For the floor plan shown, if a = sm b= 8m, specify type of Load on Beam AHS
D
B В

Answer:

CMRR(Common Mode Rejection Ratio) is the ratio of differential gain and the common mode gain.

Explanation:

The clause "Provide service in their areas of competence, being honest and forthright about any limitations of their experience and education" can guide a software engineer to make a better choice when deciding which projects to take on and how to communicate their skills and limitations to their clients and employers.

This clause emphasizes the importance of a software engineer's competence and transparency in their professional interactions. By providing service in their areas of expertise, software engineers ensure that they can deliver high-quality work that meets the client's expectations. This helps to build trust and maintain a positive relationship with the client and employer.

Furthermore, being honest and forthright about any limitations in experience and education is crucial for managing expectations and avoiding potential pitfalls. When a software engineer acknowledges their limitations, they can seek appropriate support or resources to overcome them or recommend alternative solutions if necessary.

This approach not only protects the client and employer's interests but also upholds the public interest by promoting ethical and responsible software development practices.

For instance, if a software engineer is offered a project that requires expertise in a programming language they are not familiar with, they can decline the project or express their limitations upfront. This allows the client and employer to make informed decisions and potentially find a more suitable resource for the task.

By following this clause, the software engineer ensures that the client and employer's best interests are upheld while maintaining professional integrity.

In conclusion, the clause encourages software engineers to provide services within their competence and be transparent about their limitations. By adhering to this principle, software engineers can make better choices in project selection and communication, leading to improved outcomes for clients, employers, and the public interest.

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Answer:

For a 1 kWh, heat supplied for the cost of furnace is = $1.66 *1 0^-5 /kJ * 3600 =$0.06/kWh.

Therefore, supplied heat for natural gas furnace is $0.06/kWh which is lower than $0.12/kWh cost of electricity of refrigerator.

Explanation:

Solution

Given that:

The thermal efficiency of furnace = 0.8 or 80%

The cop of refrigerant COP = 3.5

The unit cost of electricity for refrigerant is =$ 0.12kWh

The unit cost of natural gas of furnace is = $1.40/therm

1 therm = 105,500 kJ

Now,

In the summer the usage or utilization of lightening in the house will be lesser than winter, hence the total cost of energy used in the household will be decreased.

Thus,

In winter, the utilization of lightening will be higher with regards to electricity

For a natural gas furnace it is given below:

The unit cost =$1.40/ηth (I therm/105,500)

= 1.40/0.8 (I therm/105,500)

= $1.66 *1 0^-5 /kJ

For a 1 kWh, heat supplied for the cost of furnace is = $1.66 *1 0^-5 /kJ * 3600 =$0.06/kWh.

So,for the heat supplied for natural gas furnace is $0.06/kWh which is less er than $0.12/kWh cost of electricity of refrigerator.

Therefore, the efficiency of energy lightning will reduce the total energy cost of the building both in winter and summer.

Answer: B. Particles of liquids can move from place to

Explanation:

Fast-moving particles transfer energy to slower-moving particles ... The motion of water molecules causes them to leave the liquid and become a gas.

After 4 years, the all-electric car model is more economic due to lower fuel and maintenance costs.

To determine which car model is more economic after 4 years, we need to consider the costs associated with fuel consumption, energy prices, and depreciation.

For the traditional gasoline car, the fuel consumption is given as 7 liters per 100 km, and the fuel price is $0.95 per liter. Assuming a total distance of 22,000 km per year, the annual fuel cost for the gasoline car is calculated as (22,000 km / 100 km) * 7 liters * $0.95.

For the all-electric car, the energy consumption is given as 13 kWh per 100 km, and the energy price is $0.30 per kWh. Using the same distance, the annual energy cost for the electric car is calculated as:

(22,000 km / 100 km) * 13 kWh * $0.30.

Next, we need to consider depreciation. Both cars experience a 10% decrease in market value per year. After 4 years, the market value of each car is calculated by multiplying the original price by \((1 - 0.10)^4.\)

By comparing the total costs, including fuel/energy costs and depreciation, we can determine which car model is more economic over the 4-year period. Considering 0% interest rate, the all-electric car tends to be more economic due to lower fuel/energy costs and potentially lower maintenance costs associated with electric vehicles.

