FO
1.0 A 0.250 kg block attached to a light spring oscillates on a frictionless, horizontal table. The
oscillation amplitude is A = 0.125 m and the block moves at 3.00 m/s as it passes through
equilibrium at x =
<= 0.
(a) Find the spring constant

Answers

Answer 1

The spring constant, k, will be equal to 18 N/m. The spring constant is defined as the force-to-displaced-length ratio.

What is the spring constant?

Spring constant is defined as the ratio of force per unit displaced length.

Given data;

Mass of  block,m=0.250 k

Amplitude,A = 0.125 m

Velocity,V=3.00 m/

Spring constant, K=?

The spring constant formula when the spring oscillates at the specified amplitude A:

\(\rm k= \frac{v_{max}^2 m}{A} \\\\ k =\frac{3.0 m/s^2 \times 0.250 \ kg}{0.125 \ m} \\\\ k=18 \ N/m\)

Hence, the spring constant, k will be 18 N/m

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Related Questions

A parallel beam of light containing orange (610 nm) and violet (410 nm) wavelengths goes from fused quartz to water, striking the surface between them at a 60.0°60.0° incident angle. What is the angle between the two colors in water?

Answers

Answer:

0.98°

Explanation:

First we find the refracting angle of orange in water

Which is given as

စr= sin^-1. ( 1.456 sin60°/1.33)

= 71.2°

Then that of violet in water

စv=sin^-1. ( 1.468sin60°/1.342)

= 72.3°

So angle between boths colours is the difference

71.2- 72.3= 0.98°

Identify the isotope that has atoms with 117
neutrons, 77 protons, and 77 electrons.
1. None of these
2. 194Ir
3. 77Pt
4. 117Hg
5. 117Os
6. 194Au
7. 77Ti

Answers

Explanation:

Since the atomic number is 77, this means that the element is iridium (Ir). The nucleide notation of this element is

\(^{194}_{\:\:77}\text{Ir}\)

A projectile is fired into the air at an angle of 50° above ground level and hits a target downrange. Neglecting air drag, it will also hit the target if fired at the same speed at an angle of

Answers

Answer:

18 m/s

Explanation:

Range of a projectile on level ground is:

R = v₀² sin(2θ) / g

14.3 m = v₀² sin(2×13°) / 9.8 m/s²

v₀ = 17.9 m/s

Rounded to two significant figures, the launch speed was 18 m/s.

If the bullet is launched at an angle of 50 degrees above ground level, the target will be struck. The angle remains the same. The launch angle obtained is 50 degrees.

Given:

The initial shot was fired at an angle of 50 degrees above ground.

The projectile's starting velocity (v) and magnitude of velocity will remain constant if it is shot at the same pace.

Let the angle of the projectile is x,

The horizontal component of velocity can be calculated as follows:

\(v(x) = v * cos(x)\)

We can write:

since the horizontal part of velocity remains constant:

\(v(x1) = v(x2)\)

\(cos(50) = cos(x)\)

\(50 = x\)

Therefore, if the projectile is launched at the same speed at a 50° angle above ground level, it will strike the target.

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The correct response is given when the angle is asked a question.

Why does the force of gravity on Earth always pull things down?

a
The force of gravity on Earth is always pointing down
b
The force of gravity on Earth always points to the center of the planet
c
The force of gravity on Earth is a force that repulses
d
The force of gravity on Earth is a force that pulls objects away from each other

Answers

Explanation:

the answer is D because of inertia aka the force that pulls obejects downs

How much impulse is imparted on a 0.14 kg baseball initially traveling at 32 m/s when it is struck by a baseball bat and begins to travel in the opposite direction at 49 m/s

Answers

ANSWER AND EXPLAINATION:
To calculate the impulse imparted on the baseball, we can use the impulse-momentum principle, which states that the impulse experienced by an object is equal to the change in momentum of the object. Mathematically, it can be expressed as:

Impulse = Change in momentum

The momentum of an object is given by the product of its mass and velocity:

Momentum = mass × velocity

In this case, the baseball has an initial mass of 0.14 kg and an initial velocity of 32 m/s. After being struck by the bat, it travels in the opposite direction at a velocity of 49 m/s.

