How could the age be interpreted in a rock in which the blocking temperature has been reached?

Answer:

N₂ + 3H₂ → 2NH3

4Fe + 2Cl₂ → 4FeCl

Explanation:

This equations are now balanced

pls rate as brainliest

The density of ammonia gas in the 6.0 L container at a pressure of 820 mm Hg is approximately 0.805 g/L.

To determine the density of ammonia gas (NH3) in a 6.0 L container at a pressure of 820 mm Hg, we need to use the ideal gas law equation, which relates pressure, volume, number of moles, and temperature for a given gas.

The ideal gas law equation is:

PV = nRT

Where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.

Since we are given the pressure (820 mm Hg), volume (6.0 L), and assuming standard temperature and pressure (STP), we can use the values for R (0.0821 L·atm/(mol·K)) and convert the pressure to atm by dividing by 760 (1 atm = 760 mm Hg).

820 mm Hg / 760 mm Hg/atm = 1.08 atm

Now we can rearrange the ideal gas law equation to solve for density (d):

d = (P * M) / (RT)

Where M is the molar mass of ammonia (NH3), which is approximately 17.03 g/mol.

Substituting the values, we have:

d = (1.08 atm * 17.03 g/mol) / (0.0821 L·atm/(mol·K) * 298 K)

Simplifying the equation, we find:

d ≈ 0.805 g/L

Therefore, the density of ammonia gas in the 6.0 L container at a pressure of 820 mm Hg is approximately 0.805 g/L.

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Answer:

C, Diffusion

Explanation:

Sorry If I am wrong, Thanks for letting me answer

(P.S I am Probably right)

The solution of KCl in water will undergo precipitation of KCl crystals as the temperature decreases from 50 °C to 20 °C and then to 34 °C due to the decreasing solubility of KCl in water.

What happens to a solution of KCl in water when cooled from 50 °C to 20 °C and then to 34 °C?

When the solution of KCl in water is cooled from 50 °C to 20 °C, the solubility of KCl in water decreases. As a result, some of the KCl will start to come out of the solution and form solid crystals.

Then, when the temperature of the solution is further decreased from 20 °C to 34 °C, the solubility of KCl in water decreases even further, causing more KCl to come out of the solution and form solid crystals. This is known as precipitation.

The amount of KCl that will come out of the solution depends on the solubility of KCl at the respective temperatures. The solubility of KCl in water is about 34 g/100 mL at 20 °C and about 42 g/100 mL at 34 °C. Therefore, when the solution is cooled from 50 °C to 20 °C, some KCl will come out of solution until the concentration in solution reaches about 34 g/100 mL. Further cooling to 34 °C will cause more KCl to come out of solution until the concentration in solution reaches about 42 g/100 mL.

The exact amount of KCl that will come out of solution can be calculated using thermodynamic models and experimental data on the solubility of KCl in water at different temperatures.

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Answer: 14.0

Explanation: 14.0 is a base. The more basic, the less hydrogen ion concentration.

Answer:

nepal

Explanation:

Answer:

Explanation:

It is necessary to use the Periodic Table of Elements to find the atom with atomic number of 16 and a mass number of 32, that is Sulfur (S).

The correct way to write it is using the mass number of the element, so sulfur can be written as sulfur-32.

This is a stoichiometry problem, where we have an initial amount of reactant and we need to find out how much of the product will we end up with, in order to do that we need to:

1. Set up the properly balanced equation, which the question already provided us

2 H2 + O2 -> 2 H2O

2. See how many moles of reactant there are in the given amount of grams, which we don't have to do since the question already gave us the number of moles of Hydrogen, 6.0 moles

3. Check the molar ratio between the two compounds, which will be 2:2, the same amount of moles of H2 is needed to produce the same amount of moles of H2O, therefore if we have 6 moles of H2, we will also have 6 moles of H2O

4. Calculate how many grams will be equal to the number of moles that we found out, we will do that by calculating the number of moles with the molar mass, 18g/mol

18g = 1 mol

x grams = 6 moles

x = 108 grams of H2O will be produced

For the purpose of the table, everything I write left will be on the top side, everything I write right will be on the bottom

6 moles of H2

2 moles of H2O/2 moles of H2 (H2 will cancel out)

18 grams of H2O/1 mol of H2O (mol will cancel)

108 grams of H2O will be the final answer

Answer:

B

Explanation:

Answer:

B.

