in 5.05 moles.

The amount of water removed from every kilogram of commercial sea salt would be 27.57 kg.

Seawater contains 3.5% sodium chloride by mass. This means every 1 kg of seawater contains 0.035 kg of sodium chloride.

Sea salt contains about 10% water. This means every 1 kg of sea salt contains 0.1 kg of water.

In order to calculate the amount of water removed from every kilogram of commercial sea salt produced, we need to know the amount of seawater that will give 1 kilogram of sea salt.

We said every 1 kg of seawater contains 0.035 kg of salt. How many 0.035 kg can be found in 1kg?

1/0.035 = 28.57

This means 28.57 kg of seawater would need to be processed in order to have 1 kg of salt. Thus, the amount of water removed can be calculated as:

28.57 - 1 = 27.57 kg

In other words, about 27.57 kg of water is removed for every kilogram of commercial salt produced.

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Answer:

Fertilisers

And also organic compounds

Answer:it is sterilized in the process

Explanation:

There are several factors that can cause a decrease in the rate of dissolution:

Decrease in temperature: As the temperature decreases, the kinetic energy of the particles decreases, and the rate of dissolution also decreases.

Increase in solute concentration: If the solution is already saturated with solute, then adding more solute will cause it to become supersaturated, which can cause a decrease in the rate of dissolution.

Increase in pressure: Increasing the pressure can force more solute into the solution, but it can also cause an increase in the solubility of the solute, which can cause a decrease in the rate of dissolution.

Decrease in surface area: If the solute is in the form of large particles, then breaking it down into smaller particles will increase the surface area available for dissolution and increase the rate of dissolution. Conversely, decreasing the surface area will decrease the rate of dissolution.