Therefore, the change in momentum is given by:

Change in momentum = (mass × final velocity) - (mass × initial velocity)

Change in momentum = mass × (final velocity - initial velocity)

Change in momentum = 0.14 kg × (49 m/s - (-32 m/s))

Change in momentum = 0.14 kg × (49 m/s + 32 m/s)

Change in momentum = 0.14 kg × 81 m/s

Change in momentum = 11.34 kg·m/s

So, the impulse imparted on the baseball is 11.34 kg·m/s.

The efficiency of a machine can be increased by

Answers

Explanation:

the efficiency of a machine can be increased by reducing the friction

please mark the brainliest

Reducing the friction

Which one of the following statements concerning weight and energy balance is most accurate?

A. People generally need the same amount of physical activity to maintain weight stability.

B. Regular physical activity doesn’t impact the percentage of body fat in children and adolescents.

C. It’s possible to achieve weight stability by doing the equivalent of 60–120 minutes a week of moderate-intensity walking.

D. The optimal amount of physical activity needed to maintain weight is unclear.

Answer: D. I took the test and got it right

Answers

The correct answer choice concerning weight and energy balance which is most accurate is the optimal amount of physical activity needed to maintain weight is unclear.

What is energy balance?

Energy balance refers to the way in balance is achieved when intake of energy is equal to energy expended.

Energy refers to the impetus behind all motion and all activity. If is also the capacity to do work. Energy is measured in a unit dimensioned in mass × distance²/time² (ML²/T²) or the equivalent.

So therefore, the correct answer choice concerning weight and energy balance which is most accurate is the optimal amount of physical activity needed to maintain weight is unclear.

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** State the reason why heat transfer by radiation is faster than heat transfer by conduction ​

Answers

Heat transfer by radiation is faster than heat transfer by conduction because radiation can occur through a vacuum, while conduction requires the presence of a medium, such as a solid, liquid, or gas. Radiation is the transfer of energy through electromagnetic waves and does not require any medium to propagate, which means that radiation can occur even in a vacuum or through transparent materials.

On the other hand, conduction requires particles to transfer heat energy from one object to another. In a solid, this occurs through the transfer of kinetic energy from one molecule to another through direct contact, while in a liquid or gas, conduction occurs through collisions between molecules. This process of molecule-to-molecule transfer of heat energy is much slower than radiation and is limited by the physical properties of the medium, such as its thermal conductivity.

Therefore, heat transfer by radiation is faster than heat transfer by conduction because radiation can occur through a vacuum, and is not limited by the physical properties of a medium, while conduction is limited by the thermal conductivity of the medium and requires direct contact between molecules.

a test charge with loaded +4e and d1=2mm above ground
with reference 1, test charge end with charge +6e and position d2=6mm from the origin
It shows 2. Accordingly, consumption 2 over delivery 1 electrostatic
what is the magnitude of the x-component of the force

a test charge with loaded +4e and d1=2mm above groundwith reference 1, test charge end with charge +6e

Answers

Answer:

I didn't mean to click give answer sorry

What is the acceleration due to the gravity at a distance of 2 earth radii above earth’s surfaceanswer is: g/9=1.11m/s^2

Answers

Given data

*The height above the earth's surface is

\(h=2R_e\)

The formula for the Earth's gravity variation with altitude is given as

\(g_h=g(\frac{R_e}{R_e+h})^2\)

*Here g is the standard gravitational acceleration

*Here R_e is the earth's mean radius

Substitute the known values in the above expression as

\(\begin{gathered} g_h=g(\frac{R_e}{R_e+2R_e})^2 \\ =\frac{g}{9} \\ =\frac{9.81}{9} \\ =1.09m/s^2 \end{gathered}\)

Can anyone please help me

Can anyone please help me

Answers

To solve this problem, we can use Coulomb's law, which states that the electric force between two point charges is proportional to the product of their charges and inversely proportional to the square of the distance between them.

We can then use the electric force to find the electric field at the location of q3 and the initial acceleration of q3.

a) To find the electric field at the location of q3, we can first find the electric force on q3 due to q1 and q2 and then use the definition of the electric field, which is the electric force per unit charge. The electric force on q³ due to q¹ and q² is:

F1 = k x q¹ x q³/ r1²

F2 = k x q² x q³ / r2²

where r¹ and r² are the distances from q¹ and q² to q³, respectively, and k is Coulomb's constant.