Therefore, the all-electric car model is more economic after 4 years.

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A "baseline" is a formal reference point that measures system characteristics at a specific time.

In project management, a baseline is a predetermined snapshot of a project's scope, schedule, and cost at a specific point in time. It serves as a reference point against which project progress can be measured and compared.

For example, a project manager may create a baseline for a software development project at the beginning of the development phase. This baseline would capture the project's initial scope, schedule, and budget. As the project progresses, the project manager can compare actual progress against the baseline to track the project's progress and identify any deviations from the original plan.

Creating a baseline is an important part of project management because it helps to establish clear goals and expectations, and provides a benchmark against which to measure progress and performance.

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To determine the convection heat flux in each scenario, we can use the formula Q = hA(T_surface - T_surrounding), where Q is the heat flux, h is the convection coefficient, A is the surface area, and T_surface and T_surrounding are the temperatures of the surface and the surrounding medium, respectively.

For scenario (a):
- Vehicle speed: 40 km/h
- Air temperature: -8°C
- Surface temperature: 30°C
- Convection coefficient: 40 W/m²·K

First, we need to convert the vehicle speed from km/h to m/s:
40 km/h = (40 * 1000) m / (60 * 60) s ≈ 11.11 m/s

Next, we can calculate the heat flux:
Q = 40 W/m²·K * A * (30°C - (-8°C))

Now, let's move on to scenario (b):
- Water stream velocity: 0.2 m/s
- Water temperature: 10°C
- Surface temperature: 30°C
- Convection coefficient: 900 W/m²·K

For this scenario, we can calculate the heat flux using the same formula:
Q = 900 W/m²·K * A * (30°C - 10°C)

To determine which condition feels colder, we compare the heat flux values. The higher the heat flux, the faster heat is transferred away from the hand, making it feel colder.

Now, let's compare the heat flux values with the approximate heat flux under normal room conditions (30 W/m²):
- If the heat flux is higher than 30 W/m², the condition would feel colder.
- If the heat flux is lower than 30 W/m², the condition would feel warmer.

To find the convection heat flux, we use the formula Q = hA(T_surface - T_surrounding). By calculating the heat flux for each scenario, we can determine which condition would feel colder by comparing the values with the approximate heat flux under normal room conditions.

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Answer:

Positive logic is defined as a high voltage level representing a logic 1 and a low voltage level representing a logic 0. Negative logic is the reverse, i.e., a low voltage level represents a logic 1 and a high voltage level represents a logic 0.

Explanation:

Thanks

Answer:

Tech A

Explanation:

A faulty vacuum booster can actually affect the operation of an engine. Engine stalls when brakes are applied. And this can happen when the diaphragm that is inside the brake booster fails. The failing thus allows air to bypass the seal. When the brakes are then pressed, the engine will actually feel like it will stall, and the idle will most probably drop. Also, asides a reduction in the break performance quality, a stalling engine is very bad and can result to many negative effects.

To determine the minimum diameter of the component to prevent buckling, we can use the Euler's buckling equation. The Euler's buckling equation states that the critical buckling load (Pcr) is equal to (pi^2 * E * I) / (L^2), where E is the modulus of elasticity, I is the moment of inertia, and L is the effective length of the column.

In this case, since the column has pinned-pinned end conditions, the effective length (L) is equal to the actual length of the column (assuming it is vertical).

To calculate the moment of inertia (I) for a solid and round cross section, we can use the formula I = (pi * d^4) / 64, where d is the diameter of the column.

Given that the factor of safety (FOS) is 1.8, we can rearrange the equation to solve for the minimum diameter (d) as follows:

\(Pcr = (pi^2 * E * I) / (L^2)Pcr = (pi^2 * E * (pi * d^4) / 64) / (L^2)Pcr = (pi^3 * E * d^4) / (64 * L^2)Pcr * FOS = (pi^3 * E * d^4) / (64 * L^2)d^4 = (Pcr * 64 * L^2) / (pi^3 * E * FOS)d = ((Pcr * 64 * L^2) / (pi^3 * E * FOS))^(1/4)\)

Plug in the given values for Pcr (load), L (effective length), E (modulus of elasticity), and FOS (factor of safety) into the equation to find the minimum diameter (d) in inches.