Explanation:

customization requires more material, more machine time which can creates a greater impact on the environment in the sense of pollution (travel by the extra employees, creation of custom materials, increased machine running time). Good luck in your studies. Hope this answers your question in full.

Calculating the equilibrium constant (K) for a reaction requires knowing the balanced equation of the reaction. I won't be able to give the exact value of K without the exact reaction equation. However, I can explain how to use the concentrations provided to determine K.

An equilibrium constant statement for the reaction has the general form:

\(K = [C]^c[D]^d / [A]^a[B]^b\)

In this case, let's assume the reaction is:

aA + bB ⇌ cC + dD

Given the initial and equilibrium concentrations of CO and Cl 2, the following values ​​can be applied to the concentrations:

[A] = [CO] (initial concentration)

[B] = [Cl2] (initial concentration)

[C] = [CO] (equilibrium concentration)

[D] = [Cl2] (equilibrium concentration)

Now that the concentration is determined, we can determine the equilibrium constant (K):

\(K = ([C]^c [D]^d) / ([A]^a [B]^b)K = ([CO]^c [Cl2]^d) / ([CO]^a [Cl2]^b)K = ([0.25]^c [0.15]^d) / ([0.79]^a [0.69]^b)\)

The equilibrium constant (K) for the reaction can be obtained by substituting the values ​​of a, b, c and d based on the balanced equation and the specified concentration.

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To graph the function g(x) = f(-x), you can start with the graph of f(x) and then reflect it about the y-axis.

To find the graph of the function g(x) = f(-x), we can start with the graph of the function f(x) and then reflect it about the y-axis.

If the graph of f(x) is symmetric with respect to the y-axis, meaning it is unchanged when reflected, then g(x) = f(-x) will have the same graph as f(x).

However, if the graph of f(x) is not symmetric with respect to the y-axis, then g(x) = f(-x) will be a reflection of f(x) about the y-axis.

In either case, the resulting graph of g(x) = f(-x) will be symmetric with respect to the y-axis.

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The decay constant ( λ) tells us the probability of a radioactive nuclide in time. We can relate the decay constant to the half-life of the nuclide by the following equation:

Where λ is the decay constant and t1/2 is the half-life time

We replace the value of λ and we find the half-life time

The half-time of Cobalt-60 is 5.26 years

Answer: 5.26 years

Answer:

i dont knoiwxplanation:

Answer:

D 4,3,2

Explanation:

4 Co + 3 O2 ----> 2 Co2O3

240 g of water (specific heat = 4.186 J/g°C, initial temperature = 20°C) is mixed with an unknown mass of iron (specific heat = 0.444 J/gºC, initial temperature 500°C). When equilibrium is reached,The answer for this would be 69.6

You use q = mcΔT, but you assume aluminum = water and crack for This the final temperature.

We need to look up heat values (c) for aluminum and h20. This will uses 0.901 for aluminum and 4.18 use water

: (10)(130 - T)(0.901) = (200.0)(T - 25 (6)

Hence, The answer for this would be 69.6.  

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Answer:

-11.13 Degree Celsius

Explanation:

Here

Kf for H20 is 1.86 C/m

Mass of ethylene glycol = 27.1/100 * 100 = 27.1 grams

Number of moles of ethylene in 30 grams of ethylene = 27.1 g/molar mass of ethylene glycol = 27.1/62.07 = 0.4366 mol

Mass of water = 100 – 27.1 = 72.9 grams

Molality  = Moles/Mass of water in Kg = 0.4366 /0.0729 = 5.989 m

Melting Point Depression = Kf * Molality = 1.86 *5.989 = 11.13 deg C

Melting point of solution = Melting point of water - Melting Point Depression

= 0 – 11.13 = -11.13 Degree Celsius

The graphs which use axes both labeled with quantitative values and show individual points of data include:

Thus is defined as a pictorial representation of data or variables in an organized or definite manner.