Since q³ is equidistant from q¹ and q², we have r¹ = r² = 0.20 m. Substituting the given values, we get:

F1 = (9.0 x 10⁹ N-m²/C²) x (4.0 x 10⁻⁶ C) x (2.0 x 10⁻⁶C) / (0.20 m)² = 1.8 N

F2 = (9.0 x 10⁹ N-m⁻²/C²) x (-6.0 x 10⁻⁶ C) x (2.0 x 10⁻⁶C) / (0.20 m)² = -5.4 N

The negative sign of F2 indicates that the force on q³ due to q² is in the opposite direction to the force due to q¹.

The net electric force on q3 is the vector sum of the forces due to q1 and q2:

Fnet = F1 + F2 = 1.8 N - 5.4 N = -3.6 N

The electric field at the location of q³ is then:

E = Fnet / q³ = (-3.6 N) / (2.0 x 10⁻⁶ C) = -1.8 x 10⁻⁶N/C

The negative sign of the electric field indicates that the field is directed towards q².

b) To find the initial acceleration of q³, we can use Newton's second law, which states that the net force on an object is equal to its mass times its acceleration:

Fnet = ma

where m is the mass of q³ and a is its initial acceleration.

Substituting the given values, we get:

-3.6 N = (2.0 x 10⁻⁶ kg) x a

Solving for a, we get:

a = -1.8 x 10³ m/s²

The negative sign of the acceleration indicates that it is directed towards q².

c) The direction of the initial acceleration of q³ is towards q².

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Which is considered computer storage
The options are application Hard drive input and software

Which is considered computer storage The options are application Hard drive input and software

Answers

Answer:

Second Option

Explanation:

The "hard drive" or the second option is one of the main components of storing information on a computer. You already have a hard drive built into your computer, or laptop when you buy it, and you can buy additional hard drives in the form of plugins that can store even more data if your original hard drive becomes full of data.

Hope this helps.

Answer:

B

Explanation:

Whereas memory refers to the location of short-term data, storage is the component of your computer that allows you to store and access data on a long-term basis. Usually, storage comes in the form of a solid-state drive or a hard drive.

The first P-wave of an earthquake travels 5600 kilometers from the epicenter and arrives at a seismic station at 10:05 a.m. At what time did this earthquake occur?

Ahhhhhh I have a Regent's test in 2 hours and I don't know how to solve this type of question! Any help would be appreciated.

Anyone know what the steps to do this are? I dont even need an answer, just how to get to it. Thank you!

Answers

The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.

The p-waves travel with a constant velocity of 7 km/s

The time can be calculated by using the formula

t = d / v

where

T1 =  10:05 a.m

d is the distance they take to travel from the epicenter

v is the speed of the p-waves

On average, the speed of p-waves is

v = 7 km/s

d = 5600 km (given)

Substituting the values in the formula;

t = d / v

t = 5600 ÷ 7

t = 800 seconds

Converting into minutes,

t = 800 ÷ 60

t = 13.3

≈ 13 mins

T1 -  13 mins = T2

10:05 - 13 mins = 9.52 am

It means the earthquake occurred prior 13 minutes, that is at 9.52 am.

Therefore, the earthquake occurred at 9.52 am.

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A hydraulic system has two pistons. Input force on one piston is 15.8 lb and the other piston can lift a weight of 93 lb. What is the mechanical advantage?​

Answers

Answer:

The mechanical advantage of a hydraulic system is given by the ratio of the output force to the input force. In this case, the input force is 15.8 lb and the output force is 93 lb.

So, the mechanical advantage of the hydraulic system is:

MA = Output force / Input force

MA = 93 lb / 15.8 lb

MA = 5.89

Therefore, the mechanical advantage of the hydraulic system is 5.89. This means that the system can lift a weight that is almost 6 times greater than the input force applied to the other piston.