Note: Since you mentioned not using preferred sizes, the diameter calculated may not match a standard size available in the market.

Remember to provide the values for Pcr, L, E, and FOS to get the specific minimum diameter for your component.

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how am I going to do this, I have a friend that might be able to help I will check

For a polymer-polymer blend system (binary mixture), the type of phase separation that can be expected depends on the interactions between the polymers and their miscibility. The following keywords can be used to describe different types of phase separation:

1. USCT (Upper Critical Solution Temperature): In this case, the blend exhibits phase separation upon heating above a specific temperature. Below the critical temperature, the polymers are miscible, but phase separation occurs as the temperature exceeds the USCT.

2. LCST (Lower Critical Solution Temperature): This refers to phase separation occurring upon cooling below a specific temperature. The blend is miscible above the critical temperature, but phase separation occurs as the temperature decreases below the LCST.

3. Spinodal: A spinodal phase separation occurs when the blend is thermodynamically unstable, leading to the spontaneous formation of separate phases without the presence of a distinct critical temperature. This type of phase separation results in the formation of a bicontinuous morphology.

4. Binodal: Binodal phase separation refers to the situation where phase separation occurs at a specific composition and temperature. Above or below this composition and temperature, the blend remains miscible.

5. Droplet: In a droplet phase separation, one polymer forms dispersed droplets within the continuous phase of the other polymer. This occurs when the two polymers have limited miscibility.

6. Bicontinuous: Bicontinuous phase separation results in the formation of interpenetrating and continuous networks of the two polymers. The blend exhibits interconnected phases without a clear distinction between the two.

7. Macrophase separation: Macrophase separation is characterized by the formation of large-scale phase separation, resulting in distinct and separate regions of each polymer. This type of phase separation is more pronounced and easily visible.

The specific type of phase separation observed in a polymer-polymer blend will depend on factors such as the polymer chemistry, molecular weight, interactions, and thermodynamic properties of the polymers involved.

For a polymer-polymer blend system (binary mixture), the type of phase separation that is expected to be observed depends on the specific polymers and their interaction parameters. Here are the descriptions of the keywords you provided:

USCT (Upper Critical Solution Temperature): In a USCT phase separation, the polymer blend remains miscible above a certain temperature but undergoes phase separation as the temperature is lowered below the critical temperature. This results in the formation of two distinct phases.

LCST (Lower Critical Solution Temperature): In an LCST phase separation, the polymer blend remains miscible below a certain temperature but undergoes phase separation as the temperature is increased above the critical temperature. This leads to the formation of two distinct phases.

Spinodal: In a spinodal phase separation, the polymer blend spontaneously undergoes phase separation without the presence of a distinct phase boundary. This results in the formation of a continuous network structure or a bicontinuous morphology.

Binodal: In a binodal phase separation, the polymer blend undergoes phase separation with the formation of distinct droplet-like regions dispersed in a continuous phase. The phase separation occurs along a specific composition range.

Droplet: In a droplet phase separation, the polymer blend forms distinct droplets or domains of one polymer dispersed in a continuous phase of the other polymer. This can occur when the blend has a limited miscibility or the interaction between the polymers is unfavorable.

Bicontinuous: In a bicontinuous phase separation, the polymer blend forms a network-like structure with two continuous phases interpenetrating each other. This can occur when the blend has a high degree of miscibility or when the polymers have a specific compatibility.

Macrophase separation: In a macrophase separation, the polymer blend undergoes phase separation on a larger scale, resulting in the formation of macroscopic regions or domains of each polymer. This can occur when the blend has a limited miscibility or when there are significant differences in the properties of the polymers.

The specific type of phase separation observed in a polymer-polymer blend system depends on factors such as polymer composition, molecular weight, interaction parameters, and processing conditions. Experimental characterization techniques, such as microscopy, scattering methods, and thermal analysis, are often used to determine the nature of phase separation in polymer blends.