Formation of a precipitate: If the solute is capable of forming a precipitate in the solution, then the rate of dissolution may decrease as the solute is removed from the solution and deposited as a solid.

~~~Harsha~~~

Answer: \(1.25dm^3\) of unreacted oxygen is left.

Explanation:

To calculate the moles :

\(\text{Moles of solute}=\frac{\text{given volume}}{\text{Molar Volume}}\)    

\(\text{Moles of} CO_2=\frac{3.60dm^3}{22.4dm^3}=0.161moles\)

\(\text{Moles of} O_2=\frac{7.25dm^3}{22.4dm^3}=0.324moles\)

\(C_3H_8(g)+5O_2(g)\rightarrow 3CO_2(g)+4H_2O(l)\)  

According to stoichiometry :

3 moles of \(CO_2\)  = 5 moles of \(O_2\)  

Thus 0.161 moles of \(CO_2\) =\(\frac{5}{3}\times 0.161=0.268moles\)  of \(O_2\)

moles of \(O_2\)  left unreacted = (0.324-0.268) = 0.056

Volume of \(O_2\) left unreacted = \(moles\times {\text {Molar volume}}=0.056mol\times 22.4dm^3/mol=1.25dm^3\)

Thus \(1.25dm^3\) of unreacted oxygen is left.

The order of alkanes according to their increasing density can be seen below:

This is referred to a hydrocarbon with a single carbon to carbon bond and examples include butane etc.

Its density increases with increasing number of carbon and hydrogen atoms thereby making it the most appropriate choice.

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Answer: Option c

Explanation:

Answer:

The weak acid will give it's H+

Explanation:

If a strong base is added to a buffer, the weak acid will give up its H+ in order to transform the base (OH-) into water (H2O) and the conjugate base: HA + OH- → A- + H2O. Since the added OH- is consumed by this reaction, the pH will change only slightly.

To calculate the mass percent of the acid in the original solution, you must first calculate the moles of acid used in the reaction. Since oxalic acid has a molar mass of 90.03 g/mol, 13.1 g of the acid is equivalent to 0.145 moles of acid.

Then, you can use the moles of acid to calculate the moles of base required to neutralize it. Since 28.05 ml of 0.103 M base was used, this is equivalent to 0.0288 moles of base. Since the reaction involves a 1:2 mole ratio of acid to base, the moles of acid used was twice the moles of base, or 0.145 moles.

Finally, you can calculate the mass percent of the acid in the original solution by dividing the mass of the acid used (13.1 g) by the total mass of the solution (13.1 g + 28.05 ml of 0.103 M base). This gives a mass percent of 32.2%.

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Answer:

wood burning and cookies baking

Explanation:

took the test <333

Answer:

Wood burning and cookies baking

Explanation:

The following formula can be used to determine how many moles of KC1 are present in 1250 mL of 0.75 M KC1: Molarity (M) is equal to the moles of solute per litre of solution.

In this instance, the volume of the solution is 1250 mL, and the molarity of KC1 is 0.75 M. The following formula can be used to determine how many moles of KC1 are present in 1250 mL of 0.75 M KC1: Molarity (M) times the number of litres in the solution equals 0.75 M times (1250 mL/1000 mL/L) or 0.9375 moles of KC1.

Consequently, 0.9375 moles of KC1 are present in 1250 mL of 0.75 M KC1. It is significant to remember that a solution's molarity is a measurement of the amount of a solute present in a given volume of the solution.

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The reaction of Al₂S₃ with Li forms the displaced product Li₂S₃ and Al. The correct formula of the compound with X having one valence electron and Z with 6 valence electrons is XZ₂. The given reaction in the third image is a single replacement reaction and the reaction in the fourth image is double displacement. Options A, B and E are correct for the reaction in fifth image.

In displacement reactions , an atom or group is displaced by other atom or group from a reactant. In double displacement reactions, two group or atoms are displaced between two reactants.

In the reaction between  Al₂S₃ with Li forms the displaced product Li₂S₃ and Al. It is a single displacement reaction.

The element X with 1 valence electron will form a compound with Z having 6 valence electrons with the formula XZ₂. Z needs two electrons to attain octet. Thus two X provides one electron by each to Z.

The reaction of Na metal with HCl producing NaCl and hydrogen gas is a single displacement reaction. Whereas, the reaction between NaCl and MgF2 is double displacement because, both Cl and F atoms are displacing their position.

Sodium phosphate reacts with ferric chloride giving the ferric phosphate precipitate. Here the metals replaces nonmetals and the reaction involves formation of a precipitate. Thus, option A, B and E are correct.

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Answer:Atomic radius gets bigger

Explanation:

Atomic radius bigger because not only do the atoms have more and more protons and neutrons, and thus more mass in general, there is also stronger shielding affect. Shielding affect is when electrons closer to the nucleus block the positive charge from reaching electrons farther from the nucleus, and thus those far electrons are not drawn towards the nucleus as strongly, and spread out more, increasing atomic radius.

a decrease in oxygen levels in the blood during exercise

an artificial light that attracts insects

stimulus is an example of an internal stimulus

 Things like oxygen levels, blood sugar and pH levels, water levels, and internal temperature are examples of internal stimuli. If any of these factors becomes too high or too low, the body will react in order to reestablish homeostasis.

There are both internal and exterior stimuli. One illustration of external stimulation is how your body reacts to drugs. Vital sign alterations brought on by internal body changes are an example of internal stimulation.

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Answer:

When the frozen popsicle sitting outside in the Sun is exposed to warm air, energy will travel between the popsicle and the warm air as follows;

1) Convection current

Heat will be gained by the frozen popsicle by coming into contact with fresh warm air as the air flows around the popsicle while the cooling of the warm air will cause the water vapor in the air to condense and form the visible mist

In turn the popsicle will gain heat resulting in melting of the ice

2) Conduction

As the some of the mist from the air settles on the popsicle, they share their heat resulting further melting of the popsicle

3) Radiation

Radiated heat energy from the Sun is absorbed by the popsicle resulting in the melting of the popsicle

Explanation:

Answer:

Nuclear fission

Explanation:

Even though the equation is not too clear, however, we can see that the uranium nucleus was bombarded with a particle leading to its disintegration to yield other nuclides.

A nuclear fission reaction is one in which a heavier nuclide is bombarded with a particle (usually a neutron) leading to the disintegration of that nuclide into other nuclides with the release of tremendous energy. More neutrons are released in the process to continue the reaction. Hence, it is a chain reaction.

Answer:

Carbon dioxide extinguishes work by displacing oxygen, or taking away the oxygen element of the fire triangle. The carbon dioxide is also very cold as it comes out of the extinguisher, so it cools the fuel as well.