(4x)。
(2x+6)。
I need to solve x for these angles

(4x)(2x+6)I need to solve x for these angles

Answers

Answer: x=14

Explanation:

there is 90° in a right angle so

(4x)+(2x+6) =90

collect like terms

6x+6=90

 -6 from both sides

6x=84

 ÷6

x=14

Testing shows that a sample of wood from an artifact contains 50% of the original amount of carbon-14. Given that the half-life of carbon-14 is 5730
years, how old is the artifact?
A. 22,920 years
B. 11,460 years
C. 5730 years
D. 2865 years

Answers

Answer:

C. 5730 years

Explanation:

N(t) = N(0)e^-kt

The half-life is T = 5730 years,

e^-kT = 1/2

→ k = - ln(1/2) / T

→ - ln(1/2) / 5730

→ 1.209681 x 10^-4 years^-1

The amount present dropped to 50%.

Then one half-life has elapsed, so the age is 5730 years.

During the earthquake, what we need to do to be safe,write steps.
(i) When you are in the classroom.
(ii) When you are out of danger

Answers

During an earthquake, it is important to take appropriate steps to ensure safety

Steps you can follow in two different scenarios

(i) When you are in the classroom

Drop, Cover, and Hold On: Quickly drop to the ground, take cover under a sturdy desk or table, and hold on to it to protect yourself from falling objects and potential structural collapse.

Protect Your Head: If possible, use your arms to cover your head and neck to provide additional protection.

Stay Indoors: Remain inside the classroom until the shaking stops and it is safe to exit. Be prepared for aftershocks, which are smaller tremors that may occur after the main earthquake.

(ii) When you are out of danger:

Evacuate to Open Space: If you are no longer in immediate danger, move quickly to an open space away from buildings, trees, streetlights, and utility wires that may pose a risk of falling or collapsing.

Watch for Falling Debris: Be aware of your surroundings and watch out for any hazards such as falling debris, broken glass, or damaged infrastructure.

Stay Clear of Buildings: Avoid entering damaged buildings or structures as they may be unstable. Keep a safe distance until authorities confirm it is safe to enter.

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Which kind of precipitation is formed, in part, by wind?

A. Rain
B. Snow
C. Sleet
D. Hail

Answers

Answer:

Rain

Explanation:

the answer would be A. rain

Find the direction and magnitude of the vectors (a) A = (25m)x + (-12m)y(b) B = (2.0m)x + (15m)y and(c) A + B

Answers

ANSWER

\(\begin{gathered} a)\theta=-25.6\degree;|A|=27.73m \\ b)\theta=82.4\degree;|B|=15.13m \\ c)\theta=6.3\degree^{};|A+B|=27.17m \end{gathered}\)

EXPLANATION

To find the direction of a two-dimensional vector, we apply the formula:

\(\theta=\tan ^{-1}(\frac{a_y}{a_x})\)

To find the magnitude of a two-dimensional vector, we apply the formula:

\(|a|=\sqrt[]{(a^{}_y)^2+(a_x)^2}\)

a) The direction of vector A is:

\(\begin{gathered} \theta=\tan ^{-1}(\frac{-12m}{25m}) \\ \theta=\tan ^{-1}(-0.48) \\ \theta=-25.6\degree \end{gathered}\)

The magnitude of vector A is:

\(\begin{gathered} |A|=\sqrt[]{(25m)^2+(-12m)^2} \\ |A|=\sqrt[]{625m^2+144m^2}=\sqrt[]{769m^2} \\ |A|=27.73m \end{gathered}\)

b) The direction of vector B is:

\(\begin{gathered} \theta=\tan ^{-1}(\frac{15m}{2m}) \\ \theta=\tan ^{-1}(7.5) \\ \theta=82.4\degree \end{gathered}\)

The magnitude of vector B is:

\(\begin{gathered} |B|=\sqrt[]{(2.0m)^2+(15m)^2} \\ |B|=\sqrt[]{4m^2+225m^2}=\sqrt[]{229m^2} \\ |B|=15.13m \end{gathered}\)

c) First, we have to find the sum of A and B:

\(\begin{gathered} A+B=(25m)x+(-12m)y+(2.0m)x+(15m)y \\ A+B=(25m+2.0m)x+(-12m+15m)y \\ A+B=(27m)x+(3m)y \end{gathered}\)

The direction of the vector (A + B) is:

\(\begin{gathered} \theta=\tan ^{-1}(\frac{3m}{27m}) \\ \theta=\tan ^{-1}(0.1111) \\ \theta=6.3\degree^{} \end{gathered}\)

The magnitude of the vector (A + B) is:

\(\begin{gathered} |A+B|=\sqrt[]{(27m)^2+(3m)^2} \\ |A+B|=\sqrt[]{729m^2+9m^2}=\sqrt[]{738m^2} \\ |A+B|=27.17m \end{gathered}\)

A 0.15 kg baseball moving at +26 m/s is slowed to a stop by a catcher who exerts a

constant force of -390 N. How long does it take this force to stop the ball?