The graphs mentioned above always have each point matching with one value on the x-axis and one value on the y-axis.

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Answer:

The sodium has more moles.

n(Na)=2.09 mole

n(O)=0.999 mole

A new alloy is designed for use in a car radiator. If the 17.6 kg radiator required 8.69 × 105 J of heat to warm from 22.1°C to 155.8°C, the specific heat of the new alloy is 369.2 J /  kg °C.

Specific heat formula is given as :

Q = mcΔT

given that :

mass , m = 17.6 kg

Q = 8.69 × 10⁵ J

ΔT , change in temperature = 22.1 °C - 155.8 °C = 133.7  °C

c = specific heat = ?

Substituting the values in the formula we get:

Q = mcΔT

c = Q / mΔT

c = 8.69 × 10⁵ J / 17.6 kg × 133.7  °C

c = 8.69 × 10⁵ J / 2353.12 kg °C

c = 369.2 J /  kg °C

Thus, A new alloy is designed for use in a car radiator. If the 17.6 kg radiator required 8.69 × 10⁵ J of heat to warm from 22.1°C to 155.8°C, the specific heat of the new alloy is 369.2 J /  kg °C.

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Answer:

4 on the top

He in the middle

2 on the bottom

Explanation:

Correct on plato

The missing of the part of the chemical equation when the two atoms interact is Helium with mass number 4 and atomic number 2.

The two atoms interact with each other as shown by the equation below;

\(^4_2He\)

where;

Thus, the missing of the part of the chemical equation when the two atoms interact is Helium with mass number 4 and atomic number 2.

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Mescaline produces a wide range of psychoactive effects when ingested, including altered perception of reality, hallucinations, and euphoria. It is a powerful psychedelic drug that has been used for centuries by Native American tribes in spiritual ceremonies

Mescaline is a hallucinogenic alkaloid that is derived from the Peyote cactus. Mescaline is a complex organic molecule that can be synthesized in the laboratory from 3,4,5-trimethoxybenzyl bromide in two steps.The first step involves nucleophilic substitution using sodium cyanide, and the second step is a reduction using lithium aluminum hydride (LAH).Here's how mescaline can be synthesized from 3,4,5-trimethoxybenzyl bromide:Step 1: Nucleophilic substitution using sodium cyanideThe reaction of 3,4,5-trimethoxybenzyl bromide with sodium cyanide results in the formation of the nitrile derivative. NaCN serves as the nucleophile in this reaction, and it replaces the bromide ion.The mechanism for this reaction involves the following steps: A nucleophilic attack by the cyanide ion on the benzyl bromide. The carbon-bromine bond breaks, and the benzyl cation is formed. A second nucleophilic attack by the cyanide ion occurs on the benzyl cation, resulting in the formation of the nitrile derivative.Here's the reaction equation for this step:Step 2: Reduction using lithium aluminum hydrideThe next step is the reduction of the nitrile derivative using LAH. LAH serves as a strong reducing agent in this reaction and reduces the nitrile derivative to the amine. The mechanism for this reaction involves the following steps: A nucleophilic attack by LAH on the nitrile derivative. This results in the formation of an imine intermediate. The imine intermediate reacts with another LAH molecule, resulting in the formation of the amine.Here's the reaction equation for this step:Mescaline structure: Mescaline is a psychoactive compound that belongs to the phenethylamine class of alkaloids. The structure of mescaline is as follows: The molecule has three methoxy groups attached to the benzene ring, and it has an amine functional group. The molecule is a white crystalline powder that is soluble in water and alcohol.

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The answer is 1ml. The answer is 1ml because of calibration of this graduated cylinder

Answer:

1 mL

Explanation:

According to your definition, it is the difference between marked spaces divided by the # of spaces between marked values.

Difference between 2 marked values: 5 mL

# Of Spaces between marked values: 5

Calibration: 5 mL / 5 mL = 1 mL

1. The constituent gases of air are:

2. The surrounding air is not seen with the eyes because it is transparent. Air molecules are not visible to the na-ked eye, and they do not scatter or absorb visible light significantly. Therefore, air appears colorless and transparent.