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Answer:

a). 139498.24 kg

b). 281.85 ohm

c). 10.2 ohm

Explanation:

Given :

Diameter, d = 22 m

Linear strain, \($\epsilon$\) = 3%

                        = 0.03

Young's modulus, E = 30 GPa

Gauge factor, k = 6.9

Gauge resistance, R = 340 Ω

a). Maximum truck weight

σ = Eε

σ = \($0.03 \times 30 \times 10^9$\)

\($\frac{P}{A} =0.03 \times 30 \times 10^9$\)

\($P = 0.03 \times 30 \times 10^9\times \frac{\pi}{4}\times (0.022)^2$\)

 = 342119.44 N

For the four sensors,

Maximum weight = 4 x P

                            =  4 x 342119.44

                            = 1368477.76 N

Therefore, weight in kg is \($m=\frac{W}{g}=\frac{1368477.76}{9.81}$\)

                     m = 139498.24 kg

b). Change in resistance

\(k=\frac{\Delta R/R}{\Delta L/L}\)

\($\Delta R = k. \epsilon R$\)    , since \($\epsilon= \Delta L/ L$\)

\($\Delta R = 6.9 \times 0.03 \times 340$\)

\($\Delta R = 70.38 $\) Ω

For 4 resistance of the sensors,

\($\Delta R = 70.38 \times 4 = 281.52$\) Ω

c). \($k=\frac{\Delta R/R}{\epsilon}$\)

If linear strain,

\($\frac{\Delta R}{R} \approx \frac{\Delta L}{L}$\)  , where k = 1

\($\Delta R = \frac{\Delta L}{L} \times R$\)

\($\Delta R = 0.03 \times 340$\)

\($\Delta R = 10.2 $\) Ω

Answer:

the lead of a 1/2 inch diameter drill with a 118 degree included angle is approximately 0.661 inches.

Explanation:

The lead of a drill bit is the distance that the bit advances axially for each complete revolution. The formula for lead is:

lead = (π / tan(θ)) x d

where:

- π is the mathematical constant pi (approximately 3.14159)

- θ is the included angle of the drill bit (in radians)

- d is the diameter of the drill bit

In this case, the diameter of the drill bit is given as 1/2 inch. We need to convert this to inches:

d = 1/2 inch = 0.5 inches

The included angle of the drill bit is given as 118 degrees. We need to convert this to radians:

θ = 118 degrees x (π / 180 degrees) = 2.058 radians

Now we can use the formula to calculate the lead:

lead = (π / tan(θ)) x d

= (π / tan(2.058)) x 0.5

≈ 0.661 inches

Therefore, the lead of a 1/2 inch diameter drill with a 118 degree included angle is approximately 0.661 inches.

It should be noted that to construct the expression tree from postfix expression we use below stack based algorithm.

In this case, each element in the stack is a node of the binary tree with the character value of postfix expression:

Algorithm:

1.Start traversing the expression from left to right

2.If current character is operand

Push it in the stack

3.If current character is operator

Pop first two values from the stack and make them the right and left child consecutively of the operator and push this operator node to the stack.

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To find the tension in the string and the acceleration of the block, we can use the equations of motion for the system.

Assuming the mass of the block M1 is 1500N and the mass of the block M2 is 1000N, the equation of motion for the system is given by:

T - μMgcos(θ) = M1a + M2a

Where T is the tension in the string, μ is the coefficient of friction between the block M1 and the inclined plane, Mg is the weight of the blocks, θ is the angle of the inclined plane, and a is the acceleration of the blocks.

Substituting the given values, we get:

T - 0.2(1500 + 1000)9.81cos(45°) = 1500a + 1000a

Simplifying, we get:

T = 6715N - 3000a

Solving for a, we get:

a = (6715 - T)/3000

Therefore, the acceleration of the block is given by (6715 - T)/3000, where T is the tension in the string.

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Answer:

70%

Explanation:

The type of bias present in the above example is called "selection bias" or "sampling bias."