Answers

Answer:

0.01 s

Explanation:

The following data were obtained from the question:

Mass (m) of baseball = 0.15 kg

Initial velocity (u) = +26 m/s

Final velocity (v) = 0 m/s

Force (F) applied = –390 N

Time (t) =?

Next, we shall determine the acceleration of the baseball. This can be obtained as follow:

Mass (m) of baseball = 0.15 kg

Force (F) applied = –390 N

Acceleration (a) of baseball =?

F = ma

–390 = 0.15 × a

Divide both side by 0.15

a = –390/0.15

a = –2600 m/s²

Finally, we shall determine the time taken for the baseball to stop. This can be obtained as follow:

Initial velocity (u) = +26 m/s

Final velocity (v) = 0 m/s

Acceleration (a) = –2600 m/s²

Time (t) =?

v = u + at

0 = 26 + (–2600 × t)

0 = 26 – 2600t

Collect like terms

0 – 26 = – 2600t

– 26 = – 2600t

Divide both side by – 2600

t = –26 / –2600

t = 0.01 s

Thus, it will take 0.01 s for the baseball to stop.

Answer:

0.01 s

Explanation:

The answer above is correct.

two wharves A and B are directly opposite each other on a 40m wide river which flows in the direction shown. a boat leaves A and heads at constant speed at right angles to the flow of the river. it lands at point C, with the trip taking 20 seconds.
find;
a) the displacement from C to A

b) the speed of the boat as seen by people standing at A.

c) the speed of the water in the river

d) the speed of the boat as seen by a fish drifting with the river.

e) Draw a vector diagram and u
se it to find the direction the boat should head ( at the same constant speed as before) if it is to travel directly from A to B.​

two wharves A and B are directly opposite each other on a 40m wide river which flows in the direction

Answers

Answer:

a)40 meters

b)2 m/s

c)2 m/s

d)0 m/s

e)45 degrees northeast

Explanation:

a) The displacement from C to A is the distance directly across the river, which is 40 meters.

b) The speed of the boat as seen by people standing at A is the magnitude of the boat's velocity vector, which is equal to the displacement divided by the time taken:

Speed = displacement / time = 40 m / 20 s = 2 m/s.

c) Let v be the speed of the water in the river. The boat is moving at right angles to the flow of the river, so the water exerts a perpendicular force on the boat. The time taken for the boat to travel from A to C is 20 seconds, during which time the boat will have been carried downstream by the river by a distance equal to v times the time taken.

Distance carried downstream = v × time = v × 20 m.

Since the boat landed at C, which is directly across the river from A, the distance it traveled horizontally is 40 meters. Therefore:

40 m = (boat speed) × (time taken) = (boat speed) × 20 s.

Hence, the speed of the boat is:

Boat speed = 40 m / 20 s = 2 m/s.

So, we have two equations:

Distance carried downstream = v × 20 m

Boat speed = 2 m/s

From the first equation, we get:

v × 20 m = 40 m

Therefore, the speed of the water in the river is:

v = 40 m / 20 m = 2 m/s.

d) The speed of the boat as seen by a fish drifting with the river is the difference between the speed of the boat and the speed of the water in the river:

Boat speed - Water speed = 2 m/s - 2 m/s = 0 m/s.

So, the speed of the boat as seen by a fish drifting with the river is zero.

e) The boat should head in a direction that makes its velocity vector point directly from A to B. Since A and B are directly opposite each other, this means the velocity vector should be perpendicular to the line connecting A and B.

We know the boat's velocity vector has a magnitude of 2 m/s and is at right angles to the velocity vector of the water in the river, which has a magnitude of 2 m/s. So, we can draw a vector diagram with the velocity vector of the boat pointing straight up and the velocity vector of the water pointing straight to the right. The vector connecting the tail of the water velocity vector to the head of the boat velocity vector will then point directly from A to B.