3. To prove that air supports burning, you can perform an experiment with a burning candle. Place a glass jar or bell jar over a lit candle, ensuring that the jar is airtight. As the candle burns, it consumes oxygen from the air inside the jar. Eventually, the candle flame will go out due to the lack of oxygen, proving that air (specifically oxygen) is necessary for burning.

4. To show that air occupies space, you can perform a simple experiment using a plastic bottle or syringe. Fill the bottle or syringe with water, ensuring there are no air bubbles. Then, cover the opening tightly and try to compress the air inside. You will find that it is not possible to compress the air significantly, indicating that air occupies space.

5. To prove that air has weight, you can use a sensitive balance or scale. Weigh an airtight container or balloon, and then fill it with air. The weight of the container or balloon with the added air will be greater than its initial weight, demonstrating that air has weight.

6. Air is useful to us in various ways. Three points highlighting the importance of air are:

7. Three properties of air include:

Air exerts force in various ways. For example, air pressure allows objects like airplanes to fly by providing lift. Air resistance or drag opposes the motion of objects moving through the air, creating a force that can affect their speed and trajectory.

8. Four effects of air pollution include:

9. Causes of pollution:

10. Two control measures for air pollution include:

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The usual enthalpy change for the 200g/7.68 mol of ethyne reaction is C2H6g C2H2g Plus 2H2g - 2,388.5kJ.

The quantity of heat released or absorbed during a reaction occurring at constant pressure is known as the enthalpy change.

H stands for "enthalpy change," Hf for "system final enthalpy" (i.e., the enthalpy of the byproducts of the system in equilibrium in a chemical reaction), and Hi for "system initial enthalpy" (i.e., the entropy for the reactants in a chemical reaction).

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390 g KNO₃

Atomic Structure

Pre-Algebra

Order of Operations: BPEMDAS

Step 1: Define

2.3 × 10²⁴ formula units KNO₃

Step 2: Identify Conversions

Avogadro's Number

Molar Mass of K - 39.10 g/mol

Molar Mass of N - 14.01 g/mol

Molar Mass of O - 16.00 g.mol

Molar Mass of KNO₃ - 39.10 + 14.01 + 3(16.00) = 101.11 g/mol

Step 3: Convert

\(2.3 \cdot 10^{24} \ formula \ units \ KNO_3(\frac{1 \ mol \ KNO_3}{6.022 \cdot 10^{23} \ formula \ units \ KNO_3} )(\frac{101.11 \ g \ KNO_3}{1 \ mol \ KNO_3} )\) = 386.172 g KNO₃

Step 4: Check

We are given 2 sig figs. Follow sig fig rules and round.

386.172 g KNO₃ ≈ 390 g KNO₃

Answer: 20030.41

Explanation:

2-chloroethanol is more acidic than ethanol due to presence of an electron - withdrawing group.

Basically, out of 2-chloroethanol and ethanol, 2-chloroethanol is more acidic in nature tan ethanol due to the presence of an electron withdrawing group i.e., chlorine atom. Due to the presence of the electron withdrawing group it results in negative inductive effect and thus, the electron density in the –O-H bond decreases significantly and the O-H bond present in the 2-chloroethanol becomes weaker than O-H bond present in the ethanol.

This stabilizes the alkoxide ion and therefore, 2-chloroethanol can easily release a proton and becomes more acidic.

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Answer:

\(h=100.8cm\)

Explanation:

Hello,

In this case, considering the density and mass of both water and heptane we first compute the volume of each one:

\(V_{water}=\frac{m_{water}}{\rho _{water}}=\frac{34g}{1.00g/mL}=34mL\\ \\V_{heptane}=\frac{m_{heptane}}{\rho _{heptane}}=\frac{34.6g}{0.684g/mL}=50.6mL\\\)

Now, the total volume is:

\(V=50.6mL+34mL=84.6mL\)

Which is equal to:

\(V=84.6cm^3\)

Then, by knowing that the volume of a cylinder is πr²h or π(D/2)²h, we solve for the height as follows:

\(h=\frac{V}{\pi (D/2)^2} \\\\h=\frac{84.6cm^3}{\pi (3.16cm/2)^2} \\\\h=100.8cm\)

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