Sampling bias happens when the information used to teach or create something does not accurately represent all the people or things it is meant to. This selection bias means that the algorithm may not work well or give accurate results when used on people who do not speak English as their first language.

In detecting Alzheimer's disease by analyzing how people talk, this bias might cause wrong or limited results when used on people who speak different languages.

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Answer:

  239 mL

Explanation:

The average of any set of data is the sum of the values, divided by their number.

  v = (240 +242 +235)/3 = 717/3 = 239 . . . mL

The average of the three measurements is 239 mL.

Determining the amount of aluminum required to achieve a specific dislocation length is not possible without more information on crystal structure and material dimensions.

The amount of aluminum required to achieve a specific dislocation length cannot be determined based on the information provided. The dislocation density of 10^12 m/m^3 only provides information on the concentration of dislocations in the material, but it does not give any information on the actual length of the dislocations. Additionally, the comparison to the distance between New York City and Oklahoma is not relevant in this context, as dislocations are three-dimensional structures within the material and not a two-dimensional line. To determine the total dislocation length, one would need to know the crystal structure and dimensions of the material in question.

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The pressure of seawater will be 2.14*107 N/m2 and the density will be 8.53*103 kg/m3.

Pressure is a type of force applied to an object by another object over a surface area. Pressure is measured in units of force per unit area and is usually expressed in terms of pascals (Pa).

The bulk modulus of elasticity, K, is a measure of the stiffness of a material and is defined as the ratio of bulk stress to the resulting strain. In this problem, we need to calculate the density and pressure at a depth of 2500 m, based on the given bulk modulus and 98 kPa pressure at the surface.
To solve this problem, we will use the equation K = -dp/dρ, where dp is the change in pressure with depth and dρ is the change in density with depth. Since we are given the bulk modulus and pressure on the surface, we can calculate the change in density with depth as follows:
dρ = -K*dp/dz
where dp = rgdz and rg is the gravity of the Earth. Substituting these values, we get:
dρ = -2.34*109*98*103/(9.8*2500) = -7.78*103 kg/m3
This means that for every metre of depth, the density of seawater decreases by 7.78*103 kg/m3. Therefore, at a depth of 2500 m, the density of seawater will be:
ρ = 1030 - 7.78*103*2500 = 8.53*103 kg/m3
Similarly, we can calculate the pressure at a depth of 2500 m using the equation P = P0 + rgdz, where P0 is the pressure at the surface. Substituting the values, we get:
P = 98*103 + 9.8*2500*8.53*103 = 2.14*107 N/m2
Therefore, at a depth of 2500 m, the pressure of seawater will be 2.14*107 N/m2 and the density will be 8.53*103 kg/m3.

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1. Jobs arrived ready for processing by the time the first job is finished or first interrupted:

a. FCFS (First-Come, First-Served):

  Job A will have arrived ready for processing by the time the first job is finished.

b. SJN (Shortest Job Next):

  Job B will have arrived ready for processing by the time the first job is finished.

c. SRT (Shortest Remaining Time):

  Job B will have arrived ready for processing by the time the first job is finished.

d. Round Robin:

  Job A, Job B, and Job C will have arrived ready for processing by the time the first job is interrupted.

2. Start time and finish time for each job using different scheduling algorithms:

a. FCFS (First-Come, First-Served):

  Job A: Start Time = 0, Finish Time = 15

  Job B: Start Time = 15, Finish Time = 17

  Job C: Start Time = 17, Finish Time = 31

  Job D: Start Time = 31, Finish Time = 41

  Job E: Start Time = 41, Finish Time = 42

b. SJN (Shortest Job Next):

  Job A: Start Time = 0, Finish Time = 15

  Job B: Start Time = 2, Finish Time = 4

  Job C: Start Time = 4, Finish Time = 18

  Job D: Start Time = 18, Finish Time = 28

  Job E: Start Time = 28, Finish Time = 29

c. SRT (Shortest Remaining Time):