The angle between the boat's velocity vector and the line connecting A and B can be found using trigonometry. Let θ be this angle. Then:

tan(θ) = (boat speed) / (water speed) = 2 m/s / 2 m/s = 1.

Taking the inverse tangent of both sides gives:

θ = tan^(-1)(1) = 45°.

So, the boat should head in a direction 45 degrees to the right of straight up, or northeast.

You throw a water ballon straight up with a velocity of 12 m/s. What is its maximum height

Answers

Answer:7.35 meters

Explanation:

Assuming that air resistance is negligible, we can use the kinematic equation:

h = (v^2)/(2g)

where h is the maximum height, v is the initial velocity, and g is the acceleration due to gravity (9.8 m/s^2).

Substituting the given values:

h = (12^2)/(2 × 9.8)

h = 7.35 meters

Therefore, the maximum height of the water balloon is approximately 7.35 meters.

3A ball rolls off a 1.0 m high table with a speed of 4.0 m/s, as shown in the figure below. Calculate the speed as the ball strikes the floor:
4.0 ms¹
1.0 m

3A ball rolls off a 1.0 m high table with a speed of 4.0 m/s, as shown in the figure below. Calculate

Answers

Answer:

Vy = g T       where T is the time taken to fall

1 = 1/2 g T^2      time to fall 1 m

T = (2 / 9.8)^1/2 = .45 sec

Vy = 9.8 * .45 = 4.43 m/s

V = (Vx^2 + Vy^2)^1/2 = (16 + 19.6)^1/2 = 5.97 m/s

.

Calculate the ideal mechanical advantage of a pair of scissors where the length of the blade is 5 cm and the length of the handle is 2.5 cm.

Answers

Answer:

m = 0.5

Explanation:

Given that,

The length of the blade of scissors = 5 cm

The length of the handle = 2.5 cm

Here, effort arm is 2.5 cm and load arm is 5 cm. The mechanical advantage is the ratio of effort arm to the load arm as follows :

\(m=\dfrac{2.5}{5}\\\\m=0.5\)

So, the ideal mechanical advantage of a pair of scissors is 0.5.

A small business operates3 pieces of equipment for 9 hrs continuously per day for 6 days a week if the 3 equipment consume 10kw, 2.5kw and 600watts respectively calculate the weekly cost if charge per unit is 7.9 pence​

Answers

Answer:

5588.46 pence

Explanation:

The following data were obtained from the question:

Power of 1st equipment (P₁) = 10 KW

Power of 2nd equipment (P₂) = 2.5 KW Power of 3rd equipment (P₃) = 600 W

Time (t) = 9 hours per day.

Cost per day = 7.9 pence​ per unit KWh

Cost for a week =?

Next, we shall convert 600 W to KW. This can be obtained as follow:

1000 W = 1 KW

Therefore,

600 W = 600 W × 1 KW / 1000 W

600 W = 0.6 KW

Next, we shall determine the total power consumed. This can be obtained as follow:

Power of 1st equipment (P₁) = 10 KW

Power of 2nd equipment (P₂) = 2.5 KW Power of 3rd equipment (P₃) = 0.6 KW

Total power (Pₜ) =?

Pₜ = P₁ + P₂ + P₃

Pₜ = 10 + 2.5 + 0.6

Pₜ = 13.1 KW

Next, we shall determine the total time of operation in a week. This can be obtained as follow:

From the question given above, we were told that:

1 day = 9 hours

Therefore,

6 days = 6 × 9 = 54 hours.

Thus, the total time of operation is 36 hours.

Finally, we shall determine the cost operating the three (3) equipment for a week (i.e 6 days). This can be obtained as follow:

Total power (Pₜ) = 13.1 KW

Total time (tₜ) = 54 hours

Cost per day (Cₔ) = 7.9 pence​ per unit KWh

Cost per week (Cᵥᵥ) =?

Cᵥᵥ = Pₜ × tₜ × Cₔ

Cᵥᵥ = 13.1 × 54 × 7.9

Cᵥᵥ = 5588.46 pence

Therefore, the cost operating the three (3) equipment for a week (i.e 6 days) is 5588.46 pence

An object with a mass of 5 kg is traveling ata velocity of 20 m/s. How much kinetic energy does it have?

An object with a mass of 5 kg is traveling ata velocity of 20 m/s. How much kinetic energy does it have?

Answers

Answer:

KE = ½mv²

KE = ½5kg×(20m/s)²

KE = ½5kg×400m²/s²

KE =5kg×200m²/s²

KE = 1000joules

Do you believe you can create a Controlled experiment without an Observational Study? Why or Why not. Include scientific evidence to support your response. PLEASE HELP I BEG YOU.

Answers

Answer:

No, it is very unlikely to perform a controlled experiment, because you need to observe the amount or anything from something. Consider someone on the busy street of a New York neighborhood asking random people that pass by how many pets they have, then taking this data and using it to decide if there should be more pet food stores in that area.

Lab Report Sun, Earth, and Moon Models It’s time to complete your Lab Report. Save the lab to your computer with the correct unit number, lab name, and your name at the end of the file name (e.g., U5_ Lab_SunEarthAndMoonModels_Alice_Jones.doc). Introduction 1. What was the purpose of the investigation? Type your answer here: 2. What causes the bright part of the moon to appear bright? Type your answer here: Experimental Methods 1. What materials did you use to create your model? Type your answer here: 2. Describe how you created your model. Type your answer here: Develop a Model 1. Show your model and the relationships between the components. Include labeled pictures or diagrams that describe causal accounts for the phases of the moon and eclipses. Type your answer here: Use a Model 1. Use your model to predict the relative positions of the earth, sun, and moon when the moon is full. Type your answer here: 2. Use your model to explain why a lunar eclipse does not occur every month when there is a full moon. Type your answer here:

Answers

1. The purpose of the investigation was to study the relationship between the Sun, Earth, and Moon.

2. The bright part of the moon appears bright due to the reflection of sunlight.

Introduction: The purpose of the investigation was to study the relationship between the Sun, Earth, and Moon. By creating models of the three celestial bodies, we aimed to understand how their movements and positions influence the phases of the moon and eclipses.The bright part of the moon appears bright due to the reflection of sunlight. As sunlight hits the moon's surface, it bounces back and reflects into space. This reflected light is what we see as the bright part of the moon.

Experimental Methods: To create our model, we used a lamp to represent the Sun, a ball to represent the Earth, and a smaller ball to represent the Moon. We also used a ruler, tape, and a protractor to measure distances and angles.We created our model by placing the lamp at one end of a table, the Earth in the middle, and the Moon at the other end. We attached the Moon to a string and moved it around the Earth to simulate the Moon's orbit around the Earth.

Develop a Model: Our model consists of a lamp, a ball, and a smaller ball on a string. The lamp represents the Sun, the ball represents the Earth, and the smaller ball on the string represents the Moon. As the Moon moves around the Earth, it goes through phases, from a new moon to a full moon and back again.We used diagrams and pictures to label the components of our model and describe causal accounts for the phases of the moon and eclipses.

Use a Model: When the Moon is full, it is in a direct line with the Earth and the Sun. Using our model, we can predict that the Moon would be directly opposite the Sun in the sky during a full moon. A lunar eclipse does not occur every month when there is a full moon because the Moon's orbit around the Earth is tilted at an angle of about 5 degrees to the Earth's orbit around the Sun. Therefore, the Moon is not always in a direct line with the Earth and the Sun during a full moon, which is necessary for a lunar eclipse to occur.

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The form of energy found in moving objects is ___??

Answers

Answer:

kinetic energy

Explanation:

It is kinetic energy because it is an energy in motion. In order words it is an energy which the body or object moves.

If the sound level at a point is 98.0 dB, what is the intensity of sound at that point (Unit=W/m^2)? please help will give brainliest

Answers

Explanation:

The decibel scale is a logarithmic scale where each bel or 10 decibels correspondents to a factor of ten. A power intensity of 10^(-12) watts per square meter is the standard reference for a SPL of 0 db. So an SPL of 98 db corresponds to a power intensity of 10^(9.8)*10^(-12) or 10^(9.8–12) w/m^2.

0.006309573 w/m^2.

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