  Job A: Start Time = 0, Finish Time = 15

  Job B: Start Time = 2, Finish Time = 4

  Job C: Start Time = 4, Finish Time = 18

  Job D: Start Time = 18, Finish Time = 28

  Job E: Start Time = 28, Finish Time = 29

d. Round Robin (Time Quantum = 5):

  Job A: Start Time = 0, Finish Time = 15

  Job B: Start Time = 2, Finish Time = 7

  Job C: Start Time = 7, Finish Time = 21

  Job D: Start Time = 15, Finish Time = 25

  Job E: Start Time = 21, Finish Time = 22

Please note that the timeline representation and precise calculation of start and finish times may vary depending on the specific implementation of the scheduling algorithm and any additional considerations or constraints. The above calculations provide a general understanding of the job scheduling process using the given information and algorithms.

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The capitalized cost of the permanent roadside historical marker is $116,386.30.

Capitalized cost

The capitalized cost is an assessment of the cost of the investment. Capitalized cost is a useful metric in cost accounting, particularly in the case of business assets. In the case of permanent roadside historical markers, we need to calculate the capitalized cost given the first cost and maintenance cost of $90,000 and $3,100 respectively that is done every 5 years.

Assuming the interest rate of 10% per year. We can use the following formula to calculate the capitalized cost.

C = P * (i / (1 - (1 + i)^(-n)))

Where,

C = Capitalized cost

P = First cost

i = Interest rate per year

n = Total number of years

To calculate the capitalized cost of the permanent roadside historical marker, we need to calculate the present value of the investment. We are given that the first cost of the historical marker is $90,000 and the maintenance cost of $3,100 is incurred once every 5 years at an interest rate of 10% per year.

The total number of years n = 20 years (4 maintenance cycles of 5 years each).

Therefore, using the formula, we have,

C = $90,000 + $3,100 * (PVIFA10%,20)

$3,100 * (PVIFA10%,20) = 8.513 (calculated using Excel or tables)

C = $90,000 + $3,100 * 8.513

C = $90,000 + $26,386.30 = $116,386.30.

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Engineer's approvall makes it appropriate to alter from the drawing

Engineering drawing is a document that contain the design of an engineer represented in a sketch.

deviating fron the drawing is same as deviating from the design. it is therefore necessary to call the engineers attention before altering the drawing.

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Answer:

Well there are a lot of delicious food in the philppines but my most favorite is the Lechon, Adobo, Sisig, Chicken Curry, Crispy pata and Sinigang

(a) For iD = 100μA, vGS = 1.3 V and vDS = 0.4 V. (b) For iD = 50μA (with constant vGS), vDS = 0.5 V. To find the values of vGS and vDS that result.

The MOSFET operating at the edge of saturation with a given drain current (iD), we can use the following equations: (a) For iD = 100μA: vGS = vGSth + sqrt(2μnCox(iD - 0.5μnCox(vGSth)^2)) = 1.3 V vDS = vDSsat = vGS - vGSth = 0.4 V Here, vGSth represents the threshold voltage of the MOSFET, Cox is the gate oxide capacitance per unit area, and μn is the electron mobility. (b) For iD = 50μA (with constant vGS): vDS = vGS - vGSth = 0.5 V In both cases, the threshold voltage (vGSth) and other process technology parameters are assumed to be given. By using the provided process technology specifications and the given drain current, we can calculate the required values of vGS and vDS for the MOSFET to operate at the desired conditions. These values are crucial for determining the operating characteristics and performance of the MOSFET in the given process technology.

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The refrigerant blends that are approved for use in MVAC systems can never be topped off never be recycled and re-charged into a system. The correct option is d.

Refrigeration is used in motor vehicle air conditioning (MVAC) equipment to cool the driver's or passenger's compartment. Section 609 of the Clean Air Act governs the maintenance of these systems.

The United States Environmental Protection Agency (EPA) currently does not require the recovery and recycling of natural refrigerants such as carbon dioxide; HCs such as propane, isobutane, blends such as R-441A, or ethane; or ammonia.

This is such a blatant air conditioning myth that it inspired the title of this blog post. You should never have to "top off" or "refill" the refrigerant in your air conditioner.

Thus, the correct option is d.

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